Answer:
in contrast, peru and Bolivia entered the war hindered by numerous domestic fractures and by an economic and insititutional backwardness that nearly prevented the two countries from fighting the war at all
............................................................................................................................
Answer:
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Explanation:
because ........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................
how many hydrogen atoms are in 2 moles of h2o?
Answer:
1 mole = 6.022×10^23 atoms. 1 water molecule = 2 Hydrogen atoms + 1 oxygen atom. So, 1 mole H2O = 1.2044×10^24 hydrogen atoms. Therefore 2 mole H2O will have 2.4088×10^24 hydrogen atoms.
Explanation:
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On beaches there are often areas of grassy dunes where people are prohibited from walking. How do these protected areas preserve ecosystem services? Use the graphic organizer to categorize the following as either examples of land reclamation of protecting biodiversity.
Answer:
Preventing erosion – Land Reclamation
Protecting nesting areas – Protecting Biodiversity
Preventing littering – Land Reclamation
Preventing habitat disruption – Protecting Biodiversity
Protecting native species – Protecting Biodiversity
Preventing contamination of soil – Land Reclamation
Explanation:
I really hope I'm right! I tried my hardest, please give me brainliest :)
have a good day!
How is Carbon-12 and Carbon-13 different? What’s is the name that describes these two atoms?
Answer:
Carbon 12 and 13 are carbon isotopes, meaning that they have additional neutrons:
Carbon 12 has exactly 6 protons and 6 neutrons ( hence the 12 )
Carbon 13 has 6 protons and 7 neutrons ( hence the 13 )
They differ in the number of neutrons in the nucleus.
Names:
carbon-13, C-13
carbon-12, C-12
3. Which particles of an atom have the greatest mass?
A. Proton and electron
B. Proton, neutron, and electron have the same mass
C. Electron and Neutron
D. Proton and Neutron
Answer:
i think its B.
Explanation:
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For the chemical reactionHCIO (aq)+NaOH(aq) H, O(l) + NaClo, (aq)write the net ionic equation, including the phases.net ionic equation:Which ions are considered spectator ions for this reaction?HNatOHCIO:
Explanation:
We are given this molecular equation:
HCIO₄ (aq) + NaOH (aq) -----> H₂O (l) + NaCIO₄ (aq) Molecular Equation
And we have to find the net ionic equation. Before that, we have to write the total ionic equation. We have to split all the compounds that we can into its ions. We have 3 aqueous solution:
HClO₄ (aq) ----> H⁺ (aq) + ClO₄⁻ (aq)
NaOH (aq) ----> Na⁺ (aq) + OH⁻ (aq)
NaCIO₄ (aq) ----> Na⁺ (aq) + ClO₄⁻ (aq)
And H₂O is a liquid so we leave it like that. The total ionic equation will be:
H⁺ (aq) + ClO₄⁻ (aq) + Na⁺ (aq) + OH⁻ (aq) ----> H₂O (l) + Na⁺ (aq) + ClO₄⁻ (aq) Total Ionic Equation
Finally to get the net ionic equation we have to cancel the spectator ions. By definition they are ions that doesn't participate in the reaction and are found on both sides of the equation.
Spectator ions = ClO₄⁻ (aq) and Na⁺ (aq)
H⁺ (aq) + OH⁻ (aq) ----> H₂O (l) Net Ionic Equation
Answer: The spectator ions are ClO₄⁻ (aq) and Na⁺ (aq).
The net ionic equation is: H⁺ (aq) + OH⁻ (aq) ----> H₂O (l)
Suppose that a 10-mL sample of a solution is to be tested for I− ion by addition of 1 drop (0.2 mL) of 0.13 M Pb(NO3)2.
What is the minimum number of grams of I− that must be present in order for PbI2(s) ( Ksp=8.49×10−9 ) to form?
The minimum number of grams of I that must be present is ; 0.01836 * 10⁻³ mol
Given data :
Volume of solution to be tested for I-ion = 10 mL
Volume of Pb(NO₃)₂ = 0.2 mL
molarity of Pb(NO₃)₂ = 0.13 M
Determine the number of I that must be presentFirst step : calculate conc of PB²⁺ ions in the solution
conc of PB²⁺ ions = ( molarity of Pb(NO₃)₂ * volume of Pb(NO₃)₂ ) / ( total volume )
= ( 0.13 * 0.2 ) / ( 10 + 0.2 )
= ( 0.026 ) / ( 10.2 ) = 0.002549 M
Next step : determine the molarity of I
using the dissociation reaction of PbI₂
PbI₂(s) ---> Pb²⁺ (aq) + 2I (aq)
also; Ksp = [ Pb²⁺ ] [ I ]² ---- ( 1 )
From the question the given value of Ksp = 8.49 * 10⁻⁹
Therefore equation ( 1 ) becomes
8.49 * 10⁻⁹ = ( 0.002549 ) * [ I ]²
[ I ] = √ ( 8.49 * 10⁻⁹ ) / ( 0.002549 )
= 0.0018 M
Final step : Determine the minimum number of grams of I
moles of I = molarity of I * total volume
= 0.0018 M * 10.2 mL
= 0.01836 * 10⁻³ mol
Hence we can conclude that The minimum number of grams of I that must be present is ; 0.01836 * 10⁻³ mol
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How many moles of He are in a
container with a volume
of 5.6 L at STP?
Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 0.25moles of He are in a container with a volume of 5.6 L at STP.
What is mole?The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.
One mole of ideal gas has 22.4L volume at STP.
number of moles of Helium = Given volume ÷volume occupied by gas at STP
Given volume of helium = 5.6 L
Substituting all the given values, we get
number of moles of Helium = 5.6 L ÷22.4L
number of moles of Helium =0.25moles
Therefore, 0.25moles of He are in a container with a volume of 5.6 L at STP.
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Answer: 0.25 moles
Explanation:
Given volume of helium = 5.6 L
Substituting all the given values, we get
number of moles of Helium = 5.6 L ÷22.4L
number of moles of Helium =0.25moles
Therefore, 0.25moles of He are in a container with a volume of 5.6 L at STP.
C c Why did they work an average brightness for each length of graphite tested?
An average brightness was calculated for each length of graphite tested to get a better understanding of the relationship between the length of the graphite and the brightness of the line it produced.
What is the use of graphite?Graphite has many uses in various industries. Some of its uses include: Pencils, Lubricants, Refractories, Batteries, Electrodes, Nuclear reactors, Aerospace industry.
By calculating the average, it is possible to see if there is a trend in the data and if longer or shorter lengths of graphite produce brighter or duller lines. This information can be useful in determining the best length of graphite to use for a particular task or project.
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A rattlesnake is 2.44m long. How many centimeters (cm) long is the snake? 1 m = 100 cm (please show the work) ASAP
Answer:
The rattlesnake is 144 cm long
Explanation:
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A quantity of nitrogen gas is enclosed in a tightly stoppered 500 mL flask at room temperature (20.0 °C) and 0.836 atm pressure. The flask is then heated to 680 °C. If the flask can withstand pressures up to 3 atm, will it explode under this heating? (In other words, what is the final pressure?). Remember to convert between °C and K.
Will the flask explode if the pressure is less than 3 atm if it can tolerate pressures up to that level.
Is nitrogen beneficial to the body?To create the proteins found in your muscles, skin, blood, hair, nails, and DNA, your body needs nitrogen. According the Royal Society of Chemistry, your diet's protein-containing foods are where you get your nitrogen. Meat, fish, beans, nuts, eggs, milk, and other dairy items are some of these foods. Nitrogen exposure is hazardous because it can displace oxygen and induce asphyxia.
Briefing:The formula below is used to determine the pressure at a given temperature for a given volume of nitrogen gas:
P₁/T₁ = P₂/T₂
where;
Initial pressure is P1.
Initial temperature is T1.
Final pressure is P2.
T2 is the final temperature.
P2 solution
P₂ = P₁ * T₂ / T₁
P₂ = 0.836 * (680 + 273) / (20 + 273)
P₂ = 2.72 atm =3atm
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Hydrochloric acid and oxygen gas form water and chlorine gas. How many moles of oxygen are required to produce 7.03 moles of water.
Explanation:
According to the problem, hydrochloric acid and oxygen gas form water and chlorine gas. The unbalanced equation will be:
__ HCl + __ O₂ ---> __ H₂O + __ Cl₂
We have two atoms of O on the left and just one on the right. We can change the coefficient for H₂O to balance the O.
__ HCl + __ O₂ ---> 2 H₂O + __ Cl₂
Now we have four atoms of H on the right and just one on the left. We can change the coefficient for HCl to balance the H.
4 HCl + __ O₂ ---> 2 H₂O + __ Cl₂
And finally we have four atoms of Cl on the left and just two on the right. We can change the coefficient for Cl₂ to balance the Cl. The balanced equation is:
4 HCl + O₂ ---> 2 H₂O + 2 Cl₂
According to the coefficients of the equation, 4 moles of HCl will react with 1 mol of O₂ to produce 2 moles of H₂O and 2 moles of Cl₂. So 1 mol of O₂ will be required to produce 2 moles of H₂O. We can use that ratio to find the number of moles of O₂ that are required to produce 7.03 moles of H₂O.
1 mol of O₂ : 2 moles of H₂O molar ratio
moles of O₂ = 7.03 moles of H₂O * 1 mol of O₂/(2 moles of H₂O)
moles of O₂ = 3.52 moles
Answer: 3.52 moles of oxygen gas are required to produce 7.03 moles of water.
Suppose you did the lab and someone came and said your unknown acid sample was
actually HCl instead of H2SO4. Everything else remains the same; the standard acid was H2SO4,
the base was NaOH. What would change in your final calculation of the unknown acid
concentration
Answer:
H2SO4
Explanation:
because it's not more acidic
Both sulfuric acid and hydrochloric acid are potent acids, but hydrochloric acid is stronger. Because HCl is monoprotic and H2SO4 is diprotic, they differ mostly in their acid types.
Can HCl be substituted for H2SO4?Instead of using hydrochloric acid, sulphuric acid (H 2 SO 4) is preferred because: This acid is commonly utilized for a variety of neutralization reactions. Sulphuric acid is more potent than all other acids and is also simpler and safer to use. Even if there is a risk for negative reactions, they are uncommon.
The majority of the time because it is for a redox reaction or titration in which HCl would react to produce chlorine on its own. You could use phosphoric or sulfuric acid.
In this situation, H 2 SO 4 is preferable to HCl. Due to the considerable acidity of H 2 SO 4, the solution is made to be more acidic than HCl. As a result, the findings of titration using H 2 SO 4 are more precise. H 2 SO4 generates two hydronium ions, whereas HCl only generates one.
It shows how many protons split apart to create hydronium ions. The acid will be more potent the lower the pKa value. Therefore, we can conclude that HCl is more acidic than H2S O 4.
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13. Which of the following chemical reactions is an oxidation-reduction reaction?
A. C02 + H20 - H2C03
B. Pb(N03)2 + 2HC1- PbCh + 2HN03
C. H2S04 + Ba(OH)2 - BaS04 + 2H20
D. NH3 + HCl - NH4CI
E. Mg + CO2 - MgO + CO
Mg + CO\(_2\)→ MgO + CO is an oxidation-reduction reaction. Therefore, the correct option is option E among all the given options.
Redox reactions involve oxidation-reduction chemical processes in which the oxidation states of the reactants change. Redox is a shortened version of reduction-oxidation. Two distinct processes—a reduction process or an oxidation process—can be used to describe all redox reactions.
In redox and oxidation-reduction processes, the oxidation or reduction reactions usually take place concurrently. In a chemical reaction, the material that is being reduced is referred to as the reducing agent, and the substance that is being oxidised is the oxidising agent. Mg + CO\(_2\)→ MgO + CO is an oxidation-reduction reaction.
Therefore, the correct option is option E.
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what is the PH scale of 0.02m of hydrochloric acid
Answer:
Explanation:
The pH of 0.02 M hydrochloric acid is approximately 1.7.
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This element has 4 more protons than Silicon
Answer:
Argon would be the correct choice.
Explanation:
Silicon has a total of 14 protons. If 4 protons would be added, you would now have argon, the 18th element.
Which of the following is not a base :CaSO4, Al(OH)3, Ca(OH)2, KOH
Answer:
among these which is not a base is CaSO4
What is the average atomic mass of 10 hydrogen -1 molecules?
Answer:
1.674 x 10^-23 grams
Explanation:
Hydrogen-1 is called Protium
wikipedia
atomic mass of Protium is 1.00794 amu
sciencedirectcom
atomic mass of 10 Protiums is 10.0794 amu
10.0794 amu in grams is
1.6737236x10^-23 grams
what is lithification
lithification is a complex process where sediments are compact under pressure, expel connate fluids and converted into solid rock.
What are Rock?A rock is the collection of solid (grains) mineral materials that grow or become cemented together. it can be a natural substance composed of solid crystals of different minerals that have been blend together into a solid lump.
Types of Rocks?The major types of rocks are:
Igneous rocks: also known as fire ( Latin ) are form when hot, molten rock (magma) crystallizes and solidifies. The melt substance originates deep within the Earth.sedimentary: sedimentary rocks are generally formed from pre-existing rocks or remains of once-living organisms. They are also form from deposits that accumulate on the Earth's surface. It is observed that sedimentary rocks often have distinctive layering or bedding.metamorphic: this type of rock is also referred as changed rocks, it occurs when solid rock changes in composition and/or texture without the mineral crystals melting. The changes is as a result of the subject to high heat, high pressure, hot mineral-rich fluids.learn more about Rocks here:
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The elementary steps for the catalyzed decomposition of dinitrogen monoxide are:
N2O (g) + NO (g) → N2 (g) + NO2 (g)
2 NO2 (g) → 2 NO (g) + O2 (g)
Which of the following statements are CORRECT?
1. The overall balanced reaction is 2 N2O (g) → 2 N2 (g) + O2 (g).
2. NO (g) is a catalyst for the reaction.
3. N2 (g) is a reaction intermediate.
4. NO2 (g) is a reaction intermediate.
A. 1, 2, and 4
B. 1, 2, and 3
C. 1 and 2
D. 1 only
E. 4 only
The correct option for the catalyzed decomposition for given dinitrogen monoxide are- A. 1, 2, and 4
Explain the formation of dinitrogen monoxide?Nitrous oxide, also referred to as laughing gas, nitrous, simply nos, is a chemical substance that has the formula N2O and is also known as dinitrogen oxide as well as dinitrogen monoxide.
It is a colorless, nonflammable gas that tastes and smells mildly sweet at normal temperature. It is used as a sedative during medical and dental operations to assist patients feel more at ease and to reduce their anxiety. The melting point of dinitrogen monoxide is -88.48 °C.The fundamental procedures for dinitrogen monoxide's catalyzed breakdown are:
N2O (g) + NO (g) → N2 (g) + NO2 (g)
2 NO2 (g) → 2 NO (g) + O2 (g)
Thus, the correct statements are-
1. The overall balanced reaction is 2 N2O (g) → 2 N2 (g) + O2 (g).
2. NO (g) is a catalyst for the reaction.
4. NO2 (g) is a reaction intermediate.
Therefore, A. 1, 2, and 4 is the correct option.
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An object has a mass of 57.8 g. Find the object's density, given that its volume is 40.14 cm3.
Answer:
1.44 g/cm^3
Explanation:
The equation for density is d=m/v.
Two practical solutions that a learner can use to resolve conflict with their parents about poor school performance.
Here are two practical solutions that a learner can use to resolve conflict with their parents about poor school performance:
Communicate openly: One of the best ways to resolve conflict is to communicate openly and honestly with your parents. This means expressing your concerns and sharing your feelings about your school performance. Explain to your parents why you are struggling and what you think could be done to help you improve. Be willing to listen to their concerns and ideas as well. Try to find common ground and work together to come up with a plan for improvement.
Seek support: Sometimes, it can be helpful to seek support from outside sources. This could include talking to a teacher, counselor, or tutor about your struggles and getting their advice on how to improve. You could also consider joining a study group or seeking out other academic resources that can help you succeed in school. By showing your parents that you are taking steps to address the issue, you may be able to ease their concerns and build their trust in you.
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Which of Newton's Three Laws is BEST described by the following statement: A ball dropped from the 10th story of a hotel had more force than when the same ball was dropped from the 5th story of the same hotel
Answer:
I believe the answer is Newton's Second Law
Explanation:
Newton's Second Law states that the acceleration of an object will count on how much mass and the amount of force that is applied.
The bowling ball was dropped from the 10th story window and had more force than when the ball was dropped from the 5th story window because the 10th story window gave the bowling ball more acceleration.
Discuss the importance of Icaming social anthropology for university students
Answer:
what is the importance of anthropology as a student?
Social anthropology plays a central role in an era when global understanding and recognition of diverse ways of seeing the world are of critical social, political and economic importance. Social anthropology uses practical methods to investigate philosophical problems about the nature of human life in society.
Explanation:
The half reaction with a more positive standard reduction potential will
The half reaction with a more positive standard reduction potential will proceed spontaneously in a redox reaction
The half reaction with a more positive standard reduction potential will undergo reduction when compared to the half reaction with a more negative standard reduction potential.
Oxidation-reduction reactions, often known as redox reactions, are a set of chemical reactions that involve electron transfer between reactants. In a redox reaction, one reactant is oxidized, losing electrons, while the other reactant is reduced, gaining electrons.
The oxidation half-reaction is the process of losing electrons and increasing the oxidation number, whereas the reduction half-reaction is the process of gaining electrons and decreasing the oxidation number. The total reaction is referred to as the redox reaction.
Half-reaction:Half-reaction refers to the two parts of an oxidation-reduction reaction that happen separately. A half-reaction must always be either an oxidation reaction or a reduction reaction. It also describes the movement of electrons and hydrogen ions in an equation.
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The following series of reactions were carried out.
PbCO3(s) + 2HNO3(aq) → Pb(NO3)2(aq) + H₂O(1) + CO₂(g)
Pb(NO3)2(aq) + 2HBr(aq) → 2HNO3(aq) + PbBr2(s)
(a) If a student starts with 2.457 g of lead(II) carbonate for the first reaction and all
other reagents are added in excess, what is the theoretical yield of lead(II) bromide
solid?
8. In the nucleus, I tell cells what to do and how to change. 9. The fastest growing organ in humans is the
Answer:
skin is the fastest growing organ in human beings.
Nerve impulses are picked up by a neuron’s:
(1) dendrites
(2) axon
(3) synapse
(4) neurotransmitter
number of particles and moles in CoCl2
In CoCl2, there are:1 mole of Co atoms,2 moles of Cl atoms,6.022 × 10^23 particles in total.
To determine the number of particles and moles in CoCl2 (cobalt(II) chloride), we need to consider Avogadro's number and the formula of the compound.
The formula CoCl2 indicates that there is one cobalt atom (Co) and two chlorine atoms (Cl) in each unit of CoCl2.Avogadro's number states that there are 6.022 × 10^23 particles (atoms, molecules, or ions) in one mole of any substance.
Thus, in one mole of CoCl2, we have:
1 mole of cobalt atoms (Co)
2 moles of chlorine atoms (Cl)
The number of particles in one mole of CoCl2 is 6.022 × 10^23, which includes all the atoms (1 Co and 2 Cl) in that one mole.
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determine the rate law and the value of k for the following reaction using the data provided. 2NO(g) + O2(g) -----> 2NO2
The rate law and the value of k for the given reaction is 1.7×103 M⁻²s⁻¹. Therefore, option D is correct.
What is rate law ?The word "rate law" refers to an expression that expresses reaction rate as the product of the stoichiometric coefficient of the reacting species in a balanced chemical equation multiplied by the molar concentration of the reactants, with each term raised to a power.
\(\rm Rate = k \times [NO]^{n} x [O_{2}]^ {m}\)
Thus, m must = 1
\(\rm Rate\ 1 = k \times [NO 1]^ {m} x [O_{2} 1]^ {n}\\Rate\ 2 = k \time [NO 2]^ {m} x [O_2 2]^ {n}\)
Rearranging this equation
\(Rate1 / [O_2 1]^{n} = k x [NO1]^ {m}Rate2 / [O_2 2]^{n} = k x [NO2]\)
but [NO 1] = [NO 2]
Hence,
\(Rate1 / [O_2 1]^ {n}= Rate2 / [O_2 2]^{n}\)
Rearranging and substituting in the values
\(([O_2 2] / [O_2 1])^{n} = Rate2 / Rate 1\)
\(2^{n} = 2\)
So, n = 1
Same from run 1 to 3
[NO] doubled
[O₂] stayed constant
Rate quadrupled
\((2)^{n} = 4\)
n = 2
we know that rate = k x [NO]² x [O₂]
Substitute in any value for [NO], [O₂] and rate and calculate K
k = rate / [NO]² x [O₂]
= (8.55x10⁻³ M / sec) / ((0.030M)² x (0.0055M))
= 1.7×103 M⁻²s⁻¹
Thus, option D is correct.
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Your question is incomplete, most probably complete question is
Determine the rate law and the value of k for the following reaction using the data provided.
2 NO(g) + O2(g) 2 NO2(g)
[NO]i (M) [O2]i (M) Initial Rate (M-1s-1)
0.030 0.0055 8.55 x 10-3
0.030 0.0110 1.71 x 10-2
0.060 0.0055 3.42 x 10-2
A. Rate = 57 M-1s-1[NO][O2]
B. Rate = 3.8 M-1/2s-1[NO][O2]1/2
C. Rate = 3.1×105 M-3s-1[NO]2[O2]2
D. Rate = 1.7×103 M-2s–1[NO]2[O2]