Microwaves are used for heating because they are able to quickly and evenly heat food items without the need for a physical contact source, like a sand bath.
The microwave uses electromagnetic radiation to excite the water molecules in the food, which then generate heat. This process is much faster and more efficient than heating with a sand bath, as the heat source is more evenly distributed throughout the food item. On the other hand, a sand bath uses conduction to transfer heat, which can be slower and less consistent in comparison. Additionally, microwaves offer more precise temperature control, allowing for specific heating times and power levels to be set for different food items. Overall, the convenience and speed of the microwave make it the preferred method for heating food in most situations.
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why do all stars spend most of their lives on the main sequence?
All stars spend most of their lives on the main sequence is a result of it having enough hydrogen which is an important component and acts as the fuel for energy production used to ensure it remains in the main sequence.
Every star has a lot of hydrogen and which is a vital element every star has lots as it encourages the burning of hydrogen into helium which helps to put the stars in the main sequence during most of their lives.
The mass of the stars is also a determinant factor as the more mass a star the more amount of Hydrogen it uses and the less time it takes to remain in the main sequence.
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angular speed. it rotates at 75 rev/s with the axis of rotation perpendicular to a 1.08 t magnetic field. if there are 1534 turns on the loop, what is the maximum voltage induced in it?
The maximum induced voltage in the loop is found to be 1.25 x 10⁵ V, as it is rotating perpendicular.
The induced voltage is given by the formula,
V = NBAw, where, A is the area, B is the magnetic field, N is the loops in the coil, w is the angular speed. The loop has 1534 turns and rotates at a speed of 75 rev/s with its axis perpendicular to a 1.08T magnetic field.
Putting all the values,
V = 1534 x 1.08 x 1.01 x 75
V = 1.25 x 10⁵ V.
So, the voltage induced in the loop is found to be 1.25 x 10⁵ V.
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Complete question - The loop area of 1.02 m² is rotating with some angular speed. it rotates at 75 rev/s with the axis of rotation perpendicular to a 1.08 t magnetic field. if there are 1534 turns on the loop, what is the maximum voltage induced in it?
WILL PICK BRAINLYEST AND GETS 25 POINTS
Justin is planning his science fair project. He wants to measure how oxygen levels affect the rate of photosynthesis in plants. Is this an example of a scientific investigation or an experiment?
A. An experiment because it tests a cause and effect relationship
B. An experiment because it does not ask a testable question
C. An investigation because it uses only observations
D. An investigation because there is a control group
Answer:
is: B. why ? u ask.... well u forgot one important factor when ansering that factor being that...... H'ES CRACKED AT FORTNITE MY GUY
i desereve bwainweist... JK LOL give it to the other guy.
The given one is an experiment because it tests a cause and effect relationship. The rate of photosynthesis is determined by measuring the concentration of carbon dioxide on an enclosed transparent chamber.
What is photosynthesis ?Photosynthesis is a biochemical process by which green plants synthesis chemical energy with the aid of light energy. The photosynthetic reaction is the combination of carbon dioxide and water to form oxygen molecule and glucose.
The photosynthetic reaction is given here:
\(\rm 6CO_{2} + 6H_{2}O \rightarrow C_{6}H_{12}O_{6} + 6O_{2}\)
Here, the oxygen gas is the product in the reaction. Hence, increase in the oxygen level will reverse the reaction and thus, rate of photosynthesis decreases.
The rate of photosynthesis is determined by the measurement of concentration of carbon dioxide within the closed transparent chamber in which the plant is placed. Hence, we are testing a cause and effect and it is a scientific experiment. Hence, option A is correct.
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a person is on a motoboat that is capable of a maximum speed of 10 km/h in still water, and wishes to cross a 2 km wide river to a point directly across from the starting point. if the speed of the water in the river is 6 km/h, how much time is required for the crossing, assuming the boat is moving at its maximum speed?
An individual on a motorboat with a top speed of 10 km/h wants to travel across a 2 km wide river to a location that is exactly opposite the beginning spot. The time required for crossing the river is approximately 12.4 minutes.
To calculate the time required for crossing the river, we can use the formula:
time = distance/speed
Let's call the speed of the boat in still water "v" and the speed of the river "u". The boat is moving at its maximum speed in still water, so its speed relative to the shore is also "v" km/h.
Now, to cross the river, the boat must move at an angle to the shore to compensate for the sideways drift caused by the river current. We can use trigonometry to determine the composition of the boat's speed in the direction perpendicular to the river, which is the distance that the boat covers while crossing the river.
The component of the boat's speed perpendicular to the river is given by:
v_perp = v * sin(theta)
where theta is the angle between the boat's path and the direction of the current, and sin(theta) is the sine of this angle.
Since the boat is moving at its maximum speed, v = 10 km/h, and the speed of the river is u = 6 km/h, we can use trigonometry to find the angle theta:
sin(theta) = u / v = 6 / 10 = 0.6
theta = sin^-1(0.6) = 36.87 degrees
Now we can find the distance that the boat covers while crossing the river:
distance = 2 km * sin(theta) = 1.2 km
The time required to cover this distance at the boat's maximum speed is:
time = distance / v_perp = 1.2 km / (10 km/h * sin(36.87)) = 0.206 hours
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How does an inclined plane increase force?
Acceleration will increase as the angle of incline does, and as a result, force will as well.
The gravitational force acting on the cart increases as the slope of the incline increases, causing it to accelerate more quickly.The ramp's steepness will cause an increase in inclination. As a result, the acceleration increases as the inclination angle increases. This acceleration causes the object to descend with greater speed.
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Plz don’t send me link over what the answer is just tell me. What force is represented by the vector?
A. friction
B. gravity
C. normal force
D. push
Answer:
B. gravity
Explanation:
The ball if moving down so gravity is acting on it because it is pulling it down to earths toward the center of earth aka the ground.
simplify \frac{2b-5}{b^2-2b-15}-\frac{3b}{b^2+b-30}. state any restrictions on the variables.
To simplify the expression, we need to combine the fractions into a single fraction. To do this, we'll first find a common denominator for the two fractions.
The denominators are (b^2 - 2b - 15) and (b^2 + b - 30). To find the common denominator, we factorize both denominators:
b^2 - 2b - 15 = (b - 5)(b + 3)b^2 + b - 30 = (b - 5)(b + 6)The common denominator is (b - 5)(b + 3)(b + 6).
Now, let's rewrite the fractions with the common denominator:
\frac{2b-5}{b^2-2b-15} - \frac{3b}{b^2+b-30} = \frac{(2b-5)(b+6)}{(b-5)(b+3)(b+6)} - \frac{3b(b+3)}{(b-5)(b+3)(b+6)}Next, we can combine the fractions:
\frac{(2b-5)(b+6) - 3b(b+3)}{(b-5)(b+3)(b+6)}Expanding the numerator and simplifying further:
\frac{2b^2 + 7b - 30 - 3b^2 - 9b}{(b-5)(b+3)(b+6)}Combining like terms in the numerator:
\frac{-b^2 - 2b - 30}{(b-5)(b+3)(b+6)}Finally, we have simplified the expression to:
\frac{-b^2 - 2b - 30}{(b-5)(b+3)(b+6)}Restrictions on the variables:
To find any restrictions on the variables, we need to consider the values that would make the denominator zero. In this case, the denominator is (b - 5)(b + 3)(b + 6). Therefore, the restrictions on the variables are:
b ≠ 5, -3, -6
These values are excluded because they would result in a zero denominator, which would make the expression undefined.
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rocket a passes earth at a speed of 0.70 c. at the same time, rocket b passes earth moving 0.86 c relative to earth in the same direction. how fast is b moving relative to a when it passes a?
Rocket B's speed in relation to rocket A is 0.4c
If the two frames of reference's directions are at odds with one another, the two frames of reference would see the relative speed as the total of their individual speeds. Furthermore, if the motion of the two frames is parallel, relative speed would be seen as the difference between the individual speeds.
The Earth's frame of reference is at rest, but the two rockets passing by are traveling relativistically with respect to Earth.
Since both rockets are moving in the same general direction, rocket B's relative speed to rocket A is equal to the difference between the two rockets' individual speeds.
Speed of rocket A is v = 0.70c
speed of the rocket B is u =0.86c
let,
speed of the rocket B with respect to rocket A is u₁
Now,
u₁ = (u - v) / [(1 - u) * (v / c²)]
u₁ = (0.86 - 0.70) / (1 - 0.86 * 0.70 / c²)
u₁ = 0.16 / (1 - 0.6) = 0.16 / 0.4
∴ u₁ = 0.4c
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What characterizes static stretching? A. having a partner hold limbs in a stretch position B. assuming and holding a stretch position C. bouncing while in a stretch position D. using a tool or object to increase a stretch Please select the best answer from the choices provided. A B C D
Answer:
B.
assuming and holding a stretch position
Explanation:
The characteristics of static stretching is assuming and holding a stretch position.
What is static stretching?Static stretching is a type of stretch exercises in which the person involved is static position and he stretched out.
The person does not move out of his position but the person move his moves as many times as it can without experiencing any pain.
Therefore, The characteristics of static stretching is assuming and holding a stretch position.
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if a truck has 40,00kg*m/s of momentum and is moving with a velocity of 90m/s.what is the trucks mass?
Answer:
mass = 444.44 kg
Explanation:
To calculate the mass of the truck, we can use the formula for momentum:
Momentum (p) = mass (m) × velocity (v)
Given:
Momentum (p) = 40,000 kg·m/s
Velocity (v) = 90 m/s
We can rearrange the formula to solve for mass (m):
m = p / v
Substituting the given values:
m = 40,000 kg·m/s / 90 m/s
m ≈ 444.44 kg
Therefore, the mass of the truck is approximately 444.44 kg.
I need help with this plz help me
Answer:
yes
Explanation:
lick me
G 13% part (g) using the numbers from the previous step, give a numeric answer for the time in seconds that elapse when the package, initially at rest, travels a distance of 2. 25 m down the ramp
The time required for the container to move 2.25 metres down the ramp is roughly 0.104 seconds.
From part (f), we have determined the final velocity of the package to be 1.38 m/s. Using this value along with the distance traveled (Δx = 2.25 m), we can calculate the time elapsed using the kinematic equation:
Δx = (vf² - vi²) / 2a
Substituting the values, we get:
2.25 = (1.38² - 0) / (2 * 0.087)
Solving for time (t), we get:
t = 2.25 * 0.087 / 1.897
t ≈ 0.104 seconds
Therefore, the time elapsed when the package travels a distance of 2.25 m down the ramp is approximately 0.104 seconds.
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I need help with this question someone
The properties of group 18 elements, also referred to as noble gases or group 8 elements.
Eight valence electrons make them up.
They have enough electrons in their octet, therefore they don't need any more (stable).
are steady
Noble gases are those that are not reactive.
Why do elements desire to create ions?In order to gain or lose valence electrons to the element they interact with, elements create ions. They acquire a whole octet as a result. You might be wondering what a whole octet is. When an element contains all 8 valence electrons and is stable, it is said to have an octet, rendering it nonreactive.
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Velocity (m/s)
25
20
15
10
5
0
0
Velocity vs Time
1
2
3
Time (s)
4
5
What is the initial velocity of the object represented by
the graph?
m/s
The object depicted by the graph initially moves at a speed of 25 m/s.
The rate at which the position of an item changes with respect to time is represented by the vector quantity known as velocity. It is calculated by dividing an object's displacement by the time period during which the displacement took place.
Velocity is a phrase used to more simply define the direction and speed of an object's motion. Both the direction and the speed of an object's motion are specified. The International System of Units (SI) uses metres per second (m/s) as the standard unit for measuring velocity.
We must look at the behaviour of the graph before to time 1 second in order to ascertain the initial velocity of the object the graph represents.
From the graph provided,
From the given graph, We can see that from time 0 to time 1 second, the velocity is 25 m/s and stays that way.
As a result, the object's starting velocity is 25 m/s.
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A person runs 2 laps around a 400 meter track and stops where they initially
began running. It took this person 3 minutes and 18 seconds to complete this
run. What is this persons average velocity?
A:4.04 m/s
B:2.02 m/s
c:0 m/s
The runner's total distance covered was 800 meters. Her displacement (straight-line distance between start-point and end-point) was zero.
Her average speed = (distance)/(time) = 4.04 m/s
Her average velocity = (displacement) / (time) = zero (choice - c)
Spherical aberration in the primary mirror of a reflecting telescope is generally avoided by
making the mirror surface a parabolic shape.
a refraction of light by turbulent currents of air of differing densit
rapidly change the tilt and shape of an intermediate mirror.
Spherical aberration in the primary mirror of a reflecting telescope is generally avoided by making the mirror surface a parabolic shape.
Spherical aberration in the primary mirror of a reflecting telescope is a significant issue that can affect image quality. This problem arises when light rays entering the telescope at different distances from the central axis converge at different points, leading to a blurred image. To avoid spherical aberration, telescope designers typically use a parabolic-shaped mirror instead of a spherical one.
A parabolic mirror ensures that all incoming light rays, regardless of their distance from the central axis, converge at a single focal point. This results in a sharp and clear image, free from the distortion caused by spherical aberration. In contrast, using a spherical mirror would cause the light rays to converge at multiple points, leading to a blurry image.
It is important to note that other factors, such as the refraction of light by turbulent currents of air with differing densities, can also cause image distortion. These atmospheric effects, however, are not directly related to the telescope's mirror shape.
In some advanced telescope systems, rapidly changing the tilt and shape of an intermediate mirror can help compensate for atmospheric disturbances. This adaptive optics technique allows for improved image quality by correcting for the atmospheric distortions in real-time. Nevertheless, the primary mirror's parabolic shape remains crucial for avoiding spherical aberration and maintaining optimal image clarity in a reflecting telescope.
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Which mathematically describes the wave properties of electrons?.
Answer:
On Waves. Quantum mechanically, an electron can be described by a wave function oscillating in space and time that has mean values equal to the expectation values of observables corresponding to given operators. ... Electrons are fermions. They are charged particles. in short the quantum theory
i hope its helpful !
a carnot engine operates between reservoirs at 500 k and 300k, discarding 1800 j of heat in each cycle. how much heat is supplied to the engine by the hot reservoir in each cycle? give your answer in j but do not include the units in the answer box.
The Carnot engine is 40% efficient.
It's far a super reversible thermodynamic manner that includes the subsequent 4 tactics, Isothermal growth, No different heating is more efficient than this one, as there may be no finite temperature distinction between the warmth supply and warmth receiver. Therefore, it's miles the most efficient reversible system.
A Carnot engine can be notion of to include a cylinder with adiabatic lateral partitions packed with a substance which can take in and supply warmness. The cylinder is closed by way of an adiabatic piston which could move out and deliver work. The cylinder can acquire paintings by means of shifting the piston inward.
The Carnot engine is a theoretical thermodynamic cycle proposed by means of Leonard Carnot. It estimates the maximum feasible performance that a heat engine all through the conversion manner of warmth into paintings and, conversely, operating among two reservoirs can own.
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explain the dangers of electrostatics
What is true of daylight hours at locations north and south of the equator? Days are longer than nights north of the equator. Nights are longer than days south of the equator. The length of days and nights change with the seasons.
Answer:
The length of days and nights change with the seasons.
Explanation:
Distance from the equator along with the tilt of Earth's rotational axis contributes to day and night period differences. Daylight hours or the period of sunlight exposure vary due to the inclined axis of the latitudes. In the northern hemisphere during summers, the tilt of the axis is towards the sun which brought more sunlight to the exposed region. And therefore the length of day hours is more than the southern hemisphere which at the same time will be tilted away from the sun.
Answer:
pablo
Explanation:
si pablo come tacos con barbacoa
A hockey player, named Brandon Camp, is standing on his skates on a frozen pond when an opposing player, moving with a uniform speed of 4.0 m/s, skates by with the puck. After 1.40 s, Brandon makes up his mind to chase his opponent. Suppose that Brandon starts from rest and accelerates uniformly at 0.44 m/s2 . Assume the player with the puck remains in motion at constant speed. After Brandon starts from rest, it takes the time 19.5 s for Brandon to catch his opponent. How far has Brandon traveled during this time interval
Brandon has traveled approximately 83.79 meters during the time interval.
To find the distance traveled by Brandon during the time interval, we can use the equation of motion: distance = initial velocity × time + 0.5 × acceleration × time^2.
Given:
Initial velocity of Brandon (u) = 0 m/s (starting from rest)
Acceleration of Brandon (a) = 0.44 m/s²
Time taken by Brandon to catch his opponent (t) = 19.5 s
Using the equation: distance = u × t + 0.5 × a × t^2
distance = 0 × 19.5 + 0.5 × 0.44 × (19.5)^2
distance = 0 + 0.5 × 0.44 × 380.25
distance ≈ 83.79 meters
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Suppose an automobile has 2000-joules of kinetic energy. when it moves at twice the speed, what will be its kinetic energy? what's its kinetic energy at three times the speed?
Answer:
K.Eₓ = 4 K.E
K.Eₓ = 9 K.E
Explanation:
Th formula for the kinetic energy of a body is given as follows:
\(K.E = \frac{1}{2}mv^2\\\) ---------------equation (1)
where,
K.E = Kinetic Energy of Automobile
m = mass of automobile
v = speed of automobile
For twice speed:
vₓ = 2v
then,
\(K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(2v)^2\\K.E_{x} = 4\frac{1}{2}mv^2\\\)
using equation (1):
K.Eₓ = 4 K.E
For thrice speed:
vₓ = 3v
then,
\(K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(3v)^2\\K.E_{x} = 9\frac{1}{2}mv^2\\\)
using equation (1):
K.Eₓ = 9 K.E
A. The kinetic energy of automobile when it moves at twice the speed is 8000 J
B. The kinetic energy of automobile when it moves at three times the speed is 18000 J
Let the mass of the automobile be constant.
Let the initial velocity be v
A. Determination of the kinetic energy of the automobile when it moves at twice the speed.
Initial kinetic energy (KE₁) = 2000 JInitial velocity (v₁) = vFinal velocity (v₂) = 2vFinal kinetic energy (KE₂) =?KE₁ /v₁² = KE₂ / v₂²
2000 / v² = KE₂ / (2v)²
2000 / v² = KE₂ / 4v²
Cancel out v²
2000 = KE₂ / 4
Cross multiply
KE₂ = 2000 × 4
KE₂ = 8000 J
B. Determination of the kinetic energy of the automobile when it moves at three times the speed.
Initial kinetic energy (KE₁) = 2000 JInitial velocity (v₁) = vFinal velocity (v₂) = 3vFinal kinetic energy (KE₂) =?KE₁ /v₁² = KE₂ / v₂²
2000 / v² = KE₂ / (3v)²
2000 / v² = KE₂ / 9v²
Cancel out v²
2000 = KE₂ / 9
Cross multiply
KE₂ = 2000 × 9
KE₂ = 18000 J
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1. When does raising the temperature of a gas increase its pressure? when volume is increased and the number of particles is constant when volume is increased and the number of particles is increased when volume and the number of particles are constant
Answer:
when volume and the number of particles are constant
Explanation:
Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Gay Lussac's law is given by;
\( PT = K\)
\( \frac{P1}{T1} = \frac{P_{2}}{T_{2}}\)
The ideal gas law is the equation PV = nRT
Where;
P is the pressure.
V is the volume.
n is the number of moles of substance.
R is the ideal gas constant.
T is the temperature.
Generally, raising the temperature of an ideal gas would increase its pressure when volume and the number of particles are constant.
This ultimately implies that, when volume and the number of particles are held constant, there would be a linear relationship between the temperature and pressure of a gas i.e temperature would be directly proportional to the pressure of the gas. Thus, an increase in the temperature of the gas would cause an increase in the pressure of the gas at constant volume and number of particles.
A system consists of multiple objects connected by ropes. How many equations need to be written to solve this problem?
A) two for each object
B) one or two for each object
C) one for each object
D) two for the system
Answer:
the correct answer is B
Explanation:
To solve the system they must have the same amount of unknowns as equations,
a) If the system does not have friction, we must write the x-axis equation for each body, therefore we need to write N equations
b) if the system has friction, two equations are needed for each particle
therefore the correct answer is B
if you pull the wagon's handle at 30 degrees and the wagon moves at a constant rate, how far can you pull the wagon?
If the rate of pulling the wagon is increased, then the distance will be shortened as the force will be too great for the coefficient of friction to handle.
What is distance?Distance is the measure of how far apart two objects are or how long it would take to travel between them. It is typically measured in terms of length, such as kilometers, meters, miles, feet, yards, or other units of length. Though it can also be measured in terms of time, such as hours, minutes, or seconds. Distance can be calculated using a variety of methods, such as using a ruler, using a map, or using a GPS device. Distance can be used to describe both physical and abstract concepts, such as the distance between two people or the distance between two ideas.
The distance that a wagon can be pulled when its handle is pulled at a 30 degree angle depends on a variety of factors, such as the friction between the wagon and the surface it is being pulled on, the weight of the wagon and the force being applied to the handle. Generally speaking, a heavier wagon will require more force to move it the same distance as a lighter wagon when pulled at the same angle.
In order to determine the distance that a wagon can be pulled at a 30 degree angle, it is necessary to calculate the force being applied to the handle and the coefficient of friction between the wagon and the surface. Once these two values are known, it is possible to calculate the maximum distance that can be traveled by applying the equation distance = force * coefficient of friction * cosine (30 degrees).
It is important to note that the distance will only be the maximum distance that can be traveled if the wagon is being pulled at a constant rate. If the rate of pulling the wagon is increased, then the distance will be shortened as the force will be too great for the coefficient of friction to handle.
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The diagram below shows a 5.0-kilogram bucket of water being swung in a horizontal circle of 0.70-meter radius
at a constant speed of 2.0 meters per second.
5.0-kg Bucket
0.70 m
The magnitude of the centripetal force on the bucket of water is approximately
1) 5.7 N
2) 14 N
3) 29 N
4) 200 N
Answer:
F = 29 N
Explanation:
We have,
Mass of the bucket of water is 5 kg
Radius of a horizontal circle is 0.7 m
Speed of the circle is 2 m/s
It is required to find the magnitude of centripetal force on the bucket of water. The formula used to find the magnitude of centripetal force is given by :
\(F=\dfrac{mv^2}{r}\\\\F=\dfrac{5\times (2)^2}{0.7}\\\\F=28.57\ N\)
or
F = 29 N
So, the centripetal force on the bucket of water is 29 N.
The magnitude of the centripetal force on the bucket of water is approximately 29 N
Definition of centripetal forceCentripetal force is the force that acts to keep an object moving in a circular motion. It is expressed mathematically as:
F = mv² / r
With the above formula, we can obtain the centripetal force acting on the bucket.
How to determine centripetal force•Mass (m) = 5 Kg
•Radius (R) = 0.7 m
•Velocity (v) = 2 m/s
•Centripetal force (F) =?
F = mv² / r
F = (5 × 2²) / 0.7
F = (5 × 4) / 0.7
F = 20 / 0.7
F = 29 N
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social problems obstruct the development of society
Answer:
This leads to backwardness and lagging in the development of the the society. Social problems such as sickness, poverty , social injustices , corruption , nepotism, tribalism are slowing down the process of development .
Mr. Krabs created a secret ingredient for breath mint that he thinks will "cure" the bad breath people
get from eating crabby patties at the Krusty Krab. He asked 100 customers with a history of bad breath
to try his new breath mint. He had fifty customers (Group A) eat a breath mint after they finished
eating a crabby patty. The other fifty (Group B) also received a breath mint after they finished the
sandwich, however, it was just a regular breath mint and did not have the secret ingredient. Both
breath mint that would cure their bad breath. Two hours
groups were told that they were getting the
after eating the crabby patties, thirty customers in Group A and ten customers in Group B reported
having better breath than they normally had after eating crabby patties.
2. What is the independent variable?
3. What is the dependent variable?
4. What should Mr. Krabs' conclusion be?
5. Why do you think 10 people in group B reported fresher breath?
The answers to the following questions are 1. Group B, 2. secret ingredient, 3. bad breath, 4. not effective cent percent, 5. the placebo effect.
1. The group of people who received the normal mint which does not contain Mr. krab's secret ingredient for breath mint is the control group. So, Group B of people are in the control group.
2. Independent variable in the one for which the research is being conducted. So in this case the secret ingredient in the breath mint is the independent variable.
3. Dependent variable is the one that affects the result of the research. So, the bad breath, in this case, is the dependernt variable.
4. The Group A of fifty people received the secret ingredient in breath mint; 30 people it reported better breath. Therefore the mint that has a secret ingredient is successful in reducing the amount of bad breaths in the individual but does not appear to be effective cent percent.
5. The 10 people in group B may have reported fresher breath due to the 'placebo' effect. It is the effect where the physical or mental health of the individual appears to improve after a fake, dummy, or sample treatment is given to him/her.
Therefore, 1. Group B, 2. secret ingredient, 3. bad breath, 4. not effective cent percent, 5. the placebo effect.
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A ball is attached to the end of a string it swung at a vertical circle of three of 0.33M what is the minimum velocity that the ball must have to make it around the circle
Answer:
To make it around the circle, the tension in the string must provide the necessary centripetal force to keep the ball moving in a circle. At the top of the circle, the tension in the string must provide all the force to keep the ball moving in a circle. At the bottom of the circle, the tension in the string must provide the centripetal force in addition to the force of gravity.
We can use the centripetal force formula to solve for the minimum velocity: F_c = m * a_c
where F_c is the centripetal force, m is the mass of the ball, and a_c is the centripetal acceleration.
At the top of the circle, the centripetal force is equal to the tension in the string: F_c = T
where T is the tension in the string.
At the bottom of the circle, the centripetal force is equal to the sum of the tension in the string and the force of gravity:
F_c = T + mg
where m is the mass of the ball, g is the acceleration due to gravity (9.8 m/s^2), and T is the tension in the string.
The centripetal acceleration is given by: a_c = v^2 / r
where v is the velocity of the ball and r is the radius of the circle.
Since the circle has a radius of 0.33 m, we can substitute this into the equation for a_c: a_c = v^2 / 0.33
Combining these equations, we get:
At the top of the circle: T = m * v^2 / 0.33
At the bottom of the circle: T + mg = m * v^2 / 0.33
We can solve for the minimum velocity by using these two equations to eliminate the tension in the string: m * v^2 / 0.33 + mg = m * v^2 / 0.33
Simplifying this equation, we get: v = sqrt(0.33 * g)
Plugging in the values, we get: v = sqrt(0.33 * 9.8) = 1.81 m/s
Therefore, the minimum velocity that the ball must have to make it around the circle is 1.81 m/s
3. Calculate the speed for a car that went a distance of 155 kilometers in 3 hours
Answer:This is an explanation
for 150 km its all ik i tried hard ty
Explanation:The car covers 150 km in 3 hours or 3*60 = 180 minutes.
So in 12 min the car will cover (12/180)*150 = 10 km.
Answer:
The average speed would be the distance covered divided by the time. In this case, (130 km)/(2 hours) = 65 km/hour. Note that you didn't ask for the average speed, just the speed