Answer:The percentage of the work input that becomes work output is the efficiency of a machine. Because there is always some friction, the efficiency of any machine is always less than 100 percent.
Explanation:
Sub to rockingcoolstyle15 on yt
How do home computer scanners generally use electromagnetic waves?
O A. They change information received from sound waves into electromagnetic waves.
OB. They gather information from reflected and absorbed waves.
O C. They receive microwaves that are emitted by natural objects.
O D. They use X-rays that penetrate most objects. SUBMIT
Answer:
they gather information from reflected and absorbed waves.
Explanation:
In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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If a 5-L balloon at 25 degrees celsius were gently heated to 30 degrees celsius, what new volume would the balloon have? Show all work for credi
Answer: 5.08 L.
Explation down below
Understanding how behavior has changed over time to help humans adapt to their environment is known as the __________ approach to psychology.
biological
evolutionary
sociocultural
behavioral
The behavioral approach's main objective is to describe how leaders mix those same two types of actions to influence followers throughout their attempts to achieve those goals.Behaviorism seems to be a teaching strategy, whereas theoretical approaches are concerned with how humans are conditioned just to respond to events as well as stimuli. Several ideas describe how conduct is influenced by experience.
Thus the response above is correct.
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1. Determine the kinetic energy of a 625-kg roller coaster car that is moving with a speed of 18.3 m/s,
Answer:
104653.13J
Explanation:
Given parameters:
Mass of roller coaster = 625kg
Speed = 18.3m/s
Unknown:
Kinetic energy = ?
Solution:
The kinetic energy is the energy due to the motion of a body.
Kinetic energy = \(\frac{1}{2}\) x m x v²
m is the mass
v is the speed
Kinetic energy = \(\frac{1}{2}\) x 625 x 18.3² = 104653.13J
A 45.0-kg girl stands on a 13.0-kg wagon holding two 18.0-kg weights. She throws the weights horizontally off the back of the wagon at a speed of 6.5 m/s relative to herself . Assuming that the wagon was at rest initially, what is the speed of the girl relative to the ground after she throws both weights at the same time
Answer:
v = 4.0 m/s
Explanation:
Assuming no external forces acting during the instant that the girl throws the weights, total momentum must be conserved.Since all the masses at rest initially, the initial momentum must be zero.So, due to momentum must keep constant, final momentum must be zero too, as follows:\(p_{f} = m_{w} * v_{w} + m_{g+w} *v_{g+w} = 0 (1)\)
Assuming the direction towards the back of the wagon as positive, and replacing the masses in (1), we can solve for vg, as follows:\(v_{g+w} =- \frac{m_{w} *v_{w}}{m_{g+w} } = - \frac{36.0kg *6.5m/s}{58.0kg } = -4.0m/s (2)\)
This means that the girl (along with the wagon on she is standing) will move at a speed of 4.0 m/s in an opposite direction to the one she threw the weights.What is the slope of the line that passes through the points (-8, -3)(−8,−3) and (-12, -3) ?(−12,−3)? Write your answer in the simplest form.
single black dude
Notice that both of those points are 3 units below the x-axis. So the line is horizontal ... its slope is zero.
In 1960, the US Navy sent the submersible Trieste to the bottom of the Marianas Trench 11,000m deep. What was the force on the small 15cm diameter circular viewing window?
Answer:
P = d g h pressure = density * g * depth
P = 1000 kg/m^3 * 9.8 m / s^2 * 1.1 * 10E4 m = 1.1 * 10E8 N/m^2
F = P * A = 1.1 * 10E8 N/m^2 * pi * .075^2 / m^2 = 1.9 * 10E6 N/m^2
I’ll give brainliest
The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.
Thus, Waveforms with periodic variations are those that recur consistently at set intervals.
The phrase is typically used in electronics to describe periodically changing voltages, currents, or electromagnetic fields. It is typically used in acoustics to describe constant periodic sounds caused by changes in air pressure or other media.
In these situations, the signal's frequency, amplitude, or phase shift have no bearing on the waveform, which is a characteristic. Additionally, non-periodic signals like chirps and pulses can be referred to by this name.
Thus, The waveform of a signal is the shape of its graph as a function of time in the domains of electronics, acoustics, and allied sciences, regardless of its time and magnitude scales or any shift in time.
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Problem B.2: Escaping a Star (6 Points) It takes many years for a photon produced in a star's centre to reach its surface and escape into space. This is due to its constant interaction with other particles. To estimate the time it takes for a photon to escape a star's interior, we assume that the photon is deflected in equal time intervals into a random direction in a two-dimensional space (i.e., a random walk): At each step i, the photon moves a constant distance in an angle, thus changing its position: cos(4) sin(y) Ai, - c (a) Determine the distance R(n) from the centre (0,0) after n steps.
Answer:
This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.
The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.
The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).
The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:
R(n) = √(X² + Y²)
Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.
However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:
<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2
<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2
Because <X²> = <Y²>, we can write:
<R²> = <X²> + <Y²> = n A²
So, the root mean square distance (the square root of the mean square displacement) after n steps is:
R(n) = √(<R²>) = √(n) * A
Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.
A car starts at a position of 1 km and moves to a final position of -3 km. What is the total distance traveled by the car?
The total distance covered by the car is 4 kilometers, this is because we are taking into account displacement and not just distance.
What is displacement?Displacement is defined as the change in the position of an object while distance is an object's overall movement in a directionless fashion.
There are many different units that can be used to measure distance (inches, feet, miles, kilometers, and centimeters), but the meter is the SI unit. It is a scalar amount because it does not consider
On the number line, we can see the movement as follows
1 0 -1 -2 -3= 4km
Distance is always positive and never gets smaller as you move. Displacement can be negative, positive, or zero because it refers to the change in the position of an object with respect to its original location.
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A liquid x at 25 degree Celsius is poured to a height of 40cm in a capillary tube of length 70cm and the diameter is 1cm .Assume that volume does not change with temperature. A find the initial volume of the liquid in cm^3. B. The temperature is reduced by 10°C causing the liquid to reduce in height to 37cm.Find the volume coefficient of the thermal expansion of the liquid. C. At the initial height of 40cm and temperature of 25°C , what change in temperature is needed for liquid to rise to a height of 49cm.
The initial volume of the liquid is 31.4 cm³. The volume coefficient of thermal expansion of the liquid is 0.002 per degree Celsius. A temperature increase of 109.5°C is needed for the liquid to rise to a height of 49cm.
The initial volume of the liquid can be found using the formula for the volume of a cylinder:
V = πr²h
where r is the radius (half the diameter), h is the height, and π is approximately 3.14. Plugging in the given values, we get:
V = π(0.5 cm)²(40 cm)
V = 31.4 cm³
The volume coefficient of thermal expansion (β) is defined as the fractional change in volume per degree Celsius change in temperature. It can be calculated using the formula:
β = ΔV/(VΔT)
where ΔV is the change in volume, V is the initial volume, and ΔT is the change in temperature. We can rearrange this formula to solve for ΔV:
ΔV = βVΔT
We know that ΔT = -10°C (a decrease of 10°C) and that the height decreased from 40cm to 37cm, or by 3cm. The change in volume can be found using the formula for the volume of a cylinder again, with the new height of 37cm:
ΔV = π(0.5 cm)²(40 cm - 37 cm)
ΔV = 0.59 cm³
Plugging in all the values, we get:
0.59 cm³ = β(31.4 cm³)(-10°C)
β = 0.002
To find the change in temperature needed for the liquid to rise to a height of 49cm, we can use the same formula as before, but solve for ΔT:
ΔT = ΔV/(βV)
We know that ΔV is the difference between the initial volume and the volume at the new height, which is:
ΔV = π(0.5 cm)²(49 cm - 40 cm)
ΔV = 6.86 cm³
Plugging in all the values, we get:
ΔT = 6.86 cm³/(0.002)(31.4 cm³)
ΔT = 109.5°C
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g if the distance between the Earth and the Sun were increased by a factor of 2.87, by what factor would the strength of the force between them change
We have that the the strength of the force between the Sun and the moon is mathematically given as
F2=0.12140F1N
Strength of the ForceQuestion Parameters:
Distance between the Earth and the Sun were increased by a factor of 2.87,
Generally the equation for the Gravitational Force is mathematically given as
\(F=\frac{Gm1m2}{d^2}\\\\Where\\\\f1/f2=d1^2/d2^2\\\\Therefore\\\\F2=\frac{F1*d1}{3.23^2}\\\\F2=\frac{F1*1}{2.87^2}\\\\\)
F2=0.12140F1N
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Nervous tissue is made up of neuroglia and what other type of cell?
neurons
sarcomeres
ovules
stem cells
Answer:
Neurons
Explanation:
A student determines a value for a force using the formula F = k I l.
k is a constant with units of N A-1 m-1
I is current measured in mA
l is length measured in mm
The student uses the numbers directly from each measurement in their calculation.
What will be the units of the force from that calculation?
1 Newton force is equal to the 10⁻⁵ dynes. The unit of force will be dyne and the value of force will be 0.1 dynes.
What is force?
Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body. Force is defined as the product of mass and acceleration.
Its SI unit is Newton, MKS unit is kgm/s² and CGS unit is dyne.
The given formulae are;
F = k I l
k is a constant with unit= N A-1 m-1
I is currently measured in mA = 10⁻³A
l is the length measured in mm= 10⁻³ m
F = k I l
F= N A-1 m-1× 10⁻³A×10⁻³ m
F= 10⁻⁶ N ( 1N = 10⁻⁵ dyne)
F= 0.1 dyne
Hence the unit of force will be dyne and the value of force will be 0.1 dynes.
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water flows into the house by means of pipe.inner diameter 2,4cm
absolute pressure 400kpa
flow rate 6
height 4
upper level inner diameter 1,2cm
calculate pressure at the upper level
The pressure at the upper level of a water flow into the house by means of pipe is 1081 kPa.
How to determine pressure?Calculate the cross-sectional area of the lower pipe:
A₁ = πr₁²
where:
A₁ = cross-sectional area of the lower pipe (m²)
π = mathematical constant (3.14)
r₁ = radius of the lower pipe (m)
A₁ = π(0.12 m)² = 0.0452 m²
Calculate the cross-sectional area of the upper pipe:
A₂ = πr₂²
where:
A₂ = cross-sectional area of the upper pipe (m²)
π = mathematical constant (3.14)
r₂ = radius of the upper pipe (m)
A₂ = π(0.06 m)² = 0.0113 m²
Calculate the flow rate per unit area:
q = Q/A
where:
q = flow rate per unit area (m³/s)
Q = flow rate (m³/s)
A = cross-sectional area (m²)
q = 6 m³/s / 0.0452 m² = 13.28 m²/s
Calculate the velocity of the water in the lower pipe:
v₁ = q/A₁
where:
v₁ = velocity of the water in the lower pipe (m/s)
q = flow rate per unit area (m³/s)
A₁ = cross-sectional area of the lower pipe (m²)
v₁ = 13.28 m²/s / 0.0452 m² = 29.3 m/s
Calculate the velocity of the water in the upper pipe:
v₂ = q/A₂
where:
v₂ = velocity of the water in the upper pipe (m/s)
q = flow rate per unit area (m³/s)
A₂ = cross-sectional area of the upper pipe (m²)
v₂ = 13.28 m²/s / 0.0113 m² = 117.0 m/s
Calculate the head loss:
hL = (v₁² - v2₂²) / 2g
where:
hL = head loss (m)
v₁ = velocity of the water in the lower pipe (m/s)
v₂ = velocity of the water in the upper pipe (m/s)
g = acceleration due to gravity (9.8 m/s²)
hL = (29.3 m/s)² - (117.0 m/s)² / 2(9.8 m/s²) = 23.2 m
Calculate the pressure at the upper level:
p₂ = p₁ + ρghL
where:
p₂ = pressure at the upper level (Pa)
p₁ = pressure at the lower level (Pa)
ρ = density of water (1000 kg/m³)
g = acceleration due to gravity (9.8 m/s²)
hL = head loss (m)
p₂ = 400 kPa + 1000 kg/m³(9.8 m/s²)(23.2 m) = 1081 kPa
Therefore, the pressure at the upper level is 1081 kPa.
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can someone help im not sure of my answer
Answer:
Yes
Explanation:
But I feel also 2 is correct but your answer is right
An object has mass M (uppercase) and is located at the origin of the coordinate system. A second object has mass m (lowercase) and is located at a distance r from the origin. This exercise explores the potential energy of the two-mass system. A spherical coordinate system is appropriate, but only the radial direction, r^, needs to be considered.
Enter a vector expression for the force, F⃗ , acting on mass m . The expression must be valid for all values of the radial coordinate, 0 0, and the zero of potential energy is taken as limr→∞UG=0.
Mass of the second object located at a distance r from the origin, r^ is the unit vector in the radial direction, and the negative sign indicates that the force
What is a system ?The System can refer to a set of interacting or interdependent components forming an integrated whole. The term can be applied to various fields, including physics, engineering, biology, and social sciences, among others. In physics, a system typically refers to a collection of objects or particles that are studied together, often with the goal of understanding the behavior of the system as a whole. In engineering, a system can refer to a group of components that work together to perform a specific function, such as an electrical power grid or an automobile engine. In biology, a system can refer to an organism or group of organisms that interact with their environment, such as an ecosystem or the human body.
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A spectral line is emitted when an atom undergoes transition between two levels with a difference in energy of 2.4eV. What is the wavelength of the line?
Given:
The energy difference, E=2.4 eV
To find:
The wavelength of the emitted line.
Explanation:
The energy of the wave emitted will be equal to the energy difference between the two energy levels.
The energy of the wave is given by the equation,
\(E=\frac{hc}{\lambda}\)Where h is the Plank's constant and c is the speed of light.
The energy in joules is given by,
\(\begin{gathered} E=2.4\times1.6\times10^{-19} \\ =3.84\times10^{-19}\text{ J} \end{gathered}\)On substituting the known values in the equation of the energy,
\(\begin{gathered} 3.84\times10^{-19}=\frac{6.626\times10^{-34}\times3\times10^8}{\lambda} \\ \implies\lambda=\frac{6.626\times10^{-34}\times3\times10^8}{3.84\times10^{-19}} \\ =517.7\times10^{-9}\text{ m} \\ =517.7\text{ nm} \end{gathered}\)Final answer:
Thus the wavelength of the line is 517.7 nm
A body is projected down at an angle of 30° with the horizontal
from the top, of a building 170m high. Its initial speed is 40m/s .
How long will it take before striking the ground.
Answer:
It will take 15 seconds
A hollow glass sphere has a density of 1.3g/cm at 20 C. Glycerine has a density of 1.26 g/cm at 20 C. At what temperature would the sphere begin to float in glycerine
A hollow glass sphere has a density of 1.3g/cm at 20 C. Glycerine has a density of 1.26 g/cm at 20 C.
To determine the temperature at which the hollow glass sphere begins to float in glycerine, we need to calculate the density of glycerine at various temperatures and compare it to the density of the glass sphere.
The density of glycerine changes with temperature, so we need to use a density-temperature chart or equation to determine the density of glycerine at different temperatures.
Assuming the hollow glass sphere has a uniform wall thickness, we can calculate its volume by subtracting the volume of the hollow interior from the volume of the whole sphere
Volume of sphere = (4/3)π\(r^{3}\)
Volume of hollow interior = (4/3)π\((r-t)^{3}\)
Volume of glass wall = (4/3)π(\(r^{3}\) - \((r-t)^{3}\)), where t is the thickness of the glass wall.
From the density and volume of the glass sphere, we can determine its mass
Mass of glass sphere = Density of glass sphere x Volume of glass sphere
Next, we can use Archimedes' principle to determine the volume of glycerine displaced by the glass sphere when it is submerged in the glycerine
Volume of glycerine displaced = Mass of glass sphere / Density of glycerine at the given temperature
When the glass sphere floats, the volume of glycerine displaced will be equal to the volume of the glass sphere. Thus, we can set the two volumes equal to each other and solve for the temperature at which the density of glycerine matches the density of the glass sphere
Volume of glass sphere = Volume of glycerine displaced
(4/3)π\(r^{3}\) - (4/3)π\((r-t)^{3}\) = Mass of glass sphere / Density of glycerine at the given temperature
Hence, for the temperature requires knowing the radius and thickness of the glass sphere and the mass of the sphere.
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On a warm summer day, a large mass of air (atmospheric pressure 1.01×105Pa) is heated by the ground to a temperature of 25.0 ∘C and then begins to rise through the cooler surrounding air. Calculate the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×104 Pa. Assume that air is an ideal gas, with γ=1.40. (This rate of cooling for dry, rising air, corresponding to roughly 1 ∘C per 100 m of altitude, is called the dry adiabatic lapse rate.)
The temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.
Using the ideal gas law, we can write: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. Since the mass of air is not changing, we can write: PV = constant.
Applying this to the situation where the air mass rises to a level where the pressure is 8.70×10⁴ Pa, we get:
(1.01×10⁵ Pa)×V = (nR/T1)×T1(8.70×10⁴ Pa)×V = (nR/T2)×T2Dividing the second equation by the first and using the fact that γ=Cp/Cv=1.40 for air, we get:
(T2/T1) = [(P2/P1)^(γ-1)/γ] = [(8.70×10⁴ Pa)/(1.01×10⁵ Pa)]^(1.4/1.4) = 0.813Solving for T2, we get:
T2 = T1×(P2/P1)^(γ-1)/γ = (25+273) K×0.813 ≈ 287.3 K ≈ 14.3°CThus, the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.
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A woman holds a frozen smoothie in her hand on a warm
day.
Which photo shows the direction of thermal energy transfer?
O A.↕️
B
C ⬆️
D⬇️
Answer:
C
Explanation:
The thermal energy from her hand will go up into the smoothie.
Answer:
C bois
Explanation:
A soccer ball accelerated at a rate of 500(m)/(s^(2)) when it was kicked by a player. The soccer ball had a mass of 0.5kg, and it reached a speed of 40(m)/(s). During this acceleration, what was the net force applied on the soccer ball to the nearest newton? [8.2E] Enter your answer in the space.
Net force applied on the soccer ball was approximately 250 N (newtons) when it was kicked by the player.
What is Newton's second law of motion?We use Newton's second law of motion, which states that net force (F_net) applied to an object is equal to the product of its mass (m) and acceleration (a):
F_net = m * a
In this case, mass of the soccer ball is given as 0.5 kg and the acceleration is 500 (m)/(s²), so:
F_net = 0.5 kg * 500 (m)/(s²) = 250 N
Therefore, net force applied on the soccer ball was approximately 250 N (newtons) when it was kicked by the player.
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Scott drives a jeep 12 km east, then 4 km north, then finally 3 km west. He traveled a total distance of:
Answer:
Using the pythagoras theorem
S²=9²+4²
S²=81+16
S²=97
S=9.85km.
In finding the direction
tan□=opposite/Adjacent
=4/9
□=23.96
¤=90-23.96
=66.03 degrees
9.85, N 66.03 E
A. Organized process to test a hypothesis
B. An educated guess about the solution to a problem
C. Observations & measurements recorded
D. A summary based on the results of an experiment
E. The response that is measured in an experiment
F. The factor that is manipulated during an experiment
The scientific method include Observations >> Data; Factor manipulated >> Independent Variable, process to test >> experiment, guess >> hypothesis, results >> Conclusion and response >> dependent variable.
What is an observation in science?Observation is the first step of the scientific method, which then requires to raise a question that will be answered by a testable hypothesis.
The scientific method is a series of well-established steps used to collect scientific empirical data/evidence, which allow to test a given hypothesis.
In conclusion, the scientific method include Observations >> Data; Factor manipulated >> Independent Variable, process to test >> experiment, guess >> hypothesis, results >> Conclusion and response >> dependent variable..
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Slogan for clinical psychologist
An object A is placed 12cm in front of a concave mirror M₁ of focal length 8cm and a plane mirror M₂ is placed 30cm in front of the concave mirror as shown in Figure 1 The object A is first reflected by M₁and then reflected by M₂ to get an image 1₂. What is the distance between 1₂ and the object A?
According to the question the distance between the object A and the image 1₂ is 6 cm.
What is distance?Distance is the measure of how far apart two objects, points, or locations are from one another. Distance can be measured in linear units such as feet, meters, or kilometers, or angular units such as degrees. The concept of distance is a fundamental concept in mathematics, physics, and other sciences. Distance is used to calculate the speed and velocity of objects, as well as the force of gravity between two objects.
The distance between the object A and the image 1₂ can be calculated using the mirror equation.
Mirror equation: 1/d₁ + 1/d₂ = 1/f
Where d₁ is the object distance, d₂ is the image distance, and f is the focal length of the mirror.
In this case, d₁ = 12 cm, d₂ = ? and f = 8 cm.
Substituting these values into the equation gives us:
1/12 + 1/d₂ = 1/8
Rearranging the equation gives us:
1/d₂ = 1/8 – 1/12
Plugging in the values gives us:
1/d₂ = 1/8 – 1/12 = 1/6
Solving for d₂ gives us:
d₂ = 6 cm
Therefore, the distance between the object A and the image 1₂ is 6 cm.
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Science has been wrong in the past. For example, we now know that the original models of the atom were not fully correct. In response to this, a friend tells you, "Science cannot be trusted. Don't believe anything a scientist says." What is your response to this statement? (For full credit, you need to write at least a full sentence explanation"
Although it is true that scientific models and hypotheses have been updated and improved over time, this is not sufficient justification to reject science as a whole or to doubt what scientists claim.
Given that we are aware of their limitations, why do scientists continue to employ atomic model simulations?Models aid in our comprehension of systems and their characteristics. An atomic model, for instance, depicts what an atom's structure may like based on what is known about how atoms function. It may not accurately represent the precise makeup of an atom. Models are frequently condensed.
Why do scientific theories alter over time, including the atomic model?Over time, this atomic model has evolved. The model was used by scientists to make predictions. Their trials occasionally yielded unexpected outcomes that did not match the pre-existing model. The model was modified by scientists so that it could account for the fresh data.
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Water at 100 is taken off the stove and allowed to cool for 10 minutes. In this 10 minutes, the temperature decreased to 65. Given that the room temperature is 21, find the temperature of the water in degrees Celsius after an additional 5 minutes waiting time and on condition that the Newton’s Law of cooling is not violated.
Newton's Law of Cooling states that the rate of cooling of an object is proportional to the temperature difference between the object and its surroundings.
The rate of cooling of the water can be described as:dQ/dt = -k(T - Troom)
where Q is the amount of heat in the water, t is time, k is a constant, T is the temperature of the water, and Troom is the room temperature.
Using the given information, we can set up the following system of equations:
100 = k(100 - 21) (at t = 0) 65 = k(100 - 21) e⁽⁻¹⁰⁾k (at t = 10)
Solving for k in the first equation gives k = 1/79. Plugging this value into the second equation and solving for T gives T = 36.1 degrees Celsius.
Now, to find the temperature after an additional 5 minutes, we can use the same equation with a new time value:
T = (65 - Troom) e^(-k(10+5)) + Troom
Plugging in the values we know gives T = 30.4 degrees Celsius.
Therefore, the temperature of the water after an additional 5 minutes of cooling is approximately 30.4 degrees Celsius
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