why does sound energy even exist

Answers

Answer 1
So you can hear stuff

Related Questions

please help science .

please help science .

Answers

Answer:

I think it's shape the shape of the samples

Which of the following is an example of predation?

Which of the following is an example of predation?

Answers

A. Owl is looking and attacking

Answer:

an owl hunts, catches, and consumes a field mouse for energy

Explanation:

A uniform 1200 N piece of medical apparatus that is 3.5 m long is suspended horizontally by two vertical wires at its ends. A small but dense 550 N weight is placed on the apparatus 2.0 m from one end, as shown in the figure. What are the tensions, A and B, in the two wires?

Answers

To determine the tensions in the two wires suspending the medical apparatus, we can analyze the forces acting on it.

Let's consider the apparatus to be divided into two sections: Section A (with length 2.0 m) and Section B (with length 1.5 m, which is the remaining length).

In Section A:
- The weight of the apparatus (1200 N) exerts a downward force at the center of gravity, which is 1.0 m from each end of Section A.
- The small weight (550 N) is placed 2.0 m from one end, which means it exerts a downward force 2.0 m from the same end.

In Section B:
- Only the weight of the apparatus (1200 N) exerts a downward force at the center of gravity, which is at the midpoint of Section B (0.75 m from each end).

Considering equilibrium, the sum of the clockwise moments (due to the forces) should be equal to the sum of the counterclockwise moments.

Let's calculate the tensions in the wires. Let T_A represent the tension in wire A and T_B represent the tension in wire B.

Clockwise moments (due to the forces):
- Weight of the apparatus in Section A: 1200 N * (2.0 m) = 2400 N·m
- Small weight in Section A: 550 N * (2.0 m) = 1100 N·m

Counterclockwise moments:
- Weight of the apparatus in Section B: 1200 N * (0.75 m) = 900 N·m

For equilibrium, the clockwise moments should be equal to the counterclockwise moments:
2400 N·m + 1100 N·m = 900 N·m

To find the tensions in the wires, we can consider the vertical forces:
In the vertical direction:
T_A + T_B = weight of the apparatus (1200 N) + small weight (550 N) = 1750 N

Now we have two equations:
T_A + T_B = 1750 N
T_B = 1750 N - T_A

Substituting the value of T_B in the clockwise moments equation:
2400 N·m + 1100 N·m = 900 N·m + T_A * (3.5 m)

Simplifying the equation:
3500 N·m = 900 N·m + T_A * (3.5 m)

Rearranging the equation to solve for T_A:
T_A * (3.5 m) = 3500 N·m - 900 N·m
T_A * (3.5 m) = 2600 N·m
T_A = 2600 N·m / (3.5 m)
T_A ≈ 742.86 N

Now, substituting the value of T_A in the equation T_A + T_B = 1750 N:
742.86 N + T_B = 1750 N
T_B = 1750 N - 742.86 N
T_B ≈ 1007.14 N

Therefore, the tension in wire A (T_A) is approximately 742.86 N, and the tension in wire B (T_B) is approximately 1007.14 N.

when a constant force is applied to an object the acceleration of the object varies inversely with its mass. when a certain constant force acts upon an object with mass 4kg, the acceleration of the object is 17m/s^2. when the same force acts upon another object, its acceleration is 2m/s^2. what is the mass of this object?​

Answers

The mass of the the object, given that the same force acted upon it to accelerate at 2 m/s² is 34 Kg

How to determine the mass of the object

First, we shall determine the force. This can be obtained as follow:

Mass (a) = 4 KgAcceleration (a) = 17 m/s²Force (F) =?

Force (F) = mass (m) × acceleration (a)

Force = 4 × 17

Force = 68 N

Finally, we shall determine the mass of the object that will accelerate at 2 m/s² when the force of 68 N is applied to it. Details below:

Acceleration (a) = 2 m/s²Force (F) = 68 NMass (m) = ?

Force = mass × acceleration

68 = mass × 2

Divide both sides by 2

Mass = 68 / 2

Mass = 34 Kg

Thus, from the above calculation, we can conclude that the mass is 34 Kg

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A ball is thrown with an initial velocity of 10 m/s at an angle of 30 degrees with respect to the horizontal. Calculate the horizontal and vertical components of the ball's initial velocity. Using equations of uniformly accelerated motion, calculate the maximum height reached by the ball and the time it takes to reach the ground. Finally, calculate the maximum range of the ball, that is, the horizontal distance traveled before hitting the ground.

Answers

Answer:

=55.21 is the answer.........

A ball is thrown with an initial velocity of 10 m/s at an angle of 30 degrees with respect to the horizontal.

Describe how to demonstrate the thermal energy is dissipated from a cup of hot tea

Answers

Answer:

Explanation:

1. Place a cup of hot tea on a flat surface.

2. Place a thermometer in the tea and record the temperature.

3. Place a fan in front of the cup of tea and turn it on.

4. Place the thermometer in the tea again and record the temperature.

5. Compare the two temperatures and observe the difference.

6. The difference in temperature is an indication of the thermal energy that has been dissipated from the cup of hot tea.

how are characteristics of electromagnetic waves affected by medium

Answers

Answer:

Hello,

QUESTION)

Light is an electromagnetic wave, its speed is maximum in space and almost in the air where interactions have almost no effect. In other non-opaque media, light is subject to several phenomena: refraction and reflection. Part of the incident ray will be reflected in the same medium while the other part will be refracted in the new medium with a lower speed. In general, the medium influences the speed, and therefore the wavelength.  

how are characteristics of electromagnetic waves affected by medium

Two charged particles are near each other – the charge magnitudes are +3 uC and +7 uC, respectively. The electrostatic force between these charges is 25 N. A charged particle of -1 uC is added to both of the original two charges. What is the electrostatic force between the two charged particles after the -1 uC charge is added?

Answers

Answer:

Approximately \(14\; {\rm N}\).

Explanation:

By Coulomb's Law, the magnitude of the electrostatic force between two charges is proportional to the product of the magnitudes of the two charges.

For example, consider charges of magnitude \(q_{1}\) and \(q_{2}\) that are apart from one another by a distance of \(r\) in between. Let \(k\) denote Coulomb's constant. By Coulomb's Law, the magnitude of electrostatic force between the two charges would be:

\(\displaystyle F = \frac{k\, q_{1}\, q_{2}}{r^{2}}\).

In this question, the product of the magnitude of the two charges was originally \(3\; {\rm \mu C} \times 7\; {\rm \mu C} = 21\; {\rm (\mu C)^{2}}\). After \((-1\; {\rm \mu C})\) is added to each charge, product of the magnitude of the two charges would become \((3 - 1)\; {\rm \mu C} \times (7 - 1)\; {\rm \mu C} = 12\; {\rm (\mu C)^{2}}\).

Thus, the product of the magnitude of the two charges has been scaled to \(12\; {\rm \mu C}\) from \(21\; {\rm \mu C}\) . The magnitude of the electrostatic force between the two charges would be scaled from \(25\; {\rm N}\) to \(25\; {\rm N} \times (12 / 21) \approx 14\; {\rm N}\).

An equipotential surface that surrounds a point charge q has a potential of 536 V and an area of 1.20 m2. Determine q.

Answers

Answer:

q = 1.84×10^-8coulombs

Explanation:

Surface area = 4πr²

r is the distance

1.2 = 4(3.14)r²

1.2 = 12.56r²

r² = 1.2/12.56

r² = 0.0956

r = √0.0956

r = 0.309m

Get the charge C

V = kq/r

536 = 9.0×10^9q/0.309

536×0.309 = 9×10^9q

165.73 = 9×10^9q.

q = 165.73/9×10^9

q = 1.84×10^-8coulombs

A mineral oil has a density of 0.875 g/cm3. Suppose you spread 0.60 g of this oil over the surface of water in a large dish with an inner diameter of 21.6 cm. How thick is the oil layer

Answers

With a density of 0.875 g/cm³, a sample of 0.60 g of this oil would have a volume V such that

0.875 g/cm³ = (0.60 g)/V   ==>   V ≈ 0.686 cm³

If the oil is spread out uniformly over the water's surface, then it forms a cylinder whose diameter is equal to that of the dish, 21.6 cm. Then the thickness d of the oil cylinder is such that

V = π ((21.6 cm)/2)² d   ==>   d0.0202 cm

A scientist wants to know if adults prefer watching movies in a theater or in their home. He interviews 500 people leaving a local movie theater and finds that 480 of them like watching movies in theaters. The scientist concludes that 96 percent of people like watching movies in theaters more than at home. Why is the scientist's conclusion most likely unreliable?
Not enough people were interviewed.
The investigation was based on preferences.
The investigation was not replicable.
The location of the survey introduced bias

Answers

Answer:

The location of the survey is biased.

Explanation:

If someone left a movie theater, it is most likely because he likes watching movies there. A better place to interview would be on the streets, as it’s less biased there

Answer:

It will be D/ The location of the survey introduced bias!

Explanation:

why was bowling one of the first racially integrated sports

Answers

Answer:

bowling was one of the first racially integrated sports because bowling alleys were primarily located in urban areas. Racial integration was inevitable since it was promoted by US Armed Forces during 1940s and its image as sport for the common man made it a choice of activity for Americans!!

Explanation:

How much heat has to be added to 1 gallon of water to raise the temperature from
68F to 40C?

Answers

Answer:

The heat needed to raise the temperature of 1 gallon of water from 68°F to 40°C is approximately 28,265 Joules.

Explanation:

A loaded tractor-trailer with a total mass of 4800 kg
traveling at 3.2 km/h
hits a loading dock and comes to a stop in 0.60 s

Answers

7120 N  is the magnitude of average force exerted on the truck by the dock.

What in physics is magnitude?

Magnitude is essentially "distance or amount" in the perspective of physics. In terms of motion, it shows the absolute or relative volume, direction, or movement of an item. It is used to describe there is something size or scope. Magnitude in physics often refers to a quantity.

The impulse-momentum theorem can be used to resolve this issue:

Pinitial = m*Vinitial

where Vinitial is the initial velocity and m is the truck's mass. We may convert the speed to m/s as follows:

Vinitial = 3.2 km/h * 1000 m/km / 3600 s/h = 0.89 m/s

So,

Pinitial = 4800 kg * 0.89 m/s = 4272 kg m/s

The truck's final momentum is:

Pfinal = m*Vfinal

where Vfinal represents the final velocity, which is 0 m/s as a result of the vehicle stopping.

So,

Pfinal = 4800 kg * 0 m/s = 0 kg m/s

Δp = Pfinal - Pinitial = -4272 kg m/s

The change in momentum is equal to the impulse on the truck, so:

Impulse = Δp = -4272 kg m/s

The average force times the time period is also equivalent to the impulse:

Impulse = Favg * Δt

where Δt is the length of time (0.60 s) during which the force is delivered.

So,

Favg = Impulse / Δt = (-4272 kg m/s) / (0.60 s) = -7120 N

The negative sign denotes a stopping force, which is a force acting in the opposite direction of the truck's velocity.

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The complete question is -

A loaded tractor-trailer with a total mass of 4800 kg traveling at 3.2 km/h hits a loading dock and comes to a stop in 0.60 s. What is the magnitude of average force exerted on the truck by the dock ?

Two girls are standing on a rollerskates holding a basketball. One girl throws the ball to the other. Explain what happens to the girls with references to newton's third law of motion

Answers

Answer:

Pretty sure that the they both go backwards because of the basketballs motion

Answer:

One girl had thrown a ball to other girl . Since , she must have an exerted a force on ball in order to throw it to other girl, that ball will exert an equal and opposite force on the other girl according to newton's law which states every action have equal and opposite reaction .In result of what other girl felt an force .

What is Newtons law of motion ?

Newtons law of motion states that every action have an equal and opposite reaction. If an object A exert a force on object B must exert a force of equal magnitude and opposite direction back on object A .

In question it is said that ,one girl had thrown a ball to other girl . Since , she must have an exerted a force on ball in order to throw it to other girl, that ball will exert an equal and opposite force (because of newton's law ) on the other girl .In result of what other girl fell an force .

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mechanical energy defintion

Answers

Answer:   Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.

(The energy acquired by the objects upon which work is done)

How many magnetic pole reversals has Earth endured in the last 265 million years if the average time between reversals is 700,000 years?

Answers

Explanation:

265 000 000 yrs /  700 000 yrs/reversal = 378.6 reversals

                                                            (round as appropriate)

A 1200 kg car moving +13.7 m/s makes
an elastic collision with a 3200 kg truck,
initially at rest. What is the velocity of the
car after the collision?
(Unit = m/s)
Remember: right is +, left is -

Answers

When a car collides with another object, the total momentum of the system before and after the collision must be conserved. Momentum, on the other hand, is a product of mass and velocity. To find the velocity of a car after a collision, we must first consider the initial momentum of the system before the collision and compare it to the final momentum after the collision.

The total momentum of the system before the collision is calculated as follows:P_initial = m_car x v_carP_initial = 1200 kg x 13.7 m/sP_initial = 16,440 kg*m/s Since the two cars stick together after the collision, their final velocity is the same. Let's suppose the final velocity of the cars after the collision is v_f. Then:P_final = (m_car + m_obstacle) x v_fwhere m_obstacle is the mass of the object the car collided with. Because the car is at rest after the collision, we can assume that the velocity of the object it collided with is zero. Therefore:P_final = m_car x v_fP_final = 1200 kg x v_fThe momentum of the system after the collision must be equal to the momentum of the system before the collision. That means:P_initial = P_final16,440 kg*m/s = 1200 kg x v_fv_f = 13.7 m/s - (16,440 kg*m/s / 1200 kg) v_f = 13.7 m/s - 13.7 m/s v_f = 0 m/sTherefore, the car will come to a stop after the collision.

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a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!​

Answers

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Which of the following X-Y tables agrees with
the information in this problem?
A)
Vi
Vf
a
ΔΧ
t
A plane is flying east at 115 m/s. The wind
accelerates it at 2.88 m/s² directly northwest.
After 25.0 s, what is the velocity of the plane?
X
115
?
Y
115
?
88 2.88
2.88
25
25
B) X
V₁
Vf
a 2.04 2.04
ΔΧ
t
Y C) X
V₁ 115
V₁
?
0115
25
25
a -2.04
ΔΧ
t
25
Y
0
?
2.04
25

Which of the following X-Y tables agrees withthe information in this problem?A)ViVfatA plane is flying

Answers

Table A agrees with the information in the problem. After 25.0 seconds, the velocity of the plane is 187 m/s.

Based on the given problem, we need to determine the velocity of a plane after 25.0 seconds. The plane is initially flying east at a velocity of 115 m/s, and it experiences an acceleration of 2.88 m/s² in the northwest direction.

Let's analyze each option and calculate the final velocity (Vf) of the plane after 25.0 seconds:

Option A:

Vi = 115 m/s

a = 2.88 m/s²

t = 25.0 s

Using the equation Vf = Vi + at, we can calculate:

Vf = 115 m/s + (2.88 m/s²)(25.0 s) = 115 m/s + 72 m/s = 187 m/s

Option B:

V₁ = 2.04 m/s

a = 2.04 m/s²

t = 25.0 s

Using the equation Vf = V₁ + at, we can calculate:

Vf = 2.04 m/s + (2.04 m/s²)(25.0 s) = 2.04 m/s + 51 m/s = 53.04 m/s

Option C:

V₁ = 115 m/s

a = -2.04 m/s²

t = 25.0 s

Using the equation Vf = V₁ + at, we can calculate:

Vf = 115 m/s + (-2.04 m/s²)(25.0 s) = 115 m/s - 51 m/s = 64 m/s

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If a electrician measures the current of a circuit to be 100 Amps and the circuit is only designed to have a current of 80 Amps, which of the following is the best explanation of what has happened to the circuit ?

A. a There are too many batteries in the circuit.
B. There are too many resistors in the circuit.
C. A battery in the circuit is missing.
D. A resistor in the circuit is missing.

Answers

There are too many batteries in the circuit, which increased the emf of the circuit and in turn increased the current in the circuit.

Current in the circuit

The current in the circuit is determined by applying Ohms law as shown below;

V = IR

where;

I is the currentV is the voltageR is the resistance

I = V/R

At a constant resistance of the circuit, the current in a circuit will increase when the emf of the circuit increases.

Thus, we can conclude that, there are too many batteries in the circuit, which increased the emf of the circuit and in turn increased the current in the circuit.

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What is the maximum speed at which a car can round a curve?

Answers

Answer:

36 kmp or 22.37 mph

An automobile is traveling on a long, straight highway at a steady 80.0 mi/h when the driver sees a wreck 190 m ahead. At that instant, she applies the brakes (ignore reaction time). Between her and the wreck are two different surfaces. First there is 100 m of ice, where the deceleration is only 1.20 m/s2 . From then on, it is dry concrete, where the deceleration is a more normal 6.80 m/s2 .

a) What was the car’s speed just after leaving the icy portion of the road?
b)What is the total distance her car travels before it comes to a stop?
c)What is the total time it took the car to stop?

Answers

Answer:

a) The car’s speed just after leaving the icy portion of the road is the first part

Explanation:

Calculate the molar heat capacity at pressure and volume constant ( ) when knowing = = 1.4 and the gas density: 0 = 1.3 /3 .

Answers

(a) The molar heat capacity at pressure is 29.1 J/K.mol.

(b) The molar heat capacity at volume is 20.785 J/K.mol.

Molar heat capacity of gas at volume

Molar heat capacity of a gas at constant volume is defined as the quantity of heat required to raise the temperature of one mole of the gas by 1 degree Kelvin when its volume is constant.

Cv = R/(γ - 1)

where;

R is universal gas constant = 8.314 J/K.mol.γ is heat ratio = 1.4

Cv = (8.314) / (1.4 - 1)

Cv = 20.785 J/K.mol

Molar heat capacity of gas at pressure

Molar heat capacity of a gas at constant volume is defined as the quantity of heat required to raise the temperature of one mole of the gas by 1 degree Kelvin when its pressure is constant.

γ = Cp/Cv

Cp = γCv

Cp = 1.4 x 20.785

Cp = 29.1 J/K.mol

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before leaving earth, the mass if an astronaut is measured to be 60kg. the astronaut lands on the moon and measures the acceleration of gravity to be 1.6 m/s^2. what is the mass of the astronaut at moon?​

Answers

Answer:

The answer is 2,475$+948= add you will get the answer rn

The weight we experience on a surface is the product of our mass and acceleration due to gravity on that surface. The mass of the astronaut in earth was 60 kg . Then his mass at moon will be 9.76 kg.

What is gravitational force ?

The gravitational force is the force by which an object attracts other objects into its center of mass. Earth attracts every objects into its center. That why we are all standing on the ground.

The weight we experience on earth is due to the gravity. That is the product of mass and acceleration due to gravity of a planet is the weight on the planet.

The weight of astronaut in earth = 60 kg

acceleration due to gravity on earth = 9.8 m/s²

mass = 60/9.8 m/s² = 6.19 kg

Acceleration due gravity on moon = 1.6 m/s²

then weight on moon = 1.6 m/s² ×6.19 kg = 9.7 kg.

Therefore, the weight of the astronaut in moon will be 9.7 kg.

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Question 1

Describe the path light takes as it travels through air and into glass

Question 2

Explain the brightness of light using the wave model of light

Answers

Answer:

here is answer!

Explanation:

Question 1:

Light bends when it transitions from air to glass due to differences in refractive indices. It follows an incident path in air, refracts at the air-glass boundary, and continues through the glass as a transmitted ray. Total internal reflection may occur if the angle of incidence is large enough.

Question 2:

Brightness in the wave model of light is determined by the amplitude and intensity of the light waves. Higher amplitudes and intensities correspond to brighter light. When multiple light waves overlap, their amplitudes add up, resulting in increased brightness

Question 1 :
The path light bends as it travels through air and into glass.
What is light?
The light is the ray form of energy obtained from the Sun.
The path of light will look like bended when it has crossed the interface of two medium.
As. the light ray falls on the surface of glass travelling through air, the ray appears to bend after refraction.
Thus, the path of light bends as it travels through air and into glass.
———————
Question 2 :
According to the wave theory of light, the energy of radiation depends only on the intensity or wave amplitude (brightness), not the frequency (what type of light; e.g red light or green light; visible light or gamma) According to the particle theory of light states the energy of radiation depend only on the frequency

to measure the static friction coefficient between a block and a vertical wall, a spring is attached to the block, is pushed on the end in a direction perpendicular to the wall until the block does not slip downward. If the spring is compressed, what is the coefficient of static friction

Answers

Answer:

μ = mg/kx

Explanation:

Since the bock does not slip, the frictional force equals the weight of the block. So, F = mg. Now, the frictional force, F = μN where μ = coefficient of static friction and N = Normal force.

Now, the normal force equals the spring force F' = kx where k = spring constant and x = compression of spring.

N = F' = kx

So, F = μN = μkx

μkx = mg

So, μ = mg/kx

1. What is the function of a lightning rod?
2. How is charge build-up reduced on airplanes?
3. Why is a ground strap a necessary safety feature when transferring fuel?
4. What are three different methods for reducing charge build-up in clothes dryers?
5. What are four different methods for reducing charge build-up in a computer room with a carpet?​

Answers

Answer:  1. The function of a lightning rod is to protect buildings, structures, and people from lightning strikes by providing a path of least resistance for the electrical current to follow, directing it safely into the ground instead of through the structure or people.

2. Charge build-up is reduced on airplanes through various methods, such as using conductive materials in the airplane's structure, applying anti-static coatings on the airplane's surface, and installing static discharge wicks or similar devices on the airplane's trailing edges, which provide a way for any accumulated charge to safely dissipate into the air.

3. A ground strap is a necessary safety feature when transferring fuel because it provides an electrical connection between the fuel container and the receiving container, allowing any static charge to safely dissipate into the ground. Without a ground strap, the static charge could build up and potentially ignite the fuel.

4. Three different methods for reducing charge build-up in clothes dryers are: (1) using dryer sheets or fabric softeners, which can help neutralize static charges on the clothes, (2) adding a damp cloth to the dryer, which can help dissipate static charges, and (3) using metal dryer balls, which can physically separate clothes and prevent them from rubbing against each other and creating static charges.

5. Four different methods for reducing charge build-up in a computer room with a carpet are: (1) using conductive flooring or carpet tiles that can help dissipate static charges, (2) using anti-static mats or wrist straps for personnel who work in the room, (3) using air ionizers or humidifiers, which can help neutralize static charges in the air, and (4) grounding all equipment and devices in the room to prevent the buildup of static charges.

Explanation:

I hope this helps!

What is the relationship Between frequency and sound?

Answers

Answer:

The sensation of a frequency is commonly referred to as the pitch of a sound. A high pitch sound corresponds to a high frequency sound wave and a low pitch sound corresponds to a low frequency sound wave.

Explanation:

Hope this helps : )

What if boy A and boy B pull the heavy cabinet at the same time in opposite directions with 10N and 5N of force perspectively, what will be the net force on the cabinet?

Answers

Answer:

Explanation:

Boy b will win and cabinate will move in his direction

15 is maybe the net force

A force is a vector quantity, and the net force on an object is the vector sum of all the forces acting on the object

The net force on the cabinet is 5 Newtons in the direction boy A is pulling

The reason the net force value is correct is given as follows

The known parameter are;

Force with which boy A pulls the cabinet = 10 NForce with which boy B pulls the cabinet = 5 NThe direction boy B pulls the cabinet = Opposite direction to the direction boy A pulls the cabinet

Required:

The net force on the cabinet

Solution:

Let the vector form of the force applied by boy A, \(\overset \rightarrow {F_1}\) = 10·i, therefore, the force applied by boy B in the opposite direction is, \(\overset \rightarrow {F_2}\) = -5·i

The net force on the cabinet,  \(F_{NET}\) = \(\overset \rightarrow {F_1}\) + \(\overset \rightarrow {F_2}\), therefore;

\(F_{NET}\) = 10·i - 5·i = 5·i

The net force on the cabinet, \(F_{NET}\) = 5 Newton, in the direction of boy A

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