Why can some mixtures not be classified as solutions?

Not all mixtures are heterogeneous.

Not all mixtures are homogeneous.

Not all mixtures have solutes and solvents.

Mixtures are made of only one substance.

Answers

Answer 1

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Not all mixtures are solutions.

A solution is a specific term that describes an even or homogeneous mixture of a solute, the substance being mixed, in a solvent, the substance that is in a greater amount in which the solute dissolves.

All solutions are mixtures because it is two or more substances mixed together.

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Why Can Some Mixtures Not Be Classified As Solutions?Not All Mixtures Are Heterogeneous.Not All Mixtures

Answer 2

Some mixtures cannot be classified as solutions because not all mixtures have solutes and solvents. Thus option C is correct.

What are mixtures?

Mixtures are combination of two or more components mixed together. They can be heterogenous or homogenous. In homogenous mixtures, the components form sonly one phase and appear to be one.

In heterogenous mixtures, individual components forms different phases and thus appear to be dispersed and separate. A solution is formed by dissolving a solute in a solvent.

Solutions can also be homogenous or heterogenous based on solubility of solute in the solvent. If the solute forms a separate phase from the solvent and is called heterogenous and if appear as one phase then it is homogenous.

Now, some mixtures does not have a solvent or solute, some of them can be a mixtures of two solids or two solvents. Therefore, they cannot be considered as solutions.

Hence, option C is correct i.e., not all mixtures have solute and solvent.

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Related Questions

How many moles of UF6 would have to be decomposed to provide enough fluorine to prepare 8.99 mol of CF4? (Assume sufficient carbon is available).

Answers

Answer:

5.99 moles of \(UF_6\)

Explanation:

In this case, we can start with the decomposition of \(UF_6\), so:

\(UF_6~->~U~+~3F_2\) (Reaction 1)

The \(F_2\) can react with carbon to produce \(CF_4\):

\(CF_4~+~2F_2~->~CF_4\) (Reaction 2)

If we 8.99 mol of \(CF_4\), we can calculate the moles of \(F_2\) that we need. In reaction 2 we have a molar ratio of 1:2 (2 moles of \(F_2\) will produce 1 mol of \(CF_4\)):

\(8.99~mol~CF_4\frac{2~mol~F_2}{1~mol~CF_4}~=~17.98~mol~F_2\)

With this value and using the molar ratio in reaction 1 (3 moles of \(F_2\) are producing by each mol of \(UF_6\)), so:

\(17.98~mol~F_2\frac{1~mol~UF_6}{3~mol~F_2}~=~5.99~mol~UF_6\)

So, we will need 5.99 moles of \(UF_6\) to produce 8.99 mol of \(CF_4\).

I hope it helps!

How much ice in grams would have to melt to lower the temperature of 352 mL
of water from 15 ∘C
to 0 ∘C
? (Assume that the density of water is 1.0 g/mL

Answers

Answer:

66 grams of ice would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C.

Explanation:

To calculate the amount of ice that would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C, we need to use the formula:

Q = m_water * c_water * ΔT_water + m_ice * Lf

where,
Q = the amount of heat transferred,
m_water = the mass of water, c_water is the specific heat capacity of water,
ΔT_water = the change in temperature of water, m_ice = the mass of ice,
Lf = the specific latent heat of fusion of ice.

First, let's calculate the amount of heat transferred to the water:

Q = m_water * c_water * ΔT_water
Q = 352 g * 1.0 cal/(g*°C) * (15-0) °C
Q = 5,280 cal

Next, we can use the specific latent heat of fusion of ice, which is 80 cal/g, to calculate the amount of heat required to melt the ice:

Q = m_ice * Lf
Q = m_ice * 80 cal/g
m_ice = Q / Lf
m_ice = 5,280 cal / 80 cal/g
m_ice = 66 g

How many moles are in 1.25 x 1030 atoms of chlorine?

Answers

Answer:

1287.5

Explanation:

1287.5 is the answer

Answer:

5098.68

Explanation:

What frequency does a photon of wavelength 4.5 x 10-4 m have?
A. 6.67 x 1011 Hz
B. 1.47 x 10-30 Hz
C. 2.98 x 10-37 Hz
D. 1.35 x 105 Hz
SUBMIT

Answers

Answer:

6.67* 1011 Hz

Explanation:

a p e x

Answer:

Awnser above is correct

Explanation:

a. 6.67

I WILL GIVE 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE

Answers

The molarity of the solution prepared by dissolving 0.355 moles of NH₃ in enough water to make 3.84 L of solution is 0.092 M

How do i determine the molarity of the solution?

First, we shall list out the given parameters from the question. This is given below:

Number of mole of NH₃ = 0.355 moleVolume of solution = 3.84 LMolarity of solution = ?

Molarity of a solution is defined as mole per unit volume i.e

Molarity of solution = mole / volume

Inputting the various parameters, we have:

Molarity of solution = 0.355 / 3.84

Molarity of solution = 0.092 M

Thus, from the above calculation, it is evident that the molarity of the solution is 0.092 M

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When lead (II) nitrate reacts with sodium iodide, sodium
nitrate and lead (II) iodide are formed. If you start with 25.0
grams of lead (II) nitrate and 15.0 grams of sodium iodide, how
many grams of sodium nitrate can be formed?

Answers

Answer:

20.44 grams of sodium nitrate can be formed

Explanation:

The balanced chemical equation for the reaction between lead (II) nitrate and sodium iodide is:

Pb(NO3)2 + 2NaI → 2NaNO3 + PbI2

explain what you would do expect caesium astatide to look like .will it be soluble in water ?explain your reasoning

Answers

Answer:

it will not be soluble in water Becoz it can only be

separated by passing it through silver nitrate solution

Explanation:

i hope you understand

An early arrangement of the then known elements was proposed by a British scientist John Newlands, which he called the Law of Octaves. Like other scientists at the time, Newlands arranged the elements in order of increasing atomic mass and noted that every eighth element had similar physical/chemical properties. In the modern Periodic Table, which of the following represents the last pair of elements for which Newlands' Law of Octaves would hold true?

Answers

In the modern Periodic Table, the last pair of elements for which Newlands' Law of Octaves would hold true is Calcium (Ca) and Titanium (Ti).

What leads directly to the formation
of black holes?

Answers

Answer:

When a star bigger than our sun, Collapse a black hole may" formed. Most of the time when a star collapse it explodes and this explosion is called "Super Nova".

Explanation:

i hope this helps you

Which type of property does each statement describe?

Drag each tile to the correct location.

The boiling point of methane is
‑161.5°C.A sample of steel is 2 meters
in length.The water in a beaker has a
volume of 50 milliliters.Chlorine gas is green.A sample of gold has a mass of
5 grams.The freezing point of ethanol is
‑114.1°C.

Answers

The property described by each statement is as follows:

The boiling point of methane is ‑161.5°C: Intensive propertyA sample of steel is 2 meters in length: Extensive propertyThe water in a beaker has a volume of 50 milliliters: Extensive propertyChlorine gas is green: Intensive propertyA sample of gold has a mass of 5 grams: Extensive propertyThe freezing point of ethanol is ‑114.1°C: Intensive property

What is intensive property?

Intensive property is the property of a material that does not depend on the amount or shape of the material.

On the other hand, extensive property is the property of a component or system that is a function of the whole component, a property that changes if material is added or subtracted to the component.

Examples of intensive properties are;

DensityBoiling and freezing pointTemperature

Examples of extensive property are;

VolumeMassLength

Therefore, the property described by each statement is as follows:

The boiling point of methane is ‑161.5°C: Intensive propertyA sample of steel is 2 meters in length: Extensive propertyThe water in a beaker has a volume of 50 milliliters: Extensive propertyChlorine gas is green: Intensive propertyA sample of gold has a mass of 5 grams: Extensive propertyThe freezing point of ethanol is ‑114.1°C: Intensive property

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Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 3.45 g of hexane is mixed with 19. g of oxygen. Calculate the minimum mass of hexane that could be left over by the chemical reaction. Round your answer to significant digits.

Answers

A chemist I’m sorry I wish I could answer but I’m sorry I do t know but hope you get it right okay bye

How would you convert 500cc of 2M H2SO4 into g/l?

Answers

Answer:

Number of replacable H

ions in H

=n=2

Normality =n× Molarity=2×2=4 N

13 V
3 A
4V
3V
R=?
Calculate the resistance measured across the second light bulb.

Answers

Net potential

13V+4V+3V20V

Net current=3A

Apply ohm's law

R=V/IR=20/3R=6.67Ohm

THIS IS TIMED!! PLEASE HELP A student has about 250 mL of the liquid acetone. She wants to get a precise and accurate measure of the actual volume of the liquid without losing any. Which of these would be the best instrument to use. 500 mL graduated cylinder (±1mL) 100 mL graduated cylinder (±0.5mL) 250 mL beaker (±5mL) 500 mL beaker (±7mL)

Answers

Answer:

500 mL graduated cylinder (±1mL)

Explanation:

Several laboratory glasswares are used in the laboratory, which serves different functions. They include: beakers, volumetric flask, Erlenmeyer flask etc. Beakers are flat-based glasswares used majorly for storing and mixing chemical solutions. Some beakers are also used to measure liquids.

However, graduated cylinders are tall flasks that has graduated markings on it, hence, it is majorly used for measuring liquids. According to this question, a student wants to get a precise and accurate measure of the actual volume of acetone liquid, which is about 250mL.

To do this, the best instrument she can use is a 500 mL graduated cylinder (±1mL). This is because the graduated cylinder holds enough space to contain the liquid and measure it with a level of accuracy better than beakers.

what is the difference between crystalline and amorphous solid..???

Answers

Answer:

Crystalline solids have regular ordered arrays of components held together by uniform intermolecular forces, whereas the components of amorphous solids are not arranged in regular arrays.

Explanation:

Why is the top ruler more reliable in measuring length than the bottom ruler?

Answers

I’m assuming the top ruler has more measurement points, like more specific numbers. This would mean the top ruler is more reliable because you can be more specific with your measurements

Answer:

cause the bottom part starts at 0 and the top starts at 12

Explanation:

Which of the following choices describe the steps required to determine the empirical formula of a compound from the mass %? Select all that apply. Check all that apply. The mass percentage of each element is converted to moles using the mass mass formula molar mass If a compound contains 52% of mass of C, it can be assumed that there are 52 g of C in 100 g of the compound. Therato of atoms of each element must bo a rato of ntege nmbers If the sample contains 52 g of carbon, it is assumed that this compound has 52 mass percent of carbon. The mass percentages are divided among the smallest number to calculate the ratio of atoms of each element present.

Answers

The steps required to determine the empirical formula of a compound from the mass % are:

1. Convert the mass percentages of each element to moles using the molar mass formula.

2. Divide the mass percentages among the smallest number to calculate the ratio of atoms of each element present.

3. Ensure that the ratio of atoms of each element is a ratio of integer numbers.

What is empirical formula ?

The empirical formula of a compound is the simplest whole number ratio of the elements present in the compound. It is often represented using the symbols of the elements involved and can be calculated from the relative masses of the elements. It is helpful in identifying the composition of a compound. For example, the empirical formula for glucose is CH2O, indicating that there is one carbon atom, two hydrogen atoms, and one oxygen atom present in the compound.

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What is the volume of 1g of ice in cm3?

Answers

Answer:

What is the volume of 1g of ice in cm3?

Explanation:

You find a 1979 copper penny (pre-1982 pennies are pure copper) in the snow and pick it up. How much heat does the penny absorb as it warms from the temperature of the snow, -5.0∘C to the temperature of your body, 37∘C. Assume the penny is pure copper and has a mass of 3.10 g. (The specific heat capacity of copper is 0.385 J/g∘C.)

Answers

Answer:

50.127 J

Explanation:

The following data were obtained from the question:

Initial temperature (T₁) = –5 °C

Final temperature (T₂) = 37 °C

Mass (M) = 3.10 g

Specific heat capacity (C) = 0.385 J/gºC

Heat (Q) absorbed =?

Next, we shall determine the change in temperature. This can be obtained as follow:

Initial temperature (T₁) = –5 °C

Final temperature (T₂) = 37 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 37 – (–5)

ΔT = 37 + 5

ΔT = 42 °C

Finally, we shall determine the heat absorbed. This can be obtained as follow:

Mass (M) = 3.10 g

Specific heat capacity (C) = 0.385 J/gºC

Change in temperature (ΔT) = 42 °C

Heat (Q) absorbed =?

Q = MCΔT

Q = 3.10 × 0.385 × 42

Q = 50.127 J

Thus, the heat absorbed is 50.127 J.

What are two things plants have which animal cells do not

Answers

Answer:

Animal cells don't have a dividing cell wall like plant cells do

Explanation:

Plants cells use photosynthesis from the sun, which requires them to have chloroplast filled with chlorophyll to complete this function; animal cells do not have chloroplasts

Animal cells and plant cells share the common components of a nucleus, cytoplasm, mitochondria and a cell membrane.

Plant cells have three extra components, a vacuole, chloroplast and a cell wall.

A mineral sample has a mass of 48.6 grams and a volume of 18 milliliters. What is the density of the mineral?

Density = Mass divided by Volume

2.7 g/mL

1.9 g/mL

4.6 g/mL

3.5 g/mL

Answers

Answer:

\(\boxed {\boxed {\sf 2.7 \ g/mL}}\)

Explanation:

Density is the mass per unit volume of a substance. It is calculated by dividing the mass by the volume.

\(\rho = \frac{m}{v}\)

The mass of the mineral is 48.6 grams. The volume is 18 milliliters.

m= 48.6 g v= 18 mL

Substitute the values into the formula.

\(\rho= \frac{ 48.6 \ g}{18 \ mL}\)

Divide.

\(\rho = 2.7 \ g/ mL\)

The density of the mineral sample is 2.7 grams per milliliter.

Determine the acid dissociation constant (Ka) for a 0.200 M solution of hydrogen sulfate ion with
the pH of 1.35 if the reaction for the dissociation of this acid is
HSO 4 →→ H+ + SO 4-²
(Hint: [H+] = 10-PH; Ka = [product]/[reactant])

Answers

The acid dissociation constant(Ka) is 0.0095

The reaction for this dissociation of acid is

HSO4 ⇄H+ + SO4 -2

The dissociation constant can be determined from the following expression

\(Ka= \frac{[H+] [SO4]-2}{[HSO4}\)

[H+] = 10-PH

= 10-1.35

[H+] = 0.0447

[H+] = 0.0447 mol / L

From equation, [H+] = [SO4-2] = 0.0447 mol / L

[SO4-2] = 0.0447 mol / L

From the values of [H+], [SO4-2] and [HSO4] Ka can be calculated as follows,

Ka = 0.0447 * 0.0447 / 0.200

= 0.0019 / 0.200

= 0.0095

Hence the value of the acid dissociation constant (Ka) for the given reaction is 0.0095

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A solid piece of lead has a mass of 36.24 g and a volume of 3.22 cm3. From these data, calculate the density of lead in SI units (kilograms per cubic meter).

Answers

Answer:

Density = 11.25

Explanation:

Using the formula

p = \(\frac{m}{v}\)

we can use that, p is for density

p = 36.24 ÷ 3.22

p = 11.25

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How many grams of sulfur dioxide will exert a pressure of 0.705 atm in a 2.50L tank at 0 °C?

Answers

The mass of sulfur dioxide required is approximately 6.36 grams.

To determine the number of grams of sulfur dioxide (SO2) required to exert a pressure of 0.705 atm in a 2.50L tank at 0 °C, we can use the ideal gas law equation: PV = nRT.

First, we need to convert the temperature from Celsius to Kelvin by adding 273.15, so the temperature becomes 273.15 K. The ideal gas constant (R) is 0.0821 L·atm/(mol·K).Rearranging the ideal gas law equation to solve for the number of moles (n), we get n = PV / RT.

Plugging in the given values, n = (0.705 atm) * (2.50 L) / [(0.0821 L·atm/(mol·K)) * (273.15 K)]. Calculating this expression, we find that n is approximately 0.0993 moles.The molar mass of sulfur dioxide is 64.06 g/mol (32.06 g/mol for sulfur + 2 * 16.00 g/mol for oxygen).

Finally, we can calculate the mass of sulfur dioxide using the formula: mass = n * molar mass = 0.0993 moles * 64.06 g/mol. Thus, the mass of sulfur dioxide required is approximately 6.36 grams.

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What volume of CO2(g), measured at STP is produced if 15.2 grams of CaCO(s) is heated?

Answers

Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

= \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

= 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

= 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

7. Which object is excellent at holding onto electrons?

Answers

Answer:

Insulator

Explanation:

When the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely

Answers

When the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely become surface run off.

What is super saturation?

Super saturation occurs with a chemical solution when the concentration of a solute exceeds the concentration specified by the value equilibrium solubility.

Additional water into the soil will cause the soil to be super saturated and eventually runs off due to the steepness of the area.

Thus, when the soil is saturated in a gently sloping area, any additional rainfall in the area will most likely become surface run off.

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Please how to do question 4.

Answers

Answer:

all you have to so answer it all done

What function is most affected if the sepal of a flower is damaged by air pollution?

Answers

Answer:answer in explanation try to understand dear

Explanation:Air pollutants have a negative impact on plant growth, primarily through interfering with resource accumulation. Once leaves are in close contact with the atmosphere, many air pollutants, such as O3 and NOx, affect the metabolic function of the leaves and interfere with net carbon fixation by the plant canopy.

Chemistry Lab Determination of the Universal Gas Constant (R)
SHOW ALL WORK

Given:

Initial mass of butane lighter: 54.24g

Final Mass of Butane Lighter: 54.01g

Temperature of water: 23.0°C

Volume of gas collected: 100.0mL

FIND:
Barometric pressure of room: 766.86 mmHg CONVERTED TO atm

Vapor pressure of water at room temperature(PH2O) (IN atm)

FIND:

Mass difference if butane lighter in grams

Moles of Butane gas collected in moles of C4H10

Partial pressure if butane gas in atm

Converted temperature of water in Kelvin

Converted volume of gas collected in Liters

Experimental value of R in Latm/molk

Accepted value of R in Latm/molk

Percent error in experimental value of R in %

CONCLUSION QUESTIONS:

1. List at least 3 factors that either did it could contribute to the percent error

2. Should the value of R go up or down if the gas had not been corrected for the partial pressure of water. Why?

3. How could this experiment be repeated to increase the accuracy, or in other words, decrease the percent error?

NOTE: LET ME KNOW IF YOU WANT A PICTURE OF THE LAB INSTRUCTIONS TO HELP SOLVE

ALSO SHOW ALL WORK PLS

Answers

To solve this problem, I'll need some additional information related to the molar mass of butane (C4H10). Please provide the molar mass of butane so that I can proceed with the calculations.

Other Questions

As I mentioned in the class, intuition sometimes may not be as reliable as it looks like. One well known example is called Birthday Paradox. Let us investigate it formally. Consider a group of N people and let p Nbe the probability that there exists at least two people whose birthdates share the exact same month and date (we ignore the birth year here). For analysis convenience, let us assume that every year has 365 days and thus, every person's birthday has in total 365 possible outcomes. It may be hard for some of you to develop the exact formula for p Nin terms of N. However, we can approximate p Nby applying Monte-Carlo simulations as details below. Monte-Carlo simulations to approximate p N. Consider a given integer N and M. Step 1: Generate a random vector P of size N such that each element of P is sampled from {1,2,,365} uniformly at random independently, and check if there exists at least two values are the same in P (we call the trial "good" if there does); Step 2: Repeat Step 1 independently for M times and the output the value M /M as the approximation of p N, where M is the number of times we end up with a good trial. For each given N=1,2,3,,50, please run the above Monte-Carlo simulations to output the approximate value of p Nwith M reasonably large as long as you computer can afford to (e.g., you can set M=1000). Please use a table to present the approximate results of p Nfor all N=1,2,3,,50, and attach your pseudo codes in your submission PDF. (20 Points) classmateDatePagecauseGInclustrialization and urbanizationenvironmental imbakeimbake. Justify according to class 7 in the meselson-stahl experiment, was the dna circular or linear? 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Why can some mixtures not be classified as solutions? Not all mixtures are heterogeneous. Not all mixtures are homogeneous. Not all mixtures have solutes and solvents. Mixtures are made of only one substance.

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Why can some mixtures not be classified as solutions?

Not all mixtures are heterogeneous.

Not all mixtures are homogeneous.

Not all mixtures have solutes and solvents.

Mixtures are made of only one substance.