Why can concave mirror is used in cosmetic mirror​

If the same motor is to be driven from a 440-V, 60 Hz power supply, The slip at pullout torque is 0.0455.

The slip at pullout torque, pullout torque, and rotor speed at the pullout torque of the motor are given by Slip

\(s = Pmech/ (Xm\times 1.5\times V^2/1000)\)

Pullout torque is given by \((0.5 \times V^2 / X2) \times (R2 / (R1^2 + (X1 + X2)^2))\)

Rotor speed at pullout torque is given by Ns = (120f/p)(1 - s)

The given parameters of the motor are R1 = 0.075 Ohms, R2 = 0.065 Ohms, Xm = 7.2 Ohms, X1 = 0.17 Ohms, X2 = 0.17 Ohms, Pmech = 1.0 KW W, Pstray = 150 W, Pcore = 1.1 KW.

The motor is rated at 75 KW with a power factor of 0.85.Assuming the motor is running at unity power factor.

The output power of the motor is Pout = 75 KW and the input power to the motor is Pin = 75 KW / 0.85 = 88.24 KW

The input current to the motor is \(Iin = 88.24 KW / (3 \times 440 V \times sqrt(3)) = 89.5 A\)

Therefore, the torque developed by the motor is \(T = 1000 \times Pout / (2 \times pi \times N)\)

The slip at the pullout torque is given by \(s = sqrt((Pcore + Pstray) / Pout) = sqrt((1.1 KW + 150 W) / 75 KW) = 0.0455.\)

The pullout torque is given by \((0.5 \times 440^2 / 0.17) \times (0.065 / (0.075^2 + (0.17 + 0.17)^2)) = 411.7 Nm.\)

The rotor speed at pullout torque is \(Ns = (120 \times 50 / 2) \times (1 - 0.0455) = 2846 rpm.\)

The pullout torque of the motor if driven from a 440 V, 60 Hz power supply is given by

\((0.5 \times 440^2 / 0.17) \times (0.065 / (0.075^2 + (0.17 + 0.17)^2)) \times (60 / 50) = 548.4 Nm.\)

The slip at pullout torque is given by \(s = sqrt((1.1 KW + 150 W) / 75 KW) = 0.0455.\)

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Answer:

Slow down, stop, speed up.

It slows due to gravity (acting against gravity due to upward motion), stops because at maximum height vertical velocity is zero and the body has only the horizontal velocity, speed up due to action of gravity on the body due to downward motion.

Answer:

The lens is a concave lens

Explanation:

In concave lens, the image formed is erect. diminished and virtual. The more the distance of the object from the mirror, the more diminished the image formed will be. Concave lens are used in binoculars and telescopes and are installed before or in the eye piece to enable a clear focus.

Answer:

\(\boxed {\boxed {\sf 2.2 \ m/s^2}}\)

Explanation:

We are asked to solve for the magnitude of the car's acceleration.

We are given the initial speed, final speed, and distance, so we will use the following kinematic equation.

\({v_f}^2={v_i}^2+2ad\)

The car is initially traveling at 15.0 meters per second and accelerates to 20.0 meters per second over a distance of 40.0 meters. Therefore,

Substitute the values into the formula.

\((20.0 \ m/s)^2= (15.0 \ m/s)^2 + 2 a (40.0 \ m)\)

Solve the exponents.

\(400.0 \ m^2/s^2 = 225.0 \ m^2/s^2 + 2 a(40.0 \ m)\)

Subtract 225.0 m²/s² from both sides of the equation.

\(400.0 \ m^2/s^2 - 225.0 m^2/s^2 = 225.0 \ m^2/s^2 -225 \ m^2/s^2 +2a(40.0 \ m)\)

\(400.0 \ m^2/s^2 - 225.0 m^2/s^2 = 2a(40.0 \ m)\)

\(175 \ m^2/s^2 = 2a(40.0 \ m)\)

Multiply on the right side of the equation.

\(175 \ m^2/s^2 =80.0 \ m *a\)

Divide both sides by 80.0 meters to isolate the variable a.

\(\frac {175 \ m^2/s^2}{80.0 \ m}= \frac{80.0 \ m *a}{80.0 \ m}\)

\(\frac {175 \ m^2/s^2}{80.0 \ m}=a\)

\(2.1875 \ m/s^2 =a\)

Round to the tenths place. The 8 in the hundredth place tells us to round the 1 up to a 2.

\(2.2 \ m/s^2=a\)

The magnitude of the car's acceleration is 2.2 meters per second squared.

Unit vector n is (7/√6206)i - (30/√6206)j - (97/√6206)k and is a right handed system because of its positive value.

To find a unit vector n normal to the plane containing a and b, we need to take the cross product of a and b:

a × b =

| i j k |

| 31 4 -1 |

| 1 -3 1 |

= (4×1 - (-1)×(-3))i - (31×1 - (-1)×1)j + (31×(-3) - 4×1)k

= 7i - 30j - 97k

To make this a unit vector, we need to divide it by its magnitude:

|n| = √(7² + (-30)² + (-97)²) = √(6206)

n = (7/√6206)i - (30/√6206)j - (97/√6206)k

To check that this forms a right-handed system with a and b, we can take their dot product:

a · (b × n) =

(31+4j-k) · (7i-30j-97k) =

31×7 + 4×(-30) + (-1)×(-97) = 505

Since this is a positive value, we can conclude that a, b, and n form a right-handed system.

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Answer:

I think its Baking soda, antacids, Sorry if i'm wrong!

Explanation:

Answer:

it base

Explanation:

because i passed the test on that

Acceleration is the change in velocity over time. We can calculate the acceleration of the bicyclist during the time 2.0 s to 5.0 s using the formula acceleration = (final velocity - initial velocity) / time.

The initial velocity of the bicyclist at 2.0 s is 2.0 m/s and the final velocity at 5.0 s is 8.0 m/s. The time interval between 2.0 s and 5.0 s is 3.0 s.

Substituting these values into the formula, we get acceleration = (8.0 m/s - 2.0 m/s) / 3.0 s = 6.0 m/s / 3.0 s = 2.0 m/s^2.

So, the acceleration of the bicyclist during the time 2.0 s to 5.0 s was 2.0 m/s^2.

Answer:

Explanation:

Coefficient of static friction μs = .830216

Coefficient of kinetic friction μk = .326245

a ) The angle at which the box starts sliding depends upon coefficient of static friction . If θ be the required angle

tanθ = μs

tanθ = .830216

θ = 39.7°

b )

When the box starts sliding , kinetic friction will be acting on it .

frictional force on the box = μk mg cos 39.7

net force on the box

= mg sin39.7 -  μk mg cos 39.7

Applying Newton's law of motion

mg sin39.7 -  μk mg cos 39.7  = m a

a = g sin39.7 -  μk g cos 39.7

= 9.8 x sin 39.7 - .326245 x 9.8 x cos 39.7

= 6.26 - 2.46

= 3.8 m /s² .

The magnitude of acceleration of block 2 is 4.67 m/s².

The diagram representing the blocks is shown below:It can be observed that the two blocks are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.Now let's derive the equation for acceleration, a2.

A key concept that must be understood to solve the problem is the difference in tension on either side of the string. Since the pulley is massless and frictionless, the tension must be the same on both sides. We can derive this concept using the following equations:Tension on block 1 side:T1 = m1(g)sin(1) - m1(g)cos(1) * f1Tension on block 2 side:T2 = m2(g)sin(2) + m2(g)cos(2) * f2Where g is acceleration due to gravity, which is equal to 9.8 m/s².Then:T1 = T2T1 + m1(g)cos(1) * f1 = m2(g)sin(2) + m2(g)cos(2) * f2Substitute the values into the above equation:2.25(9.8)cos(42.5) * 0.205 + 2.25(9.8)sin(42.5) = 5.55(9.8)sin(33.5) + 5.55(9.8)cos(33.5) * 0.105T2 = 25.836 N (correct to 3 significant figures)Now we can find the acceleration of block 2.

The acceleration of block 1 can be determined using the following equation:a1 = g(sin(1) - f1 cos(1))a1 = 9.8(sin(42.5) - 0.205cos(42.5))a1 = 5.748 m/s² (correct to 3 significant figures)Using the equation for acceleration of block 2:a2 = (T1 - T2) / m2a2 = (25.836 - 0) / 5.55a2 = 4.667 m/s² (correct to 3 significant figures).

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On colliding, the truck applies a force on the stationary car, and the stationary car applies an opposite force on the truck. The front of the truck is designed to crumple in order to absorb the impact of the collision, which protects the well-being of the passengers.

Answer:

Yeah

Explanation:

Thermoproteota is a prokaryote.

Prokaryotes are unicellular

Answer: It takes 12 N of force to pull the wagon.

Explanation:

Answer:

has a thick atmosphere which traps heat:))

Answer:

This link was diagram

Explanation:

https://doubtnut.app.link/FnsNC80Dccb

Answer:

a. 2.25 × 10^10 yrs

b. 9 × 10^9 yrs

c. 59.5g

d. 8.78g

Explanation:

(a) Original sample(N) = 238g

Half-life = 4.5 × 10^9 yrs

5 half-life 5T½ = 5 × 4.5 × 10^9 yrs

= 2.25 × 10^10 yrs

(b) If N = 240g

N/2 = 120g

N/4 = 60g

Meaning 2T½

= 2 × 4.5 × 10^9 yrs

= 9 × 10^9 yrs

(c) 1.8 × 10^10 ÷ 4.5 × 10^9 = 4

at 4T½ we have N/16 = 238/4 = 59.5

=> the sample left = 59.5g

(d) from the question N = 562g

at 6T½

the amount left will be N/64

= 562÷64 = 8.78g

NB: For questions please you can read more on radioactivity

The extension in the string when the particle hangs in equilibrium is e = mg/k. The constant n in the equation of motion is n = (2π/T)²m. The time it takes for the particle to enter simple harmonic motion is t = √(2§/g).

To find the extension in the string when the particle hangs in equilibrium, we need to consider the forces acting on the particle. The weight of the particle is mg, acting vertically downward. The tension in the string exerts an equal and opposite force, mg, to balance the weight. Since the particle is in equilibrium, the total force acting on it is zero.When the particle is dropped from a point below O, it will stretch the string due to its weight. Let's denote the extension of the string as e. The tension in the string will now be greater than mg because it needs to support the weight of the particle and provide the necessary centripetal force for the simple harmonic motion.The extension in the string is given by Hooke's law: F = kx, where F is the force, k is the modulus of the string, and x is the extension. In this case, the force is the tension in the string, and the extension is e. Thus, we have mg = ke. Rearranging the equation, we get e = mg/k.

To find the constant n in the equation of motion, › = -n?, we can use the fact that the period of simple harmonic motion is given by T = 2π√(m/k), where m is the mass of the particle and k is the spring constant. Comparing this with the equation of motion, we see that ω² = n/m. Since ω = 2π/T, we can substitute ω in terms of T and solve for n: n = (2π/T)²m.

To determine when the particle enters simple harmonic motion, we need to find the time it takes for the string to reach its equilibrium position. Since the particle is dropped from a point § meters below O, it will accelerate towards the equilibrium position due to the tension in the string. The time taken for this free-fall motion can be calculated using the equation of motion for constant acceleration: § = ½gt². Solving for t, we get t = √(2§/g).The amplitude of the simple harmonic motion is equal to the maximum displacement from the equilibrium position. In this case, the maximum displacement is equal to the initial dropped distance, § meters.To determine the time it takes for the particle to come to instantaneous rest for the first time, we need to find the time period of the simple harmonic motion. The time period, T, is given by T = 2π√(m/k). To find the time it takes to come to rest, we need to consider half of the time period, T/2.The amplitude of the simple harmonic motion is equal to the initial dropped distance, § meters. The time it takes for the particle to come to instantaneous rest for the first time is T/2, where T is the time period of the simple harmonic motion.

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Answer: Rectangular frames are easy to make but can get pulled out of shape. so if the sides are still attached , then the figure formed is parallelogram. useing the given measurement use the formula of a parallelogram.

formula : A = BASE X HEIGHT

Explanation:

Answer: Fitness assessments are designed to screen for risk of heart disease.

Explanation:

Fitness assessments are medical examinations that are designed to measure a person's physical fitness and identify any health risks they may have. These assessments may include tests of strength, endurance, flexibility, and cardiovascular fitness. One of the primary objectives of a fitness assessment is to screen for the risk of heart disease, which is a major health concern that can be prevented or treated through exercise and other lifestyle changes. While fitness assessments may identify specific injuries or medical conditions, their primary focus is on evaluating a person's overall health and fitness.

Answer:

first one :

the object will stay at the same speed and direction unless it is acted upon by an internal unbalanced force.

Determine the magnitude of B-A is 53.68

1.4

Magnitude is a term used to describe size or distance. We can relate the magnitude of the movement to the size and movement speed of the object. The magnitude of a thing or an amount is its size. A car moves at a faster pace than a motorcycle, just in terms of speed.

Magnitude is the relative size of an object (mathematics). The mathematical term for a vector's length or size is the norm. By using the symbol |v|, the magnitude of a vector formula can be utilized to determine the length of a given vector (let's say v). This amount is essentially the distance between the vector's beginning point and ending point.

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Answer:

By examining its external shape, color, hardness, etc.

Explanation:

Answer:

the answer is b

Explanation:

Answer:

I think its A.........

Knowing that the greatest horizontal pressure is the pressure made by the material on the wall -considering for that the total height of the wall-, then P = 4.375 t/m

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Available data:

From this information, we need to calculate the greatest horizontal pressure.

Horizontal pressure refers to the force made by the supported soil on the retaining wall that tends to deflect the wall outward.

We can calculate horizontal pressure at different heights from the top. And since we need to calculate the greatest horizontal pressure, we need to consider the total height that equals the wall height, H.  

To do it, we will use the following formula, and replace the terms.

P  = [ k   γ H² ] / 2

P = [ 0.25 x 1.4 t/m³ x 5m² ] / 2

P = 8.75/2

P = 4.375 t/m          

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Answer:

6.96ms/2 or 7ms/2

Explanation:

v2=u2 +2as second equation of motion

u=o

v=35

S=88

a=?

35^2=0^2 +2xax88

=1225 =0+176a

1225=176a

1224/176=6.96ms/2 or 7ms/2

A 0.842g sample of Hydrogen-3 decays to 0.0526g. Approximately 4.206 half-lives have occurred.

To determine the number of half-lives that have occurred, we can use the decay equation and the concept of exponential decay. The decay equation for radioactive decay is given by:

N(t) = N₀ * (1/2)^(t/T),\((1/2)^(^t^/^T^),\)

where N(t) is the remaining amount of the substance at time t, N₀ is the initial amount, t is the time elapsed, and T is the half-life of the substance.

In this case, we have an initial mass of 0.842g (N₀) and a remaining mass of 0.0526g (N(t)). We can set up the equation as follows:

0.0526g = 0.842g \(* (1/2)^(^t^/^1^2^.^3^2)\),

where t represents the number of half-lives that have occurred.

To solve for t, we can take the logarithm of both sides of the equation:

log(0.0526g/0.842g) = log\([(1/2)^(^t^/^1^2^.^3^2^)\)].

Using the logarithmic property log(\(a^b\)) = b*log(a), we can rewrite the equation as:

log(0.0526g/0.842g) = (t/12.32) * log(1/2).

Simplifying further:

log(0.0526g/0.842g) = (t/12.32) * (-log2),

where log2 is the logarithm base 2.

Now, we can solve for t:

t = (12.32 * log(0.0526g/0.842g)) / (-log2).

Using the given values and performing the calculation, we find:

t ≈ 4.206.

Therefore, approximately 4.206 half-lives have occurred.

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Answer:896000 J

Explanation: K.E = 1/2*m*v^2

Answer:

The car has Kinetic energy. 896000 Joules

Explanation:

Kinetic energy formula: 1/2 (mass)(speed)^2

First you multiply 1120 by 1/2 and get 560

Then you take the square root of 40 (\(40x^{2}\)) and get 1600

Finally to get the answer multiply 560 by 1600 and your final answer should be 896000 Joules

Answer:

C

Explanation:

Foot-in-the-door technique is a compliance tactic that aims at getting a person to agree to a large request by having them agree to a modest request first

The behavior that should be closely associated is option c. Sutan asks his father for $5, and when he agrees, Sutan asks him for $15 more.

It is a tactic of compliance that focuses on agreeing on the person by having a request.

It shows the connection that lies between the person who is asking for a request and the person who is being asked.

So based on this, option c is correct.

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