Particle size, distribution, and shape are crucial variables in powder metallurgy because they impact the packing density, sintering behavior, and final properties of the product.
Smaller particle sizes and a narrower distribution result in higher packing density and better properties such as wear resistance and hardness. Particle shape affects packing and can lead to voids and defects in the final product. Spherical or near-spherical particles pack more efficiently, leading to higher packing density and more uniform properties. Therefore, controlling these variables is critical in optimizing the properties of the final product in powder metallurgy.
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the two main categories of home and office printers are
The two main categories of home and office printers are:
1. Inkjet Printers: Inkjet printers are commonly used for both home and office settings. They work by spraying tiny droplets of ink onto paper to create text and images. Inkjet printers are known for their versatility, affordability, and the ability to produce high-quality color prints. They are suitable for printing documents, photos, and graphics with varying levels of detail.
2. Laser Printers: Laser printers are widely used in office environments due to their speed and efficiency. These printers use a laser beam to transfer toner onto paper, producing sharp and precise prints. Laser printers are known for their fast printing speeds, high-volume capabilities, and superior text quality.
Both inkjet and laser printers have their own advantages and are designed to cater to different printing needs. Inkjet printers excel in producing high-quality color prints and are often preferred for printing photos and graphics. On the other hand, laser printers are more commonly used for printing text-heavy documents in office settings due to their speed, cost-effectiveness, and crisp text output. The choice between inkjet and laser printers depends on factors such as the intended use, required print quality, volume of printing, and budget.
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What song do you play most often?
What’s your favorite quote from a movie?
What’s your “go to” joke?
Answer:
I play dynamite BTS.
”Don’t give up!”
Knock knock who’s there jimmy, jimmy who jimmy back my formula!
Explanation: Thx for asking
.
Answer:
1: I listen to a lot of different types of songs but one I play a lot is "Chasing" by NF
2: I don't really know but... Probably, " There's a snake in my b0ot!" lol
3: My "go to" joke is 100% always ... " If I look like my mom, would I technically be my dads t y p e?"
It gets them every time. ;)
Sketch the frequency spectrum (Make sure to label all the axes and all relevant details in the plot) and find the bandwidth of each of the following signals:(a) x(t) = (3 cos(4t))^2(b) x(t) = 2 + 0.8 cos(100t) cos(150t)(c) x(t) = (1 + sin(t)) cos(10t)
The frequency spectrum plots for signals (a), (b), and (c) are provided below. The bandwidth for each signal is determined as follows: (a) has a bandwidth of 4 Hz, (b) has a bandwidth of 50 Hz, and (c) has a bandwidth of 20 Hz.
(a) Signal x(t) = (3 cos(4t))^2 represents a square of a cosine waveform with a frequency of 4 Hz and an amplitude of 3. The frequency spectrum of this signal will consist of two delta functions centered at positive and negative 4 Hz, representing the fundamental frequency and its harmonics. Since a square waveform contains odd harmonics, only the odd multiples of the fundamental frequency will be present. Therefore, the bandwidth of this signal is equal to the fundamental frequency, which is 4 Hz. (b) Signal x(t) = 2 + 0.8 cos(100t) cos(150t) represents a modulation of two cosine waveforms with frequencies 100 Hz and 150 Hz. The modulation produces sum and difference frequencies around the carrier frequencies. The frequency spectrum of this signal will consist of two delta functions centered at positive and negative 100 Hz and two delta functions centered at positive and negative 150 Hz. Additionally, sidebands will be present at the sum and difference frequencies of the carrier frequencies, which are 250 Hz and 50 Hz. The bandwidth of this signal can be determined by considering the highest frequency component, which is 250 Hz. Therefore, the bandwidth of this signal is 250 Hz.
(c) Signal x(t) = (1 + sin(t)) cos(10t) represents the product of a cosine waveform with a frequency of 10 Hz and an envelope given by (1 + sin(t)). The frequency spectrum of this signal will consist of a delta function at the frequency of the cosine waveform (10 Hz) and sidebands resulting from the modulation of the envelope. The envelope is a sinusoidal waveform with a frequency of 1 Hz, which will produce sidebands at the sum and difference frequencies of the carrier frequency. Therefore, the frequency spectrum will have delta functions centered at positive and negative 9 Hz, 10 Hz, and 11 Hz. The bandwidth of this signal can be determined by considering the highest frequency component, which is 11 Hz. Therefore, the bandwidth of this signal is 11 Hz.
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What are baselines in geodetic control networks?
Baselines in geodetic control networks are a critical component of modern surveying and mapping. Baselines are defined as the straight-line distance between two points in a geodetic survey, which is used to create a reference system for all other measurements.
The baseline is then used to calculate distances and angles between other points, which can be used to create maps and survey data. Baselines are typically measured using a variety of methods, including satellite-based Global Positioning Systems (GPS), which provide highly accurate measurements. Geodetic control networks are used for a wide range of applications, including construction, mining, land management, and environmental studies.
By providing accurate, reliable data about the earth's surface, these networks are essential for effective management of natural resources and development projects. In summary, baselines in geodetic control networks are the fundamental building blocks that allow surveyors and mapping professionals to create accurate and reliable data about the earth's surface.
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What is constructor and it's example in C++?
In C++, a constructor is a special "MEMBER FUNCTION" with the same moniker as the class it belongs to and is used to establish some data points to an object's data members.
What does the term "constructor" mean?Constructor: In object-oriented programming, a constructor is a particular method of a form or structure that initializes a newly formed object of that kind. The constructor is always invoked when an object is created.
How does the constructor operate?The name of the constructor frequently matches that of the declaring class. They must initialize the data members of the object and establish the class invariant, failing if the equilibrium point is incorrect.
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If you deposit today 11,613 in an account earning 8% compound interest, for how long should you invest the money in order to earn 15,131.76 (profit)?
A computer puts out binary data at the rate of 56 kilobits per second. The computer output is transmitted using a baseband binary PAM system that is designed to have a raised-cosine pulse spectrum. Determine the transmission bandwidth required for each of the following roll-off factors: (a) α = 0.25 (b) α = 0.5 (c) α = 0.75 (d) α = 1.0
Given information: A computer puts out binary data at the rate of 56 kilobits per second. The computer output is transmitted using a baseband binary PAM system that is designed to have a raised-cosine pulse spectrum.
We have to determine the transmission bandwidth required for each of the following roll-off factors: (a) α = 0.25 (b) α = 0.5 (c) α = 0.75 (d) α = 1.0.So, to solve this question we have the following formulas:1. The data rate of PAM system can be calculated as follows:$$C=\frac{1}{T}=2B log_2{M}$$Where,B = bandwidth of PAM pulseT = time of one pulseM = number of discrete voltage levels that can be transmitted using PAM pulseTherefore, the transmission bandwidth required is 2B.Answer:Transmission bandwidth required for each of the following roll-off factors:αBandwidth (BT)0.251.25B0.51.5B0.751.75B1.02B
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We can see here that the transmission bandwidth required for each roll-off factor is as follows:
(a) α = 0.25: 70 kilobits per second
(b) α = 0.5: 84 kilobits per second
(c) α = 0.75: 98 kilobits per second
(d) α = 1.0: 112 kilobits per second
What is transmission bandwidth?Transmission bandwidth refers to the range of frequencies required to transmit a signal or data through a communication channel. It represents the amount of frequency spectrum needed to carry the signal without distortion or loss of information.
To determine the transmission bandwidth required for each roll-off factor, we can use the formula:
Transmission Bandwidth = (1 + α) × Data Rate
Given:
Data Rate = 56 kilobits per second
Let's calculate the transmission bandwidth for each roll-off factor:
(a) α = 0.25:
Transmission Bandwidth = (1 + 0.25) × 56 kilobits per second
= 1.25 × 56 kilobits per second
= 70 kilobits per second
(b) α = 0.5:
Transmission Bandwidth = (1 + 0.5) × 56 kilobits per second
= 1.5 × 56 kilobits per second
= 84 kilobits per second
(c) α = 0.75:
Transmission Bandwidth = (1 + 0.75) × 56 kilobits per second
= 1.75 × 56 kilobits per second
= 98 kilobits per second
(d) α = 1.0:
Transmission Bandwidth = (1 + 1.0) × 56 kilobits per second
= 2.0 × 56 kilobits per second
= 112 kilobits per second
Thus, we here that the transmission bandwidth required for each of the following roll-off factors are:
(a) α = 0.25: 70 kilobits per second
(b) α = 0.5: 84 kilobits per second
(c) α = 0.75: 98 kilobits per second
(d) α = 1.0: 112 kilobits per second
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What is different about residential construction on the local level from residential construction on the national level?
Answer:
The difference lies in the coverage of the construction. While local level construction focuses on the local area, national level construction has a nation-wide coverage.
Explanation:
Residential construction concentrates on the construction of residential buildings that have sleeping accommodations. Such constructions are opposed to the construction of other buildings that are meant for commercial uses as they lack sleeping accommodations. The federal, state, and local governments can embark on the construction of residential quarters for their residents. The constructions are also funded at the given level. When it is locally funded, the construction is meant to satisfy specific local needs. The constructions by the federal government consider the needs of many localities, and may not meet specific local needs.
Answer: A Residential construction is local in its effects even though those effects have a national impact.
Explanation:
12. in an undisturbed soil formation, it is known that the dry unit weight is 18.06 kn/m3 . the specific gravity of the soil particles is 2.75. a. what is the saturated wet unit weight of the soil in kn/m3 unit? b. what is the submerged effective weight of the soil in kn/m3 unit?
Unit Weight in Bulk For many top soils, this is typically 15 kN/m3, although it can range from 11 kN/m3 for a loose, dry soil to 18 kN/m3 for a dense, moist soil.
What is soil formation?Soil is built on minerals found in the soil. They are created from rocks (the parent material) by the natural erosive and weathering processes. Parent material is dissolved with the assistance of water, wind, gravity, temperature variation, chemical reactions, living things, and pressure variations. Pedogenesis, also known as soil creation, is the process of soil genesis as it is influenced by site, environment, and history. The biogeochemical processes in soils have the power to either generate or destroy order.The following factors, according to scientists, contribute to the creation of soil: parent material, climate, biota (organisms), terrain, and time. In Minnesota, these elements combine to create about 1,108 distinct soil series.To learn more about soil formation, refer to:
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The county is normally the state's largest political and _____ unit.
Answer:
Hello There!!
Explanation:
The answer is territorial.
hope this helps,have a great day!!
~Pinky~
\(\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}\)
The county is normally the state's largest political and Territorial unit.
ThanksThe Specific weight of an unknown liquid is 12400N/m³. What mass of the liquid is contained in a volume of 500 cm³ ? use; (a) The Standard value of gravity. (6) The minimum value of gravity on the earth (c) The maximum value of gravity on the earth
The mass of the liquid is 61.029 N. The mass of the liquid is 60.636 N in the second scenario.
What is density?The density of a solid, liquid, or gas describes how closely packed the particles are. Density is defined as the amount of mass per unit volume.
The mass of a liquid can be calculated using its volume and density. The formula is:
mass = density x volume
We are given the density of the unknown liquid as 12400 N/m³ and the volume as 500 cm³.
We need to convert the volume from cm³ to m³ before we can use the formula:
500 cm³ = 0.0005 m³
(a) Using the standard value of gravity (9.81 m/s²):
mass = density x volume x gravity
= 12400 N/m³ x 0.0005 m³ x 9.81 m/s²
= 61.029 N
Therefore, the mass of the liquid is 61.029 N.
(b) Using the minimum value of gravity on Earth (9.78 m/s²):
mass = density x volume x gravity
= 12400 N/m³ x 0.0005 m³ x 9.78 m/s²
= 60.636 N
Therefore, the mass of the liquid is 60.636 N.
(c) Using the maximum value of gravity on Earth (9.83 m/s²):
mass = density x volume x gravity
= 12400 N/m³ x 0.0005 m³ x 9.83 m/s²
= 61.422 N
Thus, the mass of the liquid is 61.422 N.
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Choose two other elements from the periodic table that you predict should react to form something like table salt
Please pleassssss helppp
I give branlistttttt
Some_____
include peanut butter, bacon, and chocolate.
Snap traps baits
Glue boards
Catchalls
IGRs
Bait stations
Answer:
it’s IGS
Explanation:
because i read
Answer:
snap trap baits
Explanation: its kind of obvi, but i took the test and got it right.
.If aligned and continuous carbon fibers with a diameter of 6.90 micron are embedded within an epoxy, such that the bond strength across the fiber-epoxy interface is 17 MPa, and the shear yield strength of the epoxy is 68 MPa, compute the minimum fiber length, in millimeters, to guarantee that the fibers are conveying an optimum fraction of force that is applied to the composite. The tensile strength of these carbon fibers is 3960 MPa.
Answer:
the required minimum fiber length is 0.80365 mm
Explanation:
Given the data in the question;
Diameter D = 6.90 microns = 6.90 × 10⁻⁶ m
Bond strength ζ = 17 MPa
Shear yield strength ζ\(_y\) = 68 Mpa
tensile strength of carbon fibers \(6t_{fiber\) = 3960 MPa.
To determine the minimum fiber length we make use of the following relation;
L = (\(6t_{fiber\) × D) / 2ζ
we substitute our given values into the equation;
L = ( 3960 × 6.90 × 10⁻⁶) / (2 × 17 )
L = 0.027324 / 34
L = 0.000803647 m
L = 0.000803647 × (1000) mm
L = 0.80365 mm
Therefore, the required minimum fiber length is 0.80365 mm
A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
Write an Essay describing in your own words, the two-way Communication Cycle naming all the stages and explaining what goes on at each stage. Illustrate any two barriers that may occur at each of the stages. A correctly labelled diagram is essential for your essay.
n
e
g
r
o
means black in spanish!
A horizontal poly crystalline solar panel module has to be investigated by natural cooling. For crystal silicon, the thermal coefficient approximately 0.0045/K is used. Investigate the effect of air velocity on the cooling performance of PV panels at 0-5 m/s air velocities, 25-40 ºC ambient temperatures, and 400-1000 W/ m2 solar radiation
Solution :
It is given that :
Thermal coefficient = 0.0045/K
Ambient temperature, \($T_a = 25 - 40^\circ$\)
air velocity, v = 0-5 m/s
Solar radiation, \($G= 400-100 \ W/m^2$\)
\($P=50 \ W$\)
Model calculations :
Cell temperature (\($T_c$\))
\($T_c = T_a + \left(\frac{0.25}{5.7+3.8 \ v_w}\right) G$\)
where \($ v_w - v_a = $\) wind speed / air speed
∴ \($T_c = 2 \pi + \left(\frac{0.25}{5.7+3.8 \times 1}\right) \times 400$\)
\($T_c = 35.526 ^\circ$\)
\($\Delta T = T_c -25$\)
= 35.526 - 25
= 10.526 K
Thermal coefficient = 0.0045 x 10.526
= 0.04737
Pv power = \($(1 -C_T) \times P \times \frac{G}{1000}$\)
\($=(1 -0.04737) \times 50 \times \frac{400}{1000}$\)
= 17.0526 W
the diagram illustrates a method of producing plastics called
Answer:
polymerisation,
Explanation:
Which is not a noun
Answer:
Near
Explanation:
Please mark me brainliest
Answer:
Near.... bcoz it is an adverb...
2.13 LAB: Expression for calories burned during workout
This section has been set as optional by your instructor.
The following equations estimate the calories burned when exercising (source):
Men: Calories = ( (Age x 0.2017) — (Weight x 0.09036) + (Heart Rate x 0.6309) — 55.0969 ) x Time / 4.184
Women: Calories = ( (Age x 0.074) — (Weight x 0.05741) + (Heart Rate x 0.4472) — 20.4022 ) x Time / 4.184
Write a program using inputs age (years), weight (pounds), heart rate (beats per minute), and time (minutes), respectively. Output calories burned for men and women.
Output each floating-point value with two digits after the decimal point, which can be achieved as follows:
print('Men: %0.2f calories' % calories_man)
Ex: If the input is:
49
155
148
60
Then the output is:
Men: 489.78 calories
Women: 580.94 calories
299420.1660094
Answer:
ee
Explanation:
This is an over the top question
The program requires a sequence control structure; First, we get input for the variables, and then use the formula to calculate the amount of calories burnt.
The program in python is as follows, where comments (in italics) are used to explain each line.
#This gets input for age, in years
age = int(input("Age (years): "))
#This gets input for weight, in pounds
weight = int(input("Weight (pounds): "))
#This gets input for heart rate, in beats per minutes
heart_rate = int(input("Heart Rate (beats per minutes): "))
#This gets input for time, in minutes
time = int(input("Time (Minutes) : "))
#This calculates the calories burnt for men
calories_man = ((age * 0.2017) - (weight * 0.09036) + (heart_rate * 0.6309) - 55.0969) * time / 4.184
#This calculates the calories burnt for women
calories_woman = ((age * 0.074) - (weight * 0.05741) + (heart_rate * 0.4472) - 20.4022 ) * time / 4.184
#This prints the calories burnt for men
print('Men: %0.2f calories' % calories_man)
#This prints the calories burnt for women
print('Women: %0.2f calories' % calories_woman)
Please note that the program does not check for valid inputs
See attachment for program output
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true/false. many auto repair shops now hire only ase-certified technicians.
The statement "Many auto repair shops now hire only ASE-certified technicians" is false.
While ASE (Automotive Service Excellence) certification is highly regarded in the automotive industry, it is not a requirement for all auto repair shops to exclusively hire ASE-certified technicians.
ASE certification is a voluntary certification program that allows technicians to demonstrate their knowledge and expertise in specific areas of automotive repair and service.
It serves as a benchmark of competency and professionalism in the field. Many technicians pursue ASE certification to enhance their credentials and career prospects.
However, the decision to hire ASE-certified technicians ultimately depends on the individual auto repair shop's policies, requirements, and preferences.
Some shops may prioritize ASE certification and prefer to hire certified technicians to ensure a certain level of skill and expertise. However, there are also many competent and skilled technicians who may not hold ASE certification but have gained experience and expertise through other means such as vocational training or on-the-job experience.
Therefore, while ASE certification is highly valued and sought after, it is not a universal requirement or practice for all auto repair shops to hire only ASE-certified technicians. Hiring decisions may vary based on the specific needs and preferences of each individual shop.
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Kinetic energy kx is 1/2mvx2. evaluate the mean square kinetic energy < kx2 >in one dimension for n2 molecules at 25°c (hint: in the derivation of < kx2 > use f (vx.) )
The mean kinetic energy of the N₂ molecules at 25 °C is 3593.519 joules per mole.
How to estimate the mean square kinetic energy associated to gas molecules
Let suppose that the gas sample behaves ideally. The Graham's law establishes a connection between the ideal gas model and the kinetic theory of gases.
In this question we need to use this law to estimate the average kinetic energy (Kₐ), in joules per mole, of a diatomic gas (N₂), which is defined by the following expression:
\(K_{a} = \frac{3}{2}\cdot R_{u}\cdot T\) (1)
Where:
\(R_{u}\) - Ideal gas constant, in joules per mole-Kelvin.\(T\) - Temperature, in KelvinIf we know that \(R_{u} = 8.314\,\frac{J}{mol\cdot K}\) and \(T = 288.15\,K\), then the average kinetic energy is:
\(K_{a} = \frac{3}{2}\cdot \left(8.314\,\frac{J}{mol\cdot K} \right) \cdot (288.15\,K)\)
\(K_{a} = 3593.519\,\frac{J}{mol}\)
The mean kinetic energy of the N₂ molecules at 25 °C is 3593.519 joules per mole. \(\blacksquare\)
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on older mac oss all information about the volume is stored in the ____
On older Mac OSs, all information about the volume is stored in the "Volume Information Block" or "VIB."
The Volume information block (VIB) contains information about the complete file system on this volume. It is located in the first sector of the volume. The VIB takes the role both of the volume specifier and of the root directory specifier. The volume header is a data structure located at the beginning of the volume that contains important information about the volume, such as its size, file system type, partition map, and other metadata. This information is used by the operating system to mount the volume and access its contents.
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Question Is in the image provided
The two ways through which a computer model is likely to be used by an engineer in order to help refine a design are as follows:
Calculating the possible costs of building a design.Running simulations to test a problem with the design.Thus, the correct options for this question are A and D.
What do you mean by Computer model?A Computer model may be defined as a type of computer program that significantly runs on a computer that typically develops a model, or simulation, of a real-world feature, phenomenon, or any other event.
According to the context of this question, an engineer would try to perform the ways in order to support the refining of the design through the help of calculating the possible costs of building a design and the run simulations to test a problem with the design.
Therefore, the correct options for this question are A and D.
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luminaires that are installed on the outside of an office building under a covered entryway are permitted to be marked as suitable for locations. i. wet ii. damp iii. dry a. iii only b. i only c. ii only d. i, ii, or iii e. ii or iii only f. i or ii only
Luminaires that are installed on the outside of an office building under a covered entryway are permitted to be marked as suitable for locations of i. wet ii. damp. Hence, f. i or ii only is correct.
A luminaire serves what purpose?A luminaire, also known as a light fixture, is an entire lighting assembly made up of one or more lamps (light bulbs or tubes), as well as the socket and other components that hold and safeguard the lamp, the wiring that attaches the lamp to a power source, and a reflector that helps focus and distribute the light.
An electrical device with an illumination-producing electric lamp is known as a light fixture (US English), light fitting (UK English), or luminaire.
Therefore, A fixture body and one or more lamps are components of every light fixture. In some LED lights, the lamps may be hard-wired in place rather than in sockets for simple replacement.
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Which team made pies at a rate of 4.5 per hour
Answer:
Pie piece?? i think
Explanation:
Compute the braking distance for a car moving at an initial
Velocity of 60 kph and a final velocity of 40 kph, slope of the roadway is
+5%, coefficient of friction between road pavement and tires =0.15 and
The perception-reaction time is =3/4 sec.
(a) 39.33 m
(b) 40.23 m
(c) 41.10 m
(d)43.23 m
To compute the braking distance for a car, we need to consider the deceleration of the vehicle and the perception-reaction time. Here are the steps to calculate the braking distance:
Convert the initial and final velocities from kilometers per hour (kph) to meters per second (m/s):
Initial velocity (v1) = 60 kph = (60 * 1000) / 3600 m/s = 16.67 m/s
Final velocity (v2) = 40 kph = (40 * 1000) / 3600 m/s = 11.11 m/s
Calculate the deceleration (a) using the following equation:
a = (v2 - v1) / t
where t is the perception-reaction time
Given perception-reaction time (t) = 3/4 sec = 0.75 sec
a = (11.11 m/s - 16.67 m/s) / 0.75 sec
a = -8.89 m/s²
Note: The negative sign indicates deceleration (braking).
Calculate the braking distance (d) using the equation:
d = (v1^2 - v2^2) / (2 * |a|)
where |a| is the absolute value of the deceleration
d = (16.67^2 - 11.11^2) / (2 * |-8.89|)
d = (277.77 - 123.46) / 17.78
d = 154.31 / 17.78
d ≈ 8.67 m
Calculate the additional distance due to the slope of the roadway:
Slope of the roadway = +5% = 0.05
Additional distance = (slope * d) / friction coefficient
Additional distance = (0.05 * 8.67) / 0.15
Additional distance ≈ 0.29 m
Add the braking distance and the additional distance:
Total braking distance = d + additional distance
Total braking distance ≈ 8.67 m + 0.29 m
Total braking distance ≈ 8.96 m
Therefore, the closest option to the calculated braking distance is (b) 40.23 m.
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A laminated steel ring is wound with 3000 turns. When the magnetism current varies between 7 and 9 A, the magnetic flux varies between 860 and 900Nwb, calculate the incremental inductance of the coil over this range of current variation
Answer:
60000 H
Explanation:
We are given;
Number of turns; N = 3000 turns
Change in flux = 900 - 860 = 40 Wb
Change in current = 9 - 7 = 2 A
Now, the formula for incremental inductance is given as:
L = N(Change in flux/Change in current) where;
N is Number of turns
Plugging in the relevant values, we have;
L = 3000(40/2)
L = 60000 H.
An alternating copolymer is known to have a number-average molecular weight of 100,000 g/mol and a degree of polymerization of 2210. If one of the repeat units is ethylene, which of styrene, propylene, tetrafluoroethylene, and vinyl chloride is the other repeat unit?
a. vinyl chloride
b. propylene
c. tetrafluoroethylene
d. styrene
Answer:
d. Styrene
Explanation:
An alternating copolymer repeat unit types if the other is Styrene. The equation to calculate m is :
m = Mn / Dp
m = 100,000 / 2210 = 45.25g/ mol
alternating copolymer is chain fraction than of each repeat unit type then chain fraction is styrene and unknown repeat units.
A circuit is set up with two parallel resistors, each have a resistance of 250Ω. If another resistor with a resistance of 300Ω is added in series with these two parallel resistors, what is the total resistance?
Answer:
The answer is .....
Explanation:
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