WHO CAN HELP ME WITH THIS MATH PROBLEM! ID APPRECIATE THE HELP NEEDED!

Answer:

2600

Step-by-step explanation:

2.6 × 103

Answer:

Step-by-step explanation:

We use BODMAS

39×52/3.8×4.9

Division first

That's

39 × 13.68 × 4.9

2614.248

= 3000 to 1 significant figure

To solve this system of equations, we can use the method of elimination. The goal is to eliminate one of the variables, such as x or y, by adding or subtracting the equations.

First we can eliminate the y variable by adding the two equations together:

X + 3y = 14

2x - 3y = -8

3x = 6

Dividing both sides by 3:

x = 2

Now we have the value of x, we can substitute it back into one of the original equations:

X+3y=14

2 + 3y = 14

Subtracting 2 from both sides:

3y = 12

Dividing both sides by 3:

y = 4

So the solution of the system of equations is (x,y) = (2,4)

To check the solution, we can substitute the values back into the original equations:

x + 3y = 14

2 + 3(4) = 14

2 + 12 = 14

14 = 14

and

2x - 3y = -8

2(2) - 3(4) = -8

4 - 12 = -8

-8 = -8

As the equation holds true, the solution (2,4) is correct.

Answer: (t-r) / 21 = -0.857    where,   t= -6 and r= 12

Step-by-step explanation:

Given data,

t-r divided by 21

where, t= -6 and r= 12

So, we can write,

                            = (t-r) / 21

Let us assume,

                  (t-r) / 21 = x

So,

           x = (t-r) / 21 { t = -6 and r = 12             (eq-1)

         x = (t-r) / 21

We can substitute,    t = -6 and r = 12   values in this equation 1

so, we can write,

                            x =   (t-r) / 21

                            x = (-6-12) / 21

                            x = -18/21

                            x = -6/7

                            x = -0.857

Therefore,

                       (t-r) / 21 = -0.857    where,   t= -6 and r= 12

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Answer:

the answer would be 12/5

Given, the height \($h=6$, the base $b_1=9$ and $b_2=12$.\)

The area of the trapezoid is given by the formula,

\(\[A = \frac{1}{2}h(b_1+b_2)\]\)

Substitute the given values,  

\(\[A = \frac{1}{2} \times 6 \times (9+12)\]\\\)

Simplifying the above expression,

\(\[A = 45 \text{ square feet}\]\)

Therefore, the area of the trapezoid is $45$ square feet.

The perimeter of a two-dimensional geometric shape is the entire length of the boundary or outer edge. It is the sum of the lengths of all the shape's sides or edges.

The perimeter of a square, for example, is calculated by adding the lengths of all four sides of the square.

Similarly, to find the perimeter of a rectangle, sum the lengths of two adjacent sides and then double the result because there are two pairs of adjacent sides.

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Answer:

9

Step-by-step explanation:

brainliest?

If the price elasticity of demand is equal to 0.02/0.1, then the demand for apples is inelastic and if the price elasticity of demand is equal to 0.2/5, then the demand for apples is elastic.

The price elasticity of demand is calculated using the midpoint method with formula:

Price Elasticity of Demand = (Percent Change in Quantity Demanded) / (Percent Change in Price)

The value of the price elasticity of demand tells us whether the demand for a product is elastic (sensitive to price changes), inelastic (insensitive to price changes), or unitary elastic (neither elastic nor inelastic). A value of price elasticity of demand greater than 1 indicates that the demand for the product is elastic, meaning that a small change in price leads to a large change in the quantity demanded. A value of price elasticity of demand less than 1 indicates that the demand for the product is inelastic, meaning that a small change in price leads to a small change in the quantity demanded.

If the price elasticity of demand is equal to 0.02/0.1, then the demand for apples is inelastic between points X and Y, meaning that a small change in price leads to a small change in the quantity demanded. If the price elasticity of demand is equal to 0.2/5, then the demand for apples is elastic between points X and Y, meaning that a small change in price leads to a large change in the quantity demanded.

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Answer:

a

Step-by-step explanation:

The ball will need to travel 126 feet since it will be dropped from a height of 6 feet and then bounce 10/11 feet.

A number is split in division, which is a straightforward procedure. The simplest way to conceptualize it is as a set of things being distributed among a set of individuals, as in the example given above. In mathematics, division is the process of dividing a number into equal parts and calculating the maximum number of equal parts that may be formed. For instance, dividing 15 by 3 results in the division of 15 into 3 groups of 5 each.

Here,

2*{6/(1-10/11)}-6

2*(6/1/11)-6

2*6*11-6

required distance=126 feet

The required distance will be 126 feet as the ball is dropped from 6 feet and rebounds 10/11 of the distance.

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Answer:

100

Step-by-step explanation

5^2=25 25x4=100

Answer:

A c

Step-by-step explanation:

Answer:

A and C

Step-by-step explanation:

Took the unit test review got it right.

Answer:

3 1/5

Step-by-step explanation:

8×2/5 is 16/5= 3 1/5

because u multiple the top number

Answer:

h(2) = 5.2 + 1 = 10 + 1 = 11

Answer:

0.84

Step-by-step explanation:

You got number 38 wrong. It should be 0.625

So number 39's answer should be the code.

0.84

The normally distributed process has specifications of LSL = 75 and USL = 85 has a Cp of 2.22 , this process is capable and 0.08 defective parts can be expected per day.

To obtain the estimate of Cp, we first need to calculate the process capability index (Cpk) using the formula:

Cpk = min[(USL - mean) / (3 * standard deviation), (mean - LSL) / (3 * standard deviation)]

In this case, the sample mean is 80 and the sample standard deviation is 1.5, so:

Cpk = min[(85 - 80) / (3 * 1.5), (80 - 75) / (3 * 1.5)]
   = min[1.11, 1.11]
   = 1.11

To obtain Cp, we simply multiply Cpk by 2, since Cp = 2 * Cpk when the process is centered:

Cp = 2 * Cpk
  = 2 * 1.11
  = 2.22

Since Cp is greater than 1.0, this process is capable.

To calculate the expected number of defective parts per day, we need to know the proportion of parts that are defective.

Assuming that the process is centered, the proportion of parts that are defective can be estimated using the area under the normal distribution curve beyond the specification limits.

Since the process is normally distributed with mean 80 and standard deviation 1.5, we can use a standard normal distribution table to find the area beyond the limits:

Area beyond USL = P(Z > (USL - mean) / standard deviation) = P(Z > (85 - 80) / 1.5) = P(Z > 3.33) = 0.0004

Area beyond LSL = P(Z < (LSL - mean) / standard deviation) = P(Z < (75 - 80) / 1.5) = P(Z < -3.33) = 0.0004

So the proportion of parts that are defective is:

Proportion defective = 0.0004 + 0.0004 = 0.0008

To find the expected number of defective parts per day, we multiply this proportion by the number of parts produced per day:

Expected number of defective parts per day = 0.0008 * 100 = 0.08

So we would expect to see approximately 0.08 defective parts per day.

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Answer:

b

Step-by-step explanation:

100 plus 400 doesn't equal 900

The area under the curve is \(\frac{6 \sqrt{3}}{5}\).

Consider the following parametric equations:\($$x=t^2-3 t \text { and } y=\sqrt{t} \text { and the } y \text {-axis. }$$\)

The objective is to find area enclosed by the curve using the formula.

The area under the curve is given by parametric equations x=f(t), y=g(t),  and is traversed once as t increases from α to β, then the formula for calculating the area under the curve:

\($$A=\int_\alpha^\beta g(t) f^{\prime}(t) d t$$\)

The curve has intersects with y-axis. so x=0

\($$\begin{aligned}t^2-3 t & =0 \\t(t-3) & =0 \\t & =0 \text { or } t=3\end{aligned}$$\)

Now we have to draw the graph,

Let f(t)=\(t^2-3 t, g(t)=\sqrt{t}$\)

Differentiate the curve f(t) with respect to t.

\(f^{\prime}(t)=2 t-3\)

Now, find the area under the curve use the above formula.

\(\begin{aligned}A & =\int_0^3(\sqrt{t})(2 t-3) d t \\& =\int_0^3(2 t \sqrt{t}-3 \sqrt{t}) d t \\& =\int_0^3\left(2 t^{\frac{3}{2}}-3 t^{\frac{1}{2}}\right) d t \\& =\left[2 \frac{t^{\frac{5}{2}}}{\frac{5}{2}}-3 \frac{t^{\frac{3}{2}}}{\frac{3}{2}}\right]_0^3 \\& \left.\left.=\left[\frac{4 t^{\frac{5}{2}}}{5}-2 t^{\frac{3}{2}}\right]_0^3\right]^{\frac{5}{2}}\right] \\\\\end{aligned}$$\)

\(& =\left[\frac{4(3)^{\frac{5}{2}}}{5}-2(3)^{\frac{3}{2}}\right]-\left[\frac{4(0)^{\frac{5}{2}}}{5}-2(0)^{\frac{3}{2}}\right]\)

\($\begin{aligned}& =\left[\frac{4(3)^{\frac{5}{2}}}{5}-2(3)^{\frac{3}{2}}\right]-\left[\frac{4(0)^{\frac{5}{2}}}{5}-2(0)^{\frac{3}{2}}\right] \\& =\frac{4(3)^{\frac{5}{2}}}{5}-2(3)^{\frac{3}{2}}-0 \\& =\frac{6 \sqrt{3}}{5}\end{aligned}\)

Therefore,  the area of the curve is \(\frac{6 \sqrt{3}}{5}\).

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Frequency tables are used to show the number of occurrence of each data in a dataset.

The complete frequency table is as follows:

\(\begin{array}{cc}{Trick}&{Years}\\52&0&53&1&54&2&55&1&56&2\end{array}\right]\)

The given data are:

54, 56, 53, 54, 56, 55

To complete the frequency table, we simply count each data element and the number of occurrence (i.e. the frequency).

So, we have:

52 has a frequency of 0

53 has a frequency of 1

54 has a frequency of 2

55 has a frequency of 1

56 has a frequency of 2

So, the complete frequency table is:

\(\begin{array}{cc}{Trick}&{Years}\\52&0&53&1&54&2&55&1&56&2\end{array}\right]\)

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Answer:

x = 4

Step-by-step explanation:

perpendicular lines have opposite and reciprocal slopes

the line y = 2 is a horizontal line, which means the slope is zero

also, y = 2 intersects the y-axis at 2

a line perpendicular to a horizontal line is a vertical line and, if it passes through the point (4,5) will intersect the x-axis at 4

therefore, the equation would be x = 4

The fraction of whole chocolate left with Rajan is 0.

What is fraction?

In mathematics, a fraction is used to denote a portion or component of the whole. It stands for the proportionate pieces of the whole. Numerator and denominator are the two components that make up a fraction. The numerator is the number at the top, and the denominator is the number at the bottom.

Rajan is given half a chocolate to divide amongst 4 people, including himself.

This means that each person will get 1/4 of the half chocolate, which simplifies to 1/8 of the whole chocolate.

So, Rajan gets 1/8 of the whole chocolate for himself.

Therefore, the fraction of the whole chocolate that is left with him is -

1/2 (the original size of the chocolate) - 4 × 1/8 (the amount of chocolate given to each person, including Rajan)

= 1/2 - 1/2

= 0

So, Rajan is not left with any fraction of the whole chocolate.

He has given away all of it to the 4 people.

Therefore, nothing is left with Rajan.

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Answer:

3 hours

Step-by-step explanation:

you would have to subtract 5 from 8 and there's you answer

Hope that helps. XD

The opportunity cost is merely the expense of not making a decision.

As a result, if you chose Project P placed above a white Project Q, the opportunity cost for such a decision is 75,000 times the estimated NPV of Project Q.

The distinction between current value of money over time value of cash outflows over time is defined as net present value (NPV).

Some key features regarding the Net Present Value (NPV) are-

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i think Is 9p centímetros

When three standard six-faced dice are rolled, the probability that the sum of the three numbers rolled is 9 is equal to 10/216 or 5/108.

Total number of ways three dice can be rolled = 6 × 6 × 6 = 216.

Each dice can have any number from 1 to 6. The probability of rolling a particular number on a dice = 1/6.

The probability of rolling a particular number on three dice = (1/6) × (1/6) × (1/6) = 1/216.

In order to get a sum of 9, there are four combinations that can be rolled:

3 + 3 + 3 = 9

3 + 4 + 2 = 9

3 + 5 + 1 = 9

4 + 3 + 2 = 9

The probability of rolling any of these combinations = probability of rolling 3-3-3 + probability of rolling 3-4-2 + probability of rolling 3-5-1 + probability of rolling 4-3-2

= (1/216) + (3/216) + (3/216) + (3/216)

= 10/216 or 5/108.

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a) We get: \(400 = x^2 + 20x\) This is the required equation.

b) To three decimal places, x is approximately equal to 5.657.

As you may already know, a trapezium is a quadrilateral with one pair of parallel sides. To find the area of a trapezium, we use the formula:

Area = (1÷2) × height × (sum of parallel sides)

In this formula, the height is the perpendicular distance between the parallel sides, and the sum of the parallel sides is the length of one parallel side plus the length of the other parallel side.

So, if the trapezium has parallel sides of length a and b, and a height of h, then the area can be calculated as:

Area = (1÷2) × h × (a + b)

a) To find the area of a trapezium, we use the formula:

Area = (1÷2) × height × (sum of parallel sides)

So, for this trapezium, we have:

Area = (1÷2) × 2x × (x + 20)

Simplifying this expression, we get:

Area = \(x^2 + 20x\)

We know from the problem that the area is \(400 cm^2\), so we can set this expression equal to 400.

Therefore, \(x^2 + 20x = 400\).

b) To solve for x, we can rearrange the equation into standard quadratic form:

\(x^2 + 20x - 400 = 0\)

Now, we can use the quadratic formula to solve for x:

\(x = (-b\)±\(\sqrt(b^2- 4ac)) / 2a\)

In this case, a = 1, b = 20, and c = -400, so we have:

\(x = (-20\)± \(\sqrt(20^2 - 4(1)(-400))) / 2(1)\)

\(x = (-20\) ± \(\sqrt(400 + 1600)) / 2\)

\(x = (-20\) ± \(\sqrt(2000)) / 2\)

\(x = (-20\)± \(44.72) / 2\)

We can simplify this expression by dividing both the numerator and denominator by 2.

Since the length of a side cannot be negative, we can disregard the negative solution, and we get:

\(x = -10 + 22.36\)

To three decimal places, x is approximately equal to 12.360.

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Using the exponential growth formula, the population in 2005 was 161 million.

The equation f(x) = a(1 + r)^x can also be used to compute exponential growth, where: The function is represented by the word f(x). The initial value of your data is represented by the a variable. The growth rate is represented by the r variable. To calculate growth rates, divide the difference between the starting and ending values for the period under study by the starting value.

Growth factor = (159/154) for the eleven-year period between 1990 and 2001.

The population growth might thus be described by the exponential equation

p(t) = 154(159/154)^(t/11), where t is the number of years since 1990.

The model forecasts a population of... p(15) = 154(159/154)^(15/11)

= 160.86 = 161 million

In 2005, there were about 161 million people living there.

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Correct Question:

A country's population in 1990 was 154 million. In 2001 it was 159 million. Estimate the population in 2005 using the exponential growth formula. Round your answer to the nearest million.

(a) The unit vector u in the direction of movement for the charge at the point (3, -3, 1) is given by <-3 / sqrt(99), 9e^18 / sqrt(99), -9 / sqrt(99)>.

To determine the direction of movement for a charge at the point (3, -3, 1), we need to find the negative gradient of the electric potential function V(x, y, z) = exyz.

The negative gradient vector is given by:

∇V(x, y, z) = -<∂V/∂x, ∂V/∂y, ∂V/∂z>

Let's find the partial derivatives of V with respect to x, y, and z:

∂V/∂x = yze^(xyz)

∂V/∂y = xze^(xyz)

∂V/∂z = xye^(xyz)

Now, we can evaluate the partial derivatives at the point (3, -3, 1):

∂V/∂x = (-3)(1)e^(3*(-3)1) = -3e^(-9)

∂V/∂y = (3)(1)e^(331) = 9e^9

∂V/∂z = (3)(-3)e^(3(-3)*1) = -9e^(-9)

Therefore, the negative gradient vector at the point (3, -3, 1) is:

∇V(3, -3, 1) = -<-3e^(-9), 9e^9, -9e^(-9)>

To find the unit vector u in this direction, we need to normalize the gradient vector:

|∇V(3, -3, 1)| = sqrt((-3e^(-9))^2 + (9e^9)^2 + (-9e^(-9))^2) = sqrt(99e^(-18))

Now, divide each component of the gradient vector by |∇V(3, -3, 1)|:

u = <-3e^(-9) / sqrt(99e^(-18)), 9e^9 / sqrt(99e^(-18)), -9e^(-9) / sqrt(99e^(-18))>

Simplifying the expression further, we have:

u = <-3 / sqrt(99), 9e^18 / sqrt(99), -9 / sqrt(99)>

Therefore, the unit vector u in the direction of movement for the charge at the point (3, -3, 1) is given by <-3 / sqrt(99), 9e^18 / sqrt(99), -9 / sqrt(99)>.

(b)The potential changes at a rate of sqrt(99e^(-18)) as the charge leaves the point (3, -3, 1)

To determine how fast the potential changes as the charge leaves the point (3, -3, 1), we need to find the magnitude of the gradient vector ∇V(3, -3, 1).

This will give us the rate of change of potential with respect to position.

|∇V(3, -3, 1)| = sqrt((-3e^(-9))^2 + (9e^9)^2 + (-9e^(-9))^2) = sqrt(99e^(-18))

Therefore, the potential changes at a rate of sqrt(99e^(-18)) as the charge leaves the point (3, -3, 1)

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Answer:

420

Step-by-step explanation:

Take the the amount of pages(60) multiply it by the number of days (7)

you will get 420