while spinning in a centrifuge a 70.0 kg astronaut experiences an acceleration of 5.00 g, or five times the acceleration due to gravity on the earth. what is the centripetal force acting on her

Answer:

All of the above.

Explanation:

A person is said to be at rest when he or she is not performing any action. The heartbeat stays normal in this condition.

A person is said to perform a moderate activity when his heart beats faster than the normal rest condition. It requires extra effort within the limit. For example, walking and dancing are examples of moderate activity.

A person is said to perform a vigorous activity when his heart beats much than in moderate activity. It requires a lot of effort over the limit. Running is an example of vigorous activity.

In view of the above information, all the options given in the question are true. Hence, the correct answer will be:

All of the above.

(a) The first block  moves at 4.0 m/s in the same direction right after colliding.

(b) the system's total kinetic energy changes by  28.75 J

(c) the system's total kinetic energy changes by -1.25 J

Given;

First block's mass, m1, is 5 kg.

u1 = 3.0 m/s is the first block's starting speed.

m2 weight of the second block is 10.0 kg.

u2 = 2.0 m/s is the second block's initial speed.

v2 = 2.5 m/s is the second block's final speed.

Immediately following the impact, the first block block's Part (A) velocity is as follows:

Apply the law of conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2, where v1 is the speed of the first block after it collides.

(5 x 3.0) + (10 x 2.0) = 5.0v₁ + (10 x 2.5) (10 x 2.5)

35= 2.5v₁ + 25

2.5v₁ = 35-25

2.5v₁ = 10

v₁ = 10/2.5

v₁ = 4

2.5 m/s in the same direction for v1.

Change in the system's overall kinetic energy, part (B):

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

ΔK = (1/2m1v1^2 + 1/2m2v2^2) - (1/2m1u1^2 + 1/2m2u2^2)

ΔK is equal to (1/2 x 5 x 4^2 + 1/2 x 10 x 2.5^2) – (1/2 x 5 x 3^2 + 1/2 x 10 x 2^2).

ΔK = 71.25 J - 42.5 J

ΔK = 28.75 J

Change in part (C) of the system's total kinetic energy if the second block accelerates to 5.2 m/s

Determine the final speed of the first block using the conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2 (5 x 3.0) + (10 x 2.0) = 5v1 + (10 x 4)

35 = 2.5v₁ + 40

2.5v₁ = -5

2.5v₁ = - 5 v₁ = - 5 / 2.5 \s v₁ = -2 m/s

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

K = (1/2m1v12 + 1/2m2v22) - (1/2m1u12 + 1/2m2u22)

K is equal to (1/2 x 5 x 22 + 1/2 x 10 x 2.52) - (1/2 x 5 x 3 + 1/2 x 10 x 2).

ΔK = 41.25 - 42.5 J

ΔK = -1.25 J

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1. Filter absorbs all colors of white light.

2. The light that has passed through a filter, is always dim.

The filter selectively transmits the red and blue portions of the incident white light spectrum, but absorbs most of the green wavelength.

Color filters absorb certain wavelengths of color and transmit the other wavelengths allowing them to be seen.

Therefore in conclusion, the right filter can reduce glare, increase contrast, and make lunar features pop.

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Answer:

Triton is the largest of Neptune's 13 moons. It is unusual because it is the only large moon in our solar system that orbits in the opposite direction of its planet's rotation―a retrograde orbit. ... Like our own moon, Triton is locked in synchronous rotation with Neptune―one side faces the planet at all times.

A 100kg man jumping off a 10m high building in 10 seconds has a power of 1000 Watts.

When the man jumps off the building, he initially possesses potential energy due to his position above the ground. As he falls, this potential energy is converted into kinetic energy, which is the energy of motion. The work done by the man is equal to the change in potential energy.

The potential energy (PE) can be calculated using the formula PE = mgh, where m represents the mass, g represents the acceleration due to gravity, and h represents the height. In this case, the mass is given as 100kg, the acceleration due to gravity is 10 m/s², and the height is 10m.

Substituting these values into the formula, we get PE = 100kg * 10m/s² * 10m = 10,000 Joules. This means that the work done by the man while jumping off the building is 10,000 Joules.

Power is defined as the rate at which work is done. In this scenario, we divide the work (10,000 Joules) by the time taken (10 seconds) to obtain the power. Therefore, Power = Work/Time = 10,000 J / 10 s = 1000 Watts.

Hence, the power of the 100kg man who jumps off the 10m high building in 10 seconds is calculated to be 1000 Watts. Power represents the rate at which energy is transferred or work is done, indicating how quickly the man transformed potential energy into kinetic energy during the jump.

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The answer you are looking for is S=D/T, which is the formula.

It is also read as Speed=Distance/Time, or Speed=Distance divided by Time.

The "S" stands for "Speed."

The "D" stands for "Distance."

The "T" stands for "Time."

I hope this has helped answer your question. Enjoy your day, and take care.

Answer:

The formula is S=D/T.

Explanation:

The minimum stopping distance of the car is determined as 8 m.

The minimum stopping distance of the car is calculated as follows;

d = (u²)/(2a)

where;

when the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s

2 = (11.11²)/(2a)

a = (11.11²)/(2 x 2)

a = 30.86 m/s²

when the speed becomes 80 km/h, the minimum stopping distance is calculated as;

u = 80 km/h = 22.22 m/s

d = (22.22² )/ (2 x 30.86)

d = 8 m

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a) The gravitational potential energy of the system of three masses at the given positions is 188.36md.

(b) The redefined reference height is h₀ = 0.55d.

(c) The new reference height measured from the base is h₀' = 0.96d.

(a) The gravitational potential energy of the system of three masses at the given positions is calculated as;

total gravitational potential energy = P.E(mass 1) + P.E(mass 2) + P.E(mass 3)

T.G.P.E = m₁gh₁ + m₂gh₂ + m₃gh₃

where;

T.G.P.E = (4.6m x 9.8 x 3d) + (2.21m x 9.8 x 2d) + (m x 9.8 x d)

T.G.P.E = 135.24md  +   43.32md  + 9.8md

T.G.P.E = 188.36md

(b) The redefined reference height is calculated as follows;

0 =  (4.6m x 9.8 x h₀) + (2.21m x 9.8 x (h₀ - d) + (m x 9.8 x (h₀ - 2d)

0 = 45.08mh₀ + 21.66mh₀ - 21.66md  +  9.8mh₀ - 19.6md

0 = 45.08h₀ + 21.66h₀ - 21.66d  +  9.8h₀ - 19.6d

0 = 76.54h₀ - 41.26d

76.54h₀ = 41.26d

h₀ = 41.26d/75.54

h₀ = 0.55d

(c) The new reference height measured from the base such that the highest two objects have the exact same gravitational potential energy is calculated as follows;

m₂gh₂ = m₁gh₁

2.21m x 9.8 x h₂ = 4.6m x 9.8 x h₁

21.66mh₂  =  45.08mh₃

21.66h₂  =  45.08h₁

h₁ = 21.66h₂/45.08

h₁ = 0.48h₂

h₀' = 0.48 x (2d)

h₀' = 0.96d

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Answer:

KE=½mv²

KE=½2.3kg×(10m/s)²

KE=½2.3kg×100m²/s²

KE=2.3kg×50m²/s²

KE=115joules

Answer:

When light traveling through air enters water at an angle, it moves in a curve in air and changes direction when it enters water. This bending of light is known as refraction. The angle at which the light bends depends on the difference in the refractive indices of the two media, which is why the light bends when it enters the denser medium of water.

The magnitude of the velocity the blinking tree has when it is 2 meters from the ground is 21.8 m/s.

To calculate the velocity of the blinking tree when it is 2 meters from the ground, we can use the principles of conservation of energy.

First, let's determine the potential energy of the tree when it is 50 meters off the ground. The potential energy (PE) can be calculated using the formula:

PE = mgh

Where:

m = mass of the tree (2.3 kg)

g = acceleration due to gravity (9.8 m/s^2)

h = height (50 m)

PE = 2.3 x 9.8 x 50

PE = 1131 J

Next, we can calculate the potential energy of the tree when it is 2 meters from the ground:

PE = mgh

Thus:

PE = 2.3 x 9.8 x 2

PE = 45.04 J

According to the conservation of energy principle:

PE(initial) = PE(final) + KE(final)

1131 J = 45.04 J + KE(final)

Now, let's solve for the kinetic energy (KE) at the final position:

KE(final) = PE(initial) - PE(final)

KE(final) = 1131 J - 45.04 J

KE(final) = 1085.96 J

KE = (1/2)mv^2

1085.96 J = (1/2) x 2.3 kg x v^2

Thus

v^2 = (2 x 1085.96 J) / 2.3 kg

v^2 = 474.76 m^2/s^2

v ≈ 21.8 m/s

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Answer:

E. All of the Above

Explanation:

BRAINLIEST me pls

Have a nice day!

Answer:

generator

Explanation:

it gives u electricity can i get brainliest

Answer/Explanation:

m= 2kg

t= 40s

P= 100J/s

C= 400J/kg°C

Q= P×t

= 100×40= 4000J

Q= m×C×∆t

4000= 2×400×∆t

∆t= 4000/(2×400)

∆t= 5°C

P stands for power

Q is heat energy, and we know that power multiplied by time gives amount of energy (which in this case is heat energy)

Brainliest?!

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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The required, it experiences a downward force due to gravity and a force due to air resistance.

Projectile motion is the movement of an entity projected into space. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.

Here,

When throwing a ball vertically upward, there is a displacement of about 1.0 m from the initial position of the hand to the position where the ball leaves the hand. The mass of the ball is 0.80 kg and it reaches a maximum height of about 20 m above the initial position of the hand. While the ball is in the hand after it leaves, it experiences a downward force due to gravity and a force due to air resistance.

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Answer:

 v = 220 m / s

Explanation:

This is a kinematics exercise, the expression for velocity is

          v = 25 t² - 80 t - 200

asks the velocity for time t = 6 s.

let's calculate

        v = 25 6² - 80 6 - 200

        v = 220 m / s

The velocity for the first six seconds when acceleration is zero is -44 m/s.

The velocity of an object is the rate of change displacement with time.

The velocity of the object for the first six seconds when the acceleration is zero is calculated as follows;

\(a = \frac{dv}{dt} \\\\a = 50t - 80\\\\0 = 50t - 80\\\\50t = 80\\\\t = 1.6 \ s\)

Velocity when time = 1.6 s

\(v(1.6) = 25(1.6)^2 - 80(1.6) - 200\\\\v(1.6) = -264 \ m/s\)

The velocity for the first six seconds when acceleration is zero.

\(v = v_{a =0} + v_6\\\\v = - 264 \ + 25(6)^2 - 80(6) - 200\\\\v = -44 \ m/s\)

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The displacement of the object after 1 second, is 3 m.

The displacement of the object after 3 seconds, is 9 m.

The displacement of the object after 5 seconds, is 15 m.

The displacement of an object is the change in the position of the object.

The displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m

The displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m

The displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m

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Answer:

When a heavy football player and a light one run into each other, does the lighter player really exert as much force on the heavy player s the heavy player exerts on the light one. Yes. The interaction between the two players, the force each exerts on the other have equal strength.

Explanation:

Answer:    Vf = Vi + A(t)

Vf= -2+ (-9.8)(5)

Vf = -51 m/s

Explanation:

The final velocity is equal to the initial velocity plus the acceleration multiplied by the time

(-9.8) is used for the acceleration for this question because that is the speed at which things in free fall accelerate when they are on earth

-2 is used as the initial velocity because the ball was thrown in the negative direction which is down.

The time of 5 was given in the question so you can plug it in for time

Answer:

Explanation:

Given:

V₀ = 2 m/s

g = 9.8 m/s²

t = 5 s

____________

V - ?

Axis OX direct vertically down. Then:

V = Vₓ = V₀ₓ + g·t

V = 2 + 9.8*5 = 51 m

Answer:

56

Explanation:

I just want the points to be completely honest with you.  

Explanation:

\(\boxed{\sf{K.E = \dfrac{1}{2} \times m \times v^2}}\)

Let's Do!

\(\boxed{\sf{14 = \dfrac{1}{2} \times 17 \times v^2}}\)

\(\boxed{\sf{\dfrac{14 \times 2}{17} = v^2}}\)

\(\boxed{\sf{ \sqrt{\dfrac{14 \times 2}{17}}= v}}\)

So, 1.283 m/s is the required answer.

The angular speed of the race car is 0.698 rad/s and the linear speed is 35 m/s.

The angular speed of the race car is calculated by applying the following kinematic equation as follows;

ω = θ/t

where;

ω =  2π/9

ω = 0.698 rad/s

The linear speed of the race car is calculated as shown below;

v = ωr

where;

v = 0.698 rad/s x 50 m

v = 35 m/s

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The complete question is below:

A race car makes one lap around a track of radius 50 m in 9.0 s. Find the angular speed and linear speed of the race car.

Answer:

y = 0.0233 m

Explanation:

In a Young's Double Slit Experiment the distance between two consecutive bright fringes is given by the formula:

Δx = λL/d

where,

Δx = distance between fringes

λ = wavelength of light

L = Distance between screen and slits

d = Slit Separation

Now, for initial case:

λ = 425 nm = 4.25  x 10⁻⁷ m

y = 2Δx = 0.0177 m => Δx = 8.85 x 10⁻³ m

Therefore,

8.85 x 10⁻³ m = (4.25 x 10⁻⁷ m)L/d

L/d = (8.85 x 10⁻³ m)/(4.25 x 10⁻⁷ m)

L/d = 2.08 x 10⁴

using this for λ = 560 nm = 5.6 x 10⁻⁷ m:

Δx = (5.6 x 10⁻⁷ m)(2.08 x 10⁴)

Δx = 0.0116 m

and,

y = 2Δx

y = (2)(0.0116 m)

y = 0.0233 m

The greatest distance of the block from the center of rotation so that it does not slip is approximately 0.089 meters or 8.9 centimeters.

In order for the block to remain on the turntable without slipping, the frictional force between the block and the turntable must be equal to or less than the maximum friction that can be developed, which is 2 N in this case. The maximum frictional force is given by the product of the coefficient of friction and the normal force.The normal force is equal to the weight of the block, which is 5 N. Therefore, the maximum frictional force is 2 N.

To find the greatest distance of the block from the center of rotation without slipping, we need to consider the centrifugal force acting on the block due to the rotation of the turntable. The centrifugal force is given by the product of the mass of the block, the acceleration due to the rotation (which is equal to the square of the angular velocity times the radius), and the coefficient of friction.

Since the weight of the block is 5 N, the mass can be calculated as 5 N divided by the acceleration due to gravity (approximately 9.8 m/s^2), which gives us a mass of approximately 0.51 kg.

Given that the turntable is rotating at 0.6 revolution per second, the angular velocity can be calculated as 2π times the frequency, which gives us approximately 3.77 rad/s.

Let's assume the greatest distance of the block from the center of rotation is "r" meters.

The centrifugal force is then given by m * (ω^2) * r, and this force must be equal to or less than the maximum frictional force, which is 2 N.

Therefore, we can write the equation:

m * (ω^2) * r ≤ 2 N

Substituting the values we calculated:

0.51 kg * (3.77 rad/s)^2 * r ≤ 2 N

Simplifying the equation, we find:

r ≤ 0.089 m

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Of the options listed, the only effect that can be caused by exposure to infrared light is overheating (option a).

Infrared light is a form of electromagnetic radiation that is invisible to the human eye but can be detected as heat. When exposed to high levels of infrared light, such as in close proximity to a powerful infrared source, it can lead to overheating of the body or objects. Skin cancer (option b) is not directly caused by infrared light. It is primarily associated with overexposure to ultraviolet (UV) radiation from the sun or artificial sources like tanning beds. UV radiation falls in the higher energy range of the electromagnetic spectrum, while infrared radiation has lower energy. Radiation sickness (option c) is caused by exposure to high-energy ionizing radiation, such as gamma rays or X-rays. Infrared light does not possess enough energy to cause ionization and is therefore not capable of inducing radiation sickness. Memory loss (option d) is not a known effect of exposure to infrared light. Memory loss can be attributed to various factors, such as neurological conditions, head injuries, or aging, but not specifically to infrared light exposure. In summary, while exposure to high levels of infrared light can lead to overheating, it does not cause skin cancer, radiation sickness, or memory loss.

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Answer:

The Speed Of The Lightwave Will Be Modified As It Enters Another Medium (State Of Matter)

Explanation:

As The Lightwave Enters The Medium The Light Will Bend Toward The Normal E.g. Incident Ray Which Indicates It Will Modify It's Speed But When it Leaves The Medium It Will Increase Until As It Leaves The Sold

Answer:

B

Explanation:

its B on Edge

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt.

How do you determine a car’s acceleration when braking?

To calculate the acceleration, use v=u+at, where v is the end velocity, u is the beginning velocity, t is the time, and an is the car’s mean acceleration. To calculate the distance traveled, use s=ut+12at2 or v2=u2+2as (You can use both). S is the distance the automobile has traveled since it began to brake.

The formula for determining the magnitude of a vector v = (x, y) in two dimensions is: |v| =(x2 + y2). The Pythagorean theorem is used to derive this formula.

The formula for determining the magnitude of a vector V = (x, y, z) in three dimensions is: |V| = (x2 + y2 + z2).

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The distance that a tennis ball will travel in 2.5 seconds would be 112.5 meters if it has a velocity of 45 m / s.

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.

As given in the problem we have to find the distance that a tennis ball will travel in 2.5 seconds if it has a velocity of 45 m/s.

The distance traveled by the tennis ball = 2.5 × 45

                                                                   = 112.5 meters

Thus, the distance traveled by the tennis ball would be  112.5 meters.

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Answer:

They all have electrical currents

Answer:

They have electronic parts and currents

Answer:

Option D. ²³⁹₉₃Np

Explanation:

From the question given above, the following data were:

²³⁹₉₂U —> ⁰₋₁e + __

Let ⁿₘX represent the unknown. Thus, the equation above becomes

²³⁹₉₂U —> ⁰₋₁e + ⁿₘX

Next, we shall determine n, m and X. This can be obtained as follow:

239 = 0 + n

239 = n

n = 239

92 = –1 + m

Collect like terms

92 + 1 = m

93 = m

m = 93

ⁿₘX => ²³⁹₉₃X => ²³⁹₉₃Np

Thus, the balanced equation becomes:

²³⁹₉₂U —> ⁰₋₁e + ⁿₘX

²³⁹₉₂U —> ⁰₋₁e + ²³⁹₉₃Np

Option D gives the correct answer to the question.

Answer:

D

Explanation:

239 93 Np