Which word best describes something that works in the same way as a radar

Given the provided information, the expected production rate is calculated as q = 1008.6 bbl/ and the corresponding bottom-hole pressure is Pwf = 5022.5 psi.

To calculate the expected production rate, we can use the IPR equation Pwf = 5651 - 5.58q, where Pwf represents the bottom-hole pressure and q represents the production rate. We are given the wellhead pressure as 150 psi, which can be substituted into the equation. Solving for q, we find that q = (5651 - Pwf) / 5.58. Substituting the wellhead pressure of 150 psi, we get q = (5651 - 150) / 5.58. Therefore, the expected production rate is calculated as q = 1008.6 bbl/day.

To calculate the corresponding bottom-hole pressure, we substitute the production rate q into the IPR equation and solve for Pwf. Pwf = 5651 - 5.58 * 1008.6. Therefore, the corresponding bottom-hole pressure is calculated as Pwf = 5022.5 psi.

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Answer:

B

Explanation:

Energy is neither created nor destroyed, the law of conservation states that.

Answer:

The speed of water is 32.2 m/s .

Explanation:

Mass of squid, M = 1.5 kg

mass of water, m = 0.12 kg

velocity of squid, V = - 2.8 m/s

Let the speed of water is v.

Use the conservation of momentum,

Momentum before expelling the water  momentum after expelling water

M x 0 = (M - m) x V + m x v

0 = - (1.5 - 0.12) x 2.8 + 0.12 v

3.864 = 0.12 v

v = 32.2 m/s

The  value of C is 0.0592 pF (picofarads), rounded to three significant figures.

Part A:
The resonant frequency of a parallel resonant circuit is given by the formula:

fo = 1 / (2π√(LC))

where fo is the resonant frequency in Hz, L is the inductance in Henrys, and C is the capacitance in Farads.

Rearranging the formula, we get:

L = 1 / (4π^2f^2C)

Substituting the given values, we get:

L = 1 / (4π^2 x (100 MHz)^2 x C)

Solving for C, we get:

C = 1 / (4π^2 x (100 MHz)^2 x L)

Substituting the given values, we get:

C = 1 / (4π^2 x (100 MHz)^2 x 8 kΩ)

C = 5.05 x 10^-13 F

Therefore, the value of C is 5.05 pF (picofarads).

Part B:
The bandwidth B is related to the quality factor Q and the resonant frequency fo by the formula:

B = fo / Q

The quality factor Q of a parallel resonant circuit is given by the formula:

Q = foL / R

Substituting the given values, we get:

Q = (100 MHz) x L / 8 kΩ

Substituting the value of Q in the formula for bandwidth, we get:

B = fo / (foL / R)

B = R / (2πL)

Substituting the given values, we get:

B = 8 kΩ / (2π x L)

Substituting the given values for fo and B, we get:

7 MHz = 100 MHz / Q = 8 kΩ / (2π x L)

Substituting the value of L from Part A, we get:

7 MHz = 100 MHz / Q = 8 kΩ / (2π x 1.689 x 10^-6 H)

Solving for Q, we get:

Q = 100 MHz x 1.689 x 10^-6 H / 8 kΩ

Q = 21.027

Substituting the value of Q and L in the formula for capacitance, we get:

C = 1 / (4π^2 x (100 MHz)^2 x 1.689 x 10^-6 H)

C = 1/ (4π^2 x (100 MHz)^2 x 1.689 x 10^-6 H)

C = 0.0592 x 10^-12 F

C = 0.0592 pF

Therefore, the value of C is 0.0592 pF (picofarads), rounded to three significant figures.

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Answer:

probaby not

Explanation:

you might get thrown in jail tho

Answer:they are in group 17 and called halogens

Explanation:

As stronger winds cause waves to grow larger, the amount of energy lost to friction increases as the wind moves over the ocean

Friction is a force that prevents two solid objects from rolling or sliding over one another. Although frictional forces, such as the traction required to walk without slipping, might be advantageous, they also provide a significant amount of resistance to motion.

Friction is defined as the resistance that results when surfaces rub together or the tension or disquiet that is caused when two persons of different opinions or ideas come together. When Republicans and Democrats meet to talk politics, it can cause conflict.

The imperfections on the two surfaces in contact are what produce friction. Even the smoothest surfaces include tiny abnormalities, and when two surfaces interact with one another, these irregularities cause friction. The friction increases as the imperfections get bigger.

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For most everyday objects, scientists use a balance to obtain an object's mass. A balance compares an object with a known mass to the object in question. One example of a balance is the triple beam balance.

If a particle moves along a straight line, if the velocity of the particle v = 2t², then the acceleration versus time graph will be a straight line, therefore the correct answer is option C,

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².

As we know the rate of change of velocity is known as acceleration

acceleration =change in velocity/change in time

As given in the problem If a particle moves along a straight line, if the velocity of the particle v = 2t²,

acceleration = dv/dt

                     =d ( 2t²)/dt

                     =4t

Thus, the acceleration versus time graph would be a straight line.

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Answer:

B

Explanation:

Answer:

B

Explanation:

To keep the seesaw balanced, the torque on both sides of the pivot must be equal. Assuming that the pivot is in the middle of the seesaw, the torque on the left side of the pivot must be equal to the torque on the right side of the pivot.
The torque is calculated by multiplying the force by the distance from the pivot. Since the seesaw is balanced, the total force on each side of the pivot must be equal. Let's call this force "F".
On the left side of the pivot, we have a 4.0 kg cat standing at a distance "d" from the pivot. The torque on this side is then: T_left = F * d

On the right side of the pivot, we have an unknown weight (let's call it "W") standing at a distance "x" from the pivot. The torque on this side is:
T_right = F * x
Since the seesaw is balanced, T_left = T_right. Therefore:
F * d = F * x
Dividing both sides by F:
d = x

So the distance the cat must stand from the pivot is equal to the distance the unknown weight is from the pivot. We don't know the weight or the distance, but we know that they must be equal. The cat must stand the same distance from the pivot as the unknown weight. We don't know the exact distance, but it must be equal to keep the seesaw balanced.

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Answer:

8716.97 N

Explanation:

The force between the planet and the satellite can be calculated using the following equation

Where G = 6.67 x 10^(-11) N m²/kg², m1 is the mass of the satellite, m2 is the mass of the Earth and d is the distance from the center of the Earth to the satellite

Since the radius of the Earth is 6,371 km, we get

d = 42 km + 6,371 km = 6413 km

Then, to convert to m, we need to multiply by 1000

d = 6413 km x 1000 m/km = 6.413 x 10^6 m

Finally, replacing m1 = 900 kg, m2 = 5.972 x 10^24 kg, and d = 6.413 x 10^6 m, we get:

Therefore, the force between the planet and the satellite is 8716.97 N

(9)  The force needed to make the object fall on Earth is 127.4 N.

(10) The mass of the object falling at the acceleration due is 1.94 kg.

(11)  The force required for feather is 0.98 N and the force required for the bowling ball is 44.1 N

(9) The force needed to make the object fall on Earth is calculated form Newton's second law of motion.

F = mg

where;

F = 13 x 9.8 = 127.4 N

Thus, the force needed to make the object fall on Earth is 127.4 N.

(10) The mass of the object is calculated from Newton's second law of motion.

F = mg

\(m = \frac{F}{g} \\\\m = \frac{19}{9.8} \\\\m = 1.94 \ kg\)

Thus, the mass of the object falling at the acceleration due is 1.94 kg.

(11) The force required to make each of the objects fall is calculated from Newton's second law of motion.

Force required for feather: F = 0.1 x 9.8 = 0.98 N

Force required for the bowling ball: F = 4.5 x 9.8 = 44.1 N.

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The distance from the axis of the force applied is 2.05 m.

The distance from the axis of the force applied is calculated as follows;

The formula for torque;

τ = Fr

where;

Another formula for torque is given as;

τ = Iα

where;

τ = (mr²)α

τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)

τ = 39.36 Nm

The distance is calculated as;

r = τ/F

r = ( 39.36 Nm ) / (19.2 N)

r = 2.05 m

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Two negatively charged objects are 2 meters apart. the student adds electrons through conduction to one of the objects, then the force of repulsion between the two objects will decrease.

The reason for this is that the negatively charged electrons on the first object will repel the negatively charged electrons on the second object, creating a force of repulsion between them. Adding electrons to one of the objects will increase the number of electrons on that object, resulting in a stronger negative charge. This increase in the negative charge on one object will make it more difficult for the electrons on the other object to push against it, reducing the force of repulsion between the two objects. It's important to note that the amount of decrease in the force of repulsion will depend on the amount of electrons added and the initial charge of the objects. Also, If the distance between the two objects does not change and the charges on the objects are not affected by other factors, the electrostatic force of repulsion between the objects will be inversely proportional to the square of the distance between them.

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Question - Two negatively charged objects are 2 meters apart. The student adds electrons through conduction to one of the objects. What is the force of repulsion between the two objects?

Work done by a force is given as the product of force and the distance moved by the force.

Work done is the product of force and the distance moved by the the force.

Thus, distance required by the 100 N force is given as:

Distance = 1000/100 = 10 m

Distance to be moved is 10 m.

Force applied = work done/ distance

Force applied by the hoist = 500/2

Force applied by the hoist = 250 N

Distance moved in one push-up = 25 cm = 0.25 m

Work done by the athlete after one push-up = 250 × 0.25 m

Work done by the athlete = 62.5 J

Distance moved by the force = 0 m

Work done = 500 × 0 = 0 N

Therefore, for work to be done, force has to move a distance.

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The energy levels of the quantum harmonic oscillator are crucial for analyzing the spectra of diatomic and polyatomic molecules, including carbon monoxide.

The quantum harmonic oscillator provides a fundamental model for understanding the behavior of molecular systems. It describes the vibrational motion of molecules, such as the stretching and bending of chemical bonds. By applying the principles of quantum mechanics, the energy levels of the harmonic oscillator can be calculated, which directly correspond to the spectral lines observed in the molecule's spectrum.

In the case of carbon monoxide (CO), the quantum harmonic oscillator allows us to determine the vibrational energy levels associated with the stretching of the carbon-oxygen bond. As the bond oscillates, it absorbs or emits energy in discrete quanta, resulting in characteristic absorption or emission lines in the spectrum of CO. By analyzing the energy levels and transitions between them, we can gain insights into the molecular structure and properties of carbon monoxide.

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Answer:

The direction in which they rotate is determined by the hemisphere in which they are located. The main overall global wind patterns, the rotation of the Earth, and the shape of ocean basins are the three major factors that decide surface currents.

Oceanic factors are Tempature, salinity, density, pressure gradient and melting of ice. Atsmopheric factors are atsmopheric pressure, winds, rainfall, evaporation and insolation

Answer:       If you let a helium balloon go, and if, as it rises, it stays at a constant temperature, the volume of the balloon will. The magnitude of the buoyant force is equal to the weight of the amount of fluid that has the same total volume as the object.

If you let a helium balloon go, it rises, it stays at a constant temperature, the volume of the balloon will increases.

A measurement of three-dimensional space is volume. Several imperial or US customary units, as well as SI-derived units (such the cubic meter and liter), are frequently used to quantify it quantitatively (such as the gallon, quart, cubic inch). Volume and length (cubed) have a symbiotic relationship.

The density for helium remains lower than that of air, therefore when the balloon is inflated with that as well, it rises. The atmosphere's pressure continues to drop as it rises, which causes the internal pressure to rise. The balloon's volume of the balloon will increase.

Therefore, the volume of the balloon will increase.

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Increasing the distance between an electromagnet and the compass will cause the observed effect of the compass to decrease in strength

The strength of the magnetic field produced by an electromagnet decreases as the distance from the electromagnet increases. This means that if the distance between the electromagnet and the compass increases, the magnetic field that the compass is experiencing will weaken.

As a result, the observed effect of the compass will decrease in strength as the distance between the electromagnet and the compass increases.

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The value of resistor R that gives the circuit in the figure a time constant of 22 μs is 220 Ω.

The circuit that is in the figure is shown below:Given that time constant (RC) = 22 μs. To find the value of resistor R, we need to use the formula for the time constant:

RC = τ, where R is the resistance and C is the capacitance of the circuit.

Rearranging the above formula, we get:R = τ / C

Where τ is the time constant and C is the capacitance of the circuit.

From the figure, the capacitance is given as 0.1 μF

.Substituting the values of τ and C in the above formula, we get:

R = (22 × 10⁻⁶ s) / (0.1 × 10⁻⁶ F)

R = 220 Ω

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Answer:

a.  Frequency is 5.45 x 10^14 hz

b.   The period = 1.8 x 10^-15 sec  {or 1.8 femptoseconds]

Explanation:

The velocity of an electromagnetic wave is given by the product of the wave's frequency(f) times its wavelength(λ).  

V = λ f     where,

V is the wave speed,

f is the wave frequency,

λ is the wavelength.

To find frequency, rearrange to:

f = V/ λ

Light travels at 3.00x10^8 m/sec.

λ is 5.50 x 10^-7 m

f = (3.00x10^8 m/sec)/(5.50 x 10^-7 m)  meters cancels, secs is on the bottom]

f = (3.00/5.50)*(10^15)  [The base 10 exponent on the bottom ius subtracted from the one on top:  98-(-7)) = 15)  

f = 0.545 x 10^15 1/s or hz

f = 5.45 x 10^14 hz

b.  The period of a wave is the inverse of it's frequesncy.  It is the time it takes for 1 wave to pass.  Invert the frequency:

 Period = 1/f

  Period =  1/(0.545 x 10^15 1/s)

Period = 1.8 x 10^-15 sec  {or 1.8 femptoseconds]

Answer:

658.2 nm

Explanation:

Since the galaxy is moving at relavitistic speed, we use the equation for relativistic Doppler shift of light.

So, the wavelength of light observed on the Earth is λ

λ = λ'(\(\sqrt{\frac{ 1 + \frac{v}{c} }{1 - \frac{v}{c} } }\))

where  λ' = wavelength of light emitted by galaxy = 656 nm, v = speed of galaxy = 1000 km/s (positive since the galaxy is moving away from the Earth) and c = speed of light = 300000 km/s

So, substituting the values of the variables into the equation, we have

λ = λ'(√[{1 + (v/c)}/(1 - (v/c)]

λ = 656 nm(√[{1 + (1000 km/s/300000 km/s)}/(1 - (1000 km/s/300000 km/s)]

λ = 656 nm(√[{1 + 1/300}/(1 - 1/300]

λ = 656 nm(√[{(300 + 1)/300}/{(300 - 1)/300}]

λ = 656 nm(√[{(301)/300}/{(299)/300}]

λ = 656 nm(√[301/299])

λ = 656 nm(√1.0067)

λ = 656 nm × 1.0033

λ = 658.19 nm

λ ≅ 658.2 nm

So, the wavelength observed on Earth is 658.2 nm