Which verbal model represents the algebraic expression 5(n+1) ?
O five divided by the quantity of a number minus 1
O five divided by the quantity of a number plus 1
O five times the quantity of a number minus 1
five times the quantity of a number plus 1
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Answer:

12 hundereds

Step-by-step explanation:

Answer:

.8000+.4000

Step-by-step explanation:

I have nothing to go off on, but an equation that would fit for (1,2) is y=2x.

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hope it helps

If x is the largest of the three consecutive integers, then the three consecutive integers can be represented as x-1, x, and x+1.

The sum of these three consecutive integers is:

(x-1) + x + (x+1)

Simplifying the expression, we get:

3x

Therefore, the expression in terms of the given variables that represents the sum of three consecutive integers when x is the largest is 3x.

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Answer:

Hello! The answer to your question will be below.

Step-by-step explanation:

The answer would be clockwise.

So point k was rotated 90 degrees clockwise.....

Review.....

Question:

Point K is rotated 90 degrees. The coordinate of the pre-image point K was (2,-6) and it’s image K’ is at the coordinate (-6,-2).Find the direction of the rotation.

THE DIRECTION OF THE ROTATION WAS CLOCKWISE.

Hope this helps! :)

⭐️Have a wonderful day!⭐️

Answer:

clockwise.

So point k was rotated 90 degrees clockwise.....

Review.....

Question:

Point K is rotated 90 degrees. The coordinate of the pre-image point K was (2,-6) and it’s image K’ is at the coordinate (-6,-2).Find the direction of the rotation.

Step-by-step explanation:

This pattern is additive because when we add 6 to x we get y

12+6=18

24+6=30

48+6=54

60+6=66

so the answer is D

Answer:

28.3 units^2

Explanation:

The area A of the circle is given by the formula

where

π = 3.1415..

d = diameter of the circle.

Now, in our case d = 6; therefore,

Rounded to the nearest tenth this is

Answer:

the box diagonal is about 41.68

Step-by-step explanation:

yes the bat will fit but not by much

Answer:

The coordinates of the image are (10,6)

Step-by-step explanation:

Translation

A point located at (x,y), translated by (a,b) maps to the point (x+a,y+b).

If we know the location of the point (x,y) and the location of its image (x',y'), we can know the values of (a,b) by subtracting:

(a,b) = (x',y') - (x,y)

We know the coordinates of the point (4,9) and the coordinates of its image (9,13). Calculate the translation:

(a,b) = (9,13) - (4,9) = (5,4)

If the point (5,2) is translated under the same conditions, then it will map to the point (5,2) + (5,4) = (10,6).

The coordinates of the image are (10,6)

The final point after reflecting (-4, -7) twice across the x-axis is (-4, 7).To reflect a point across the x-axis, we change the sign of its y-coordinate while keeping the x-coordinate the same.

Given the initial point (-4, -7), let's perform the first reflection across the x-axis. By changing the sign of the y-coordinate, we get (-4, 7). Now, to perform the second reflection across the x-axis, we once again change the sign of the y-coordinate. In this case, the y-coordinate of the previously reflected point (-4, 7) is already positive, so changing its sign results in (-4, -7). Therefore, after reflecting the point (-4, -7) across the x-axis twice, the final point is (-4, 7). The reflection process can be visualized as flipping the point across the x-axis. Initially, the point (-4, -7) lies below the x-axis. The first reflection across the x-axis brings it to the upper side of the x-axis, resulting in (-4, 7). The second reflection flips it back down below the x-axis, yielding the final point (-4, -7).It's worth noting that reflecting a point across the x-axis twice essentially cancels out the reflections, resulting in the point returning to its original position. In this case, the original point (-4, -7) and the final point (-4, -7) have the same coordinates, indicating that the double reflection has brought the point back to its starting location.

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Answer:

Measure of arc TSU = 201°

Step-by-step explanation:

For the inscribed circle of  triangle XYZ, we have;

∠XZY = 21°

Segment TZ and segment  UZ are tangent to circle R

Therefore, ∠ZUR = ∠ZTR = 90° (angle formed by a tangent)

Length UR = Length TR = Radius of circle R

∴ ΔZTR ≅ ΔZUR Side Angle Side (SAS) rule of Congruency

∴ ∠RZT ≅ ∠RZU, (Congruent Parts of Congruent Triangles are Congruent, CPCTC)

∠XZY = ∠RZT + ∠RZU (Angle summation)

21° = ∠RZT + ∠RZU  = 2×∠RZU (Transitive property)

∠RZU = 21°/2 = 10.5° = ∠RZT

∴ ∠URZ = 180- 90 - 10.5 = 79.5° = ∠TRZ (CPCTC)

arc TU = ∠URT = ∠URZ + ∠TRZ = 79.5 + 79.5 = 159° (angle addition)

∴ Measure of arc TSU = 360° - 159° = 201° (Sum of angles at the center of the circle R)

Measure of arc TSU = 201°.

\(5y = 6x + 21 \\ y = \frac{6}{5} x + \frac{21}{5} \)

y intercept:

\(y = \frac{21}{5} \)

The solution to the trigonometric equation with sine function is x = 2.5.

Starting with 3√2 sin π/3 (x − 2) + 4 = 7:

First, we can simplify 3√2 sin π/3 to 3, since sin π/3 = √3/2 and 3√2 = 3 x √2 x √2 = 3 x 2 = 6.

6(x - 2) + 4 = 7

6x - 12 + 4 = 7

6x - 8 = 7

6x = 15

x = 2.5

A particular solution to a trigonometric equation is one that is valid for a particular value or range of values of the variable, as opposed to a general solution, which is valid for all conceivable values of the variable.

Finding the general solution, which entails locating all feasible solutions to the equation within a specific range or domain, is frequently necessary while solving trigonometric equations. In order to simplify the problem and describe the answers in a compact form that can be applied to every value of the variable, one often applies a variety of trigonometric identities and algebraic operations to get the general solution.

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From the given picture, we can relate sides a and x by means of the tangent function as follows:

by moving a to the left hand side, we have

since a=45 and tan41=0.869, we get

Then, by roundinf the nearest hundredths the answer is 39.12

Answer: 1 by 20, 2 by 19, 3 by 18, 4 by 17, 5 by 16, 6 by 15, 7 by 14, 8 by 13, 9 by 12, 10 by 11.

The initial value problem. y'(t) = 1 + e^t, y(0) = 20 The specific solution is y(t)= t + e^t + 19.

Let's go step-by-step:
1. Identify the problem: We are given a differential equation y'(t) = 1 + e^t and an initial value y(0) = 20.

2. Integrate the differential equation: To find y(t), we need to integrate the given equation with respect to t.
  ∫(y'(t) dt) = ∫(1 + e^t dt)

3. Perform the integration: After integrating, we obtain the general solution of the problem:
  y(t) = t + e^t + C, where C is the constant of integration.

4. Apply the initial value: We are given y(0) = 20, so we can plug this into the general solution to find the specific solution.
  20 = 0 + e^0 + C
  20 = 1 + C

5. Solve for the constant of integration C: From the above equation, we find the value of C.
  C = 19

6. Write the specific solution: Now that we have the value of C, we can write the specific solution for y(t).
  y(t) = t + e^t + 19

So, the specific solution for this initial value problem is y(t) = t + e^t + 19.

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Answer: y = -3x + -0.25

Step-by-step explanation:

-3 (Slope)

X (Term)

B (Initial Value aka. Y - Intercept)

Find Initial Value

y = mx + b

-4 = -3 (1.25) + b

-4 = -3.75 + b

-0.25 = b

Instead of ( 1 - 4) all satisfy the equation

hope it helps

Answer:

subs 3 and 4 into the equation and then compare the two equation to get the value of two constants p n q

Rate of the jet in still Air is 716 miles per hour and

wind speed is 80 miles/hour.

The velocity of an item in relation to another observer is known as its relative velocity. It is the pace at which one item's relative location changes in relation to another object over time. When two bodies are travelling in opposing directions, their relative velocity is at its highest. They are approaching one another.

Let ‘X’ be speed of jet and

'Y’ be speed of Wind

Relative velocity when jet travels against wind: X - Y = ( 2544 / 4 ) = 636 miles/hour

Relative velocity when jet travels with wind is: X + Y = ( 3184 / 4 ) = 796 miles/hour

By adding these two equations we will get

2 X = 1432 or X = 716 miles /hour and

or, Y = 796 - 716 = 80 miles/hour

Hence,

Rate of the Jet in still Air is 716 miles per hour and

Wind speed is 80 miles/hour.

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The inequalities and their graphs are;

1)  -x - 5 ≤ -2 is represented by the third graph

2) 6 + x ≤ 3 is represented by the fourth graph

3) x - 4 < -7 is represented by the second graph

4) 2x > -6 is represented by the first graph

1) We are given the inequality;

-x - 5 ≤ -2

Rearranging gives us;

-x ≤ -2 + 5

- x ≤ 3

Divide both sides by -1 to get;

x ≥ -3

The graph must be a closed circle starting at -3 and pointing to the right.

It is the third graph in the link at the end of this answers.

2) We are given the inequality; 6 + x ≤ 3

Rearranging gives;

x ≤ -6 + 3

x ≤ -3

The graph must be a closed circle starting at -3 and pointing to the left. Thus, it is the fourth graph.

3) We are given the inequality; x - 4 < -7

Rearranging gives us;

x < -7 + 4

x < -3

The graph must be an open circle starting at -3 and pointing to the left.

Thus, it is the second graph.

4) We are given the Inequality; 2x > -6

Divide both sides by 2 to get;

x > -6/2

x > -3

It must be a graph with an open circle starting at -3 and then to the right.

Thus, it is the first graph as seen in the attached link

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Answer:lol

Step-by-step explanation: supercalifragelesticexpialidocious

Answer: 18 inches

Step-by-step explanation:

2 x 6 = 12 inches (wide)

3 x 6 = 18 inches (tall)

The statement "In the statement ~(M ⊃ X)~) governs the simple statement M" is false

From the question, we have the following parameters that can be used in our computation:

In the statement ~(M ⊃ X)~) governs the simple statement M.

In logic and binary, the negation of an implication (M ⊃ X) is written as ~(M ⊃ X), which is read as "not (M implies X)".

This statement does not govern or control the simple statement M. The simple statement M can be true or false independently of the negation of the implication.

In other words, the truth value of ~(M ⊃ X)is dependent on the truth values of both M and X, not just M.

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An inequality equation to determine the amount of money she will spend is x > 6

Mae wants to make more than 6 gift baskets for the school raffle. Each gift basket costs $15.50. To determine the amount of money she will spend to make these gift baskets, we can write an inequality.

Let's assume that the number of gift baskets Mae wants to make is represented by the variable "x". The inequality can be written as follows: 15.50x > 6 * 15.50.

This inequality equation states that the total cost of the gift baskets, which is represented by 15.50 times the number of gift baskets (x), must be greater than the cost of 6 gift baskets (6 * 15.50).

Alternatively, we can rewrite the inequality as 15.50x > 93, which states that the total cost of the gift baskets must be greater than $93 if Mae wants to make more than 6 gift baskets.

Finally, we can simplify the inequality to x > 6, which states that the number of gift baskets Mae wants to make must be greater than 6 in order for her to spend more than $93 on the gift baskets.

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Answer:

2x + 3y - 1 = 0

5x + 2y + 3 = 0

10x + 15y - 5 = 0

10x + 4y + 6 = 0

11y + 1 = 0

11y = -1

y = -1/11

2x + 3 × -1/11 - 1 = 0

2x - 3/11 - 1 = 0

2x = -14/11

x = -7/11

ok but where are the cases ?!

Answer:

the answer is 3n+7 please do you get it

The rate of increase in the radius is larger because, as the radius increases, the rate of change in the volume increases as well.

(a) The rate at which the volume of the balloon is increasing can be found by using the formula for the volume of a sphere: V = (4/3)πr3. Differentiating this with respect to time gives the rate at which the volume is increasing: dV/dt = 4πr2(dr/dt). When r = 5.20 cm and dr/dt = 0.840 cm/s, the rate at which the volume is increasing is 4π(5.20 cm)2(0.840 cm/s) = 4.15 cm3/s.

(b) When the radius is 13.90 cm, the rate at which the volume is increasing is 4π(13.90 cm)2(dr/dt). For this rate to remain constant, dr/dt must increase. Thus, the rate at which the radius is increasing must be larger than 0.840 cm/s.

(c) Physically, this is because the rate of change in the volume of the balloon increases as the radius increases. As the radius increases, the surface area of the balloon increases, allowing more air to enter the balloon. Thus, in order to maintain a constant volume rate, the rate of increase in the radius must also increase.

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Griffith's criteria for fast fracture in an ideal brittle material provide a framework for assessing the conditions necessary for rapid fracture. This theory is only applicable to brittle materials and assumes sharp, circumferential cracks with a small radius compared to the crack length.

By calculating the critical crack length using the formula σ = KIc/√(πa), we can determine the crack length required for propagation. In the example provided, the critical crack length for a nickel alloy is larger (1.73 × 10−6 m) compared to Sic ceramic (2.31 × 10−8 m). This implies that the nickel alloy can withstand more damage before fracturing, making it more suitable for applications such as compressor blades in jet engines.

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