Which type of force occurs between two objects at a distance?

A. Applied force
B. Contact force
C. Non-contact force
D. Normal force
If your right you get 100 points & brainliest

Answer:

18 kg * m/s

Explanation:

The equation for momentum is:

momentum = mass * velocity

And although the problem already gave velocity, you must calculate the mass from the graviational force.

Fg = 3.4N = mg = 9.8m

mass = 3.4 N / 9.8 m/s^2 = 0.3469 kg

Momentum = 52m/s * 0.3469 kg - 18.041 kg * m/s = 18

Answer:

75 cm/second.

Explanation:

Formula:

Walking speed = stride length / time per step

Walking speed = 90cm/time per step

                         = 90cm/1.2 seconds (a common estimate time per step)

                         = 75cm/second.

Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that:

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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Answer:

Conduction

Explanation:

Conduction is a process whereby heat is transfer through solid state.

Answer:

Explanation:

A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:

Output force = Weight of object = m * g

where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:

Output force = 15 kg * 9.81 m/s^2 = 147.15 N

Therefore, the output force required to lift a 15 kg object would be 147.15 N.

B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.

C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:

Mechanical advantage = Output force / Input force = 40 N / 10 N = 4

So, the ramp multiplies your force by a factor of 4.

Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.

Answer:

No. A:

1-tension

No. B:

4-the string

Explanation:

The upward force that acts on the book is called "tension" while the "string" is the object that exerts a force on the block that is directed to the right.

As the string is pulled, the tension exerts an upward force on the block. The frictional force acts on the block to the left. So, both the tension and friction will act on the block in order to effect its pulling on the surface of the table.

A ray diagram with given information gives an image location of 10.7 cm on the ruler. This method helps determine characteristics of images formed by lenses.

To build a beam graph to decide the picture area, we first need to draw an outline with the given data. We start by defining an upward boundary to address the focal point, with the ruler and the dark spot on one or the other side of it. We then, at that point, draw a bolt on the left half of the focal point at the 3.0 cm mark.

Then, we draw three beams from the bolt. The primary beam is attracted lined up with the important pivot and goes through the point of convergence on the right half of the focal point.

The subsequent beam goes through the focal point of the focal point and go on in an orderly fashion. The third beam goes through the point of convergence on the left half of the focal point and becomes lined up with the essential pivot subsequent to going from the perspective.

Where these three beams cross on the right half of the focal point is the picture area. For this situation, the beams converge at a point situated at 10.7 cm on the ruler, which is the response to the inquiry. Thusly, the picture is situated at 10.7 cm on the ruler.

This strategy for developing a beam graph is a valuable apparatus in deciding the area and qualities of pictures shaped by focal points, and is a significant idea in the investigation of optics.

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The force required to rescue in the swimming pool with a mass of 60 kg is 588N and the pressure exerted in the area of 0.5 m² is 1.176×10³Pa.

Force is defined as the push or pull of an object. Force equals the product of the mass and acceleration of the object. Acceleration is defined as the rate of change of velocity per unit time. The force also equals the rate of change of momentum per unit of time. The unit of force is Newton (N).

Pressure is defined as the force applied perpendicular to the surface area. It equals the ratio of force per unit area and the unit of pressure is Pascal (Pa).

From the given,

mass of the swimmer's body (m) = 60 kg

Acceleration. due to gravity (g) = 9.8m/s²

area (A) = 0.5 m²

Force, F = m×a

F = 60×9.8

  = 588 N

The force to rescue the swimmer's body is 588N.

Pressure  = Force/Area

               = 588 / 0.5

               = 1176 Pa

               = 1.176×10³Pa

The pressure exerted on the body is 1.176×10³Pa.

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According to Faraday's law, the various magnetic flux via a closed loop induces an emf in it, given by E=−dϕdt so the current in the resistor during this time is 0.81818 A.

Here we have;

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Answer:

The parents and offspring all have phenotype ww. That leaves 100% probability of short wings and 0% long wings.

Explanation:

If long wings are a dominant trait, that means short wings are recessive. If two short winged flies are crossed, each of their phenotypes are ww. Therefore, each of their offspring also have phenotype ww, or short wings.

Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.

Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.

Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.

Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.

To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.

For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.

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Answer:

first

Explanation:

also wat u need help with

Please find attached photographs of your answer. Hope it helps. Please do comment

Answer:

decrease

Explanation:

weight

As water accumulates in the car, its speed decrease according to Newton's second law of motion

Newton's second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

according to newton's second law

force = mass * acceleration

as water accumulate in the car , mass will increase

since mass and acceleration are inversely proportional to each other

hence , acceleration will decrease and speed will decrease

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Answer:

when air or water cools it sinks

Answer:

hope this helpes!!

Explanation:

plz mark brainliest

The nuclear equation for the alpha decay of astatine-213 is shown below:

²¹³₈₅At ⇒   ²⁰⁹₈₃X +  ⁴₂He

²¹³₈₅At ⇒   ²⁰⁹₈₃Bi +  ⁴₂He

This is derived by calculating a and b of the new element.

²¹³₈₅At ⇒   ᵇₐX +  ⁴₂He

213 = b + 4

213-4 = b

209 =b

b= 209

85= a+2

85-2 = a

83=a

a=83

The alpha decay of Astatine-213 forms the element known as Bismuth.

Astatine has an atomic number of 85. Alpha decay involves an element

being split into a new element and a Helium ion.

The atomic mass is usually decreased by 4 and the atomic number is usually

decreased by 2 which gives rise to  the element Bismuth which is denoted by

²⁰⁹₈₃Bi

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The required quarts that is equals to 5 pounds of ethanol would be 3 quarts if the density of ethanol is 0.789 g/mL.

Density is the ratio of mass and volume.

density = mass/volume

The density of ethanol is 0.789 g/mL.

Convert pounds to grams

∵ 1 pounds = 453.592 grams

∴ 5 pounds = 2267.96 grams

So the mass of ethanol would be 2267.96 grams

Density Equation

density = mass/volume

Solve for volume.

volume = mass / density

volume = 2267.96 g / (0.789 g/mL)

volume = 2267.96 g / (0.789 g/mL)

volume = 2874.47 mL

Convert milliliters to quarts.

∵ 1 mL = 0.00105669 quarts

⇒ 2874.47 mL × 0.00105669 qt /1 mL

⇒ 3 quarts

Hence, the volume of ethanol would be 3 quarts.

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The schrodinger's equation for \((A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)\) for the particular U and E can be expressed as \((A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)=E(A\Psi_1+B\Psi_2)\).

The solution to the equation is based on Fourier's Eigen Values method. This is the expression for any mathematical function as the sum of an infinite series of other periodic functions. The trick is to find the right functions with the right amplitudes so that when they are superimposed, they give the desired solution.

As a result, the solution to Schrondinger's equation, the system's wave function, was replaced by the wave functions of the individual series, natural harmonics of each other, resulting in an infinite series. Shrodinger discovered that replacement waves described individual states of the quantum system, and their amplitudes indicated the relative importance of that state to the entire system.

The schoringer 's equation is

\(-\frac{h^2}{2m}\frac{d\psi^2}{dx^2}+U(x) \psi=E\psi\)

here, the E is the energy of the particle.

since the wave function \(\psi_1\) is the solution of the schrodinger's equation,

\(-\frac{h^2}{2m}\frac{d\psi_1^2}{dx^2}+U(x) \psi=E\psi_1\)

Since, the wave function \(\psi_2\) is the solution of the schrodinger's equation,

\(-\frac{h^2}{2m}\frac{d\psi_2^2}{dx^2}+U(x) \psi=E\psi_2\)

Then,

\((A\phi_1+AU\Psi_1)+(B\phi_2+BU\Psi_2)=(A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2})+AU\Psi_1)+(B(-\frac{h^2}{2m}\frac{d\Psi^2}{dx^2})+BU\Psi_2)\\\\=A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U\Psi_1)+B(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U\psi_2)\\\\=A(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U(x)\Psi_1)+B(-\frac{h^2}{2m}\frac{d\Psi_1^2}{dx^2}+U(x)\psi_2)\\\\=A(E\Psi_1)+B(E\Psi_2)\\\\=E(A\Psi_1+B\Psi_2)\)

Thus, the schrodinger's equation  for particular U and E can be expressed as \(E(A\Psi_1+B\Psi_2)\).

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Your question is incomplete, here is the complete question in the figure,

Answer:

Check how much energy was released during the reaction or check for a change in total mass

The objective of a heat engine is to transform heat into work. So, correct option is A.

A heat engine is a device that converts thermal energy (heat) into mechanical work. It operates by absorbing heat from a hot source, such as a furnace, and converting it into useful mechanical energy, such as rotating a shaft or driving a machine. The efficiency of a heat engine is determined by the difference between the temperature of the hot source and the temperature of the cooled working fluid (usually air or water). Examples of heat engines include internal combustion engines in cars, steam turbines in power plants, and Stirling engines in heat pumps and refrigeration systems.

The objective of a heat engine is to transform heat into work. A heat engine is a device that uses heat energy from a high-temperature source to perform mechanical work by using a thermodynamic cycle. The basic idea behind a heat engine is to extract thermal energy from a high-temperature source, convert some of this energy into useful mechanical work, and then reject the remaining heat to a lower-temperature sink. The efficiency of a heat engine is determined by the amount of thermal energy that is converted into useful work and the amount of heat that is rejected to the lower-temperature sink.

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The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.

Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.

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According to the question, the impact of an electric car to reach its top speed is found to be 51 sec.

Acceleration may be defined as the process of the rate of change of the velocity of an object with respect to time. It is a vector quantity as it has both magnitude and direction.

According to the question,

The acceleration of an electric car = 1.6 m/s²

The speed of an electric car = is 296 km/hour = 1000 m/hour. = 82.2 m/sec.

The acceleration of any moving object is calculated with the help of the following formula:

         1.6 m/s²            =  82.20 - 0/t

           t = 51.45 sec ≅ 51 seconds.

Therefore, the impact of an electric car to reach its top speed is found to be 51 sec.

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Answer:

12345678901234567890

As 500 kg of supplies are added to the truck, the gravitational force between the two vehicles rises from 1.27 106 N to 1.33 106 N.

As a result, when the space between the objects is cut in half, the gravitational force multiplies by four.

The Newton's Law of Universal Gravitation can be used to compute the gravitational force between the two vehicles: F = G * (m1 * m2) / d²

Plugging in the values given in the problem, we get:

F = 6.6743 × 10⁻¹¹ * ((3,650 kg) * (9,850 kg)) / (25.0 m)²

F = 1.27 × 10⁻⁶ N

As a result, there is 1.27 106 N of gravitational force between the two vehicles.

The separation between the two vehicles stays constant. Hence, after entering the updated values, we obtain:

F = 6.6743 × 10⁻¹¹ * ((3,650 kg) * (10,350 kg)) / (25.0 m)²

F = 1.33 × 10⁻⁶ N

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Answer:

partecls

Explanation:

because they are to small to see with plain eyes

Answer:

1600

Explanation:

Answer:

!!!2400!!!

Explanation:

Answer:

Sources:

-- https://intblog.onspot.com/en-us/why-do-bridges-become-icy-before-roads

and

-- https://www.accuweather.com/en/accuweather-ready/why-bridges-freeze-before-roads/687262

I hope this helps you! ^^

The audience for the 9th grade physics MCAS is students in the 9th grade who are taking the Massachusetts Comprehensive Assessment System (MCAS) physics exam.

The exam is designed to assess students' knowledge and skills in physics, and it is used to make decisions about students' placement in courses, graduation requirements, and eligibility for college and career programs.

The 9th grade physics MCAS is a multiple-choice exam that consists of 50 questions. The questions are based on the Massachusetts Curriculum Framework for Science, which outlines the standards that students are expected to meet in physics.

Students who take the 9th grade physics MCAS must score at least proficient in order to meet the state's graduation requirements. Students who score below proficient may be required to take additional courses or remediation.

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One of the advantages of reverberation is that it enhances the quality of a sound and one disadvantage is that when the reverberation is in excess it creates unpleasant sound.

Reverberation is the phenomenon of persistence of sound after it has been stopped as a result of multiple reflections from a given surfaces.

The advantages of reverberation include the following;

The disadvantages of reverberation include the following;

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