Which two statements describe what happens in both nuclear fusion and nuclear fission reactions?
Answers
Answer:
.
Fusion powers the Sun and stars as hydrogen atoms fuse together to form helium, and matter is converted into energy.
nuclear fission reactors include the possibility of radiation-releasing nuclear accidents, the problems of radioactive waste disposal, and the possibility of contributing to nuclear weapon proliferation
Related Questions
parallel adaptive fluid–structure inter- action simulation of explosions impacting on building structures.
Answers
The phrase "parallel adaptive fluid–structure interaction simulation of explosions impacting on building structures" refers to a computational method used to study the effects of explosions on buildings. Let's break it down step by step:
"Parallel adaptive": This refers to the use of parallel computing techniques, where multiple processors or cores work together to solve the simulation problem faster. It allows for efficient computation of complex simulations by dividing the workload.
"Fluid–structure interaction": This term describes the interaction between a fluid (such as air or water) and a solid structure (such as a building) in a simulation. It considers how the fluid affects the structure and vice versa. In this case, it refers to how the explosion impacts the building and how the building responds to the explosion.
"Simulation of explosions impacting on building structures": This means that the simulation aims to model the effects of explosions on buildings. It can help researchers and engineers understand how buildings behave under explosive forces, and can be used to design safer structures or develop strategies to mitigate the damage caused by explosions.
The phrase refers to a computational method that uses parallel computing techniques to simulate the interaction between fluids and structures, specifically focusing on explosions impacting building structures. This simulation can provide valuable insights into the behavior of buildings under explosive forces.
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The mass of a cannon ball is 10 kg. If the speed of the cannon ball is 50 m/s in
position A and E (just before hitting the ground), Calculate:
Answers
Answer:
Explanation:
Kinetic Energy = 0.5(Mass)(Velocity2)
Kinetic energy= 0.5 × 10kg × (50m/s)2
Kinetic Energy = 5kg × 2500m/s
Kinetic energy = 125000 J ( Ans)
The figure shows three objects that are all made of the same material. The forces applied to the three objects all have the same magnitude.
Order the objects according to the shear stress acting on them, from greatest to least.
a) (iii) > (i) = (ii)
b) (i) = (ii) > (iii)
c) (i) > (iii) > (ii)
d) (i) > (ii) = (iii)
e) (i) > (ii) > (iii)
Answers
Shear stress is tangential tension that results from fluid moving against resistance against a solid surface. therefore (iii) > (i) = (ii) option a).
What is tangential shear stress?An item experiences deformation when an exterior force works upon it. if the force's orientation is parallel to the object's surface. Along that line, there will be a distortion. The item in this instance is under tensile or tangential tension.
The stress an object experiences is known as shearing stress or tangential stress when the path of the deforming force or exterior force is parallel to the cross-sectional area.
Shear stress results from forces that are parallel to and reside in the plane of the cross-sectional area, whereas normal stress results from forces that are perpendicular to a cross-sectional area of the substance.
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a) If these two particles are a closed system, what do you know about the total energy as their separation changes? b) In general, what is the minimum value of KE that a system of particles can have? c) Use your response to the two previous parts of this question and the fact that the total energy is equal to -0.8e to determine the two values of r where KE is minimum. d) Explain how your responses to all of the above determine the range of possible values of the separation of the two particles for this total energy
Answers
Answer:
In a closed system, the total energy remains constant as the separation between the two particles changes. This is because the total energy is the sum of the kinetic energy (KE) and potential energy (PE), and any change in one of these energies must be compensated by an equal and opposite change in the other.
Explanation:
a) If these two particles are a closed system, the total energy of the system will remain constant as their separation changes. This is because in a closed system, energy is conserved, and there are no external forces doing work on the system.
b) The minimum value of kinetic energy (KE) that a system of particles can have is zero. This occurs when the particles are at rest or have no relative motion. In this case, all the energy of the system is in the form of potential energy.
c) Given that the total energy is equal to -0.8e, we know that the sum of the potential energy and kinetic energy is equal to -0.8e. Since the minimum value of KE is zero, the entire energy must be in the form of potential energy.
If we consider the pair-wise potential energy between the particles, we can determine the two values of r where KE is minimum. These values occur when the potential energy is maximum. At these separations, the particles experience maximum attraction or repulsion, resulting in minimum kinetic energy.
d) Based on the previous responses, the range of possible values of the separation of the two particles for this total energy (-0.8e) corresponds to the range where the potential energy is maximum. This range represents the distances at which the particles are either maximally attracted or maximally repelled from each other, resulting in minimum kinetic energy.
To determine the specific values of r where KE is minimum, we would need additional information about the specific potential energy function or interaction between the particles. Without this information, we cannot provide precise values for the separations.
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A magnet is hung by a string and then' placed near a wire as shown. When the switch is closed, the magnet rotates such that the ends of the magnet move as indicated by the arrows. At the instant the switch is closed determine: the direction of the current through the wire segment nearest the magnet. Explain. the direction of the force exerted by the magnet on the wire segment (assume the magnet is in the position shown). Explain.
Answers
The current through the wire segment is determined by the right-hand rule, while the force exerted is determined by the left-hand rule.
The direction of the current through the wire segment nearest the magnet can be determined using the right-hand rule. If we point our right thumb in the direction of the magnetic field created by the magnet, and then curl our fingers around the wire, the direction in which our fingers curl represents the direction of the current. The specific direction will depend on the orientation of the magnet's poles and the wire.
The direction of the force exerted by the magnet on the wire segment can be determined using the left-hand rule. If we extend our left hand, with the thumb pointing in the direction of the current flowing through the wire, and the fingers pointing in the direction of the magnetic field created by the magnet, the palm of our hand will indicate the direction of the force.
The force exerted by the magnet on the wire segment will be perpendicular to both the current and the magnetic field, and its specific direction will depend on the orientation of the magnet's poles and the wire.
It's important to note that the specific directions will vary depending on the orientation and configuration of the magnet and the wire in the given setup.
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A boy runs on a circular path of radius R = 28 m with a constant speed u = 4 m/s. Another boy starts from the centre of the path to catch the first boy. The second boy always remains on the radius connecting the centre of the circle and the first boy and maintains magnitude of his velocity constant V = 4 m/s. If the time of chase is (10 + x) sec then
Answers
Answer:
We can solve this problem by using the concept of relative motion. Let's assume that the first boy is running in the clockwise direction and the second boy is chasing him in the counterclockwise direction.
Since the second boy always remains on the radius connecting the center of the circle and the first boy, the distance between them is always equal to the radius of the circle, which is 28 m.
Let's denote the distance covered by the first boy as S1 and the distance covered by the second boy as S2. We know that the first boy is running with a constant speed of 4 m/s, so we can write:
S1 = u*t1
where t1 is the time taken by the first boy to complete the chase.
The second boy is moving with a constant velocity of 4 m/s towards the first boy, so we can write:
S2 = V*t2
where t2 is the time taken by the second boy to catch up with the first boy.
Since the second boy is always moving on the radius connecting the center of the circle and the first boy, the distance covered by him is equal to the distance on the circumference of the circle covered by the first boy, minus the distance covered by the first boy along the radius. We can write:
S2 = S1 - 2*pi*R
where pi is the mathematical constant pi (approximately equal to 3.14).
Substituting the values of S1 and S2, we get:
u*t1 = V*t2 + 2*pi*R
Since the time of chase is (10 + x) sec, we can also write:
t1 + t2 = 10 + x
We have two equations and two unknowns (t1 and t2), so we can solve for them. First, we can solve for t2:
t2 = (u*t1 - 2*pi*R) / V
Substituting this in the second equation, we get:
t1 + (u*t1 - 2*pi*R) / V = 10 + x
Simplifying this equation, we get:
t1*(1 + u/V) = 10 + x + 2*pi*R/V
Finally, we can solve for t1:
t1 = (10 + x + 2*pi*R/V) / (1 + u/V)
Substituting the given values of R, u, and V, we get:
t1 = (10 + x + 56*pi) / 20
Simplifying this expression, we get:
t1 = 2.8*pi + 0.5*x + 2.8
Therefore, the time taken by the first boy to complete the chase is 2.8*pi + 0.5*x + 2.8 seconds.
Explanation:
this gives me nightmare
will the star of bethlehem be visible on december 21st
Answers
Answer:
The best time to view the spectacle on Dec. 21 will be around an hour after sunset.
There are 2 rocks sitting on 2 cliffs. One rock is sitting on a cliff that is 25 m high. The
other rock is sitting on a cliff that is 12 m high. Which rock has the greater gravitational
potential energy?
Explain.
Answers
The rock sitting on the cliff that is 25 m high has the gratest gravitational potential energy.
How do I determine the rock that has a greater potential energy?Potential energy is defined as the energy of an object by virtue of it's location. Mathematically, it is written as:
PE = mgh
Where
PE is the potential energym is the mass g is the acceleration due to gravityh is the heightTo determine the rock with the grater potential energy, we shall determine the potential energy of both rock assuming they have the same mass. Details below:
For rock sitting at 25 m high:
Mass (m) = 10 KgHeight (h) = 25 mAcceleration due to gravity (g) = 9.8 m/s² Potential energy (PE) = ?PE = mgh
PE = 10 × 9.8 × 25
PE = 2450 J
For rock sitting at 12 m high:
Mass (m) = 10 KgHeight (h) = 12 mAcceleration due to gravity (g) = 9.8 m/s² Potential energy (PE) = ?PE = mgh
PE = 10 × 9.8 × 12
PE = 1176 J
From the above calculation, we have:
Potential energy of rock at 25 m high = 2450 JPotential energy of rock at 12 m high = 1176 JThus, we can conclude that the rock sitting at 25 m high, has the gratest potential energy.
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Assume the supports of the uniform cantilever (m= 2900 kg) are made of wood. Calculate the minimum cross-sectional area required of each, assuming a safety factor of 9.0. Fa (20.0 m), Fb, center of gravity (distance from Fb to end is 30.0 m)
Answers
the minimum cross-sectional area required for each support, assuming a safety factor of 9.0 and a compressive strength of 40 MPa for the wood supports, is 99.58 mm^2 for support A and 14.88 mm^2 for support B.
To calculate the minimum cross-sectional area required for each support, we need to first determine the maximum force that each support will experience.
Assuming a uniform cantilever with a mass of 2900 kg and a length of 50.0 m (20.0 m to support A and 30.0 m to the center of gravity at point B), we can calculate the total weight of the cantilever as:
W = m*g = 2900 kg * 9.81 m/s^2 = 28,449 N
At support A, the maximum force will be equal to the weight of the cantilever plus any additional loads or forces applied to the cantilever at that point. Since no additional loads or forces were specified, we can assume that Fa = W = 28,449 N.
At point B, the maximum force will be equal to the weight of the portion of the cantilever from point B to the end, which is:
Wb = (m/2)*(Lb/L) * g = (2900/2)*(30.0/50.0)*9.81 = 4262 N
To determine the minimum cross-sectional area required for each support, we need to consider the maximum stress that the supports will experience. Assuming a safety factor of 9.0, the maximum stress can be calculated as:
σmax = Fmax/SF
Where Fmax is the maximum force on the support and SF is the safety factor.
Assuming a compressive strength of 40 MPa for the wood supports, the minimum cross-sectional area required for each support can be calculated as:
Amin = Fmax/(σmax)
For support A, the minimum cross-sectional area required is:
Amin,A = Fa/(σmax*SF) = 28,449 N/(40 MPa*9.0) = 99.58 mm^2
For support B, the minimum cross-sectional area required is:
Amin,B= Wb/(σmax*SF) = 4262 N/(40 MPa*9.0) = 14.88 mm^2
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a 44 kg package is dropped by a parachute out of an airplane. what is the terminal speed of the package if the parachute has an area of 25 square meters. (use air density, p= 1.2kg/m^3
Answers
Terminal velocity of the package is 5.16 m/s
When the object's drag force is equal to the gravitational force then it experiences zero acceleration and so the velocity remains constant. Such constant velocity is called as terminal velocity.
Drag force is a kind of frictional force that opposes the flow of motion.
Mathematically drag force F = \(\frac{1}{2}\)ρA\(v^{2}\)
ρ = density of the package = 1.2 kg/\(m^{3}\)
A = 25 \(m^{2}\)
v = terminal speed
Also Force is the product of mass and acceleration
Mathematically F = ma
where
m = 44 kg
a = 10 m/\(s^{2}\)
Therefore, F = 44 * 10 = 400 N
Putting value of F in the drag force equation we get,
400 = \(\frac{1}{2}\)ρA\(v^{2}\)
400 = \(\frac{1}{2}\) * 1.2 * 25 * \(v^{2}\)
\(v^{2} = \frac{400*2}{1.2 * 25}\)
\(v^{2} = \frac{800}{30}\)
v = \(\sqrt{26.66}\)
v = 5.16 m/s
The terminal speed of the package if the parachute has an area of 25 \(m^{2}\) is 5.16 m/s.
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a. What is the Kinetic Frictional Force on the Sled?(40 N)
b. If the weight of the sled is 200 N, what is the co-efficient of Kinetic Friction (uk) between
the sled and snow?(0.20)
c. If 30 kg of wood is placed in the sled, what pulling force is needed to move the
sled at constant velocity?(98.8 N)
Answers
Answer:
Given:
Pulling force= 40N
Mass of sled= 200N
Weight of wood= 30kg= 30 X 9.8N = 294N
Solution:
a) Since the sled is moving with constant velocity
⇒ net acceleration on sled= 0
⇒ net force on sled= 0
⇒ Pulling force= frictional force
⇒ Frictional force= 40N
b) Frictional force= μ N = μ mg
or 40 = μ X 200
or μ= 0.2
c) If 30 kg of wood is placed in the sled, new normal reaction= 294 + 200N
Pulling force required= frictional force
= μ N'
= 0.2 X 494
= 98.8N
While analyzing smoke detector designs that rely on the photoelectric effect, you are evaluating surfaces made from each of the materials listed in (Figure 1). One particular application uses ultraviolet light with wavelength 273 nm
Answers
Photodetectors that rely on the external photoelectric effect are known as photoemissive detectors (sometimes spelled photoelectric detectors).
A photocathode of some kind is present in such a device, where incident light is partially absorbed to produce photoelectrons, which are released into free space.
The light reflected off of particles by a light beam inside the sensor chamber is used by smoke detectors to detect smoke. When there are no particles in the sensing chamber, the beam's light does not hit the light detector, signaling that everything is in order.
Ionization smoke alarms detect smoke from rapidly blazing fires, while photoelectric smoke detectors are best for detecting smoke from smoldering fires.
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Which is a longer distance; 150 inches or 13 feet?
Answers
Step by step
13 feet is 156 inches (12 inches per foot x 13)
Compared with 150 inches
13 feet is longer than 150 inches
8) The weight of a pony standing still on Earth is 1025N.
What is the pony's mass?
A)
m=
g
g
1025 N
9.8 m/s²
JP
C) Where will the pony weigh the least (Moon, Jupiter, impossible)?
pick one of these three
D) Where will the pony have less mass (Moon, Jupiter, impossible)?
pick one of these three
Answers
Explanation:
mass = newton ÷ g
m = 1025 ÷ 10
mass= 102.5kg
3
Question 2 (1 point)
If a runner is racing at a velocity of 1.7 m/s North for 3.0 seconds, how far did they
run?
5.1 m [N]
0.57 m IN)
57 m
51 m[N]
O 1.8 m [N]
Answers
Answer:
A, 5.1 m [N]
Explanation:
1.7 times three equals 5.1, and since the runner was running north, the direction was north.
Guys I need help I will make brainliest!!
Comes with no word bank btw
Answers
Answer:
When an object applies a force on another object, the second object applies a force of the SAME amount/magnitude on the first object, but the force is in the opposite direction.
Which of the following is an example of a dry lubricant? oil grease graphite petroleum
ANSWER ASAP WILL GIVE BRAINLIEST!
Answers
Answer:
Dry lubricants or solid lubricants are materials that, despite being in the solid phase, are able to reduce friction between two surfaces sliding against each other without the need for a liquid oil medium.
Explanation:
Answer:
Your answer is graphite :) Have a nice day
Explanation:
You are ask to bring a cylindrical rod of length 45cm and diameter of 4.53cm to a mechanic. what is the weight of the aluminum rod if the density is 3.7*10^3kg/m^3
Answers
26.676 × 10³ kg is the weight of the aluminum rod.
To calculate specific weight:Given:
Length of cylindrical rod (h) = 45 cm
Diameter of a cylindrical rod = 4.53 cm
Radius of a cylindrical rod (r) = 2.3 cm
The density = 3.7*10^3kg/m^3
Volume of a cylindrical rod = πr²h
= 3.14× (2.3)² × 45
= 747.89 cm
= 7.4789 m
To find weight ;
ρ = \(\frac{Mass}{Volume}\) ; ρ = Density
Mass = ρ × Volume
= 3.7 × 7.48 × 10³
=27.676 × 10³ kg
Therefore, the weight of the aluminum rod is 27.676 × 10³ kg.
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what is the vmax(app) value for the hydroxylamine inhibition
Answers
The Vmax(app) value for hydroxylamine inhibition refers to the maximum apparent velocity of an enzymatic reaction when hydroxylamine acts as an inhibitor.
The specific value of Vmax(app) would depend on the enzyme and reaction under investigation. The Vmax(app) value represents the maximum apparent velocity of an enzymatic reaction. It is a measure of the rate at which the reaction proceeds when the enzyme is saturated with substrate molecules. In the case of hydroxylamine inhibition, hydroxylamine acts as an inhibitor of the enzyme.
The specific value of Vmax(app) for hydroxylamine inhibition would depend on the enzyme and reaction being studied. To determine the Vmax(app) value, experimental studies would need to be conducted. These studies typically involve measuring the initial reaction rates at various substrate concentrations in the presence of hydroxylamine. By analyzing the data obtained from these experiments, it is possible to determine the apparent maximum velocity of the reaction under hydroxylamine inhibition conditions.
It is important to note that the Vmax(app) value can vary depending on the experimental conditions, such as temperature, pH, and substrate concentration. Therefore, it is necessary to conduct careful experiments and perform appropriate data analysis to obtain accurate Vmax(app) values for hydroxylamine inhibition of specific enzymes.
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What is the equilibrant force for 53 newtons, W: 28 newtons, S:12
newtons, N; 24 newtons, E?
Answers
The equilibrant force is 45 N, acting in the direction opposite to the net force.
What is meant by equilibrant force?The equilibrant force is the force that is required to balance all other forces acting on an object in a specific situation. To find the equilibrant force for the given forces, you need to determine the net force acting on the object.
The net force can be found by adding the individual forces acting on the object:
Net force = 53 N + 28 N - 12 N - 24 N = 45 N
Equilibrant force = - 45 N = 45 N, acting in the opposite direction of the net force.
In this case, the equilibrant force is 45 N, acting in the direction opposite to the net force.
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the electric cell of internal resistance 0.5ohms delivers a current of 2 amperes when a resistance of 3 ohm is connected across it, find the electromotive force of the cell. Show all workings
Answers
Answer:
7 volts
Explanation:
Applying,
E = IR+Ir................ Equation 1
Where E = electromotive force of the cell, I = current. R = External resistance, r = internal resistance.
From the question,
Given: I = 2 amperes, R = 3 ohm, r = 0.5 ohm
Substitute these values into equation 1
E = (2×3)+(2×0.5)
E = 6+1
E = 7 volts
A 2,500 Hz sound wave travels with a speed of 15 m/s in water. A paleontologist measures
the valley to the second valley of the wave to be 7.5 cm.
➤What is the (a) period? What is the (b) frequency? What is the (c) wavelength?
Answers
The answers are A. The period of the wave is 4 × 10⁻⁴ s, B. The frequency is 2500 Hz and C. The wavelength is 6 cm.
A sound wave is a type of wave that travels through the medium by compressing and expanding the particles of the medium. These waves have certain characteristics that are used to measure their properties. The following are the answers to the given question: A 2,500 Hz sound wave travels with a speed of 15 m/s in water. A paleontologist measures the valley to the second valley of the wave to be 7.5 cm.a) The period of a wave is the time it takes to complete one cycle. The formula for calculating the period of a wave is Period = 1/Frequency. Here, the frequency of the wave is 2500 Hz. Hence, the period of the wave can be calculated as Period = 1/2500 Hz = 4 × 10⁻⁴ s.b) The frequency of a wave is the number of cycles that pass a point in one second. The formula for calculating the frequency of a wave is Frequency = 1/Period. Here, the period of the wave is 4 × 10⁻⁴ s. Hence, the frequency of the wave can be calculated as Frequency = 1/4 × 10⁻⁴ s = 2500 Hz.c) The wavelength of a wave is the distance between two successive points on the wave that are in phase. The formula for calculating the wavelength of a wave is Wavelength = Wave speed / Frequency. Here, the wave speed of the sound wave is 15 m/s and the frequency of the wave is 2500 Hz. Hence, the wavelength of the wave can be calculated as Wavelength = 15 / 2500 = 0.006 m = 6 cm.For more questions on frequency
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True or false? When an object deforms, the change of shape is always permanent.
false
true
Answers
2. A javelin is thrown through an angle of 30o to the horizontal. Find the time taken by the javelin to reach the maximum height if the initial velocity is 60ms-1 [ take g =10 ms-1]
Answers
Answer:
3 seconds
Explanation:
The initial velocity is 60 m/s at an angle of 30° to the horizontal, so we can calculate the initial velocity in the vertical direction as
Viy = Vi sin(θ)
Viy = 60 sin(30)
Viy = 60(0.5)
Viy = 30 m/s
Then, we can use the following equation to calculate the time that it takes to reach the maximum height.
\(\begin{gathered} v_{fy}=v_{iy}-gt \\ v_{fy}+gt=v_{iy} \\ gt=v_{iy}-v_{fy} \\ \\ t=\frac{v_{iy}-v_{fy}}{g} \end{gathered}\)At a maximum height the vertical velocity is 0 m/s, so replacing viy = 30 m/s, vfy = 0 m/s and g = 10 m/s², we get
\(\begin{gathered} t=\frac{30\text{ m/s-0m/s}}{10\text{ m/s}^2} \\ \\ t=\frac{30\text{ m/s}}{10\text{ m/s}^2} \\ \\ t=3\text{ s} \end{gathered}\)Therefore, the answer is 3 seconds
A 5-kg fish swimming at a speed of 1 m/s swallows an absent-minded 1-kg fish at rest. The speed of the larger fish after lunch is
Answers
Answer:
Explanation:
So:
(
5
⋅
1
)
+
(
1
⋅
−
4
)
=
(
5
+
1
)
v
5
−
4
=
6
v
v
=
1
6
=
0.17
m
s
many of the ancient greeks believed that the earth was the stationary center of the universe. what type of model of the universe is this? quizlit
Answers
The type of model of the universe in which many of the ancient Greeks believed that the earth was the stationary center of the universe is called geocentric model.
In this model, the Earth is considered to be at the center, with the Sun, Moon, planets, and stars orbiting around it. This geocentric view of the Universe was prevalent in ancient Greek cosmology and was also adopted by other civilizations, such as ancient Babylonian and medieval European societies. One of the most influential proponents of the geocentric model was the Greek philosopher Aristotle. It was not until the 16th century when the heliocentric model, with the Sun at the center of the Solar System, was proposed by astronomers such as Nicolaus Copernicus and later confirmed by observations and discoveries made by Galileo Galilei and others.
The question should be:
Many of the ancient Greeks believed that the Earth was the stationary center of the Universe. What type of model of the Universe is this?
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A pendulum is swinging in a circular path at angle θ and string length L. What is the tension in the string? Use m, g, and θ. Your answer should have m, g, θ, and a trig function. Your answer will be T=.
What is the centripetal acceleration? Your answer will have g, θ, and 1 or 2 trig functions. Your answer will be \(a_{c}\)=.
Answers
Answer:
T = mg / cos θ
ac = g tan θ
Explanation:
Draw a free body diagram. There are two forces acting on the pendulum bob. A tension force T acting θ from the vertical, and gravity pulling down.
Sum the forces in the y direction:
∑F = ma
T cos θ − mg = 0
T = mg / cos θ
Sum the forces in the centripetal direction (towards the center).
∑F = ma
T sin θ = m ac
ac = T sin θ / m
Substitute for tension T:
ac = (mg / cos θ) sin θ / m
ac = (mg / m) (sin θ / cos θ)
ac = g tan θ
In a hydrogen atom, the electric force is the centripetal force. Determine the speed of an electron in orbit around a proton if the distance between them is 5.29 x 10^{-11} m. The mass of an electron is 9.11 x 10^-31 kg. (HINT: equate centripetal force and electric force)
Answers
hope this helps
4 (JAMB) The diagram below shows a light see-saw, which is balanced horizontally by the weights W₁, W2, W3, W4 in the positions shown: d a W₁ Fig. 4.44 W₂ b W3 WA Which of the following equations correctly represents the principle of the lever balance? A W₁ + W₂ = W3 + W4 B W₁-W₁ = W4 - W3 C W₁a+W₂b = W3c+Wad D (W₂-W₁)a= (W4 - W3)c E (W₁ + W₂ )ab = (W3+ W4)cd (SCIGCE) 4 ( JAMB ) The diagram below shows a light see - saw , which is balanced horizontally by the weights W₁ , W2 , W3 , W4 in the positions shown : d a W₁ Fig . 4.44 W₂ b W3 WA Which of the following equations correctly represents the principle of the lever balance ? A W₁ + W₂ = W3 + W4 B W₁ - W₁ = W4 - W3 C W₁a + W₂b = W3c + Wad D ( W₂ - W₁ ) a = ( W4 - W3 ) c E ( W₁ + W₂ ) ab = ( W3 + W4 ) cd ( SCIGCE )
Answers
The equation that represents the principle of the lever balance is:
W₁ + W₂ = W3 + W4; option A.What is the principle of moments?The principle of moments states when a body is in equilibrium, the sum of the clockwise moment about a point equals the sum of anticlockwise moment about that point.
A see-saw represents a balanced system of moments.
The sum of clockwise moment = The sum of anticlockwise moments.
Assuming W1 and W2 are clockwise moments and W3 and W4 are anticlockwise moments.
The equation will b: W₁ + W₂ = W3 + W4
In conclusion, a balanced see-saw illustrates the principle of the lever balance.
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The volume between two spherical conducting surfaces of radii a
and b (a < b) is filled with an inhomogeneous dielectric medium
whose dielectric function is
where 0 and ξ are constants and r is t
Answers
To analyze the volume between two spherical conducting surfaces filled with an inhomogeneous dielectric medium described by ε(r) = ε₀(1 + ξr), the electric field and potential are calculated using Gauss's law and boundary conditions.
To analyze the volume between two spherical conducting surfaces of radii a and b, filled with an inhomogeneous dielectric medium characterized by the dielectric function ε(r) = ε₀(1 + ξr), where ε₀ and ξ are constants and r is the radial distance, we can follow these steps:
Step 1: Define the boundaries of the volume between the two spherical conducting surfaces, with the inner sphere of radius a and the outer sphere of radius b.
Step 2: Calculate the electric field (E) within the inhomogeneous dielectric medium using Gauss's law. The electric field is related to the radial distance r and the dielectric function ε(r) by the equation ε₀E = Q(r)/ε(r), where Q(r) is the charge enclosed within a Gaussian surface of radius r.
Step 3: Integrate the electric field (E) with respect to the radial distance r to obtain the electric potential (V) within the inhomogeneous dielectric medium. This integration involves evaluating ∫(ε₀/E) dr.
Step 4: Apply boundary conditions to determine the electric potential at the inner and outer surfaces of the conducting spheres. The boundary conditions typically involve continuity of the electric potential and the normal component of the electric field at the interfaces.
Step 5: Once the electric potential is determined, the electric field can be obtained by taking the negative gradient of the electric potential using the relationship E = -∇V.
By following these steps, you can analyze the volume between the two spherical conducting surfaces filled with the inhomogeneous dielectric medium described by the given dielectric function ε(r).
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