which statement about 3/4 multiplied by 16/5 is true?

A. The product is greater than 5
B. The product is less than 3/4
C. The product is between 3/4 and 16/5
D. The product is between 16/5 and 5

Answer:

4yd

144

Step-by-step explanation:

because 4yd is greater than 144

The graph of the equation 3x + 4y = 0 is a straight line with a negative slope passing through the origin.

The given equation, 3x + 4y = 0, represents a linear graph in the Cartesian coordinate system. Let's analyze its characteristics.

First, note that the equation is in the standard form for a linear equation, which is Ax + By = C, where A, B, and C are constants. In this case, A = 3, B = 4, and C = 0.

To graph this equation, we can rewrite it in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept. By isolating y, we have y = (-3/4)x + 0. Since the y-intercept (b) is 0, the line intersects the y-axis at the origin (0,0).

Next, we can examine the slope. The coefficient of x, -3/4, represents the ratio of the change in y (vertical) to the change in x (horizontal) as we move along the line. In this case, the slope is negative, indicating that the line descends from left to right. The magnitude of the slope, 3/4, implies that for every 4 units moved horizontally to the right, the line goes 3 units down vertically.

Therefore, we can conclude that the graph of the equation 3x + 4y = 0 is a straight line passing through the origin (0,0) with a negative slope. It extends indefinitely in both directions, with the line getting steeper as we move to the right.

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Answer:

The values of x and y that will minimize the cost is 15 ft and 5 ft respectively and the minimum cost will 3,375

Step-by-step explanation:

With a 1125 ft^3 open-top rectangular tank with a square base x ft on a side and y ft deep is to be built with its top lush with the ground to catch runoff water, x is the length, y is the height;

x^2*y = 1125

y = 1125/x^2 ----(1)

The total cost of c = 5(x^2 + 4xy) + 10xy

Then,

c = 5(x^2 + 4x*(1125/x^2)} + 10x*(1125/x^2)

c = 5x^2 + 22,500/x + 11,250/x

c = 5x^2 + 33,750/x

To minimize the cost of c, find the derivatives of c; c'

c' = 10x - 33,750/x^2

c' = (10x^3 - 33,750)/x^2

c'(x) = 0; 10x^3 = 33,750

x = ³√33,750 = 15

x = 15; y = 1125/x^2

y = 1125/15^2 = 5

(x,y) = (15,5)

c = 5x^2 + 33,750/x

c = 5*15^2 + 33,750/15 = 3,375

The values of x and y that will minimize it is 15 ft and 5 ft respectively and the minimum cost will 3,375

The values of x and y that will minimize the cost is 15ft and 5ft. The minimum cost is 3,375

We have volume of a rectangular tank = 1125 ft^3

Side of a rectangular tank = x ft and

Length of a rectangular tank =y ft  

So, \(x^2y = 1125\)

\(y = \frac{1125}{x^2} ...(1)\)

The total cost of rectangular tank (c) = \(5(x^2 + 4xy) + 10xy\)

 \(c = 5(x^2 + 4x(\frac{1125}{x^2} ) )+ 10x(\frac{1125}{x^2} )\\c = 5x^2 +\frac{22,500}{x} + \frac{11250}{x} \\c = 5x^2 + \frac{33750}{x}\)

Differentiating it w.r.t x, we get

\(c' = 10x - 33,750/x^2\\c' =\frac{10x^{3}-33750 }{x^{2} } \\c'(x) = 0\\10x^3 = 33,750\\x = \sqrt[3]{33,750} \\ = 15\\x = 15; y = \frac{1125}{x^2} \\y = \frac{1125}{15^{2} } \\= 5\\(x,y) = (15,5)\\c = 5x^2 + \frac{33750}{x} \\c = 5(15)^2 + 33,750/15 \\= 3,375\)

The values of x and y that will minimize the cost is 15 ft and 5 ft and the the minimum cost is 3,375.

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For the given expression, the variable is p, coefficient is 17 and the exponent is 5.

Expression:

Expression refer the algebraic expression that consists of variables, numbers and math operators.

Given,

Here we have the expression 17p⁵

Now, we have to find the exponent, coefficient and variable.

As per the definition of exponent, the term exponent refers the power value of the expression.

So, the exponent is 5.

And the definition of coefficient is an integer that is written along with a variable or it is multiplied by the variable.

So, the coefficient is 17.

And the variable of this expression is p.

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The amount natalya will spend constructing the patio with concrete and brick is $4320, the correct option is D.

We are given that;

The concrete portion of the patio cost=$3 per square

To construct and the brick portion of the patio cost= $6 per square

Now,

The area of a rectangle is given by length times width. The concrete portion of the patio is a rectangle with length 6 cm and width 3 cm. Using the scale, we can convert these to feet:

6 cm = 6 x 4 ft = 24 ft 3 cm = 3 x 4 ft = 12 ft

Therefore, the area of the concrete portion is:

24 ft x 12 ft = 288 ft^2

The brick portion of the patio consists of two identical rectangles with lenth 3 cm and width 6 cm. Using the scale, we can convert these to feet:

3 cm = 3 x 4 ft = 12 ft 6 cm = 6 x 4 ft = 24 ft

Therefore, the area of one brick rectangle is:

12 ft x 24 ft = 288 ft^2

Since there are two brick rectangles, the total area of the brick portion is:

2 x 288 ft^2 = 576 ft^2

Now we can multiply the areas by their costs per square foot to get the costs of each portion:

Concrete cost = $3 x 288 ft^2 = $864 Brick cost = $6 x 576 ft^2 = $3456

The total cost of constructing the patio is the sum of the costs of each portion:

Total cost = $864 + $3456 = $4320

Therefore, by area the answer will be $4320.

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Answer:

greenn paint trust me balls

The missing value in the proportion is C- 10

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

We are given that 2/5 = ?/25

Let x be the unknown number.

Here first we have the bottom half of type equation equal each other

5x=25 (2)

x= 25 (2) / 5

x = 5 (2)

x = 10

10 is the answer

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Answer:

2√2 units.

Step-by-step explanation:

To find the length of the line joining points A(3, 5) and B(1, 3), we can use the distance formula. The distance formula is given by:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Substituting the coordinates of points A and B into the formula, we have:

d = sqrt((1 - 3)^2 + (3 - 5)^2)

  = sqrt((-2)^2 + (-2)^2)

  = sqrt(4 + 4)

  = sqrt(8)

  = 2sqrt(2)

Therefore, the length of the line joining points A and B is 2√2 units.

Answer:

Refer to the step-by-step explanation.

Step-by-step explanation:

Come up with a monomial expression and solve it.

A monomial expression is an algebraic expression that consists of a single term. It is an expression that can contain variables, constants, and non-negative integer exponents, but there should be no addition or subtraction between different terms.

Here are a few examples of an monomial expression:

\(\hrulefill\)

Let's work with the monomial expression, 3x²y³z.

To solve this expression, I assume you would like to evaluate it for specific values of the variables x, y, and z. So let x=3, y=2, and z=1.

Plug these values into the expression:

3x²y³z

=> 3(3)²(2)³(1)

=> 3(9)(8)(1)

=> 27(8)(1)

=> 216(1)

=> 216

Thus, the expression is solved.

The true statements are:

A circle is a closed, two-dimensional shape where every point in the plane is equally spaced from a central point. The line of reflection symmetry is formed by all lines that traverse the circle. Additionally, every angle has rotational symmetry around the middle.

To identify the true statements, we can first rewrite the given equation of the circle in standard form:

x² - 2x + y² = 8

Completing the square, we get:

(x - 1)² + y² = 9

Now we can identify the true statements:

Therefore, the true statements are:

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Answer:

Open points on 1 and 3 with ray connecting.

Step-by-step explanation:

Because it's right.

From the graph of the function |(f)| and |(g)|, the interval at which both functions are negative are 1 and 3.

A quadratic function can be defined as a mathematical expression that can be used to define and represent the relationship that exists between two or more variable on a graph.

In Mathematics, the graph of a quadratic function is parabolic because it is u-shaped. From the graph of the function |(f)| and |(g)|, we can deduce that the interval at which both functions are negative are 1 and 3 as shown in the image attached below.

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To determine the area of the remaining piece of cardboard expressed in terms of x when a square of side length x inches is cut out from a rectangular piece of cardboard having a length of 6x+2 inches and a width of 2x-4 inches, use the following steps.

Draw and label a diagram of the problem. The rectangle should be labeled as 6x+2 inches by 2x-4 inches, and the square cut out should be labeled as x inches by x inches. This is how the diagram looks like: Determine the area of the rectangle, Arect.

The area of the rectangle is given by the product of its length and width. Thus, Arect = (6x + 2)(2x - 4) Determine the area of the square, Asq. The area of the square is given by the square of its side length. Thus, Asq = x²Step 4: Determine the area of the remaining cardboard after the square is cut out, Ar.

This is the difference between the area of the rectangle and the area of the square. Thus, Ar = Arect - Asq= (6x + 2)(2x - 4) - x²= 12x² - 20x - 16

Simplify the expression. The final answer is given in terms of x. Thus, Ar = 12x² - 20x - 16.The area of the remaining piece of cardboard is expressed in terms of x as 12x² - 20x - 16.

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Answer:

672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

Step-by-step explanation:

No. of customers pass the display on the day of sale = 1462

Proportion of people will purchase if pass such a special display = 0.43

Mean = E(X)=np

E(X)=\(1462 \times 0.43\)

E(X)=628.66

Standard deviation = \(\sqrt{npq}\)

Standard deviation =\(\sqrt{1462 \times 0.43 \times (1-0.43)}=18.92\)

Now we are supposed to find how many units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

P(X<x)=0.01

Using z table

\(P(\frac{x-\mu}{\sigma})= 2.33 \\\frac{x-628.66}{18.92}=2.33\\x=(2.33 \times 18.92)+628.66\\x=672.7436\)

Hence 672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale

The number of units should be 672.7436 units.

Since No. of customers pass the display on the day of sale is 1462 and the proportion of people who will purchase if pass such a special display is 0.43

So,

Mean should be = 43% of 1,462

= 628.66

Now the standard deviation should be

\(= \sqrt{1462 \times 0.43 \times (1-0.43)}\)

= 18.92

Now the number of units should be

\(x - 628.66 \div 18.92 = 2.33\)

x = 672.7436

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Answer:

8.12

Step-by-step explanation:

Answer:

{-5, -1, 2}

Step-by-step explanation:

domain is the inputs or x numbers

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\( log(550) = log(2 \times 5 \times 5 \times 11) = \\ \)

\( log(2) + log( {5}^{2} ) + log(11) = \)

\(1 - log(5) + 2 log(5 ) + log(11) = \\ \)

\(1 + log(5) + log(11) = \)

\(1 + a + b\)

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Answer:

log(a x b) = Log(550)

Step-by-step explanation:

Depends what question is asking

Log rule (So long as they have the same base)

Log(m) + Log(n) = Log(m x n)

Log(a) + Log(b) = Log(a x b)

Log(5) + Log(11) = Log(5 x 11)

=Log (550)

The following percentages are listed below:

In this question we have seven cases of real life situations in which percentages are used. Mathematically speaking, percentages are represented by the following expression:

x = r / r' × 100       (1)

Where:

Now we proceed to determine quantities related to percentages:

2.8 mm as a per cent of 2.24 cm

x = (2.8 mm / 22.4 mm) × 100 %

x = 12.5 %

What per cent of 1.5 m is 60 cm?

x = (60 cm / 150 cm) × 100 %

x = 40 %

What per cent of 2 kg is 125 g?

x = (125 g / 2000 g) × 100

x = 6.25 %

What per cent of R 6 to 40 p?

x = (40 / 600) × 100

x = 6.667 %

What per cent of a day is 10 h?

x = (10 h / 24 h) × 100

x = 41.667 %

What per cent of 7 1 / 3 m in 5 1 / 2 m ?

x = [(11 / 2) / (22 / 3)] × 100 %

x = 75 %

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Answer:

ok i have choose 3 but why

Step-by-step explanation:

Slope 1/2    point    5,1  

  in point slope form would be

    (y-1) = 1/2 (x-5)

Answer:

8700kg

Step-by-step explanation:

b = mass of bricks

l = mass of lorry

b+l = total mass = 11600kg

b = 3l  ==>  l = b/3

substitute: b + b/3 = 11600

multiply every term by 3 to get rid of denominator: 3b + b = 34800

simplify and solve:  4b = 34800  ==>  b = 8700

check:  l = 8700/3 = 2900

2900 + 8700 = 11600?  YES

Answer:

a) The null hypothesis is \(H_0: p \leq \frac{2}{3}\) and the alternate hypothesis is \(H_1: p > \frac{2}{3}\).

b) The sample proportion is 0.6710.

Step-by-step explanation:

Question a:

An airline promotion to business travelers is based on the assumption that no more than two-thirds of business travelers use a laptop computer on overnight business trips.

At the null hypothesis, we test if the proportion is two-thirds or less, that is:

\(H_0: p \leq \frac{2}{3}\)

At the alternate hypothesis, we test if the proportion is of more than two-thirds, that is:

\(H_1: p > \frac{2}{3}\)

b. What is the sample proportion from an American Express-sponsored survey that found 359 of 535 business travelers use a laptop computer on overnight business trips (to 4 decimals)?

359 out of 535 is 359/535 = 0.6710.

The sample proportion is 0.6710.

For the function  f(x) = 2x + 3 the third iterate x₃  is 37

To find the third iterate, x3, of the function f(x) = 2x + 3, given an initial value of x₀ = 2,

we can apply the function repeatedly.

Starting with x₀ = 2:

x₁ = f(x₀)

= 2(2) + 3

= 7

x₂ = f(x₁)

= 2(7) + 3 = 17

x₃ = f(x₂)

= 2(17) + 3

= 37

Therefore, the third iterate x₃  is 37.

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Answer:

I think the answer of this question is b

Answer:

  1.4

Step-by-step explanation:

The average rate of change is the "rise" divided by the "run".

  rise/run = (f(4) -f(-1))/(4 -(-1)) = (0 -(-7))/(4+1)

  rise/run = 7/5 = 1.4

The average rate of change on the interval [-1. 4] is 1.4.

We will see that the average rate of change in the given interval is 1.4

For a given function f(x), the average rate of change on an interval [a, b] is given by:

\(r = \frac{f(b) - f(a)}{b - a}\)

In this case the interval is [-1, 4], using the graph we can see that:

f(-1) = -7

f(4) = 0

replacing that in the formula we get:

\(r = \frac{0 - (-7)}{4 - (-1)} = \frac{7}{5} = 1.4\)

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Answer:

16.5

Step-by-step explanation:

36^2-32^2 =272

sqrt272 =16.5

The height of the building is approximately 16.5 feet.

The Pythagoras theorem which is also referred to as the Pythagorean theorem explains the relationship between the three sides of a right-angled triangle. According to the Pythagoras theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides of a triangle.

Given that, place a 36-foot ladder against the top of a building and the bottom of the ladder is 32 feet from the bottom of the building.

So, hypotenuse of the triangle is 36 feet and base of the triangle is 32 feet.

Let h be the height of the building.

Now, 36²=32²+h²

1296=1024+h²

h²=1296-1024

h²=272

h=16.5 feet

Therefore, the height of the building is approximately 16.6 feet.

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Answer:

6/18 or 1/3

Step-by-step explanation:

there are 18 balls and 6 brown balls so it will be 6/18 or 1/3

Answer:

6/18 or 1/3 if simplified

Step-by-step explanation:

In order to find this, all you have to do is add up all the numbers and then write it as a fraction.

So since 4+6+8= 18 and there are only six brown balls, the probability would be written as 6 (number of brown balls) over 18 (total number of balls)

The Equivalent ratio to 8/2 is 4/1, 24/6, 32/8 and 48/12.

We have,

Cylinder and prism.

Here we have to find the equivalent ratio to 8/2.

First simplifying the given ratio as

8/2

= (4 x 2)/2

= 4 /1

Now, some more ratios equivalent to 8/2.

1. 8/2 x 3/3 = 24/ 6

2. 8/2 x 4/4 = 32/8

3. 8/2 x 6/6= 48/12

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As a result, the median is 13. The data has a minimum value of 11 and a maximum value of 17.

The median is the value in the center of a data collection, which means that 50% of the data points have a value less than or equal to the median, and 50% of the data points have a value greater than or equal to the median. For a small data collection, count the number of data points (n) and arrange them in increasing order.

Here,

(a)(i) The median of the data can be found by ordering the data and finding the middle value. In this case, the data has 16 values, so the median is the average of the 8th and 9th values when the data is ordered. The median is therefore 13.

(ii) The minimum value of the data is 11 and the maximum value is 17.

(b) The box-and-whisker diagram is a graphical representation of the distribution of a set of data. It consists of a box, whiskers and dots that show the distribution of the data.

The box represents the interquartile range (IQR), which is the range of the middle 50% of the data. The IQR is calculated as the difference between the upper quartile (Q3) and the lower quartile (Q1). In this case, the IQR is 15 - 12.5 = 2.5.

The lower edge of the box is Q1 and the upper edge of the box is Q3. The line inside the box is the median.

Whiskers are drawn to the minimum and maximum values, excluding outliers. Outliers are values that are significantly different from the rest of the data. In this case, there are no outliers.

Dots may be used to represent individual data points.

Here's what the box-and-whisker diagram would look like for this data:

| |

| |

|_13|

12.5 15

The median is therefore 13. The minimum value of the data is 11 and the maximum value is 17.

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