which salt would you predict to have a solubility in water that increases as the ph decreases? a. silver chloride b. lead (ii) bromide c. calcium fluoride d. mercury (i) nitrate

The heat of reaction (ΔH) for the given reaction is -890 kJ/mol. This negative value indicates that the reaction is exothermic, meaning that it releases energy in the form of heat.

The heat of reaction (ΔH) for the given reaction can be calculated using bond energies of the molecules involved. The bond energy is defined as the energy required to break a bond, and the bond energy of a reaction is the difference between the bond energies of the reactants and the products. In this case, the bonds broken in the reactants are CH and O2, while the bonds formed in the products are CO2 and H2O.

Using the bond energy values from the table of bond energies, we get:

ΔH = Σ(ΔH of bonds broken) - Σ(ΔH of bonds formed)
  = (1x413 + 2x498) - (1x799 + 2x464)
  = -890 kJ/mol

Therefore, the heat of reaction (ΔH) for the given reaction is -890 kJ/mol. This negative value indicates that the reaction is exothermic, meaning that it releases energy in the form of heat.

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The total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.

To calculate the total charge that flows while the battery is being charged, we can use the relationship between electrical energy, potential difference, and charge.

The electrical energy (E) stored in the battery is given as 64 mega Jules (64 MJ). The potential difference (V) provided by the battery is 330 volts. We know that the energy (E) is equal to the product of the potential difference (V) and the charge (Q):

E = V * Q

Since the charging process is 100% efficient, all the electrical energy supplied is stored in the battery. Therefore, we can rearrange the equation to solve for the charge (Q):

Q = E / V

Substituting the given values, we have:

Q = 64 MJ / 330 V

To perform the calculation, we need to convert mega Jules (MJ) to joules (J) since the SI unit of energy is joules. One mega Joule is equal to 1 million joules:

Q = (64 * 10^6 J) / 330 V

Calculating the division:

Q ≈ 193,939.39 Coulombs

Therefore, the total charge that flows while the battery is being charged is approximately 193,939.39 Coulombs.

This value represents the quantity of electric charge transferred during the charging process, and it indicates the amount of electricity that enters the battery.

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Answer:

A, C, and E. I hope you have a good day.

Explanation:

Answer:

1, 3, and 5

Explanation:

Answer:

 6.022 × 10²³ units of that substance 

Explanation:

Equilibrium is a state in a chemical reaction where the rate of the forward reaction is equal to the rate of the reverse reaction, resulting in no net change in the concentrations of reactants and products. It is represented by a double arrow (⇌) in chemical equations. In the given equation: H₂O (g) + CO (g) ⇌ H₂(g) + CO₂(g) + 42 KJ

To shift the equilibrium to the right, one or more of the following could occur:

Increasing the concentration of H₂ or CO₂

Decreasing the concentration of H₂O or CO

Increasing the pressure

Removing some of the products (H₂ and CO₂)

Decreasing the temperature

To shift the equilibrium to the left, one or more of the following could occur:

Decreasing the concentration of H₂ or CO₂

Decreasing the pressure

Increasing the temperature

If pressure is increased, the equilibrium will shift in the direction that produces fewer moles of gas. In this case, since there are fewer moles of gas on the right side of the equation (H₂ and CO₂), the equilibrium will shift to the right. If heat is added, the equilibrium will shift in the endothermic direction to absorb the additional heat. In this case, the forward reaction is endothermic (42 KJ on the right side), so the equilibrium will shift to the right to consume the added heat.

If CO is added, the equilibrium will shift to the right to consume the additional CO.The concentration of H₂O and CO₂ will increase, while the concentrations of H₂ and CO will decrease until a new equilibrium is reached.

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Answer:

single displacement

Direct expansion systems require the vapour exiting the evaporator to be superheated to avoid liquid slugging, to improve the effectiveness of the evaporator and to maintain the stability of the compressor. (B) Forced draft and induced draft evaporators differ in the way air is introduced into them. (C) CClF2CF3 (also known as R12) is a chlorofluorocarbon refrigerant. (ii) Tetrafluoroethane (also known as R134a) is a hydrofluorocarbon refrigerant and H2O is not classified as a refrigerant. (D) The partial pressure of hydrogen in the evaporator is 1.6 mmHg.

(a) Direct expansion systems are those in which the refrigerant in the evaporator evaporates directly into the space to be cooled or frozen. The evaporator superheat is used to make sure that only vapor and no liquid is carried over into the suction line and compressor. Superheating is required for the following reasons :

(b) Forced draft and induced draft evaporators differ in the way air is introduced into them. In an induced draft evaporator, a fan or blower is positioned at the top of the evaporator, and air is drawn through the evaporator from the top. In a forced draft evaporator, air is propelled through the evaporator by a fan or blower that is located at the bottom of the evaporator. Forced draft evaporators are frequently used in direct expansion systems because they allow for better control of the air temperature. Because the air is directed upward through the evaporator and out of the top, an induced draft evaporator is less effective at keeping the air at a uniform temperature throughout the evaporator.

(c) (i) CClF2CF3 (also known as R12) is a chlorofluorocarbon refrigerant.

(ii) Tetrafluoroethane (also known as R134a) is a hydrofluorocarbon refrigerant.

(iii) H2O is not classified as a refrigerant.

(d) The function of hydrogen gas in an absorption refrigeration system (NH3/H2O/H2) is to increase the heat of reaction between ammonia and water.

The pressure of hydrogen gas in the evaporator of an absorption refrigeration system can be determined using the formula, Pa/Pb = (Ta/Tb)^(deltaS/R),

where Pa = partial pressure of hydrogen in the evaporator, Ta = evaporating temperature, Tb = condensing temperature, Pb = partial pressure of hydrogen in the absorber, deltaS = entropy change between the absorber and evaporator, R = gas constant.

Substituting the given values, Ta = −2.0 ∘C = 271 K ; Tb = 38.0 ∘C = 311 K ; Pb = atmospheric pressure = 1 atm ;

deltaS = 4.7 kJ/kg K ; R = 8.314 kJ/mol K

we get, Pa/1 atm = (271/311)^(4.7/8.314)

Pa = 0.021 atm or 1.6 mmHg

Therefore, the partial pressure of hydrogen in the evaporator is 1.6 mmHg.

Thus, Direct expansion systems require the vapour exiting the evaporator to be superheated to avoid liquid slugging, o improve the effectiveness of the evaporator and to maintain the stability of the compressor. (B) Forced draft and induced draft evaporators differ in the way air is introduced into them. (C) CClF2CF3 (also known as R12) is a chlorofluorocarbon refrigerant. (ii) Tetrafluoroethane (also known as R134a) is a hydrofluorocarbon refrigerant and H2O is not classified as a refrigerant. (D) The partial pressure of hydrogen in the evaporator is 1.6 mmHg.

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The complete, balanced chemical reaction for the reaction between gold (Au) and selenic acid (H2SeO4) is: 4Au + 3H2SeO4 → 2Au2(SeO4)3 + H2SO3 + H2O. The coefficients for the reactants and products are as follows: 4 for Au, 3 for H2SeO4, 2 for Au2(SeO4)3, 1 for H2SO3, and 1 for H2O. The type of chemical reaction is a single displacement reaction.

The balanced chemical equation for the reaction between gold (Au) and selenic acid (H2SeO4) is:

4Au + 3H2SeO4 → 2Au2(SeO4)3 + H2SO3 + H2O

In this equation, the coefficient in front of Au is 4, indicating that 4 moles of gold are involved in the reaction. The coefficient in front of H2SeO4 is 3, indicating that 3 moles of selenic acid are present.

On the product side, the coefficient in front of Au2(SeO4)3 is 2, indicating the formation of 2 moles of gold selenate. The coefficient in front of H2SO3 is 1, representing the formation of 1 mole of sulfurous acid. The coefficient in front of H2O is also 1, indicating the production of 1 mole of water.

Based on the reactants and products involved, the type of chemical reaction is a single displacement reaction, as gold displaces hydrogen in selenic acid to form gold selenate.

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Answer:

10.2 times 7.0 times 15.1 times 32.9 times

Explanation:

The quantity of refrigerant in a system is less critical when the system has increased operating pressures.

A low coolant level can cause the engine to overheat. This can cause the compressor not to start or the circuit breaker to trip prematurely. If left unchecked, the engine will eventually burn out and completely stall. Refrigerants with a low critical temperature have a large decrease in cooling performance.

The critical temperature of the refrigerant should be higher than the condensing temperature to obtain greater heat transfer at a constant temperature. When the air conditioner runs low on refrigerant, it loses its ability to transfer heat from within. This means that the air that's being blown into your AC coil isn't cooling properly, so your vents will start circulating warm air throughout your home.

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Answer:

Explanation:

Density is m/V. Also, 1 liter = 1000 \(cm^3\). So, we get 0.890/(5*1000) = \(1.78*10^{-4}\) g/cm^3. You can convert this to kg/m^3 as well by multiplying it by 10. Depends which one you want.

The ratio of the mass in grams and volume in cubic meters gives the density. The density of 0.80 gm helium is 1.78 × 10 ⁻⁴ g/cm³.

Density is the amount or the number of entities that can be contained in an area. It is denoted by ρ and is calculated as,

Given,

Mass = 0.890 gm

Volume = 5000 cm³

ρ = Mass ÷ Volume

= 0.890 ÷ 5000

= 1.78 × 10 ⁻⁴ g/cm³

Therefore, 1.78 × 10 ⁻⁴ g/cm³ is the density of helium.

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Answer:

5.6 grams of water.

Explanation:

Please, notice that we can't see the spot with the question mark, so I will answer the question completely step by step.

We know that water is made from two hydrogen molecules and one oxygen molecule.

By looking at the atomic weight, we know that the weight of one mole of oxygen is:

16 grams.

While the weight of one mole of hydrogen is 1 gram (and we have two of these)

Then we have a total mass of 16 g + 2 g = 18 g

Now let's find what fraction of this is the oxygen, here we just need to take the quotient between the mass of oxygen and the total mass:

16g/18g = 0.89

Now, this means that if we have M grams of pure water, then we will have:

0.89*M grams of oxygen.

Ok, now let's use this to solve our problem, we want to find how many grams of water are made from 5 grams of oxygen.

Then let's write:

5 grams  = 0.89*M grams

Where M represents the grams of water that we would get, here we just need to isolate M.

M = (5 g/0.89) = 5.6 grams

This means that out of 5 grams of oxygen, we can make 5.6 grams of water.

Answer: 107 grams

Explanation: got it right on the test

The mass of a sample of f NH₃ containing  3.80 x 10²⁴ molecules of  NH₃ is  107.27 grams.

A molecule is a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance.

6.02214076 × 10²³  molecules constitute 1 mole of NH₃

3.80 x 10²⁴ molecules constitutes of = 6.31 moles

1 mole of NH₃ = 17 gm

11.19 mole will be = 17 X 6.31

= 107.27 grams

Therefore the mass of a sample of NH₃ containing 3.80 x 10²⁴ molecules of NH₃ is 107.27 grams.

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Answer:

it's volume also decrease

Answer: C - The iron becomes harder and stronger

Explanation:

The pure iron when mixed with the carbon then steel is formed which is the interstitial alloy of iron. About 0.002%- 2.1% (m/m) of carbon. The carbon atoms being smaller than the iron atom occupy the interstitial spaces or interstices in between the iron atoms. Thus these carbon atoms introduce imperfections in the iron crystal layer. The iron crystal layers become harder and they slide past one another and the iron becomes harder.

Pauli exclusion principle, the Aufbau principle, and the Hund's rule.

Moreover, In simple terms, the Aufbau principle means fill the orbitals from bottom to top. In simple terms, Hund's rule requires single occupancy before pairing. Pauli Exclusion Principle. No two electrons in a atom can have an identical set of four quantum numbers.

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Answer:

it's a chemical Element

Explanation:

symbol He

atomic number 2.

The mass of KF in the mixture is 1.067 grams

As per the details provided in the question are as follow,

Total weight of mixture (LiF+KF)= 5.08 grams

Mixture contains 3.26 grams of fluorine

Molar mass K = 39.10 g/mol

Molar mass F = 19.00 g/mol

Molar mass KF = 58.10 g/mol

Molar mass of lithium = 6.94 g/mol

mass of KF and LiF

Mass KF = X grams

Mass LiF = 5.08 -X grams

Now Calculate the moles

Moles KF = x grams / 58.10 g/mol

Moles LiF = (5.08-X grams) / 25.94 g/mol

1 mol of KF contains 1 mol of F atoms.

1 mol of LiF contains 1 mol of F atoms.

moles of F in KF= moles of KF= x/58.10 g/mol

moles of F in LiF = moles of LiF=  (5.08-x)/25.94g/mol

Total moles of Fluorine =(x/58.10)+((5.08-x)/25.94)

Calculate mass

The total weight of Fluorine in sample

3.26 grams =((x/58.10)+((5.08-x)/25.94))*19g/mol

x = 1.067 grams

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Answer:

Organisms move and eat through their habitats. They adapt to the environment and can survive in the environment with their own behavior.

Explanation:

Organisms are of many types. Some lives on land, some lives in water while others are hybrid organisms which can survive in water as well as on land. The organisms body movement is dependent on its cell functioning. Every organism has different cell structures which help them to survive on the earth.

Chemical reactions can heat homes. The reason is sometimes they make a little explosion which can light up the home. And it can linge around for awhile and still light. If chemicals dd not exist Albert would have not invented the lightbulb. That is how chemicals can heat homes.

- Madeleine109

Answer:

Q = 5254.39 J

Explanation:

Given that,

Mass of ethanol, m = 68.8 g

The temperature increases from 40.0°C to 71.3°C.

The specific heat of ethanol is 2.44 j/g°C

We need to find the heat absorbed by the ethanol. We know that the heat absorbed due to the change in temperature is given by :

\(Q=mc\Delta T\)

Put all the values,

\(Q=68.8\times 2.44\times (71.3-40)\\\\Q=5254.39\ J\)

So, 5254.39 J of heat is absorbed by Ethanol.

The inorganic substance with the chemical formula BaSO4 is barium sulfate (or sulphate). It is a tasteless, crystalline white substance that is insoluble in water.

A barium cation and a sulfate anion are the two elements that make up barium sulfate. There are four oxygen atoms joined to the sulfur. A sulfate salt of barium, known as BaSO4, is present in the mineral barite. It is a white crystalline substance that is soluble in strong acids but insoluble in water and alcohol.

Elements include both barium and bromine. Barium is a metal belonging to Group 2 of the modern periodic table, and bromine is a non-metal belonging to Group 17 (halogen).

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The concentration of A decreases and then levels out. Option A

In many chemical reactions, a reactant is consumed as the reaction progresses, leading to a decrease in its concentration over time. The reactant molecules are transformed into products, and as the reaction proceeds, the concentration of the reactant gradually diminishes.

At equilibrium, the concentrations of both reactants and products remain relatively constant over time, although they can coexist.

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The statement about elemental nickel used in the hydrogenation of polyunsaturated oils is also incorrect as it refers to a heterogeneous catalyst, not a homogeneous one.

They are always present in the same phase as the reactants.

They typically interact with reactants to form intermediates, which eventually react away to regenerate the catalyst.

The following statements are correct:

Homogeneous catalysts are always present in the same phase as the reactants.

They typically interact with reactants to form intermediates, which eventually react away to regenerate the catalyst.

The following statement is incorrect:

They function by furnishing an active surface upon which reactions can occur. (This is true for heterogeneous catalysts, not homogeneous catalysts.)

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Answer:

Option 1

Explanation:

Option number 1 is the most compact one which indicates it is a solid

A sample containing both KBr and KI in unknown quantities is given. The sample has a total mass of 5 g and contains 1.51 K. The objective is to determine the percentages of KBr and KI. The percentage of KBr and KI in the sample can be determined by using the following steps

:Step 1: Find the number of moles of K in the sample. Mass of K in the sample = 1.51 gMolar mass of K = 39.1 g/molNumber of moles of K in the sample = Mass of K/Molar mass of K= 1.51/39.1 = 0.0386 mol of K

Step 2: Find the number of moles of KBr and KI in the sample Let the number of moles of KBr be x and the number of moles of KI be y .According to the law of conservation of mass, the mass of KBr and KI will be equal to the total mass of the sample.x+y = 5 g/ (119 g/mol + 166 g/mol) = 0.01875 mol of KBr + KI  (approx)

Step 3: Determine the masses of KBr and KI in the sample Mass of KBr in the sample = number of moles of KBr × Molar mass of KBr= 0.01875 × 119 = 2.231 g of KBr Mass of KI in the sample = number of moles of KI × Molar mass of KI= 0.01875 × 166 = 3.107 g of KI

Step 4: Calculate the percentage of KBr and KI in the sampleThe percentage of KBr in the sample = (mass of KBr / Total mass of the sample) × 100%= (2.231 g / 5 g) × 100% = 44.62 %The percentage of KI in the sample = (mass of KI / Total mass of the sample) × 100%= (3.107 g / 5 g) × 100% = 62.14 %Hence, the percentages of KBr and KI in the given sample are 44.62 % and 62.14 %, respectively.

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Answer:

3.2 cm X 2.8 cm X 2.6 cm/ 1 cube - not exact

1 mL - exact

1 cm³ - exact

12 cubes/ 1 tray - exact

268.8 mL/tray - not exact

Explanation:

We can use the picture attached below to solve this problem. The first part is not exact because Sally is using a ruler to measure the cube which would have a margin of error, regardless of how small. The \(\frac{1ml}{1cm^{3} }\) is exact, since that is the actual accurate exchange. Next, since there are 12 cubes in a single ice tray this measurement is also exact. Lastly, since Sally's initial measurement of the cubes is not exact, then the final calculated value will also not be exact.

a) Caffeine and naphthalene are ideal candidates for sublimation due to their ability to directly transition from a solid to a gaseous state without passing through the liquid phase. b) During the sublimation procedure, caffeine is separated from impurities by heating the crude mixture. c) Two other chemicals that can be purified by sublimation are iodine and camphor.

a) Caffeine and naphthalene are ideal candidates for sublimation because they have high vapor pressure at room temperature, which means that they can easily convert from a solid to a gas without going through a liquid phase. This property is important because it allows the impurities to be left behind in the solid state, while the desired compound (in this case, caffeine and naphthalene) is vaporized and collected.

b) During the sublimation procedure, the crude caffeine is placed in a sublimation apparatus and heated gently. As the temperature increases, the caffeine molecules vaporize and rise to the top of the apparatus. The impurities, which have a higher boiling point and do not vaporize as easily as caffeine, remain in the solid state and are left behind at the bottom of the apparatus. At the end of the process, the caffeine is collected from the top of the apparatus as a purified solid, while the impurities are left behind in the sublimation flask.

c) Two chemicals that could be purified by sublimation include camphor and anthracene. Both of these compounds have high vapor pressure and can easily be converted from a solid to a gas without going through a liquid phase, making them ideal candidates for sublimation purification.

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