Which of the following is closest to the area, in square inches, of the shaded sector of circle Y?
A. 25.7 square inches
B. 51.3 square inches
C. 128.3 square inches
D. 153.9 square inches

And What is the length, to the nearest tenth of an inch, of minor arc XZ?

Blank inches

Which Of The Following Is Closest To The Area, In Square Inches, Of The Shaded Sector Of Circle Y?A.

Answers

Answer 1
That would be B



Answer is B

Related Questions

the equation a=0.003x^2+21.3 models the average ages of women when they first married since the year 1940. In this equation, a represents the average age and x represents the years since 1940. Estimate the year in which the average age of brides was the youngest

Answers

Answer:

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Step-by-step explanation:Please help me important question in image

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Answer:

The equation a=0.003x^2+21.3 models the average ages of women when they first married since the year 1940 in the United States. In this equation, a represents the average age and x represents the years since 1940. To estimate the year in which the average age of brides was the youngest, we need to find the minimum value of the quadratic function a=0.003x^2+21.3. This can be done by using the formula x=-b/2a, where b is the coefficient of x and a is the coefficient of x^2. In this case, b=0 and a=0.003, so x=-0/(2*0.003)=0. This means that the average age of brides was the lowest when x=0, which corresponds to the year 1940. The value of a when x=0 is a=0.003*0^2+21.3=21.3, so the average age of brides in 1940 was 21.3 years old. This is consistent with the historical data, which shows that the median age of women at their first wedding in 1940 was 21.5 years old. The average age of brides has been increasing since then, reaching 28.6 years old in 2021.

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The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass. Starting with grams of a radioactive isotope, how much will be left after 4 half-lives?

Answers

After 4 half-lives, only 1/16th (or 0.0625) of the initial amount of the radioactive isotope will remain.

The amount of a radioactive isotope remaining after a certain number of half-lives can be calculated using the formula:

Amount remaining = Initial amount × (1/2)^(number of half-lives)

In this case, we are given the initial amount as "grams" and we want to find out the amount remaining after 4 half-lives.

So, the equation becomes:

Amount remaining = Initial amount × (1/2)^4

Since each half-life reduces the quantity to half, (1/2)^4 represents the fraction of the initial amount that will remain after 4 half-lives.

Simplifying the equation:

Amount remaining = Initial amount × (1/16)

Therefore, after 4 half-lives, only 1/16th (or 0.0625) of the initial amount of the radioactive isotope will remain.

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i don't understand how to do percentages please explain​

i don't understand how to do percentages please explain

Answers

Answer:

$60.79

Step-by-step explanation:

First take off the 30% from $78.95. That will leave you with $55.265.

Add 6% of $78.95 for sales tax (4.737) to the $55,265 = $60.002

Then add the 1% of $78.95 for local option tax (.7895) to the $60.002.

That gives you $60.7915   - round it to the nearest cent and it gives you

$60.79

Answer: $60.7915

Step-by-step explanation:

think of percents as a portion of something

if Dave has to pay 6% tax on something + 1% tax he will pay 7% tax.

This means he will pay 7% of 78.95.

In multiplication 'of' means multiply.

just use this as a rule so 7% × 78.95 will be the amount of tax he has to pay

0.07 × 78.95 = $5.5265

However, he has a 30% off coupon

so,

30% × 78.95 will give the amount he saves

.3 × 78.95 = $23.685 saved

now lets find the actual amount he saves with his coupon after taxes:

$23.685 - $5.5265 = $18.1585 saved

we can subtract this amount by the price and we will have the amount Dave has to pay for the jeans:

$78.95 - $18.1585 = $60.7915

⇒ $60.7915 is the price Dave pays

rounding we get $60 and 79 cents

Consider the equation: f (x) = 4/x-3+2. Please explain where the vertical asymptote would be algebraically and graphically. Why are asymptotes important when explaining the graph of a rational function? What are the horizontal and vertical shifts from this function compared to the parent function, and how do you know?

Answers

A polynomial is considered rational if it can be written as a polynomial divided by a polynomial.

What is meant by rational function?

Any function that can be expressed as a rational fraction in mathematics—an algebraic fraction in which the numerator and denominator are both polynomials—is referred to as a rational function.

Here,

Given :f (x) = 4/x-3+2.

=> vertical asymptotes :

=> 4/x

and

horizontal asymptotes :

=> -1

The rational function is (x/y)where y≠ 0

So,

x≠0.

can be a rational function for them.

Oblique, vertical, and horizontal asymptotes are the three forms of asymptotes that make up the different types of rational functions. The maximum number of horizontal or oblique asymptotes for a rational function is one, although there can be multiple vertical asymptotes.

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As the CAPS document outlines, the Content Specification and Content Clarification for Patterns, Functions, and Algebra shows sequenced mathematics content topics and a content area spread. In the Intermediate Phase, select one topic and report on the topic sequence and content area spread. Your report should demonstrate mathematics concepts and procedures’ hierarchical and logical progression.

Answers

Answer:

Step-by-step explanation:

In the Intermediate Phase of mathematics education, one topic that demonstrates a hierarchical and logical progression in patterns, functions, and algebra is the concept of "Linear Equations."

The topic of Linear Equations in the Intermediate Phase builds upon the foundation laid in earlier grades and serves as a stepping stone towards more advanced algebraic concepts. Here is an overview of the topic sequence and content area spread for Linear Equations:

Introduction to Variables and Expressions:

Students are introduced to the concept of variables and expressions, learning to represent unknown quantities using letters or symbols. They understand the difference between constants and variables and learn to evaluate expressions.

Solving One-Step Equations:

Students learn how to solve simple one-step equations involving addition, subtraction, multiplication, and division. They develop the skills to isolate the variable and find its value.

Solving Two-Step Equations:

Building upon the previous knowledge, students progress to solving two-step equations. They learn to perform multiple operations to isolate the variable and find its value.

Writing and Graphing Linear Equations:

Students explore the relationship between variables and learn to write linear equations in slope-intercept form (y = mx + b). They understand the meaning of slope and y-intercept and how they relate to the graph of a line.

Systems of Linear Equations:

Students are introduced to the concept of systems of linear equations, where multiple equations are solved simultaneously. They learn various methods such as substitution, elimination, and graphing to find the solution to the system.

Word Problems and Applications:

Students apply their understanding of linear equations to solve real-life word problems and situations. They learn to translate verbal descriptions into algebraic equations and solve them to find the unknown quantities.

The content area spread for Linear Equations includes concepts such as variables, expressions, equations, operations, graphing, slope, y-intercept, systems, and real-world applications. The progression from simple one-step equations to more complex systems of equations reflects a logical sequence that builds upon prior knowledge and skills.

By following this hierarchical progression, students develop a solid foundation in algebraic thinking and problem-solving skills. They learn to apply mathematical concepts and procedures in a systematic and logical manner, paving the way for further exploration of patterns, functions, and advanced algebraic topics in later phases of mathematics education.

a committee of six is chosen from 12 men and 8 women. determine the number of ways of selecting the committee if​

Answers

Answer: there is different types of selecting committe but most of the tuime is men before women

Step-by-step explanation:

try to answer all the questions below!

try to answer all the questions below!

Answers

Part 1

a.  In function notation, we have that R(3) > D(3)

b. In function notation, we have that R(0) - D(0) = 25

Part 2

The drone is 20 feet above the ground when the rocket hit the ground.

Part 3

a. R(t) = D(t) when the graphs intercept at t = 4.75 s

b.  It tell us that the drone and rocket are at the same height at that time.

What is a function notation?

A function notation is the representation of a statement as a mathematical equation using symbols.

Part 1

a. To write the statement at 3 seconds the toy rocket is higher than the drone in function notation.

Since

R(t) represents height of toy rocket and D(t) represents height of drone.

At t = 3, the toy rocket is higher than the drone.

So, in function notation, we have that R(3) > D(3)

b. To write the statement at the start the toy rocket is 25 feet above the drone.

Since R(t) represents height of toy rocket and D(t) represents height of drone.

At the start t = 0, and the toy rocket is 25 feet above the drone.

So, in function notation, we have that R(0) - D(0) = 25

Part 2.

To find the height of the drone when the rocket hit the ground,

Since

R(t) represents height of toy rocket and D(t) represents height of drone.

We find R(t) = 0 and find the time t, where it intercepts the height of the drone.

So, from the graph R(t) = 0 at t = 5. And at t = 5, D(t) = 20

So, the drone is 20 feet above the ground when the rocket hit the ground.

Part 3.

a. The value of t at which R(t) = D(t) is where the graphs intercept.

The graphs intercept at t = 4.75 s

b. Since R(t) = D(t) at t = 4.75 s, it tell us that the drone and rocket are at the same height at that time.

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Ahab spent the day at the mall. First, he bought three tires for $50 each. Later, he returned one tire. After that, he found a five dollar bill. Also,he bought two jackets for $40 each. Write the total change to Ahab's funds as an integer.

Ahab spent the day at the mall. First, he bought three tires for $50 each. Later, he returned one tire.

Answers

Ahab's total change to funds is -$175, which means he spent more than he gained.

What are the funds?

Ahab spent 3 tires at $50 each, which is a total of 3 x $50 = $150.

Later, he returned one tire, so he gets $50 back.

He also found a $5 bill, so he has an extra $5.

He then bought 2 jackets at $40 each, which is a total of 2 x $40 = $80.

The total amount Ahab spent is $150 + $80 = $230.

However, he also received $50 back and found $5, so his total change to funds is $50 + $5 - $230 = -$175.

Therefore, Ahab's total change to funds is -$175, which means he spent more than he gained.

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The result of which expression will best estimate the actual product ofO(-1)(-1O(-1)(1)- OMark this and returnK

The result of which expression will best estimate the actual product ofO(-1)(-1O(-1)(1)- OMark this and

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

data:

numerical expression

Step 02:

We must apply the algebraic rules to find the solution.

numerical expression:

\((-\frac{4}{5})*(\frac{3}{5})*(-\frac{6}{7})*(\frac{5}{6})=\frac{12}{35}\)

We must compare the result obtained in the original expression to find the solution.

Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.
a. Calculate a 95% two-sided confidence interval on the death rate from lung cancer.
b. Using the point estimate of p obtained from the preliminary sample, what sample size is needed to be 95% confident that the error in estimating the true value of p is less than 0.03?
c. How large must the sample be if you wish to be at least 95% confident that the error in estimating p is less than 0.03, regardless of the true value of p?

Answers

Answer:

a) \(0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799\)

\(0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847\)

The 95% confidence interval would be given by (0.799;0.847)

b) \(n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79\)  

And rounded up we have that n=622

c) \(n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11\)  

And rounded up we have that n=1068

Step-by-step explanation:

Part a

\(\hat p=\frac{823}{1000}=0.823\)

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \(\alpha=1-0.95=0.05\) and \(\alpha/2 =0.025\). And the critical value would be given by:

\(z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96\)

The confidence interval for the mean is given by the following formula:  

\(\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}\)

If we replace the values obtained we got:

\(0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799\)

\(0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847\)

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

\( ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}\)    (a)  

And on this case we have that \(ME =\pm 0.03\) and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

\(n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}\)   (b)  

And replacing into equation (b) the values from part a we got:

\(n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79\)  

And rounded up we have that n=622

Part c

\(n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11\)  

And rounded up we have that n=1068

the nominal interest rate is 29% compounded quarterly. compute the effective annual interest rate. express your answer as a percentage rounded to the nearest one-hundredth decimal place (for example, enter 15.47 for an answer of 15.4695236%).

Answers

From the given information provided, as the nominal interest rate is 29%, the effective annual interest rate is 35.84%.

To calculate the effective annual interest rate, we need to use the following formula:

Effective Annual Interest Rate = \((1 + (Nominal Interest Rate / m))^m\)

where m is number of compounding periods per year.

In this case, the nominal interest rate is 29%, compounded quarterly, so m = 4.

Plugging in the values, we get:

Effective Annual Interest Rate = (1 + (0.29 / 4))⁴ - 1

= 0.3584

To express this as a percentage rounded to the nearest one-hundredth decimal place, we multiply by 100 and round:

Effective Annual Interest Rate = 35.84%

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For the question below, think carefully about what you divide 80 by to calculate the value of one part.

In a housing estate the direct proportion of flats to houses is 2:5. If there are 80 flats, how many houses are there?

Answers

Answer:

200

Step-by-step explanation:

\(\frac{2}{5}\) = \(\frac{80}{x}\)

2 x 40 = 80, so

5 x 40 = 200

Answer:

200 houses

Step-by-step explanation:

Flat: 2 parts = 80 flats
1 part => 80 : 2 = 40 flats
Houses: 5 parts = 40 x 5 = 200 houses

If a=2 and c=10 what does b equal ? ( Pythagorean Therom

Answers

Answer:

b = \(\sqrt{96}\)

Step-by-step explanation:

a^2 + b^2 = c^2 is the Pythagorean theorem

if A = 2 and C = 10 then you get

2^2 + b^2 = 10^2

or 4 + b^2 = 100

b^2 = 96

b = square root of 96 or approximately 9.8

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Ashanti Goldfields, wanted to undertake a project which will costs GH 30,000 now and is expected to generate year –end cash inflows of GH 9000, GH 8000, GH 7000, GH 6000, GH5000 and GH 4000 in years 1 through 6.The opportunity cost of capital may be assumed to be 10 percent.

Answers

Answer:

I strongly believe that NPV of the project is the requirement of this question:

NPV is -$486.82

Step-by-step explanation:

The NPV is the present value of the future cash flows from year 1 through year 6 minus the initial capital investment of GH30,000

The cash flow discount factor =1/(1+r)^n

r is the opportunity cost of capital at 10%

n is the relevant year of each cash flow

NPV=-30,000+9000/(1+10%)^1+8000/(1+10%)^2+7000/(1+10%)^3+6000/(1+10%)^4+5000/(1+10%)^5+4000/(1+10%)^6=-$486.82

The project is not viable since NPV is negative

How to solve adjacent angles?

How to solve adjacent angles?

Answers

Answer:

D

Step-by-step explanation:

1 + 4x and 57° are corresponding angles and are congruent , so

1 + 4x = 57 ( subtract 1 from both sides )

4x = 56 ( divide both sides by 4 )

x = 14

order froom least to greatest, 1/4, 32%, 0.4​

Answers

Answer:

1/4

32%

0.4

Step-by-step:

1/4 = 0.25

32 = 0.33

0.4 = 0.40

Select the choice that translates the following verbal phrase correctly to algebra:

the difference of m and 7 increased by 15

m − (7 + 15)
7m + 15
(m − 7) + 15
m − 7 ÷ 15

Answers

The answer is:
(M - 7) +15

Jane has been practicing sewing, and she wants to make a rectangular blanket to give as a gift to her best friend. So that the blanket is not too small, Jane decides the blanket will have an area of approximately 40 square feet, or 5,760 square inches. She also wants the blanket to be 18 inches longer than it is wide to have room to embroider her friend's name along one edge.
To the nearest tenth of an inch, what is the width of the blanket?

Answers

The width of the blanket to the nearest tenth of an inch is approximately 67.4 inches.

What is width in rectangle ?

In a rectangle, the width refers to the measurement of the shorter side of the rectangle, which is perpendicular to its length.

Let x be the width of the blanket in inches. Then the length of the blanket is x + 18 inches.

The area of the blanket is given by:

Area = Length x Width

5760 sq inches = (x + 18) inches * x inches

Expanding the right-hand side and solving for x, we get:

\(x^2 + 18x - 5760 = 0\)

We can solve this quadratic equation using the quadratic formula:

\(x = (-b \pm \sqrt{(b^2 - 4ac)}) / 2a\)

where a = 1, b = 18, and c = -5760. Plugging in these values, we get:

\(x = (-18 \pm \sqrt{(18^2 - 4(1)(-5760))}) / 2(1)\)

\(x = (-18 \pm \sqrt{(18^2 + 23040)}) / 2\)

x ≈ 67.42 or x ≈ -85.42

Since the width cannot be negative, the width of the blanket to the nearest tenth of an inch is approximately 67.4 inches.

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\(\frac{d}{dx} \int t^2+1 \ dt\)
There is a 2x on the bottom and x^2 on top of the integral symbol
Please help me my teacher did not teach us this:(

Answers

Answer:

\(\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2\)

Step-by-step explanation:

\(\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} = \ ?\)

We can use Part I of the Fundamental Theorem of Calculus:

\(\displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}\)

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

\(\displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}\)

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

\(\displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}\)

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

\(\displaystyle\int\limits^b_a \text{f(t) dt}\ = -\int\limits^a_b \text{f(t) dt}\)

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

\(\displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}\)  

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

\(\displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]\)where u represents any function other than a variable

For the first term, replace \(\text{t}\) with \(2x\), and apply the chain rule to the function. Do the same for the second term; replace

\(\displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)\)  

Simplify the expression by distributing \(2\) and \(2x\) inside their respective parentheses.

\([-(8x^2 +2)] + (2x^5 + 2x)\) \(-8x^2 -2 + 2x^5 + 2x\)

Rearrange the terms to be in order from the highest degree to the lowest degree.

\(\displaystyle2x^5-8x^2+2x-2\)

This is the derivative of the given integral, and thus the solution to the problem.

Is this a false or true statement? Extrapolation is the use of the regression line to estimate a mean of y-values for an x-value that is far outside the x-range of data.

Answers

This is False in light of the stated statement. due to the employment of a regression line to calculate the mean of y for x that are outside the x-range of the data.

How is regression calculated?

Y = mX + b, where X is the predictive (independent) factor, m is really the approx slope, and b is the expected intercept, is the methodology for simple linear regression.

What makes regression math so special?

Regress, from whence the word "regression" is derived, means "to go back" in Latin (to something). Regression is the method that enables "going back" from muddled, challenging data to a clearer and more significant model in this manner.

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Melinda is planning for retirement so she makes monthly deposits of $420 in an account earning 5% compounded monthly for 30 years.

(a) Find the amount that Melinda has in the account in 30 years.
$?

(b) Once she retires she will make monthly withdraws on the account for 20 years. Assuming that once she starts withdrawing on the account, she will earn 4% compounded monthly. Find the amount that she can withdraw every month.
$?

Answers

a) 5/100 x 420 = 21
21 x 12 x 3= 756
420 x 12 x 3 = 15,120
15,120+756= 15,876

b) 4/100 x 420= $16.8

A deli sandwich shop is offering either a ham or turkey sandwich, either tomato or vegetable soup, and either coffee or milk for their lunch special. What is the probability that a customer will choose vegetable soup as part of the chosen combination?

Answers

Answer:

Ok, the first step is to count all the possible selections that we have and the number of options in each selection:

1) Sandwich: 2 options, ham or turkey.

2) Soup, 2 options, tomato or vegetable.

3) Drink, 2 options, coffee or milk.

(i assume that the sandwich and the soup are separated selections)

Now, if the customer chooses at random, the probability that in one given selection he selects a given outcome is equal to the number of options that match the outcome divided by the total number of options for that selection.

Then in the soup selection we have: options that match the outcome (one, is the vegetable soup). Total number of options = 2.

Then the probability is:

P = 1/2 = 0.5

or 0.5*100% = 50% in percentage form.

Answer:

1/2

Step-by-step explanation:

the question is 4 1/5 x 5/14

Answers

Answer:

3/2

Step-by-step explanation:

Simplify the following:

((4 + 1/5)×5)/14

((4 + 1/5)×5)/14 = ((4 + 1/5)×5)/14:

((4 + 1/5)×5)/14

Put 4 + 1/5 over the common denominator 5. 4 + 1/5 = (5×4)/5 + 1/5:

(((5×4)/5 + 1/5) 5)/14

5×4 = 20:

((20/5 + 1/5)×5)/14

20/5 + 1/5 = (20 + 1)/5:

(((20 + 1)/5)×5)/14

20 + 1 = 21:

(21/5×5)/14

21/5×5 = (21×5)/5:

((21×5)/5)/14

((21×5)/5)/14 = (21×5)/(5×14):

(21×5)/(5×14)

(21×5)/(5×14) = 5/5×21/14 = 21/14:

21/14

The gcd of 21 and 14 is 7, so 21/14 = (7×3)/(7×2) = 7/7×3/2 = 3/2:

Answer:  3/2

A phone company offers two monthly plans. Plan A costs $20 plus an additional $0.08 for each minute of calls. Plan B costs $16 plus an additional $0.13 for each minute of calls. For what amount of calling do the two plans cost the same? minutes What is the cost when the two plans cost the same? ​

Answers

20 + 0.08x = 16 + 0.13x
20 - 16 = 0.13x - 0.08x
4 = 0.05x
x = 80 minutes

20 + 0.08(80) = 16 + 0.13(80)
20 + 6.4 = 16 + 10.4
$26.40

why the nature of the roots depend on the value of the discriminant​

Answers

The value of a discriminant determines the kind of roots in a quadratic equation, and the sign of a discriminant indicates whether the roots were real or complex, unique or recurring.

What does a math quadratic equation mean?

Definitions: x ax2 + bx + c = 0 is a quadratic equation, which is a 2nd quadratic formula in a single variable. a 0. It has at most one solution since it is a 2nd quadratic problem, which is guaranteed by the algebraic basic theorem. The solution could be straightforward or difficult.

How do you determine whether an equation is quadratic?

To put it another way, if a twice the square of a expression that comes after b plus b times the same expression never squared plus c equals 0.

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4y-27=3y then y is equal to ?

Answers

Answer:

y=4/3y -9

Step-by-step explanation:

just divide both sides of the equation by 3


The value of a machine depreciates at the rate of 10% per annum. It was purchased 3 years ago. If its present value is Rs 43740, find its purchase price.

pls anwer in details! no spam...​

Answers

Given

present value of the machine : Rs 43,740Rate of depreciation per annum : 10%

To find

Purchase value of the machine ( 3 years before )

Let the purchase value be P,

ATQ,

P -3 x 0.1P = Rs 43,740

P-0.3P = Rs 43,740

0.7P = Rs 43,740

P = Rs 43,740/0.7

P = Rs 62,486 (approx)

Hence, the purchase value of the machine would be Rs 62,486

What shape best describes the cross-section cut perpendicular to the base of a right rectangular prism? O Parallelogram Trapezoid O Rectangle O Rhombus​

What shape best describes the cross-section cut perpendicular to the base of a right rectangular prism?

Answers

The cross-section perpendicular to the base of a right rectangular prism is a rectangle.

What is a three dimensional shape?

A shape or a solid that has three dimensions that is length, width and height is called a 3D shape. 3D shapes have faces, edges, and vertices. Examples are cylinder, cone, prism, pyramid.

A shape that has two dimensions is called a 2D shape. 2D shapes have breadth and length.

The cross-section perpendicular to the base of a right rectangular prism is a rectangle.

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help me please

Indicate the method you would use to prove the two triangles. If no method applies, enter "none".
AAS
SSS
NONE
SAS
ASA

help me pleaseIndicate the method you would use to prove the two triangles. If no method applies, enter

Answers

ASA is the correct answer

Based on the information given, we know that the two triangles have two pairs of congruent angles. This is sufficient to prove that the two triangles are congruent using the AAS (Angle-Angle-Side) postulate. Therefore, the method I would use to prove the two triangles congruent is **AAS**.

Ming rented a bike from Ted's Bikes. It cost $13 plus $3 per hour. If Ming paid $31,
then he rented the bike for how many hours?

A)7.
B)10.3333
C)6
D)10

Answers

Answer:

C, 6

Step-by-step explanation:

31-13 is 18, 18/3 is 6.

Answer:

6

Step-by-step explanation:

31-13= 18

18÷3 = 6

Answer from Gauthmath

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