which of the following equations are linear? question 1 options: 4y=8 y2=6x3 8 3y=6x 5y2 y-x=8x2

Step 2.1 code is given in the question. In step 2.2, we have to change the variables, m(t) and c(t) and plot the following equations:m(t) = 3cos(2π*700Hz*t)c(t) = 5cos(2π*11kHz*t)The modified code will be:Amplitude of message signal, Am = 3 Amplitude of carrier signal, Ac = 5 Frequency of message signal, fm = 700Hz Frequency of carrier signal, fc = 11kHz.

The amplitude modulation index is given as, mi = Am/Ac = 3/5 = 0.6The modulated signal is given as,s=Ac*(1+mi*cos(2*pi*fm*t)).*cos(2*pi*fc*t);The plot of the signals can be seen below:From the plots, we can see that the signal, s(t), faithfully represents the original message wave m(t). Hence, the correct option is (a) The signal, s(t), faithfully represents the original message wave m(t).

Step 2.3 requires us to plot the following equations:m(t) = 40cos(2π*300Hz*t)c(t) = 6cos(2π*11kHz*t)The modified code will be:Amplitude of message signal, Am = 40 Amplitude of carrier signal, Ac = 6 Frequency of message signal, fm = 300HzFrequency of carrier signal, fc = 11kHz The amplitude modulation index is given as, mi = Am/Ac = 40/6 > 1The modulated signal is given as,s=Ac*(1+mi*cos(2*pi*fm*t)).*cos(2*pi*fc*t);The plot of the signals can be seen below:From the plots, we can see that the signal, s(t), is distorted because the AM Index value is too high. Hence, the correct option is (a) The signal, s(t), is distorted because the AM Index value is too high.

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Answer:

She can refill 2 cages.

Step-by-step explanation:

Since Megan puts 1/3 of a kilogram of bird seed in each bird cage, she can fill 2 cages.

Answer: she can fill 2 times the amount of cages she has.

say: x=the cages

so 2x/ 2 times of the cages

hope this helps! i tried :)

Answer:

x = 45, y = 85

Step-by-step explanation:

In this figure we can see a Z-angle, which tells us that x = 45

In a triangle, the sum of the angles is 180 degrees,

so the unknown angle in the triangle is 180 - 45 - 85 = 50

For a straight line, the total angle is 180 degrees,

, so y + x + unknown angle of triangle = 180

since x = 45, and unknown angle of triangle = 50,

y = 180 - 45 - 50 = 85

This can also be seen when you realise that the two parallel lines give an F-angle, which tells us that Y = 85

Let's assume the sum of the scores of the 28 students who took the test yesterday is 28 * 72 = 2016.

We know that the sum of the scores of all 30 students is (28 * 72) + x + y, where x and y are the scores of the two students who took the test this morning.

We also know that the mean of all 30 scores is 73. So we can write an equation:

[(28 * 72) + x + y]/30 = 73

Multiplying both sides by 30, we get:

2016 + x + y = 2190

So, x + y = 174.

We are given that the difference of the two scores is 22, so we can write another equation:

y - x = 22

Solving these two equations simultaneously, we get y = 98 and x = 76.

Therefore, the lower score from this morning is 76.

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The product of the two polynomials is (8x³)(4x⁷) = 32x¹⁰.

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The first-order partial derivative fy of the function f(x, y) = y * in(2\(x^{2}\)4 + 3y) is:

fy = in(2\(x^{2}\) 4 + 3y) + y * (1 / (2\(x^{2}\) 4 + 3y)) * (0 + 3)

The first-order partial derivative fy of the given function can be found by taking the derivative of the function with respect to y while treating x as a constant. In this case, the function is f(x, y) = y * in(2\(x^{2}\)4 + 3y). To find fy, we first apply the derivative of the natural logarithm function. The derivative of in(2\(x^{2}\)4 + 3y) with respect to y is simply 1 / (2\(x^{2}\)4 + 3y) since the derivative of in(u) with respect to u is 1/u.

Next, we use the product rule to differentiate y * in(2\(x^{2}\)4 + 3y). The derivative of y with respect to y is 1, and the derivative of in(2\(x^{2}\)4 + 3y) with respect to y is 1 / (2\(x^{2}\)4 + 3y). Finally, we multiply the derivative of in(2\(x^{2}\)4 + 3y) with respect to y by y, giving us fy = in(2\(x^{2}\)4 + 3y) + y * (1 / (2\(x^{2}\)4 + 3y)) * (0 + 3).

Partial derivatives allow us to analyze how a function changes concerning each input variable while holding the others constant. In this case, finding the first-order partial derivative fy helps us understand how the function f(x, y) changes with respect to y alone.

It provides insight into the rate of change of the function concerning variations in the y variable, independent of x. This information is valuable in many mathematical and scientific applications, such as optimization problems or understanding the behavior of multivariable functions.

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Answer: If Henry wants to buy the MP3 player he needs 9weeks worth of allowance.

Step-by-step explanation:

Answer:

A Because It's Called *Fixed*

Step-by-step explanation:

Sorry If it's Wrong

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The Correct choice is ~

Answer:

the answer is 2...........jpjpjp ion knowwwwwwwww

Step-by-step explanation:

Answer:

A(t) = -(15/2)t + 50

Step-by-step explanation:

First, let me complete the question for you, cause there are a missing part here:

Addison painted her room. She had 50 square meters to paint, and she painted at a constant rate. After 2 hours of painting, she had 35 square meters left. Let A(t), denote the area to paint A (measured in square meters) as a function of time t (measured in hours).

According to the question, we want an expression as a function that explains the rate of painting of Addison. It states that is painting at a constant rate, therefore, we can assume that is a linear function (Cause is constant with time)

The expression for a linear function is:

y = mx + n    (1)

So, If A(t) is the area to paint, we know that at the beggining, before it began the painting we have the whole 50 m² to paint, and hence, we can assume that at time 0 h, we have left to paint 50 m².

After t = 2h, 35 m² were left unpainted, so in order to write an function we need a slope and a interception in y axis. to get the slope we apply the following expression:

m = y₂ - y₁ / x₂ - x₁  (2)

We have two points, so we can use them to  get the slope:

Point 1: (0, 50);   Point 2: (2, 35)

m = 35 - 50 / 2 - 0

m = -15/2 or -7.5

Now that we have the slope, let's get interception n:

50 = -7.5(0) + n

50 = n

Hence, the expression to this painting rate will be:

You can use any of these two.

Hope this helps

Step-by-step explanation:

rewriting the third equation

\(4x - y + z = - 5 \\ - x + y - z = 5 \\ 2x - y - z = 1\)

add to second equation to the first

\(4x - y + z = - 5 \\ + (- x + y - z )= 5 \\ = 3x = 0 \\ x = 0\)

\( - y + z = - 5 \\ y - z = 5 \\ - y - z = 1\)

I add third equation to the second

\(y - z = 5 \\ + ( - y - z) = 1 \\ = - 2z = 6 \\ z = - 3\)

substitute z = -3 into either one of the other two equations and solve for y

\( - y + ( - 3) = - 5 \\ - y - 3 = - 5 \\ - y = - 2 \\ y = 2\)

x = 0

y = 2

z = -3

Answer:

x=0,z=-3,y=2

Step-by-step explanation:

sry for late response

To find the arc length of the function y = 2x^2 + 4 on the interval 0 < x < 4, we first need to use the formula for arc length:

arc length = ∫(sqrt(1 + (dy/dx)^2)) dx, where the integral is taken over the given interval.

Taking the derivative of y with respect to x, we get:

dy/dx = 4x

Substituting this back into the formula for arc length, we get:

arc length = ∫(sqrt(1 + (4x)^2)) dx from x = 0 to x = 4

Simplifying the expression inside the integral, we get:

arc length = ∫(sqrt(1 + 16x^2)) dx from x = 0 to x = 4

Using the substitution u = 4x^2 + 1, du/dx = 8x, we can rewrite the integral as:

arc length = (1/8)∫sqrt(u) du from u = 5 to u = 33

Solving the integral, we get:

arc length = (1/8)(2/3)(33^(3/2) - 5^(3/2)) ≈ 16.83 units

Therefore, the arc length of y = 2x^2 + 4 on 0 < x < 4 is approximately 16.83 units.

The arc length of the function y = 2x^2 + 4 on the interval 0 < x < 4 is approximately 16.83 units. This was found by using the formula for arc length, taking the derivative of the function, simplifying the expression inside the integral, and solving the integral using substitution.

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The probability for the particle to exist between x=0 and x=L/3, when the quantum number n=3, is 1/9.

In quantum mechanics, a particle in a one-dimensional box of length L can only occupy certain discrete energy levels determined by the quantum number n. The energy levels are given by the equation En = (\(n^2\) * \(h^2\))/(8m\(L^2\)), where h is Planck's constant and m is the mass of the particle.

Given that the quantum number n = 3, we can determine the energy associated with this level as E3 = (\(3^2\) * \(h^2\))/(8m\(L^2\)).

The probability of finding the particle between x=0 and x=L/3 corresponds to the portion of the total probability density function (PDF) within that range. The PDF for a particle in a box is given by P(x) = |ψ\((x)|^2\), where ψ(x) is the wave function.

For the ground state (n = 1), the wave function is a sin(xπ/L) and the corresponding PDF is proportional to \(sin^2\)(xπ/L). For n = 3, the wave function becomes sin(3xπ/L), and the corresponding PDF is proportional to\(sin^2\)(3xπ/L).

To find the probability, we integrate the PDF from x=0 to x=L/3, which is equivalent to calculating the area under the PDF curve within that range. In this case, the integral is ∫[0 to L/3] \(sin^2\)(3xπ/L) dx.

Evaluating this integral gives us a result of 1/9, indicating that there is a 1/9 probability of finding the particle between x=0 and x=L/3 when the quantum number n=3.

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Answer:

5 1/7 pages in one hour. And what does "A.B.C.D." Mean?

Step-by-step explanation:

The probability of meeting the manager's objectives is 0.0118.

The probability of meeting the manager's objectives if members for the team and the captain were randomly selected is very low, at 0.0118.

This is due to the fact that there are 50 basketball players in total, and the manager wants to select 5 of them, with 2 of them being seniors, 3 of them being juniors, and one of the seniors to be the captain.

This narrows the number of possibilities greatly and makes it a difficult task for the manager to fulfill.

Furthermore, the fact that the selection process is random does not help either.

This means that the manager has no control over who is chosen, and thus has to hope that the randomly selected group fulfills the desired criteria.

This makes the probability of meeting the manager's objectives even lower, as the chances of a completely random selection meeting the criteria is very low.

In conclusion,

The probability of meeting the manager's objectives if members for the team and the captain were randomly selected is very low, at 0.0118.

This shows that it is a difficult task for the manager to fulfill, and that the selection process should be carefully considered if they want to ensure that they meet their objectives.

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Step-by-step explanation:

well that is the really easy one :

the number of produced drills cannot be more than 210 per day.

while the first inequality addressed the work hours, the second simply addresses the number of drills.

therefore,

x + y <= 210

We need to  know about margin of error to solve the problem. The factors that influence margin of error are confidence level and sample size.

Margin of error is a statistic expressing the amount of random sampling error in the results of a survey. The larger the margin of error, the less confidence one should have that a poll result will reflect the result of a census of the entire population. Margin of error is influenced by three factors, confidence level, sample size and population standard deviation. In absence of population standard deviation, the margin of error is influenced by confidence level and sample size.

Therefore the margin of error is influenced by confidence level and sample size.

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Step-by-step explanation:

I hope this answer is helpful ):

Using a significance level of α = 0.05, the critical value is -1.645, and we should reject H0, indicating that there is evidence to support the claim that p < 0.45.

We have,

You are testing the claim that p < 0.45 using a test statistic of z = -3.19 and a significance level of α = 0.05.

Step 1:

Determine the critical value(s) using the significance level:
Since this is a left-tailed test (claim is p < 0.45), you'll need to find the critical value for a one-tailed test at α = 0.05. Using a standard normal distribution table or a calculator, you find that the critical value is z = -1.645.

Step 2:

Compare the test statistic to the critical value:
The test statistic z = -3.19 is more negative (to the left) than the critical value z = -1.645.

Step 3:

Make a decision regarding H0:
Since the test statistic is more negative than the critical value, we reject H0. This means there is sufficient evidence to support the claim that p < 0.45 at a significance level of 0.05.

Thus,
Using a significance level of α = 0.05, the critical value is -1.645, and we should reject H0, indicating that there is evidence to support the claim that p < 0.45.

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The value of the error for Z, where x = 5.9 +/- 0.5 and y = 2.1 +/- 0.2, with one decimal place is 4.

To calculate the error in Z, we need to consider the uncertainties in both x and y. The error in Z can be determined by propagating the uncertainties using the formula for error propagation.

In this case, Z is given by the equation Z = x/y. To propagate the uncertainties, we use the formula for relative error:

ΔZ/Z = sqrt((Δx/x)^2 + (Δy/y)^2)

Given the uncertainties Δx = 0.5 and Δy = 0.2, and the values x = 5.9 and y = 2.1, we substitute these values into the formula:

ΔZ/Z = sqrt((0.5/5.9)^2 + (0.2/2.1)^2) = sqrt(0.0089 + 0.0181) ≈ 0.134

Multiplying this value by 100 to convert it to a percentage, we get approximately 13.4%. Rounding to one decimal place, the value of the error is 4.

Therefore, the value of the error for Z, with one decimal place, is 4.

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Answer: Job catagory.

Answer:

Total area of board = 36x² + 324 + 216x

Step-by-step explanation:

Given:

Side of square = x + 3

Total number of square = 6 x 6 = 36

Area of each square = Side x Side

Area of each square = (x + 3)²

Area of each square = x² + 9 + 6x

Total area of board = 36[Area of each square]

Total area of board = 36[x² + 9 + 6x]

Total area of board = 36x² + 324 + 216x

The 95% confidence interval estimate for the population proportion of car deals that used 0% financing is (0.1612, 0.2308). So, the correct option is (b).

To construct a confidence interval estimate for the population proportion of car deals that used 0% financing, we can use the formula

CI = p ± z√((p(1-p))/n)

where

p = sample proportion = 98/500 = 0.196

n = sample size = 500

z = z-score for the desired level of confidence, which is 95% in this case. From a standard normal distribution table, the z-score corresponding to 95% confidence level is approximately 1.96.

Substituting the values, we get

CI = 0.196 ± 1.96√((0.196(1-0.196))/500)

= (0.1612, 0.2308)

Therefore, the 95% confidence interval estimate is (0.1612, 0.2308).

The correct answer is (b).

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We know that there is only 1 group of 3/4 on the number line and 5 ÷ 3/4 is 3/20 respectively.

A number line is a diagram of a graduated straight line used to represent real numbers in introductory mathematics.

It is assumed that every point on a number line corresponds to a real number and that every real number corresponds to a point.

Above the first hashmark on the left, start at zero.

Write the following number up at each hashmark. Write 1, for instance, above the hash mark next to zero.

You can write these in pen as well, allowing you to repeatedly use the number line.

So, while observing the number we know that there is only 1 group of 3/4 on the number line.

Now, calculate for: 5 ÷ 3/4

5 ÷ 3/4

5/1 ÷ 3/4

1/5 × 3/4

3/20

Therefore, we know that there is only 1 group of 3/4 on the number line and 5 ÷ 3/4 is 3/20 respectively.

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Step-by-step explanation:

x^2 + 10 = 0

x^2 = -10

x =  ± i \(\sqrt{10}\)

We're dealing with linear functions. f(x) = mx + b, We have here the first function. g(x) = 3x That is a linear function with a slope and no linear coefficient because, However, because all of the functions below have the same slope value, they all describe parallel lines.  

Their non-zero linear coefficients are -6,-18,6,18, despite the fact that they all have the same slope value. The first one, though, was

\($\begin{aligned} & h(x)=3(9 x-2) \rightarrow h(x)=27 x-6 \\ & i(x)=9(3 x-2) \rightarrow i(x)=27 x-18 \\ & j(x)=3(9 x+2) \rightarrow j(x)=27 x+6 \\ & k(x)=9(3 x+2) \rightarrow k(x)=27 x+18\end{aligned}$\)

A possible solution would be adjusting any of these, whose operation would result in g(x)=3x, but

Like

\($y=9\left(\frac{3 x}{9}-2\right)+18=3 x$\)

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The type of sampling described in the scenario is known as systematic sampling.

Systematic sampling involves selecting elements from a population in a systematic and predetermined manner. In this case, the researcher is selecting every 20th name from the student directory to form her sample. This method of sampling is relatively simple to execute and can be less time-consuming compared to other methods such as random sampling. However, it is important to ensure that the selected interval does not coincide with any underlying patterns in the population that may bias the results.

Overall, systematic sampling can be a useful method for obtaining a representative sample from a large population, but it is important to consider the potential limitations and biases associated with this approach.

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Answer:

The answer is option C

Step-by-step explanation:

f(x) = x³ + 2x² + 3x + 4

To find f(-1) substitute the value of x that's

- 1 into f(x)

That's

We have the final answer as

Hope this helps you