an astronomer wants to observe a cloud of cold neutral (not ionized) hydrogen, far away from any stars. what would be an instrument that could help in this task?
Why is an electromagnet used instead of a permanent magnet in magnetic cranes?
Answer:
an electromagnet is a metal which has the ability to turn into a magnet on passing electricity through it .
But once the electric flow is withdrawn the circuit breaks and it no more behaves like a magnet.
but this is not so in permanent magnets
Explanation:
thus electromagnet is used in magnetic cranes bcoz their magnetism can be controlled conveniently.
Which statement is correct about the equation for work?
O work = force x distance
work = fulcrum x distance
O work = force x direction
Answer:
work equal to Force times distance
An air conditioner costs $13.50 to run for nine hours a day. If the thermostat temperature was adjusted so that the air conditioner would be on only five hours a day, how much money would be saved daily
Adjusting the thermostat to reduce the air conditioner usage to five hours a day would save $7.50 daily.
The cost to run the air conditioner for nine hours a day is $13.50. To find the cost per hour, we can divide the total cost by the number of hours: \(\frac{13.50}{9} = $1.50 per hour\).
If the air conditioner is only running for five hours a day, the daily cost would be 5 hours × $1.50 per hour = $7.50.
By adjusting the thermostat to reduce the air conditioner usage from nine hours to five hours, there would be a daily saving of $7.50. This reduction in operating time leads to decreased energy consumption, resulting in cost savings. It's important to note that these calculations assume a consistent electricity rate and do not consider other factors such as seasonal variations, maintenance costs, or the specific energy efficiency of the air conditioner.
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A 35kg wheel rotate with an angular speed of 3000rev/min if the radius gyration of a wheel is 12cm. determine the kinetic energy
The kinetic energy of the wheel, with an angular speed of 3000rev/min if the radius gyration of the wheel is 12cm, is approximately 24,568.15 Joules.
To determine the kinetic energy of the wheel, we'll need to use the following formula:
Kinetic Energy (KE) = 0.5 * I * ω²
Where I is the moment of inertia, and ω is the angular speed in radians per second.
First, we need to convert the angular speed from rev/min to radians per second:
ω = 3000 rev/min * (2π radians/rev) * (1 min/60 sec) = 314.16 radians/sec
Next, we can calculate the moment of inertia using the mass (35 kg) and radius of gyration (0.12 m):
I = m * k² = 35 kg * (0.12 m)² = 0.504 kg*m²
Finally, we can find the kinetic energy:
KE = 0.5 * 0.504 kg*m² * (314.16 radians/sec)² = 24,568.15 J
The kinetic energy of the wheel is approximately 24,568.15 Joules.
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what is a limitation of the electron cloud model theory that a law about electrons would not have? the theory describes electrons in experiments, but
The theory describes electrons in experiments, but the electron cloud model theory has limitations in its ability to provide precise information about the exact position and trajectory of electrons in an atom.
This is due to the inherent probabilistic nature of electron behavior, as described by quantum mechanics. The electron cloud model represents the probability distribution of finding electrons in certain regions around the nucleus but does not provide specific information about the precise paths or orbits they follow.
On the other hand, a law about electrons would typically focus on the observed behavior or relationships of electrons rather than attempting to describe their precise positions or trajectories.
Laws, such as the law of conservation of charge or the law of electric current, provide general principles or rules that govern electron behavior within a given context. They are empirical observations derived from experimental evidence rather than detailed theoretical models.
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The kinetic energy KE of an object of mass m moving with velocity v is defined as KE = = 2 mv². If a force f(x) acts on the object, moving it along the x-axis from x₁ to x2, the Work-Energy Theorem states that the net work done is equal to the change in kinetic energy: mv₂2-1mv2, where v₁ is the velocity at x and v₂ is the velocity at x2.
Suppose that when launching an 800-kg roller coaster car an electromagnetic propulsion system exerts a force of 5.7x2+ 1.5x newtons on the car at a distance x meters along the track. Use the Work-Energy Theorem to find the speed of the car when it has traveled 50 meters. (Round your answer to two decimal places.)
X m/s
To find the speed of the car when it has traveled 50 meters, we need to use the Work-Energy Theorem and equate the net work done to the change in kinetic energy.
The net work done (W_net) is given by integrating the force (f(x)) over the displacement (x₁ to x₂):
W_net = ∫[x₁ to x₂] f(x) dxIn this case, the force acting on the car is given by f(x) = 5.7x² + 1.5x.
The change in kinetic energy (∆KE) is given by:
∆KE = KE₂ - KE₁Since the car starts from rest (v₁ = 0), the initial kinetic energy (KE₁) is 0.
Using the formula for kinetic energy KE = 1/2 mv², we can express the final kinetic energy (KE₂) in terms of the car's mass (m) and its final velocity (v₂):
KE₂ = 1/2 mv₂²According to the Work-Energy Theorem, W_net = ∆KE. Therefore, we can write:
∫[x₁ to x₂] f(x) dx = 1/2 mv₂²Substituting the given force expression into the integral:
∫[x₁ to x₂] (5.7x² + 1.5x) dx = 1/2 mv₂²Now we can solve this equation to find the velocity v₂. However, the problem statement does not provide the values of x₁ and x₂, which are necessary to evaluate the integral and determine the velocity. Without those values, we cannot proceed with the calculation.
If you have the values of x₁ and x₂, please provide them, and I'll be happy to assist you further in finding the speed of the car when it has traveled 50 meters.
About Kinetic energyKinetic energy or energy of motion is the energy possessed by an object due to its motion. The kinetic energy of an object is defined as the work required to move an object with a certain mass from rest to a certain speed.
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1. Which of the following has the most potential energy?
A. a ball buried under the ground
B. a ball on the ground
C. a ball at the top of a mountain
D. a ball in a tree
Answer:
C. a ball at the top of a mountain
Explanation:
It has more potential energy because it is the highest from the ground. The higher it is, the more potential energy it has.
n Olympic diver is on a diving platform 3.60 m above the water. To start her dive, she runs off of the platform with a speed of 1.3 m/s in the horizontal direction. What is the diver's speed, in m/s, just before she enters the water
Answer:
8.5m/s
Explanation:
Using the equation of motion
v² = u² + 2gH
v is the final speed of the diver
u is the initial speed of the diver
g is the acceleration due to gravity
H is the height of the object
Given the following
V = 1.3m/s
H = 3.60m
g = 9.8m/s²
Required
Initial speed of the diver u
Substitute the given values into the formula:
v² = u² -2gH
1.3² = u² - 2(9.8)(3.60)
1.69 = u²-70.56
u² = 1.69+70.56
u² = 72.25
u = √72.25
u = 8.5m/s
Hence the diver's speed, in m/s, just before she enters the water is 8.5m/s
the time period of planet x around sun is 8 times that of y. the distance of x from the sun is how many times greater than that of y?
The distance of planet X from the sun is 8 times greater than that of planet Y.
The time period of a planet around the sun is directly proportional to the distance of the planet from the sun. The relationship between the time period and distance of a planet around the sun is given by the formula T^2 = k*r^3, where T is the time period, r is the distance of the planet from the sun and k is a constant.
Given that the time period of planet X around the sun is 8 times that of planet Y.
T_x = 8 * T_y
We can square the equation, we have:
T_x^2 = 8^2 * T_y^2
We can divide the above equation by the constant k, we have:
r_x^3 = 8^2 * r_y^3
We can take the cube root of both sides, we have:
r_x = (8^2 * r_y^3)^(1/3)
r_x = 8 * r_y
So the distance of planet X from the sun is 8 times greater than that of planet Y.
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How cold is it in texas rn?
Answer:
cold
Explanation:
!!! If each compound undergoes electrophilic aromatic substitution, where should the substituent be added? Phenol?
Benzaldehyde?
Benzoic Acid?
Bromobenzene?
Nitrobenzene?
Toluene?
The substituent should be added at different locations on the compounds in electrophilic aromatic substitution are: Phenol: ortho or para position to the -OH group, Benzaldehyde: ortho or para position to the -CHO group.
What is Electrophilic aromatic substitution?For each of the compounds that undergo electrophilic aromatic substitution, the substituent should be added to the ring. The location of the substituent, however, differs depending on the specific compound. The location is dependent on the presence of any functional groups already present in the ring.
Phenol: The substituent is added to the ortho or para position to the -OH group.
Benzaldehyde: The substituent is added to the ortho or para position to the -CHO group.
Benzoic acid: The substituent is added to the ortho or para position to the -COOH group.
Bromobenzene: The substituent is added to the ortho or para position to the bromine atom.
Nitrobenzene: The substituent is added to the meta position to the nitro group.
Toluene: The substituent is added to the ortho or para position to the methyl group.
Therefore, when each compound undergoes electrophilic aromatic substitution, the substituent should be added to the ring. The specific location is determined by the presence of any functional groups already present in the ring.
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find the following, given that p(a) = 0.56, p(b) = 0.63, p(a union b) = 0.41 find p(a^c|b^c) (a) 0.4054(b) 0.1500(c) 0.5946(d) 0.7321(e) 0.2381
The result of the equations p(a) = 0.56, p(b) = 0.63, and p(a union b) = 0.41 is (a) 0.4054.
Using the formula: we can determine p(ac|bc).
P(A|C|B) is equal to P(A|C intersection P(B))
p(ac) = 1 - p(a) = 1 - 0.56 = 0.44 and p(bc) = 1 - p(b) = 1 - 0.63 = 0.37 are both known values.
The following formula may be used to determine p(ac intersection bc):
P((a union b) = p(a c intersection b)
We are aware of:
P(a intersection b) = P(a) + P(b) - P(a union b)
p(a intersection b) = 0.78 - 0.41 = 0.37, where p(a intersection b) = 0.41 = 0.56 + 0.63
p((a union b)c) is therefore 1 - p(a union b) = 1 - 0.41 = 0.59.
We can now enter these numbers into the formula:
P(A|C|B) is equal to P(A|C intersection P(B))
If p(ac|bc) = 0.37 / 0.37, then ac|bc = 1.
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64. an express train passes through a station. it enters with an initial velocity of 22.0 m/s and accelerates opposite to the motion at a rate of 0.150m/s2 as it goes through. the station is 210.0 m long. (a) how fast is it going when the nose leaves the station? (b) how long is the nose of the train in the station? (c) if the train is 130 m long, what is the velocity of the end of the train as it leaves? (d) when does the end of the train leave the station?
Therefore, the final velocity of the train when the nose leaves the station is 27.4 m/s. Therefore, the nose of the train is in the station for 4.32 seconds. Therefore, the velocity of the end of the train as it leaves the station is 20.5 m/s. Therefore, the end of the train leaves the station after 15.74 seconds.
What is velocity?The primary indication of an object's position and speed is its velocity. It is defined as the distance traveled by an item in one unit of time. The displacement of an item in unit time is defined as velocity. The directional speed of an item in motion as an indicator of its rate of change in position as perceived from a certain frame of reference and measured by a specific standard of time (e.g., 60 km/h northbound) is known as velocity. Simply put, velocity is the rate at which something travels in a certain direction. For example, the speed of a car driving north on a highway or the speed of a rocket after launch.
Here,
(a) To find the final velocity of the train when the nose leaves the station, we can use the equation:
v² = u² + 2as
where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled. We can split the distance traveled into two parts: the distance covered while accelerating, and the length of the station.
For the distance covered while accelerating, the initial velocity is 22.0 m/s, the acceleration is -0.150 m/s² (opposite to the motion of the train), and the distance is the length of the station minus the initial distance covered by the train:
s₁ = (210.0 m - 0 m) - (130.0 m + 22.0 m/s × t) = 80.0 m - 22.0 m/s × t
where t is the time taken to cover the distance.
For the distance covered in the station, the initial velocity is the final velocity from the acceleration phase, and the acceleration is 0 (since the train is no longer accelerating):
s₂= 130.0 m
The total distance traveled is the sum of s₁ and s₂:
s = s₁+ s₂ = 80.0 m - 22.0 m/s × t + 130.0 m
Substituting the given values into the first equation, we get:
v² = (22.0 m/s)² + 2 × (-0.150 m/s²) × [80.0 m - 22.0 m/s × t + 130.0 m]
Simplifying, we get:
v² = 22.0² - 0.3t + 2.0 × 130.0
v² = 484 - 0.3t + 260
v² = 744 - 0.3t
Taking the square root of both sides, we get:
v = √(744 - 0.3t)
At the moment when the nose of the train leaves the station, the distance traveled is 210.0 m. Therefore, we can set s = 210.0 m and solve for t:
210.0 = 80.0 m - 22.0 m/s × t + 130.0 m
Simplifying, we get:
t = 4.32 s
Substituting this value into the expression for v, we get:
v = √(744 - 0.3 × 4.32)
v = 27.4 m/s
Therefore, the final velocity of the train when the nose leaves the station is 27.4 m/s.
(b) The time that the nose of the train spends in the station is the time it takes to travel the length of the station at a constant speed, which is the time between the end of the acceleration phase and the moment when the nose leaves the station. From part (a), we know that the acceleration phase lasts for:
t₁= (v - u) / a = (27.4 m/s - 22.0 m/s) / (-0.150 m/s²) = 36.67 s
Therefore, the total time it takes for the nose to leave the station is:
t₂ = t₁ + 4.32 s = 41.0 s
The time that the nose of the train spends in the station is:
t_station = t₂- t₁ = 4.32 s
Therefore, the nose of the train is in the station for 4.32 seconds.
(c) The velocity of the end of the train as it leaves the station can be found using the same kinematic equation:
v² = u²+ 2as
where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance.
In this case, the initial velocity is 22.0 m/s, the acceleration is -0.150 m/s², and the distance is the length of the station:
s = 210.0 m
Substituting these values, we get:
v² = (22.0 m/s)² + 2(-0.150 m/s²)(210.0 m)
v² = 484.0 m²/s² - 63.0 m²/s²
v² = 421.0 m²/s²
Taking the square root of both sides, we get:
v = 20.5 m/s
Therefore, the velocity of the end of the train as it leaves the station is 20.5 m/s.
(d) To find the time when the end of the train leaves the station, we can use the same kinematic equation used in part (b):
s = ut + (1/2)at²
where s is the displacement of the end of the train, which is 210.0 m + 130.0 m = 340.0 m, u is the initial velocity of the train, and a is the acceleration of the train.
Substituting the given values, we get:
340.0 m = (22.0 m/s)t + (1/2)(-0.150 m/s²)t²
Simplifying and solving for t, we get:
t = 15.74 s
Therefore, the end of the train leaves the station after 15.74 seconds.
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As a baseball is being caught, its speed goes from 30.0 m/s to 0.0 m/s in about 0.0050 s. The mass of the baseball is 0.145 kg.
What is the baseball's acceleration?
What are the magnitude and the direction of the force acting on it?
What are the magnitude and direction of the force acting on the player who caught it?
Answer: Force = 870 N
Explanation:
acceleration = a = (final velocity - initial velocity) / time elapsed
a = (0-30)/.005 = -6000 m/s2 (negative sign means the ball is slowing down)
Force = F = mass x acceleration = ma
F = (0.145 kg)(6000 m/s2) = 870 N away from the player throwing the ball
The magnitude of the force on the player catching the ball is equal, 870N. The mitt acts on the ball with an equal and opposite force (Newton's 3rd Law of Motion)
Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?
The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:
\($$F=k\frac{q_1q_2}{r^2}$$\)
where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:
\($$E=\frac{kq}{r^2}$$\) where k is the Coulomb constant.
So, let's calculate the electric field due to each charge separately and then add them up:
For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)
For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:
\($$E_2=\frac{kq_2}{r^2}\)
\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)
The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.
To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)
Substituting the values of E1 and E2:
\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)
net comes out to be -1.5×10⁴ N/C.
Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
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Who was the first man on planet Jupiter
If the spring constant is 30 N/m and x
has a value of 0.5 m as shown in the
attached diagram, what is m equal to?
Hooke's Law gives the relationship between applied forces m·g, 2·m·g and extensions of an elastic material x, 2·x based on its elasticity.
The value of the mass, m is approximately 1.53 kg.Reason:
Given parameter;
Spring constant = 30 N/m
Value of the extension, x = 0.5 m
Extension of the spring by mass, m = x
Extension of the spring by mass, 2·m = 2·x
Required:
To find the value of mass m.
Solution:
The measures of weight and extension from the diagram are;
\(\begin{array}{|l|cl|}\mathbf{Extension}&&\mathbf{Weight \ (Force), \, F}\\0&&0\\x&&m \cdot g\\2 \cdot x&&2 \cdot m \cdot g\end{array}\right]\)
The rate of change of the extension with the applied force are;
\(Between \ second \ and \ frirst\ row, \ \dfrac{\Delta F}{\Delta x} =\dfrac{m \cdot g}{x}\)
\(Between \ third \ row \ and \ second \ row, \ \dfrac{\Delta F}{\Delta x} = \dfrac{2 \cdot m \cdot g - m \cdot g}{2 \cdot x - x} = \dfrac{m \cdot g}{x}\)
Therefore;
The rate of change of the extension with the applied force, \(\dfrac{\Delta F}{\Delta x}\), is a
constant equal to m·g, and the spring obeys Hooke's law.
According to Hooke's law, force applied to the spring, F = -K·xWhere;
F = The spring force
Therefore;
The force applied by the weight of the mass, m·g = -F∴ m·g = -(-k·x) = 30 N/m × 0.5 m
Where;
g = Acceleration due to gravity = 9.81 m/s²
\(m = \dfrac{30 \, N/m \times 0.5 \, m }{9.81 \, m/s^2} \approx 1.53 \, kg\)The mass, m ≈ 1.53 kg
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a child of mass 26 kg sits on a wooden horse on a carousel. the wooden horse is 4.3 m from the center of the carousel, which rotates at a constant rate and completes one revolution every 6.1 seconds.What are the magnitude and direction of d|p|/dt p^, the parallel component of dp/dt for the child?
The angular velocity of the carousel is constant, and there is no change in the direction of the child's momentum. Therefore, the magnitude and direction of d|p|/dt p^ is zero.
What is the conservation of angular momentum?Conservation of angular momentum is a fundamental principle in physics that states that the total angular momentum of a system remains constant if there are no external torques acting on the system. Angular momentum is a measure of the rotational motion of an object or a system of objects. It is defined as the product of the moment of inertia of the object or system and its angular velocity.
Mathematically, the conservation of angular momentum can be expressed as:
L = Iω
Where L = the angular momentum,
I = the moment of inertia,
ω= the angular velocity.
If the net external torque acting on a system is zero, then the angular momentum of the system is conserved. This means that the angular momentum of the system will remain constant over time.
Here in the question,
We can use the conservation of angular momentum to solve this problem. The angular momentum of the system remains constant as there are no external torques acting on it.
The moment of inertia of the child and the horse is negligible compared to the moment of inertia of the carousel. Therefore, we can assume that the moment of inertia of the system is that of a point mass located at the center of the carousel:
I = MR²
Where M =the mass of the carousel
R =the distance from the center of the carousel to the child.
The angular velocity of the system is given by:
ω = 2π/T
Where T = the period of rotation of the carousel.
Substituting these values, we get:
L = MR²(2π/T)
As the angular momentum is conserved, we can differentiate it with respect to time to get:
dL/dt = 0
Differentiating the equation for angular momentum, we get:
dL/dt = M(R²)dω/dt + 2MRdR/dt ω
The first term on the right-hand side represents the change in the angular velocity of the carousel, and the second term represents the change in the distance of the child from the center of the carousel. As the angular momentum is conserved, this expression must be equal to zero.
Solving for dω/dt, we get:
dω/dt = -(2RdR/dt ω)/(R²)
Substituting the given values, we get:
R = 4.3 m
M = mass of the carousel = unknown
T = 6.1 s
m = mass of the child = 26 kg
The angular velocity is:
ω = 2π/T = 2π/6.1 s ≈ 1.03 rad/s
Differentiating the equation for R with respect to time, we get:
dR/dt = 0 (as R is constant)
Substituting these values, we get:
0 = M(4.3²)dω/dt + 2M(4.3)×0 ω
Therefore, the angular velocity of the carousel is constant, and there is no change in the direction of the child's momentum. Therefore, the magnitude and direction of d|p|/dt p^ is zero.
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suppose you and your sister travel in space in such a way that you notice a slowing of time for your sister. your sister will notice that your time runs
False This phenomenon is known as time dilation and is a consequence of the theory of relativity, specifically the theory of special relativity.
According to special relativity, time dilation occurs when an observer is in relative motion with respect to another observer. When two observers move at different velocities relative to each other, they will experience time passing at different rates.In the scenario you described, if you and your sister are traveling in space at different velocities, you would observe that time appears to be running slower for your sister compared to your own perception of time. This means that your sister's clock would appear to be ticking slower from your perspective.
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Hey can anyone pls pls pls answer dis i rlly need it i only need the conclusion!!
Explanation:
since oil needs more boiling time and a higher boiling temperature the oil would have to be in the pot longer than the water if it needs to be boiled longer that is why the blue line for oil temp. is significantly higher than that of the water temp.
Although the Radical Republicans had the votes necessary to impeach president Andrew Johnson in 1868, they voted narrowly not to do so. Why
The Radical Republicans narrowly voted not to impeach President Andrew Johnson in 1868 due to a combination of political considerations, strategic calculations, and concerns about the potential negative consequences of impeachment.
Political Considerations: While the Radical Republicans strongly disagreed with President Johnson's lenient approach towards Reconstruction and his resistance to their policies, they were aware of the potential backlash and political consequences that could arise from impeaching a sitting president. They had to consider the broader political climate and public sentiment at the time.
Strategic Calculations: The Radical Republicans likely assessed their chances of successfully convicting Johnson in a Senate trial. They needed a two-thirds majority vote in the Senate to remove him from office. It is possible that they believed they did not have enough support to secure a conviction, and impeachment without removal could have weakened their position.
Potential Negative Consequences: Impeaching and removing a president was an unprecedented action in American history. The Radical Republicans may have been concerned about the potential destabilizing effects on the nation and the risk of setting a dangerous precedent for future impeachments. They may have feared that removing Johnson from office could create further political divisions and hinder the progress of Reconstruction.
The Radical Republicans narrowly voted not to impeach President Andrew Johnson in 1868 due to a combination of political considerations, strategic calculations, and concerns about the potential negative consequences of impeachment. While they strongly opposed Johnson's policies, they weighed the political climate, the chances of conviction, and the potential destabilizing effects of removing a president from office. Ultimately, they decided against impeachment, choosing to pursue other avenues to advance their Reconstruction agenda.
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A rock is thrown horizontally from a height of 6.00 m. what
is the time required for the rock to reach the ground
The time required for the rock to reach the ground is 1.11 second.
What is acceleration?
Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Initial height of the rock: h = 6.00 m.
Acceleration due to gravity: g = 9.8 m/s²
Let, the time required for the rock to reach the ground is = t.
Then:
h = 1/2 × gt²
t = √(2h/g)
= √ {(2 × 6.00)/9.8} second.
= 1.11 second.
Hence, the time required for the rock to reach the ground is 1.11 second.
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A wave has a speed of 20 m/s and a wavelength of 5 meters. if the same wave was created in the same medium, with half the original frequency, how would the wavelength change?
Answer:
The wavelength of the wave would increase to 10 meters.
Explanation:
We can use the formula:
velocity = frequency × wavelength
to relate the velocity, frequency, and wavelength of a wave.
Given that the wave has a speed of 20 m/s and a wavelength of 5 meters, we can solve for its frequency as follows:
frequency = velocity ÷ wavelength = 20 m/s ÷ 5 meters = 4 Hz
Now, if the same wave is created in the same medium, but with half the original frequency, its new frequency will be:
new frequency = 4 Hz ÷ 2 = 2 Hz
To find the new wavelength of the wave, we can rearrange the formula above to solve for wavelength:
wavelength = velocity ÷ frequency
Using the new frequency of 2 Hz, we get:
new wavelength = 20 m/s ÷ 2 Hz = 10 meters
Therefore, if the same wave was created in the same medium, with half the original frequency, the wavelength of the wave would increase to 10 meters.
What would be the wavelength of an electromagnetic wave having a frequency equal to the clock speed of a 2.7 GHz personal computer? In what part of the electromagnetic spectrum would such a wave lie?
Answer:
the wavelength of the electromagnetic wave with a frequency is approximately 0.111 meters or 11.1 centimeters.
the electromagnetic wave falls within the radio wave.
Explanation:
Equation:
wavelength = speed of light / frequency
Given:
Frequency = 2.7 GHz = 2.7 × 10^9 Hz
so...
wavelength = (3.00 × 10^8 m/s) / (2.7 × 10^9 Hz)
then the answer would be...
wavelength ≈ 0.111 meters or 11.1 centimeters
now regarding the second question...in the given scenario, the wavelength of 11.1 centimeters is relatively long, indicating a lower frequency. Therefore, the electromagnetic wave in question falls within the radio wave part of the electromagnetic spectrum.
A jetliner, traveling northward, is landing with a speed of 69 m/s. Once the jet touches down, it has 750 m of runway in which to reduce its speed to 5.1 m/s. Compute the average acceleration (magnitude and direction) of the plane during landing (take the positive direction to be northward).
The average acceleration of the jetliner during landing can be calculated using the formula:
average acceleration = (final velocity - initial velocity) / time
Initial velocity (u) = 69 m/s (northward)
Final velocity (v) = 5.1 m/s (northward)
Distance (d) = 750 m
First, we need to find the time taken (t) using the formula:
t = d / average speed
Average speed = (initial velocity + final velocity) / 2
Average speed = (69 m/s + 5.1 m/s) / 2 = 37.05 m/s
t = 750 m / 37.05 m/s = 20.26 s
Now we can calculate the average acceleration:
average acceleration = (v - u) / t
= (5.1 m/s - 69 m/s) / 20.26 s
≈ -3.469 m/s² (southward)
The average acceleration of the jetliner during landing is approximately -3.469 m/s² in the southward direction. This is calculated using the initial velocity of 69 m/s (northward), final velocity of 5.1 m/s (northward), and a distance of 750 m.
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a boy whose mass is 40kg runs up a flight of 30 step each 150 mm in 60 second find the averse power develop expansion explain the anomalous of two of water
The average power developed by the boy during the climb is approximately 29.4 W.
What is power?In physics, the amount of energy transferred or converted per unit time is called power.
total height = number of steps x height of each step
total height = 30 x 0.15 m = 4.5 m
Given, time = 60 s
As power = work done / time
work done = force x distance
force = mass x gravity
mass is boy's mass (40 kg) and gravity is acceleration due to gravity (9.81 m/s²).
force = 40 kg x 9.81 m/s² = 392.4 N
The distance that the boy moves is equal to the total height that he has climbed: distance = total height = 4.5 m
work done = force x distance
work done = 392.4 N x 4.5 m = 1765.8 J
power = work done / time
power = 1765.8 J / 60 s
power ≈ 29.4 W
Therefore, the average power developed by the boy during the climb is approximately 29.4 W.
As for the anomalous behavior of water, water has a higher boiling point and melting point as compared to other substances with similar molecular weight. This is due to the strong hydrogen bonding between water molecules, which requires more energy to break the bonds and change the state of water from solid to liquid to gas.
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The speed of light traveling through an unknown material is 1.98×108 m/s. Given that the speed of light in a vacuum is 3.00×108 m/s, what is the dielectric constant of the unknown material?
The dielectric constant of the unknown material is 2.3.
What is dielectric constant?Dielectric constant is referred as a relative permittivity or amount of charge required to produce one unit of electric flux in a given medium.
Given the speed of light in vacuum c =3 x 10⁸ m/s and the speed of light through an unknown material v = 1.98 x 10⁸ m/s.
The dielectric constant is related to the velocity by the following relation,
v = c/√K
Rearranging for dielectric constant, we get
K = (c/v)²
Substitute the value into the expression ,we get
K =(3 x 10⁸ / 1.98 x 10⁸)²
K = 2.3
Thus, the dielectric constant of the unknown material is 2.3.
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Which type of electromagnetic radiation is useful in communications technology?
A. X-rays
B. visible light
C. radio waves
D. ultraviolet radiation
disregarding air drag, how fast must you toss a ball straight up in order for it to take 2 seconds to return to the level from which you tossed it?
The ball should be tossed with speed 10 m/s in order for it to take 2 second to return to the level from which it was tossed.
The Time of flight of projectile motion is defined as the total time taken during ascent and fall to the ground.
Here, time of flight is given 2 seconds. So, Time of ascent is 1 second. Time of ascent is time taken to reach the highest height.
We have to apply the formula
v= u +at
At the maximum height, v =0 m/s.
0 = u - 10×1
So, u = 10 m/s
So, our answer depends on the value of g. If we take the value of g as 9.8, then speed required will be 9.8 m/s
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