which of the following are statistics outputted by the mos? which of the following are statistics outputted by the mos? dew point maximum temperature probability of precipitation all of these answers

Answer:

See explanation.

Explanation:

Since no figure was given I solved a problem that was similar to the one you described that I worked in my mechanics of materials class. The method should be very similar for your figure. See attached image for my work.

If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

We need to perform a two step process to obtain the maximum shear stress on the shaft. For the solid shaft,

P=2×pi×N×T/60 or T=60×p/2×pi×N

Where P=power transmitted by the shaft=50×10³W

N=rotation speed of the shaft in rpm=730rpm

Pi=3.142

T is the twisting moment

By substituting the values for pi, N and P, we get

T=654Nm or 654×10³Nmm

Also, T=pi×rho×d³/16 or rho=16×T/pi×d³

Where rho=maximum shear stress

T = twisting moment=654×10³Nmm

d= diameter of shaft= 40mm

By substituting T, pi and d

Rho=52Mpa

b. For a hollow shaft, the value for rho is unknown

T=pi×rho(do⁴-di⁴/do)/16

Rho=T×16×do/pi×(do⁴-di⁴)

Where

T= twisting moment=654×10³Nmm gotten above

do=outside shaft diawter=40mm

di= inside shaft diameter =30mm

Pi=3.142

Substituting values for pi, do, di and T.

Rho=76Mpa

Therefore, If it is subjected to the couple determine the maximum shear stress in regions AC and CB of the shaft. G st = 75 GPa. Than the answer will be 52Mpa.

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(a) The temperature of the exiting mixture is 300.8 8C.

(b) The rate of entropy production is 0.767 kW/K.

(c) The rate of exergy destruction is 177.5 kW.

Air at 50 8C, 1 atm and a volumetric flow rate of 60 m3/min mixes with helium entering as a separate stream at 120 8C, 1 atm and a volumetric flow rate of 25 m3/min. A single mixed stream exits at 1 atm. Ignoring kinetic and potential energy effects, determine for the control volume.

(a) the temperature of the exiting mixture, in 8C. (b) the rate of entropy production, in kW/K. (c) the rate of exergy destruction, in kW, for T0 5 295 K.The given problem can be solved by the application of the energy and mass balance equations as well as the second law of thermodynamics.

The rate of mass flow (m) of air (ṁ_air) and helium (ṁ_he) can be calculated using the given volumetric flow rate and the density of air and helium.The mass flow rate of air (mṁ_air) = Volumetric flow rate of air (V_air) × Density of air (ρ_air) = 60 m3/min × 1.2 kg/m3= 72 kg/min

The mass flow rate of helium (mṁ_He) = Volumetric flow rate of helium (V_He) × Density of helium (ρ_He) = 25 m3/min × 0.166 kg/m3 = 4.15 kg/min.The mass flow rate of the mixture is the sum of the mass flow rates of the air and helium.

Therefore, the mass flow rate of the mixture (mṁ_mixture) = mṁ_air + mṁ_He = 72 + 4.15 = 76.15 kg/min(a) Calculation of the temperature of the exiting mixture:By applying the energy balance equation for steady-state processes, the energy input equals the energy output. That is,Q_in = Q_outor, mṁ_air Cpa T1 + mṁ_He Cp_He T2 = mṁ_mixture Cp T3

where, Cpa and Cp_He are the specific heat capacities of air and helium at constant pressure respectively.Cp is the specific heat capacity of the mixture at constant pressure.T1 and T2 are the temperatures of air and helium before mixing.T3 is the temperature of the mixture after mixing.

Substituting the given values into the above equation and solving for T3, we get;72 × 1.005 × (508 − T3) + 4.15 × 5.193 × (1208 − T3) = 76.15 × 1.128 × (T3 − 298)T3 = 573.8 K = 300.8 8C

Therefore, the temperature of the exiting mixture is 300.8 8C.

(b) Calculation of the rate of entropy production:The rate of entropy production can be calculated using the second law of thermodynamics. The entropy generation (S_gen) is given by the equation:S_gen = ṁ_mixture × s_mixture − ṁ_air × s_air − ṁ_He × s_He

where, s_air and s_He are the specific entropies of air and helium respectively.s_mixture is the specific entropy of the mixture.Taking the reference temperature (T0) to be 295 K, the rate of entropy production can be calculated as:

S_gen = ṁ_mixture × [s_mixture − s_0(T0)] − ṁ_air × [s_air − s_0(T0)] − ṁ_He × [s_He − s_0(T0)]where, s_0(T0) is the entropy at reference temperature (T0).

s_mixture = 1.128 × ln [(0.21 × P_1)/(0.21 × P_1 + 0.79 × P_2)] + 0.881 × ln [(0.79 × P_2)/(0.21 × P_1 + 0.79 × P_2)] = 1.128 × ln [(0.21 × 1)/(0.21 × 1 + 0.79 × 1)] + 0.881 × ln [(0.79 × 1)/(0.21 × 1 + 0.79 × 1)] = 0.375 kJ/kg.K

where, P_1 and P_2 are the partial pressures of air and helium respectively at the exit temperature.Taking the specific entropies of air and helium from steam tables, we get;

s_air = 72 × 1.005 × [ln T3/T0] − 72 × R_air × [ln P1/P0] = 72 × 1.005 × [ln(573.8/295)] − 72 × 0.287 × [ln 1/1] = 349.1 J/kg.ks_He = 4.15 × 5.193 × [ln T3/T0] − 4.15 × R_He × [ln P2/P0] = 4.15 × 5.193 × [ln(573.8/295)] − 4.15 × 2.076 × [ln 1/1] = 602.1 J/kg.k

Where, R_air and R_He are the specific gas constants of air and helium respectively.The rate of entropy production (S_gen) = 76.15 × [0.375 − 0.365] − 72 × [0.349 − 0.300] − 4.15 × [0.602 − 0.176] = 0.767 kW/K

Therefore, the rate of entropy production is 0.767 kW/K.

(c) Calculation of the rate of energy destruction:

The rate of energy destruction is calculated using the equation:Energy destruction rate = S_gen × (T − T0)where, T is the temperature at which the entropy is generated.Substituting the given values, the rate of energy destruction is;Energy destruction rate = 0.767 kW/K × (573.8 K − 295 K) = 177.5 kW

Therefore, the rate of energy destruction is 177.5 kW.

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If the electrical resistance of a household appliance becomes four times larger than the original value and the appliance follows Ohm's law, the current it uses will be one-fourth of the original current.

Ohm's law states that I = V/R, where I is the current, V is the voltage, and R is the resistance. If the resistance becomes four times larger (R_new = 4R_original), the new current (I_new) can be calculated as:
I_new = V/R_new = V/(4R_original)
Since I_original = V/R_original, we can rewrite the equation as:
I_new = (1/4) * I_original
This shows that the current used by the appliance will be one-fourth of its original value when the resistance increases four times.

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Answer:

La Comunión o la Cena del Señor es el partir y comer el pan para simbolizar el cuerpo de Cristo partido por nosotros y beber vino para recordar la sangre que derramó por nuestros pecados.

Explanation:

Answer:

The Material engineers trying to discover when they study different materials is described below in complete detail.

Explanation:

Material engineers analyze various elements to discover the purpose and explanation of its existence, the chemical characteristics, how long it has stood there, and how it influences human life. The material engineer is an engineering exercise that concentrates to enhance human activity by investigating the environment and the diverse elements or elements it holds.

Answer:

STEP1 Cut to Rough Length

STEP2 Cut to Rough Width

STEP 3 Face-Jointing

HOPE THAT HELPSSS!!!

a) The final composition of the pressurizer will be 50% water and 50% steam by volume.
b) The final system pressure will be 2040 psia.

Pressurizer is a tool used to measure and adjust the pressure of liquids, gases and vapors. It is used to maintain the pressure within a system, to regulate the flow of fluids and to monitor the health of the system. It is a crucial instrument in many industrial processes and helps to ensure the safety of personnel and equipment. It is easy to use, cost-effective and reliable, and helps keep operations running smoothly.

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The answer to this question is D. The energy used is the same for both segments, the power while running is greater.

To explain this answer, it's important to understand the definitions of energy and power. Energy is the ability to do work, while power is the rate at which work is done.

During the walking segment of the journey, the person is expending energy to move their body 1 km. This requires a certain amount of work to be done, which translates to a certain amount of energy being used. However, because the person is walking at a slower pace, the rate at which work is being done (power) is lower.

During the running segment of the journey, the person is again expending energy to move their body the same 1 km distance, but they are doing so at a faster pace. This means that the rate at which work is being done (power) is higher.

So while the energy used is the same for both segments (1 km worth of energy), the power during the running segment is greater. This is because the person is doing the same amount of work in a shorter amount of time, which requires a higher rate of power.

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Answer:

  A battery

Explanation:

There are several words used to describe such an assembly:

  pile, battery, electrolytic cell

Answer:

wind vane if it can be used to show wind speed and the other is a

Explanation:

please mark 5 star if im right and brainly when ya can

Answer:

Explanation:

Static electricity is the result of an imbalance between negative and positive charges in an object. These charges can build up on the surface of an object until they find a way to be released or discharged.

The property is that polyurethanes have a good tear resistance as well as tensile strength.

Polyurethane is an umbrella word for a group of polymers formed via the condensation of polyisocyanates and polyalcohols. Despite its xenobiotic origins, polyurethane has been discovered to be biodegradable by naturally occurring microbes.

Polyurethanes are synthesized by reacting a polyol (an alcohol having more than two reactive hydroxyl groups per molecule) with a diisocyanate or a polymeric isocyanate in the presence of appropriate catalysts and additives

To manage cell fate and tissue healing, biodegradable polyurethane platforms have been used. Cell bonding, spreading, multiplication, and separation are all influenced by framework features such as compound, mechanical, and primary. These are not fully fixed as the science of biodegradable polyurethanes, platform manufacturing technologies, and surface change approaches.

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A real-world application for a circularity tolerance is Sealing surface(i.e., engines, pumps, valves). So option B is the correct answer.

A sealing surface refers to the area or surface where two components come into contact to create a seal. It is specifically designed and engineered to prevent the passage of fluids, gases, or other substances between two adjoining components.

Sealing surface (i.e., engines, pumps, valves) is a real-world application for circularity tolerance. Circularity tolerance ensures that the sealing surface is round and smooth, allowing for proper sealing and preventing leaks.

This is critical in applications such as engines, pumps, and valves where fluid or gas must be contained within a system. Without proper circularity tolerance, the sealing surface may be uneven, leading to leakage and potential system failure.

So the correct answer is option B.

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918.63517 is the answer.

Answer:

Reduce manufacturing costs.

Explanation:

Hope This Helps

Have A Great Day

Answer:

The wind force on the screen is approximately 5,341.5936 \(lb_f\)

Explanation:

The speed of the wind, v = 36 mph

The width of the outdoor movie, w = 70 ft. wide

The height of the outdoor movie, h = 20 ft. tall

The drag coefficient, Cd = 1.15

We have;

\(C_d = \dfrac{F}{\dfrac{\rho \cdot v^2 \cdot A}{2} }\)

From which we have;

The wind force, F = 0.00256·\(C_d\)·v²·A

Where;

A = The cross sectional area of the rectangular outdoor movie screen, A = w × h

∴ A = 70 ft. × 20 ft. = 1,400 ft.²

The wind force, F = 0.00256 × 1.15 × (36 mph)² × 1,400 ft.² = 5,341.5936 \(lb_f\)

The wind force on the screen, F = 5,341.5936 \(lb_f\).

The wind force on the outdoor movie screen is;

F = 23437.26 N

We are given;

Wind speed; v = 36 mph = 16.0934 m/s

Width of screen; w = 70 ft = 21.336 m

Height of screen; h = 20 ft = 6.096 m

Drag coefficient; Cd = 1.15

Now formula for the drag force is;

F = ½•C_d•ρ•A•v²

Where;

F is drag force

C_d is drag coefficient

ρ is density of object

v is speed of object

A is area

Let us use density as 1.21 kg/m³

Area; A = wh = (21.336 × 6.096)

Thus;

F = ½ × 1.15 × 1.21 × (21.336 × 6.096) × 16.0934²

F = 23437.26 N

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Answer:

Tires or wheels? I think this is the answer. ^_^

Explanation:

Answer:

871.8008 KJ/kg

2573.42085 KJ/kg

0.3743

Explanation:

Solution:-

- We are to analyze an ideal Rankine cycle, where the condenser and boiler operating temperatures are defined.

- We start of by evaluating the properties of water at each state before and after the process.

State 1: Condenser Exit / Pump Inlet

           T1 = 40°C   ---> P1,sat = 7.3851 KPa , v1 = vf = 0.001008 m^3/kg

            sat liquid         h1 = hf = 167.53 KJ/kg , s1 = sf = 0.5724 KJ/kg.K

            P1 = condenser pressure

State 2: Pump Exit / Boiler Inlet

           P2 = P3 = Psat,300°C = 8587.9 KPa

Process 1: " Isentropic Compression - constant volume "

The work done by pump in the compression process is:

          wp = v1* ( P2 - P1 )

          wp = ( 0.001008 ) * ( 8587.9 - 7.3851 )

          wp = 8.64915 KJ /kg

Determine the enthalpy at " State 2 " by energy balance on pump ( control  Volume) :

          h2 = h1 + wp

          h2 = 167.53 + 8.64915

          h2 = 176.17915 KJ/kg

State 3: Boiler Exit / Turbine Inlet

          T1 = 300°C   ---> P3,sat = 8587.9 KPa

           sat vapor         h3 = hg =  2749.6 KJ/kg , s3 = sg =  5.7059 KJ/kg.K

           P3 = Boiler pressure

Process 2: " Heat Addition - constant pressure "

The heat supplied in the boiler is:

          qb = h3 - h2

          qp = ( 2749.6 - 176.17915 )

          qb = 2573.42085 KJ /kg    .... Answer ( b )

State 4: Turbine Exit / Condenser Inlet ( Isentropic )

          P4 = P1 = 7.3851 KPa         ..... sfg = 7.685 KJ/kg.K

          s4 = s3 = 5.7059 KJ/kg.K       sf = 0.5716994 KJ/kg.K

                                                           hf = 170.32524 KJ/kg

                                                          hfg = 2406.11 KJ/kg

Process 3: Isentropic Expansion - Determine the quality of liquid-vapor mixture phase ( x ) at state (4):

          x = (s4 - sf) / sfg

          x = (5.7059 - 0.5716994) / 7.685

          x = 0.66808

          h4 = hf + x*hfg

          h4 = 170.32524 + 0.66808*2406.11

          h4 = 1777.79920 KJ/kg

- The work-done by the turbine in the isentropic expansion process ( wt ) is:

          wt = h3 - h4

          wt = 2749.6 - 1777.7992

          wt = 971.8008 KJ/kg   ... Answer ( a )

- To determine the thermal efficiency ( nth ) of the rankine cycle. We need to determined the net work produced by the cycle ( wn ). The net work is the energy balance between the isentropic compression ( work done - pump ) and isentropic expansion ( work produced - turbine ):

          wn = wt - wp

          wn = 971.8008 - 8.64915

          wn = 963.15165 KJ/kg

- The thermal efficiency of a power cycle is the ratio of net work-produced ( wn ) and the heat supplied to the working fluid in the boiler ( qb ) as follows:

         nth = wn / qb

         nth = 963.15165 / 2573.42085

         nth = 0.3743    ..... Answer ( c )

The hardware that I am using to take this course is a Laptop computer running on windows operating system.

When you send a query, like your previous message, your laptop's operating system breaks it into smaller units called packets. These packets contain parts of your message, destination address, and other metadata.

They're sent over the internet through your Internet Service Provider (ISP), which directs them through routers and switches. These network devices ensure packets take the most efficient path.

They reach the server where I'm hosted. The server processes your query, generates a response, divides it into packets, sends them back through the same process, and your laptop reassembles them to display my answer.

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The combination of physical fitness, skills, habits, attitude, emotional fitness, knowledge, and mental fitness make up the Arch of Safe Drivers.

Correct answer  is c) The Arch of Safe Drivers.

Safe driving requires more than just being physically able to operate a vehicle. It involves having a variety of skills, such as being able to navigate traffic, obey traffic laws, and react to unexpected situations. Good driving habits, such as avoiding distractions and not driving under the influence, are also important for staying safe on the road. Attitude plays a big role in safe driving as well, as drivers with a positive attitude are more likely to stay calm and focused behind the wheel. Emotional fitness is also important, as being able to manage stress and other emotions while driving can help prevent accidents. Knowledge of traffic laws and safe driving techniques is also crucial for safe driving.

This concept highlights the importance of these factors in ensuring that drivers are well-equipped to maintain safety on the roads.  Finally, mental fitness, such as being able to concentrate and make quick decisions, is also important for safe driving. All of these factors combined make up the Arch of Safe Drivers.

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The technician B is correct in this case since a turbocharger should not be operated at an engine oil pressure lower than 30 psi.

A turbocharger is a device that increases the efficiency of an engine by forcing air into it at a higher pressure. It increases the engine's power and efficiency by supplying it with additional oxygen.Turbochargers are used in both petrol and diesel engines. They are most commonly found in large diesel engines.

It is also used in motorsports, where it is used to improve engine efficiency and power output.Turbochargers are lubricated by engine oil, and most turbochargers have their lubrication system. A turbocharger cannot be operated at an engine oil pressure lower than 30 psi, which can cause damage to the engine's parts.

A turbocharger's lifespan is determined by how well it is maintained, as well as the quality of the oil being used. It is advised to keep your vehicle serviced and your oil changed regularly to keep your turbocharger running smoothly.

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The ethanol-aqueous interface typically contains impurities such as surfactants, soluble organic and inorganic compounds, and other contaminants. Impurities such as this can affect the quality and purity of the final product. There are various ways to remove this interface.

One of them is by using a centrifuge. It can be used to physically remove the interface by spinning the mixture at high speeds. This separates the ethanol and aqueous layers, making it easier to eliminate the interface.Another option is to use a decanter. It is a device that separates liquids with different densities. It can be used to remove the ethanol-aqueous interface by gravity separation.The most effective way of eliminating impurities in the ethanol-aqueous interface is through distillation. It separates the impurities from the ethanol, resulting in a pure ethanol product. This is done by heating the mixture to the boiling point of ethanol. The ethanol vapor is then condensed into a separate container, leaving behind the impurities in the original container.There are several ways to eliminate the ethanol-aqueous interface, but the method you choose will depend on the amount and type of impurities present, as well as the desired purity of the final product.

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Answer:

To document your work and projects.

Explanation:

I hope I got the right meaning. :)

Answer:

Please check the photo (solve)

The answer to the question is e) All of the answer options are correct.The researcher is likely constructing a pedigree for a trait that shows recessive inheritance in humans, which means:

For Part a) This trait may not occur within every generation of a family―it could be said to "skip" generations.For part b) The parents of children who have this trait may not themselves be affected.For part c) Both males and females within a given family can have this trait―it doesn't appear to be sex-specific.For part d) There may be instances of first-cousin mating in this pedigree, resulting in affected children.Therefore, the answer to the question is e) All of the answer options are correct.

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Answer:

The answer is the strain gauges.

Explanation:

Inspection systems work or are performed to measure the characteristics of a product, to verify if it meets specified requirements, all using benchmarks and test equipment.

The strain gauges are part of the test equipment used for inspection. These are sensors that measure deformation, pressure and load in resistance tests of materials.

Aligning the cutting tool when performing a setup on a lathe involves positioning the tool to the same height as the center of the workpiece. This ensures that the tool is correctly aligned to the workpiece, which is crucial in ensuring a proper cut.

Operators should adjust the height of the cutting tool by using the tool post and compound slide. The tool post is used to hold the cutting tool while the compound slide adjusts the height of the tool. The cutting tool tip should be set at the same height as the center of the workpiece. Once the height is adjusted, the operator should make sure that the tool is aligned parallel to the axis of the lathe bed.

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