Which MOLECULES do cells need to get in order to function properly?

The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.

To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.

The ideal gas law equation is given by:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

At STP, the pressure is 1 atm, and the temperature is 273.15 K.

From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.

Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.

Therefore, the volume of I2 gas formed is 21 L.

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Answer:

\(P=1.95atm\)

Explanation:

Hello!

In this case, since we are asked to compute the pressure of 0.175 moles of the given gas at 22.0 °C occupying a volume of 2175 mL, we can use the ideal gas equation as shown below:

\(PV=nRT\)

Whereas our unknown is P and we solve for it as shown below:

\(P=\frac{nRT}{V}\\ \\P=\frac{0.175mol*0.082\frac{atm*L}{mol*K}*(22.0+273.15)K}{2175mL*\frac{1L}{1000mL} }\\ \\P=1.95atm\)

Take into account that based on the given R units, the temperature must be in Kelvins and the volume in liters.

Best regards!

20

12 3.2

12bw

7. A certain music box ha the shape of a cube. Ea

cm long. What is the surface area of the box?

8. Find the amount of tin needed to make a milk to

cm and a height of 5cm.

9. Angelo is wrapping a present. The box he is using is

of 10 cm, a width of 7 cm and a height of 5 cm. Find

gift wrapper he needs to wrap the entire box?

10.

The side of the a cube measures 12 cm. Sc

a

Answer:

The activity relates to the process of igneous rock formation by the cooling of magma. It can be used to illustrate how the rate at which molten rock cools affects the size of the crystals that form within the solid rock – rapid cooling producing small crystals, slower cooling producing larger ones.

Explanation:

Answer:

rmm doesn't need to include unit and molar mass need to include unit

Answer:

B. PROTONS EXHIBIT STRONGER PULL ON OUTER f ORBITALS

Explanation:

Lanthanide contraction is the greater than normal decrease in the ionic radius of the lanthanide series from atomic number 57 to atomic number 71. This decrease is rather not expected of the ionic radii of these elements and they result in the greater decrease in the subsequent series of the lanthanides from the atomic number 72. The cause of which is as a result of the poor shielding effects of the nuclear charge around the electrons of the f orbitals. So therefore, protons are strongly pulled out of the 4f orbital and as a result of the poor shielding effect which causes the electrons of the 6s orbitals to be drawn more closer to the nucleus and hence resulting in a smaller atomic radii. It is worthy to note that the shielding effects of the inner electrons decreasing from s orbital to the f orbital; that is s > p > d > f. So from the decrease in the shielding effects from s to the f orbitals, lanthanide contraction results from the inability of the orbitals far away from s like the 4f orbiatls to shield the outermost shells of the lanthanide elements. So the cause of lanthanide contraction is the action of the protons which strongly pull the electrons of the f orbitals because of the poor shielding effects due to the distance of this orbital from the nucleus.

Answer:

B) Protons exhibit a stronger pull on outer f orbitals than on d orbitals.

Explanation:

Answer:

The two objects have different volumes.

Explanation:

The density of an object measures how closely packed the mass in the object is. Density of an object is obtained by taking the ratio of the mass of an object and its volume.

Density = mass/volume

The mass present in an object is constant, but the volume may vary with temperature. The volume of substances generally increases with temperature, therefore, density decreases with increase in volume.

Two objects at the same temperature having equal masses may or may not have the same density depending on the volume each object occupy.

If two substances are at the same temperature and have equal masses but different densities, then they must have different volumes.

1) The molar mass of the acid of the titration curve is 166 g/mol

2) The pKa of the acid of the titration curve is 4.97.

1) The molar mass of the acid can be determined from the equivalence point of the titration curve

Mass of acid sample = 0.431 g

Volume of KOH solution at equivalence point = 24.0 mL = 0.0240 L

Molarity of KOH solution = 0.108 M

Number of moles of KOH added at equivalence point = Molarity x Volume

= 0.108 M x 0.0240 L

= 0.00259 moles

Number of moles of acid = Number of moles of KOH added

= 0.00259 moles

Molar mass of acid = Mass of acid sample ÷ Number of moles of acid

= 0.431 g ÷ 0.00259 moles

= 166 g/mol

2) The pKa of the acid can be determined from the half-equivalence point of the titration curve.

Volume of KOH solution at half-equivalence point = 11.5 mL = 0.0115 L

Number of moles of KOH added at half-equivalence point = Molarity x Volume

= 0.108 M x 0.0115 L

= 0.00124 moles

Concentration of acid at half-equivalence point = Number of moles of acid remaining ÷ Volume of acid

= (0.431 g - (0.00124 moles x 56.1 g/mol)) ÷ 0.025 L

= 0.017 M

Concentration of conjugate base at half-equivalence point = Number of moles of KOH added ÷ Volume of KOH

= 0.00124 moles ÷ 0.0115 L

= 0.108 M

pKa = pH + log([conjugate base] ÷ [acid])

= 7.08 + log(0.108 ÷ 0.017)

= 4.97

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The pOH of the solution containing 9.8×10⁻³ M of hydrogen ion concentration, [H⁺] is 11.99

First, we shall determine the hydroxide ion concentration [OH⁻] in the solution. Details below:

[H⁺] × [OH⁻] = 10¯¹⁴

9.8×10⁻³ × [OH⁻] = 10¯¹⁴

Divide both side by 9.8×10⁻³

[OH⁻] = 10¯¹⁴ / 9.8×10⁻³

[OH⁻] = 1.02×10⁻¹² M

Finally, we shall determine the pOH of the solution. Details below:

pOH = -Log [OH⁻]

pOH = -Log 1.02×10⁻¹²

pOH = 11.99

Thus, from the above calculation, we can conclude that the pOH of the solution is 11.99

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Answer:

Kinetic energy

Explanation:

Di ako sure kung Tama

Answer: metal turn orange and weaker as it gets oxidised

Explanation:

Explanation:

Sublimation describes a solid turning directly into a gas. Melting, on the other hand, occurs when a solid turns into a liquid. Water can, under the right circumstances, sublimate, though it usually melts at temperatures above 0 degrees Celsius or 32 degrees Fahrenheit. Carbon dioxide (CO2), however, is very different. The conditions that determine whether CO2 melts or sublimates are both temperature and atmospheric pressure.

Answer:

The balanced equation for the reaction of aqueous calcium chloride and sodium carbonate solutions is:

CaCl2(aq) + Na2CO3(aq) → 2NaCl(aq) + CaCO3(aq)

CaCl2 and Na2CO3 are the reactants in this equation, whereas NaCl and CaCO3 are the products. The coefficients are balanced such that each element has an equal amount of atoms on both the reactant and product sides of the equation.

(it might be wrong, super sorry!)

The waves that  has the greatest wavelength is Wavelength shown with 1 wavelength stretched over a long distance.

A wave could be a disturbance or variety that voyages through a medium or space, carrying vitality without transporting matter. Waves can take different shapes and happen totally different sorts of waves, counting mechanical waves and electromagnetic waves.

Mechanical waves require a medium to propagate, meaning they require a substance like water, discuss, or a strong fabric to transmit the wave. Illustrations of mechanical waves incorporate water waves, sound waves, and seismic waves. In these waves, particles of the medium sway or vibrate in a design, exchanging energy from one molecule to another.

Electromagnetic waves, on the other hand, don't require a medium and can travel through vacuum, such as in space. Electromagnetic waves comprise of electric and attractive areas swaying opposite to each other and to the heading of wave engendering. Illustrations of electromagnetic waves incorporate obvious light, radio waves, microwaves, infrared waves, bright waves, X-rays, and gamma beams.

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The heat required is to convert 75.0 g of C₂Cl₃F₃ from a liquid at 13.60 ∘C to a gas at 76.00 ∘C is 17.55 kJ.

To solve this problem, we need to consider the different steps involved in the process of converting 75.0 g of C₂Cl₃F₃ from a liquid at 13.60 ∘C to a gas at 76.00 ∘C;

Heating the liquid C₂Cl₃F₃ from 13.60 ∘C to its boiling point at 47.6 ∘C, Vaporizing the liquid C₂Cl₃F₃ at its boiling point, and heating the resulting gas from 47.6 ∘C to 76.00 ∘C

Now, we can use the equations to calculate the heat required for each step;

q₁ = m × C₁ × ΔT₁

where q₁ is the heat required, m is the mass of C₂Cl₃F₃, C₁ is the specific heat of C₂Cl₃F₃(l), and ΔT₁ is the temperature change from 13.60 ∘C to 47.6 ∘C.

q₁ = 75.0 g × 0.91 J/g⋅K × (47.6 ∘C - 13.60 ∘C)

= 2466 J

q₂ = n × ΔHvap

where q₂ is the heat required, n is the number of moles of C₂Cl₃F₃, and ΔHvap is the heat of vaporization of C₂Cl₃F₃.

n = m/M

= 75.0 g / 137.37 g/mol

= 0.5464 mol

q₂ = 0.5464 mol × 27.49 kJ/mol

= 15.038 kJ

q₃ = m × C₂ × ΔT₂

where q₃ is the heat required, m is the mass of C₂Cl₃F₃(g), C₂ is the specific heat of C₂Cl₃F₃(g), and ΔT₂ is the temperature change from 47.6 ∘C to 76.00 ∘C.

m = n × M

= 0.5464 mol × 137.37 g/mol

= 75.0 g

q₃ = 75.0 g × 0.67 J/g⋅K × (76.00 ∘C - 47.6 ∘C)

= 1446 J

The total heat required is the sum of the heats required for each step;

\(q_{total}\)= q₁ + q₂ + q₃

= 2466 J + 15.038 kJ + 1446 J

= 17.55 kJ

Therefore, the total heat required is 17.55 kJ.

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Answer: The total pressure is 7 atm

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

\(p_{total}=p_A+p_B+p_C...\)

Given : \(p_{total}\) =total pressure of gases = ?

\(p_{O_2}\) = partial pressure of oxygen = 2 atm

\(p_{N_2}\) = partial pressure of nitrogen = 4 atm

\(p_{Ar}\) = partial pressure of argon = 1 atm

putting in the values we get:

\(p_{total}=2atm+4atm+1atm\)  

\(p_{total}=7atm\)

Thus the total pressure is 7 atm

This element is in group 1.

According to the octet rule, this element would be expected to form an ion with a charge of +1.

If X is in period 5, the ion formed has the same electron configuration as the noble gas Krypton

The symbol for the ion is Rb⁺

Electronic configuration refers to the arrangement of electrons in the orbitals of an atom or molecule, indicating the energy level of the electrons, the number of electrons in each energy level, and the number of electrons in each orbital.

Considering the given element:

It has one valence electron, hence it is in group 1. Group 1 elements form ions with a charge of +1.

Losing one electron will give the ion the same electron configuration as Kyrton since it is the noble gas in Period 4.

The element is rubidium and the ion is Rb⁺.

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The energy of light with a wavelength of 589 nm is approximately 3.36 × 10^(-19) Joules.

To calculate the energy of light, we can use the equation E = hc/λ, where E represents the energy, h is Planck's constant (6.626 × 10^(-34) J·s), c is the speed of light in a vacuum (3.00 × 10^8 m/s), and λ is the wavelength of light.

Given that the wavelength is 589 nm (which is equivalent to 589 × 10^(-9) m), we can substitute the values into the equation:

E = (6.626 × 10^(-34) J·s × 3.00 × 10^8 m/s) / (589 × 10^(-9) m)

Simplifying the equation, we get:

E = (1.9778 × 10^(-25) J·m) / (5.89 × 10^(-7) m)

Dividing these values, we find:

E ≈ 3.36 × 10^(-19) J

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Explanation:

Antacids are medications used to manage the symptoms of indigestion and heartburn. Antacids contain active ingredients that are bases. These allow antacids to neutralize any stomach acid which could be causing digestive discomfort.

Answer: norganic compounds are compounds that do not deal with the formation of ... are every other molecule that does not include these distinctive carbon and hydrogen structures. ... This is indicated by assigning a Roman numeral after the metal. ... For example, iron can form two common ions, Fe2+ and Fe3+.

The normality of the H₂SO₄ that reacted with 25cc of 5 % NaOH solution is 1.1 N.

The molarity of 5% NaOH is 1.32 M

25 cc of NaOH neutralized 30cc of H₂SO₄ solution.

Equation of reaction is given below:

Molarity of H₂SO₄ = 1.32 x 1 x 25/(30 x 2) = 0.55 M

moles of H⁺ ions per mole of H₂SO₄ = 2

Normality of H₂SO₄ = 0.55 x 2 = 1.1 N

In conclusion, the normality of an acid is determined from the molarity and the moles of H⁺ ions per mole of acid.

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Answer: :)

The temperature of a gas is directly proportional to the average kinetic energy of the particles of the gas. But the total kinetic energy of the molecules of a gas is a measure of the internal energy or thermal energy of the gas.

Explanation:

Answer:

The chemical equation H2 + O2 + H2O represents what type of equation?

A. A balanced equation

xXxAnimexXX

The balanced chemical equation for the reaction between strontium and oxygen can be written as follows: 2 Sr (s) + \(O_2\)(g) → 2 SrO (s).

In this equation, solid strontium (Sr) reacts with gaseous oxygen (\(O_2\)) to produce solid strontium oxide (SrO).

To determine the mass of product expected to form in this reaction, we need to consider the molar ratio between strontium and strontium oxide. From the balanced equation, we can see that 2 moles of strontium react to produce 2 moles of strontium oxide.

The molar mass of strontium (Sr) is 87.62 g/mol, and the molar mass of strontium oxide (SrO) is 119.62 g/mol. Since the molar ratio is 1:1 between strontium and strontium oxide, the mass of strontium oxide formed will be equal to the mass of strontium used.

In this case, the student added 4.93 g of strontium to the crucible. Therefore, the expected mass of strontium oxide formed will also be 4.93 g.

It's important to note that this calculation assumes that the reaction proceeds to completion, meaning that all of the strontium reacts with oxygen. In actual laboratory conditions, the yield of the reaction may be less than 100% due to factors such as incomplete reaction, side reactions, or product loss.

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Li is likely to make +1 charge. This is because lithium atoms contain 3 protons and 3 electrons. It loses one of its electrons, making it an ion. It now has more positive protons than electrons so it has an overall positive charge.

This refers to a chemical element with the symbol Li and atomic number 3. It belongs to a group known as alkali metals. During electronic configuration, it loses one electron to become a positive ion.

This refers to elements occupying Group IA (1) of the periodic table. They are very reactive, electropositive, monovalent metals forming strongly alkaline hydroxides. All the alkali metals have a +1 charge.

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By performing the calculations and comparing the F-value to the critical F-value, we can determine whether the variance of the Gravimetric method differs significantly from that of the Volumetric method in the analysis of iron in sample A.

To determine if there is a significant difference between the variances of the Gravimetric and Volumetric methods used to determine iron in sample A, we can employ the F-test, also known as Fisher's F-test or the variance ratio test. The F-test compares the ratio of the variances to assess if there is a statistically significant difference.

Let's denote the Gravimetric method as Group 1 and the Volumetric method as Group 2. The first step is to calculate the variances for each group.

For Group 1 (Gravimetric):

Variance_1 = [(13.0-13.1)^2 + (13.5-13.1)^2 + (13.3-13.1)^2 + (12.9-13.1)^2 + (15.1-13.1)^2 + (13.3-13.1)^2 + (12.7-13.1)^2 + (12.6-13.1)^2 + (13.1-13.1)^2] / (n-1)

For Group 2 (Volumetric):

Variance_2 = Calculate the variance in the same manner for the data obtained from the Volumetric method.

Once we have the variances, we can calculate the F-value using the formula:

F = Variance_1 / Variance_2

Next, we need to compare this F-value with the critical F-value at a chosen significance level (usually α = 0.05 or 0.01) and degrees of freedom for each group (df_1 and df_2).

If the calculated F-value is greater than the critical F-value, it indicates a significant difference between the variances of the two methods. Conversely, if the calculated F-value is less than the critical F-value, there is no significant difference in the variances.

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Answer:

Explanation:

A Basketball Weigh in Grams? A 29.5 inch (75 cm) basketball typically weighs about 624 grams (g). A 28.5 inch (72.4 cm) basketball weighs about 567 grams (g).

Answer:

B) The density changed.

C) The salt dissolved in the water.  

E) The salt and the water can still be separated into their individual molecules

Explanation:

A physical change is a change that occurs in a substance which affects only the physical properties of that substance such as color, density, boiling o melting point, etc. In a physical change, the substance retains its chemical composition and no new substances are formed. The changes that occur can as well be reversed.

A chemical change is a change that occurs in a compound which affects or alters the chemical properties of that substance, hence transforming the substance into an entirely new substance different from the original substance. The changes that occur in a chemical change are not easily reversible.

In the given experiment, addition of salt to water results in the following changes:

Density is a physical property of a substance, and as the dissolved salt can be easily recovered from the salt solution solution by evaporation followed by condensation, the changes observed are physical changes.

Answer:

The Answer is A

Explanation:

The answer is A because in picture A, they are too close together to move around.