Answers
An image which shows an object or objects moving with accelerated motion is: A. image A.
What is an acceleration?In Science, an acceleration can be defined as the rate of change of the velocity of a physical object or body with respect to time.
How to calculate the acceleration of an object?Mathematically, the acceleration of a physical object or body can be calculated by using this formula:
a = (V - U)/t
Where:
a represents the acceleration.V represents the final velocity.U represents the initial velocity.t represents the time measured in seconds.Generally speaking, a physical object would experience an accelerated motion when the rate of change of velocity with respect to time throughout the motion is uniform and in a straight line.
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Related Questions
Use the vocabulary words from
“Read It” to complete the
following sentences.
Light from the Sun reaches Earth very
quickly. The (4)_____ is 186,000 miles per
second! We capture sunlight using
(5)_____, which are devices that use the
(6)_____ to convert light to electricity. As
atoms absorb energy, the electrons get
“excited” and release energy as (7)_____.
Whatever light that is not absorbed will
(8)_____ off the surface of the object and
bounce back toward the source.
Answers
Answer:
Light from the Sun reaches Earth very quickly. The (4) speed of light is 186,000 miles per second! We capture sunlight using (5) solar panels, which are devices that use the (6) photovoltaic effect to convert light to electricity. As atoms absorb energy, the electrons get “excited” and release energy as (7) photons. Whatever light that is not absorbed will (8) reflect off the surface of the object and bounce back toward the source.
Ajani is trying to experimentally measure Planck's constant h. He does this by shining different wavelengths of monochro- matic (i.e., single-wavelength) EM radiation on a metal plate with unknown work function W, and then measuring the stop- ping voltage required to bring the ejected electrons to a halt. When he uses λ1= 400 nm, he finds that a stopping voltage of V1 = 0.7 V is required. When he uses λ2 = 500 nm, he finds that a stopping voltage of V2= 0.2 V is required. Based on these two data points, what is Ajani's measurement of Planck's constant?
Answers
Answer:
h = 1.01 x 10⁻³⁴ J.s
Explanation:
The energy applied by the voltage must be equal to the energy associated with the wavelength of light:
\(eV = \frac{hc}{\lambda}\\\)
where,
e = charge on electron = 1.6 x 10⁻¹⁹ C
V = stopping potential
h = Planck's Constant = ?
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of light
For λ = 400 nm = 4 x 10⁻⁷ m, V = 0.7 V:
\((1.6\ x\ 10^{-19}\ C)(0.7\ V) = \frac{h(3\ x\ 10^8\ m/s)}{4\ x\ 10^{-7}\ m}\\\)
h = 1.49 x 10⁻³⁴ J.s
For λ = 500 nm = 5 x 10⁻⁷ m, V = 0.2 V:
\((1.6\ x\ 10^{-19}\ C)(0.2\ V) = \frac{h(3\ x\ 10^8\ m/s)}{5\ x\ 10^{-7}\ m}\\\)
h = 0.53 x 10⁻³⁴ J.s
Taking average of both values:
\(h = \frac{(0.53+1.49)\ x\ 10^{-19}\ J.s}{2}\)
h = 1.01 x 10⁻³⁴ J.s
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Which of these units is most appropriate to use when measuring the mass of a person?
Answers
The SI unit of mass is the kilogram
What is sound waves
Answers
Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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write down the value of
920 kg in g
Answers
Answer:
920000
Explanation:
Each kg contains 1,000 grams
What are used to measure temperature.
Answers
Answer:
A thermometer is an instrument that measures temperature.
Explanation:
Tom applied 10 000J of heat energy to four (4) metals A, B, C and D. All the metals were of the same mass and were initially at the same temperature. After heating the metals the temperature change was noted as shown in the table below. Metal 9 A.25 B.35 C.10 D.15 Which of these four (4) metals has the highest heat capacity?
Answers
The metal with the highest heat capacity between metals A.25 B.35 C.10 and D.15 is metal A.
How to determine heat capacity?Heat capacity is the amount of heat required to raise the temperature of a substance by one degree Celsius. Metal A has a heat capacity of 400 J/kg°C, which means that it takes 400 joules of heat to raise the temperature of one kilogram of metal A by one degree Celsius.
Metal B has a heat capacity of 285.7 J/kg°C, metal C has a heat capacity of 1000 J/kg°C, and metal D has a heat capacity of 666.7 J/kg°C. Therefore, metal A has the highest heat capacity of the four metals.
Metal A's high heat capacity means that it can absorb a lot of heat without its temperature changing very much. This makes metal A a good material for things like heat sinks and thermal insulation.
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If 10 waves pass one dock every 16.0 seconds, determine the frequency of the wave.
Answers
The frequency of the wave is 0.625 waves per second, calculated by dividing the number of waves (10) by the time (16.0 seconds).
To determine the frequency of a wave, you need to divide the number of waves (in this case, 10) by the time it takes for those waves to pass a certain point (in this case, a dock) within 16.0 seconds.
Frequency is usually measured in Hertz (Hz), which represents the number of cycles or events per second. So, to find the frequency, we calculate 10 waves / 16.0 seconds = 0.625 waves per second or 0.625 Hz.
This means that every second, 0.625 waves pass by the dock, giving you the frequency of the wave.
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What is the Russell-Vogt theorem? Why is it important? How does it shed
light on the existence of the Main Sequence?
Answers
According to the Vogt-Russell theorem, the structure of a star in hydrostatic and thermal equilibrium with all energy produced from nuclear processes is uniquely defined by its mass and chemical element distribution throughout its interior.
Despite being called a theorem, the Vogt-Russell theorem has never been officially proven. The theorem is named for the astronomers Heinrich Vogt and Henry Norris Russell, who separately devised it.
What is the relevance of the Vogt-Russell theorem?The Russell-Vogt Theorem, which states that the nature of a star is essentially entirely governed by its mass, age, and starting composition, explains why stars have such a well-defined brightness and temperature range while they are burning hydrogen in their interiors.
This trend is especially noticeable because the initial composition has little influence in comparison to the other two. The upper luminosity limit is caused by stars more massive than about 100 times the mass of the sun blowing themselves apart, while the lower luminosity limit is caused by objects less massive than about 0.08 times the mass of the sun failing to develop satisfactory pressure and temperature in their cores to burn hydrogen.
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Based on the diagram, why does the lightbulb light when the loop rotates, and what is the energy change involved?
Responses
When the wire moves in an electric field, electrons in the wire move and become mechanical energy. The mechanical energy causes the light to glow. Electrical energy used to rotate the loop is converted to light energy.
When the wire moves in an electric field, electrons in the wire move and become mechanical energy. The mechanical energy causes the light to glow. Electrical energy used to rotate the loop is converted to light energy.
When the wire moves in a magnetic field, electrons in the wire move and become an electric current. The current causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
When the wire moves in a magnetic field, electrons in the wire move and become an electric current. The current causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
When the wire moves in an electric field, electrons in the wire move and become mechanical energy. The mechanical energy causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
When the wire moves in an electric field, electrons in the wire move and become mechanical energy. The mechanical energy causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
When the wire moves in a magnetic field, electrons in the wire move and become an electric current. The current causes the light to glow. Mechanical energy used to rotate the loop is converted to light energy.
Answers
Answer: When the wire moves in a magnetic field, electrons in the wire move and become an electric current. The current causes the light to glow. Mechanical energy used to rotate the loop is converted to electrical energy.
Explanation:
In the given scenario, the rotating loop of wire creates a changing magnetic field. According to Faraday's law of electromagnetic induction, this changing magnetic field induces an electric current in the wire. The electrons in the wire move as a result of this induced current, and this current flows through the lightbulb, causing it to light up.
Therefore, the energy change involved is the conversion of mechanical energy (from rotating the loop) into electrical energy (as the induced current flows through the lightbulb), which then produces light energy in the lightbulb.
A particle is projected vertically upwards from the ground with a speed of 36m/s^-1, calculate.
a. The time for which it is above a height of 63m.
b. The speed which it has at this height on its way down
c. The total time of flight
Answers
To solve this problem, we can use the equations of motion for a freely falling body with constant acceleration due to gravity (g = 9.81 m/s²).
a. The time for which it is above a height of 63m:
We can use the following equation of motion to find the time t it takes for the particle to reach a height of 63 m above the ground:
y = uyt + (1/2)gt²
where y is the displacement (height) of the particle, uy is the initial velocity in the y-direction (upward), and t is the time.
At the highest point of its trajectory, the particle will have zero velocity, so we can use the initial velocity as uy = 36 m/s. We want to find the time t when the particle reaches a height of y = 63 m, so we can rearrange the equation to solve for t:
t = (-uy ± sqrt(uy² + 2gy))/g
where the ± sign indicates that there are two possible solutions, one for when the particle is going up (positive root) and one for when the particle is coming down (negative root).
Plugging in the values for uy, g, and y, we get:
t = (-36 ± sqrt(36² + 2*(-9.81)*63))/(-9.81)
t = 6.53 s (upward)
b. The speed which it has at this height on its way down:
When the particle reaches a height of 63 m on its way down, we can use the following equation to find its velocity vy:
vy² = uy²+ 2g(y - yo)
where yo is the initial height (0 m) and uy is the initial velocity in the y-direction (upward).
We can plug in the values for uy, g, and y, and solve for vy:
vy²= 36²+ 2(-9.81)(63 - 0)
vy = 32.2 m/s (downward)
c. The total time of flight:
The total time of flight is twice the time it takes for the particle to reach the maximum height, since it takes the same amount of time to come back down to the ground. Therefore, the total time of flight is:
t_total = 2t_upward = 2(6.53) = 13.06 s
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Bro help me
Explain how an object with a higher temperature can have less thermal energy than an object with a lower temperature. ASAP
Answers
The total energy of all the particles makes up thermal energy. This implies that larger objects with slower-moving particles at low temperatures can have more energy than smaller ones with higher temperatures.
What is thermal energy?Thermal energy is the sum of the energies of all the particles. This implies that larger objects at low temperatures can have more energy than smaller ones at higher temperatures due to slower-moving particles.
These molecules and atoms move more quickly when something is heated, providing it with more thermal energy. Compared to cold water, hot water has more thermal energy.
Therefore, molecules and atoms in colder objects move more slowly and have less thermal energy than those in warmer ones. The ability of particles to transfer energy increases with speed.
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wire (mass = 50 g, length = 40 cm) is suspended horizontally by two vertical wires which
conduct a current I = 8.0 A, as shown in the figure. The magnetic field in the region is into the
paper and has a magnitude of 60 mT. What is the tension in either wire?
Answers
The magnetic field in the region is into the paper and has a magnitude of 60 mT and the tension in either wire is 0.096 N.
To find the tension in either wire, we can apply the equation for the force experienced by a current-carrying wire in a magnetic field.
The force experienced by a current-carrying wire in a magnetic field is given by the equation F = B * I * L * sin(θ), where B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.
In this case, the wire is suspended horizontally by two vertical wires, and the magnetic field is into the paper. Since the wire is horizontal, the angle between the wire and the magnetic field is 90 degrees, so sin(θ) = 1.
The force experienced by the wire due to the magnetic field is F = B * I * L.
Given:
Current (I) = 8.0 A
Magnetic field (B) = 60 mT = 60 * 10^(-3) T
Length of the wire (L) = 40 cm = 40 * 10^(-2) m
Substituting the given values into the equation, we get:
F = (60 * 10^(-3) T) * (8.0 A) * (40 * 10^(-2) m)
Simplifying the expression, we find:
F = 0.192 N
Since the wire is suspended by two vertical wires, the tension in each wire will be half of the total force. Therefore, the tension in either wire is 0.192 N / 2 = 0.096 N.
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How are magnetic fields like vectors?
Answers
Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.
Explanation:
An object traveling at 1.5 rad
accelerates at 0.75d for 12
S
seconds. What is the object's final
velocity?
Answers
The object's final velocity, given the data is 10.5 rad/s
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the final velocityThe following data were obtained from the question
Initial velocity (u) = 1.5 rad/sAcceleration (a) = 0.75 rad/s²Time (t) = 12 sFinal velocity (v) = ?The final velocity can be obtained as follow:
a = (v – u) / t
0.75 = (v – 1.5) / 12
Cross multiply
v – 1.5 = 0.75 × 12
v – 1.5 = 9
Collect like terms
v = 9 + 1.5
v = 10.5 rad/s
Thus, the final velocity of the object is 10.5 rad/s
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An astronaut measure the period of a mass spring system on Earth. How would the period be affected if the astronaut measured the period of the same mass spring system on the moon? (Moon's gravity = 1/6 Earth's gravity.)
Answers
An astronaut measure the period of a mass spring system on Earth.
The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.
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Two stars M1 and M2 of equal mass make up a binary star system. They move in a circular orbit that has its center at the midpoint of the line that separates them. If M1 = M2 = 5.45 sm (solar mass), and the orbital period of each star is 3.20 days, find their orbital speed. (The mass of the sun is 1.99E30 kg.)
Answers
Since Two stars M1 and M2 of equal mass make up a binary star system. their orbital speed is 2.69E4 m/s.
What is the orbital speed about?The orbital period of a binary star system is given by the equation:
T = 2 * pi * sqrt(a³ / (G * (M1 + M2)))
where T is the orbital period, a is the semi-major axis of the orbit (half of the distance between the two stars at their closest approach), G is the gravitational constant, and M1 and M2 are the masses of the two stars.
Substituting the given values into this equation, we get:
3.20 days = 2 * pi * sqrt(a³ / (6.67E-11 m³ kg^⁻¹ s^⁻² * (5.45 sm * 1.99E30 kg/sm + 5.45 sm * 1.99E30 kg/sm)))
Solving for the semi-major axis, we find that a = 2.11E11 m.
The speed of each star in the orbit can be found using the equation:
v = sqrt(G * (M1 + M2) / a)
Substituting the values we have calculated, we find that v = 2.69E4 m/s. This is the speed of each star in the orbit.
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URGENT HELP IT IS DUE BY TONIGHT PLEASE HELP
Answers
Answer:
45.8
Explanation:
becuse 9.8+36=45.8 simple
if the water measures -5 feet at low tide and 3ft at high tide what is the tidal range
Answers
Answer:
8 feet
................
find a time period whose frequency is 300 hertz
Answers
Answer:
0.0333
Explanation:
frequency=1/T
making T the subject of formula, we have
T=1/f
since f=300hertz
T=1/300
T=0.00333
Good luck
An aluminum wire having a cross-sectional area equal to 2.20 10-6 m2 carries a current of 4.50 A. The density of aluminum is 2.70 g/cm3. Assume each aluminum atom supplies one conduction electron per atom. Find the drift speed of the electrons in the wire.
Answers
Answer:
The drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.
Explanation:
We can find the drift speed by using the following equation:
\( v = \frac{I}{nqA} \)
Where:
I: is the current = 4.50 A
n: is the number of electrons
q: is the modulus of the electron's charge = 1.6x10⁻¹⁹ C
A: is the cross-sectional area = 2.20x10⁻⁶ m²
We need to find the number of electrons:
\( n = \frac{6.022\cdot 10^{23} atoms}{1 mol}*\frac{1 mol}{26.982 g}*\frac{2.70 g}{1 cm^{3}}*\frac{(100 cm)^{3}}{1 m^{3}} = 6.03 \cdot 10^{28} atom/m^{3} \)
Now, we can find the drift speed:
\(v = \frac{I}{nqA} = \frac{4.50 A}{6.03 \cdot 10^{28} atom/m^{3}*1.6 \cdot 10^{-19} C*2.20 \cdot 10^{-6} m^{2}} = 2.12 \cdot 10^{-4} m/s\)
Therefore, the drift speed of the electrons in the wire is 2.12x10⁻⁴ m/s.
I hope it helps you!
un auto si muove lungo una strada rettilinea
Answers
Answer:
Un'auto si muove lungo un percorso rettilineo con velocità variabile come mostrato in figura. Quando l'auto è in possesso di A, la sua velocità è 10 ms-1 e quando è in posizione B, la sua velocità è 20 ms-1. Se l'auto impiega 5 secondi per spostarsi da A a B, trova l'accelerazione dell'auto.
Explanation:
A bus is travelling along straight road at 100km/hr and the bus conductor walks a 6km/hr on the floor of the bus and in the same direction as the bus. Find the speed of the conductor relative to the road and relative to the bus. If the bus conductor now walks at the same rate but in opposite direction as the bus, find his new speed relative to the road.
Answers
Given data:
* The speed of the bus is 100 km/hr.
* The speed of the conductor is 6 km/hr.
Solution:
(a). If the bus and conductor are traveling in the same direction.
The net speed of the conductor relative to the road is,
\(v_1=v_b+v_c_{}\)where v_1 is the velocity of the conductor relative to the road, v_b is the velocity of the bus, and v_c is the velocity of the conductor inside the bus,
Substituting the known values,
\(\begin{gathered} v_1=100+6 \\ v_1=106\text{ km/hr} \end{gathered}\)Thus, the speed of the conductor relative to the road is 106 km/hr.
(b). The speed of the conductor relative to the bus is the speed of the conductor on the bus,
Thus, the speed of the conductor relative to the bus is 6 km/hr.
You connect three resistors with resistances R, 2R, and 3R in parallel. The equivalent resistance of the three resistors will have a value that is:_______
a. less than R.
b. between R and 2R.
c. greater than 3R.
d. between 2R and 3R.
Answers
Less than R, less than 2R, less than 3R, and less than any other possible hookup of any one, any two, or all three of these resistors.
What is the length of the x-component of the vector shown below?
у
6
28°
Answers
Answer:
Explanation:
6cos28
=5.3 N
I have multiple voltage sources of different rating like 5V,6V,1V and 20V draw schematic diagram using these sources to power a light of rating 11 volt
Answers
Answer:
add molecules
URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!!
Answers
Answer:
it’s the last one chemical covered to mechanical
Explanation:
asked my science teacher to make sure it’s correct
Can someone please help me with this following question, If you could visit Pangaea what animals would you find
A). Penguins
B). Mammals
C). Dinosaurs
D). Eagles
Answers
Answer:
C). Dinosaurs
Explanation:
Steve is planning his annual Spring Break road trip. He pulls out his map and draws out his route to visit the five locations that he has planned for this year. They go in a counterclockwise loop and he ends up at home, where he started, just in time to start classes again. Whenever he is on the road he travels a constant 60 miles/hour. When Steve adds up the total distance traveled, as measured by his odometer, and divides it by the time that his trip took, he has measured what quantity?
a. His average velocity.
b. His average speed.
c. His instantaneous velocity.
d. His instantaneous speed.
Answers
Answer:
His average speed.
Explanation:
Average speed = Total distance travelled / total time .
In the given case odometer measures total distance travelled . Dividing it by time will give average speed .
Average velocity can not be the answer as it is measured by dividing displacement by time . Displacement here is zero because initial and final point are same . Instantaneous velocity is given by the speedometer . It keeps on changing all the time . It is actually speed at a particular point of time . It can not be average velocity or speed .