Which have the same velocity?

A. A boy walking east at 2 km/h and a man walking east at 4 km/h
B. A car standing still and a truck driving in a circle at 4 km/h
C. A dog walking west at 3 km/h and a cat walking west at 3 km/h
D. A girl walking west at 3 km/h and a boy walking south at 3 km/h

Answer:

If Earth hadn't been hit by Orpheus, it would be covered by ocean, with perhaps a few mountaintops emerging through the water. There would be no humans, but there could be other forms of life. Earth would rotate rapidly, as the moon would not be present to produce the tidal friction that slows Earth's rotation today

Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

Answer:

Charged

Explanation:

When an atoms loses or gains electrons they become charged(ion)

When an atom loses electrons it becomes positively charged and it is called a Cation

When an atom gains electrons it becomes negatively charged and it is called an Anion

Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.

In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.

Here,

a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.

b. Since no work is done, no energy is used or transferred.

c. The power exerted by the man can be calculated using the formula:

Power = Work / Time

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The liquid's surface tension in N/m is determined as 0.25 N/m.

Surface tension is defined as the property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.

Mathematically, the formula for surface tension of a liquid is given as;

γ = F/L

γ = F/2x

where;

From Hooke's law, the force applied on an elastic material is directly proportional to the extension of the material.

F = kx

where;

The final equation for the surface tension of the liquid film becomes;

γ = F/2x

γ = kx/2x

γ = k/2

γ = (0.5 N/m) / 2

γ = 0.25 N/m

Thus, the surface tension of a liquid depends on the applied force and length of the liquid surface.

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Answer:

A closed system.

Explanation:

The three major types of system are: open, closed and isolated. Open system interacts with its surroundings with respect to its particles and energy. A closed system interacts with its surroundings with respect to energy but not its particles. While an isolated system does not interact with its surroundings in any way.

Therefore, after the jar is sealed, it is an example of a closed system. This is because the emitted gas could not escape into the surroundings, but thermal energy was emitted into its surroundings after the chemical reaction has taken place.

Stars that are approximately 8 to 20 solar masses leave behind neutron stars.

What is neutron star?

A neutron star is a highly compact and dense object that is created when a massive star undergoes a supernova explosion and its core collapses. It is composed almost entirely of neutrons, hence the name "neutron" star. The gravitational force of a neutron star is so strong that it compresses its mass into a very small volume, typically about 10 kilometers (6.2 miles) in radius.

Neutron stars are formed when a massive star undergoes a supernova explosion, and the core of the star collapses under its own gravity. The minimum mass of a star that can form a neutron star is about 8 solar masses, while the maximum mass is thought to be around 20-25 solar masses.

Stars with masses greater than 20-25 solar masses are expected to collapse into black holes instead of neutron stars. Therefore, option A is incorrect. Stars with masses less than 8 solar masses are not massive enough to undergo supernova explosions, and they typically end their lives as white dwarfs. Option C is therefore also incorrect.

Thus, option D is the correct answer, as stars that are approximately 8 to 20 solar masses leave behind neutron stars.

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The size of stars that typically leave behind a neutron star depends on their mass. Neutron stars are formed as the result of a supernova explosion of a massive star, where the core of the star collapses and forms a highly dense, compact object.

According to current models, any star with a mass greater than 20 solar masses will undergo a supernova explosion and leave behind a neutron star.

However, stars with masses between 8 and 20 solar masses can also form neutron stars, depending on their composition and other factors. In general, O-type stars that are approximately 2 to 7 solar masses are more likely to form neutron stars compared to other types of stars.

On the other hand,

stars with masses less than 8 solar masses are not massive enough to undergo a supernova explosion and form a neutron star. Instead, they typically end their lives as white dwarfs or low-mass black holes. Overall, the size of stars that leave behind a neutron star depends on their mass, with the most massive stars being the most likely to form neutron stars.

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Answer:

\(12.35\:\mathrm{m/s}\)

Explanation:

We can use the work-energy theorem to solve this problem. The work-energy theorem states that the work done on an object will be equal to that object's change in kinetic energy. Thus, we have the following equation:

\(W=\Delta KE,\\W=\frac{1}{2}mv^2-0,\\122=\frac{1}{2}\cdot 1.6\cdot v^2,\\v^2=152.5,\\v\approx \boxed{12.35\:\mathrm{m/s}}\)

Answer:

general steps of performing an autopsy:

1. The body is identified and the relevant information about the deceased is collected.

2. A visual examination of the body is performed to look for any abnormalities or signs of injury.

3. The external examination is followed by an internal examination. The body is opened up to examine the organs, including the brain, heart, lungs, liver, and kidneys, for any signs of disease or injury.

4. The organs are weighed, measured and dissected.

5. Tissue samples are taken and sent for laboratory analysis.

6. The cause of death is determined based on the autopsy findings, and a report is generated.

7. The body is then closed and prepared for release to the family for funeral arrangements.

It is important to note that the specific steps involved may vary depending on the type of autopsy being conducted and the circumstances surrounding the death.

Explanation:

Answer:

It will take 2.94 s to run 40 meters starting from rest.

Explanation:

Given that,

Initial speed of cheetah, u = 0

Final speed of cheetah, v = 26.8 m/s

Time, t = 2.9 s

We need to find how long will it take a cheetah to run 40 meters.

First finding acceleration of cheetah ,

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{26.8-0}{2.9}\\\\a=9.24\ m/s^2\)

Let it will take t seconds. So, using second equation of motion to find it.

\(d=ut+\dfrac{1}{2}at^2\\\\40=0+\dfrac{1}{2}\times 9.24t^2\\\\40=0+4.62t^2\\\\t^2=\dfrac{40}{4.62}\\\\t=2.94\ s\)

So, it will take 2.94 s to run 40 meters starting from rest.

The magnitude of the displacement is 1,097.7 mi, and the angle is 89.9°

To find the displacement from Dallas to Chicago, we can break down the vectors representing the distances and directions into their x and y components. Since the Earth is modeled as flat, we can use basic trigonometry to calculate the components.

Let's start by considering the vector from Dallas to Atlanta. The magnitude of this vector is given as 730 miles, and the direction is 5.00° north of east. To calculate the x and y components, we can use the following equations:

Substituting the values:

x = 730 * cos(5.00°)

y = 730 * sin(5.00°)

Similarly, for the vector from Atlanta to Chicago, with a magnitude of 560 miles and a direction 21.0° west of north:

x = magnitude_AC * sin(angle_AC)

y = magnitude_AC * cos(angle_AC)

Substituting the values:

x = 560 * sin(21.0°)

y = 560 * cos(21.0°)

To find the displacement from Dallas to Chicago, we can sum the x and y components:

Now, we can calculate the magnitude and direction of the displacement using these x and y components:

magnitude_displacement = √(x_displacement² + y_displacement²)

angle_displacement = atan(y_displacement / x_displacement)

Finally, we can substitute the calculated values and solve for the magnitude and direction:

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The total resistance in the circuit is 30 ohms. Option d is correct.

In an electric circuit, resistors can be connected in different ways, such as in series or parallel. When resistors are connected in series, the total resistance is equal to the sum of the individual resistances. This is because the same current flows through each resistor, and the total voltage across the resistors is divided among them.

The resistances in series is the sum of all resistances. The three resistances are, 10 ohms, 15 ohms and 5 ohms. Therefore,

Total Resistance = 10 ohms + 15 ohms + 5 ohms = 30 ohms.

Hence, option d is correct.

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The size of the angle θ of a point object moving from point A to point B along a circular path is 2πR / L.

To understand this, consider a simple example. Suppose that a point object that moves from point A to point B along a circular path with a radius of 1 meter. The distance between points A and B is also 1 meter. Therefore, the size of the angle θ is equal to 2π × 1 / 1 = 2π radians.

In general, the size of the angle θ = ratio of the circumference of the circle to the distance between points A and B. The circumference of the circle is equal to 2πR, where R = radius of the circle. Therefore, the size of the angle θ is equal to 2πR / L.

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Complete question:

A point object moves from point A to point B along a circular path with a radius R. What is the size of the angle θ?

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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The terminal velocity of the sphere is approximately 22.68 mph.

The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:

Fd = (1/2) * rho * Cd * A * v²

where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.

The gravitational force pulling the sphere down is given by:

Fg = m * g

where m is the mass of the sphere and g is the acceleration due to gravity.

At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:

Fd = Fg

Substituting the expressions for Fd and Fg and solving for v, we get:

v = √((2 * m * g) / (rho * Cd * A))

where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.

Plugging in the given values, we get:

v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s

To convert this to mph, we multiply by 2.23694:

v ≈ 22.68 mph

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Answer:

hydrogen, helium, lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine, neon, sodium, magnesium, aluminum, silicon, phosphorus, sulfur, chlorine, argon, potassium, calcium, scandium, titanium, vanadium, chromium, maganese, iron, cobalt, nickel, copper, zinnc, gallium, germanium, aresnic, selenium, bromine, krypton, rubidium, strongtium, yttrium, zirconium, niobium, molybdenum, technetium, ruthenium, rhodium, palladium, silver, cadmium, indium, tin, atimony, tellurium, iodine, xenon, cesium, barium, lanthanum, cerium, praseodyumium, neodymim, promethium, samarium, europium, gadolinium, terbium, dysprosium, holmium, erbium, thulium, ytterbium, luteium, hafnium, tantalum, tungsten, rhenium, osmium, irdium, platinum, gold, mercury, thallium, lead bismuth, polnium, astatine, radon, rancium, radium, actinum, thorium, protactinium

Explanation:

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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Answer:

false

Explanation:

Answer:

false

Explanation:

edge

Answer:

Heat content

Explanation:

Heat doesnt need an object to be large or small, for example a lump of coal is hotter and smaller than a big piece of brick.

Answer:

B. the number of field lines on the source charge

Explanation:

As we know that electric flux is defined as the number of electric field lines passing through a given area.

So here  electric flux due to a point charge "q" is given by

so here we know that flux depends on the magnitude of charge and hence we can say that number of filed lines originating from a point charge will depends on the magnitude of the charge.

The factor indicates the amount of charge on the source charge is the number of field lines on the source charge.

The electric flux is defined as the number of electric field lines passing through a given area.

The electric flux due to a point charge q is given by the number of filed lines through particular closed area.

We know that flux depends on the magnitude of charge and number of field lines starting from a point charge will depends on the magnitude of the charge.

Thus, the correct option is B.

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The final speed of cart 2 is -1.0 m/s, and the final speed of cart 3 is 0.5 m/s.

To find the final speeds of cart 2 and cart 3 after the collision, we can use the principles of conservation of momentum and kinetic energy.

Given:

Mass of cart 1 (approaching cart): m = 0.20 kg

Initial velocity of cart 1: v0 = 1.5 m/s

Mass of cart 2: 2m

Mass of cart 3: 3m

Let's denote the final velocities of cart 2 and cart 3 as v2 and v3, respectively.

According to the conservation of momentum, the total momentum before the collision should be equal to the total momentum after the collision.

Initial momentum = Final momentum

(m * v0) + (2m * 0) + (3m * 0) = m * v2 + 2m * v3 + 3m * v3

Simplifying the equation, we have:

m * v0 = m * v2 + 5m * v3    ...(1)

Since the collision is elastic, the total kinetic energy before the collision should be equal to the total kinetic energy after the collision.

Initial kinetic energy = Final kinetic energy

(1/2) * m *\(v0^2 = (1/2) * m * v2^2 + (1/2) * 2m * v3^2 + (1/2) * 3m * v3^2\)

Simplifying the equation, we have:

(1/2) * m *\(v0^2 = (1/2) * m * v2^2 + m * v3^2 + (3/2) * m * v3^2\)

m * \(v0^2 = m * v2^2 + 2m * v3^2 + 3m * v3^2\)

\(v0^2 = v2^2 + 2v3^2 + 3v3^2\)    ...(2)

Now, we have two equations (equation 1 and equation 2) with two unknowns (v2 and v3). We can solve these equations simultaneously to find the values of v2 and v3.

From equation 1, we can rewrite it as:

v2 = v0 - 5v3

Substituting this expression into equation 2, we get:

\(v0^2 = (v0 - 5v3)^2 + 2v3^2 + 3v3^2\)

Expanding and simplifying the equation, we have:

\(v0^2 = v0^2 - 10v0v3 + 25v3^2 + 2v3^2 + 3v3^2\)

\(0 = -10v0v3 + 30v3^2\)

Rearranging the equation, we get:

10v0v3 = 30\(v3^2\)

v0 = 3v3

Solving for v3, we find:

v3 = v0/3 = (1.5 m/s) / 3 = 0.5 m/s

Substituting this value of v3 back into the expression for v2, we have:

v2 = v0 - 5v3 = 1.5 m/s - 5 * 0.5 m/s = 1.5 m/s - 2.5 m/s = -1.0 m/s

Therefore, the final speed of cart 2 is -1.0 m/s (indicating it moves in the opposite direction with respect to the initial velocity), and the final speed of cart 3 is 0.5 m/s.

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The formula for determining the gravitational potential energy of the balloon is expressed as

Energy = mgh

where

m is the mass of the ballon

g is the accelaration due to gravity and the value is 9.8m/s^2

h is the height of the balloon above the ground

From the information given,

m = 371

h = 615

Thus,

= 371 x 89.8 x615 = 22316017 NKJoulesJoules8298.651

The change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

The given parameters;

The initial area of the copper wire;

\(A_1 = \frac{\pi d^2}{4} = \frac{\pi \times (0.004)^2}{4} =1.257\times 10^{-5} \ m^2\)

The final area of the copper wire;

\(A_2 = \frac{\pi d^2}{4} = \frac{\pi (0.001)^2}{4} = 7.86\times 10^{-7} \ m^2\)

The initial drift velocity of the electrons is calculated as;

\(v_d_1 = \frac{I}{nqA_1} \\\\v_d_1 = \frac{4\times 10^{-3} }{8.5\times 10^{28} \times 1.6\times 10^{-19} \times 1.257\times 10^{-5}} \\\\v_d_1 = 2.34 \times 10^{-8} \ m/s\)

The final drift velocity of the electrons is calculated as;

\(v_d_2 = \frac{I}{nqA_2} \\\\v_d_2 = \frac{4\times 10^{-3} }{8.5\times 10^{28} \times 1.6\times 10^{-19} \times 7.86\times 10^{-7}} \\\\v_d_2 = 3.74\times 10^{-7} \ m/s\)

The change in the mean drift velocity is calculated as;

\(\Delta v = v_d_2 -v_d_1\\\\\Delta v = 3.74\times 10^{-7} \ m/s \ -\ 2.34 \times 10^{-8} \ m/s = 3.506\times 10^{-7} \ m/s\)

The time of motion of electrons for the initial wire diameter is calculated as;

\(t_1 = \frac{L}{v_d_1} \\\\t_1 = \frac{2}{2.34\times 10^{-8}} \\\\t_1 = 8.547\times 10^{7} \ s\)

The time of motion of electrons for the final wire diameter is calculated as;

\(t_2 = \frac{L}{v_d_1} \\\\t_2= \frac{2}{3.74 \times 10^{-7}} \\\\t_2 = 5.348 \times 10^{6} \ s\)

The average acceleration of the electrons is calculated as;

\(a = \frac{\Delta v}{\Delta t} \\\\a = \frac{3.506 \times 10^{-7} }{(8.547\times 10^7)- (5.348\times 10^6)} \\\\a = 4.38\times 10^{-15} \ m/s^2\)

Thus, the change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

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Answer:

The change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

The given parameters;

Current flowing in the wire, I = 4.00 mA

Initial diameter of the wire, d₁ = 4 mm = 0.004 m

Final diameter of the wire, d₂ = 1 mm = 0.001 m

Length of wire, L = 2.00 m

Density of electron in the copper, n = 8.5 x 10²⁸ /m³

The initial area of the copper wire;

The final area of the copper wire;

The initial drift velocity of the electrons is calculated as;

The final drift velocity of the electrons is calculated as;

The change in the mean drift velocity is calculated as;

The time of motion of electrons for the initial wire diameter is calculated as;

The time of motion of electrons for the final wire diameter is calculated as;

The average acceleration of the electrons is calculated as;

Thus, the change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

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Explanation:

Answer:

yes

Explanation:

and also no

Answer:

yep

Explanation:

Answer:

-20,000N

Explanation:

Force (N) = mass (kg) x acceleration (m/s²)

So,

Force = 2000 x -10

= -20,000N (Newtons)

The correct answer is : Planet X, because the sun pulls it with a greater force

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Answer: A A A !!!!  

Explanation: just did the test, got it right thx thx!!!

When a butane lighter is lit, chemical energy transforms into heat energy.

Energy cannot be created or destroyed, says the law of conservation of energy. However, it has the ability to change its form. The total energy of an isolated system is constant when all sources of energy are taken into account.

The chemical energy is the bonds of chemical molecules contain energy. Exothermic reactions are those in which chemical energy is released during the reaction, frequently in the form of heat.

In butane energy is stored as a chemical energy as  bonds of chemical molecules and when it is lit, the chemical energy of the butane transforms into heat energy.

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Answer:

5 m/s

Explanation:

5000/1000=5 m/s

:))

Answer:

A. 9280.78 moles.

B. 37123.12 g.

Explanation:

We'll begin by calculating the volume of the spherical balloon. This can be obtained as follow:

Diameter (d) = 6 m

Radius (r) = d/2 = 6/2 = 3 m

Pi (π) =3.14

Volume (V) =?

V = 4/3πr³

V = 4/3 × 3.14 × 3³

V = 4/3 × 3.14 × 27

V = 113.04 m³

Next, we shall convert 20°C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 20°C

T(K) = 20°C + 273

T(K) = 293 K

Next, we shall convert 200 KPa to Pa. This can be obtained as follow:

1 KPa = 1000 Pa

Therefore,

200 KPa = 200 KPa × 1000 Pa / 1 KPa

200 KPa = 2×10⁵ Pa

A. Determination of the number of mole of He in the spherical balloon.

Volume (V) = 113.04 m³

Temperature (T) = 293 K

Pressure (P) = 2×10⁵ Pa

Gas constant (R) = 8.314 m³Pa/Kmol

Number of mole (n) =?

PV = nRT

2×10⁵ × 113.04 = n × 8.314 × 293

22608000 = n × 2436.002

Divide both side by 2436.002

n = 22608000 / 2436.002

n = 9280.78 moles

B. Determination of the mass of He.

Mole of He (n) = 9280.78 moles

Molar mass of He = 4 g/mol

Mass of He =?

Mass = mole × molar mass

Mass of He = 9280.78 × 4

Mass of He = 37123.12 g