Answers
Answer:
the car has greater momentum.
the car has greater kinetic energy.
Explanation:
FOR MOMENTUM:
Momentum is given as the product of mass and velocity of an object:
\(P = mv\)
where,
P = momentum
m = mass
v = velocity
For Truck:
\(P_{truck} = (3530\ kg)(21\ m/s)\\P_{truck} = 74130 Ns\)
For Car:
\(P_{car} = (1620\ kg)(54\ m/s)\\P_{car} = 87480\ Ns\)
Therefore, car has greater momentum.
FOR KINETIC ENERGY:
Kinetic Energy is given as:
\(K.E = \frac{1}{2} mv^{2}\)
where,
K.E = Kinetic Energy
m = mass
v = velocity
For Truck:
\(K.E_{truck} = \frac{1}{2} (3530\ kg)(21\ m/s)^{2}\\K.E_{truck} = 778365\ J = 778.36\ KJ\)
For Car:
\(K.E_{truck} = \frac{1}{2} (1620\ kg)(54\ m/s)^{2}\\K.E_{truck} = 2361960\ J = 2361.96\ KJ\)
Therefore, car has greater kinetic energy.
Related Questions
If one pound of force acts through a distance of two feet, one foot-pound of work is done.
True
False
Answers
It is false that if one pound of force acts through a distance of two feet, one foot-pound of work is done.
What is work?Work is a measure of energy expended in moving an object. It is most commonly calculated by multiplying the force by distance.
It is said that no work is done if the object does not move.
According to this question, if one pound of force acts through a distance of two feet, a work of one pound-two feet is done.
It is therefore, false that if one pound of force acts through a distance of two feet, one foot-pound of work is done.
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Consider the arrangement shown in the figure below where R = 8.50 Ω, ℓ = 1.10 m, and B = 2.00 T. A vertical bar and two parallel horizontal rails lie in the plane of the page, in a region of uniform magnetic field, vector B, pointing into the page. The parallel rails run from left to right, with one a distance ℓ above the other. The left ends of the rails are connected by a vertical wire containing a resistor R. The vertical bar lies across the rails to the right of the wire. Force vector Fapp points from the bar toward the right. HINT (a) At what constant speed (in m/s) should the bar be moved to produce a current of 1.70 A in the resistor? (b) What power (in W) is delivered to the resistor? W (c) What magnetic force (in N) is exerted on the moving bar? (Enter the magnitude.) N (d) What instantaneous power (in W) is delivered by the force Fapp on the moving bar?
Answers
The velocity of the conducting bar is 6.6 m/s.
Resistance, R = 8.5 Ω
Length of the bar, l = 1.1 m
Magnetic field, B = 2 T
Current in the bar, I = 1.7 A
The expression for motional emf is given by,
ε = B x l x v
where v is the velocity of the conducting bar.
a) Applying Ohm's law,
I x R = Blv
Therefore, v = IR/Bl
v = 1.7 x 8.5/(2 x 1.1)
v = 6.6 m/s.
b) Power delivered to the resistor,
P = (Blv)²/R = (2 x 1.1 x 6.6)²/8.5
P = 24.8 W
c) Force exerted on the bar,
F(ext) = B²l²v/R = (2 x 1.1)²x 6.6/8.5
F(ext) = 3.75 N
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In a compound microscope, the objective has a focal length of 1.0 cm, the eyepiece has a focal length of 2.0 cm, and the tube length is 25 cm. What is the magnitude of the overall magnification of the microscope?
Answers
Answer:
m = 312.5
Explanation:
Given that,
The focal length of the objecive lens, \(f_o=1\ cm\)
The focal length of eye piece, \(f_e=2\ cm\)
length of the tube, L = 25 cm
We need to find the magnitude of the overall magnification of the microscope. It is given by the formula as follows :
\(m=\dfrac{L}{f_o}\times \dfrac{D}{f_e}\)
D = 25 cm
So,
\(m=\dfrac{25}{1}\times \dfrac{25}{2}\\\\m=312.5\)
So, the overall magnification of the microscope is 312.5.
What is the formula to calculate the thickness of a test tube?
Answers
Answer:
Having the inside dimensions (ID) and the outside dimensions (OD) will allow you to figure out the wall thickness on tubing. You would need to subtract the ID from the OD and then divide by two. This number is the wall thickness.
Explanation:
An ice skater is moving in a circle at a constant speed. Which of the following best explains the forces acting on the ice skater.
Please give answer I’ll give brainiest
A. Ice skater is moving so the forces acting on her must be unbalanced
B.the ice skater has a constant speed so the forces acting on her must be unbalanced
C. The ice skater had a changing cellos the forces acting on her must be unbalanced
D.not enough information to answer the question
Answers
d. Two point charges, q1 = +25 nC and q2 = -75 nC, are separated by a distance of 3.0 cm. Find the magnitude and direction of; i. the electric force q1 exerts on q2 [5] ii. the force that q2 exerts on q1 [4] (take k = 9.0 x 109 N.m2 /C2 )
Answers
Answer:
a) F₂₁ = 0.02 N, attracting.
b) F₁₂ = 0.02 N, attracting.
Explanation:
a)
The magnitude of the force that q₁ exerts on q₂ (F₂₁) is given by Coulomb's Law, as follows:\(F_{21} = k * \frac{q_{1} *q_{2}}{r_{12}^{2} } = 9e9 N.m2/C2 * \frac{(25e-9C)*(75e-9C)}{(0.03m)^{2}} = 0.02 N (1)\)
Since q₁ and q₂ have opposite signs, the force between them will be always attractive, i.e., from q₂ towards q₁, along the line that joins both charges.b)
The magnitude of the force on q₁ due to q₂ can be obtained applying Newton's 3rd Law, or using (1), because all parameters are the same, so F₁₂ (in magnitude) = F₂₁ = 0.02 NAs we have already said, it must be opposite to the one found in a) so it must go from q₁ towards q₂, it is an attracting force also.A 23900N/C electric field points down. What is the value of a charge placed in the field if it experiences a force of 7520N up?
Answers
Answer:
0.315C
Explanation:
Force/Electric field
7520N/23900C
if constant positive acceleration s-t graph represents (A)balanced forces (B)unbalanced forces
Answers
Answer:
Graph b is correct
Explanation:
write down the value of
920 kg in g
Answers
Answer:
920000
Explanation:
Each kg contains 1,000 grams
why ultrasonic sound waves can pass through hard objects?
Answers
Answer: At such high frequencies it is very difficult for a sound wave to propagate efficiently; indeed, above a frequency of about 1.25 × 1013 hertz it is impossible for longitudinal waves to propagate at all, even in a liquid or a solid
A 5kg monkey is running with a velocity of 5 m/s to the right
Answers
The momentum of the monkey of mass 5 kg is 25 kgm/s.
What is Momentum?Momentum is the product of mass and velocity.
To calculate the momentum of the monkey, we use the formula below.
Formula:
M = mv..................... Equation 1Where:
M = Momentum of the monkeym = Mass of the monkeyv = Velocity of the monkeyFrom the question,
Given:
m = 5 kgv = 5 m/sSubstitute these values into equation 1
M = 5×5M = 25 kgm/sHence, the momentum of the monkey is 25 kgm/s.
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Complete question: A 5kg monkey is running with a velocity of 5 m/s to the right. Find the momentum of the monkey
Demario's biology class has a quiz every other Friday. This is the third time Demario has been so worried about other personal matters that he hasn’t done quite as well on the quizzes as he might have otherwise. What has Demario upset is the fact that the professor leaves the room while the students take the quiz, and over half the class is taking the opportunity to cheat. Demario knows personally several of the other students in the class, and some of the ones Demario hangout with are among those who are cheating. Demario knows that a failure to speak to the professor about the cheating will result in his own grade being lower, since the school grades on the curve system. But if Demario does say something to the professor he will be doing his friends and the others a great harm, since cheating is taken very seriously at the school and can lead to expulsion. If Demario doesn’t “turn in” the classmates, the only other alternative is he will get a worse grade than he deserves. He will also be labled as a snitch among is peers and a cheater at the school, either of which Demario has never done. Further, if the professor somehow discovers that Demario is hiding the cheating of others, Demario will be considered an accessory to the cheating, and may be reprimanded for not turning others in, since the school operates on an honor system.
Critical thinking About Ethics Right vs Wrong
What should Demario do?
Should Demario cheat?
Should Demario turn in the cheating classmates?
Should Demario say nothing and not cheat himself?
Be specific in your answer about exactly what Demario should do. (Remember to use one of the three moral theories to solve this dilemma.)
Answers
1. It is unethical for Demario to cheat
2. Demario should not engage in cheating himself
3. Demario should not turn in cheating classmates without careful consideration
4. Reporting classmates may harm relationships, create animosity, and potentially lead to severe disciplinary actions.
What is ethics?A virtue ethics perspective may also be useful in this circumstance. Demario should make an effort to respect moral principles like honesty, fairness, and integrity while taking the potential repercussions into account and exhibiting empathy for his fellow students.
By employing this strategy, Demario behaves responsibly, deals with the problem subtly, encourages fairness in the educational setting, and upholds his or her own moral standards.
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A 100-n object and a 50-n object are placed on scales a and b respectively inside an elevator ascending with constant velocity 3.0m/s which statement below correctly describes the readings on the scales inside the elevator
Answers
Answer: b
Explanation:
The reading of the scale of the elevator ascending with constant velocity is 150 N.
Reading of the scale
The reading of the scale on the elevaor is calculated by applying Newton's second law of motion;
R = m(a + g)
R = ma + mg
R = F + W
where;
a is the acceleration of the objectsAt constant velocity, the acceleration of the object is zero (0).
R = 0 + 100 + 50
R = 150 N
Thus, the reading of the scale of the elevator ascending with constant velocity is 150 N.
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since the time of hubble, astronomers have learned that the blue color observed in some galaxies is the result of recent star formation. the blue regions can be seen in the following figure, where the color differences are schematically depicted. this interpretation has been confirmed by multiwavelength observations that have revealed the presence of star-forming gas clouds in galaxies hosting newly formed o-and b-type stars. sort the galaxy types according to their level of star-forming activity.
Answers
Many of the properties of galaxies (including the galaxy color–magnitude diagram) indicate that there are fundamentally two types of galaxies. These groups divide into blue star-forming galaxies that are more like spiral types, and red non-star forming galaxies that are more like elliptical galaxies.
In a spiral galaxy the interstellar medium makes up 3 to 5 percent of the galaxy’s mass, but within a spiral arm its mass fraction increases to about 20 percent. Spiral galaxies—of which the Milky Way system is a characteristic example—tend to be flattened, roughly circular systems with their constituent stars strongly concentrated along spiral arms.Elliptical galaxies have roundish shapes rather than the flattened distributions that characterize spiral galaxies, and they tend to occur in rich clusters (those containing thousands of members) rather than in the loose groups favoured by spirals. These systems exhibit certain characteristic properties. They have complete rotational symmetry; i.e., they are figures of revolution with two equal principal axes.
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what are the limiting and excess reactants to CO(g) + 2H2 - CH3OH if 1.55 moles of CO react with 1.22 moles of H2
Answers
CO + 2(H2) ----- CH3OH, this is the reaction we obtaine, now based on moles we have to find what hapen if we change the moles
1.55(CO) + 1.22(H2) ---- n(CH3) + m(OH)
We have:
1.55 C
1.55 O
2.44 H
And we need:
1 C
1 O
4 H
The difference are:
0.55 C, excess
0.55 O, excess
1.56 H, limiting
Potential energy results from the _ or position of an object
Answers
Answer:
The only answers I can think of are state or arrangement. Any of these two should be theoretically correct.
The potential energy is the energy that is stored in an object due to its position.
What is potential energy ?The term potential energy is defined as the stored energy tha depend on the various parts of the system. Any object that is stretched from its resting position has stored energy. As a result, it is known as potential energy because it has a potential to do work when it lifted.
The formula of the potential energy is depending on the force of two object. P.E. = mgh
An object possesses gravitational potential energy if it is placed at a height above or below the zero height. The potential energy is the energy that is stored in an object.
Thus, The potential energy is the energy that is stored in an object due to its position.
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A rocket blasts off from rest and attains a speed of 33.9 m/s in 12.7 s. An astronaut has a mass of 65.1 kg. What is the astronaut's
apparent weight during takeoff?
Answers
The apparent weight of the astronaut of mass 65.1 kg moving with a speed of 33.9 m/s in 2.7 s is 811.797 N.
What is weight?Weight is the force with which a body is attracted toward the earth or a celestial body by gravitation and which is equal to the product of the mass and the local gravitational acceleration.
To calculate the astronaut's apparent weight, we use the formula below.
Formula:
W = m{[(v-u)/t]+g}............ Equation 1Where:
W = The apparent weight of the astronautm = Mass of the astronautv = Final speedu = Initial speedt = Timeg = Acceleration due to gravityFrom the question,
Given:
m = 65.1 kgv = 33.9 m/su = 0 m/s (from rest)t = 12.7 sg = 9.8 m/s²Substitute these values into equation 1
W = 65.1{[(33.9-0)/12.7]+9.8]W = 65.1×12.47W = 811.797 NHence, the apparent weight of the astronaut is 811.797 N.
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Interactive Solution 8.29 offers a model for this problem. The drive propeller of a ship starts from rest and accelerates at 2.38 x 10-3 rad/s2 for 2.04 x 103 s. For the next 1.48 x 103 s the propeller rotates at a constant angular speed. Then it decelerates at 2.63 x 10-3 rad/s2 until it slows (without reversing direction) to an angular speed of 2.42 rad/s. Find the total angular displacement of the propeller.
Answers
Answer:
Δθ = 15747.37 rad.
Explanation:
The total angular displacement is the sum of three partial displacements: one while accelerating from rest to a certain angular speed, a second one rotating at this same angular speed, and a third one while decelerating to a final angular speed.Applying the definition of angular acceleration, we can find the final angular speed for this first part as follows:\(\omega_{f1} = \alpha * \Delta t = 2.38*e-3rad/s2*2.04e3s = 4.9 rad/sec (1)\)
Since the angular acceleration is constant, and the propeller starts from rest, we can use the following kinematic equation in order to find the first angular displacement θ₁:\(\omega_{f1}^{2} = 2* \alpha *\Delta\theta (2)\)
Solving for Δθ in (2):\(\theta_{1} = \frac{\omega_{f1}^{2}}{2*\alpha } = \frac{(4.9rad/sec)^{2}}{2*2.38*e-3rad/sec2} = 5044.12 rad (3)\)
The second displacement θ₂, (since along it the propeller rotates at a constant angular speed equal to (1), can be found just applying the definition of average angular velocity, as follows:\(\theta_{2} =\omega_{f1} * \Delta_{t2} = 4.9 rad/s * 1.48*e3 s = 7252 rad (4)\)
Finally we can find the third displacement θ₃, applying the same kinematic equation as in (2), taking into account that the angular initial speed is not zero anymore:\(\omega_{f2}^{2} - \omega_{o2}^{2} = 2* \alpha *\Delta\theta (5)\)
Replacing by the givens (α, ωf₂) and ω₀₂ from (1) we can solve for Δθ as follows:\(\theta_{3} = \frac{(\omega_{f2})^{2}- (\omega_{f1}) ^{2} }{2*\alpha } = \frac{(2.42rad/s^{2}) -(4.9rad/sec)^{2}}{2*(-2.63*e-3rad/sec2)} = 3451.25 rad (6)\)
The total angular displacement is just the sum of (3), (4) and (6):Δθ = θ₁ + θ₂ + θ₃ = 5044.12 rad + 7252 rad + 3451.25 rad ⇒ Δθ = 15747.37 rad.The power of a wave comes from the wave's ..
Answers
Answer:
waves energy i think
Explanation:
A toy car is given an initial velocity of 5.0 m/s and experiences a constant acceleration of 2.0 m/s.
What is the final velocity after 8.0
Answers
The NEC states the resistance of 4/0 coated
copper conductors is 0.0626 ohms per 1000
feet. What would be the total resistance of the
three 4/0 conductors installed in parallel, if the
total length for each of the three conductors is
323 feet?
Answers
Answer:
The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.
Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:
Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet
To find the total resistance when the conductors are in parallel, we use the formula:
1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3
Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)
Substituting the values, we get:
Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))
Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.
The __________________ is the entire range of Electromagnetic Waves.
Absorption
Opaque
Electromagnetic Spectrum
Refraction
✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧
Answers
Answer:
I think its the electromagnetic spectrum
A uniform solid cylindrical flywheel has a mass of 50 kg and a radius of 40 cm. The flywheel begins to rotate faster with an acceleration of 1.5 rad/s2. The kinetic energy of the flywheel after 1 minute of rotation is:
A. 16.2 KJ
B. 180 KJ
C. 40.5 KJ
D. 32.4 KJ
Answers
The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)
How do I determine the kinetic energy?We'll begin by obtaining the velocity of the flywheel. This is shown below:
Radius (r) = 40 cm = 40 / 100 = 0.4 mAcceleration (a) = 1.5 rad/s² = 1.5 × 0.4 = 0.6 m/s²Time (t) = 1 minute = 1 × 60 = 60 sVelocity (v) = ?v = at
v = 0.6 × 60
v = 36 m/s
Finally, we shall determine the kinetic energy of the flywheel. Details below:
Mass (m) = 50 KgVelocity (v) = 36 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 50 × 36²
KE = 25 × 1296
KE = 32400 J
Divide by 1000 to express in KJ
KE = 32400 / 1000
KE = 32.4 KJ
Thus, the kinetic energy is 32.4 KJ (Option D)
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A 1.0 kg cube of ice is dropped into 1.0 kg of water, and when equilibrium is reached, there are 2.0 kg of ice at 0.0° C. The initial temperature of the water was 0°C. What was the original temperature of the ice? (Cw = 4186 J/kgo°C, c; = 2093 J/kg.°C, and If = 3.3 × 105 J/kg)
Answers
The initial temperature of the water was 0°C and the original temperature of the ice was -78.8°C.
First, we need to determine how much heat was transferred from the water to the ice to melt the ice and raise its temperature to 0°C.
The heat is required to melt the ice will be;
Q₁ = m_ice x Lf
where m_ice is the mass of the ice and\(L_{f}\) is the latent heat of fusion of ice.
Q₁ = 1.0 kg x 3.3 x 10⁵ J/kg
= 3.3 x 10⁵ J
The heat required to raise the temperature of the melted ice from -x°C to 0°C is;
Q₂ = m_ice x c_ice x ΔT
where c_ice is the specific heat capacity of ice and ΔT is the change in temperature.
Q₂ = 1.0 kg x 2093 J/kg.°C x (0 - (-x))°C
= 2093x J
The heat lost by the water will be equal to the heat gained by the ice;
Q₁ + Q₂ = m_water x Cw x ΔT
where m_water is the mass of the water and Cw is the specific heat capacity of water.
3.3 x 10⁵ J + 2093x J = 1.0 kg x 4186 J/kg.°C x (0 - T)°C
Solving for T, we get;
T = -[(3.3 x 10⁵ J + 2093x J)/(4186 J/kg.°C)]
= -78.8°C
Therefore, the original temperature of the ice was -78.8°C.
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Your car gets a flat! You go from 90 kilometers per hour to a stop in 6 seconds. What is your rate of deceleration? (it's negative!) I need this asap help
Answers
Answer:
at a rate of deceleration of -15 kilometers per second
Explanation:
90/6=15
The rate of deceleration when a car goes from 90km/h to 0 in 6 seconds is 4.16m/s².
HOW TO CALCULATE DECELERATION?The rate of deceleration can be calculated by using the following formula:
d = v - u/t
Where;
d = deceleration (m/s²)v = final velocity = 90km/h = 25m/su = initial velocity = 0km/h = 0t = time (s)d = 25 - 0/6
d = 4.16m/s²
Therefore, the rate of deceleration when a car goes from 90km/h to 0 in 6 seconds is 4.16m/s².
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34. [8 Marks] A spring is compressed with a 5.0 kg mass by 20.0 cm from its equilibrium position. When the spring is released, the 5.0 kg mass travels along a smooth horizontal surface and then up a frictionless plane at 30° to the horizontal. Calculate the distance it would travel up the inclined plane before coming back down again.
Answers
Answer and Explaination:
To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.
1. Gravitational force:
The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.
2. Force exerted by the spring:
The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.
Given:
Mass (m) = 5.0 kg
Compression of the spring (x) = 20.0 cm = 0.20 m
Angle of the inclined plane (θ) = 30°
First, let's find the force exerted by the spring (F_spring):
F_spring = -kx
To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.
Next, let's calculate the gravitational force components:
Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ
Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ
Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.
At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).
Therefore, we have:
F_perpendicular = F_spring
mg * cosθ = -kx
Now, let's substitute the known values and solve for k:
(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m
49.0 N * 0.866 = -k * 0.20 m
42.426 N = -0.20 k
k = -42.426 N / (-0.20 m)
k = 212.13 N/m
Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:
PE_spring = (1/2) * k * x^2
PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2
PE_spring = 4.243 J
The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.
KE_max = PE_spring = 4.243 J
Next, we can calculate the height (h) the mass reaches on the inclined plane:
KE_max = m * g * h
4.243 J = 5.0 kg * 9.8 m/s^2 * h
h = 4.243 J / (5.0 kg * 9.8 m/s^2)
h = 0.086 m
The height the mass reaches on the inclined plane is 0.086 m.
Now, we can calculate the distance traveled.
A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.
Given data: Mass of the object, m = 5.0 kg, Displacement of the spring, x = 20.0 cm = 0.20 mAngle of the inclined plane, θ = 30°Calculating the spring constant, k. Using Hooke’s Law; F = -kx Where F is the restoring force required to bring the spring back to its equilibrium position.From the equation, F = ma For the object attached to the spring,m * a = -kx. On integrating,∫ma dt = -∫kx dt .On integrating the left side with limits from 0 to t and right side with limits from 0 to x, where the limits on the left are for acceleration and the right are for the displacement of the spring; mv - mu = -½ kx²At maximum compression, the velocity of the mass is zero, i.e., v = 0 and the initial velocity is also zero. Therefore, mv - mu = -½ kx²0 - 0 = -½ k (0.20)²∴ k = 25 N/mWork done on the spring in compressing it, W = ½ kx² = 0.5 * 25 * (0.20)² = 0.5 JSince the inclined plane is frictionless, the only force acting on the object will be the component of its weight acting along the plane. Hence, it will move up the incline with an acceleration of, a = g sin θ = 9.8 * sin 30° = 4.9 m/s²When the object has reached its maximum height, its velocity will be zero. Using the equation of motion; v² - u² = 2as0 - u² = 2as∴ s = u² / 2a. Now, the initial velocity of the object up the incline is,u = √(2gH)Where H is the height to which it climbs, and is given by, H = W / m g Where W is the work done on the object in lifting it to height H, and m is the mass of the object. W = 0.5 J, m = 5 kg. So, H = 0.5 / (5 * 9.8) = 0.0102 m∴ u = √(2gH) = √(2 * 9.8 * 0.0102) = 0.4525 m/sNow, the distance traveled by the object up the incline is,s = u² / 2a = (0.4525)² / (2 * 4.9) = 0.0214 m. When the object comes back down, it will travel the same distance down the incline, before coming to rest. Therefore, the total distance travelled up and down the incline is,2s = 2 * 0.0214 = 0.0428 m.For more questions on the spring constant
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What is the result of two displacement vectors having opposite directions? Question 6 options: The resultant is the sum of the two displacements, having the same direction as the smaller vector. The resultant is the sum of the two displacements, having the same direction as the larger vector. The resultant is the difference of the two displacements, having the same direction as the smaller vector. The resultant is the difference of the two displacements, having the same direction as the larger vector.
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The resultant of two displacement vectors having opposite directions is the difference of the two displacements, having the same direction as the smaller vector.
When two displacement vectors have opposite directions, it means they are pointing in opposite ways. In other words, one vector is in the opposite direction of the other. To find the resultant of these vectors, we need to subtract one vector from the other.
If we consider two displacement vectors, let's say vector A and vector B, and they have opposite directions, we can represent them as A and -B.
To find the resultant, we subtract vector B from vector A: A - (-B) or A + B.
The resultant will have the same direction as the smaller vector. This is because when we subtract a larger vector from a smaller vector, the resultant will have the direction of the smaller vector.
Therefore, the correct option is: "The resultant is the difference of the two displacements, having the same direction as the smaller vector."
For more such questions on displacement vectors.
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how would you define an ocean current?
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Answer:
i would describe an ocean current like a pull of the water
Explanation:
water
31.______
muscle is voluntary muscle that allows the body to move.
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Answer:
Brainliest pls?
Explanation:
Skeletal Muscle is voluntary muscle that allows the body to move.
Which graph shows the change in velocity of an object in free fall?
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Answer:
The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.
Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:
Free Fall Velocity Graph