The generalization can be made about the climate of these two areas which are-
because water warms and cools more slowly than land, Palm Coast, Florida, has much less seasonal changes.
in step with a generalisation about the weather of these locations, Palm Coast, Florida, has softer seasonal fluctuations than different components of the country because water warms and cools greater slowly than land.
what is Palm Coast, Florida?
normally speakme, Flagler County is wherein Palm Coast, Florida, is situated. In 2000, there had been 32,832 residents; as of the 2010 census, there had been seventy five,a hundred and eighty.
In conclusion, Palm Coast, Florida, has extra slow seasonal modifications than the alternative location due to the fact water warms and cools extra slowly than land.
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will give correct answer brainliest
Answer:
I THINK it’s A
Explanation:
Because all the other answers don’t make sense.
Is a car slowning down an exaple of acceleration
Answer:
No not at all. A car speeding up is an example of acceleration.
Answer:
No.
Explanation:
Its a example of decceleration because its slowing down not speeding up. If the car were to go faster then it would be an example of acceleration. Hope this helps :)
How many electrons are located in the outermost orbit in the bohr model of a boron atom?.
Electrons that are located in the outermost orbit in the Bohr model of a boron atom will be 3.
A nucleus with six neutrons and five protons makes up the Bohr model of boron. The K-shell and L-shell electron shells around the nucleus The valence electrons, which make up three of the electrons in the outermost shell of the Bohr diagram, are also present. The orbits of the electrons around the small nucleus are described by the Bohr model of boron.
It utilizes a number of different electron shells, including K, L, M, and N. The number of electrons that each shell can hold varies, with the shell closest to the nucleus having the least energy. The energy levels increase as the shell recedes more. According to the Bohr model, the electrons in an atom may be seen to orbit the nucleus in a variety of orbits with differing energies.
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How long would it take Jesse with an acceleration of -2.50 m/s^2 to bring his bicycle with an initial velocity of 13.5 m/s to a complete stop?
a.6.1 s
b.3.7 s
c.12.1 s
D.5.4 s
Answer:
use first equation of motion v=u+at..v is 0..since we have to take him to rest and u is 13.5
Explanation:
u = 13.5 m/s
a = - 2.5 m/s^2
v = u + at
0 = 13.5 - 2.5 * t
t (time to reach a complete halt) = 5.4 sec
You accidentally throw your car keys horizontally at 8.0 m/s from a cliff. If yours keys land 28 m from the base of the cliff, how high was the cliff? Question 10 options: 17.15 m 60 m 45 m 28 m
Answer:
\(45m\)
Explanation:
Let \(V_0\) be the horizontal speed of the keys and D be the horizontal distance covered by the keys.
\(V_0= 8.0 \frac ms\)
\(D= 28 m\)
The initial velocity in the vertical direction is \(0\).
Let \(g\) be the acceleration due to gravity, which always acts vertically downwards, so, it will not change the horizontal direction of the speed, i.e. \(V_0\) will remain constant throughout the projectile motion.
Let \(t\) be the total time of flight in seconds. So,
\(D= V_0t\)
\(\Rightarrow 28=8t\)
\(\Rightarrow t=3 s \; \cdots (i)\)
Let \(H\) be the hight of the cliff.
Now, from the equation of motion
\(s=ut+\frac 1 2 at^2\;\cdots(ii)\)
Where is the displacement is the direction of force, is the initial velocity in the direction of force, is the constant acceleration due to force and is the time of flight.
Here, , and (negative sign is for taking the sigh convention positive in the direction as shown in the figure.)
From equation (ii)
\(-H=0\times t + \frac 1 2 (-g)t^2\)
\(\Rightarrow H= \frac 1 2 gt^2\)
Take \(g= 10 \frac m{s^2}\) and put the value of \(t\) from equation (i), we have
\(H=\frac 1 2 \times 10\times 3^2\)
\(\Rightarrow H= 45 m\).
Hence, the height of the cliff was \(45 m\).
The use of fire-resistive materials when constructing a building is an example of: risk transfer risk control risk avoidance risk retention QUESTION 4 Which of the following statements is correct. 1. One of the pre-loss objectives of risk managers is to meet any legal requirements the company may face. II. One of the post-loss objectives of risk managers is to maximize his own wealth. I only II only Both I and II Neither I nor II
The correct statement is "I only." One of the pre-loss objectives of risk managers is to meet any legal requirements the company may face.
The use of fire-resistive materials when constructing a building is an example of risk control. This is because risk control involves taking proactive steps to reduce the likelihood or severity of loss when an incident occurs. Fire-resistive materials are designed to withstand fire, and they are meant to slow down or contain the spread of fire in a building, thus reducing the risk of loss or damage.
In risk management, risk control is one of the four basic methods used to handle or mitigate risks. The other methods include risk transfer, risk avoidance, and risk retention. Risk transfer involves shifting the risk of loss to another party, such as through insurance or contract agreements. Risk avoidance involves eliminating the activity that could lead to loss or harm, while risk retention involves accepting the risk and dealing with any losses that may occur. As for the second question, the correct statement is "I only."
One of the pre-loss objectives of risk managers is to identify, assess, and evaluate potential risks that could negatively affect an organization. They also work to develop strategies to manage these risks and to ensure that the company is meeting any legal or regulatory requirements. On the other hand, one of the post-loss objectives of risk managers is to minimize the impact of losses that occur. They work to evaluate the effectiveness of the company's risk management strategies and to ensure that the company recovers from the loss as quickly as possible. Maximizing the risk manager's wealth is not a post-loss objective of risk managers.
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A wave has a wavelength of 125 meters and is moving at a speed of 250 m/s. What is its frequency?
Answer:
0.16Hz
Explanation:
Given that:
wavelength (λ) = 125 meters
speed (V) = 20 m/s
frequency (F) = ?
Recall that frequency is the number of cycles the wave complete in one second. And its value depends on the wavelength and speed of the wave.
So, apply the formula V = F λ
Make F the subject formula
F = V / λ
F = 20 m/s / 125 meters
F = 0.16 Hz
Thus, the frequency of the wave is 0.16 Hertz.
true or false: the calorie used in physics and the calorie used in measuring the energy content of food are the same.
False. The calorie used in physics (also known as the "gram calorie" or "small calorie") is the amount of energy required to raise the temperature of one gram of water by one degree Celsius.
It is equal to 1,000 small calories and is the amount of energy required to raise the temperature of one kilogram of water by one degree Celsius.
The calorie used in measuring the energy content of food (also known as the "kilocalorie" or "large calorie") often abbreviated as "kcal", it represents the amount of energy obtained from the food when it is metabolized in the human body. So when we refer to "calories" on food labels or in discussions about nutrition, we are actually referring to kilocalories.
Therefore, the two units of measurement are not the same.
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Mars has two moons. What does the orbital speed of these moons depend on?
Answer:
their masses and their distances from Mars
Explanation:
Hope this helped
Also can u pls mark me brainliest
A fridge uses about 200 watts of power. This means that the fridge uses 200 joules per second of energy. If managed to turn 1 g of matter into energy, according to Einstein's equation E = mc², how long would I be able to power my fridge with that energy?
Answer:
Approximately \(4.50 \times 10^{11}\; {\rm s}\).
Explanation:
The speed of light is \(c \approx 3.00\times 10^{8}\; {\rm m\cdot s^{-1}}\).
Note that the standard unit of energy, joule, is a derived unit. In terms of the standard base units:
\(\begin{aligned}1\; {\rm J} &= (1\; {\rm N})\, (1\; {\rm m}) \\ &= (1\; {\rm kg \cdot m \cdot s^{-2}})\, (1\; {\rm m}) \\ &= 1\; {\rm kg \cdot m^{2} \cdot s^{-2}} \end{aligned}\).
Apply unit conversion and ensure that the unit of mass is in the standard unit kilogram (\({\rm kg}\)):
\(\begin{aligned} m &= 1\; {\rm g} \times \frac{1\; {\rm kg}}{10^{3}\; {\rm g}} &= 10^{-3}\; {\rm kg}\end{aligned}\).
Apply the equation \(E = m\, c^{2}\) to find the energy equivalent to \(m = 10^{-3}\; {\rm kg}\) of matter:
\(\begin{aligned}E &= m\, c^{2} \\ &= (10^{-3}\; {\rm kg})\, (3.00 \times 10^{8}\; {\rm m\cdot s^{-1}})^{2} \\ &= 9.00\times 10^{13}\; {\rm kg \cdot m^{2} \cdot s^{-2}} \\ &= 9.00\times 10^{13}\; {\rm J} \end{aligned}\).
Divide energy \(E\) by power \(P\) to find the duration \(t\) of the power consumption:
\(\begin{aligned} t &= \frac{E}{P} \\ &\approx \frac{9.00 \times 10^{13}\; {\rm J}}{200\; {\rm J \cdot s^{-1}}} \\ &= 4.50 \times 10^{11}\; {\rm s}\end{aligned}\).
In other words, the energy equivalent to \(1\; {\rm g}\) of matter could power this fridge for approximately \(4.50 \times 10^{11}\; {\rm s}\).
What is the acceleration of a 7 kg mass being pulled by a 56 N force?
Answer:
8 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
\(a = \frac{f}{m} \\ \)
m is the mass
f is the force
From the question we have
\(a = \frac{56}{7} \\ \)
We have the final answer as
8 m/s²Hope this helps you
What happens if there is no transformation of energy in the world ?
Answer:
If there were no transformation of energy in the world, everything would come to a standstill.
Explanation:
Energy is required for all processes and interactions to occur, including movement and chemical reactions. Without energy, matter would not be able to move or change in any way. This would mean that living organisms would not be able to survive, as they rely on energy to carry out metabolic processes and maintain their body's functions.
The sun would not shine, the wind would not blow and the water would not flow, as they are all driven by energy transformations. The weather would not change, and there would be no seasons. The temperature would not vary and the weather patterns would not change.
Machines and technology would not work, as they also rely on energy to operate. There would be no electricity, transportation, or communication. The economy would come to a standstill as all the industry, trade, and commerce would stop.
In short, without energy transformation, the world would be a static, lifeless place, and life as we know it would not be possible.
If a force of 250 N acts on a lawn roller at an angle of 30 degrees with horizontal, then the vertical component of the force is 216.5 N true or false
Answer:
False
Explanation:
Vertical component = 250 sin30
250×1/2=125N
What is the objects acceleration
A 4 kg block is pushed 2m at an acceleration of 0.2 meter per second square up a vertical wall by constant force f applied at an angle of 37 degree with the horizontal if the coefficient of kinetic friction between the block and the wall is 0.30 find the work done by the applied force the frictional force
The work done by the applied force on the block against the frictional force is 15.75 J.
What is work done?Work done is equal to product of force applied and distance moved.
Work = Force x Distance
Given is a 4 kg block is pushed 2m at an acceleration of 0.2 meter per second square up a vertical wall by constant force f applied at an angle of 37 degree with the horizontal if the coefficient of kinetic friction, μ between the block and the wall is 0.30.
From the equilibrium of forces acting on the block, we have
F - f = ma
where, F is applied force, f is frictional force, m is the mass and a is the acceleration.
Frictional force f = μmgsinθ
Substitute the values, we get
Fcos(37) - μmgsin(37) = ma
Fcos(37) - (0.3)(4)(9.8)sin(37) = 4(0.2)
0.799F - 7.077 = 0.8
F = 9.86 N
Work done by the applied force is
W = Fdcosθ
W = 9.86 x 2 x cos(37)
W = 15.75 J
Thus, the work done by the applied force on the block against the frictional force is 15.75 J.
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an object with a mass of 2.4 kg has a force of 12.6 N applied to it. What is the resulting acceleration of the object? WITH PROOF/WORK :)
A boy is pulling his two sisters on a sled.
If one sister weigh 30.0 kg, the other
weights 40.0 kg, and the coefficient of
kinetic friction is 0.120, how much force
is required to pull the sled?
[?] N
Answer:
Explanation:
The oly way we can figure this out is if the boy is pulling the sled at a constant velocity. If not, we need a value for acceleration, and you don't have that here. If the boy is pulling the sled at a constant velocity, then the value for acceleration is 0, making this a really simple problem. I'm going with that, since there is no way to answer you otherwise. If velocity is not constant, please either repost the question or put it in the notes section under the question as it stands. If acceleration is 0, then
F - f = ma becomes
F - f = m(0) which is
F - f = 0 and
F = f which says that the applied force is the same as the frictional force. We need then to find the frictional force, which has an equation of
f = μ\(F_n\) where normal force is the same as the weight of the 2 girls. We will find that, then:
Each girl's mass is different so the normal force/weight equation is
w = (30.0)(9.8) + (40.0)(9.8) to get
w = 290 + 390 and
w = 680. Plug that into the frictional force equation:
f = (.120)(680) so
f = 82N
A glacier advances at 8 x 10-6 cm/s.
How far will it move in 6.6 y?
Answer in units of cm
when the pressure Is High the density Is smaller or larger
The total mass of eight identical
building blocks is 31.52 kg. Find the
mass of 1 block.
Answer:
3.94
Explanation:
divide total mass by the number of blocks since they are identical
Answer:
3.94
Explanation:
You want to find the mass of one block. Since we know there is 8 blocks with the same mass, you can divide the total mass by 8 since the mass is equally distributed within the 8 blocks
If 175 kJ of heat caused a chunk of ice at 0°C to melt to liquid water at 0°C, how many moles were in the ice? How many grams of ice? (Note: molar mass of ice/water is 18.02 g/mol)
Answer is 29.1 mol or 525 g
Explanation:
The distance between earth and sun is 15000000km. Light takes 499 seconds to reach earth from sun. Calculate the speed of light from the data provided. Mention the unit as well.
Answer:
The speed of light is 30,060,120.24048 m/s.
Explanation:
15000000 km into m
1 km = 1000m
15000000 km = 15000000 × 1000 m
= 15000000000m
speed = distance travelled / time taken
or, speed = 15000000000/499 m/s
so, speed = 30,060,120.24048m/s
To solve the problem we must know about the relationship between Speed, distance, and Time.
What is the relationship between Speed, distance, and Time?We know that sped, distance, and time all are in a relationship to each other. this relationship can be given as,
\(\rm{Speed = \dfrac{Distance}{Time}\)
The speed of the light is 30,060.12 km/sec.
Given to us
The distance between the earth and the sun is 15000000km Light takes 499 seconds to reach earth from the sun.We know that speed can be described as,
\(\rm{Speed = \dfrac{Distance}{Time}\)
Therefore,
What is the speed of the light?\(\text{Speed of light} = \dfrac{\text{Distance between the earth and the sun}}{\text{Time taken by the light to travel the distance}}\)
Substitute the value,
\(\text{Speed of light} = \dfrac{15,000,000\ km}{499\ seconds}\)
\(\text{Speed of light} = 30,060.12\ km/sec\)
Hence, the speed of the light is 30,060.12 km/sec.
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A bullet with a mass of 4.26 g and a speed of 881 m/s penetrates a tree horizontally to a depth of 4.44 cm. Assume that a constant frictional force stops the bullet. Calculate the magnitude of this frictional force. Try energy considerations.
Let F be the magnitude of the frictional force. This force performs an amount of work W on the bullet such that
W = -Fx
where x is the distance over which F is acting. This is the only force acting on the bullet as it penetrates the tree. The work-energy theorem says the total work performed on a body is equal to the change in that body's kinetic energy, so we have
W = ∆K
-Fx = 0 - 1/2 mv²
where m is the body's mass and v is its speed.
Solve for F and plug in the given information:
F = mv²/(2x)
F = (0.00426 kg) (881 m/s)² / (2 (0.0444 m))
F = 37,234.8 N ≈ 37.2 kN
PLEASE HELPPPPPPPPPP
Answer:
Peer Review
Explanation:
When scientist check other scientists the process is dubbed "peer review".
What is Nicolas would be the least likely to undergo radioactive decay?
A nucleus whose total mass is less than the sum of the masses of its individual particles.
What is a nucleus?
The centre of an atom contains the nucleus, a tiny, dense, positively charged organelle. It is composed of nucleons, which are protons and neutrons put together. Negatively charged electrons travel in shells or levels of energy around the nucleus.Because it controls an element's chemical properties, the nucleus is the distinguishing characteristic of an atom. The atomic number, also referred to as the number of protons in the nucleus, is what establishes an element's identity. For instance, all carbon atoms have six protons in their nucleus, compared to eight protons for all oxygen atoms.One of the four fundamental forces of nature, the strong nuclear force, keeps the nucleus together.To know more about nuclei, click the link given below:
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How to Calculate Average Velocity with Examples
Answer:
Average velocity is calculated by the formula V = D/t, where V equals the average velocity, D equals total displacement and t equals total time.
Explanation:
Average velocity is calculated by dividing your displacement (a vector pointing from your initial position to your final position) by the total time; average speed is calculated by dividing the total distance you traveled by the total time.
For example, someone who takes 40 minutes to drive 20 miles north and then 20 miles south (to end up at the same place), has an average speed of 40 miles divided by 40 minutes, or 1 mile per minute (60 mph). Average velocity, however, involves total displacement, instead of distance.
tell what physical property of the emitting matter can be determined by each of the 3 kinds of spectra
The three kinds of spectra can be used to determine different physical properties of the emitting matter.
Three kinds of spectrums :
1. Continuous spectrum: This type of spectrum is produced by a hot, dense matter, such as a solid or dense gas.
It displays a range of wavelengths or colors without any gaps.
The physical property that can be determined using a continuous spectrum is the temperature of the emitting matter.
analyzing the peak wavelength and the distribution of energy, you can calculate the temperature using Wien's Law.
2. Emission spectrum: This spectrum is produced by hot, low-density gas.
It displays bright, distinct lines at specific wavelengths, which correspond to the energy levels of the emitting atoms.
The physical property that can be determined using an emission spectrum is the chemical composition of the emitting matter.
Each element has a unique set of emission lines, so you can identify the elements present in the matter by comparing its emission lines to known reference spectra.
3. Absorption spectrum: This spectrum is produced when light passes through a cooler, low-density gas, and the gas absorbs specific wavelengths, leaving dark lines at those positions.
The physical property that can be determined using an absorption spectrum is the chemical composition of the absorbing matter, similar to the emission spectrum.
By comparing the absorption lines to known reference spectra, you can identify the elements present in the matter.
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A 10kg cannonball is fired from a 250kg cannon. The cannonball accelerates at a rate of 150 m/s2. What happened to the cannon? Find the acceleration of the cannon as it recoils.
Answer:
1500m/s^2
Explanation:
I'm not sure if its right but I think acceleration=mass x velocity so 150×10=1500
As I said I'm not sure if its right
Three resistors of 4.0 ohms, 6.0 ohms, and 12 ohms are connected in parallel to an applied potential difference of 12 volts. (1) Calculate the equivalent resistance. (2) Determine the potential difference across each resistor. (3) Calculate the current through each resistor.
Answer:
(1) 2 ohms
(2) 12 Volts Across each resistor
(3) I₁ = 3 A, I₂ = 2 A, I₃ = 1 A
Explanation:
From the question,
(1) Equilvalent Resistance (Rt) for parallel connection is
1/Rt =(1/R₁)+ (1/R₂) + (1/R₃)
Where R₁ = 4 ohms, R₂ = 6 ohms, R₃ = 12 ohms
1/Rt = 1/4 +1/6 +1/12
1/Rt = (3+2+1)/12
1/Rt = 6/12
1/Rt = 1/2
Rt = 2 ohms.
(2) Since the resistors are connected in parallel, They will have the same potential difference across them,
Hence the P.d across each resistor = 12 Volts.
(3) For R₁,
I₁ = V/R₁ = 12/4
I₁ = 3 A.
For R₂,
I₂ = V/R₂
I₂ = 12/6
I₂ = 2 A
For R₃,
I₃ = V/R₃
I₃ = 12/12
I₃ = 1 A
A 0.50 kg grenade explodes horizontally into three pieces. The first piece has a velocity of 10 m/s [N] and a mass of 0.10 kg. The second piece has a velocity of 5.0 m/s [S 10⁰ E ] and a mass of 0.20 kg. Find the velocity of the third piece.
The velocity of the third piece is mathematically given as
v=0.88m/s
What is the velocity of the third piece.?Generally, the equation for conservation is mathematically given as
\(m u=m_{1} v_{1 \mathrm{x}}+m_{2} v_{2 \mathrm{x}}+m_{1} v_{x}\)
Here, is the mass of the grenade, \(m_{1}, m_{2}, m_{3}\) the masses of the pieces after an explosion, and \(v_{1 \mathrm{x}}, v_{2 \mathrm{x}}\) are velocities of the first and second pieces after the explosion.
\(m u_{1} &=m_{1} v_{1 x}+m_{2} v_{2 \mathrm{x}}+m_{3} v_{x} \\0 &=0+(0.2 \mathrm{~kg})((5 \mathrm{~m} / \mathrm{s})\\v_{x} &=\frac{-0.173 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}}{0.3 \mathrm{~kg}} \\&=-0.578 \mathrm{~m} / \mathrm{s}\)
the equation for conservation
\(m u=m_{1} v_{1 y}+m_{2} v_{2 y}+m_{3} v_{y}\)
\(m u_{1} &=m_{1} v_{1 \mathrm{y}}+m_{2} v_{x y}+m_{3} v_{y} \\0 &=(0.10 \mathrm{~kg})(10 \mathrm{~m} / \mathrm{s})+(0.2 \mathrm{~kg})\left((5 \mathrm{~m} / \mathrm{s}) \cos 10^{\circ}\right)+(0.3 \mathrm{~kg}) v_{y} \\v_{y} &=\frac{-1.98 \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}}{0.3 \mathrm{~kg}} \\&=-0.661 \mathrm{~m} / \mathrm{s}\)
In conclusion, the magnitude of the velocity
\(v=\sqrt{v_{\mathrm{x}}^{2}+v_{\mathrm{y}}^{2}}\)
\(Substitute $-0.578 \mathrm{~m} / \mathrm{s}$ for $v_{\mathrm{s}}$ and $-0.661 \mathrm{~m} / \mathrm{s}$ for $v_{\mathrm{y}}$\)
\(v &=\sqrt{v_{x}^{2}+v_{y}^{2}} \\&=\sqrt{(-0.578 \mathrm{~m} / \mathrm{s})^{2}+(-0.661 \mathrm{~m} / \mathrm{s})^{2}} \\&=0.88 \mathrm{~m} / \mathrm{s}\)
v=0.88m/s
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