Which force exists between any objects with mass?

A. friction

B. gravity

C. magnetism

D. weight

Answer:

U^U

Explanation:

Two-dimensional vectors have two components: an x vector and a y vector. Each of these vector components is a vector in the direction of one axis. The sum of the components of vectors is the original vector. Three-dimensional vectors have a z component as well.

We know, formula of capacitance in parallel plate capacitor is given by :

\(C = \dfrac{\epsilon_o A}{d}\)

Here, \(\epsilon_o = 8.85 \times 10^{-12} \ F.m^{-1}\)

So,

\(A = \dfrac{Cd}{\epsilon_o}\\\\A = \dfrac{1.11 \times 10^{-9}\times 8.89 \times 10^{-7}}{8.85\times 10^{-12}}\\\\A = 1.11 \times 10^{-4}\ m^2 \ or \ 1.11 \ cm^2\)

Hence, this is the required solution.

Answer:

7.09797297 • 10^-7

Explanation:

You just follow the formula:

C = εA/d

ε = 8.85 • 10^-12

A = 8.89 • 10^-7

D = 1.11• 10 ^-9

So:

C = (8.85 • 10^-12)(8.89• 10^-4)/1.11 • 10 ^-9 = 7.09797297 • 10^-7

Good Luck!  :)

Answer:

Depending on the relative position of the Earth the Sun and Neptune in the Earths orbit the distances are;

The closest (minimum) distance of Neptune from the Earth is 29 AU

The farthest (maximum) distance of Neptune fro the Earth is 31 AU

Explanation:

The following parameters are given;

The distance from the Earth to the Sun = 1 AU

The distance of Neptune from the Earth = 30 AU

We have;

When the Sun is between the Earth and Neptune, the distance is found by the relation;

Distance from the Earth to Neptune = 30 + 1 = 31 AU

When the Earth is between the Sun  and Neptune, the distance is found by the relation;

Distance from the Earth to Neptune = 30 - 1 = 29 AU

Therefore, the closest distance from Neptune to the Earth in the Earth's Orbit is 29 AU

The farthest distance from Neptune to the Earth in the Earth's orbit is 31 AU.

Answer:

29 AU

Explanation:

Given,

The length is r=5.70 m

The tangential speed is r=9.10 m/s

The centripetal acceleration is:

The acceleration is:

Answer:

electrical energy change into heat and light energy.

Answer:

The magnitude of magnetic force between the two parallel wires is 1.13 N.

Explanation:

Given;

length of each wire, l = 31 m

distance between the two parallel wires, r = 0.155 m

current on each wire, I = 168 A

The magnitude of magnetic force between the two parallel wires is calculated as;

\(F = \frac{\mu _oI_1I_2 L}{2\pi r} \\\\F = \frac{(4\pi \times 10^{-7}) \times (168)^2 \times (31)}{2\pi \times 0.155} \\\\F = 1.13 \ N\)

Therefore, the magnitude of magnetic force between the two parallel wires is 1.13 N.

Answer:

I suppose that this is a problem of rotation with constant angular velocity.

This can be answered with arcs.

Suppose that we have a circle of radius R, and an angle A (A expressed in radians)

The length of that arc will be:

L = R*A

Now, a rotating object that rotates at a constant angular velocity, in a time t moves an angle A.

so if this object is moving in a circle of radius R, in the time t the distance traveled is the same that we found above.

L = R*A

Now, if the object moves away from the axis of rotation, we have that the radius of the circle R increases, then also does the value of L (the distance traveled in the time t)

Then, when the object moves away from the axis of rotation, in the same time t, the distance traveled will be higher, which means tath the tangential velocty increased (regardless the fact that the angular velocity is constant)

Answer: 3.9 x 1200 = 4680

Explanation:

Answer:

So I think that the sound waves travel faster through water than air.

Explanation:

And the explanation would be that sound travels faster in more denser substances like water.

Answer:

B- Group 2...  It says my answer is too short so how ya'll doing today?

Answer:=mgh

Explanation:

Work is equivalent to a rate of dissipation of power per unit time. The given statement is true because work and power are related concepts in the realm of physics, transfer and conversion of energy

Work is the amount of energy transferred by a force acting through a distance, and it is typically measured in joules (J). Power, on the other hand, is the rate at which work is done or the rate at which energy is transferred or converted per unit time, and it is measured in watts (W). One watt is equal to one joule per second (1 W = 1 J/s). In a physical process, when work is done on or by a system, energy is transferred between the system and its surroundings, this energy transfer can take various forms, such as kinetic energy, potential energy, or thermal energy.

The dissipation of power refers to the conversion of useful energy into a form that cannot be easily converted back into work, such as heat or sound. The rate of dissipation of power per unit time is, therefore, equivalent to the rate at which work is done or the rate at which energy is transferred in the system. In summary, the statement "work is equivalent to a rate of dissipation of power per unit time" is true, as work and power are related concepts in the realm of physics, describing the transfer and conversion of energy over time.

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The force of gravity will become one fourth of the original force when the masses of the objects remain the same but their distance of separation doubles.

Force of gravity is an attraction force which holds the object towards the ground surface.

The gravitational force depends directly on the masses of two objects and indirectly on the square of the distance between them.

Let

m₁ and m₂ be the two different masses

r₁ be the initial distance between the the two masses

r₂ be the distance when their separation doubles.

i.e. r₂ = 2r₁

So, according to the formula,

F₁ =   \(\frac{Gm1m2}{r1^{2} }\)

F₂ =   \(\frac{Gm1m2}{r2^{2} }\)

since masses are same:

\(\frac{F1}{F2} = \frac{r2^{2} }{r1^{2} }\)

\(\frac{F1}{F2} = \frac{4r1}{r1}\)

F₁ = 4F₂

F₂ = \(\frac{1}{4}\)F₁

The resultant force is one fourth of the original force.

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(1) The angular velocity at position 1 of a uniform rod rotating freely around an axis can be determined.

(2) The velocity of the center of mass at position 2.

(1) To determine the angular velocity at position 1, we need to consider the conservation of angular momentum. Since the rod is rotating freely, there are no external torques acting on it.

The initial angular momentum is zero, and at position 1, the angular momentum is given by L = Iω, where I is the moment of inertia of the rod and ω is the angular velocity. By substituting the values of mass and length of the rod into the formula for moment of inertia, we can solve for ω.

(2) To calculate the velocity of the center of mass at position 2, relative to position 1 and at an angle theta, we can use the concept of angular velocity and linear velocity. The linear velocity of the center of mass is given by v = ωr, where ω is the angular velocity and r is the distance between the center of mass and the axis of rotation. By considering the given angle theta and the length of the rod, we can determine the distance r.

Substituting the value of ω calculated in part (1) into the formula, we can find the velocity of the center of mass at position 2, relative to position 1 and at angle theta.

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The resistance of the copper wire is 0.6 ohms. This means that it will take 0.6 volts of electrical potential difference to produce a current of 1 ampere through the wire.

The resistivity of copper is given as 2 × 10¯4 m, which is a measure of the material's inherent resistance to electrical flow. The resistance of a copper wire with a cross-sectional area of 1mm2 and a length of 3m can be calculated using Ohm's Law, which states that resistance equals resistivity multiplied by length divided by cross-sectional area.

Using this formula, we can find that the resistance of the copper wire is:

Resistance = Resistivity x Length / Cross-sectional area
Resistance = (2 × 10¯4 m) x (3 m) / (1mm2)
Resistance = 0.6 Ω

Knowing the resistance of a wire is important in determining its suitability for various electrical applications, as well as in designing and troubleshooting electrical circuits.

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Jupiter's moon Io exhibits a high level of geological activity on its surface.Its volcanic eruptions and the dynamic processes at work provide insights into the geological forces operating in extreme environments

Jupiter's moon Io is known for its intense geological activity, making it the most volcanically active object in our solar system. The tidal forces exerted by Jupiter and its other moons cause significant internal heating, resulting in a dynamic and geologically active surface.

Observations by various space missions, including the Voyager and Galileo missions, have revealed hundreds of active volcanoes on Io. These volcanoes spew out plumes of sulfur and other materials, creating a complex network of colorful volcanic features. Some of these eruptions reach heights of up to 300 kilometers (190 miles), far exceeding any volcanic activity on Earth.

The high level of geological activity on Io's surface makes it a fascinating celestial body to study. By studying Io, scientists gain a better understanding of how celestial bodies evolve and the complex interactions between moons and their parent planets.

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Answer:

a. 86.80 m

b. i. The mass of the bob

ii. The length of the pendulum

Explanation:

a. Determine the height of the smokestack.

Using T = 2π√(L/g) where T = period of pendulum = 18.7 s, L = length of pendulum = height of smokestack and g = acceleration due to gravity = 9.8 m/s².

So, making L subject of the formula, we have

T = 2π√(L/g)

T/2π = √(L/g)

squaring both sides, we have

(T/2π)² = L/g

L = (T/2π)²g

Substituting the values of the variables into the equation, we have

L = (T/2π)²g

L = (18.7 s/2π)²(9.8 m/s²)

L = (2.976 s)²(9.8 m/s²)

L = 8.857 s² × 9.8 m/s²

L = 86.796 m

L ≅ 86.80 m

b. What factors influence the period of a simple pendulum

The factors that influence the period of a simple pendulum are

i. The mass of the bob

ii. The length of the pendulum

Complete question is;

Kamal said the distance from the top of the balloon to the ground in the Example image attached is √353 ft. What mistake might Kamal have made?

Answer:

the mistake Kamal made is that she probably used 17 ft as the perpendicular side of the triangle with b as the hypotenuse instead of using 17ft as the hypotenuse

Explanation:

From the image attached, we can see that the distance from the top of the balloon which is blue in color to the ground is denoted by "b".

Now the triangle is a right angle triangle with hypotenuse = 15ft + 2ft = 17 ft; the adjacent side = 8 ft, while the opposite side is "b".

Thus, we can use pythagoras theorem to solve this as;

b = √(17² - 8²)

b = √(289 - 64)

b = √225

b = 15ft

However,we are told Kamal got b as √353 ft.

From inspection of the calculations we just did, if we had used addition instead of subtraction, we would have gotten b = √353 ft.

Thus, we can under that the mistake Kamal made is that she probably used 17 ft as the perpendicular side of the triangle with b as the hypotenuse instead of using 17ft as the hypotenuse.

When a brick (brickA) is resting on a rough incline, the friction force acting on the brick along the incline depends on a few factors. First, let's discuss the forces acting on the brick (brickA). The weight of the brick acts vertically downward due to gravity, and this force can be represented as the weight vector. We can decompose the weight vector into two components: one parallel to the incline (weight_parallel) and one perpendicular to the incline (weight_perpendicular).

The friction force acting on the brick (brickA) along the incline is opposing the component of the weight vector parallel to the incline (weight_parallel). The force of friction is determined by the product of the normal force (which in this case is equal to weight_perpendicular) and the coefficient of friction between the brick and the incline (brickC).
Now, let's analyze the given options:
A. Equal to the weight of the brick - This is incorrect, as the friction force is only equal to the weight_parallel component, not the entire weight of the brick.
B. Less than the weight of the brick - This is correct. The friction force acting on the brick along the incline is opposing the weight parallel component, which is always less than the total weight of the brick.
C. Greater than the weight of the brick - This is incorrect, as the friction force is only acting against the weight parallel component and cannot be greater than the total weight of the brick.
D. Zero - This is incorrect. Since the brick is on a rough incline, there will be a friction force acting against the weight parallel component.
So, the correct answer is B. The friction force acting on the brick along the incline is less than the weight of the brick.

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ANSWER

EXPLANATION

We want to find the angle of reflection of the ray of light.

According to the law of reflection, the angle of reflection must be equal to the angle of incidence of a ray of light:

Therefore, the angle of reflection of the ray of light is:

That is the answer.

The main advantage of using models in science is the chance to predict a given outcome and make new predictions.

The expression 'scientific models' makes reference to all advancements associated with the use of scientific claims, especially scientific theories that are well sustained by empirical evidence and the chance to prove these claims before their usage.

The scientific advantages are mainly associated with the possibility to predict the result of phenomena from the real world, which also allows for making new predictions.

In conclusion, the main advantage of using models in science is the chance to predict a given outcome and make new predictions.

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Answer: The answer is A- Low Tide

Explanation:

ASVAB scores are entered on the service record known as the Enlisted Record Brief (ERB) or the Officer Record Brief (ORB).

The Enlisted Record Brief (ERB) is used for enlisted service members, while the Officer Record Brief (ORB) is used for officers. Both records document a service member's career information, including qualifications and training. ASVAB scores, which assess a person's aptitude for various military jobs, are recorded in either the ERB or ORB to track an individual's capabilities and assist in career progression and assignment decisions.

ASVAB scores, which evaluate a person's aptitude for military job roles, are recorded in the service records of individuals. Enlisted service members have their ASVAB scores entered in the Enlisted Record Brief (ERB). The ERB is a comprehensive record containing career information, qualifications, training, and promotions for enlisted personnel. ASVAB scores are included in the ERB to provide a documented record of abilities for career development and decision-making purposes. Officers have their ASVAB scores recorded in the Officer Record Brief (ORB), which is tailored for officers and includes details such as career progression, training, qualifications, and ASVAB scores. These service records play a crucial role in assessing capabilities and determining suitable assignments and career progression within the military.

ASVAB scores are an important part of a service member's record, and they are entered in the appropriate service record, either the Enlisted Record Brief (ERB) or the Officer Record Brief (ORB), based on the individual's military status.

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The frequency of the simple harmonic motion of the mass attached to the spring is 2.45 Hz.

The frequency of simple harmonic motion is determined by the mass of the object and the force constant of the spring. The formula to calculate the frequency is given by:

f = (1/2π) * sqrt(k/m)

where f is the frequency, k is the force constant of the spring, and m is the mass.

In this case, the mass (m) is 0.2 kg and the force constant (k) is 30 N/m. Substituting these values into the formula, we get:

f = (1/2π) * sqrt(30/0.2) = 2.45 Hz

Therefore, the frequency of the simple harmonic motion of the mass attached to the spring is 2.45 Hz. This means that the mass completes 2.45 cycles of motion per second.

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Torque Formula:

T = d * F * sin angle

a) if the force is doubled, torque is doubled ( directly proportional)

For example, if force is 2 N, and distance is 2 m ,

T= 2*2* sin 90 = 4 Nm

If force is doubled:

T= 2*4 * sin90 = 8 Nm

b) If the distance of the center of rotation is doubled , Torque is also doubled ( same as "a")

c) If angle decreases 45° (90 - 45 = 45 )

T= 2*2*sin45 = 2.82 Nm

Torque also decreases

The internuclear distance for this CO molecule is approximately 1.128 × 10⁻¹⁰ m. By the carbon monoxide molecule, CO, absorbs a photon with a frequency of 1.15 × 101 1 Hz, making a purely rotational.

To answer this question, we need to use the equation for rotational energy levels in a diatomic molecule, which is given by E = h²/8π²I ×J(J+1). Here, E is the energy of the rotational level, h is Planck's constant, I is the moment of inertia of the molecule, J is the quantum number for rotational energy levels, and l is the reduced mass of the molecule.
We know that the photon absorbed by the CO molecule has a frequency of 1.15 × 10¹¹ Hz, which corresponds to an energy of E = hf = 7.63 × 10⁻²⁰ J. We also know that the transition is from a J=0 level to a J=1 level, which means that ΔJ = 1.
Using the equation above, we can set up the following expression for the energy difference between the two levels:
ΔE = E(J=1) - E(J=0) = h²/8π²I ₓ (1+1)(1-0) - h²/8π²I ₓ (0+1)(0-1) = h²/8π²I
We can now substitute the value for ΔE and the given frequency of the absorbed photon into this equation, giving:
h²/8π²I = 7.63 × 10⁻²⁰ J
Rearranging for the moment of inertia, we get:
Finally, we can use the expression for the moment of inertia of a diatomic molecule in terms of its reduced mass and internuclear distance, which is I = μr², to solve for the internuclear distance:
r = √(I/μ) = √(I/mCₓmO) = 1.128 × 10⁻¹⁰ m

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Answer:

Lunar eclipses are more widely visible because Earth casts a much larger shadow on the Moon during a lunar eclipse than the Moon casts on Earth during a solar eclipse.

Answer:

A force has both Direction and Motion.

Explanation:

For example, when finding acceleration you take the time and divided it by distance. If the thing you are measuring is going in the positive direction, the acceleration will be positive and if it is going in the negative direction the acceleration will be negative.

Magnitude and Direction

Explanation:

Force is a Vector Quantity

As learned in an earlier unit, a vector quantity is a quantity that has both magnitude and direction. To fully describe the force acting upon an object, you must describe both the magnitude (size or numerical value) and the direction.

The negative impact of polyurea is It needs to be reapplied to surfaces frequently. Option D.

Studies have shown that polyurea coatings can increase the deflection of steel components, especially when applied to the exterior facing the blast. Polyurea is a commonly used polymer in moisture-resistant coating systems. Polyurea does not emit CO2 or other harmful gases during manufacturing or use.

Basic components can be manufactured in a climate-neutral manner using renewable energy allowing timely action to be taken regarding the ecological footprint as well. Cured polyurea has a high glass transition temperature and heat distortion temperature, but will burn when exposed to an open flame. It will self-extinguish when the flame is removed. Polyurea coatings provide a fast-curing durable flexible protective barrier that prevents water damage and harmful chemicals from destroying virtually any structure.

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