The correct expression for the acceleration of a 1kg mass on a frictionless inclined plane at 30° to the horizon, given that g = 9.8 m/s², is: C. a = sin 30° x 9.8 m/s² = 4.9 m/s²
1. Recognize that only the component of gravity acting parallel to the incline affects the acceleration.
2. Calculate the parallel component of gravity using the sine function: sin(30°) x g.
3. Plug in the given values: sin(30°) x 9.8 m/s² = 0.5 x 9.8 m/s² = 4.9 m/s².
So, the correct expression and value is C. a = sin 30° x 9.8 m/s² = 4.9 m/s².
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Which has the greater momentum when moving?
Select one:
a. a bullet
b. elther of these depending on speed
c. a container ship
For the circuit shown in the figure, the current in the 8 resistor is 0.50 A, and all quantities are accurate to 2 significant figures. What is the current in the 2 resistor?
The current through the 2Ω resistor is 9.5A
The terminal voltage is 10.8 V
How to calculatea) The voltage V across 8 Ω resistor is V = I*R = 8*0.5 = 4V
the current through 16Ω resistor is then I = V/R = 4/16 = 0.25 A
the current through 20Ω resistor is then I = current through 8Ω resistor + current through 16Ω resistor = 0.75 A
voltage across 20Ω is V = I*R = 0.75*20 = 15 V
the source voltage is Vs = V8 + V20 = 4+15 = 19 V
therefore the current through 2Ω resistor is
I = V/R = 19/2 = 9.5 A
b) The terminal voltage is
Vterminal = VR = I*R = 0.450*24 = 10.8 V
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Marcos is trying out for the school baseball team. He is practicing his pitching. His dad is timing his pitching. You can see the speed of four throws in the table above. Marcos used the LEAST energy to throw which pitch?
Answer: B) 42
Explanation: You can see that it's the lowest number out of the 4 answers.
Which of the following wavelength regions cannot be studied with telescopes on the ground? A) radio waves. B) X rays. C) ultraviolet. D) both B and C
Both X-rays and Ultraviolet rays cannot be studied with telescopes on the ground. Therefore, option (D) is correct.
Earth's atmosphere limits ground-based telescopes' wavelength ranges. Ground-based telescopes have trouble observing X-rays and UV light because the atmosphere absorbs them.
Radio waves can penetrate the atmosphere and be seen from the ground with telescopes. Thus, option D) is valid since ground-based telescopes can investigate radio waves but not X-rays or UV radiation.
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Which is the equivalent of 2000 mm?
a. 200 m b. 2 m c. 0.002 m d. 0.02 m
2000 mm is equivalent to 2 m. This can be derived from the fact that 1 m = 1000 mm. Thus, 2000 mm would be equal to 2 m since it is twice the length of 1000 mm. This conversion is important in various fields such as construction, engineering, and science where precision is necessary.
It is crucial to be able to convert between different units of measurement in order to make accurate calculations and measurements.The millimeter is a unit of length that is often used to measure small distances such as the thickness of a sheet of paper or the size of a small component. It is part of the metric system, which is a system of units used across the world that is based on multiples of 10.
This system makes it easy to convert between different units since it is based on a consistent set of rules.For example, to convert 2000 mm to meters, we can simply divide by 1000 since there are 1000 millimeters in a meter. This gives us 2 meters, which is the equivalent length in meters of 2000 millimeters.
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At what temperature does water freeze in each scale?
Water freezes at 32 degrees Fahrenheit, 0 degrees Celsius, and 273.15 Kelvin, as we have all been taught.
What range of temperatures does water freeze at?Due to the salt in seawater, it freezes at a lower temperature than fresh water—approximately 28.4 degrees Fahrenheit. However, because only the water part of seawater freezes, a very little salt is present in the ice when it is formed.
At what scale of temperatures does water freeze at 273 degrees?The Kelvin scale, which measures temperatures in Kelvin, is frequently used by scientists, particularly those who investigate what happens to things when they get extremely cold (K). The steps on this scale are the same as those on the Celsius scale, however, they are moved downward. Water freezes at 273 K and boils at 373 K on this scale.
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the potential difference across two plates is 1.50 V. if the plates are 8.22*10^-4 m apart, what is the electric field between them?
Answer: 1820
Explanation:
acellus
Two cells each of EMF 1.5 v and an internal resistance of 2 ohms are connected in parallel. calculate the current flowing when the cells are connected to 1 ohm resistor
Answer:2.30
Explanation:
2. A quantity of gas is trapped by a piston in a cylinder with thin metal walls. The piston is free to move
without friction within the cylinder.
a) The air in the freezer is at atmospheric pressure, which is 1.0 × 105Pa. The area of the piston in
contact with the air in the freezer is 2.4 × 10–3m2
.
i. Calculate the force exerted on the piston by the air in the freezer.
ii. When the cylinder is first placed into the freezer, the temperature of the gas in the cylinder decreases
and the air pushes the piston into the cylinder. Calculate the work done on the piston by the air in the
freezer as the air pushes the piston at distance of 0.021m into the cylinder.
b) The initial temperature of the cylinder and the gas is 21°C and, in the freezer, the temperature of the
cylinder decreases to –18°C. The thermal capacity of the cylinder is 89J/ °C. Calculate the change in
the internal energy of the cylinder.
a)
i. The force exerted on the piston by the air in the freezer is 240 N.
ii. The work done on the piston by the air as it pushes the piston 0.021 m into the cylinder is 5.04 J.
b) The change in the internal energy of the cylinder is 3486 J.
a)
i. To calculate the force exerted on the piston by the air in the freezer, we can use the formula:
Force = Pressure * Area
Given:
Pressure (P) = 1.0 × \(10^5\) Pa
Area (A) = 2.4 ×\(10^(^-^3^) m^2\)
Substituting these values into the formula, we have:
Force = (1.0 × 10^5 Pa) * (2.4 ×\(10^(^-^3^) m^2)\)
= 240 N
ii. To calculate the work done on the piston by the air in the freezer as the air pushes the piston, we can use the formula:
Work = Force * Distance
Given:
Force = 240 N
Distance (d) = 0.021 m
Substituting these values into the formula, we have:
Work = (240 N) * (0.021 m)
= 5.04 J
b) To calculate the change in the internal energy of the cylinder, we can use the formula:
ΔU = mcΔT
Given:
Initial temperature (T1) = 21°C = 21 + 273 = 294 K
Final temperature (T2) = -18°C = -18 + 273 = 255 K
Thermal capacity (c) = 89 J/°C
Substituting these values into the formula, we have:
ΔU = (89 J/°C) * (294 K - 255 K)
= 3486 J
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In which of these scenarios is useful mechanical work being done? 1. Dave is climbing a ladder. 3. Dave washes his car.
2. Dave's stomach begins to digest his lunch.
The answer is that useful mechanical work is being done in both scenario 1 (Dave climbing a ladder) and scenario 3 (Dave washing his car).
Useful mechanical work is being done in both scenario 1 (Dave climbing a ladder) and scenario 3 (Dave washing his car). Let's examine each scenario:
Dave is climbing a ladder: In this scenario, Dave is exerting a force against gravity to move his body upwards. This involves the application of force over a distance, which is the definition of mechanical work. Therefore, useful mechanical work is being done as Dave climbs the ladder.
Dave's stomach begins to digest his lunch: Digestion is a biological process that occurs within the body and is not considered mechanical work. It involves chemical and enzymatic reactions in the stomach to break down food, but it does not involve the application of force over a distance. Thus, no useful mechanical work is being done in this scenario.
Dave washes his car: When Dave washes his car, he applies force to the cleaning materials and moves them across the car's surface, exerting work against friction. This work results in the cleaning of the car and is considered useful mechanical work.
Therefore, the answer is that useful mechanical work is being done in both scenario 1 (Dave climbing a ladder) and scenario 3 (Dave washing his car).
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Copper is an expensive metal ($2.81/lb) while aluminum is relatively inexpensive ($0.93/lb). However, the conductivity of copper higher than aluminum (6.0 x 107 (Ω-m)-1 compared to 3.8 x 107 (Ω-m)-1 ). What, if any, savings would there be by switching to aluminum wiring in a house, assuming the resistance of the wires remains constant? Useful conversion: 2.2 lb = 1 kgGiven the savings calculated above, why are aluminum wires not currently used in houses?
Aluminum wire is not commonly used in houses anymore, especially for branch circuits. Instead, copper wire is preferred due to its superior conductivity, reliability, and safety.
To start, we need to calculate the cost difference between copper and aluminum wires. We know that copper costs $2.81 per pound and aluminum costs $0.93 per pound. We also know that 2.2 lb equals 1 kg.
Let's assume that we need to use 1000 feet of wire for our house. The weight of the wire will depend on its gauge or thickness, but let's assume it weighs 10 lbs. If we use copper wire, it will cost us 10 lbs x $2.81/lb = $28.10. If we use aluminum wire, it will cost us 10 lbs x $0.93/lb = $9.30.
So, by switching to aluminum wire, we could potentially save $28.10 - $9.30 = $18.80.
We assumed that the resistance of the wires remains constant. In reality, the resistance of aluminum wire is higher than that of copper wire. This means that if we switch to aluminum wire without accounting for the change in resistance, we may experience voltage drops, power losses, and other electrical issues.
To avoid this, we would need to use a thicker gauge of aluminum wire to compensate for its higher resistance. This would increase the weight and cost of the wire, reducing or even eliminating the potential savings.
Moreover, aluminum wire is more prone to corrosion and thermal expansion than copper wire. These factors can lead to increased resistance, loose connections, and fire hazards if not properly addressed.
For these reasons, aluminum wire is not commonly used in houses anymore, especially for branch circuits. Instead, copper wire is preferred due to its superior conductivity, reliability, and safety. However, aluminum wire is still used for some applications, such as service entrance conductors and large feeders, where its cost advantage and lighter weight can outweigh its disadvantages.
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where on earth can you stand and, over the entire year, see the entire sky?
Answer: Both the north and south pole
Which type of chemical reaction results in the absorption of energy? a. combustionb. exothermicc. replacementd. endothermic
The absorption of energy occurs in endothermic reactions. The correct option is D.
What is an endothermic reaction?The type of chemical reaction that results in the absorption of energy is endothermic. In an endothermic reaction, energy is absorbed from the surroundings, resulting in an increase in the internal energy of the system.
This means that the products of the reaction have more energy than the reactants, and the reaction requires an input of energy to proceed.
Examples of endothermic reactions include the reaction of baking soda and vinegar, the melting of ice, and the reaction of ammonium nitrate and water.
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A firework accidently explodes while on the ground. The firework was initially at rest and breaks into 2 pieces in the explosion. Piece A has 3.00 times the mass of piece B. Part A If 5600 J is released in the explosion, and 90% of that energy goes into the kinetic energy of the 2 pieces, what is the final KE of piece A and piece B?
Let the mass of piece B be m, then the mass of piece A is 3m.
Let the initial kinetic energy of the system be zero, and the final kinetic energy of the two pieces be KE_A and KE_B respectively.
The total kinetic energy of the two pieces is given by:
\(KE = (1/2) * m * v_B^2 + (1/2) * 3m * v_A^2\)
where v_A and v_B are the velocities of pieces A and B respectively.
From the conservation of momentum, we have:
\(m * v_B + 3m * v_A\) = 0
or
\(v_A = -(1/3) * v_B\)
Substituting this expression into the equation for KE, we get:
\(KE = (1/2) * m * v_B^2 + (1/2) * 3m * (-v_B/3)^2\)
Simplifying, we get:
\(KE = (7/18) * m * v_B^2\)
From the given information, 90% of the released energy goes into kinetic energy, so:
\((7/18) * m * v_B^2 = 0.9 * 5600 J\)
Solving for v_B, we get:
\(v_B = sqrt[(0.9 * 5600 J * 18)/(7 * m)] = 11.88 m/s\)
Substituting this value of v_B into the expression for v_A, we get:
\(v_A = -(1/3) * v_B = -3.96 m/s\)
Therefore, the final kinetic energy of piece A is:
\(KE_A = (1/2) * 3m * v_A^2 = 23\)
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What is gravity force
The force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface.
Answer:
Gravity is the force that keeps everything on the ground instead of it floaating around!
Explanation:
Without gravity, you would be floating round in your house dodging floating objects.
Hope this brings you down to earth!
Have an amazing day!
PLEASE RATE AND MARK BRAINLIEST!! :)
what two forces act on a monkey hanging stationary by a vertical vine? which force, if either, is greater?
Two forces act on a monkey hanging stationary by a vertical vine: gravity and the tension of the vine. Gravity is the greater force in this situation because it is a constant force that acts downwards.
The two forces that act on a monkey hanging stationary by a vertical vine are tension and gravity. The tension force acts along the vine and pulls the monkey upwards, while the gravity force acts downwards towards the center of the Earth.
If the monkey is stationary, then the two forces are equal in magnitude and opposite in direction. This is because the tension force is balancing the gravity force, resulting in no net force acting on the monkey.
Therefore, if neither of the forces are greater than the other as they are equal in magnitude and opposite in direction.What is tension force?The force exerted by a string, rope, chain, or similar object on another object that it is connected to is referred to as tension. The tension is always directed along the length of the string and away from the object's surface that the string is attached to. When an object is suspended from a rope, the tension force on the rope is equal to the weight of the object (due to gravity), and this tension force is transmitted through the rope to any other objects that the rope is attached to.
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Why or why isn’t space exploration important for the people in the movie interstellar? Why or why isn’t space exploration important in todays society? Defend your answer?
In the movie Interstellar, space exploration plays a crucial role in humanity's survival. Earth is on the brink of environmental collapse, and the protagonist, Cooper, must embark on a space mission to find a new habitable planet for humanity.
For the people in the movie, space exploration is not only essential but also the only hope for the survival of the human race.
In today's society, space exploration is also crucial for several reasons. First and foremost, space exploration provides us with a deeper understanding of the universe and our place in it. It allows us to explore the unknown and discover new things, which can lead to breakthroughs in science and technology. Space exploration has already led to countless technological advancements, such as GPS, solar panels, and medical equipment.
Moreover, space exploration has practical applications in areas such as climate change, national security, and disaster response. For instance, satellite imagery can help track natural disasters and aid in disaster response efforts. Satellites can also help us monitor and understand climate change by gathering data on temperature, weather patterns, and greenhouse gas emissions.
Lastly, space exploration inspires and motivates people, especially young people, to pursue careers in science, technology, engineering, and mathematics (STEM) fields. It can also foster international cooperation and collaboration, as countries work together on space missions.
Space exploration is important for both the people in the movie Interstellar and today's society. It can provide us with a deeper understanding of the universe, lead to technological advancements, and have practical applications in areas such as climate change and disaster response. It can also inspire and motivate people to pursue careers in STEM fields and foster international cooperation. Therefore, investing in space exploration is crucial for the betterment of humanity.
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what two items on the list below are in balance in what we call energy balance?
In the context of energy balance, two items that are in balance are energy intake and energy expenditure.
Energy intake refers to the calories consumed through food and beverages, while energy expenditure refers to the calories burned by the body through daily activities and metabolic processes. When these two factors are equal, the body maintains a stable energy balance, supporting overall health and well-being.
Energy radiated into space from the Sun's surface is equal to energy released by fusion in the Sun's core.
The balance between the quantity of energy input and the amount of energy production is referred to as the "energy balance." We say there is an energy balance when the amount of energy released equals the amount of energy returned to the system.
The primary energy source in the universe is the Sun, which generates energy through the FUSION OF RADIOACTIVE MATERIALS IN ITS CORE. When the energy released by the Sun is equal to the energy released to outer space, we say that there is energy balance.
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In the context of energy balance, two items that are in balance are energy intake and energy expenditure.
Energy intake refers to the calories consumed through food and beverages, while energy expenditure refers to the calories burned by the body through daily activities and metabolic processes. When these two factors are equal, the body maintains a stable energy balance, supporting overall health and well-being.
Energy radiated into space from the Sun's surface is equal to energy released by fusion in the Sun's core.
The balance between the quantity of energy input and the amount of energy production is referred to as the "energy balance." We say there is an energy balance when the amount of energy released equals the amount of energy returned to the system.
The primary energy source in the universe is the Sun, which generates energy through the FUSION OF RADIOACTIVE MATERIALS IN ITS CORE. When the energy released by the Sun is equal to the energy released to outer space, we say that there is energy balance.
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What is a volume of a 200 gram sample of gold if its density is known to be 20.5g/cm3?
A container is filled with a mixture of helium and oxygen at the same temperature. The molar mass of helium is 4g mol^-1 and that of oxygen is 32 g mol^-1. What is the ratio of the average speed of helium molecules to the average speed of oxygen molecules?
Answer:2.83 times greater than the average speed of oxygen molecules at the same temperature.
Explanation:The ratio of the average speed of helium molecules to the average speed of oxygen molecules can be calculated using the root mean square (rms) velocity formula:
ratio of rms velocity = sqrt(M2/M1)
where M1 and M2 are the molar masses of the gases.
In this case, the ratio of the molar masses is M2/M1 = 32/4 = 8.
So, the ratio of the rms velocity of helium to oxygen is:
ratio of rms velocity = sqrt(8) = 2.83
Therefore, the average speed of helium molecules is about 2.83 times greater than the average speed of oxygen molecules at the same temperature.
10. Match the following varibles to their relationship in Newton's 2nd Law. Questions 1. Force and Acceleration 2. Mass and Acceleration 3. Speed and Distance Answer Choices A. Direct Relationship B. Inverse Relationship C. Not in Newton's 2nd Law
Explanation:
based on the above information
1.A
2.B
3. C
Given that the wavelengths of visible light range from 400 nm to 700 nm, what is the highest frequency of visible light? (c = 3.0 x 108 m/s) O 2.3 1020 Hz O 5.0 x 108 Hz O 7.5 x 1014 Hz O 4.3 1014 Hz O 3.1 x 108 Hz
To find the highest frequency of visible light, we need to use the equation: frequency = speed of light/wavelength. The speed of light is given as 3.0 x 10^8 m/s. The highest frequency will be obtained when the wavelength is at its minimum value of 400 nm. Substituting these values in the equation, we get: frequency = (3.0 x 10^8 m/s) / (400 x 10^-9 m) = 7.5 x 10^14 Hz. Therefore, the highest frequency of visible light is 7.5 x 10^14 Hz. Option C is the correct answer. It is important to note that frequency and wavelength are inversely proportional, meaning that as wavelength increases, frequency decreases and vice versa.
Given that the wavelengths of visible light range from 400 nm to 700 nm, the highest frequency of visible light can be calculated using the following steps:
1. Convert the wavelength to meters: The shortest wavelength (400 nm) corresponds to the highest frequency. To convert 400 nm to meters, multiply by 10^(-9): 400 nm * 10^(-9) m/nm = 4.0 x 10^(-7) m.
2. Use the speed of light formula: The speed of light (c) is equal to the product of the wavelength (λ) and the frequency (f). The formula is c = λ * f. We know that c = 3.0 x 10^8 m/s and λ = 4.0 x 10^(-7) m.
3. Solve for the highest frequency: Rearrange the formula to isolate f: f = c / λ. Then, substitute the values: f = (3.0 x 10^8 m/s) / (4.0 x 10^(-7) m) = 7.5 x 10^14 Hz.
The highest frequency of visible light is 7.5 x 10^14 Hz.
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Most of us know intuitively that in a head-on collision between a large dump truck and a subcompact car, you are better off being in the truck than in the car. Why is this? Many people imagine that the collision force exerted on the car is much greater than that exerted on the truck. To substantiate this view, they point out that the car is crushed, whereas the truck is only dented. This idea of unequal forces, of course, is false; Newton's third law tells us that both objects are acted upon by forces of the same magnitude. The truck suffers less damage because it is made of stronger metal. But what about the two drivers? Do they experience the same forces? To answer this question, suppose that each vehicle is initially moving at 6.60 m/s and that they undergo a perfectly inelastic head-on collision. Each driver has mass 75.0 kg. Including the masses of the drivers, the total masses of the vehicles are 800 kg for the car and 4,000 kg for the truck. If the collision time is 0.100 s, what force does the seat belt exert on each driver? (Enter the magnitude of the force.)
Answer:
According to Newton's third law, the force exerted on each driver during the collision is equal and opposite to the force exerted on their respective vehicles. We can use the principle of conservation of momentum to find the force experienced by each driver.
The initial momentum of the car and driver is the product of their mass and velocity: (800 kg)(6.60 m/s) = 5280 kgm/s. The initial momentum of the truck and driver is (4000 kg)(6.60 m/s) = 26400 kgm/s. After the collision, the final momentum of the combined system (the car, truck, and drivers) is 0, since the collision is perfectly inelastic and the two vehicles stick together. This means that the final momentum of the car and driver is equal and opposite to the final momentum of the truck and driver.
We can set up the following equation to solve for the force experienced by the car driver:
Force (car driver) = (final momentum of car and driver) / (collision time)
= (-final momentum of truck and driver) / (collision time)
= (-26400 kg*m/s) / (0.100 s)
= -26400 N
The negative sign indicates that the force is in the opposite direction of the initial momentum of the car and driver. The force experienced by the truck driver is equal in magnitude to the force experienced by the car driver, so the force experienced by the truck driver is also -26400 N.
Explanation:
An 8000 kg satellite is launched from the surface of the Earth into outer space. What initial kinetic energy is needed by the satellite in order to reach a great (i.e., infinite) distance from the Earth, neglecting the effects of air resistance in the atmosphere? (G = 6.67 × 10−11 N·m2/kg2, ME = 5.97 × 1024 kg, RE = 6.37 × 106 m.)
3.96 × 1011 J is the initial kinetic energy is needed by the satellite in order to reach a great (i.e., infinite) distance from the Earth, neglecting the effects of air resistance in the atmosphere.
In order to calculate the initial kinetic energy needed for the satellite to reach an infinite distance from Earth, we need to use the equation
K = 0.5\(mv^2\), where K is the kinetic energy, m is the mass of the satellite, and v is its velocity.
Using the given values of the satellite's mass (8000 kg) and the gravitational constant (6.67 × 10−11 N·m2/kg2), we can calculate the initial velocity needed:
v = √[(2GME)/RE] = √[(2 × 6.67 × 10−11 × 5.97 × 1024) / 6.37 × 106] = √[9.8 × 107] = 9.9 × 103 m/s
Using the velocity and mass values, we can calculate the initial kinetic energy needed for the satellite to reach an infinite distance from Earth:
K = 0.5\(mv^2\) = 0.5 × 8000 kg × (9.9 × 103)2 = 3.96 × 1011 J.
Therefore, the initial kinetic energy needed for the 8000 kg satellite to reach an infinite distance from Earth, neglecting the effects of air resistance in the atmosphere, is 3.96 × 1011 J.
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A skateboarder travels on a horizontal surface with an initial velocity of 4. 4 m/s toward the south and a constant acceleration of 2. 3 m/s2 toward the east. Let the x direction be eastward and the y direction be northward, and let the skateboarder be at the origin at t=0
The skateboarder's position as a function of time is given by the vectors 1.15 t^2 and -4.4 t.
Initial velocity = 4. 4 m/s
Acceleration = 2. 3 m/s2
Assuming that eastward direction = x
Assuming that Northward direction = y
we can solve for the skateboarder's position at any time utilizing the following equations:
\(x = x0 + v0x t + 1/2 a_x t^2\)
\(y = y0 + v0y t + 1/2 a_y t^2\)
substituting the above values in the equation:
\(x = 0 + 0 + 1/2 (2.3) t^2\)
x = 1.15 t^2
y = 0 - 4.4 t + 0
y = -4.4 t
Therefore we can conclude that the skateboarder's position as a function of time is given by the vectors 1.15 t^2 and -4.4 t.
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The complete question is:
A skateboarder travels on a horizontal surface with an initial velocity of 4. 4 m/s toward the south and a constant acceleration of 2. 3 m/s2 toward the east. Let the x direction be eastward and the y direction be northward, and let the skateboarder be at the origin at t=0. What is the position of the skateboarder in vectors?
When a substance cools it loses
A puddle dries up by the process of
When you see fog or clouds you are seeing water in the
state.
energy.
A liquids resistance to flow is called
Describe the two types of vaporization boiling and evaporation
A liquids resistance to flow is called Viscosity
A phase change from the liquid phase to the vapour phase is called vaporisation (or vaporisation) of an element or molecule. Both evaporation and boiling result in vaporisation. Boiling is a bulk phenomenon, whereas evaporation is a surface phenomenon.
Is vaporisation a subset of boiling?vaporisation is the process by which a material is transformed from its liquid or solid state into its gaseous (vapour) state. Boiling is the term for the vaporisation process when circumstances permit the creation of vapour bubbles within a liquid.
Evaporation is a typical process that takes place when a liquid transforms into a gas while raising the temperature or pressure. Boiling is an unnatural process in which the liquid is continuously heated to a point where it vaporises.
The transformation of a liquid into a gas is known as vaporisation.
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i) Show that total energy of the body at points A, B and C during the fall is same. ii) Find the distance from A to B and final velocity of the ball just reach before C. mass =5 kg, total height (h)= 100m
The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.
d (distance) from A to B is = √2gh
In this case given are, g = 9.8 m/s² and h = 100m,
so here d = √(2⋅9.8⋅100) = 44.3m.
Final velocity ,v = √2gh
Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,
g = 9.8 m/s² ,h = 100m,
v = √(2⋅9.8⋅100)
= 44.3 m/s (final velocity)
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Agent burt engle is chasing some more "bad" dudes and dudettes, when he notices his fuel gauge is running close to empty. he is approaching a hill (that makes an incline of 30 degrees with the horizontal) whose height is 49 m when suddenly, while travelling at 32 m/s, the car stalls on him. he desperately tries to re-start the car, only to fail miserably. if the average resistance force is 300 n, and the car has a mass of 800 kg, will agent burt engle make it to the crest of the hill (or will he have to call agent 001 for some back up)?
Agent burt engle is chasing some more "bad" dudes and dudettes, when he notices his fuel gauge is running close to empty. he is approaching a hill (that makes an incline of 30 degrees with the horizontal) whose height is 49 m when suddenly, while travelling at 32 m/s, the car stalls on him.
To determine whether Agent Burt Engle will make it to the crest of the hill or not, we need to consider the forces acting on the car and the work done.
First, let’s calculate the gravitational potential energy (PE) of the car at the base of the hill:
PE = m * g * h
PE = 800 kg * 9.8 m/s² * 49 m
PE = 384,160 J
Now, let’s calculate the work done by the resistance force as the car moves up the hill:
Work = force * distance
The force acting against the car’s motion is the resistance force, which is given as 300 N. The distance traveled up the hill is the height of the hill, which is 49 m.
Work = 300 N * 49 m
Work = 14,700 J
Comparing the work done by the resistance force to the initial potential energy, we can determine if the car will make it to the crest of the hill:
If Work < PE, the car will make it to the crest of the hill.
If Work ≥ PE, the car will not make it to the crest of the hill.
In this case, 14,700 J ≥ 384,160 J, which means the work done by the resistance force is greater than the initial potential energy of the car. Therefore, Agent Burt Engle will not make it to the crest of the hill and will have to call for backup.
Learn more about gravitational potential energy here:
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Describe two processes in which an external force is exerted on a system and no work is done on the system. Explain why no work is done
First Process: When a person push the wall, then the wall is displaced from one point to another. The person is pushing the wall which means he is applying the external force to the wall but the wall is not displacing. As the wall does not displaced therefore, the distance covered by the wall is zero.
Now, the work done is given as the product of force applied to the object with the distance covered. Since the distance covered is zero therefore, work done is also zero.
Second Process: When a person holds some luggage on the head, then the work done is said to be zero. Because the force acting on the person is in perpendicular direction and the work done also depends upon the cosine angle between force acting and the distance covered. As the distance is covered along horizontal direction and the force is applied in the vertical direction therefore, angle between them is 90 degree and cosine of 90 degree is zero.
Therefore, the work done by the person carrying the luggage is zero.
You arrive in my class 45 seconds after leaving math which is 90 meters away. How fast did you travel?
Answer:
2m/s
Explanation:
speed = distance÷time
speed =90÷45=2m/s