Which equation can be used to solve the problem?

60 percent of what number is 30?
StartFraction 60 times 2 Over 30 times 2 EndFraction = StartFraction 120 Over 60 EndFraction
StartFraction 30 divided by 1 Over 60 divided by 1 EndFraction = StartFraction 30 Over 60 EndFraction
StartFraction 60 divided by 2 Over 100 divided by 2 EndFraction = StartFraction 30 Over 50 EndFraction
StartFraction 100 times 2 Over 30 times 2 EndFraction = StartFraction 200 Over 60 EndFraction

The probability that the slope of the line determined by p and the point (5/8, 3/8) is greater than or equal to 1/2 is 5/8.

Let the coordinates of point p be (x,y). Then, the slope of the line determined by p and the point (5/8, 3/8) is:

For the slope to be greater than or equal to 1/2, we must have:

Solving for y, we get:

Graphing this inequality on the unit square, we see that the region satisfying this inequality is a trapezoid with vertices (5/8,3/8), (1,1/2), (1,1), and (3/4,1).

The area of this trapezoid is (1/2)*((5/8 - 3/4) + (1 - 5/8) + (1 - 1/2) + (3/8 - 3/16)) = 5/16.

The area of the unit square is 1, so the probability we seek is 5/16.

Hence, the answer is 5/16 written as a fraction in its simplest form, which is 5/16.

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Answer:

9/20

Step-by-step explanation:

0.45 = 45/100

45/100=9/20 (divide numerator and denominator by 5)

\( \sf \longrightarrow \: 5 \bigg( \: n - \frac{1}{10} \bigg) = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: 5 \bigg( \: \frac{n}{1} - \frac{1}{10} \bigg) = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: 5 \bigg( \: \frac{10 \times n - 1 \times 1}{1 \times 10} \bigg) = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: 5 \bigg( \: \frac{10n - 1}{ 10} \bigg) = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: \: \frac{50n - 5}{ 10} = \frac{1}{2} \\ \)

\( \sf \longrightarrow \: \: 2(50n - 5) =1(10) \\ \)

\( \sf \longrightarrow \: \: 2(50n - 5) =10 \\ \)

\( \sf \longrightarrow \: \: 100n - 10=10 \\ \)

\( \sf \longrightarrow \: \: 100n =10 + 10\\ \)

\( \sf \longrightarrow \: \: 100n =20\\ \)

\( \sf \longrightarrow \: \:n = \frac{2 \cancel{0}}{10 \cancel{0}} \\ \)

\( \sf \longrightarrow \: \:n = \frac{1}{5} \\ \)

Answer:-

To solve the equation \(\sf 5(n - \frac{1}{10}) = \frac{1}{2} \\\) for \(\sf n \\\), we can follow these steps:

Step 1: Distribute the 5 on the left side:

\(\sf 5n - \frac{1}{2} = \frac{1}{2} \\\)

Step 2: Add \(\sf \frac{1}{2} \\\) to both sides of the equation:

\(\sf 5n = \frac{1}{2} + \frac{1}{2} \\\)

\(\sf 5n = 1 \\\)

Step 3: Divide both sides of the equation by 5 to isolate \(\sf n \\\):

\(\sf \frac{5n}{5} = \frac{1}{5} \\\)

\(\sf n = \frac{1}{5} \\\)

Therefore, the solution to the equation \(\sf 5(n - \frac{1}{10})\ = \frac{1}{2} \\\) is \(\sf n = \frac{1}{5} \\\), which corresponds to option (d).

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Answer:

b hope i helped you have a good day

The Polynomial x⁵ + x³ - 5 is divided by x - 2, the quotient is x⁴ + 3x³ + 6x² + 12x + 24, and the remainder is 48.

The quotient and remainder when the polynomial x⁵ + x³ - 5 is divided by x - 2, we can use polynomial long division. Here's the step-by-step process:

1. Write the dividend (x⁵ + x³ - 5) and the divisor (x - 2).

   x - 2 | x⁵ + x³ + 0x² + 0x - 5

2. Divide the first term of the dividend (x⁵) by the first term of the divisor (x) to get x⁴. Write x⁴ above the line. x⁴

   x - 2 | x⁵ + x³ + 0x² + 0x - 5

3. Multiply the divisor (x - 2) by the quotient term (x⁴) to get x⁵ - 2x⁴. Write this under the dividend and subtract it.  x⁴

  x - 2 | x⁵ + x³ + 0x² + 0x - 5

 - (x⁵ - 2x⁴)

3x⁴ + 0x³ + 0x² + 0x - 5

4. Bring down the next term (-5) from the dividend.

x⁴ + 3x³

x - 2 | x⁵ + x³ + 0x² + 0x - 5

- (x⁵ - 2x⁴)

3x⁴ + 0x³ + 0x² + 0x - 5

5. Divide the first term of the new dividend (3x⁴) by the first term of the divisor (x) to get 3x³. Write 3x³ above the line.

 x⁴ + 3x³

   x - 2 | x⁵ + x³ + 0x² + 0x - 5

 - (x⁵ - 2x⁴)

3x⁴ + 0x³ + 0x² + 0x - 5

6. Multiply the divisor (x - 2) by the new quotient term (3x³) to get 3x⁴ - 6x³. Write this under the new dividend and subtract it.

x⁴ + 3x³

x - 2 | x⁵ + x³ + 0x² + 0x - 5

- (x⁵ - 2x⁴)

3x⁴ + 0x³ + 0x² + 0x - 5

- (3x⁴ - 6x³)

6x³ + 0x² + 0x - 5

7. Repeat steps 4-6 until you have subtracted all terms.

x⁴ + 3x³ + 6x² + 12x + 24

x - 2 | x⁵ + x³ + 0x² + 0x - 5

- (x⁵ - 2x⁴)

3x⁴ + 0x³ + 0x² + 0x - 5

- (3x⁴ - 6x³)

6x³ + 0x² + 0x - 5

- (6x³ - 12x²)

12x² + 0x + 0

 - (12x² - 24x)

 24x + 0

- (24x - 48)

 48

8. The quotient is x⁴ + 3x³ + 6x² + 12x + 24, and the remainder is 48.

Therefore, when the polynomial x⁵ + x³ - 5 is divided by x - 2, the quotient is x⁴ + 3x³ + 6x² + 12x + 24, and the remainder is 48.

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The temperature at the bottom of the mountain is 50.9 °C.

Let's work through the given information step by step to find the temperature at the bottom of the mountain.

The temperature in the hotel is 21 °C.

The temperature in the hotel is 26.7 °C warmer than at the top of the mountain.

Let's denote the temperature at the top of the mountain as T_top.

So, the temperature in the hotel can be expressed as T_top + 26.7 °C.

The temperature at the top of the mountain is 3.2 °C colder than at the bottom of the mountain.

Let's denote the temperature at the bottom of the mountain as T_bottom.

So, the temperature at the top of the mountain can be expressed as T_bottom - 3.2 °C.

Now, let's combine the information we have:

T_top + 26.7 °C = T_bottom - 3.2 °C

To find the temperature at the bottom of the mountain (T_bottom), we need to isolate it on one side of the equation. Let's do the calculations:

T_bottom = T_top + 26.7 °C + 3.2 °C

T_bottom = T_top + 29.9 °C

Since we know that the temperature in the hotel is 21 °C, we can substitute T_top with 21 °C:

T_bottom = 21 °C + 29.9 °C

T_bottom = 50.9 °C

Therefore, the temperature at the bottom of the mountain is 50.9 °C.

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Answer:

The stock market is up 49.75 for the day.

Step-by-step explanation:

-70.5 + 120.25 = 49.75

Answer:

It has a solution.

Step-by-step explanation:

Step 1: Rearrange 1st equation into slope-intercept form

2x + y = 15

y = 15 - 2x

Step 2: Rearrange 2nd equation into slope-intercept form

x = 15 - 2y

2y + x = 15

2y = 15 - x

y = 15/2 - x/2

Step 3: Rewrite systems of equations

y = 15 - 2x

y = 15/2 - x/2

Since the two lines are not parallel, they will have a solution.

Answer: T'=(-1,-1), U'=(-3,-1), V'=(-1,-4)

Step-by-step explanation:

The total principal and interest payment that Nelson will have to pay after 2 months is $4665.50.

To calculate the total principal and interest payment, we need to determine the interest amount and add it to the principal.

First, let's find the interest amount:

Interest = Principal x Interest Rate x Time

Given:

Principal = $4650

Interest Rate = 2% per year

Time = 2 months

Since the interest rate is given on an annual basis, we need to convert the time from months to years. There are 12 months in a year, so 2 months is equivalent to 2/12 = 1/6 years.

Interest = $4650 x 0.02 x (1/6) = $15.50

Now, we can calculate the total principal and interest payment:

Total Payment = Principal + Interest

Total Payment = $4650 + $15.50 = $4665.50

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Answer:

1) 7/3

2) Undefined

3) 1

4) 7/4

Step-by-step explanation:

Answer:

45

Step-by-step explanation:

Put in '5' where 'x' is

2 (5)^2 - 5 = 45

What is the equation: \(2x^2-5\)

What do we want to find: f(5)

To find f(5), we must plug the value '5'

     ⇒ into the 'x' position

        ⇒ f(x)

So: \(f(5) = 2(5^2)-5 = 2 * 25 - 5 = 50 -5 = 45\)

Thus f(5) = 45

Hope that helps!

Kinzang grew 0.96 meters.

We have,

To find how much Kinzang grew, we need to subtract his height at birth from his current height:

Height Kinzang grew = Current height - Height at birth

Height Kinzang grew = 1.49 m - 0.53 m = 0.96 m

Therefore,

Kinzang grew 0.96 meters.

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As this is a right angle triangle.

using trigonometric identity:

tanA= Perpendicular/Base

In the given figure :

Perpendicular P= √5

Base B =O

so, Tan 30°= P/B

  1/√3 = √5/

doing cross multiplication we have:

 O= √5×√3

 O=√15

To find value of Hypotenuse, we will trigonometric identity:

Cos 30°= Base/ Hypotenuse

 √3/2 = √15/p

doing cross multiplication we get:

√3×p = √15×2

p = (√15 × 2)/ √3

p= (√5 × √3 × 2)/√3

p= 2√5

Hence, the Base is √15 and Hypotenuse p is 2√5.

Answer:

Step-by-step explanation:

The milepost number of the rest area is 7 miles away from milepost 58, so it can be represented by the equation:

m = 58 + 7

This equation states that the milepost number of the rest area is equal to 58 plus 7, or 65. Therefore, the rest area can be located at milepost 65.

The solution to the system of equations is x = 1 and y = -3.

To solve the system of equations using the substitution or elimination method, let's start with the substitution method.

Given equations:

y = 4x - 7

4x + 2y = -2

We'll solve equation 1) for y and substitute it into equation 2):

Substituting y from equation 1) into equation 2):

4x + 2(4x - 7) = -2

4x + 8x - 14 = -2

12x - 14 = -2

Now, we'll solve this equation for x:

12x = -2 + 14

12x = 12

x = 12/12

x = 1

Now that we have the value of x, we can substitute it back into equation 1) to find y:

y = 4(1) - 7

y = 4 - 7

y = -3

Therefore, the solution to the system of equations is x = 1 and y = -3.

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Answer:

Step-by-step explanation:

The segment sum theorem tells you the whole is the sum of the parts. That can be used to write an equation for y.

  RS +ST = RT

  (5y +5) +(4y +8) = 67

Simplifying, we get ...

  9y +13 = 67

  9y = 54 . . . . . . . . subtract 13

  y = 6 . . . . . . . . . divide by 9

RS = 5y +5 = 5·6 +5 = 35

ST = 4y +8 = 4·6 +8 = 32

The values of interest are ...

The linear function that relates y to x is given as follows:

y = -0.5x + 57.

The slope indicates that the height decays 0.5 feet per minute. The y-intercept indicates that the descent starts at a cruising altitude of 57 feet.

The slope-intercept equation for a linear function is presented as follows:

y = mx + b

The coefficients m and b represent the slope and the intercept, respectively, and are explained as follows:

From the table, when x = 0, y = 57, hence the intercept b is given as follows:

b = 57.

When x increases by 10, y decays by 5, hence the slope m is given as follows:

m = -5/10

m = -0.5.

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Answer:

(2, -3)

Step-by-step explanation:

if move down 2 units, then y needs to move up 2 units

if move right 3 units, then x needs to move left 3 units  

(5-3, -5+2)

(2, -3)

Answer & Step-by-step explanation:

The triangle shown is an isosceles triangles. Isosceles triangles have a pair of congruent angles which are found at the bottom. These angles are called the base angles. So, when you find the measurement of one of the base angles, then the other base angle will have the same measurement.

We can find the measurement of x by subtracting 130 from 180. We are doing this because all triangles have a sum measurement of 180°. After we do this, then we will divide that number by 2 to find the measurement of x.

180 - 130 = 50

Now, we divide 50 by 2.

50 ÷ 2 = 25

So, the measurement of x is 25°.

53 years for the Population of the United States to reach 300 million people according to this model.

The recursive formula of the population of the United States is given by ao = an1.015a - 1

Let's solve this to get a formula that is not recursive.a0 = a0 givena1 = 1.015a0 - 1a2 = 1.015a1 - 1 = 1.015 (1.015a0 - 1) - 1 = 1.0152 a0 - 1.015 - 1a3 = 1.015a2 - 1 = 1.015(1.015²a0 - 1.015 - 1) - 1 = 1.015³ a0 - 1.015² - 1.015 - 1a4 = 1.015a3 - 1 = 1.015(1.015³a0 - 1.015² - 1.015 - 1) - 1 = 1.015⁴ a0 - 1.015³ - 1.015² - 1.015 - 1an = 1.015na0 - 1.015n-1 - 1.015n-2 - ... - 1.015 - 1We can rewrite this asan = a0(1.015)

where a0 is the population of the United States in 1910 (92.2 million people) .

Now, we need to write an exponential function to find the population of the United States as a function of time in years since 1910.P(t) = 92.2(1.015)

To find the number of years it takes for the population to reach 300 million people, we need to solve the equation92.2(1.015)t = 300

Dividing both sides by 92.2, we get1.015t = 3.2596

Taking the natural logarithm of both sides, we get ln(1.015) = ln(3.2596)t = ln(3.2596)/ln(1.015) ≈ 53.2

Therefore,  approximately 53 years for the population of the United States to reach 300 million people according to this model.

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Answer:

Step-by-step explanation:

What you do is multiply the previous number and add 1 to get the next answer.

Equation An = 2(An-1)+1

n = The Term

The expression which has the greatest value is 1 7/8 divided by 1/12

• For the first question,  \(\frac{3}{4} /\frac{1}{3} =2 \frac{1}{4}\)

• For the second question, \(\frac{3}{4} / \frac{1}{12} = 9\)

• For the third question,  \(1 \frac{7}{8} =\frac{15}{8}\) so \(\frac{15}{8} /\frac{1}{12} = 22 \frac{1}{2}\)

• For the fourth question, \(1 \frac{7}{8} =\frac{15}{8}\) so \(\frac{15}{8} /\frac{1}{3} = 5 \frac{5}{8}\)

—————

Please remember to revise this and make it in your own words if you want! I tried to speed this up a lot! I hope this helps you. -Doodle

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Answer:

1 7/8 / 1/ 12 has the greatest value

Step-by-step explanation:

Answer:

first and third expressions

Step-by-step explanation:

using the rule of exponents

\(\frac{a^{m} }{a^{n} }\) = \(a^{m-n}\)

then

\(\frac{3^{\frac{4}{9} } }{3^{\frac{2}{9} } }\)

= \(3^{\frac{4}{9}-\frac{2}{9} }\) ← first expression

= \(3^{\frac{2}{9} }\) ← third expression

Answer:

21

Step-by-step explanation:

given : 2 triffles = 7

6 / 2 = 3 so miutiple both side by 3

2 x 3 = 6 and 7 x 3 = 21

6 triffles = 21

OR

Find the cost of 1 triffle:

7 / 2 = 3.5

1 triffle = 3.50

3.50 each x 6 triffles = 21

The correct answer is Confidence interval lower bound: 32.52 cm,Confidence interval upper bound: 37.48 cm

To calculate the confidence interval for the true mean height of the loaves, we can use the t-distribution. Given that the sample size is small (n = 10) and the population standard deviation is unknown, the t-distribution is appropriate for constructing the confidence interval.

The formula for a confidence interval for the population mean (μ) is:

Confidence Interval = sample mean ± (t-critical value) * (sample standard deviation / sqrt(sample size))

For the first situation:

n = 15

Confidence level is 95% (which corresponds to an alpha level of 0.05)

x = 35 (sample mean)

s = 2.7 (sample standard deviation)

Using RStudio or a t-table, we can find the t-critical value. The degrees of freedom for this scenario is (n - 1) = (15 - 1) = 14.

The t-critical value at a 95% confidence level with 14 degrees of freedom is approximately 2.145.

Plugging the values into the formula:

Confidence Interval = 35 ± (2.145) * (2.7 / sqrt(15))

Calculating the confidence interval:

Lower Bound = 35 - (2.145) * (2.7 / sqrt(15)) ≈ 32.52 (rounded to 2 decimal places)

Upper Bound = 35 + (2.145) * (2.7 / sqrt(15)) ≈ 37.48 (rounded to 2 decimal places)

Therefore, the lower bound of the confidence interval is approximately 32.52 cm, and the upper bound is approximately 37.48 cm.

For the second situation:

n = 37

Confidence level is 99% (which corresponds to an alpha level of 0.01)

x = 82 (sample mean)

s = 5.9 (sample standard deviation)

The degrees of freedom for this scenario is (n - 1) = (37 - 1) = 36.

The t-critical value at a 99% confidence level with 36 degrees of freedom is approximately 2.711.

Plugging the values into the formula:

Confidence Interval = 82 ± (2.711) * (5.9 / sqrt(37))

Calculating the confidence interval:

Lower Bound = 82 - (2.711) * (5.9 / sqrt(37)) ≈ 78.20 (rounded to 2 decimal places)

Upper Bound = 82 + (2.711) * (5.9 / sqrt(37)) ≈ 85.80 (rounded to 2 decimal places)

Therefore, the lower bound of the confidence interval is approximately 78.20 cm, and the upper bound is approximately 85.80 cm.

For the third situation:

n = 1009

Confidence level is 90% (which corresponds to an alpha level of 0.10)

x = 0.9 (sample mean)

s = 0.04 (sample standard deviation)

The degrees of freedom for this scenario is (n - 1) = (1009 - 1) = 1008.

The t-critical value at a 90% confidence level with 1008 degrees of freedom is approximately 1.645.

Plugging the values into the formula:

Confidence Interval = 0.9 ± (1.645) * (0.04 / sqrt(1009))

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when x = 4, the value of y is 1.

In an inverse variation, the product of the variable and its corresponding value remains constant. Let's denote the constant of variation as k.

According to the given problem, we have the inverse variation equation:

y = k/x^3

To find the value of k, we can substitute the given values for y and x:

8 = k/2^3

8 = k/8

k = 8 * 8

k = 64

Now that we have the constant of variation, we can find the value of y when x = 4:

y = 64/4^3

y = 64/64

y = 1

Therefore, when x = 4, the value of y is 1.

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