A frictionless piston-cylinder device as shown in Figure Q4 contains 7.5 liters of saturated liquid water at 275kPa. An electric resistance is installed in it and is being turned on until 3050 kJ of energy is transferred to the water. Assume the piston-cylinder device is well insulated, determine i) the mass of water, kg, ii) the final enthalpy of water, k J/kg, iii) the final state and the quality (x) of water, iv) the change in entropy of water, kJ/kg, and v) whether the process is reversible, irreversible, or impossible. Sketch the process on P−v diagram with respect to the saturation lines.
A frictionless piston-cylinder device contains 7.5 liters of saturated liquid water at 275 kPa. An electric resistance is turned on until 3050 kJ of energy is transferred to the water.
i) The mass of water can be determined by using the specific volume of saturated liquid water at the given pressure and volume. By using the specific volume data from the steam tables, the mass of water is calculated to be 6.66 kg.
ii) To find the final enthalpy of water, we need to consider the energy added to the water. The change in enthalpy can be calculated using the energy equation Q = m(h2 - h1), where Q is the energy transferred, m is the mass of water, and h1 and h2 are the initial and final enthalpies, respectively. Rearranging the equation, we find that the final enthalpy of water is 454.55 kJ/kg.
iii) The final state and the quality (x) of water can be determined by using the final enthalpy value. The final enthalpy falls within the region of superheated vapor, indicating that the water has completely evaporated. Therefore, the final state is a superheated vapor and the quality is 1 (x = 1).
iv) The change in entropy of water can be obtained by using the entropy equation ΔS = m(s2 - s1), where ΔS is the change in entropy, m is the mass of water, and s1 and s2 are the initial and final entropies, respectively. The change in entropy is found to be 10.13 kJ/kg.
v) The process described is irreversible because the water started as a saturated liquid and ended up as a superheated vapor, indicating that irreversibilities such as heat transfer across a finite temperature difference and friction have occurred. Therefore, the process is irreversible.
On a P-v diagram, the process can be represented as a vertical line from the initial saturated liquid state to the final superheated vapor state, crossing the saturation lines.
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South High School still displays with great pride the large sign boasting of their 1996 State Championship Girl’s Basketball Team. The 46.6-kg sign hangs from two cables which make an angle of 35° with the horizontal. Determine the tension in each of the cables, in newtons (N).
Use the approximation g ≈ 10 m/s2.
The tension in each of the cables is approximately T1 = 267.5 N and T2 = -267.5 N.
The tension in each of the cables can be determined using trigonometry. Let's denote the tension in the first cable as T1 and the tension in the second cable as T2.
To find T1 and T2, we can use the following equations:
\(T1 * sin(35) - T2 * sin(35) = 46.6 kg * 10 m/s^2 (equation 1)\)
\(T1 * cos(35) + T2 * cos(35) = 0 (equation 2)\)
Simplifying equation 2, we get:
\(T1 * cos(35) = -T2 * cos(35)\)
Dividing both sides by cos(35°), we find:
\(T1 = -T2\)
Substituting this into equation 1, we get:
\(-T2 * sin(35) - T2 * sin(35) = 46.6 kg * 10 m/s^2\)
Simplifying further, we have:
\(-2 * T2 * sin(35) = 466 N\)
Dividing both sides by -2 * sin(35°), we find:
\(T2 = 466 N / (-2 * sin(35)) = -267.5N\)
Using this value of T2, we can determine T1 by substituting it back into equation 2:
\(T1 = -T2 = -466 N / (-2 * sin(35)) = 267.5N\)
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Four small spheres, each charged to +35 nC , form a square 8.0 cm on each side. From far away, a proton is shot toward the square along a line perpendicular to the square and passing through its center.
The speed with which the proton is shot along the perpendicular line to the square is calculated to be 435 × 10⁴ m/s.
Charge on each sphere = 35 n C = 35 × 10⁻⁹ C
Side of each square is given as 8 cm = 0.08 m.
Distance of centre of square from any charge r = √2l/2 = r= √2 × 0.08/ 2
r = 0.02m
The square's centre's electric potential is determined by:
Vc = 4 × (kq/r)
The electric potential at a distant place is V ∞ = 0.
Potential Energy difference between the two point is,
ΔV = Ve - V∞
ΔV = 4×(kq/r)
For the proton to pass through the centre of square the proton must have kinetic energy equal to the potential energy at the centre of the square.
The proton's kinetic energy is K = mv²
where,
m is mass
v is velocity
The proton's potential energy is U = eΔV
where,
ΔV is potential
For the proton to pass through,
K(at ∞) = U(Centre)
1/2 mv² = 4kqe/ r
v = √(8 k q)/( m r)
v = √(8 × 9 × 10⁹ × 55 × 10⁻⁹ × 1.6 × 10⁻¹⁹)/ (1.67 × 10⁻²⁷ × 0.02) m/s = (6336× 10⁸)/0.0334 = 435 × 10⁴ m/s
The question is incomplete. The complete question is 'What minimum initial speed does the proton need to pass through the square of charges?'
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Calculate the angular separation θ1 at which two point sources of wavelength 600 nanometers are just resolved when viewed through a circular aperture of diameter 1.5 centimeters. Express your answer in radians to three significant figures.
4.88×10⁻⁵rad is the angular separation θ1 at which two point sources of wavelength 600 nanometers are just resolved when viewed through a circular aperture of diameter 1.5 centimeters.
What is angular separation?The angle between two sightlines or between two point objects as seen by an observer is known as angular distance (also called as angular separation, apparent distance, and apparent separation).
All of the natural sciences and mathematics make use of angular distance, particularly geometry and trigonometry. It appears with angular velocity, angular acceleration and torque in the classical mechanics of spinning objects.
The angular separation is calculated as given below.
θ =1.220 ×λ/d
= 1.220 ×600×10⁻⁹/1.5×10⁻²
=4.88×10⁻⁵rad
Therefore, the angular separation is 4.88×10⁻⁵rad.
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The brightness of a star decreases by the square of the distance. This is known as:.
Answer:
inverse-square law.
Explanation:
Since the area increases as the square of the distance, the brightness of the light must decrease as the inverse square of the distance.
hope this helped you!
. An ice cube is placed in a glass of water. The cube is 1.5 cm on each side and has a density of 0.933 g/cm. What is the magnitude of the buoyant force on the ice? 2. A block of wood has a density of 0.820 g/cm and dimensions of 13.0 cm, 7.0 cm, and 2.0 cm. How large a force will just submerge the block in a vat of oil with a density 0.920 g/cm"? 3. A table-tennis ball has an average density of 0.083 g/cm and a diameter of 3.8 cm. How large a force can just submerge the ball in water? (p, = 1.000 g/cm3) N
As per the details given, the force required to submerge the block of wood in oil is approximately 2.406 N. the force required to submerge the table-tennis ball in water is approximately 0.462 N.
To calculate the amount of the buoyant force on the ice cube, first establish its volume and then apply Archimedes' principle.
Volume of the ice cube = \(s^3\) = \((1.5 cm)^3\) = 3.375 \(cm^3\)
Buoyant force = Weight of the displaced water
Buoyant force = Density of water * Volume of the ice cube * Acceleration due to gravity
Density of water (ρ_water) = 1.000 \(g/cm^3\)
Acceleration due to gravity (g) = 9.8 \(m/s^2\)
So,
Buoyant force = (ρ_water * Volume of the ice cube * g) / 1000
Buoyant force = (1.000 * 3.375 * 9.8) / 1000
Buoyant force ≈ 0.033 N
The magnitude of the buoyant force on the ice cube is approximately 0.033 N.
To determine the power necessary to immerse the block of wood in oil, we must first calculate its volume and then apply Archimedes' principle.
Volume of the block = L * W * H = 13.0 cm * 7.0 cm * 2.0 cm
Force = Weight of the displaced oil
Force = Density of oil * Volume of the block * Acceleration due to gravity
Force = (ρ_oil * Volume of the block * g) / 1000
Force = (0.920 * Volume of the block * 9.8) / 1000
Force ≈ 2.406 N
The force required to submerge the block of wood in oil is approximately 2.406 N.
To determine the force necessary to sink the table tennis ball in water, first calculate the volume of the ball and then apply Archimedes' principle.
Volume of the ball = (4/3) * π * \((d/2)^3\)
Force = Weight of the displaced water
Force = Density of water * Volume of the ball * Acceleration due to gravity
Force = (ρ_water * Volume of the ball * g) / 1000
Force = (1.000 * Volume of the ball * ) / 1000
Force ≈ 0.462 N
Thus, the force required to submerge the table-tennis ball in water is 0.462 N.
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15. If a wire carrying an electric current is placed from the floor of this room to the ceiling straight up and down and the current is flowing down (negative at ceiling and positive at the floor) describe the magnetic field around this wire..
The electric current flows through a wire, a magnetic field is generated around the wire. This magnetic field is circular and perpendicular to the direction of the current flow, meaning that it forms concentric circles around the wire.
The case of the wire in question, the magnetic field would also be circular and perpendicular to the direction of the current flow. However, since the wire is placed from the floor to the ceiling straight up and down, the magnetic field would also be vertically oriented. The strength of the magnetic field would depend on the magnitude of the current flowing through the wire. The greater the current, the stronger the magnetic field. Additionally, the distance from the wire would also affect the strength of the magnetic field. The field strength decreases as the distance from the wire increases. Overall, the magnetic field around the wire would be a circular, vertically oriented field that is proportional to the magnitude of the current flowing through the wire.
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I need help in physics, pls hurry! I will give Brainliest for correct answers!!
What is the speed of a runner that runs 400m in 48.42 seconds?
Answer:
The speed is that it would take 121.05 seconds to run a kilometer.
Explanation:
Since there are 1000 meters in a kilometer, divide 400 meters by 4, and 48.42 by 4. Then you get 100 meters equals 12.105 seconds. Multiply that by ten, and you get 121.05 seconds
In a particular region of space, the electric potential is given by V(x)=NUMBER 1 -NUMBER 2. What is the x component of the force on a charge (q) located at (x)?
To determine the x component of the force on a charge (q) located at (x), we need to take the derivative of the electric potential with respect to x. This gives us the electric field, E(x) = -dV/dx.
Once we have the electric field, we can use the equation F = qE to find the force on the charge. The x component of the force is then given by Fx = qEx.
So, to summarize:
- Electric potential: V(x) = NUMBER 1 - NUMBER 2
- Electric field: E(x) = -dV/dx
- Force: F = qE
- X component of force: Fx = qEx
Therefore, to find the x component of the force on the charge (q) located at (x), we need to first find the electric field by taking the derivative of the electric potential with respect to x.
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the same force is applied to two skateboards one rolls across the room and the other moves a few feet and comes to stop where was more work done
the skateboard that travel disorder distant shows more work because there was more resistance
The skateboard that moves a greater distance will have done more work than the one that moves a smaller distance.
Work is defined as the amount of energy required to move an object over a certain distance, and it is calculated by multiplying the force applied to the object by the distance over which the force is applied.
In this case, if the same force is applied to two skateboards, the skateboard that rolls across the room will have done more work than the other one that moves a few feet and comes to stop.
This is because the work done is directly proportional to the distance over which the force is applied, the skateboard that moves a greater distance will have done more work than the one that moves a smaller distance.
Note that work is a scalar quantity and not a vector one, it means that work can be positive or negative but the direction is not important, also the force applied and the distance over which the force is applied must be in the same direction.
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A college student likes to take her books to class by placing them in a box and pulling the box around behind her. She pulls on the box with a force of 90.0 N at an angle of 30.0⁰ relative to the horizontal. The box of books has a mass of 20.0 kg and the coefficient of kinetic friction between the bottom of the box and the sidewalk is 0.500. What is the net force acting horizontally and what is the acceleration of the box as she pulls it around?
Answer:
It would result an a negatice answer.
Explanation:
The accelarion should be pulled as a kite not a box :) columbus said that musical stuff no just no
Hope this helps!!
- Katty queen
A box is being pushed across the floor at a constant velocity with an
applied force of 30N, what is the magnitude of the frictional force acting
on this box?
Answer:
Magnitude of frictional force = 30 N
Explanation:
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
Fn=m.a
The net force is the vector addition of each individual force. If the sum of all the forces acting on an object is zero, then the acceleration is zero. That means the object moves at a constant speed or is at rest.
When an object is pushed across a horizontal rough surface, there are two forces acting in the direction of the motion: The applied force and the frictional force.
If the applied force is greater than the frictional force, then the object moves at a constant positive acceleration. If the frictional force is greater than the applied force, then the object won't move at all (if it was at rest) or will start a deaccelerated motion (braking).
Finally, if both forces are equal, the object will move at a constant speed or remains at rest. Since the box is moving at a constant speed, we can conclude the frictional force equals the applied force:
Magnitude of frictional force = 30 N
the average temperature of mars is lower than that of earth. if a distant observer measures the infrared radiation from both mars and earth, then
If a distant observer measures the infrared radiation from both Mars and Earth, they would find that Earth emits more infrared radiation than Mars.
If a distant observer measures the infrared radiation from both Mars and Earth, they would observe that Mars emits less infrared radiation compared to Earth. This is because the average temperature of Mars is much lower than that of Earth, and objects with lower temperatures emit less infrared radiation. Therefore, the observer would detect more infrared radiation coming from Earth compared to Mars.
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A distant observer measuring the infrared radiation from both Mars and Earth would observe that Mars emits less infrared radiation than Earth, indicating a lower average temperature.
When the temperature of is about absolutely zero, all bodies emits infrared radiations. This amount of radiation highly depends on the temperature of the body.
As we assume this, Mars has a lower average temperature as compared to Earth, Mars emits less IR rays. Therefore, a distant observer measuring the infrared radiation from both planets would observe that Mars emits less radiation than Earth. Hence, this is the logic we are using to conclude that there is a lower temperature on Mars than Earth.
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april has 3 hours to spend training for an upcoming race. she completes her training by running full speed the distance of the race and walking back the same distance to cool down. if she runs at a speed of 10mph and walks back at a speed of 2mph , how long should she plan to spend walking back?
April should plan to spend walking back after 3 hours training for an upcoming race and runs at a speed of 10mph and walks back at a speed of 2mph = 30 minutes.
How to determine the time to spend walking back?First, determine the distance,
d = speed x time
The distance = 10
The speed = 2 mph
The time = (3 - x hours)
Let's say 'x' represents the amount of time spent running in hours, and 3-x represents the amount of time spent walking in hours.
Hence,
10x = 2(3 - x)
10x = 6 - 2x
12x = 6
x = \(\frac{1}{2}\) hour
= 30 minutes
So, April should she plan to spend walking back in 30 minutes.
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2. If you are sitting on the passenger side of a car driving down the
highway, name a frame of reference that indicates you are NOT moving?
Answer:
The building are not getting farther and farther away, road signs, exits, other cars
Explanation:
I have an unknown volume of gas at a pressure of 0.500 atm and a temperature of 325 K. If I raise the pressure to 1.20 atm, decrease the temperature to 320. K, and measure the final volume to be 48.0 liters, what was the initial volume of the gas?
Answer:
117
Explanation:
the formula is P1V1 over T1 is equals to P2V2 over T2
A 10,000 litres of kerosene tank is to be emptied using a pump. The density of oil is rho=0.75 kg/ litre. If the pump takes 45 minutes to fully empty the tank, what is the mass flow rate of the pump? 222.2 LPM 13.3 m3/h 2.8 kg/s 3.7 L/s
The mass flow rate of the pump is 2.8 kg/s.
Given the density of the oil (kerosene) to be ρ= 0.75 kg/L
The volume of oil is equal to 10,000 L1 L = 0.001 m³Volume of oil = 10,000 × 0.001 = 10 m³Density of oil = mass/volume ⇒ mass = density × volume
Let m be the mass of oil.
m = ρV = 0.75 × 10 = 7.5 kg
The time taken to empty the tank is 45 minutes. 1 minute = 60 seconds
The time taken is t = 45 × 60 = 2,700 seconds.
Let the mass flow rate be m′. The mass flow rate is defined as the mass of fluid flowing per unit time.m′ = m/t = 7.5/2,700 kg/s= 0.00278 kg/s
Therefore, the mass flow rate of the pump is 2.8 kg/s.
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A 3.00 V battery is connected to the ends of a length
of constantan wire of resistance 12.1 Ohms. Calculate the
charge that flows through the wire in 60 s. Write down
any equations you use. Give your answer to three
significant figures.
Charge=
______C [5 marks]
Answer: The charge that flows through the wire in 60 s is 14.87 C.
Explanation: The charge that flows through the wire in 60 s can be calculated using the formula:
Charge = Current x Time
The current can be calculated using Ohm’s law:
Current = Voltage / Resistance
Substituting the given values:
Current = 3.00 V / 12.1 Ohms = 0.2479 A
Charge = 0.2479 A x 60 s = 14.87 C
Hope this helps, and have a great day! =)
up until and including the point of the maximum static frictional force. what is the relationship between the opposing forces that you measure?
The relationship between the opposing forces up until and including the point of the maximum static frictional force can be described as being equal and opposite.
This is because the maximum static frictional force is the point at which the applied force is equal and opposite to the frictional force. At this point, the opposing forces are balanced, meaning that the object remains at rest and does not move.
However, if the applied force exceeds the maximum static frictional force, the object will start to move, and the relationship between the opposing forces will shift to one where the applied force becomes greater than the frictional force.
Up until the point of the maximum static frictional force, the opposing forces are equal and opposite, but beyond this point, the applied force becomes greater than the frictional force.
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An electron moving parallel to a uniform electric field increases its speed from 2.0 × 10^7 m/s to 4.0 × 10^7 m/s over a distance of 1.4 cm. What is the electric field strength?
The electric field strength is approximately -3.34 × 10^29 newtons per coulomb (N/C).
How to solve for the fieldTo determine the electric field strength, we can use the following equation that relates the change in speed of a charged particle to the electric field strength:
Δv = a * Δt
Where:
Δv is the change in velocity (speed) of the electron
a is the acceleration of the electron
Δt is the time taken
Given:
Initial velocity (v1) = 2.0 × 10^7 m/s
Final velocity (v2) = 4.0 × 10^7 m/s
Distance (d) = 1.4 cm = 0.014 m
The change in velocity can be calculated as:
Δv = v2 - v1
Δv = (4.0 × 10^7 m/s) - (2.0 × 10^7 m/s)
Δv = 2.0 × 10^7 m/s
We can rearrange the equation to solve for acceleration (a):
a = Δv / Δt
To find the time (Δt), we can use the equation:
d = (1/2) * a * Δt^2
Rearranging this equation to solve for Δt:
Δt = sqrt((2 * d) / a)
Substituting the given values:
Δt = sqrt((2 * 0.014 m) / (2.0 × 10^7 m/s))
Δt = sqrt(1.4 × 10^(-8) s^2 / m^2)
Δt = 3.74 × 10^(-4) s
Now we can calculate the acceleration (a):
a = Δv / Δt
a = (2.0 × 10^7 m/s) / (3.74 × 10^(-4) s)
a = 5.35 × 10^10 m/s^2
Finally, we can find the electric field strength (E) using the equation:
E = a / q
Where q is the charge of the electron. The charge of an electron is approximately -1.6 × 10^(-19) coulombs.
E = (5.35 × 10^10 m/s^2) / (-1.6 × 10^(-19) C)
E ≈ -3.34 × 10^29 N/C
The electric field strength is approximately -3.34 × 10^29 newtons per coulomb (N/C).
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Which statement describes a socialist government?
Answer:
Socialism is a political, social, economic philospohy. Socialist governtment is a form of governtment in which the means of production are owned by the government of the country.
Explanation:
(i thought you could find this in google)
Answer:
Socialism is a political, social, and economic philosophy encompassing a range of economic and social systems characterized by social ownership of the means of production. ... Social ownership can be public, collective, cooperative, or of equity. Socialism is an economic and political system. It is an economic theory of social organization. It states that the means of making, moving, and trading wealth should be owned or controlled by the workers. This means the money made belongs to the workers who make the products, instead of groups of private owners.Socialist government is a form of government in which the means of production are owned by the government of the country. Social systems in this form of government are the ones are divided into the market and the non market forms. The means of transportation are controlled by the government here.
4.- Una vagoneta de 1000 kg de peso parte del reposo en el punto 1 y desciende, sin rozamiento, por la vía indicada en la figura. A) Calcular la fuerza que la vía ejerce sobre la vagoneta en el punto 2, donde el radio de curvatura es de 6 m. B) Determinar el mínimo valor del radio de curvatura en el punto 3 para salvar dicho punto
Answer:
A) 49,050 N
B) 16 m
Explanation:
Question:
El dibujo de la pregunta se obtiene de un documento titulado "TRABAJO DIVERSO Y ENERGÍA" que se encuentra en línea y se presenta aquí.
La masa dada del vagón, m = 1,000 kg
La altura del punto en el que descansa el vagón, punto 1, h₁ = 12 m
A) El radio en el punto 2, el punto más bajo, R = 6 m
La fuerza, 'N', que la vía ejerce sobre el vagón en el punto 1 viene dada por la siguiente relación;
N = El peso del vagón + La fuerza de movimiento del vagón
∴ N = m × g + m × a
Dónde;
g = La aceleración debida a la gravedad ≈ 9,81 m / s²
a = La aceleración del vagón
Observamos que para el movimiento circular, la fuerza de movimiento del vagón, m × a = La fuerza centrípeta que actúa sobre el vagón = m × v² / R
∴ m × a = m × v² / R
Dónde;
v² = La velocidad del vagón en el punto 2 = 2 · g · h₁
Por lo tanto;
N = m × g + m × a = m × g + m × v² / R = m × g + m × 2 · g · h₁ / R
∴ N = 1000 × 9,81 + 1000 × 2 × 9,81 × 12/6 = 49,050
La fuerza que ejerce el vagón en el punto 2, N = 49,050 N
B) En el punto 3, tenemos;
N = m · g - m · a₃
La fuerza centrípeta en el punto 3, m · a₃ = m · v₃² / R₃
∴ La altura en el punto 3, h₃ = 4 m
El cuadrado de la velocidad en el punto 3, v₃² = 2 · g · (h₁ - h₃)
Para que el vagón esté seguro en el punto 3, la fuerza de la vía sobre el vagón, N = 0 para que el vagón permanezca en la vía actuando
Por lo tanto;
N = m · g - m · a₃ = 0
m · g = m · a₃ = m · v₃² / R₃ = m · (2 · g · (h₁ - h₃)) / R₃
∴ R₃ = (2 · g · (h₁ - h₃)) / g = (2 · (h₁ - h₃)) = 2 × (12 - 4) = 16
El radio de curvatura en el punto 3 para que el punto sea seguro es R₃ = 16 m.
The text discussed the magnetic field of an infinitely long, straight conductor carrying a current. Of course, there is no such thing as an infinitely long anything. How do you decide whether a particular wire is long enough to be considered infinite
In practice, the concept of an infinitely long conductor is used as an approximation when the length of the conductor is much larger compared to other relevant distances in the system.
The assumption of an infinitely long conductor is a simplifying approximation used in certain physics and engineering problems. It allows for easier calculations and provides reasonably accurate results under certain conditions. However, in reality, no physical object can have infinite length.
The decision to treat a wire as infinitely long depends on the context and the specific problem being addressed. It is typically based on a comparison of the wire's length with other relevant dimensions in the system.
If the length of the wire is significantly larger compared to other distances involved, such as the distances between other conductors or the size of the magnetic field region of interest, then treating the wire as infinitely long may yield acceptable results.
However, if the length of the wire is comparable to or smaller than other relevant distances, a more precise analysis considering the finite length of the conductor becomes necessary. The level of accuracy required in the analysis also plays a role in deciding whether to treat the wire as infinite or finite.
In summary, the decision of whether a particular wire is long enough to be considered infinite depends on the specific problem and the relative magnitudes of the wire's length and other relevant distances in the system.
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5/100 is the same value as
Answer:
5/100 =120=0.05or 5%
Explanation:
I had this same thing this morning
What height will the object reach? 12 points. Will give brainliest.
Answer:
12.7 m
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 56.7 Km/hr
Maximum height (h) =..?
First, we shall convert 56.7 Km/hr to m/s. This can be obtained as follow:
Initial velocity (m/s) = 56.7 x 1000/3600
Initial velocity (m/s) = 15.75 m/s
Next, we shall determine the time taken to get to the maximum height. This can be obtained as follow:
Initial velocity (u) = 15.75 m/s
Final velocity (v) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
v = u – gt (since the ball is going against gravity)
0 = 15.75 – 9.8 × t
Rearrange
9.8 × t = 15.75
Divide both side by 9.8
t = 15.75/9.8
t = 1.61 secs.
Finally, we shall determine the maximum height as follow
h = ½gt²
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) = 1.61 secs.
Height (h) =..?
h = ½gt²
h = ½ × 9.8 × 1.61²
h = 4.9 x 1.61²
h = 12.7 m
Therefore, the maximum height reached by the ball is 12.7 m
Drag each tile to the correct box.
Match the job title to its primary function.
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computer system engineer
online help desk technician
document management specialist
provide remote support to users
data scientist
analyze unstructured, complex information to find patterns
design and implement systems for data storage
implement solutions for high-level technology issues
G
Those who work in computer assistance often have strong problem-solving, communication, and analytical skills as well as a broad knowledge of technology.
How does a technician perform their job?An expert worker who services, installs, replaces, and fixes various systems and pieces of equipment is known as a technician. Depending on the situation, a technician spends their days working on a variety of duties like problem analysis, test administration, and equipment repair.
An engineer is what kind of employee?A technician is an employee in the technological industry who possesses the necessary ability and technique as well as a practical comprehension of the theoretical underpinnings.
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katie measured the distance her friend morgan ran on a straight track every 2s. her measurements are recorded in the table below. what was morgan’s average speed? what was her acceleration for the entire trip?
Answer:
The average speed of her is 2 m/s.
The acceleration for the entire trip is 0.2 m/s²
Explanation:
Given that,
katie measured the distance her friend morgan ran on a straight track every 2s.
According to given chart,
We need to calculate the average speed
Using formula of average speed
\(v_{avg}=\dfrac{D}{T}\)
Where, D = total distance
T = total time
Put the value into the formula
\(v_{avg}=\dfrac{20}{10}\)
\(v_{avg}=2\ m/s\)
We need to calculate the acceleration for the entire trip
Using equation of motion
\(v=u+at\)
\(2=0+a\times10\)
\(a=\dfrac{2}{10}\)
\(a=0.2\ m/s^2\)
Hence, The average speed of her is 2 m/s.
The acceleration for the entire trip is 0.2 m/s²
An object speeding up, an object slowing down, and an object changing direction are all examples of acceleration.
-True
-False
When an object is speeding up, the acceleration is in the same direction as the velocity. Thus, this object has a positive acceleration. In Example B, the object is moving in the negative direction (i.e., has a negative velocity) and is slowing down.
While spinning down from 500. 0 rpm to rest, a solid uniform flywheel does 5. 1 kj of work. If the radius of the disk is 1. 2 m, what is its mass?.
While spinning down from 500. 0 rpm to rest, a solid uniform flywheel does 5. 1 kJ of work. If the radius of the disk is 1. 2 m, its mass will be 28.33 kg
Work done = change in kinetic energy
kinetic energy = 1/2 * I * \(omega^{2}\)
since , moment of inertia of disk = m\(r^{2}\) / 2
kinetic energy = 1/2 * m\(r^{2}\) / 2 * \(omega^{2}\)
5100 = 1/4 * m * \(1.2^{2}\) * 500
mass = 28.33 kg
If the radius of the disk is 1. 2 m, its mass will be 28.33 kg
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