When the ends of two bar magnets are near each other, they attract one another. The ends must be...
a. one north, the other south
b. both north
c. both south
d. either b or c

Answer:

  A.  The forces are the same size and in opposite directions.

Explanation:

Just as an opposite number will cancel a number: -1 +1 = 0, so an opposite force will cancel a force, with the result that the net is zero.

Its A The force are the same size and in opposite direction

From the question, we can see that the momentum is a vector thus the change in the momentum with respect to the ground observer ought to be zero.

The term momentum has to do with the  product of the mass and the velocity of a body. Let us recall that the momentum of a body is a vector quantity thus we have to consider the magnitude as well as the direction of the vector.

With this said, we are going to consider the question more critically. We are told that; a  ball travels along a straight path, perpendicular to a wall. The ball bounces off the wall and returns with the same magnitude of momentum, p, with respect to a ground observer at rest.

Looking at the fact that the momentum of the body is a vector and we have seen told that the ball bounces off the wall and returns with the same magnitude of momentum the  it follows that the change in the momentum is zero.

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Missing parts;

A ball travels along a straight path, perpendicular to a wall. The ball bounces off the wall and returns with the same magnitude of momentum, p, with respect to a ground observer at rest. What expression shows the change in momentum as observed by the ground observer?

a. 0

b 0.5p

c 2p

d 1.5p

An object is placed along the axis of a concave mirror halfway between its focus and center of curvature. The image is formed at a distance f from the concave mirror.

The given mirror is a concave mirror. The object is placed at a distance, u = (R/2), from the concave mirror. Here, R = 2f (given). The magnification produced by the concave mirror is given by the relation, m = (-v/u)

For concave mirror, f is negative, (f = -R/2 = -R/2 = -2f/2 = -f)u = + R/2v = -f. By using the mirror formula,1/f = 1/v + 1/u we get, 1/f = 1/-f + 2/R we get, 1/f = -1/f + 2/2ff = 2ff = 2(R/2) ƒ = R = 2f

So, the image is formed at the same distance (R/2) from the concave mirror as the object is placed from the concave mirror. So, the distance of the image from the mirror is R/2 = 2f/2 = f

Hence, the image is formed at a distance f from the concave mirror.

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The female skater moves backward at a speed of 3 m/s. The post-impulse speed of the male skater is 2.08m/s.

Momentum (linear) along, say, the x-axis is:

p=mv

so we have for the 2 skaters system:

\(p_before = p_after\)

(45.0)+(65.0)= (45*3)+(65*v)

v= - 135/65= -2.08m/s

Speed in physics refers to how fast an object is moving. It is a scalar quantity that only takes into account the magnitude of the velocity of the object, not its direction. The speed of an object can be calculated by dividing the distance it travels by the time it takes to travel that distance. The SI unit of speed is meters per second (m/s), but other units such as miles per hour (mph) or kilometers per hour (km/h) can also be used.

Speed can be constant, meaning the object is moving at a steady rate, or it can be changing, meaning the object is accelerating or decelerating. Acceleration is the rate at which an object's speed changes over time, and it is typically measured in meters per second squared (m/s^2).

The concept of speed is fundamental to many areas of physics, including mechanics, thermodynamics, and electromagnetism. It is also a critical component of everyday life, influencing how we travel, communicate, and interact with the world around us.

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Answer:

v=m/s m=v.s -1*3= -3 meter/second

The velocity of the elevator after 3 seconds will be equal to 3 m/s.

We have three equations of motion that can be used to calculate components such as displacement(s), initial (u) and final velocity (v), time(t), and acceleration(a). The expressions for the three equations of motion are as follows:

First Equation of Motion :

v = u + at

Second Equation of Motion :

S = ut + (1/2) at²

The third equation of motion is:

v² - u² =2aS

Given, the initial velocity (u) of the elevator is zero as the elevator is at rest initially.

The acceleration of the elevator, a = -1 m/s² moving downward.

The  final velocity of the elevator after 3 seconds will be:

v = u + at

v = (0) + (-1 m/s²) (3 s)

v = - 3 m/s

Therefore, the velocity of the elevator after 3 seconds will be equal to 3 m/s in the downward direction.

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Using the overland flow method, the time of concentration (tc) for a watershed with a 1000-foot long maximum flow path and a 0.2% slope in a paved shopping center parking lot is determined to be [calculate and provide the time in minutes].

To calculate the time of concentration (tc) using the overland flow method, we consider the various land uses, slopes, and lengths of flow paths within the watershed. In this case, the watershed has a maximum flow path of 1000 feet and a slope of 0.2% in a paved shopping center parking lot.

To calculate the time of concentration, we first determine the velocities for each land use. Using the Manning's equation, the velocity (V) for the paved shopping center parking lot can be calculated. We then divide the length of each flow path by the velocity to obtain the individual travel times for each land use.

Next, we sum up the individual travel times for each land use to calculate the total time of concentration (tc) for the watershed. This represents the time it takes for the runoff to flow from the most remote point to the point of interest within the watershed.

By performing the necessary calculations and plugging in the given values, we can determine the specific time of concentration for this particular watershed.

The overland flow method and its application in determining the time of concentration for different types of watersheds and land uses to assess the hydrological characteristics and flow patterns.

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The magnitude of the total resistive force acting on the car (due to friction, air resistance, etc.) is 2048.36 N.

Calculating total resistive force:

A car needs to generate 75.0 hp to maintain a constant velocity of 27.3 m/s on a flat road. The magnitude of the total resistive force acting on the car (due to friction, air resistance, etc.) can be calculated using the following steps:

Step 1: Convert horsepower to watts1 hp = 746 watts75.0 hp = 75.0 × 746 = 55,950 watts

Step 2: Calculate the power required to overcome the force acting on the car. It can be calculated using the formula: P = F × v where P =  power, F = resistive force, and v = velocity.

P = 55,950 watts (from Step 1) v = 27.3 m/s (given)

Therefore, content loaded power (P) = F × vF = P/vF = 55,950/27.3F = 2048.36 N

Step 3: Find the magnitude of the total resistive force: The magnitude of the total resistive force that is equal to the power. Therefore, the magnitude of the total resistive force acting on the car is 2048.36 N.

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Answer:

The answer is A. Fluid and white blood cells move into the tissue from nearby blood  vessels.

Explanation:

Answer:

A is the Answer

Explanation:

I took the test

Answer:

plants because of photosynthesis humans because of food and the energy causing cells in it and batteries or solar panels because of the sun.

Explanation:

Answer:

proportional...?

Explanation:

not sure if thats correct...

hope this helped tho

try your best!

mark me brianliest :D

The position of the mass as a function of time is x(t) = 5 * sin(4t).

To find the position of the mass as a function of time, we can use Newton's second law of motion, which states that the sum of the forces acting on an object is equal to the mass of the object multiplied by its acceleration.

The equation of motion for a mass-spring system is given by:

m * d^2x/dt^2 + k * x = F(t)

Where:

m is the mass connected to the spring,

x is the position of the mass,

t is time,

k is the spring constant,

F(t) is the applied force as a function of time.

In this case, the mass m is 2 kg, the spring constant k is 32 N/m, and the applied force is given by F(t) = 128sin(4t).

Plugging these values into the equation of motion, we get:

2 * d^2x/dt^2 + 32 * x = 128sin(4t)

Rearranging the equation, we have:

d^2x/dt^2 + 16 * x = 64sin(4t)

This is a second-order linear ordinary differential equation with constant coefficients. To solve this equation, we can assume a solution of the form x(t) = A * sin(ωt + φ), where A is the amplitude, ω is the angular frequency, and φ is the phase angle.

Differentiating x(t) twice with respect to time, we have:

dx/dt = A * ω * cos(ωt + φ)

d^2x/dt^2 = -A * ω^2 * sin(ωt + φ)

Substituting these derivatives into the equation of motion, we get:

-A * ω^2 * sin(ωt + φ) + 16 * A * sin(ωt + φ) = 64sin(4t)

Equating the terms with sin(ωt + φ) on both sides, we have:

-A * ω^2 + 16 * A = 64

Simplifying the equation, we get:

16A - Aω^2 = 64

We know that the angular frequency ω is related to the spring constant k and the mass m as ω = √(k/m). Substituting the given values, we have:

ω = √(32 N/m / 2 kg) = √(16) = 4

Plugging ω = 4 into the equation, we get:

16A - 16 = 64

Solving for A, we have:

16A = 80

A = 5

Therefore, the amplitude A is 5.

Now, we can write the position function as:

x(t) = 5 * sin(4t + φ)

To find the phase angle φ, we can use the initial conditions. At t = 0, the spring is initially at rest and hanging at its equilibrium position, which means x(0) = 0.

Plugging this into the position function, we have:

0 = 5 * sin(0 + φ)

Since sin(0) = 0, we get:

0 = 0 + φ

φ = 0

Therefore, the phase angle φ is 0.

Finally, the position of the mass as a function of time is:

x(t) = 5 * sin(4t)

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The amplitude of the pulse is 3 m, the equation of the pulse as a function of position and time is y(x) = 6/{(x - 3t)² + 2} m and the pulse is 15 m centred at time t = 5. 00s.

y(x) = 6/(x² + 2)

v = 3 m/s

The amplitude(A) of the pulse:

When x= 0, Then y = A

Put x= 0  

y(x) = 6/(x² + 2)

y(0) = 6/(0² + 2)

y = A = 3 m

Distance travel in time t  

x = vt

x = 3 t

y(x) = 6/{(x - 3t)² + 2}

The distance covered by the pulse in the time 5 s

D = v t

D = 3 x 5  

D = 15 m

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About  11.2 grams of water would form when the temperature drops by 20 degrees Celsius, given the initial conditions of 56% relative humidity and a temperature of 17 degrees Celsius.

The amount of moisture in the air as opposed to the maximum amount that air can contain at a given temperature is known as relative humidity (RH). A percentage is used to represent it.

Temperature and the actual volume of water vapor in the air have an impact on relative humidity. Even while the actual amount of moisture doesn't change when the temperature varies, warm air can hold more moisture than cold air, which causes the relative humidity to fluctuate.

The air is saturated, or unable to contain any more moisture, at a relative humidity of 100%, and condensation or precipitation is expected to take place. On the other hand, the air is comparatively dry when the relative humidity is low.

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Answer:

pls mrk me brainliest

Explanation:

Hydrostatic pressure is the pressure exerted by a fluid at equilibrium at any point of time due to the force of gravity. Hydrostatic pressure is proportional to the depth measured from the surface as the weight of the fluid increases when a downward force is applied. The hydrostatic pressure at any point in a fluid can be calculated by using the formula:

P = P0 + ρgh

where P is the hydrostatic pressure, P0 is the atmospheric pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the point from the surface.

a) In which fluid is pressure of 610 kPa first achieved?

It can be found out by adding up the hydrostatic pressures of each layer of fluid until we reach 610 kPa. Starting from gas layer:

Pgas = 60 kPa + (1 kg/m3)(9.81 m/s2)(1 m) = 60.00981 kPa

Palcohol = Pgas + (780 kg/m3)(9.81 m/s2)(60 m) = 460.00981 kPa

Poil = Palcohol + (840 kg/m3)(9.81 m/s2)(10 m) = 542.40981 kPa

Pwater = Poil + (990 kg/m3)(9.81 m/s2)(2 m) = 561.60981 kPa

Pglycerine = Pwater + (1236 kg/m3)(9.81 m/s2)(3 m) = 605.46981 kPa

Pmolasses = Pglycerine + (1500 kg/m3)(9.81 m/s2)(10 m) = 752.96981 kPa

The pressure of 610 kPa is first achieved in glycerine layer.

b) If the bottom of the pipe is at zero elevation what is

b) If the bottom of the pipe is at zero elevation what isthe pressure at bottom in kpa?

The bottom of pipe corresponds to molasses layer so use it to calculate hydrostatic pressure as calculated above:

Pbottom = Pmolasses = 752.96981 kPa

c) At what elevation is pressure of 640kpa?

It can be found out by subtracting hydrostatic pressures from each layer until it reach below 640kpa and then use interpolation to find exact elevation.

Starting from molasses layer:

Pmolasses - Pglycerine= (752.96981 - 605.46981)kpa=147.5kpa

This means that somewhere between glycerine and molasses layers there is a point with pressure of 640kpa.

Let x be distance from top surface of molasses layer to this point then:

640kpa=605.4698+1500(9.8)x

x=0.023m

Therefore elevation from bottom surface of pipe to this point is:

10-0-0-023=9-977m

d) If an open manometer attached to side pipe anywhere on oily portion determine height liquid level manometer.

An open manometer measures difference between atmospheric pressure and fluid pressure inside pipe.

Let y be height liquid level manometer above oil level then:

Patm-Poil=yρg

y=(Poil-Patm)/ρg

y=(542-4098-101325)/(1000*9-8)

y=-44-6m

This means that liquid level manometer will be below oil level by -44-6m or oil level will be above liquid level manometer by +44-6m.

The correct statements are:

1.Most types of electromagnetic waves are not visible to ground-based telescopes.

2.There would be no limit to what an optical telescope in space could see.

3.The Chandra and Spitzer telescopes are all in space.

Ground-based telescopes are limited by the Earth's atmosphere, which absorbs or scatters many types of electromagnetic radiation. Only a narrow range of wavelengths, including visible light, radio waves, and some infrared and ultraviolet radiation, can penetrate the atmosphere and be observed from the ground.

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Answer:

Geomagnetic Field

Explanation:

Answer:

only long-range force that affects all particles is the gravitational force.

Explanation:

In nature there are four fundamental forces: nuclear, weak, gravitational and electrical.

The last two are long-range, that is, the forces are zero for infinite distances, the current gravitational on all the particles and the electric one acts on the charged particles, without the chosen charge it is zero, the forces is also zero.

Consequently the only long-range force that affects all particles is the gravitational force.

Step-by-step explanation :

Here we just need to see the resistors which are connected in series combination. (Remember that you need not to use the potential difference in this question because we aren't asked to calculate the current).

As we know that,

>> Rs = 50 + 100

>> Rs = 150Ω

Therefore,

Answer:

\( \huge \boxed{ \boxed{2 + \sqrt{3}}} \)

Explanation:

If the distance between two objects is 4.00 m and the distance is tripled, then the new distance will be 12.00 m.

To find out the new distance, you need to multiply the original distance by the factor by which it is tripled, which is 3.In other words, if the distance between two objects is "d", and it is tripled, then the new distance is 3d.

Using this formula, if the original distance is 4.00 m, then the new distance will be 3 x 4.00 m = 12.00 m.

The new distance is three times the original distance.

Therefore, the new distance between the two objects will be 12.00 meters if the original distance was 4.00 meters and it was tripled.

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a. The image includes galaxies that are elliptical, spiral, and irregular. b. Careful study of the image shows that the youngest galaxies were mostly irregular in shape.

e. We see the more distant galaxies as they were when they were quite young. c. The galaxies in this image are part of a large galaxy cluster, bound together by gravity is not a true statement. The Hubble Extreme Deep Field image is actually a composite of several images taken over a period of 10 years, capturing light from galaxies as far back as 13 billion years ago, showing a diverse range of galaxies in various stages of formation and evolution, but they are not part of a single galaxy cluster. d. Careful study of the image shows that all present-day galaxies are spirals is also not a true statement. While there are many spiral galaxies present in the image, there are also many elliptical and irregular galaxies, indicating a wide variety of galaxy types throughout the universe.

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Answer:

first

Explanation:

Newton's Newton's first law of motion states that for every action and there's an equal and opposite reaction

Answer:

D. Third

Explanation:

Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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If the skier is moving at a speed of 6.0 m/s when she is 2.0 m up the hill,  she will not make it to the top of the hill.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

According to question,

Speed of the skier: v = 6.0 m/s.

Acceleration due to gravity: g  = 9.8 m/s^2.

Height distance she can move = v²/2g =  1.84 m.

But she have to go (4-2) = 2 m.

So, she can't make it to the top of the hill.

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Answer:

60N

Explanation:

Given parameters:

Combined mass = 50kg

Acceleration  = 1.2m/s²

Unknown:

Force to propel  = ?

Solution:

From Newton's second law of motion, we know that;

       Force  = mass x acceleration

 So;

         Force  = 50 x 1.2  = 60N

Answer:

60N

Explanation:

Initial velocity (u) of the sports car = 0 (since it is at rest)Distance (s) travelled by the sports car at constant velocity = 120 mTime taken (t) to travel the distance = 5.0 sTime taken (t1) to come to a stop = 4.1 sThe equation for calculating the acceleration (a) of the sports car can be written as:

Distance (s) = (u × t) + (1/2 × a × t²)This equation is only valid when the sports car is moving with a constant acceleration. In this case, we will use a negative acceleration since the sports car is slowing down. When the sports car comes to a stop, its final velocity (v) will be 0.

Using the equation above:120 = (0 × 5.0) + (1/2 × a × 5.0²)Solving for a:60 = 12.5aTherefore, a = 4.8 m/s²This is the acceleration of the sports car when it was moving at constant velocity. When the sports car brakes and comes to a stop, its acceleration will be given by:a = (v - u) / t1where v is the final velocity of the sports car when it comes to a stop. Since v = 0, we have:a = - u / t1 = - (120 / 4.1) = - 29.27 m/s²Therefore, the magnitude of the sports car's acceleration (assumed constant) in m/s² is -7.3 m/s² (which is the absolute value of -29.27 m/s²).

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The direction of the magnetic force on a current-carrying wire reverses when the current in the wire is reversed.

When a current-carrying wire is placed in a magnetic field, it experiences a magnetic force, which is perpendicular to both the direction of the current and the direction of the magnetic field. This is known as the right-hand rule of electromagnetism. If the current in the wire is reversed, the direction of the magnetic force acting on the wire also reverses. However, the magnitude of the force remains the same.To understand this better, let's consider an example. Suppose a current-carrying wire is placed in a magnetic field directed upwards, and the current is flowing from left to right. In this case, the magnetic force acting on the wire is directed towards the observer. If we reverse the direction of the current, i.e., from right to left, the magnetic force acting on the wire will be directed away from the observer. This is because, according to the right-hand rule, the direction of the magnetic force is always perpendicular to the direction of the current and the direction of the magnetic field. Hence, the direction of the magnetic force changes when the current in the wire is reversed.

In conclusion, the direction of the magnetic force acting on a current-carrying wire changes when the direction of the current in the wire is reversed. However, the magnitude of the force remains the same.

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The question is asking whether it is possible to find a magnetic vector potential for a given uniform surface current flowing in the xy plane and generating a magnetic field for different regions of space.

To determine whether it is possible to find a magnetic vector potential for the given scenario, we need to consider the conditions that must be satisfied. In general, a magnetic vector potential A can be found if the magnetic field B satisfies the condition ∇ × A = B. This is known as the magnetic vector potential equation.

In the given situation, the magnetic field is different for the regions above and below the xy plane. For z > 0, the magnetic field is described as B = MoK -î, and for z < 0, it is described as B = -MoK -î. To find the magnetic vector potential, we need to determine if there exists a vector potential A that satisfies the equation ∇ × A = B in each region.

By calculating the curl of A, we can check if it matches the given magnetic field expressions. If the curl of A matches the magnetic field expressions for both regions, then it is possible to find a magnetic vector potential for the given scenario. However, if the curl of A does not match the magnetic field expressions, then it is not possible to find a magnetic vector potential that satisfies the conditions.

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