when isopropylbenzene (cumene) is treated with nbs and irradiated with uv light, only one product is obtained. propose a mechanism and explain why only one product is formed.

Answer:

D. C₂H₂ and C₆H₆

Explanation:

The empirical formula is the simplest formula of a compound. Every compound can be simplified or represented by an empirical formula.

So, from the given choices, the pair expressed as molecular formula and empirical formula is the fourth choice.

      C₂H₂ and C₆H₆

The number of atoms in the molecular formula  C₆H₆ is 6 carbon and 6 hydrogen.

We can simplify by dividing by 3 into   C₂H₂ which is the empirical formula.

Answer:

D- C2H2 and C6H6

Explanation:

I took the quiz

Answer: A The Triangle Fire was a tragedy that could have been prevented.

Explanation:

The Triangle Fire was a tragedy that happened in the factory of Shirtwaist Company in New York City where there was.a.fore outbreak and about 145 employees of the company were killed.

The deaths could have been prevented because the company neglected safety measures such as having a good and reliable pump system, having readily available fire extinguishers. Also, what resulted in the lethal nature of the incident was because the doors within the building of the factory were locked.

The tragedy generated lots of attention and series of laws were been out in place in order to ensure that workers are safe at their workplace.

The process that moves ions from an area of high concentration to an area of lower concentration is called diffusion.

Diffusion is the movement of particles or substances from an area of high concentration to an area of lower concentration until the concentration of the substance is uniform throughout the space.

Key points:

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Improper warm up causes heat exhaustion.

WHAT IS HEAT EXHAUSTION:

Therefore, improper warm up of the body can cause heat exhaustion.

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Answer:

The answer above me is wrong. its dehydration. I took the test and obviously the other person doesn't know what they are doing.

The volume a sample of nitrogen would occupy at 32◦c if the pressure were increased to 840 torr is approximately 7.7 liters.

To solve this problem, we can use the gas law equation, which is Boyle's Law: P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

P1 = 580 torr
V1 = 11.2 L
P2 = 840 torr
Temperature (T) remains constant at 32°C.

We want to find V2:

580 torr * 11.2 L = 840 torr * V2

Now, solve for V2:

V2 = (580 torr * 11.2 L) / 840 torr
V2 ≈ 7.7 L

So, if the pressure is increased to 840 torr at 32°C, the nitrogen sample would occupy approximately 7.7 liters.

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Answer:

carbon-12

Explanation:

carbon 6/12 isotope has 6 neutrones and it is considered as a metal.

The molarity, amount and volumes required are:

Molarity of a solution is defined as the number of moles of a solute dissolved in a given volume in litres of the solution.

molarity = 2/0.1

molarity = 20. M

molarity mass of potassium iodide = 166 g/mol

100 mL = 0.1 L

number of moles = 10/166 = 0.06 moles

Molarity = 0.06/ 0.1

Molarity = 0.6 M

.

Molarity = 0.427/0.855

Molarity = 0.50 M

1500 mL = 1.5 L

molar mass of aluminium carbonate = 87 g/mol

number of moles = 2340/87 = 26.9 moles

Molarity= 26.9/1.5

Molarity = 17.9 M

100 mL = 0.1 L

molarity = 2.0

number of moles = 2.0 × 0.1 = 0.2 moles

molar mass of potassium iodide = 166 g/mol

mass = number of moles × molar mass

mass = 0.2 × 166

mass of potassium iodide = 33.2 g

Number of moles of potassium iodide = 25/166 = 0.15 moles.

Volume = number of moles/molarity

Volume of water needed = 0.15/0.6

Volume of water needed = 0.30 L or 300 mL

Number of moles of aluminium carbonate = 10/87 = 0.115 moles.

Volume = number of moles/molarity

Volume of water needed = 0.115/0.3

Volume of water needed = 0.383 L or 383 mL

Therefore, the molarity, amount and volumes required are:

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Answer: C2H5OH + 3O2-------=2CO2 + 3H2O

Explanation:

Answer:

im not sure

Explanation:

The decreasing order of ionization energy will be Mg >Al >P>K.

Ionization energy sometimes referred to as ionization potential, would be the amount of energy it takes to eliminate an electron from a single, isolated atom or molecule.

On moving top to bottom in the periodic table, ionization energy will decrease rapidly.

Al =13 (group 3)

P =15 (group 5)

Mg =12 (group 2)

K =19 (group 1)

The decreasing order of ionization energy will be Mg >Al >P>K.

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Answer:

Yes

Explanation:

Sulfur and Sodium will have the same number of electron shells.

  Electronic configuration of

           k   l  m

  Na = 2  8  1

   S =  2  8  6

We see that the have the same energy level.

Also, they belong to the same period on the periodic table. Elements in the same period will have equal number of shell.

In a 39.0% (v/v) alcohol solution, there are 39.0 mL of alcohol for every 100 mL of solution. To find out how many milliliters of each component are present in 795 mL of the solution, we need to calculate the volume of isopropyl alcohol and water separately.



Step 1: Calculate the volume of alcohol in the solution.
In a 39.0% (v/v) alcohol solution, 39.0 mL of alcohol is present for every 100 mL of solution.
To find the volume of alcohol in 795 mL of the solution, we can set up a proportion:
(39.0 mL alcohol / 100 mL solution) = (x mL alcohol / 795 mL solution)
Cross-multiplying and solving for x, we get:
x = (39.0 mL alcohol / 100 mL solution) * 795 mL solution
x ≈ 309.45 mL alcohol

Step 2: Calculate the volume of water in the solution.
The total volume of the solution is 795 mL, and we have already calculated the volume of alcohol to be 309.45 mL.
To find the volume of water, we can subtract the volume of alcohol from the total volume of the solution:
Volume of water = Total volume of solution - Volume of alcohol
Volume of water = 795 mL - 309.45 mL
Volume of water ≈ 485.55 mL

Therefore, in 795 mL of the 39.0% (v/v) alcohol solution, there are approximately 309.45 mL of isopropyl alcohol and 485.55 mL of water.

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Given data:H2O vapor content: 13 gramsH2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10∘C52 grams at 30∘CFormula used to find the dew point:$$\dfrac{13}{52}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$\frac{1}{4}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$

Where A is the constantDew Point:It is the temperature at which air becomes saturated with water vapor when the temperature drops to a point where dew, frost or ice forms. To solve this question, substitute the given data into the formula.$$13/52=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$13(17.27-A)=3\pi A(ln100)$$By simplifying the above expression, we get$$A^2-17.27A+64.78=0$$Using the quadratic formula, we get$$A=9.9,7.4$$

The dew point is 7.4 since it is less than 10°C.More than 100:The term "More than 100" has not been used in the question provided.

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The probability of finding a ground-state electron within 0.0010 nm of the wall in an infinitely deep potential well of width 0.20 nm is 0.012.

The probability of finding a ground-state electron within 0.0010 nm of the wall in an infinitely deep potential well of width 0.20 nm can be determined using the wave function of the electron.

The wave function is given by the equation : ψn(x) = (2/L)^1/2 sin(nπx/L) where

L is the width of the potential well

n is the quantum number

x is the position of the electron within the well

The probability of finding the electron within a given distance from the wall can be found by integrating the wave function over that distance.

To find the probability of finding the electron within 0.0010 nm of the wall, we need to integrate the wave function over the range 0 to 0.0010 nm :

Probability = ∫[ψn(x)]^2 dx from 0 to 0.0010 nm

Probability = ∫[(2/L)^1/2 sin(nπx/L)]^2 dx from 0 to 0.0010 nm

= (2/L) ∫sin^2(nπx/L) dx from 0 to 0.0010 nm

Probability = (2/L) [L/2 - (L/2) cos(2nπx/L)] from 0 to 0.0010 nm

Probability = 1 - cos(2nπx/L)

So, the probability of finding a ground-state electron within 0.0010 nm of the wall in an infinitely deep potential well of width 0.20 nm is given by :

Probability = 1 - cos(2πx/L)

Probability = 1 - cos[(2π)(0.0010 nm)/(0.20 nm)] = 0.012

Thus, the probability of finding a ground-state electron within 0.0010 nm of the wall in an infinitely deep potential well of width 0.20 nm is 0.012

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Answer:

4.96 x 10²²atoms

Explanation:

Given parameters

Mass of Ba  = 11.3g

Unknown:

Number of atoms  = ?

Solution:

To solve this problem, we need to find the number of moles of Ba first and then the number of atoms it contains.

    Number of moles  = \(\frac{mass}{molar mass}\)  

  Molar mass of Ba = 137.3g/mol

  Number of moles  = \(\frac{11.3}{137.3}\)   = 0.08mole

 1 mole of a substance contains 6.02 x 10²³ atoms

  0.08 mole of Ba will contain 0.08 x 6.02 x 10²³ atoms  = 4.96 x 10²²atoms

Answer:

light and chemical energy

Explanation: mark me brainliest please

Answer: 7.1

Explanation:

The specific humidity of the air is 0.0085 kg H2O/kg dry air, the relative humidity is 34%, and the enthalpy of the air is 80 kJ/kg dry air. respectively.

To determine the specific humidity, relative humidity, and enthalpy of the air, we need to use the psychrometric chart. The psychrometric chart is a graphical representation of the thermodynamic properties of moist air and is used to determine various properties of moist air.

To determine the specific humidity of the air, we need to find the point on the psychrometric chart corresponding to the dry bulb temperature of 28°C and the wet bulb temperature of 15°C. From the chart, we find that the specific humidity of the air is approximately 0.0085 kg H2O/kg dry air.

To determine the relative humidity of the air, we need to find the ratio of the actual vapor pressure to the saturation vapor pressure at the dry bulb temperature of 28°C. From the psychrometric chart, we find that the saturation vapor pressure at 28°C is approximately 3.5 kPa, and the actual vapor pressure is approximately 1.2 kPa. Therefore, the relative humidity of the air is approximately 34%.

To determine the enthalpy of the air, we need to find the point on the psychrometric chart corresponding to the dry bulb temperature of 28°C and the specific humidity of 0.0085 kg H2O/kg dry air. From the chart, we find that the enthalpy of the air is approximately 80 kJ/kg dry air.

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Chlorine may be added to water in a continuous, c.) Low dose method to initially disinfect a pipeline.

Chlorine can be added in a continuous low dose to maintain disinfection in the pipeline. This method is often used to prevent the growth of bacteria and other microorganisms in the water. Alternatively, a slug method may be used for an initial shock treatment, where a higher concentration of chlorine is added to the pipeline. Tablet or air injection methods may also be used for disinfection, but they are less commonly employed than the continuous or slug methods. Regardless of the method used, it is important to ensure that the chlorine is properly mixed and that the water is adequately monitored to ensure safe levels of chlorine and other content loaded in the water.

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The statement  "The first object is non-matter, and the second object is matter" is true.

Matter is anything that has mass and takes up space. It is the physical substance that makes up everything around us, including all the objects we can see, touch, and feel.

Matter is composed of tiny particles, such as atoms and molecules, that interact with each other through various forces to create the different forms of matter we observe. Matter exists in different states, including solid, liquid, and gas, depending on the arrangement and motion of its particles.

Thing 1, which has volume, is matter because it occupies space and has mass.

Thing 2, which is made up of particles too small to see, is also matter, as particles are the basic building blocks of matter.

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The byprοducts in this reactiοn are acetic acid (οptiοn A) and ethanοl (οptiοn C).

In acid catalysis and base catalysis, a chemical reactiοn is catalyzed by an acid οr a base. By Brønsted–Lοwry acid–base theοry, the acid is the prοtοn (hydrοgen iοn, H+) dοnοr and the base is the prοtοn acceptοr. Typical reactiοns catalyzed by prοtοn transfer are esterificatiοns and aldοl reactiοns.

The acid-catalysed hydrοlysis οf diethyl acetamidοbenzylmalοnate can lead tο variοus by prοducts depending οn the reactiοn cοnditiοns and specific chemical pathways. Hοwever, withοut mοre detailed infοrmatiοn οr a specific reactiοn mechanism, it is difficult tο prοvide a cοmprehensive list οf the by prοducts that may fοrm.

Based οn the infοrmatiοn prοvided, the acid-catalysed hydrοlysis οf diethyl acetamidοbenzylmalοnate delivers the desired (+)-phenylalanine hydrοchlοride prοduct and the fοllοwing byprοduct(s):

E. Bοth A and C: Acetic acid and ethanοl.

The hydrοlysis οf diethyl acetamidοbenzylmalοnate invοlves the cleavage οf ester bοnds, resulting in the fοrmatiοn οf acetic acid as a byprοduct. Additiοnally, since diethyl acetamidοbenzylmalοnate is an ester, hydrοlysis οf the ester bοnds can alsο prοduce ethanοl as anοther byprοduct.

Therefοre, the byprοducts in this reactiοn are acetic acid (οptiοn A) and ethanοl (οptiοn C).

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Complete Question :

Answer:

There are four significant figures in given measurement.

Explanation:

Significant figures:

All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.

Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.

Zero between the non zero digits are consider significant like 104 consist of three significant figures.

The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.

In given measurement 306.2 there are 4 significant figures.

3,0,6,2

All digits are significant.

Answer:

Martin Luther King, Jr. worked hard to bring greater equality to America and ensure civil rights for all people, regardless of race.

Answer:

It would be able to function because the ph of the environment is similar to that of intestine.

Explanation:

The pH of the small intestine is eight. The enzyme would be able to function because enzyme C functions best at a Ph range around 8.

The pH of the final buffered solution is approximately 5.20.

To determine the pH of the buffered solution, we need to calculate the concentration of acetic acid (HC2H3O2) and acetate ion (C2H3O2-) in the final solution. The Ka value for acetic acid is given as 1.8 × 10^-5. Here are the step-by-step calculations:

Step 1: Calculate the moles of sodium acetate (NaC2H3O2):

Molar mass of NaC2H3O2 = 82.03 g/mol

Mass of NaC2H3O2 = 75.0 g

Number of moles of NaC2H3O2 = mass / molar mass

Number of moles of NaC2H3O2 = 75.0 g / 82.03 g/mol

Number of moles of NaC2H3O2 = 0.914 mol

Step 2: Calculate the volume of the acetic acid solution in liters:

Volume of acetic acid solution = 500.0 mL

Volume of acetic acid solution = 500.0 mL / 1000 mL/L

Volume of acetic acid solution = 0.500 L

Step 3: Calculate the concentration of acetic acid (HC2H3O2) in the final solution:

Concentration of acetic acid = 0.64 M

Since no volume change occurs upon adding sodium acetate, the final volume of the solution is still 0.500 L. Therefore, the final concentration of acetic acid remains the same: 0.64 M.

Step 4: Calculate the concentration of acetate ion (C2H3O2-) in the final solution:

Acetate ion (C2H3O2-) is provided by the dissociation of sodium acetate (NaC2H3O2) in water. Sodium acetate is a strong electrolyte and dissociates completely in water.

The number of moles of C2H3O2- is equal to the number of moles of NaC2H3O2, which is 0.914 mol.

Concentration of acetate ion = moles / volume

Concentration of acetate ion = 0.914 mol / 0.500 L

Concentration of acetate ion = 1.828 M

Step 5: Calculate the pH of the buffered solution using the Henderson-Hasselbalch equation:

pH = pKa + log([C2H3O2-] / [HC2H3O2])

pKa = -log(Ka) = -log(1.8 × 10^-5) = 4.74 (approximated to two decimal places)

pH = 4.74 + log(1.828 M / 0.64 M)

pH = 4.74 + log(2.858)

pH ≈ 4.74 + 0.456

pH ≈ 5.20

Therefore, the pH of the final buffered solution is approximately 5.20.

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The rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.

To determine the rate of change of the concentration of sodium oxalate (Na₂C₂O4), we can use the rate equation:

Rate = (Δ[Na₂C₂O4]) / (Δt)

where Δ[Na₂C₂O4] represents the change in concentration of Na₂C₂O4 and Δt represents the change in time.

In this case, the initial concentration of Na₂C₂O4 is 1.34 M, and after 19.3 seconds, the concentration is 0.276 M.

Substituting the values into the rate equation, we have:

Rate = (0.276 M - 1.34 M) / (19.3 s - 0 s)

Rate = (-1.064 M) / (19.3 s)

Rate = -0.0551 M/s

Therefore, the rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.

The negative sign indicates that the concentration of Na₂C₂O4 is decreasing over time, as the reactant is being consumed in the reaction.

It's important to note that the rate of a reaction is influenced by various factors, such as the reaction mechanism, temperature, and presence of catalysts. The rate can be determined experimentally by measuring the change in concentration of a reactant or product over a specific time interval.

The given information allows us to calculate the rate of change for the specific reaction involving Na₂C₂O4. However, without additional information about the reaction, it is not possible to determine the exact nature or stoichiometry of the reaction, as well as any other reactants or products involved.

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A battery is a device that converts chemical energy into electrical energy through a process known as an electrochemical reaction.

When a battery is connected to a circuit, the electrochemical reaction causes a flow of electrons from the anode to the cathode, generating an electric current that can power a device.

The metal chosen for the anode must be capable of losing electrons easily, while the metal chosen for the cathode must be capable of accepting electrons. The choice of metals can also affect the voltage and capacity of the battery, as well as its overall efficiency.

In general, the metals used in a battery should have a large difference in their electronegativity values, which determines how easily an atom can attract electrons. Common metals used in batteries include zinc, lithium, nickel, and cadmium.

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The type of reaction is Mg + S → MgS is of synthesis reaction. Therefore, the correct option is option B among all the given options.

A synthesis reaction occurs when multiple chemical species unite to create a more complex product. One of the most typical chemical reactions, it is also known as a direct reaction.

A bigger compound is created when two or maybe more reactants mix. A deconstruction reaction, which occurs when the bonds in a complex product are broken and it separates the product in with its individual components or elements, is the reverse of a synthesis process.  The type of reaction is Mg + S → MgS is of synthesis reaction.

Therefore, the correct option is option B among all the given options.

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The statement among the available options that describes the result of the study is that less than 50% of the people never felt phantom pain. Option 2.

In order to interpret the data and find the best description of the outcome of the experiment, the response needs to be grouped into 2 from the 3 available responses.

Since those that phantom pain sometimes and always belong to the same category, the respondents can be summed up into one:

Number of those that sometimes feel phantom pain = 534

Number of those that always feel phantom pain = 193

Total number of people that feel phantom pain = 534 + 193

                                                                                = 727 people

Number of people that never feel phantom pain = 183

Total number of respondents in the experiment = 183 + 534 + 193

                                                                                = 910 people

Percentage of respondents that felt phantom pain = 727/910 x 100

                                                                                     = 79.89%

Percentage of people that never felt phantom pain = 183/910 x 100

                                                                                      = 20.11%

Percentage of people that felt phantom pain all the time = 193/910 x 100

                                                                                      = 21.21%

Thus, the statement that correctly describes the outcome of the experiment of all the statements is that less than 50% never felt phantom pain.

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Answer:

and I quenot se the question

Explanation:

ok firts you dirent take a god picture