When does the o-h peak overlap with the sp3 c-h peaks?.

The atom's nucleus is composed of neutrons and protons. BOTH: In the nucleus. Contribute to the mass of the atom. Mass equal 1 amu. PROTON. Number is atomic number of element. Determine the identity of the atom. NEUTRON: Neutral charge.

Subatomic particles are matter structures that are smaller in size than an atom. Hence, subatomic particles compose the atoms, determining their properties.

Many subatomic particles are unstable and remain unknown. However, three of them are the most stable ones,

Subatomic particles can be either,

Neutrons and protons compose the nucleus of the atoms, while electrons orbit around them.

These particles differ in their electric charge and their mass.

The number of protons in the atom is the atomic number and determines the atom's identity.

The massic number is the addition of the number of protons and the number of neutrons.

Atomic mass is composed of neutrons and protons mass. It is not the same as the massic number or the atomic weight.

When protons, neutrons, and electrons get together to form an atom, they lose part of their mass as energy. This is why the atomic weight is slightly inferior to the sum of masses.

1) BOTH

In the nucleus

Contribute to the mass of the atom

Mass equal 1 amu (1.67377 x 10⁻²⁷ kg or 1.67377 x 10⁻²⁴ g)

2) PROTON

Number is atomic number of element

Determine the identity of the atom

3) NEUTRON

Neutral charge

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Answer: 110 g/mol

Explanation:

First we need to find the molar mass of CaCl2 using the periodic table:

Ca: 40

Cl: 35 (Since Cl has a 2 at the end, multiply 35 by 2)

70+40= 110

Then multiply by amount of moles

110g×1.000mol = 110 g/mol

Using the regression equation, the concentration of a sample with an absorbance of 0.25 is 1.76*10^-5M

Using the regression equation obtained from the model,

y = 15200x - 0.018

y = absorbance. x = Concentration

Concentration of unknown dye sample with absorbance of 0.25:

Substitute the absorbance value y = 0.25 into the equation and calculate the concentration x:

0.25 = 15200x - 0.018

side

15200x = 0.25 + 0.018

15200X = 0.268

Division by 15200

x = (0.268 ÷ 15200)

x= 1.76*10^-5M, which is the concentration of the sample.

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TLC means Thin Layer Chromatography. It is a method that can best be described as "Affinity-Based" used in the separation of compounds that are in a mixture.

Unreacted p-nitrobenzaldehyde is simply an organic aromatic compound that contains a nitro group para-substituted to an aldehyde. in this case, if it is unreacted, that means it is the same as before the chemical reation.

Note that the question is missing key information hence the general answer.

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To determine which compounds are not true organometallic compounds in the eyes of purists, we need to consider the definition of organometallic compounds.

Organometallic compounds are compounds that contain a direct bond between a carbon atom and a metal atom. Based on this definition, we can evaluate each compound provided:

Compound 1: This compound contains a direct bond between a carbon atom and a metal atom (M), so it is a true organometallic compound.

Compound 2: This compound contains a direct bond between a carbon atom and a metal atom (M), so it is a true organometallic compound.

Compound 3: This compound does not contain a direct bond between a carbon atom and a metal atom. Instead, it has a metal atom (M) coordinated to a ligand (L) without a direct carbon-metal bond. Therefore, it is not considered a true organometallic compound in the eyes of purists.

Compound 4: This compound contains a direct bond between a carbon atom and a metal atom (M), so it is a true organometallic compound.

Compound 5: This compound does not contain a direct bond between a carbon atom and a metal atom. It has a metal atom (M) coordinated to a ligand (L) without a direct carbon-metal bond. Therefore, it is not considered a true organometallic compound in the eyes of purists.

Based on the above analysis, the correct answer is:

D. Compound 3 only

Compound 3 is not considered a true organometallic compound since it lacks a direct carbon-metal bond.

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The elements in a group often look and behave similarly, because they have the same number of electrons in their outermost shell — the face they show to the world. Group 18 elements, on the far right side of the table, for example, have completely full outer shells and rarely participate in chemical reactions.

There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. Therefore, for the easing the understanding of elements grouping of elements is done based on the way they behave in chemical reactions.

Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.

Grouping elements based on the way they behave in chemical reactions makes the study of elements in the periodic table much easier and comfortable.

Therefore, for the easing the understanding of elements grouping of elements is done based on the way they behave in chemical reactions.

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Answer:

There isn't any picture for me to see

have a good day :)

Explanation:

Answer:

347.4 (19.3 mole)

Explanation:

CH4 + 2O2 = CO2 + 2H2O

1(mole) - 9.65(mole)

2(mole) - x ⇒x = 9.65*2=19.3

m=n*M ⇒ m= 19.3*(1*2+16)= 19.3*18=347.4(g)

The neutral atom fluorine-19 has 9 protons, 10 neutrons, and 9 electrons.

Fluorine-19 is a neutral atom that has 9 protons and 10 neutrons in its nucleus. This means that the atomic number of fluorine-19 is 9, as it has 9 protons. Additionally, the mass number of fluorine-19 is 19, as it has 10 neutrons in its nucleus.As a neutral atom, the number of electrons in fluorine-19 is equal to the number of protons, which is 9. This means that fluorine-19 has 9 electrons orbiting around its nucleus. These electrons are distributed in different energy levels or shells, with the first shell having 2 electrons and the second shell having 7 electrons.Fluorine is a highly reactive element that is a member of the halogen family. It has a unique ability to form a single covalent bond with almost all other elements, except for helium, neon, and argon. This makes it an essential element in many organic and inorganic compounds.Knowing these values allows us to better understand the chemical behavior of fluorine and its role in various chemical reactions.

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φ(g1 * g2) = eH = φ(g1) * φ(g2).

This completes the proof that φ: G → H is a group homomorphism.

By showing that the map φ preserves the group operation, we have demonstrated that it is a group homomorphism.

To prove that φ: G → H is a group homomorphism, we need to show that it preserves the group operation. In other words, for any two elements g1 and g2 in G, φ(g1 * g2) = φ(g1) * φ(g2), where * denotes the group operation in G, and * denotes the group operation in H.

Given that φ(g) = eH for all g ∈ G, where eH is the identity element in H, we can start the proof as follows:

Let g1, g2 ∈ G. We want to show that φ(g1 * g2) = φ(g1) * φ(g2).

Since φ(g) = eH for all g ∈ G, we have φ(g1) = eH and φ(g2) = eH.

Now, consider the product g1 * g2 in G. Applying φ to both sides, we have:

φ(g1 * g2) = φ(g1) * φ(g2).

Substituting the values of φ(g1) and φ(g2), we get:

φ(g1 * g2) = eH * eH.

Since eH is the identity element in H, the product eH * eH is simply eH.

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The original pressure of the unknown gas sample is approximately 6.26 atm when the initial volume is 23 mL and the initial temperature is 41 Kelvin, based on the measurements indicating a final volume of 42 mL at 13 atm and 154 Kelvin.

To determine the original pressure of the unknown gas sample, we can use the combined gas law equation:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:

P1 = Original pressure (to be determined)

V1 = Original volume (23 mL)

T1 = Original temperature (41 Kelvin)

P2 = Final pressure (13 atm)

V2 = Final volume (42 mL)

T2 = Final temperature (154 Kelvin)

Substituting the given values into the equation:

(P1 * 23 mL) / (41 K) = (13 atm * 42 mL) / (154 K)

Simplifying the equation:

(P1 * 23 mL * 154 K) = (13 atm * 42 mL * 41 K)

Now, solving for P1 (the original pressure):

P1 = (13 atm * 42 mL * 41 K) / (23 mL * 154 K)

Calculating the expression:

P1 ≈ 6.26 atm

Therefore, the original pressure of the unknown gas sample is approximately 6.26 atm when the initial volume is 23 mL and the initial temperature is 41 Kelvin, based on the measurements indicating a final volume of 42 mL at 13 atm and 154 Kelvin.

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Answer:

It would take 12 minutes.

Answer:

8 minutes

Explanation:

G(g)                 T(min)

100 --------------- 0

50-------------------2

25 -------------------4

12.5  ---------------  6

6.25 ----------------8

     another    way:

100/6.25 = 16

  16 = 2⁴       ( 4 half lives)    

Each half life is 2 minutes

so 4 half lives will be 8 minutes

In a liquid H2-O2 rocket, the ratio of H2 to O2 introduced into the combustion chamber is 11,500 moles of H2 for every 5000 moles of O2 per second.

Assuming complete reaction and frozen flow in the nozzle, we need to determine the moles per second of H2, O2, and H2O exiting the rocket nozzle.

(a) To find the moles per second of each component exiting the nozzle, we need to consider the stoichiometry of the reaction. From the given ratio, for every 11,500 moles of H2, 5000 moles of O2 are present. Since the reaction is complete, all the H2 and O2 react to form H2O. Therefore, the moles per second of H2 exiting the nozzle is 11,500, the moles per second of O2 exiting the nozzle is 5000, and the moles per second of H2O exiting the nozzle is also 11,500.

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The oceans hold "A) 10,000 times more" carbon than the atmosphere.

This is because the oceans act as a large carbon sink, absorbing and storing significant amounts of carbon dioxide from the atmosphere.

In the deep waters of the ocean, coral reefs are found in abundance. Algae live on these coral reefs, providing nutrition and producing pigments that give color to the corals.

The corals offer shelter to the algae. So, they share a symbiotic association. Climate change has led to increased temperatures and has caused the corals to throw away the algae living inside them.

This action causes the corals to be bleached because of a lack of pigment. This change will lead to coral bleaching. The corals will die of lack of nutrition with time.

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Answer:

Explanation:

Aliphatic compounds are those hydrocarbons that are the open chain compounds and also closed chains. Aromatic compounds are those who have only a closed chain structure. They can be saturated as well as unsaturated where the system can be open as well as closed chain.

The mass of the sample is approximately 24.48 grams.

To determine the mass of the sample, we can use the formula:

Heat of vaporization (J/g) = Energy required to vaporize the sample (J) / Mass of the sample (g)

Given that the heat of vaporization is 3500 J/g and the energy required to vaporize the sample is 85670 J, we can rearrange the formula to solve for the mass of the sample:

Mass of the sample (g) = Energy required to vaporize the sample (J) / Heat of vaporization (J/g)

Substituting the values, we have:

Mass of the sample (g) = 85670 J / 3500 J/g

Mass of the sample (g) ≈ 24.48 grams

Therefore, the mass of the sample is approximately 24.48 grams.

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Explanation:

Oxygen has atomic number eight. This means that the nuclei of all oxygen atoms have eight protons. A neutral oxygen atom will also have eight electrons.

In an oxygen ion with a

2

−

charge, the number of protons is still 8, but the number of electrons is 10.

This results in the oxygen ion having an octet (8) of valence electrons.

Answer:

The number of protons in the nucleus of the atom is equal to the atomic number (Z). The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus.

Answer: I'm pretty sure the answer is Number of Protons

Explanation:

I took the k-12 test

Answer:

A

Explanation:

A. One element decaying into another, which decays into another

Answer:

An ion is charged because the number of electrons does not equal the amount of particles.

Explanation:

Can be positive (meaning more protons than electrons) and it can be negatively charged (meaning there are more electrons than protons).

Hope this helps!

Answer:

An ion has a charge because the number of electrons dont equal the amount of protons in the molecule or atom.

Explanation:

The negative or positive charge depend on wether the atom or molecule has more electrons(-) or protons(+).

The amount of heat absorbed to raise the temperature of 435 grams of water at 1 atm from 25°C to its boiling point, 100°C, is approximately 1.4 × 10^5 joules

What is specific heat?

Specific heat is the amount of heat energy required to raise the temperature of a substance by one unit of temperature per unit of mass. It is a physical property that helps to characterize a substance and is typically measured in units of joules per gram per degree Celsius (J/g°C) or calories per gram per degree Celsius (cal/g°C).

The amount of heat absorbed to raise the temperature of a substance can be calculated using the formula:

Q = mcΔT

where Q is the amount of heat absorbed (in joules), m is the mass of the substance (in kilograms), c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius), and ΔT is the change in temperature (in degrees Celsius).

Substituting the given values, we get:

m = 435 grams = 0.435 kg

ΔT = 100°C - 25°C = 75°C

The specific heat capacity of water is 4.184 J/g°C. We can convert this to joules per kilogram per degree Celsius (J/kg°C) by dividing by 1000:

c = 4.184 J/g°C ÷ 1000 = 4.184 J/kg°C

Substituting these values, we get:

Q = (0.435 kg) × (4.184 J/kg°C) × (75°C)

Q = 140,089.2 J

Therefore, the amount of heat absorbed to raise the temperature of 435 grams of water at 1 atm from 25°C to its boiling point, 100°C, is approximately 1.4 × 10^5 joules. The answer closest to this value is option (B).

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Answer:

ions are attracted to the anode The volume of hydrogen given off is twice the volume of oxygen given of

Explanation:

Answer:

(I). The most likely to lose electron is Rubidium

(II). The most likely to lose electron is Bromine

Explanation:

Given that,

Radium, Indium, Phosphorus, Tellurium, Bromine and Rubidium

We know that,

Metal :

They atom which to lose electron these is called metal.

When the atom loses the electron then the positive charge come on the atom.

The most likely to lose electron is Rubidium

Non metal :

They atome which is gains electron. It is called non metal.

So, we can say that, the non metal gains electron.

When the atom gains the electron then the negative charge come on the atom.

The most likely to gain electron is Bromine

Hence, This is required answer.

Sodium (Na) and the water(H₂O) undergo a chemical reaction the produces sodium hydroxide (NaOH) and hydrogen gas (H₂). The equation is :

2Na(s) + 2H₂O(l) → 2NaOH(aq) +H₂(g) . The correct option is A.

The Sodium (Na) and the water (H₂O) will undergo the chemical reaction they produces the sodium hydroxide (NaOH) and the hydrogen gas (H₂). The chemical equation is as follows :

Na(s) + H₂O(l) → NaOH(aq) +H₂(g)

The balance chemical equation is the equation in which the atoms of the reactant and the product side are equal. Multiply 2 in Na , in H₂O and in NaOH, we get :

2Na(s) + 2H₂O(l) → 2NaOH(aq) +H₂(g)

Thus, option A is correct.

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This question is incomplete, the complete question is :

Sodium (Na) and water(H₂O) undergo a chemical reaction the produces sodium hydroxide (NaOH) and hydrogen gas (H₂). Which equation represents this chemical reaction?

A. 2Na + 2H₂O ---> 2NaOH + H₂

B. 2Na+ H₂ --->  2NaOH + 2H₂O

C. 2Na + 2NaOH ----> 2H₂O + H₂

D. H₂ + 2H₂O ----> 2Na + 2NaOH

The statement that illustrates the like dissolves like rule for a solid solute in a liquid solvent are all of the options listed. The corect option is D.

The "like dissolves like" rule states that substances with similar chemical properties will dissolve in each other. This principle helps predict the solubility of a solid solute in a liquid solvent. The given options present various combinations of solutes and solvents, and we need to identify which of them best illustrate this rule.

A. An ionic compound is soluble in a polar solvent: This statement is true, as ionic compounds, which consist of charged particles, can dissolve in polar solvents due to their polarity. The polar solvent can stabilize and surround the charged particles, facilitating dissolution.

B. A polar compound is soluble in a polar solvent: This statement also adheres to the "like dissolves like" rule. Polar solutes dissolve in polar solvents due to similar intermolecular forces, such as hydrogen bonding or dipole-dipole interactions.

C. A nonpolar compound is soluble in a nonpolar solvent: This option is consistent with the rule as well. Nonpolar solutes can dissolve in nonpolar solvents due to their similar intermolecular forces, primarily the London dispersion forces.

Given that options A, B, and C all illustrate the "like dissolves like" rule, the correct answer is D. All.

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Hydrogen peroxide is one of the most common bleaching agents. It is the primary bleaching agent in the textile industry, and is also used in pulp, paper, and home laundry applications.

bleaching agent is a material that lightens or whitens a substrate through chemical reaction. The bleaching reactions usually involve oxidative or reductive processes that degrade color systems. These processes may involve the destruction or modification of chromophoric groups in the substrate as well as the degradation of color bodies into smaller, more soluble units that are more easily removed in the bleaching process. The most common bleaching agents generally fall into two categories: chlorine and its related compounds (such as sodium hypochlorite) and the peroxygen bleaching agents, such as hydrogen peroxide and sodium perborate. Reducing bleaches represent another category. Enzymes are a new category of bleaching agents. They are used for textile, paper, and pulp bleaching as well as for home laundering. Chlorine‐containing bleaching agents are the most cost‐effective bleaching agents known. They are also effective disinfectants, and water disinfection is often the largest use of many chlorine‐containing bleaching agents. They may be divided into four classes: chlorine, hypochlorites, N‐chloro compounds, and chlorine dioxide. Except to bleach wood pulp and flour, chlorine itself is rarely used as a bleaching agent. The principal form of hypochlorite produced is sodium hypochlorite. Other hypochlorites include calcium hypochlorite and bleach liquor, bleaching powder and tropical bleach. The principal solid chlorine bleaching agents are the chlorinated isocyanurates, eg, sodium dichloroisocyanurate dihydrate. Other N‐chloro compounds include halogenated hydantoins, and sodium N‐chlorobenzenesulfonamide (chloramine B). Chlorine dioxide is a gas that is more hazardous than chlorine. Large amounts for pulp bleaching are made by several processes in which sodium chlorate is reduced with chloride, methanol, or sulfur dioxide in highly acidic solutions by complex reactions. Hydrogen peroxide is one of the most common bleaching agents. It is the primary bleaching agent in the textile industry, and is also used in pulp, paper, and home laundry applications. Hydrogen peroxide reacts with many compounds, such as borates, carbonates, pyrophosphates, sulfates, etc, to give peroxy compounds or peroxyhydrates. Peracids have superior cold water bleaching capability versus hydrogen peroxide because of the greater electrophilicity of the peracid peroxygen moiety. Lower wash temperatures and phosphate reductions or bans in detergent systems account for the recent utilization and vast literature of peracids in textile bleaching. The reducing agents generally used in bleaching include sulfur dioxide, sulfurous acid, bisulfites, sulfites, hydrosulfite (dithionites), sodium sulfoxylate formaldehyde, and sodium borohydride. These materials are used mainly in pulp and textile bleaching.

Answer:

KBr final solution:

V = 250mL --> 0.25L

Concentration/Molarity = 1.5 mol/L

To find the amount of moles of KBr here, just multiply the volume by the concentration (0.25 x 1.5 = 0.375 mol)

So the amount of moles for KBr is 0.375 mol. Now we know that the mass divided by the molar mass (the atomic mass values of K and Br in the periodic table added together) would give us the amount of moles aswell.

n = moles

m = mass

M = molar mass

n = m/M

so if we rearrange this equation to find mass, we would get:

m = n x M

Molar mass for KBr: (39.09) of K + (79.90) of Br = 118.99

m = 0.375 mol    x    118.99

m = 44.62g

Therefore 44.62g of KBr is needed to make 250mL of a 1.5 M KBr solution.

Answer:

28.00 g is the answer

Answer:200

Explanation:

It’s is the answer

An example of a secondary pollutant is option (c)- photochemical oxidants.

Secondary pollutants are formed when primary pollutants react with each other or with other substances in the atmosphere. Photochemical oxidants, such as ozone, are created through reactions involving sunlight and primary pollutants like VOCs (volatile organic compounds) and nitrogen oxides.

Hence, an example of a secondary pollutant is option (c)- photochemical oxidants.

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Answer:

ALPHA

Explanation: