when a chemical reaction occurs, chemical bonds ______ break and new chemical bonds form to create the __________

The lifetime of sun is 6.11 x 10¹⁰ years.

Mass of proton, m₁ = 1.6 x 10⁻²⁷kg

Mass of Helium nucleus, m₂ = 6.64 x 10⁻²⁷kg

Mass of positron, m₃ = 0.0009 x 10⁻²⁷kg

The energy in the sun can be calculated by using the equation,

E = Mc²

E = 8.3 x 10 ²⁷x 9 x 10¹⁶

E = 7.41 x 10⁴⁴J

The luminosity of sun, L = 3.846 x 10²⁶ W

Therefore, the lifetime of sun can be calculated as,

t = E/L

t = 7.41 x 10⁴⁴/3.846 x 10²⁶

t = 19.3 x 10¹⁷s

t = 6.11 x 10¹⁰ years

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Explanation:

The centripetal force acting on a 75 kg person standing at the equator of the earth due to the earth's rotation on its axis can be calculated using the following formula:

F = m x a

where F is the force, m is the mass of the person, and a is the centripetal acceleration.

The centripetal acceleration can be calculated using the formula:

a = v^2 / r

where v is the tangential velocity and r is the distance from the axis of rotation (in this case, the radius of the earth at the equator).

At the equator of the earth, the radius is approximately 6,378 km, and the earth completes one rotation in approximately 24 hours. Therefore, the tangential velocity can be calculated as:

v = 2 x pi x r / T

= 2 x pi x 6,378,000 m / 86,400 s

= 465.1 m/s

Using this value for v, the centripetal acceleration can be calculated as:

a = v^2 / r

= (465.1 m/s)^2 / 6,378,000 m

= 0.0339 m/s^2

Finally, the centripetal force can be calculated as:

F = m x a

= 75 kg x 0.0339 m/s^2

= 2.54 N

If the person moves to the north or south pole, they will be closer to the axis of rotation, so the radius will be smaller. At the poles, the radius is approximately 6,357 km. Using this value for r, the tangential velocity can be calculated as:

v = 2 x pi x r / T

= 2 x pi x 6,357,000 m / 86,400 s

= 368.3 m/s

Using this value for v, the centripetal acceleration can be calculated as:

a = v^2 / r

= (368.3 m/s)^2 / 6,357,000 m

= 0.0341 m/s^2

The centripetal force can then be calculated as:

F = m x a

= 75 kg x 0.0341 m/s^2

= 2.56 N

As we can see, the difference in the centripetal force between the equator and the poles is relatively small, due to the small difference in radius.

To rank car #1's speed relative to the ground at the lettered times (A through E) from largest to smallest, we need more information on the speeds at those specific times.

The ranking for the speed of car #1 relative to the ground was determined: The ranking was determined based on the given information about the speed of the car at each lettered time. The speed of the car at time A is the highest, followed by time B and so on. Thus, the ranking was established according to the given values.

The necessary information on the speeds of both cars at the lettered times, we cannot determine the ranking of car #1's speed relative to car #2. To rank the distance between the cars at the lettered times (A through E) from largest to smallest, we need more information on their positions at those specific times. We cannot determine the ranking for the distance between the two cars without the necessary information on their positions at the lettered times.

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In conclusion, the comparison and ranking of speed or distance between two cars at different time points depends on the specific data given at those points, and analyzing their changes over time will provide the best answer.

Unfortunately, I can't give a specific rank or explanation without a graph, diagram, or set of data points to use for reference. However, to answer such a question, you would need to compare the speed, relative movement, and distance between both cars at each mentioned time point.

For example, suppose at time A, car #1 is moving faster than car #2. You'd rank car #1's speed greater at time A. However, if at time B, car #1 is stationary while car #2 is still moving, you'd rank car #1's speed lowest at time B.

In terms of the speed of car #1 relative to car #2, it depends on their comparison speed at each point in time. If at one point, both cars are moving the same speed in the same direction, they're considered at relative rest, so their relative speed to each other is zero.

The distance between two cars would be determined by subtracting the distance covered by car #1 from car #2. The larger distance it covers, the greater the gap between the two cars.

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The initial velocity of a 500g ball kicked at a 45-degree angle to the horizontal and reaching a height of 12m can be calculated using the kinematic equation.

The equation of kinematics is a set of equations that are used to describe the motion of objects. They relate to displacement, velocity, acceleration, and time. Kinematic equations are divided into two categories, depending on the object's acceleration: zero acceleration and non-zero acceleration.

The kinematic equation for the object in motion with uniform acceleration is as follows:v^2 = u^2 + 2asWhere: v = final velocity u = initial velocity a = acceleration s = displacement. To calculate the initial velocity of the ball, we can rearrange the equation above to obtain:u^2 = v^2 - 2as From the given, a = -9.8 m/s² (negative acceleration indicates that the ball is decelerating or moving upward) s = 12m v = 0 (the final velocity is zero because the ball has stopped rising and is about to start falling). We'll use these values to calculate the initial velocity of the ball.u² = (0)² - 2(-9.8)(12)u² = 235.2u = sqrt(235.2)u = 15.33 m/s.

Therefore, the initial velocity of the ball is approximately 15.33 m/s.

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It requires 288 joules of heat to raise the temperature of a 225-g lead ball from 15.0°C to 25.0°C.

The formula to calculate the amount of heat, Q required to raise the temperature of an object is:

Q = mcΔT

Where:

Q = the amount of heat (in joules, J)

m = the mass of the object (in kilograms, kg)

c = the specific heat capacity

ΔT = the change in temperature

In this problem, we are given:

m = 225 g = 0.225 kg

ΔT = (25.0°C - 15.0°C) = 10.0°C

c = 128 J/kg*K

plugging in the values

Q = mcΔT

Q = (0.225 kg)(128 J/kg*K)(10.0°C)

Q = 288 J

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aircraft type means a particular model of aircraft as designated by the manufacturer of the aircraft.

I think it's false

A) 0.005

B) 0.001

C)0.0495

Step-by-step explanation:

Let A be the event that an aircraft is present and let B be the event the radar registers its presence.. Thus;

P(A) = Probability that an aircraft is present

P(A') = Probability that an aircraft is not present

P(B) = Probability that the radar generates an alarm

P(B') = Probability that the radar doesn't generate an alarm

Thus from what we are given, we have;

P(A) = 0.05

P(A') = 0.95

P(B) = 0.99

P(B') = 0.01

P(B|A') = 0.1

A) Probability of a false alarm will be;

P(A' ∩ B) = P(A) × P(B|A')

P(A' ∩ B) = 0.05 × 0.1 = 0.005

B) probability of missed detection is;

0.1 × (1 - 0.99) = 0.001

C) probability that an aircraft is present given that the radar registers a presence will be;

P(A ∩ B) = P(A) × P(B)

P(A ∩ B) = 0.05 × 0.99

P(A ∩ B) = 0.0495

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Answer: Often lightning occurs between clouds or inside a cloud. But the lightning we usually care about most is the lightning that goes from clouds to ground.

Explanation:  As the storm moves over the ground, the strong negative charge in the cloud attracts positive charges in the ground.

Answer:

the distance to the image is 1.5 m

Explanation:

To find the position of the image let's use the equation of the constructor

       \(\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\)

where p and q are the distance to the object and the image, respectively, and f is the focal length.

In this case a plane mirror has a focal length at infinity, if we substitute in the equation

        1 / p = - 1 / q

         q = -p

therefore the distance to the image is 1.5 m

this image has some characteristics:

* It is a virtual image, this means that light rays do not pass through it

* It is a right image, that is, the image is in the same direction of the object.

* the magnification is 1, since the height of the image and the object are the same

* has the right - left direction reversed

Answer:

\( \infty \infty \)

Answer:

Distance

Explanation:

Because each path you take will have a different distance. Each path will be different, leading to a different distance. Hope this helped :D

Answer:

behind

Explanation:

because just because that's why lol

The total work done by the force of friction on the block as it moves a distance L up the incline is given by the formula:

Wfric = −f × L

The work done by the force of friction on the block as it moves a distance L up the incline is equal to the product of the force of friction and the distance moved. Work is the measure of the amount of energy transferred by a force when an object is moved a certain distance. If a force acts on an object and the object moves, work is done by the force. Therefore, work can be defined as the product of force and displacement.

Mathematically, it can be expressed as follows:

W = F × S

where W is work, F is force, and S is displacement. The SI unit of work is joules (J). When a block moves on an inclined plane, friction is one of the forces acting on the block. As the block moves up the plane, the force of friction acts opposite to the direction of motion of the block. Hence, the work done by the force of friction is negative. This means that the force of friction acts to decrease the energy of the block.

The work done by the force of friction on the block as it moves a distance L up the incline is given by the formula:

Wfric = −f × L

where Wfric is the work done by the force of friction, f is the force of friction, and L is the distance moved by the block up the incline. Therefore, the total work done by the force of friction on the block as it moves a distance L up the incline is given by the formula:

Wfric = −f × L

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On a separate planet from Earth, your mass would be the same but your weight would be different due to the gravitational pull of the planet.

W = m g

W= Weight

m = Mass

g stands for gravitational acceleration.

The amount of substance in a body is measured by its mass. It is independent of all outside variables. Hence, no outside influences have an impact on its worth.

W ∝ g

As you can see, weight varies according to the force of gravity pushing on the body. A force of gravity is another name for weight. On earth, g has a different value than it does on other planets.

Gravity is a fundamental force of nature that exists between any two objects with mass or energy. It is responsible for the attraction between objects, such as planets, stars, and galaxies, and plays a crucial role in the structure and dynamics of the universe. According to the theory of general relativity, gravity is the curvature of spacetime caused by the presence of mass and energy. This means that objects with mass or energy create a distortion in spacetime that causes other objects to be attracted toward them. The strength of the gravitational force depends on the mass and distance between the objects, with larger masses and shorter distances resulting in stronger gravitational attraction.

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Both lunar and solar eclipses occur due to the alignment of the Sun, Moon, and Earth, but the specific conditions required for each type of eclipse are slightly different.

For a lunar eclipse to occur, three conditions are necessary:

Full Moon: A lunar eclipse can only occur during a Full Moon when the Moon is on the opposite side of the Earth from the Sun.

Alignment: The Earth, Moon, and Sun must be aligned in a straight line, with the Earth in the middle.

Angle: The Moon's orbit around the Earth is tilted at an angle of about 5 degrees to the Earth's orbit around the Sun. Therefore, for a lunar eclipse to occur, the Moon must pass through the Earth's shadow, which only happens when the alignment is just right.

For a solar eclipse to occur, three different conditions are necessary:

New Moon: A solar eclipse can only occur during a New Moon, when the Moon is between the Earth and the Sun.

Alignment: The Earth, Moon, and Sun must be aligned in a straight line, with the Moon in the middle.

Distance: The Moon's distance from the Earth can affect whether or not a solar eclipse occurs. The Moon's orbit around the Earth is elliptical, meaning that it is not always the same distance from Earth. If the Moon is too far away, it appears smaller in the sky and cannot completely block the Sun's disk, resulting in an annular solar eclipse. If the Moon is closer to the Earth, it appears larger and can fully block the Sun, resulting in a total solar eclipse.

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Answer:

you have to organize the data. a= acceleration vi=inicial velocity vf=final velocity  t=time.

a=80m/s

vi=0

vf=?

t=40 s

the formula you have to use is:

vf=vi+a*t  (final velocity= inicial velocity plus acceleration times time)

Explanation:

I was the best one at my class, hope it helped

Answer: 320 m/s

Explanation:  V initial = 0, V final= ?   Acceleration = 8m/s/s  t=40s

Answer:

a. 90 dB

b. 80 dB

Explanation:

The given parameter of the sound is as follows;

The level to which the headphones are tuned = All the way up

The intensity of the sound of the headphones when tuned all the way up = 100 dB

a. The relationship between level change in loudness, ΔL, and the ratio of loudness, 'x', is presented as follows;

ΔL = 10·log₂(x) ≈ 33.22·log(x)

Therefore, for a sound to be half as loud, we have x = 1/2, therefore;

ΔL = 10·log₂(1/2) = 10·log₂(2⁻¹) = -10 ≈ 33.22·log(1/2)

The change in the intensity level for a sound half as loud, ΔL = -10 dB

Given that the sound was initially at 100 dB, the new level for a sound half as loud = 100 dB + ΔL = 100 dB - 10 dB = 90 dB

The decibel level the music must be set for a sound half as loud = 90 dB

b. In order for the sound to be 1/4 as loud, we have;

ΔL = 10·log₂(1/4) = 10·log₂(2⁻²) = -20

Therefore, the change in the level of the sound intensity level, ΔL by -20 dB will given a sound that is 1/4 as loud

The initial intensity level = 100 dB

The intensity level for a sound 1/4 as loud = 100 dB - 20 dB = 80 dB

The given amplifier circuit is a common-source amplifier. The equivalent circuit diagram of the amplifier includes a MOSFET N5486 transistor. We can determine the drain current (ID) and drain-source voltage (VDS) using the following equations:

1. Voltage at the source terminal (VS) is calculated using Ohm's law: VS = IS x RS.2. The drain current (ID) can be calculated using the equation ID = IS (1 + GVin), where Vin is the input voltage, G is the voltage gain, and IS is the current flowing through RD.Let's calculate the values of ID and VDS:

Given:- IS = VDD / RD = 10V / 10Ω = 1A- Vin = -1V / (1.5 x 10^6Ω + 0.47μF) = -0.6666667μA (using voltage divider rule)- G = -RD / RS = -10Ω / 3kΩ = -0.003333 Calculating ID:ID = 1A (1 - 0.003333 x 0.6666667 x 10^6)≈ 0.997A = 997mACalculating VDS:VDS = VDD - IDRD= 10V - 997mA x 10Ω≈ 10V - 9.97V≈ 0.03VTherefore, the values of ID and VDS are approximately ID = 997mA and VDS ≈ 0.03V, respectively.

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Momentum = m • v

Original momentum = m • 10 m/s north

Final momentum = m • 15 m/s north

Change = m • (15 - 10) m/s north

Change = m • +5 m/s north

Change = +60 kg-m/s north

Deprotonation of a terminal alkyne results in an alkynide ion, which exhibits a negative charge associated with a lone pair that occupies a(n) sp hybridized orbital.

When a terminal alkyne undergoes deprotonation, the removal of a proton from the terminal carbon atom results in the formation of an alkynide ion. The alkynide ion contains a negative charge that is associated with a lone pair of electrons, which occupies a p-orbital. This p-orbital is perpendicular to the plane of the molecule and lies along the axis of the carbon-carbon triple bond.

The alkynide ion is a very strong base due to the stability of the resulting anion. This base can be used in various reactions to form new carbon-carbon bonds or as a nucleophile in substitution reactions. Additionally, alkynide ions can be used as ligands in organometallic chemistry due to their ability to donate electrons to metal centers. In summary, deprotonation of a terminal alkyne leads to the formation of an alkynide ion that has a negative charge associated with a lone pair of electrons occupying a p-orbital.

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The velocity of a small ladybug that's sitting on the edge of a rotating disk (like an old vinyl album) increases as the lady bug walks along a circular path at a constant radius.

Explanation: The acceleration experienced by the ladybug is due to centripetal acceleration, which is always perpendicular to the ladybug's velocity. Because acceleration is a vector quantity, the centripetal acceleration vector constantly changes direction as it points toward the rotation axis. To comprehend why the ladybug's velocity varies as it moves around the disc, consider two distinct locations on the ladybug's path. The first location is at the top of the circle, and the second location is halfway down the circle. Because of the centripetal acceleration, the ladybug moves in a circle. As a result, it must have a net force toward the centre of the circle. The ladybug's direction of motion is perpendicular to the force acting on it. So, the ladybug accelerates toward the centre of the circle, and its speed varies. The ladybug is initially stationary when it begins its journey around the circle. When it moves along the circle path at a constant radius, its velocity grows due to centripetal acceleration. It is said that the velocity of the ladybug increases as it travels along a circular path with a constant radius. So, the correct answer is option b.

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Answer:

Hey buddy, here is your answer.Hope it helps you.

Explanation:

A catapult is a launching device that allows us to experimentally observe projectile motion. Once the ball is launched, the only forces acting are gravity and air resistance.

Krypton was soon revealed to have formerly been a planet like Earth, only older by eons and possessing. All the advantageous advancement that entailed, starting in the Superman comic strip (though the downside was the hint that Krypton exploded due mainly to old age).

Superman's ability to defy gravity is also explained by another school of thinking, although with a slight variation. Krypton was a gigantic planet with a gravity so strong that typical humans would be crushed beneath its gravitational pull because it was about 1000 times bigger than Earth.

Therefore, Krypton, which was about 1.5 times the size of Earth and was located 50 light-years from the Sun, orbited the red star Rao.

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Answer:

D. Violence

Explanation:

Violence is the threat of or actual use of physical force against oneself or another person. Violence often results in injury or death.

Answer:

D.Violence

Explanation:

You're welcome!

The correct term to fill in the blank is "focal point." This point is called the focal point, or principal focus, of the lens.

For a lens, or a spherical or parabolic mirror, it is a point onto which collimated light parallel to the axis is focused. Since light can pass through a lens in either direction, a lens has two focal points—one on each side. The distance in air from the lens or mirror's principal plane to the focus is called the focal length.

Refraction of the rays of light reflected from or emitted by an object causes the rays to form a visual image of the object. This image may be either real—photographable or visible on a screen—or virtual—visible only upon looking into the lens, as in a microscope. The image may be much larger or smaller than the object, depending on the focal length of the lens and on the distance between the lens and the object. The focal length of a lens is the distance from the centre of the lens to the point at which the image of a distant object is formed. A long-focus lens forms a larger image of a distant object, while a short-focus lens forms a small image.

This point is called the focal point, or principal focus, of the lens.

The correct term to fill in the blank is "focal point."

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A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4θ²) N, where θ is in radians, is applied to the cord, determine the disk’s angular acceleration when it has turned 5 revolutions. The disc has an initial angular velocity \(\omega _o = 1 \ rad/s\) and radius from the center of the disc = 300 mm

Answer:

the angular acceleration = 205.706 rad/sec²

Explanation:

GIVEN THAT:

The disc mass = 8 kg

Force = \(\dfrac{1}{4} \ \ \theta ^2* N\)

We are told that the given θ is in radians; Therefore; the when it has turned 5 revolutions; we have the θ to be:

\(\theta = 5 rev * (\dfrac{2 \ \pi * rad}{1 rev}) \\ \\ \theta = 10 \ \pi \ rad\)

Also;

the initial angular velocity \(\omega _o = 1 \ rad/s\)

radius from the center of the disc = 300 mm = 0.3 m

Thus; the mass moment about the Inertia can be determined via the following expression;

\(I_o = \dfrac{1}{2}*m*r^2\)

\(I_o = \dfrac{1}{2}*8*0.3^2\)

\(I_o = 0.36 \ kg/m^3\)

Now to calculate the angular acceleration; we equate the sum of the moments acting on the Inertia;

SO:

\(\sum M_o = I_o \alpha\)

\(F*0.3 = 0.36* \alpha\)

\(\dfrac{1}{2}* \theta^2 *0.3 = 0.36* \alpha\)

\(\alpha = 0.20836 \ \theta^2 \ rad/sec^2\)

\(\alpha = 0.20836 \ (10 \ \pi )^2 \ rad/sec^2\)

\(\alpha = 205.706 \ rad/sec^2\)

Hence; the angular acceleration = 205.706 rad/sec²

The point where the electric potential is zero is 65 cm from the 13.0 nC charge and 6 cm from the -1.2 nC charge. There is only one point at which the electric potential is zero on the x-axis.

To determine the point at which the electric potential is zero, we should use the formula for electric potential due to a point charge given by;`V=kq/r` Where`V`is the electric potential, `k`is Coulomb’s constant`

= 9 × \(10^9 Nm^2/C^2\)

`q`is the magnitude of the charge in Coulombs, `r`is the distance between the charges in meters.The total electric potential due to both charges is the sum of the electric potential due to the 13.0 nC charge and the electric potential due to the -1.2 nC charge.`

V = V1 + V2``V

= kq1/r1 + kq2/r2``

At the point where the electric potential is zero,`V1 = -V2``kq1/r1

= kq2/r2``r2/r1

= -q1/q2``r2

= -6*13/-1.2

= 65cm

Therefore, the point where the electric potential is zero is 65 cm from the 13.0 nC charge and 6 cm from the -1.2 nC charge. There is only one point at which the electric potential is zero on the x-axis.

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An electromagnet is made when when current is passed through a coil of

wire wrapped around an iron nail. The nail becomes magnetic and able to

pick up metallic objects.

The principle can be used to create an electric motor motor by forming a

current carrying coil into which is attached a movable core that is attached

to a spring.

Based on the arrangement, when a current flows in the coil, the movable

core, known as the armature, is pulled into the the coil and when the

current is switched off the spring pushes the armature out again.

The mechanical energy of the motion of the armature can be used to put

switches on or off, and to open and close valves.

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