what would happen to the final temperature if you cganged the relative amounts of water so that there was the same amount of hot water

Answer:

conservation law, also called law of conservation, in physics, a principle that states that a certain physical property (i.e., a measurable quantity) does not change in the course of time within an isolated physical system.

Explanation:

The definition of a conservation law in physics asserts that a certain observable attribute of an isolated physical system doesn't change over time.

Answer:

The force exerted by one source object on another target object always creates another force at the target object that pushes back on the source object with the same ... or His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.

The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO₂ and water is equal to the energy required to break the bonds of sugar and oxygen. So, option A.

Through a sequence of chemical processes called cellular respiration, glucose is broken down to create ATP, which may then be used as an energy source for a variety of bodily functions. The citric acid cycle, oxidative phosphorylation, and glycolysis are the three primary phases of cellular respiration.

Carbon dioxide and water are created during cellular respiration when glucose is broken down in the presence of oxygen. The energy-carrying molecule ATP (adenosine triphosphate) absorbs the energy generated during the process.

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All of the options listed are important safety measures that should be present in a laboratory, but an eyewash station is the one that has no substitute when it comes to lab safety.

An eyewash station is a crucial safety device that is used to rinse the eyes when they come into contact with chemicals or other hazardous substances. It provides a steady stream of water that can quickly flush out any contaminants that may be present in the eye, preventing further damage or injury. While spill containment kits, fire extinguishers, and laboratory showers are also essential safety measures, they do have substitutes. For example, in the case of a spill, absorbent materials can be used in place of a spill containment kit. However, when it comes to the safety of your eyes, there is simply no substitute for an eyewash station. It is a critical safety device that should always be present in any laboratory environment to protect the health and safety of laboratory workers.

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Among the list of essential safety equipment in a lab, an eyewash station could be considered irreplaceable. It's designed to reduce the potential harm caused by eyes being exposed to dangerous substances, requiring immediate and prolonged washing.

In terms of lab safety, there are important elements that have no substitution. A spill containment kit, fire extinguisher, and a laboratory shower can be very important. However, considering the fact that an eyewash station can be critical in reducing the impact of an accident involving the eyes - as illustrated by the figure highlighting the severe consequences of working without eye protection - it could be argued that an eyewash station has no substitution when it comes to safety in a lab environment.

It's used in the event that a harmful or corrosive substance comes into contact with the eyes. Safety guidelines suggest that once a person's eyes are potentially exposed to such substances, they should be washed immediately with water for at least 15-20 minutes.

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Answer:

15.8 seconds

Explanation:

Create an extended calculation to convert all the unit to what you need.

160 km      1000 m       1 hour         1 min

----------- x ------------- x -------------- x ----------   =  44.4 m/s

1 hour            1 km         60 min      60 sec

So 160km/hr is equal to 44.4m/s

Now you can figure out how many seconds it will take to go 700 meters.

44.4 m          

----------   X     x sec   =  700 m

1  sec

Solve for x sec

x sec = 700m / 44.4 m/s

         =  15.8 seconds

The total volume per minute using a standard macrodrip tubing (10 gtts/ml) is 34 drops/minute. The total volume per minute using a macrodrip tubing where 25 gtts = 1 ml is 14 drops/minute.

Calculation:

Total volume per minute using standard macrodrip tubing (10 gtts/ml):

To calculate the total volume per minute, we need to determine the total number of drops and convert it to milliliters per minute.

Given:

IV 1: 1000 mL RL

IV 2: 500 mL DENS

IV 3: 1000 mL DsW

Using a macrodrip tubing (10 gtts/ml):

IV 1: 1000 mL RL = 1000 * 10 = 10,000 drops

IV 2: 500 mL DENS = 500 * 10 = 5,000 drops

IV 3: 1000 mL DsW = 1000 * 10 = 10,000 drops

Total drops = 10,000 + 5,000 + 10,000 = 25,000 drops

Converting drops to milliliters per minute:

25,000 drops / 10 gtts/ml = 2,500 ml / minute

2,500 ml / minute ≈ 34 drops / minute

The total volume per minute using standard macrodrip tubing is approximately 34 drops/minute.

Total volume per minute using macrodrip tubing (25 gtts = 1 ml):

To calculate the total volume per minute, we need to determine the total number of drops and convert it to milliliters per minute.

Given:

IV 1: 1000 mL RL

IV 2: 500 mL DENS

IV 3: 1000 mL DsW

Using a macrodrip tubing (25 gtts/ml):

IV 1: 1000 mL RL = 1000 / 25 = 40 ml

IV 2: 500 mL DENS = 500 / 25 = 20 ml

IV 3: 1000 mL DsW = 1000 / 25 = 40 ml

Total volume = 40 ml + 20 ml + 40 ml = 100 ml

Converting milliliters to drops per minute:

100 ml * 25 gtts/ml = 2500 drops / minute

2500 drops / minute ≈ 14 drops / minute

The total volume per minute using macrodrip tubing (25 gtts = 1 ml) is approximately 14 drops/minute.

Using a standard macrodrip tubing (10 gtts/ml), the total volume per minute is approximately 34 drops/minute.

Using a macrodrip tubing where 25 gtts = 1 ml, the total volume per minute is approximately 14 drops/minute.

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Answer:

Explanation:

The horizontal component of force is Fcosθ if the man pulls the sled with a 10 N force.  Force has both a magnitude and a direction since it is a vector quantity.

A force is an external cause that, when applied, alters or has the potential to alter a body's condition. The body comes to rest while it is moving, and it moves when it is at rest.

The body's orientation, form, size, etc. may also alter as a result. An illustration would be to push or forcefully shove a door. Force has both a magnitude and a direction since it is a vector quantity. If the man pulls the sled with a 10 N force then the horizontal component of force is Fcosθ. Your training at this level should place a major emphasis on the idea that a push or even a pull was referred to as an force.

Therefore, the horizontal component of force is Fcosθ if If the man pulls the sled with a 10 N force.

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Pumping out the bottom 4m of water requires more work than pumping out the top 4m of water.

To determine which requires more work, pumping out the top 4m of water or the bottom 4m of water, we need to consider the potential energy associated with each scenario.

The potential energy of an object is given by the equation:

PE = m×g×h

where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height.

Assuming the density of water is constant, the mass of the water being pumped out will be the same for both scenarios (top 4m and bottom 4m). Therefore, the only difference will be the height (h) at which the water is being pumped.

Scenario 1: Pumping out the top 4m of water:

In this case, the height (h) is 4m.

Scenario 2: Pumping out the bottom 4m of water:

In this case, the height (h) is the total height of the water column minus 4m.

Comparing the two scenarios, pumping out the bottom 4m of water will require more work. This is because the water column height is greater when pumping from the bottom, resulting in a larger potential energy.

In conclusion, pumping out the bottom 4m of water requires more work than pumping out the top 4m of water.

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The types of particles of sand that would make up the location would be Fine sand and silt. Option a

Sand is a granular material composed of finely divided rock and mineral particles with a particle size range of 0.063 to 2 mm. The properties of sand can vary depending on factors such as the source of the sand, the size and shape of the particles, and the environment in which it is found. However, some general properties of sand include:

Particle size: Sand particles are typically larger than silt and clay particles but smaller than gravel particles. They range in size from 0.063 to 2 mm in diameter.

Texture: Sand has a gritty texture and is often used in abrasive applications, such as sandpaper or sandblasting.

Color: The color of sand can vary depending on the composition of the particles. For example, sand made from quartz crystals is typically white or light-colored, while sand made from iron-rich minerals may be darker in color.

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Answer:

E=2.58155844×10^-29

Explanation:

we use this formula

E= hc/ lambda

E= [(6.626×10^-34)( 3×10^8)]/(7.7×10^-3)

E=2.58155844×10^-29

Answer:

Gravitational potential energy is the maximum at point C and lowest at point A

Explanation:

The image for the question is provide in the attached file

The energy of pendulum is governed by mechanical energy. Mechanical energy is the sum of potential energy and kinetic energy

Potential energy increases with increasing height. Thus, when the pendulum bob is at maximum height, then its potential energy is also the highest.

Thus, At point C, the gravitational potential energy is the highest

At point A, the  gravitational potential energy  is substantial but lower than that of gravitational potential energy at point C

AT point A, gravitational energy is the lowest

Answer:

Explanation:

moment of inertia of flywheel = 1/2 m R²

= .5  x 1500 x .6²

= 270 kg m²

If required angular velocity be ω

rotational kinetic energy = 1/2 I ω²

= .5 x 270 x ω² = 135 ω²

kinetic energy of bus when its velocity is 20 m/s

= 1/2 x 10000 x 20²

= 2000000 J

Given 90 % of rotational kinetic energy is converted into bus's kinetic energy

135 ω² x 0.9 = 2000000 J

ω²=16461

ω = 128.3 radian /s

b )

Let the height required be h .

Total energy of bus at the top of hill = mgh + 1/2 m v²

m ( gh + .5 v²)

= 10000 ( 9.8h + .5 x 3²)

From conservation of mechanical energy theorem

10000 ( 9.8h + .5 x 3²) = 2000000

9.8h + .5 x 3² = 200

9.8h  = 195.5

h = 19.95 m .

Answer:

12 meters and 2 n

Explanation:

16 -  u = 6 (8.0 + 11)

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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The potential difference between the two charged parallel plates is 1.2 V. The correct option is B.

The electric field strength (E) between two charged parallel plates is given by E = V/d, where V is the potential difference and d is the distance between the plates.

We are given that the electric field strength is 6.0 V/cm, which can be converted to 6.0 × 10² V/m. The distance between the plates (d) is given as 0.20 cm, which can be converted to 0.20 × 10⁻² m.

Substituting these values into the equation E = V/d, we can solve for the potential difference (V):

V = E * d

V = 6.0 × 10² V/m * 0.20 × 10⁻² m

Simplifying this expression gives us:

V = 1.2 V

Therefore, the potential difference between the two charged parallel plates is 1.2 V. Option B is the correct answer.

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Expression for number of turns of the solenoid is d.N = L / d

number of turns, N, in the solenoid is 77,272 turns.

Expression for the length of the solenoid is L2 = π × D × N

length of the solenoid, (L2), in meters is 3,655.30 m

magnitude of the magnetic field at the center of the solenoid, in Tesla is 0.224 T.

Explanation:-

A) The expression for the number of turns, N, in the solenoid:

For any given solenoid, the number of turns, N, is proportional to the length of the wire, L, and inversely proportional to the diameter of the wire,

d.N = L / d

B) Calculation of the number of turns, N, in the solenoid:

N = L / dN

= 85 m / 1.1 × 10⁻³ mN

= 77,272 turns

C) The expression for the length of the solenoid, (L2), in terms of the hollow tube D, the length of the wire L, and the diameter of the wire d.

L2 can be calculated using the following formula:

L2 = π × D × N

Where N is the number of turns

D) Calculation of the length of the solenoid, (L2), in meters:

L2 = π × D × N

= π × 0.015 m × 77,272L2

= 3,655.30 m

E) Calculation of the magnitude of the magnetic field at the center of the solenoid, in Tesla:

The magnitude of the magnetic field at the center of the solenoid, B, can be calculated using the following formula:

B = μ₀ × N × I / L

Where N is the number of turns

I is the current flowing through the solenoid

L is the length of the solenoid

μ₀ is the permeability of free space

B = 4π × 10⁻⁷ × 77,272 × 4.5 / 3,655.30B = 0.224 T

Therefore, the magnitude of the magnetic field at the center of the solenoid is 0.224 T.

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Answer:

Explanation:

from the question we are told that

Load \(L=15kg\)

Force\(F=70N\)

Angle of inclination \(=20.0 degres\)

Displacement \(m=5 meters\)

coefficient of kinetic friction \(\alpha =0.300\)

The speed at which the motor will run on no-load can be determined by using the concept of the motor's input and output power.
Given:
Full-load power (output power) = 7.5 kW
Full-load efficiency = 86% = 0.86
Total no-load input power = 600 W
First, we can calculate the full-load input power using the efficiency formula:
Full-load input power = Full-load power / Full-load efficiency
Full-load input power = 7.5 kW / 0.86 = 8.72 kW
Now, we can determine the ratio of the no-load input power to the full-load input power:
Power ratio = Total no-load input power / Full-load input power
Power ratio = 600 W / 8.72 kW = 0.0688
Since power is directly proportional to the speed of the motor, we ca
calculate the speed on no-load using the power ratio
No-load speed = Full-load speed * √(Power ratio)
No-load speed = 1,200 r/min * √(0.0688) ≈ 292.78 r/min
Therefore, the motor will run at approximately 292.78 r/min on no-load.
1.2.2 To reduce the speed to 1,000 r/min when giving full-load torque, we need to add a resistance in the armature circuit. The speed of the motor is inversely proportional to the armature circuit resistance.
Given:
Full-load speed = 1,200 r/min
Target speed = 1,000 r/min
Using the speed ratio formula:
Speed ratio = Full-load speed / Target speed
Speed ratio = 1,200 r/min / 1,000 r/min = 1.2
Since the speed is inversely proportional to the resistance, we can calculate the resistance ratio:
Resistance ratio = 1 / Speed ratio
Resistance ratio = 1 / 1.2 ≈ 0.833
Now, we can calculate the required resistance to be added in the armature circuit:
Required resistance = Armature circuit resistance * Resistance ratio
Required resistance = 0.3 ohm * 0.833 ≈ 0.25 ohm
Therefore, a resistance of approximately 0.25 ohm needs to be added in the armature circuit to reduce the speed to 1,000 r/min when giving full-load torque, assuming the flux is proportional to the field current.

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The graph shows that the ship decelerates in the forward direction, and then continues to slow down in the forward direction, but with more deceleration.

The term deceleration refers to a gradual reduction in the velocity of the object with time. We know that when an object is moving at a steady rate, the velocity of the object does not change and this can be seen as a flat portion in the velocity time graph.

Looking at the graph, we can see that we could  tend to look at the acceleration of the ship based on the graph with the view  that the ship is moving in the forward direction at a steady rate. Then it decelerates in the forward direction, and then continues to slow down in the forward direction, but with more deceleration.

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Answer:

1200 watt

Explanation:

P= I*V=10*120=1200watt

The thickness of the foil is approximately 0.07 cm if a metal has a density of 7.4 g/cm3. a rectangular thin foil of this metal measuring 2.4 cm by 6.cm has a mass of 7.42 g.

To find the thickness of the foil, we first need to calculate its volume. As the foil has a rectangular shape with length 6.0 cm and width 2.4 cm, the area can be calculated as: A = l*w

= 6.0 cm * 2.4 cm

= 14.4 cm^2

Next, we can use the formula for density to calculate the volume of the foil: density = mass / volume

volume = mass / density

Substituting the given values, we get: volume = 7.42 g / 7.4 g/cm^3

= 1.0027 cm^3

Finally, we can calculate the thickness of the foil by dividing the volume by the area: thickness = volume / area

= 1.0027 cm^3 / 14.4 cm^2

≈ 0.0697 cm

≈ 0.07 cm (rounded to two decimal places)

The thickness of the foil is approximately 0.07 cm.

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Answer:

Dogs are able to hear much higher frequencies than humans are capable of detecting. For this reason, dog whistles that are inaudible to the human ear can be heard easily by a dog. If a dog whistle has a frequency of 30,000 Hz, what is the wavelength of the sound emitted?

Answer:

the answer would be Salt

Explanation:

Based on the measurements, the maximum height reached by the puck in trial 6 is determined as 5.1 m.

The maximum height reached by the puck is calculated by applying the principle of conservation of energy as shown below;

From the trials, the puck was thrown upwards with initial velocity of 10 m/s and the mass of the puck is given as 400 g.

With these values we can predict the maximum height the puck will reach by applying the principle of conservation of energy.

Potential energy of the puck at maximum height = Kinetic energy of the puck at minimum height

P.E = K.E

mgh = ¹/₂ mv²

h = ¹/₂ (v² / g )

where;

The maximum height reached by the puck is calculated as follows;

h =  ¹/₂ (10² / 9.8 )

h = 5.1 m

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We can find the energy needed to ionize the hydrogen atom.

We can find the wavelength of a spectral line.

We can find the energy change of the electron moving between two levels.

The first atomic model to adequately explain the radiation spectra of atomic hydrogen was Bohr's model of the hydrogen atom. The atomic Hydrogen model was first presented by Niels Bohr in 1913. Rutherford's model of the hydrogen atom leaves several holes, which Bohr's model of the hydrogen atom tries to fill in.

It has a particular place in history since it introduced the quantum theory, which led to the development of quantum mechanics. Bohr proposed that electrons moved in predetermined orbits or shells with defined radii around the nucleus. It was impossible for electrons to reside between any shells other than those having a radius given by the equation below.

\(r (n) =n^{2} * r(1)\)

\(E (n) = \frac{1}{n^{2} } 13.6eV\)

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The spring constant of a spring is a measure of its stiffness, or the amount of force required to stretch or compress the spring by a certain amount. The spring constant is directly proportional to the force applied to the spring and inversely proportional to the amount of deformation.

In the case of two identical springs, but with different lengths, the spring constant of each spring would depend on the material and the geometry of the spring, including the number of turns, diameter, and wire size. However, assuming that the two springs are made of the same material and have the same geometry except for their length, the spring constant of the longer spring would be lower than the spring constant of the shorter spring.

The reason for this is that the spring constant is inversely proportional to the length of the spring. In other words, the longer the spring, the more it will stretch under the same amount of force. This means that the longer spring will have a lower spring constant, because it takes less force to stretch the spring by a certain amount. Mathematically, we can express this relationship as:

k ~ 1/L

where k is the spring constant and L is the length of the spring. Therefore, if spring a is 3 times longer than spring b, we would expect spring b to have a spring constant that is 3 times greater than spring a.

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Hi there!

Answer:

Matter

Explanation:

To find the correct answer, you have to try all of the answers. Like below:

All cannot be created or destroyed.

This doesn't make sense.

Mass cannot be created or destroyed.

This may sound correct, but when you look at the big picture, this is wrong.

Matter cannot be created or destroyed.

This is correct because it is a saying created long ago and proven with experiments.

Galaxies cannot be created or destroyed.

This is wrong because new galaxies are being created everyday!

Stars cannot be created or destroyed.

This is wrong because like galaxies, new stars are being created everyday!

The minimum and maximum braking distances needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection are as follows:

- For small cars: Minimum ≈ 1773.028 m, Maximum ≈ 1568.850 m

- For large trucks: Minimum ≈ 3285.760 m, Maximum ≈ 2409.595 m

To calculate the minimum and maximum braking distances, we can use the equations of motion for a decelerating vehicle.

The equation for the braking distance of a vehicle is given by:

d = (v^2) / (2 * μ * g)

where d is the braking distance, v is the initial velocity of the vehicle, μ is the coefficient of friction between the tires and the road, and g is the acceleration due to gravity.

Let's calculate the minimum and maximum braking distances separately for small cars and large trucks.

For small cars with a mass of 563 kg:

- Minimum braking distance:

  v = 8989 km/h = (8989 * 1000) / 3600 m/s = 2496.944 m/s

  μ_min = 0.536

  d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.536 * 9.8) ≈ 1773.028 m

  Maximum braking distance:

  μ_max = 0.599

  \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.599 * 9.8) ≈ 1568.850 m\)

For large trucks with a mass of 3951395 kg:

- Minimum braking distance:

  v = 8989 km/h = 2496.944 m/s (same as for small cars)

  μ_min = 0.350

 \(d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.350 * 9.8) ≈ 3285.760 m\)

  Maximum braking distance:

  μ_max = 0.480

 \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.480 * 9.8) ≈ 2409.595 m\)

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The coefficient of volume expansion is 5.4 × 10⁻⁶ K⁻¹ if the coefficient of linear expansion is 1.8 × 10-6 K-1.

The relation between the coefficient of linear thermal expansion and the coefficient of volume expansion is given by the following equation:

γ = 3α, where γ is the coefficient of volume expansion and α is the coefficient of linear expansion.

Given:  coefficient of linear expansion, α= 1.8 × 10⁻⁶ K⁻¹

so, the coefficient of volume expansion, γ = 3α

γ = 3  × 1.8 × 10⁻⁶ K⁻¹

γ = 5.4 ×10⁻⁶ K⁻¹

Therefore, the coefficient of volume expansion is 5.4 × 10⁻⁶ K⁻¹ if the coefficient of linear expansion is 1.8 × 10⁻⁶ K⁻¹.

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Answer:

electrons

Explanation:

Electric fields are usually created when electrons are transferred between objects?