What will be the substitution product of (S)-2-chloro-3-methylbutane in polar aprotic conditions favoring SN2?

Answer:

490 in^3 = 8.03 L

Explanation:

Given:

The engine displacement = 490 in^3

= 490 in³

To determine the engine piston displacement in liters L;

(NOTE: Both in^3 (in³) and L are units of volume). Hence, to find the engine piston displacement in liters (L), we will convert in^3 to liters (L)

First, we will convert in³ to cm³

Since 1 in = 2.54 cm

∴ 1 in³ = 16.387 cm³

If 1 in³ = 16.387 cm³

Then 490 in³ =  (490 in³ × 16.387 cm³) / 1 in³ = 8029.63 cm³

∴ 490 in³ = 8029.63 cm³

Now will convert cm³ to dm³

(NOTE: 1 L = 1 dm³)

1 cm = 1 × 10⁻² m = 1 × 10⁻¹ dm

∴ 1 cm³ = 1 × 10⁻⁶ m³ = 1 × 10⁻³ dm³

If 1 cm³ = 1 × 10⁻³ dm³

Then, 8029.63 cm³ = (8029.63 cm³ × 1 × 10⁻³ dm³) / 1 cm³ = 8.02963 dm³

≅ 8.03 dm³

∴ 8029.63 cm³ = 8.03 dm³

Hence, 490 in³ = 8029.63 cm³ = 8.03 dm³

Since 1L = 1 dm³

∴ 8.03 dm³ = 8.03 L

Hence, 490 in³ = 8.03 L

An engine piston displacement of 490 in³ is equivalent to 8.03 L.

The engine piston displacement is 490 in³ and we want to convert it to liters. Since both of them are units of volume, we will need one or more conversion factors.

A conversion factor is an arithmetical multiplier for converting a quantity expressed in one set of units into an equivalent expressed in another.

We will use the conversion factor 1 in = 2.54 cm.

490 in³ × (2.54 cm/1 in)³ = 8.03 × 10³ cm³

We will use the conversion factor 1 L = 1000 cm³.

8.03 × 10³ cm³ × (1 L/1000 cm³) = 8.03 L

An engine piston displacement of 490 in³ is equivalent to 8.03 L.

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According to the solubility of  of sparingly soluble electrolytes by conductometer and potentiometer.

Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.

The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.It can also be determined for electrolytes.

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The unknown gas : N₂

Given

Volume : 23.1 L

Mass : 28.85 g

Required

The identity of the unknown gas

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol

So mol for The unknown gas :

= 23.1 L : 22.4 L

= 1.0313

The molar mass of unknown gas :

= mass : mol

= 28.85 g : 1.0313

= 27.974 g/mol≈ 28 g/mol

23.1 L of nitrogen has a mass of 28.85 g at STP.

An unknown gas occupies 23.1 L at STP. We will calculate the moles of the gas, considering that 1 mole of an ideal gas occupies 22.4 L at STP.

\(23.1 L \times \frac{1mol}{22.4L} = 1.03 mol\)

1.03 moles of the unknown gas have a mass of 28.85 g. The molar mass of the gas is:

\(M = \frac{28.85 g}{1.03 mol} = 28.0 g/mol\)

A gas with a molar mass of 28.0 g/mol is likely to be nitrogen gas.

23.1 L of nitrogen has a mass of 28.85 g at STP.

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6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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Answer:

2.21 x 10⁻⁷m⁻¹

Explanation:

Given parameters:

Energy of the photon = 9.02 x 10⁻¹⁹J

Unknown:

Wavelength of the photon = ?

Solution;

The wavelength and energy of a photon are related using the expression below;

       E = \(\frac{hc}{wavelength}\)

h is the Planck's constant  = 6.63 x 10⁻⁴m²kg/s²

c is the speed of light

E is the energy

   h c = E x wavelength

   Wavelength = \(\frac{hc}{E}\)   = \(\frac{6.63 x 10^{-34} x 3 x 10^{8} }{9.02 x 10^{-19} }\)  

   Wavelength = 2.21 x 10⁻⁷m⁻¹

Answer:

0.036  × 10²³ oxygen atoms

Explanation:

Given data:

Mass of compound = 0.24 g

Number of oxygen atoms = ?

Solution:

First of all we will calculate the number of moles of compound.

number of moles = mass/ molar mass

Number of moles = 0.24 g/ 100.1 g/mol

Number of moles = 0.002 mol

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole of CaCO₃ contain 3 moles of oxygen atom.

0.002 mol × 3 = 0.006 moles of oxygen atoms.

Number of oxygen atoms:

1 mole = 6.022 × 10²³ number of oxygen atoms

0.006 mol ×  6.022 × 10²³ f oxygen atoms / 1 mol

0.036  × 10²³ oxygen atoms

Answer:

1.95 g KClO3

Explanation:

We're asked to find the mass, in g, of KClO3 that decomposes to give a certain amount of O2.

 Let's use the ideal gas equation to find the moles of O2 that form. 

P=747torr(1latm760torr)=0.983 atmV=797mL(1lL103mL)=0.797 

LT=128oC+273=401 KPlugging in known values, we haven=PVRT=(0.983atm)(0.797L)(0.082057L∙atmmol∙K)(401K)=0.0238 mol O2

Now, we'll use the coefficients of the chemical equation to find the relative number of moles of KClO3 that reacted:0.0238mol O2(2lmol KClO33mol O2)=0.0159 mol KClO3

Finally, we'll use the molar mass of potassium chlorate (122.55 g/mol) to find the number of grams that reacted:

0.0159mol KClO3(122.55lg KClO31mol O2)=1.95 g KClO3

Answer:

B.

Explanation:

Can you give me brainliest? i need to rank up

Answer:

2nd One is correct

3.28mmHg

According to ideal gas equation

P is the pressure (in atm)

• V is the ,volume (i,n L)

• n is the ,moles, of the insulin

• R is the ,Gas constant = 0.08205Latm/molK

• T is the ,temperature

Determine the moles of insulin

moles = mass/molar mass

moles of insulin = 0.103/5700

moles of insulin = 0.00001807moles

Determine the required pressure

Convert the unit to mmHg

Using the conversion factor

1atm = 760mmHg

0.004315atm = 0.004315atm * 760

0.004315atm = 3.28mHg

Therefore the osmotic pressure of a solution is 3.28mmHg

Answer:

the original substances in any chemical reaction. products. the resulting substances in any....chromium(III) oxide, and water. (NH4)2Cr2O7(s) → N2(g) + Cr2O3(s) + 4H2O(g).

The correct dose for a 175 lb patient would be approximately 0.48602 grams.

To convert 6.13 mg/kg to grams, we need to consider the weight of the patient and perform a unit conversion. Here's the step-by-step process:

1. Convert the weight of the patient from pounds to kilograms.

  175 lb * (1 kg / 2.205 lb) = 79.37 kg (rounded to two decimal places)

2. Calculate the correct dose in grams by multiplying the patient's weight by the given dosage.

  79.37 kg * 6.13 mg/kg = 486.02 mg

3. Convert the dose from milligrams (mg) to grams (g) by dividing by 1000.

  486.02 mg / 1000 = 0.48602 g (rounded to five decimal places)

Therefore, the correct dose for a 175 lb patient would be approximately 0.48602 grams.

It's important to note that this calculation assumes the dosage is based on body weight and that the given dosage is appropriate for the patient's condition. Always consult a healthcare professional or follow the instructions of a medical prescription for accurate dosing information.

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Answer:

Less than 7

Explanation:

during the titration of strong acid and weak base, the weak base is usually kept in the flask and strong acid is kept in the burette. So when we add strong acid slowly drop by drop, slowly the pH level of solution starts to decrease and at equivalence point the acid overpowers the base as a strong acid was taken over a weak base.

Answer:

olivine i think

Explanation:

The final temperature of the mixture given that 25 g of water at 25 °C is mixed with 25 g of water at 65 °C, is 45 °C

The final temperature of the mixture can be obtained by calculating the equilibrium temperature of the mixture. This is shown below:

Heat loss by warm water = Heat gain by cold water

MᵥᵥC(Tᵥᵥ - Tₑ) = MC(Tₑ - T)

Cancel out C

Mᵥᵥ(Tᵥᵥ - Tₑ) = M(Tₑ - T)

25× (65 - Tₑ) = 25 × (Tₑ - 25)

Cancel out 25

65 - Tₑ = Tₑ - 25

Collect like terms

65 + 25 = Tₑ + Tₑ

90 = 2Tₑ

Divide both side by 2

Tₑ = 90 / 2

Tₑ = 45 °C

Thus, we can conclude that the final temperature the mixture is 45 °C

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Following best describes the purpose and outcome of demonstration: This is demonstration of Boyle's law. As volume increases, the pressure decreases and marshmallow will grow larger.

Gas laws are set of fundamental principles that describe the behavior of gases under different conditions of temperature, pressure, and volume.

These laws include Boyle's law, Charles's law, Gay-Lussac's law, and the combined gas law. These laws help to predict the behavior of gases in different situations and can be used to determine properties such as temperature, pressure, volume, and the number of moles of gas present.

Boyle's Law explains that volume of gas increases as the pressure decreases.

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A general exponential expression is something like:

A^n

This means that we need to multiply the number A by itself n times.

Using that we will get (-2)^6 = 64

With that definition, we can rewrite:

(-2)^6 = (-2)*(-2)*(-2)*(-2)*(-2)*(-2)

So we just need to solve the above expression.

Also, remember the rule of signs:

(-)*(-) = (+)

We will get:

(-2)*(-2)*(-2)*(-2)*(-2)*(-2) =  [(-2)*(-2)]*[(-2)*(-2)]*[(-2)*(-2)]

                                        =  4*4*4 = 16*4 = 64

Then we got:

(-2)^6 = 64

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The chemical equation that is balanced is:

2 KClO3 ( s )+ MnO2 (s)→ 2 KCl ( s ) + 3 O2 (g) ​

Potassium chlorate (s) when heated in the presence of a manganese dioxide catalyst: When heated in the presence of a manganese dioxide catalyst, potassium chlorate (s) decomposes to create potassium chloride and oxygen gas.

The chemical equation that is balanced is:

2 KClO3 ( s )+ MnO2 (s)→ 2 KCl ( s ) + 3 O2 (g) ​

When potassium chlorate (KClO3) is heated in the presence of manganese dioxide catalyst, it decomposes to form potassium chloride and oxygen gas. The reaction is termed as decomposition reaction.

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Answer:

points

Explanation:

Answer:

Where is the diagram?

Explanation:

..........................

Answer:

the answer is B- social contract

Explanation:

the person above me is correct

The heat energy released by the mercury is 44.45 J.

What is Freezing Point?

Freezing point is the temperature at which a substance changes from a liquid to a solid state at a given pressure. It is also known as the melting point in reverse, and it is the temperature at which the solid and liquid phases of a substance are in equilibrium. The freezing point of a substance depends on various factors such as pressure, composition, and the presence of impurities.

To solve the problem, we need to break it down into two steps: first, we need to calculate the heat energy required to cool the mercury from 23.0°C to -38.8°C; second, we need to calculate the heat energy required to freeze the mercury at -38.8°C.

Step 1: Cooling the mercury from 23.0°C to -38.8°C

To calculate the heat energy required to cool the mercury, we can use the formula:

Q = m × c × ΔT

where Q is the heat energy, m is the mass of the mercury, c is the specific heat of the mercury, and ΔT is the change in temperature.

The mass of 1.20 mL of mercury can be calculated using its density:

m = density × volume = 13.6 g/cm³ × 1.20 mL = 16.32 g

The change in temperature is:

ΔT = -38.8°C - 23.0°C = -61.8°C

Now we can calculate the heat energy required to cool the mercury:

Q = 16.32 g × 0.140 J/gK × (-61.8°C) = -141.6 J

Note that the negative sign indicates that heat energy is released, not absorbed, as the mercury is cooled.

Step 2: Freezing the mercury at -38.8°C

To calculate the heat energy required to freeze the mercury, we can use the formula:

Q = m × ΔHfus

where Q is the heat energy, m is the mass of the mercury, and ΔHfus is the heat of fusion of the mercury.

The heat energy required to freeze the mercury is:

Q = 16.32 g × 11.4 J/g = 186.05 J

Note that the mass of the mercury does not change during freezing, so we can use the same mass as in step 1.

Total heat energy required:

The total heat energy required is the sum of the heat energies in step 1 and step 2:

Qtotal = Q1 + Q2 = -141.6 J + 186.05 J = 44.45 J

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Equivalence point is dependent on stoichiometry of balanced reaction of acid and base. Stoichiometry only considers number of mols involved, not strength of reactants involved.

To ascertain how much of a specific drug is present in a sample, an experiment called a b is done. A diprotic acid is one that has a two-proton (H+) capacity per molecule. Two equivalence points—points at which the number of moles of acid and base are equal—are present when a diprotic acid is titrated with NaOH. When all of the acids have been neutralised, the first equivalence point is reached; meanwhile, the second equivalence point is reached when the surplus base has been neutralised. The amount of NaOH solution required to go from the first equivalence point to the second equivalence point is twice the amount required to travel from the first equivalence point to the first equivalence point.

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Answer:

Exfoliation involves the removal of the oldest dead skin cells on the skin's outermost surface. Exfoliation is involved in all facials, during microdermabrasion or chemical peels. Exfoliation can be achieved by mechanical or chemical means.

Explanation:

I did copy off internet!

:P

Answer:

what is this i dont know what kind of math this is

Answer:

A

Explanation:

brainliest pls

Heat is produced anytime current flows in a circuit, due to the collision between the flowing free electrons and the fixed atoms. When an electric current flows through a conductor, the free electrons move through the lattice of atoms.

As they move, they collide with the fixed atoms, causing the atoms to vibrate and transfer energy to neighboring atoms. This energy transfer increases the temperature of the conductor, resulting in the production of heat.

The amount of heat produced is directly proportional to the amount of current flowing through the conductor, the resistance of the conductor, and the time for which the current flows. This relationship is described by Joule's law, which states that the heat produced is equal to the product of the current, the resistance, and the time.

Mathematically, this can be expressed as H = I^2RT, where H is the heat produced, I is the current, R is the resistance, and T is the time. The collision between the flowing free electrons and the fixed atoms in a conductor leads to the production of heat, which is proportional to the current, resistance, and time for which the current flows.

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An exothermic reaction releases 325 kJ. 1359.8 kJ energy is this in calories.

An exothermic reaction is a chemical reaction that releases heat energy into the surroundings. During an exothermic reaction, the products of the reaction have less potential energy than the reactants, and the excess energy is released in the form of heat.

One calorie is defined as the amount of energy required to raise the temperature of one gram of water by one degree Celsius.

One joule is defined as the amount of energy required to apply a force of one newton over a distance of one meter.

1 cal = 4.184 J

1 cal = 0.004184 kJ

325000 cal = x kJ

0.004184/ 1 = x / 325000

x = 1359.8 kJ

Thus, 1359.8 kJ energy is this in calories.

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Explanation:

Simply multiply the # of moles of O2 by a molar ratio to give the # of moles of MgO:

#moles O2 × (2 mol MgO/1 mol O2) = # moles of MgO

where the quantity inside the parenthesis is the molar ratio between MgO and O2.

Answer:

Option d. 6.95 g

Explanation:

First of all, we state the reaction:

2NaCl + Pb(NO₃)₂ → PbCl₂ +  2NaNO₃

We determine the moles of each reactant, to state the limiting

Firstly we convert volume frm mL to L

0.200 L . 0.250M = 0.05 moles of NaCl

0.200L . 0.250M = 0.05 moles of Pb(NO₃)₂

Acording to stoichiometry we know that relation is 1:2, so the limiting reagent is the NaCl.

For 1 mol of Pb(NO₃)₂ I need 2 moles of NaCl

For 0.05 moles of Pb(NO₃)₂ I would need, the double → 0.1 moles

(We only have, 0.05 moles of NaCl)

Stoichiometry to the formed product is 2:1

From 2 moles of NaCl I produce 1 mol of PbCl₂

From 0.05 moles I would produce, the half → 0.025 moles

Let's convert the moles to mass → 0.025 mol . 278.1 g / 1mol = 6.95 g

6.95 g mass of lead (II) chloride would be produced.

Considering the balanced equation of the reaction:

2 NaCl + Pb(NO3)2 → PbCl2 + 2 NaNO3

Mole of 200 mL, 0.250 M NaCl = 0.200 x 0.25

                                                      = 0.05 mole

Mole of 200 mL, 0.25 M Pb(NO3)2 = 0.2 x 0.25

                                                          = 0.05 mole

Stoichiometric mole ratio of NaCl and Pb(NO3)2 = 2:1

Thus, NaCl is the limiting reactant.

Mole ratio of NaCl to PbCl2 = 2:1

Equivalent mole of PbCl2 = 0.05/2

                                           = 0.025 mole

Mass of 0.025 mole PbCl2 = 0.025 x 278.1

                                             = 6.95 g

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Answer:

V₁ = 808.9mL

Explanation:

Based on Charles's law, the volume of a sample of gas is directely proportional to its absolute temperature. The formula is:

\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)

Where V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas.

The initial state is:

V₁ = Our incognite

T₁ = 79°C + 273.15 = 352.15K

Final state is:

V₂ = 990.4mL

T₂ = 158°C + 273.15 = 431.15K

Replacing:

\(\frac{V_1}{352.15K} =\frac{990.4mL}{431.15K}\)

Considering the Charles's Law,  the volume at 79 °C is 808.86 mL.

Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is maintained at a constant pressure.

This law says that for a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement they have the gas molecules.

In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

\(\frac{V}{T}=k\)

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

\(\frac{V1}{T1}=\frac{V2}{T2}\)

In this case, you know:

Replacing in Charles's law:

\(\frac{V1}{352 K}=\frac{990.4 mL}{431 K}\)

Solving:

\(V1=\frac{990.4 mL}{431 K}x352 K\)

V1=808.86 mL

Finally, the volume at 79 °C is 808.86 mL.

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