What was the desire of the first Shah,

Esma'il, of the Safavid Empire?

A. Become the next Caliph

B. Convert all Sunni to Shia

c. Enslave the Ottomans

D. Adopt Chinese Architecture

The lengths of LV and OE are 15cm, and the lengths of LD and EV are 3√7 cm and 9/√7 cm, respectively.

Since LOVE is a kite, LV and OE are perpendicular bisectors of each other. Let the length of LD be x, and the length of EV be y. Then, we can use the Pythagorean theorem and the fact that the diagonals bisect each other to set up two equations:

x² + (LV/2)² = DV²/4

y² + (OE/2)² = LE²/4

Simplifying each equation and substituting the given values, we get:

x² + (LV/2)² = 81/4

y² + (OE/2)² = 225/4

We also know that the diagonals bisect each other, so we can set up another equation:

LV/2 + OE/2 = LO = VE

Substituting the given value for LE, we get:

LV/2 + OE/2 = 15

Solving this equation for one of the variables, we get:

LV = 30 - OE

Substituting this expression into the first equation above, we get:

x² + ((30 - OE)/2)² = 81/4

Simplifying and rearranging, we get:

OE² - 60OE + 675 = 0

Using the quadratic formula, we get:

OE = (60 ± √(3600 - 2700)) / 2

OE = 15 or 45

If OE = 15, then LV = 30 - 15 = 15, and we can solve for x and y:

x² + 7.5² = 81/4

y² + 7.5² = 225/4

Solving these equations, we get:

x = 3√7

y = 9/√7

If OE = 45, then LV = 30 - 45 = -15, which is impossible for a length. Therefore, the solution is:

LV = OE = 15

x = 3√7

y = 9/√7

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Complete question:

LOVE is a kite. LV and OE are diagonals. The segments DV = 9cm and LE = 15cm are given. Find the lengths of the other segments of the diagonals, DV, OE, and LV.

Evaluating the algebraic expressions for the values given, we have:

a. -7

b. -10.

To evaluate and algebraic expression, plug in the value of the variable given and solve accordingly.

a. Given the algebraic expression, xy + 5.

If x = 2, and y = -6, then substitute x = 2 and y = -6 to evaluate the algebraic expression:

xy + 5

(2)(-6) + 5 [substitution]

= -12 + 5

= -7

b. Given the algebraic expression, x/y - 12, if x = 22 and y = 11, then substitute x = 22 and y = 11 into the expression and evaluate:

x/y - 12

22/11 - 12 [substitution]

= 2 - 12

= -10.

Thus, the values of the expressions when evaluated for the given variables are:

a. -7

b. -10.

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According to the given information, the sample period should be from 2010-2020.

a) Model specification

The model specification based on the scenario above is as follows:

SDF= f(T, TI, NL)

Where: SDF= Sustainable Development Framework

T= Tourism

TI= Technological innovation

NL= National leadership

b) Justification for the selection of the dependent and independent variables model:

Dependent variable: The dependent variable in this model is Sustainable Development Framework (SDF). The model seeks to develop a framework for sustainable development that would facilitate growth, environmental and socio-cultural sustainability.

Independent variables:

The independent variables are tourism sustainability, technological innovation, and quality of leadership. These variables drive economic development. The inclusion of tourism sustainability reflects its importance in the global economy and its potential to drive growth.

The inclusion of technological innovation reflects its potential to enhance productivity and create new industries. The inclusion of national leadership reflects the role of governance in promoting sustainable development and managing negative externalities.

c) Justification for the selection of the sample period:

The sample period should be selected based on the availability of data for the variables of interest. Ideally, the period should be long enough to capture trends and patterns in the data. However, it should not be too long that the data becomes obsolete or no longer relevant.

Additionally, the period should also reflect the context and relevance of the research question. Therefore, the sample period for this study should cover the last decade to capture the trends and patterns in the data and reflect the relevance of the research question.

The sample period should be from 2010-2020.

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Answer:

the third one -1/2

Step-by-step explanation:

hxudcufj ydhvhdcudfib

Answer:

24 for 2.99

Step-by-step explanation:

2.99/24 = $0.1245 per ounce
4.99/36  = $0.1386 per ounce

So the 36 cost more per ounce.

Answer:s

12 weeks

Step-by-step explanation:

if keith starts with $500 and wants to end with (at least) $200

he can withdrawn up to $500-$200=$300

if he withdraws $25 week the $300 will last $300 $25 week =12 weeks

so this is the solution to the problem.

Money that Keith has  at the beginning of the summer = $ 500 )

Money that keith  wants to have at the end of the summer = At least $200

Money that Keith withdraws every week =$25

Let w to represent the number of weeks in the summer

In consequence , the correct inequality should be:

Amount at the beginning of the summer- money withdrawn every week ≥ money at the end of the summer

Replacing with the values we know:

500-25w≥200. The correct answer is A.

PLEASE MARK ME BRAINLIEST

a) There are 1540 ways that the teacher can select the three students.

b) The probability that all three students selected are girls is approximately 0.176 or 17.6%.

c) The probability that at least one boy is selected is approximately 0.824 or 82.4%.

a)

To find the number of ways the teacher can select three students out of 22 students (7 boys and 15 girls), we can use the combination formula. The number of ways to select r items from a set of n items is given by:

nCr = n! / (r! * (n-r)!)

where n! represents the factorial of n (i.e., n! = n x (n-1) x (n-2) x ... x 3 x 2 x 1), and r! represents the factorial of r. Applying this formula, we get:

22C3 = 22! / (3! * (22-3)!) = 22! / (3! * 19!) = (22 x 21 x 20) / (3 x 2 x 1) = 1540

Therefore, there are 1540 ways that the teacher can select the three students.

b)

To find the probability that all three students selected are girls, we can use the formula for the probability of an event occurring. Since there are 15 girls and 7 boys, the probability of selecting a girl is 15/22 for the first selection, 14/21 for the second selection (since there are now 14 girls left out of 21 remaining students), and 13/20 for the third selection. Applying the formula, we get:

P(all three are girls) = (15/22) x (14/21) x (13/20) ≈ 0.176

Therefore, the probability that all three students selected are girls is approximately 0.176 or 17.6%.

c)

To find the probability that at least one boy is selected, we can use the complement rule. The complement of selecting at least one boy is selecting all three girls, which we calculated in part (b) to be approximately 0.176. Therefore, the probability of selecting at least one boy is:

P(at least one boy) = 1 - P(all three are girls) ≈ 1 - 0.176 ≈ 0.824

Therefore, the probability that at least one boy is selected is approximately 0.824 or 82.4%.

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Answer:

They are equal.

Step-by-step explanation:

In my opinion 1/3 is grater because three 1/3's makes a whole. 30% three times is only 90% of the whole.

FALSE. The number of degrees of freedom in cross-tabulation data is calculated by subtracting 1 from the product of the number of rows and columns.

Therefore, in this case, the number of degrees of freedom would be (3-1) x (4-1) = 6.

Degrees of freedom refer to the number of independent pieces of information in a data set, which can be used to calculate statistical significance and test hypotheses.

In cross-tabulation, degrees of freedom indicate the number of cells in the contingency table that are not predetermined by the row and column totals.

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The most appropriate way to report a length measured by using this yardstick is to write the measurement in decimals (0.25) rather than in fraction (¼).

Measurement is a process through which the size, dimensions, or other physical quantities of magnitude that are associated with an object is taken, especially for use in a scientific research and experiment.

In Mathematics, a yardstick refers to a graduated measuring stick that has its length equal to one yard.

In this scenario, the most appropriate way to report a length measured by using this yardstick is to write the measurement in terms of decimals (0.25), so as to make easy approximations of the distance possible.

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One of the advantages of using face-to-face paper surveys with student workers to collect data on students' attitudes toward the new fitness and recreation center is the opportunity for immediate clarification and follow-up.

Face-to-face paper surveys offer several advantages in data collection. One significant advantage is the ability to provide immediate clarification and follow-up to respondents. When students are asked survey questions in person, they have the opportunity to seek clarification if they do not fully understand a question or need further explanation. The student workers administering the survey can address any confusion, provide additional context, or rephrase questions to ensure that respondents fully grasp the intent of each question. This immediate clarification helps reduce ambiguity and ensures accurate responses.

Moreover, face-to-face interaction allows for proactive engagement with respondents. Student workers can engage in conversations, build rapport, and encourage participation, thereby potentially increasing response rates. Students may feel more comfortable providing open-ended feedback or sharing nuanced opinions when speaking directly to another person rather than responding through online or remote methods.

Additionally, the use of paper surveys provides a tangible format for respondents to record their answers using a pencil or pen. This traditional method allows for ease of completion and familiarity, especially among individuals who may not be tech-savvy or prefer handwritten responses. Paper surveys also eliminate potential technical issues or connectivity problems that could hinder data collection in online or digital formats.

Furthermore, the face-to-face interaction during survey administration allows student workers to gauge respondent reactions, body language, and non-verbal cues, which can provide valuable insights into respondents' attitudes or emotions beyond their explicit answers. These non-verbal cues can add depth and context to the collected data, offering a more comprehensive understanding of students' attitudes toward the fitness and recreation center.

In summary, one of the advantages of using face-to-face paper surveys administered by student workers for collecting data on students' attitudes toward the new fitness and recreation center is the opportunity for immediate clarification and follow-up. This mode of data collection allows for real-time explanation of questions, addresses ambiguity, encourages participation, and provides a tangible format for respondents to record their responses. It also enables student workers to observe non-verbal cues and reactions, enhancing the overall understanding of students' attitudes and opinions.

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A. The water balloon's height is increasing over the interval [0, 2].

B. The water balloon's height is staying the same over the intervals [2, 3] and [6, ∞].

C. The water balloon's height is decreasing the fastest over the interval [3, 4].

D. The height of the water balloon at 10 seconds is 0 seconds.

For any given function, y = f(x), if the output value (range) is increasing when the input value (domain) is increased, then, the function is generally referred to as an increasing function.

Part A.

Based on the graph, the height of this water balloon is increasing over the interval [0, 2] of the domain.

Part B.

Based on the graph, the height of this water balloon is constant or stays the same over these intervals [2, 3] and [6, ∞] of the domain.

Part C.

Based on the graph, the height of this water balloon is decreasing over these intervals [3, 4] and [4, 6] of the domain. However, the water balloon's height is decreasing the fastest at [3, 4];

Rate of change at [3, 4] = (20 - 80)/(4 - 3)

Rate of change at [3, 4] = -60.

Rate of change at [4, 6] = (0 - 20)/(6 - 4)

Rate of change at [4, 6] = -10.

Therefore, -60 is greater than or steeper than -10.

Part D.

At 10 seconds, the height of the water balloon is equal to 0 feet because it hit the ground at exactly 6 seconds and continued in constant motion.

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Answer:

If 10% of the school brings lunch, and it's 31 people, we know that there are a total of 310 students. 10 times 31 is 310.

To check this, 90% of 310 is 279, and 310-279=31!

Answer:

310

Step-by-step explanation:

100 / 10 = 10

31 * 10 = 310

The sample standard deviation is (B) $3.16.

Therefore, the sample standard deviation is (B) $3.16.

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The complete question is given below:
If the sample variance for a frequency distribution consisting of hourly wages was computed to be 10, what is the sample standard deviation?

A. $4.67

B. $3.16

C. $1.96

D. $10.00

The probability that Esteban wins the game is 29/49.

Probability is a concept that refers to the likelihood of a particular event occurring. It is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.

Let's consider an example: Esteban is playing a matching card game where he wins if the cards are identical. To calculate the probability of winning, we can use the following formula:

Probability of winning = Number of favorable outcomes / Total number of possible outcomes

If we assume that the deck of cards contains seven crosses and seven stars, the probability of getting a cross on both cards is:

2/7 x 2/7 = 4/49

The probability of getting a star on both cards is:

5/7 x 5/7 = 25/49

To calculate the overall probability of winning the game, we add the probabilities of getting a cross on both cards and getting a star on both cards:

4/49 + 25/49 = 29/49

Therefore, the probability that Esteban will win the game is 29/49.

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Using the t-distribution, it is found that since the test statistic is between -1.7341 and 1.7341, we do not reject(accept) the null hypothesis, hence there is not enough evidence to conclude that the true mean discharge differs from 7 ounces.

At the null hypothesis, it is tested if the mean is of 7 ounces, that is:

\(H_0: \mu = 7\)

At the alternative hypothesis, it is tested if the mean is different of 7 ounces, that is:

\(H_1: \mu \neq 7\)

The test statistic is given by:

\(t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}\)

The parameters are:

The values of the parameters are given by:

\(\overline{x} = 7.04, \mu = 7, s = 0.17, n = 18\)

Hence the value of the test statistic is found as follows:

\(t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}\)

\(t = \frac{7.04 - 7}{\frac{0.17}{\sqrt{18}}}\)

t = 1

Considering a two-tailed test, as we are testing if the mean is different of a value, with 18 - 1 = 17 df and a significance level of 0.1, the critical value is of \(t^{\ast} = 1.7341\)

Since the test statistic is between -1.7341 and 1.7341, we do not reject(accept) the null hypothesis, hence there is not enough evidence to conclude that the true mean discharge differs from 7 ounces.

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Answer:

Option B is correct

Answer:

B there is enough raspberries to make 4 pie they can 6 pies if they 2 more of raspberries

The number of people in Heckleburg after t months is P = (240)t + 3500.

The population after "m" months would be given by the expression P + Am.
Now, we want to find out the number of months it will take for the population to increase by 1,000 people.

Let's call this target population "T".

P = pt + P₀,

where P₀ is the initial population and p is the average increase in population per month.

Since the city increases the population by an average of p people per month, we can write:

p = average increase in population per month

Therefore, the expression becomes:

P = pt + P₀ = p(t) + P₀

Substituting the given values into the expression, we get:

P = (240)t + 3500
So, we need to solve the equation P + Am = T, where T = P + 1000.
Substituting T in the equation, we get P + Am = P + 1000.
Simplifying the equation, we get Am = 1000.
Now, to find the number of months "m", we can rearrange the equation as m = 1000/A.
Therefore, the expression that correctly gives the number of months it will take for the population to increase by 1,000 people is m = 1000/A.
For example, if the average increase in population per month is 50 people, it will take 20 months for the population to increase by 1,000 people (m = 1000/50 = 20).

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The number of people in Heckleburg after t months is P = (240)t + 3500.

The population after "m" months would be given by the expression P + Am.

Now, we want to find out the number of months it will take for the population to increase by 1,000 people.

Let's call this target population "T".

P = pt + P₀,

where P₀ is the initial population and p is the average increase in population per month.

Since the city increases the population by an average of p people per month, we can write:

p = average increase in population per month

Therefore, the expression becomes:

P = pt + P₀ = p(t) + P₀

Substituting the given values into the expression, we get:

P = (240)t + 3500

So, we need to solve the equation P + Am = T, where T = P + 1000.

Substituting T in the equation, we get P + Am = P + 1000.

Simplifying the equation, we get Am = 1000.

Now, to find the number of months "m", we can rearrange the equation as m = 1000/A.

Therefore, the expression that correctly gives the number of months it will take for the population to increase by 1,000 people is m = 1000/A.

For example, if the average increase in population per month is 50 people, it will take 20 months for the population to increase by 1,000 people (m = 1000/50 = 20).

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(a) The rate at which the amount of water is changing is -1/2.

(b) It will take 20 more minutes to drain the water completely.

(c) The tank was completely full 3 minutes before Kiran arrive.

Unit rate is the amount of one quantity for a unit amount of the other quantity.

(a) Given that,

When Kiran first sees the tank, it contains 12 gallons of water. Four minutes later, the tank contains 10 gallons of water.

Rate at which the amount of water is changing = (10 - 12) / 4 = -2/4 = -1/2 gallons per minute.

(b) Time taken to drain 1/2 gallon = 1 minute

There are 10 gallons of water remaining in the tank.

Time taken to drain 10 gallons of water = (1 ÷ 1/2) × 10 = 20 minutes

It will take 20 more minutes to drain the water completely.

(c) When Kiran arrived, water tank has 12 gallons of water.

Total amount of water in the tank is 15 gallons.

Tank has lost 3 gallons of water before Kiran arrived.

Time taken to drain 3 gallons = (1 ÷ 1/2) × 3 = 6 minutes

So the tank was completely full 3 minutes before Kiran arrive.

Hence the rate is -1/2 gallons per minute.

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Step-by-step explanation:

Parallel lines cut by a transversal coloring activity is an activity that helps students understand the pattern of angles when parallel lines are cut by a transversal. The activity involves coloring the angles formed by the parallel lines and the transversal in different colors. This helps students identify the different types of angles formed and their relationships with each other.

All the points in both sets satisfy the constraints, the feasible solution is α = (1, 0, 0, 0) and β = 0. This plane separates the sets S1 and S2.

To formulate the problem as a linear optimization problem (LO), we can introduce slack variables to represent the signed distances of the points from the plane αTx = β. Let's denote the slack variables as y_i for points in S1 and z_i for points in S2.

1.1 Formulation:

The problem can be formulated as follows:

Minimize: 0 (since it is a feasibility problem)

Subject to:

α1x1 + α2x2 + α3x3 + α4x4 - β ≥ 1 for (x1, x2, x3, x4) in S1

α1x1 + α2x2 + α3x3 + α4x4 - β ≤ -1 for (x1, x2, x3, x4) in S2

α1, α2, α3, α4 are unrestricted

β is unrestricted

y_i ≥ 0 for all points in S1

z_i ≥ 0 for all points in S2

The objective function is set to 0 because we are only interested in finding a feasible solution, not optimizing any objective.

1.2 Finding a feasible solution:

To find a feasible solution for this linear optimization problem, we need to check if there exists a plane αTx = β that separates the given sets of points S1 and S2.

Let's set α = (1, 0, 0, 0) and β = 0. We choose α to have a non-zero value for the first component to satisfy α ≠ (0, 0, 0, 0) as required.

For S1:

(1, 2, 1, -1) - 0 = 3 ≥ 1, feasible

(3, 1, -3, 0) - 0 = 4 ≥ 1, feasible

(2, -1, -2, 1) - 0 = 0 ≥ 1, not feasible

(7, -2, -2, -2) - 0 = 3 ≥ 1, feasible

For S2:

(1, -2, 3, 2) - 0 = 4 ≥ 1, feasible

(-2, π, 2, 0) - 0 = -2 ≤ -1, feasible

(4, 1, 2, -π) - 0 = 5 ≥ 1, feasible

(1, 1, 1, 1) - 0 = 4 ≥ 1, feasible

Since all the points in both sets satisfy the constraints, the feasible solution is α = (1, 0, 0, 0) and β = 0. This plane separates the sets S1 and S2.

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The area of the polygon is solved to be  1044 squared cm

The area of the composite polygon is solved by dividing the object into two sections. Then adding up the areas

Section 1 has dimensions:

length * width = 46 * 14 = 644

section 2 has dimensions:

length = 46 - 21 = 25

width = 30 - 14 = 16

Area = 25 * 16 = 400

Area of the composite figure

section 1  + section 2

= 644 + 400

= 1044 squared cm

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The difference between the 2 in the tens place and 2 to its left column in the given number 2,222.222 is 180.

According to the number system, a number can be written in its expanded form according to their pace value in the chart.

2,222.222 can be written as 2×1000+2×100+2×10+2X1+2×1/10+2×1/100+2×1/1000

The place value of 2 in the tens place in given number 2,222.222 = 20

The place value of 2 in its left column in the given number 2,222.22  = 200

Difference between the place of 2 in tens place and 2 in its left column

= 200 - 20

= 180

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The fraction computed shows that 9/32 of the shapes are circles.

Find the equivalent ratio for the total shapes:

Total Black Shapes : Total White Shapes = 5 : 11

Multiply by 2:

Total Black Shapes: Total White Shapes = 10 : 22

Find the ratio for the white shapes:

White circles : White squares = 3 : 7

Sum of the units = 3 + 7

Sum of the units = 10

Find the equivalent ratio for the total shapes:

Black circles : Black squares = 3 : 8

Multiply by 2:

Black circles : Black squares = 6 : 16

Sum of the units = 6 + 16

Sum of the units = 22

Combine the ratios:

white circles : white squares : black circles : black square = 3 : 7 : 6 : 16

Circles = 3 + 6

Circles = 9 units

Total = 3 + 7 + 6 + 16

Total = 32 units

Find the fraction of all the shapes that are circles:

Fraction = 9/32

Therefore, 9/32 of the shapes are circles

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the size of the union of the three sets is: |A ∪ B ∪ C| = |A| + |B| + |C| - |A ∩ B| - |A ∩ C| - |B ∩ C| + |A ∩ B ∩ C| = 3  × 24 million - 3 × 1.4 million + 1.2 million ≈ 69 million

A combination is a way of selecting a subset of objects from a larger set without regard to their order. The formula for the number of combinations of n objects taken r at a time is:
C(n, r) = n! / (r! ×  (n - r)!)
where n! means the factorial of n, which is the product of all positive integers up to n. For example, 5! = 5 ×  4 ×  3 ×  2 ×  1 = 120.
To apply this formula to our problem, we first need to count the total number of coins in the pile. Since there are at least 16 of each type, the minimum total is:
16 + 16 + 16 + 16 = 64
But there could be more coins of each type, so the total could be larger than 64. However, we don't need to know the exact number, only that it is large enough to allow us to choose 16 coins from it.
Using the formula for combinations, we can calculate the number of different collections of 16 coins that can be chosen from the pile:
C(64, 16) = 64! / (16! × (64 - 16)!) ≈ 1.1 billion
That's a very large number! It means there are over a billion ways to choose 16 coins from a pile that contains at least 16 of each type.
To answer the second part of the question, we need to count the number of collections that contain at least 3 coins of each type. One way to do this is to use the inclusion-exclusion principle, which says that the number of elements in the union of two or more sets is equal to the sum of their individual sizes minus the sizes of their intersections, plus the sizes of the intersections of all possible pairs, minus the size of the intersection of all three sets, and so on.
In this case, we can consider three sets:
- A: collections with at least 3 pennies
- B: collections with at least 3 nickels
- C: collections with at least 3 dimes
- D: collections with at least 3 quarters
The size of each set can be calculated using combinations:
|A| = C(48, 13) ≈ 24 million
|B| = C(48, 13) ≈ 24 million
|C| = C(48, 13) ≈ 24 million
|D| = C(48, 13) ≈ 24 million
Note that we have to choose 3 coins of each type first, leaving 4 coins to be chosen from the remaining 48 coins.
The size of the intersection of any two sets can be calculated similarly:
|A ∩ B| = C(43, 10) ≈ 1.4 million
|A ∩ C| = C(43, 10) ≈ 1.4 million
|A ∩ D| = C(43, 10) ≈ 1.4 million
|B ∩ C| = C(43, 10) ≈ 1.4 million
|B ∩ D| = C(43, 10) ≈ 1.4 million
|C ∩ D| = C(43, 10) ≈ 1.4 million
Note that we have to choose 3 coins of each type first, leaving 1 coin to be chosen from the remaining 43 coins.
The size of the intersection of all three sets can also be calculated:
|A ∩ B ∩ C| = C(38, 7) ≈ 1.2 million
Note that we have to choose 3 coins of each type first, leaving 1 coin to be chosen from the remaining 38 coins.

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Answer:

21 1/6

Step-by-step explanation:

1. Multiply the whole numbers first.

7 x 3 = 21.

2. Multiply the two fractions.

When multiplying fractions, you multiply the two numerators and then the denominators.

1 x 1 = 1

2 x 3 = 6

3. Your answer is 21 1/6

The required rate of return (or minimum acceptable rate of return) is 20 percent. If the net cash flows are $15,000 per year for ten years, the total cash flow is $150,000. The project's cost is $47,500. We can now apply the net present value formula to determine whether or not the project is feasible.

Net Present Value (NPV) = Cash flow / (1 + r)^n - Cost Where, r is the discount rate, n is the number of years, and Cost is the initial outlay.

Net Present Value = 150000 / (1 + 0.20)^10 - 47500

Net Present Value = $67,482.22

Since the NPV is positive, the project is feasible. When calculating net present value, it's important to remember that a positive NPV implies that the project is expected to generate a return that exceeds the cost of capital, whereas a negative NPV indicates that the project is expected to generate a return that is less than the cost of capital, and as a result, it should be avoided.

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Answer:

Infinite amount of solutions.

General Formulas and Concepts:

Step-by-step explanation:

Step 1: Define equation

6y + 4 - 3y - 7 = 3(y - 1)

Step 2: Solve for y

Here we see that there will be infinite amount of solutions. We can plug in any number y and it will render the equation true.

No solutions.

General Formulas and Concepts:

Order of Operations: BPEMDAS

Regular + Equality Properties

Step-by-step explanation:

Step 1: Define equation

6y + 4 - 3y - 7 = 3(y - 1)

Step 2: Solve for y

Combine like terms:                         3y - 3 = 3(y - 1)

Distribute 3:                                       3y - 3 = 3y - 1

Subtract 3y on both sides:               -3 ≠ -1

Here we see that there will be no solutions of y.

Answer:

If you want to simply it, the answe is 7 cm to 5 cm

Step-by-step explanation:

Find a GCF which is 7 in this case, and divide both numbers by the GCF