what volume of 6.0 m hno3 would be needed to make 500 ml of 0.50 m solution?

Explanation:

It is not possible to give one property of sodium chloride that is not a property of sodium chloride, as properties are specific characteristics that define a substance, and different properties are unique to each substance. Sodium chloride, also known as table salt, is an ionic compound composed of positively charged sodium ions (Na+) and negatively charged chloride ions (Cl-). It is a white crystalline solid with a salty taste, and it is highly soluble in water. Some of the properties of sodium chloride include: melting point 801 °C, boiling point 1413 °C, density 2.165 g/cm3, and it is a good conductor of electricity when dissolved in water.

Answer:

It is not possible

Explanation:

The volume of H₃PO₄ : 13.33 ml

Given

0.003 M  Phosphoric acid-H₃PO₄

40 ml of 0.00150 M Calcium hydroxide-Ca(OH)₂

Required

Volume of H₃PO₄

Solution

Acid-base titration formula  

Ma. Va. na = Mb. Vb. nb  

Ma, Mb = acid base concentration  

Va, Vb = acid base volume  

na, nb = acid base valence  (amount of H⁺/OH⁻)

H₃PO₄⇒3H⁺ + PO₄³⁻ ⇒ 3 H⁺ = valence = 3

Ca(OH)₂⇒Ca²⁺ + 2OH⁻⇒ 2 OH⁻ = valence = 2

Input the value :

a = H₃PO₄, b = Ca(OH)₂

0.003 x Va x 3 = 0.0015 x 40 x 2

Va = 13.33 ml

Answer:

95% of the time (or any other percentage you choose), the electron will be found within a fairly easily defined region of space quite close to the nucleus. Such a region of space is called an orbital. You can think of an orbital as being the region of space in which the electron lives

Answer: PtF6

Explanation:  is one of seventeen known binary hexafluorides.

Answer:

carboxyl group

Explanation:

Answer:

A EDGE 2022

Explanation:

The rate law that is consistent with the proposed mechanism is [-d[H₂]/dt = k[H₂][ICl].

The sum of the two processes produces the overall reaction, which is:

H₂(g) + 2ICl(g) → 2HCl(g) + I₂(g)

We must take into account the rate-determining step, which is the step with the slowest rate, in order to derive the rate law for the total reaction. It is step 1 in this instance.

H₂(g) + ICl(g) → HI(g) + HCl(g) is the rate-determining step (g)

This step's rate rule is-d[H₂]/dt = k[H₂][ICl]

[ICl]

We can assume that the concentration of HI is always in equilibrium with the concentrations of H₂ and ICl because step 2 is quick.

Therefore, -d[H₂]/dt = k[H₂][ICl] is the rate law for the entire reaction.

Therefore,  [-d[H₂]/dt = k[H₂][ICl] is the rate law that is consistent with the hypothesized mechanism.

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The molar equivalent of benzaldehyde when you use 365 micro liters of benzaldehyde and 110 micro liters of acetone is 2.39.

To find the molar equivalent of benzaldehyde, we first need to find the moles of both benzaldehyde and acetone.

1. Calculate the mass of benzaldehyde:
Mass = Volume x Density
Mass = 365 µL x 1.044 g/mL = 0.365 mL x 1.044 g/mL = 0.38076 g

2. Calculate the moles of benzaldehyde:
Moles = Mass / Molar Mass
Moles = 0.38076 g / 106.124 g/mol = 0.00359 mol

3. Calculate the mass of acetone:
Mass = Volume x Density
Mass = 110 µL x 0.791 g/mL = 0.110 mL x 0.791 g/mL = 0.08701 g

4. Calculate the moles of acetone:
Moles = Mass / Molar Mass
Moles = 0.08701 g / 58.080 g/mol = 0.00150 mol

Now, find the molar equivalent of benzaldehyde with respect to acetone:

Molar equivalent = Moles of benzaldehyde / Moles of acetone
Molar equivalent = 0.00359 mol / 0.00150 mol = 2.39

Thus, the molar equivalent of benzaldehyde is 2.39.

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Many agricultural practices involve the emission of greater amounts of methane. The two agricultural practices which result in methane emission is manure management techniques and rice cultivation. The correct options are C and D.

The methane is defined as the simplest hydrocarbon with a chemical formula CH₄. It contains four 'H' atoms and one 'C' atom and it is the simplest alkane.

The main sources of methane emissions from agriculture are enteric fermentation, manure management, rice cultivation and residue burning. The production of methane also occurs animal wastes. Methane emissions occurs from paddy rice when soils are flooded.

Thus the correct options are C and D.

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There are 6 σ bonds and 3 π bonds in H₃C-CH₂-CH═CH-CH₂-C≡CH.

In the given chemical structure, σ (sigma) bonds are formed by the overlap of atomic orbitals in a head-to-head fashion. These bonds allow for the sharing of electrons between the atoms involved. Each single bond, whether between carbon and hydrogen or carbon and carbon, is a σ bond. Therefore, we count the number of single bonds to determine the number of σ bonds.

In this molecule, there are six single bonds: three between carbon and hydrogen  and three between carbon and carbon.Hence, there are 6 σ bonds in total.

In the given structure, there are three double bonds: one between carbon atoms (═), one between carbon and carbon (ch═ch), and one between carbon and carbon (c≡ch). Each double bond consists of one σ bond and one π bond.

Therefore, there are 6 σ bonds and 3 π bonds in the given chemical structure.

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The entropy change for 2.40 moles of HI when it condenses at atmospheric pressure is -199.968 J/mol K

Entropy change is defined as the measure of change of disorder or randomness in a thermodynamic system.

Mathematically, it is given as

\(\Delta S = \frac{\Delta H}{T}\)

where ∆S = entropy change

∆H = change in enthalpy

T = temperature

For HI,

Enthalpy of vaporization of HI, \(\Delta H_{vap}\) = 19.8 kJ/mol

We also know

Enthalpy of vaporization of HI, \(\Delta H_{vap}\) = - Enthalpy of condensation of HI, \(\Delta H_{cond}\)

\(\Delta H_{cond}\) = -19.8 kJ/mol

HI condenses at -35.36°C

Temperature, T = -35.36°C + 273 = 237.64 K

Substitute in the entropy change formula,

\(\Delta S = \frac{-19.8}{237.64}\)

\(\Delta S\) = -0.08332 kJ/mol K = -83.32 J/mol K

1 mole of HI has entropy change = -83.32 J/mol K

2.4  moles of HI have entropy change = 2.4 × (-83.32) = -199.968 J/mol K

Thus, The entropy change for 2.40 moles of HI when it condenses at atmospheric pressure is -199.968 J/mol K

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Answer:

B)  kilometer.

Explanation:

Took the test

Answer:

Because ocean water contains salt, there is also sodium and chlorine in the oceans.

Explanation:

Dalton's Atomic theory was Atom is an indivisible fundamental particle but Bohrs theory contradict it,

Atoms contain smaller particles: protons, neutrons, and electrons.

Answer:

5-20 mins

Explanation:

The pka for the HA²⁻ is about 9.67. This can be calculated through bisection method as it is a conjugate base.

HA²⁻ is the conjugate base of H₃A, a triprotic acid with pKa values of 2.50, 5.75, and 9.25. It can be written as:

Step 1: Find the pH at which the species Ha²⁻ has half the proton concentration of A³⁻. For a triprotic acid with:

pKa1 < pKa2 < pKa3, the concentration of A³⁻ can be calculated using the following equation:

[A³⁻] = ( [H⁺]³) / ([H⁺]³ + K₁[H⁺]² + K₁K₂[H⁺]+ K₁K₂K₃)

Let x be the concentration of HA²⁻. Then, [A³⁻] = ( [H⁺]³ ) / ([H⁺]³ + K₁[H⁺]² + K₁K₂[H⁺] + K₁K₂K₃) = ( [H⁺]³ ) / ([H⁺]³ + [H⁺]²[0.00316] + [H⁺][0.00316 × 0.01] + [0.00316 × 0.01 × 0.0001] )

Thus, [A³⁻] = [H⁺]³/ ([H⁺]³ + 3.16 × 10⁻⁶ [H⁺]² + 3.16 × 10⁻⁸ [H⁺] + 3.16 × 10⁻¹¹)

Let [A³⁻] = [HA²⁻]/2 = x/2

Thus,  [H⁺]³ / ([H⁺]³ + 3.16 × 10⁻⁶ [H⁺]² + 3.16 × 10⁻⁸ [H⁺] + 3.16 × 10⁻¹¹) = x/2

Since, [H⁺] = 10-pH, and pH = pKa + log10([A-]/[HA]),

we can rewrite the expression as: (10-pH)³ = x/2 (3.16 × 10⁻⁶ + × 2 3.16 × 10⁻⁸ + × 3.16 × 10⁻¹¹ +1)

Rearranging, we get: ×3.16 × 10⁻⁶ + ×2 3.16 × 10⁻⁸ + × 3.16 × 10⁻¹¹ +1 - (2 (10-pH)3) = 0

We can solve this using numerical methods such as Newton-Raphson or bisection method. For simplicity, we can use an online calculator to get the answer. We get: pH = 4.33Thus, the pKa value of Ha2- is:pKa = 14 - pH = 9.67

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Molar mass of N2 is 28(since atomic weight of nitrogen is 14and forN2=14*2). So mass of 1 mole of N2 is 28g.Therefore mass of 0.5 mole is 28/2 =14g

Entropy is a thermodynamic property that describes the degree of randomness or disorder of a system.

The change in entropy (ΔS) of a reaction can be calculated by comparing the entropy of the products to that of the reactants.

A reaction with a positive ΔS value indicates an increase in entropy, whereas a negative ΔS value indicates a decrease in entropy.

From the given reactions, the reaction in which the entropy increases can be identified as follows:

a) N2(g) + 3H2(g) → 2NH3(g)

This reaction involves the formation of two molecules of NH3 from its constituent atoms. As NH3 molecules have more disorder than the individual atoms, this reaction leads to an increase in entropy.

b) C2H6(g) + C2H4(g) + H2(g) → products

This reaction involves the formation of products from three molecules of reactants. However, as the nature of the products is not specified, it is difficult to determine if the entropy increases or decreases.

c) C2H2(g) + H2(g) → C2H4(g)

This reaction involves the formation of a single molecule of C2H4 from two reactants. As the number of molecules decreases in this reaction, the entropy is expected to decrease rather than increase.

d) 2PCl5(g) + O2(g) → 2POCl3(g)

This reaction involves the formation of two molecules of POCl3 from its constituent molecules. As the products have lower entropy than the reactants, this reaction leads to a decrease in entropy.

Therefore, the reaction in which entropy increases is option (a) N2(g) + 3H2(g) → 2NH3(g).

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Answer:

284.395332

Explanation:

1 mole= 36.46094

so multiply 36.46094 times 7.8

and you get 284.395332

hope that helped ! Please mark brainliest I only need one more.

Answer:

315 kg

Explanation:

If the ore is 65% waste material, then the mass of the actual sodium in 1 tonne of ore is:

mass of sodium = 0.35 x 1000 kg = 350 kg

The process of electrolysis separates the sodium from the other components of the ore. The amount of sodium extracted will depend on the efficiency of the electrolysis process, which is typically measured by its Faraday efficiency.

The Faraday efficiency is the ratio of the amount of substance actually produced by electrolysis to the amount predicted by the theoretical stoichiometry of the reaction. For the electrolysis of sodium, the theoretical stoichiometry is:

2 Na+ + 2 e- → 2 Na

This reaction requires 2 moles of electrons (2 Faradays) to produce 2 moles of sodium.

If we assume a Faraday efficiency of 90%, this means that 90% of the theoretical amount of sodium is actually produced by electrolysis. Therefore, the mass of sodium extracted from 1 tonne of ore would be:

mass of sodium extracted = 0.9 x (2/2) x 350 kg = 315 kg

So, the company would extract 315 kg of sodium from 1 tonne of ore that is 65% waste material, assuming a Faraday efficiency of 90%.

The wavelength of an electron can be calculated using the formula: wavelength = h / (mass of electron * velocity). Since kinetic energy is equal to the mass of the electron multiplied by the velocity squared, we can also calculate wavelength by using the formula: wavelength = h / sqrt(2mass of electron kinetic energy).

To convert the kinetic energies given in electron volts (eV) to Joules (J), you can use the formula: 1 eV = 1.6 x 10^-19 J

(a) 20.0 eV = 3.2 x 10^-18 J, wavelength = h / sqrt(2mass of electron3.2 x 10^-18 J) = 2.4 x 10^-12 m or 2.4 pm (picometers)

(b) 200 eV = 3.2 x 10^-17 J, wavelength = h / sqrt(2mass of electron3.2 x 10^-17 J) = 2.4 x 10^-11 m or 24 pm

(c) 2.00 keV = 3.2 x 10^-14 J, wavelength = h / sqrt(2mass of electron3.2 x 10^-14 J) = 2.4 x 10^-8 m or 2.4 nm

(d) 20.0 keV = 3.2 x 10^-13 J, wavelength = h / sqrt(2mass of electron3.2 x 10^-13 J) = 2.4 x 10^-7 m or 24 nm

(e) 0.200 MeV = 3.2 x 10^-11 J, wavelength = h / sqrt(2mass of electron3.2 x 10^-11 J) = 2.4 x 10^-5 m or 0.24 nm

(f) 2.00 MeV = 3.2 x 10^-10 J, wavelength = h / sqrt(2mass of electron3.2 x 10^-10 J) = 2.4 x 10^-4 m or 2.4 nm

A lower energy electron will have a longer wavelength, while a higher energy electron will have a shorter wavelength. To study the crystal structure of NaCl, you would need to use a technique such as X-ray diffraction, which typically uses X-rays with energies in the range of a few keV to a few tens of keV. Based on this, 2.00 keV and 20.0 keV energies are most suited for study of the NaCl crystal structure.

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When adding ice to a hot soup, it is generally recommended to use ice made from potable or drinkable water.

The water used to make the ice should be clean and free from any contaminants that could affect the taste or safety of the soup.

It is advisable to use filtered or purify water to make the ice to ensure that it is of good quality. This helps prevent any unwanted flavors or impurities from transferring to the soup.

Using tap water can also be acceptable if it meets the drinking water standards in your area and is considered safe for consumption. However, if you have concerns about the quality of your tap water, using filtered water is a safer option.

Ultimately, the goal is to add ice made from water that is safe and of good quality to avoid any negative impact on the taste or safety of the soup.

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Making a solution of sodium chloride for an experiment , we add 250 mg of sodium chloride to 500 ml of lab water. the sodium chloride concentration of solution in unit of mg/l is 499.7 mg/l and in ppm is 499.7 mg/l.

mass of solute = 250 mg = 0.250 g

volume of solvent = 500 ml = 500 g

mass of solution  = 0.250 g + 500 g = 500.25 g

concentration of solution in ppm ( parts per million ).m

= ( mass of solute in g / mass of solution in g  ) × 1000000

= ( 0.250 g / 500.25 g) × 1000000

= 499.7 ppm

so, we know that , 1 ppm is equivalent to 1 mg /l

1 ppm = 1 mg/l

Therefore, 499.7 ppm = 499.7 mg / l.

thus,Making a solution of sodium chloride for an experiment , we add 250 mg of sodium chloride to 500 ml of lab water. the sodium chloride concentration of solution in unit of mg/l is 499.7 mg/l and in ppm is 499.7 mg/l.

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Answer:

Chromate Chemical Formula

Explanation:

The formula of chromate is CrO42-. The chromate ion usually consists of one chromium atom (+6 oxidation state) and four oxide atoms. The overall charge is -2.

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When (trans, trans)-hepta-3,5-dien-1-yne is reacted with Pd/C and H2, the product that is formed is (trans, trans)-hept-3-en-1-ol.

The reaction between the given compound and Pd/C and H2 undergoes catalytic hydrogenation or reduction. It is a type of chemical reaction in which an unsaturated bond present in a molecule is reduced by the addition of hydrogen gas (H2) with the help of a catalyst.

In this case, the given compound contains two triple bonds and no double bonds. So, it is known as diyne. When it is subjected to hydrogenation in the presence of a catalyst like Pd/C and H2, it undergoes hydrogenation and reduces its two triple bonds to double bonds. The two hydrogen atoms are added to each triple bond to form two single bonds.To write the balanced chemical equation for this reaction, we have:(trans, trans)-hepta-3,5-dien-1-yne + H2 (in presence of Pd/C) → (trans, trans)-hept-3-en-1-olHence, the final product formed when (trans, trans)-hepta-3,5-dien-1-yne is reacted with Pd/C and H2 is (trans, trans)-hept-3-en-1-ol.

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The equilibrium vapor pressure with respect to water (eow) is 259.9 Pa. assume that saturation vapor pressure is same as equilibrium vapor pressure.

Therefore, the RH at the frost point is  

RH = (eow / saturation vapor pressure) × 100

= (259.9 Pa / 259.9 Pa) × 100

= 100%

b) At T = -11 °C, we need to compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi) to determine if ice particles will form. From the given table, at T = -11 °C, the equilibrium vapor pressure with respect to water (eow) is 237.7 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 165.3 Pa.

The air is supersaturated with respect to ice, and the presence of Kaolinite particles can provide surfaces for water droplets to condense onto, leading to the formation of ice particles.

c) At T = -12 °C, we compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi). From the given table, at T = -12 °C, the equilibrium vapor pressure with respect to water (eow) is 217.3 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 181.2 Pa.

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The statement that accurately describes a type of potential energy found in a container full of a chemical substance in liquid form is the bonds between atoms are one place where potential energy is stored.

What is Energy?

On earth, energy comes in a variety of ways. The elemental source of energy on earth is said to be the sun. Energy is seen as a quantifiable characteristic in physics that may be transferred from an item to carry out work. Thus, we might characterise energy as the capacity to engage in any form of physical action. So, to put it simply, we may define energy as:

Energy is the capacity to carry out task.

The energy that is stored in chemical bonds (between two atoms) is a form of potential energy.

The vibrations of the atoms are because of the thermal energy.

The rotation of the particles shows rotational kinetic energy.

The speed of the particles represents the translational kinetic energy of these particles.

A molecule can have all the forms of energy together. The sum of these shows the total energy stored in a molecule.

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Answer:

Decomposition

Explanation:

One reactant has formed two products