what two quantities did edwin hubble plot against each other to discover the expansion of the universe?

Answers

Answer 1

Velocity and distance are the two quantities that did Edwin Hubble plot against each other to discover the expansion of the universe.

In the field of physics, the Edwin Hubble plot can be described as a graph that is used for plotting the velocity of an object against its distance.

According to Edwin Hubble, who was a famous cosmologist, the plot between velocity and distance could be used for learning about the expansion of the whole universe.

By using this plot, Edwin Hubble was able to conclude that the further a particular galaxy is from the universe, the faster it seems to be moving toward space.

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Related Questions

Calculate the efficiency of an engine if the work input is 300. J and the work output is 100. J

Answers

Answer:

33.33%

Explanation:

take efficiency =power output/power input multiply by 100%

Explain how a battery works. What are some possible materials you could use to make a battery for a circuit?

Answers

Answer:

Batteries are systems that store chemical energy and then release it as electrical energy when they are connected to a circuit. Batteries can be made from many materials, but they all share three main components: a metal anode, a metal cathode and an electrolyte between them. The electrolyte is an ionic solution that allows charge to flow through the system. When a load, such as a light bulb, is connected, an oxidation-reduction reaction occurs that releases electrons from the anode while the cathode gains electrons

Explanation:



If a baseball has a negative velocity and a negative acceleration, its speed is

O increasing

decreasing

unknown

constant

Answers

If a baseball has a negative velocity and a negative acceleration, its speed is decreasing.

Velocity is a vector quantity that includes both magnitude (speed) and direction. In this case, the negative velocity indicates that the baseball is moving in the opposite direction of a chosen positive reference direction. Acceleration, on the other hand, represents the rate of change of velocity and also includes both magnitude and direction.

When the velocity and acceleration have the same sign (both negative in this case), it means that the baseball is slowing down. This is because the acceleration is acting in the opposite direction to the velocity, which results in a decrease in speed. Therefore, the speed of the baseball is decreasing.

characteristics of saturn

Answers

Saturn is a planet in solar system. It's ring is made out of small covered ice particle. It has over 30 moons.

uhh it’s a gas giant
made up of hydrogen and helium
second biggest planet in the solar system
least dense planet in the solar system

A carousel revolves around 9.3 times in 4.3 minutes. What is the frequency of the carousel
in hertz?

Answers

Answer:

(9.4 times / 8.5 minutes) x (1 minute / 60 seconds)

= (9.4) / (8.5 x 60) times/second

= 0.013 Hz .

The following arbitrary measurements are made and the errors sited are the aximum errors A = 15.21 +0.01, B = 10.82 +0.05, C = 11.00+ 0.03. If D= A + B + C; (a) Calculate the maximum error in D. (b) if the errors sited are standard errors, calculate the standard error in D.​

Answers

Maximum error in the result of the sum of measurement is equal to the sum absolute error of the individual observed measurements

(a) The maximum error in D is 0.09

(b) The standard error in D is approximately 0.034

The procedure for arriving at the above values is as follows;

The given measurements and the sited errors are;

A = 15.21 + 0.01

B = 10.82 + 0.05

C = 11.00 + 0.03

D = A + B + C

(a) Required parameter;

To calculate the maximum error in D

The equation for the propagation of error in addition is presented as follows;

Given that we have;

x = a + b

Therefore;

x + ±Δx = (a ± Δa) + (b ± Δb) = a + b ± (Δa + Δb)

Δx = Δa + Δb

From the above formula, we have;

Where;

D = A + B + C

The maximum error in D = The sum of the maximum error in A, B, C

∴ The maximum error in D = 0.01 + 0.05 + 0.03 = 0.09

(b) Required parameter:

To find the standard error in D

The standard error is the sampling distribution's standard deviation, SD

Variance = SD²

The combined variance, SD² = The sum of the squares of individual standard deviations

Given that the standard errors represents the standard deviation, we get;

The combined variance, SD² = 0.01² + 0.05² + 0.03²

The combined variance, SD = √(0.01² + 0.05² + 0.03²) = 0.059

\(Standard \ error = \dfrac{SD}{\sqrt{n} }\)

Where n = 3, for the three measurement, we get;

\(Standard \ error = \dfrac{\sqrt{0.01^2 + 0.05^2 + 0.03^2} }{\sqrt{3} } \approx 0.034\)

The standard error in D is approximately 0.034

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a 0.11-kg tin can is resting on top of a 1.7-m high fence post. a 0.0020-kg bullet is fired horizontally at the can. it strikes the can with a speed of 900.0 m/s, passes through it, and emerges with a speed of 720 m/s. when the can hits the ground, how far is it from the fencepost? disregard friction while the can is in contact with the post.

Answers

It is 1.93 metres away from the post.

for vertical motion

\(S= u t + \frac{1}{2} g t^{2}\)

S = 0 +  \(\frac{1}{2} g t^{2}\)

1.7 = \(\frac{1}{2} 9.8 t^{2}\)

t = 0.589 sec

using law of  conservation of momentum, on the horizontal motion

\(m_{bullet} \ v_{bullet i} = m_{bullet} \ v_{bullet f} + m_{tin} \ v_{tin}\)

\(0.0020 = 0.0020 \ 3 \ 720 + 0.11 \ v_{tin}\)

\(v_{tin}\) = 3.273 m/s

S = \(v_{tin} \ t\)

   = 3.273 m/s * 0.589 s

   = 1.93 m

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According to the metric system, 1 ________ = 1,000,000 g.

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According to the metric system, 1 metric ton (also known as a tonne) = 1,000,000 grams.  In the United States and some other countries, a ton is often used to refer to a unit of weight.

The metric system is a system of measurement used in most of the world that is based on the International System of Units (SI). The SI unit for mass is the kilogram (kg), which is defined as the mass of a specific cylinder of platinum-iridium alloy kept at the International Bureau of Weights and Measures in France.

The metric ton, also known as the tonne, is a unit of bin the metric system that is equal to 1,000 kilograms. This unit is commonly used to measure large masses of objects such as vehicles, cargo, and building materials.

Since 1 kilogram is equal to 1,000 grams, 1 metric ton is equal to 1,000 x 1,000 = 1,000,000 grams. This means that if you have a mass of 1,000,000 grams, you have a mass of 1 metric ton. Similarly, if you have a mass of 2,000,000 grams, you have a mass of 2 metric tons, and so on.

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Due to a jaw injury, a patient must wear a strap that produces a net upward force of 5.00 N on his chin. The tension is the same throughout the strap. To what tension must the strap be adjusted to provide the necessary upward force?

Answers

The strap's tension needs to be changed to 4.11 N in order to deliver the required upward force, since there are no other forces acting in the upward direction.

To generate the required upward force, the tension on the strap must be adjusted, which equals T.

R²  = T²  + T²  - 2T² Cosθ

where;

The resulting force, R, is

5² = 2T²  - 2T² cos (75), where is the angle of inclination of the tension

25 = 1.482T²

T² = 25/1.482

T² = 16.87

T = √16.87

T = 4.11 N

In order to deliver the required upward force, the strap's tension must be set to 4.11 N.

This is due to Newton's third law, which states that for every action, there is an equal and opposite reaction. In this case, the force that the strap exerts on the chin (the action) must be equal and opposite to the force that the chin exerts on the strap (the reaction).

Therefore, to provide the necessary upward force of 5.00 N, the tension in the strap must be 4.11 N.

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The speed of sound in a particular gas is 675 m/s. A sound wave propagating in this material has a wavelength offifteen meters. What is the frequency of this sound?knowns and unknownsolveright answer

Answers

Given, Speed of the sound, v=675 m/s

The wavelength of the wave, λ=15 m

Relation between speed, wavelength, and frequency of a wave is given by

\(v=f\lambda\)

Where f is the frequency of the sound.

On substituting the known values,

\(675=f\times15\)

Which gives us,

\(f=\frac{675}{15}=45\text{ Hz}\)

Therefore the frequency of the sound in the given medium is 45 Hz.

Calculate the average times it took the car to travel 0.25 and 0.50 meters. Record the averages, to two decimal tables, in table C of you student group

Answers

According to the three trial durations, the average times to for car to traverse 0.25 metres and 0.50 kilometers are as tries to follow:

0.25 miles divided by 2.23 seconds

0.50 metres divided by three seconds

Average total distance in 0.25 metres:

Challenges 1 though 3 are compounded by three.

(2.24 + 2.21 + 2.23) ÷ 3

3.x equals 6.68 outcomes in 2.226667/2.23 minutes ( rounded to 2 decimal places).

Average distance covered in 0.50 miles:

(Trials 1 minute + Trials 2 duration + Court hearing 3 minute) / 3

(3.16 + 3.08 + 3.15) ÷ 3

9.39 x 3 = 3.13 seconds

As a consequence, it takes 2.23 and 3.13 seconds, respectively, to reach 0.25 and 0.50 kilometers.

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Complete Question:

Calculate the average time it took the car to travel 0.25 and 0.50 meters with three washers attached to the pulley. Record the averages, rounded to two decimal places, in Table C of your Student Guide. What is the average time it took the car to travel 0.25 meters? seconds What is the average time it took the car to travel 0.50 meters? seconds

when the term 'light and variable' is used in reference to a winds aloft forecast, the coded group and windspeed is

Answers

When the term 'light and variable' is used in reference to a winds aloft forecast, the coded group is typically represented by '00000' and the windspeed is indicated as less than 3 knots.

In meteorological forecasts, winds aloft are often expressed using coded groups called METAR or TAF codes. The coded group '00000' indicates that the wind direction is indeterminable or has no significant direction, and the wind speed is very low or negligible.When 'light and variable' is mentioned in a winds aloft forecast, it means that the wind direction is not well-defined or consistent, and the wind speed is below 3 knots, which is considered very light. This forecast suggests minimal or no significant wind movement at the indicated altitude.

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Which substances form due to a chemical reaction?
F Mass
G Products
H Atoms
Reactants

Answers

I believe it’s the last one

The substance that forms due to a chemical reaction is product. The correct option is G.

What is a chemical reaction?

A chemical reaction is a process that converts one or more substances, known as reactants, into one or more various substances, known as products.

Chemical elements or substances are examples of substances. A chemical reaction reconfigures the constituent atoms of the reactants to produce various products.

Living things (cells, animals, humans, and insects) use chemical reactions to grow, develop, reproduce, and adapt.

When chemical bonds between molecules are formed or broken, chemical reactions occur.

The substances that initiate a chemical reaction are known as reactants, and the substances that result from the reaction are known as products.

Thus, the correct option is G.

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Find the direction of the sum of
these two vectors:
3.14 m,
30.0°
60.0°
2.71 m

Find the direction of the sum ofthese two vectors:3.14 m,30.060.02.71 m

Answers

The magnitude of the resultant vector is 4.14m and the direction is 50°.

What is the magnitude of the forces?

The resultant magnitude of the vector is the sum of the algebraic forces acting at the point.

The magnitude of the resultant vector, F is calculated below:

\(F = \sqrt{3.14^{2} + 2.71^{2}} = 4.14m\)

The direction is given below as follows:

\(x = tan^{-1} × \frac{3.14}{2.71} = 50\)

Therefore, the magnitude of the resultant vector is 4.14m and the direction is 50°.

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mple lever. A lift is used to carry boxes to the top floor of a hotel 20 m high. A total weight of 100 kg of boxes was carried up in 20 seconds. If the useful output of the engine driving the lift mechanism is 1.2 kilowatt, calculate the efficiency of the engine of the lift mechanism. (a) (i) What is meant by a​

Answers

The efficiency of the system of the levers is  122%.

What is the efficiency?

We have to note that the efficiency is the ratio of the work out put to the work out put multiplied by 100. In this case, we are told that a lift is used to carry boxes to the top floor of a hotel 20 m high. A total weight of 100 kg of boxes was carried up in 20 seconds. and that  the useful output of the engine driving the lift mechanism is 1.2 kilowatt.

Work input = 100 Kg * 9.8 m/s^2* 20 m = 19600 J

Work output = 1.2 kilowatt * 10^3 * 20 = 24000 J

Then we have;

Efficiency = Work out put/ Work input * 100

= 24000/19600 * 100

= 122%

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Snails crawl very slowly. If a garden snail crawls at 0.013 m/s north, how far will it travel in 60 seconds?

Answers

Answer:

.78 m/s north

Explanation:

Pls give brainliest if I correct

I NEEEED HELPPPP PLEASDEEE

I NEEEED HELPPPP PLEASDEEE

Answers

Answer:

2100 m

2804 g

4 '2 mm squares'

20,000 photos

Explanation:

1.5 km = 1500 m

1500 m + 600 m = 2100 m

2.8 kg = 2800 g

2800 g + 4 g = 2804 g

8mm tube / 2 mm squares

4 can fit

1 Gb = 1000 mb

40 Gb = 40,000 mb

40,000 mb / 2 mb = 20,000 photos

Here's all the help you need:

1).  1 km  =  1,000- m

2).  1 kg  =  1,000 g

3).  Freebie.  2 fits into 8 four times.

4).  1 mega...  =  1,000 kilo...

5).  1 Giga...  =  1,000 Mega...

If an object of 3.5 cm heitght is kept at a distance of 12 cm from the convex lens of focal length 8 cm. Find the position,nature and height of the height

Answers

Answer: The image is at a distance of 24 cm on the right of the lens, it will be an inverted, real image and has a height of 7 cm.

Explanation: To determine the position of the image of the object, use the Lens Equation, which is described by:

\(\frac{1}{f} = \frac{1}{u} +\frac{1}{v}\)

where

f is focal length;

u is distance of the object from the lens;

v is distance of the image of the pbject from the lens;

Calculating the position of the image will be:

\(\frac{1}{v} =\frac{1}{f} - \frac{1}{u}\)

\(\frac{1}{v} = \frac{1}{8} - \frac{1}{12}\)

\(\frac{1}{v} = \frac{1}{24}\)

v = 24 cm

Note that the distance of the image from the lens is positive. This means that the formed image is positioned at the right of the lens and is inverted.

For the height of the image, it can be used the Magnification (M) of an image:

M = \(\frac{h_{i}}{h_{o}} = \frac{v}{u}\)

where:

\(h_{i}\) is the height of the image

\(h_{o}\) is the height of the object

For this image:

\(\frac{h_{i}}{3.5} = \frac{24}{12}\)

\(h_{i} =\) 2 * 3.5

\(h_{i}\) = 7 cm

The image formed for this lens is 24 cm on the right of the lens, inverted related to the object and has height of 7 cm.

It is diffult to measure the volume of gas.Why?​

Answers

Answer:

The volume of a gas is dependent on pressure and temperature.

Explanation:

Pressure and temperature affect different gases differently giving varied conclusions to the exact volume of that gas.

:-befrank

Because it depends on the temperature and pressure of the gas too

Add the following masses and express the sum decimally in grams: 0.75 cg, 19 mg, 0.35 dg, 0.005335 kg, 0.127 g.

Answers

The sum of the given masses expressed decimally in grams is 5.524 g.

To add the following masses and express the sum decimally in grams: 0.75 cg, 19 mg, 0.35 dg, 0.005335 kg, 0.127 g, we need to convert the units to the same base units.

The common base unit is gram (g). Therefore,

1 centigram = 0.01 g1 decigram = 0.1 g1 milligram = 0.001 g1 kilogram = 1000 g

Therefore, 0.75 cg = 0.75 × 0.01 g = 0.0075 g

                 19 mg = 19 × 0.001 g = 0.019 g

                 0.35 dg = 0.35 × 0.1 g = 0.035 g

                 0.005335 kg = 0.005335 × 1000 g = 5.335 g

                 0.127 g = 0.127 g

Adding these masses together, we get:0.0075 g + 0.019 g + 0.035 g + 5.335 g + 0.127 g = 5.524 g. Therefore, the sum of the given masses expressed decimally in grams is 5.524 g.

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A 10-kg box Initially at rest and moves along a frictionless horizontal surface. A Horizontal force to the right as applied to the box. The magnitude of the box change of the function of time as shown

b. What is the velocity of the box at 10 seconds? Show your work.
c. If you want to apply at constant force starting at 10 seconds, that would stop the box at exactly 20 seconds. What would the magnitude and direction of that force be? Show your work

A 10-kg box Initially at rest and moves along a frictionless horizontal surface. A Horizontal force to

Answers

Answer:

b. 1.1 m/s c. -1.1 m/s

Explanation:

b.

m x v=f x t

The mass is 10 kg

10 x v (equation for momentum) = f x t (impulse)

you would find the impulse by finding the area under the graph, and then dividing by the mass

So in this case:

10 x v = 11

then divide by the mass

v = 11/10

v= 1.1 m/s

c.

F x t = impulse

we are trying to find force (magnitude)

impulse/t = F

we said that in order for it to stop the impulse for b would be 11, so if thats the case it would be 11 but it would be negative because when going in a positive direction and suddenly stopping the direction changes.

-11/t = F

to find t all we need to do is find the amount of seconds between 10 and 20, that would be 10.

-11/10 = F

F= -1.1 m/s

Answer B:

The velocity of the box at 10 seconds is :

Formula :

              m x v=f x t

Given Information :

Mass(m)=10kg

10 x v (equation for momentum) = f x t (impulse)10 x v = 11v = 11/10v= 1.1 m/s

Therefore, the velocity of the box at 10 seconds is 1.1m/s.

Answer C:

The magnitude and direction of that force be :

Formula:

F x t = impulse

impulse/t = F-11/t = F

To find t all we need to do is find the amount of seconds between 10 and 20, that would be 10.

-11/10 = FF= -1.1 m/s

The magnitude and direction of that force will be -1.1m/s.

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the manufacturer of a 12 v car headlight specifies it will draw a current of 6 a. you would like to check this claim with an ammeter designed to measure currents up to 10 a and having a resistance of 0.1 ohms. a. which of the two circuits in the attached figure represents a circuit where the ammeter correctly measures the current in the headlight? b) How much current (in A) would flow in the ammeter forCircuit a? c) How much current (in A) flows through the ammeter for Circuitb?

Answers

a) Circuit b represents a circuit where the ammeter correctly measures the current in the headlight.

b) The current flowing in the ammeter for Circuit a would be 6.67 A.

c) The current flowing in the ammeter for Circuit b would be 6 A.

To ensure that the ammeter correctly measures the current in the headlight, it should be placed in series with the headlight, as shown in Circuit b.

To calculate the current flowing through the ammeter in Circuit a, we can use Ohm's Law, which states that I = V/R, where I is the current, V is the voltage, and R is the resistance. In this case, the voltage across the headlight and the ammeter is 12 V, and the resistance of the ammeter is 0.1 ohms. Therefore, the current flowing through the ammeter would be I = V/R = 12/1.8 = 6.67 A.

To calculate the current flowing through the ammeter in Circuit b, we can use the same formula. Since the ammeter and the headlight are in series, they have the same current flowing through them. Therefore, the current flowing through the ammeter would be 6 A, which is the same as the current specified by the manufacturer.

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5- A 2500g object is pushed with 55N for 12m in 11s, there was a force of friction of 30N.
a) Calculate the work done.
b) Calculate the acceleration
c) Calculate the average speed

Answers

Answer:

1kg =1000g

2.5kg

D=12m

t=11s

F=2.5KG

Explanation:

work done =f.d

=2.5×12

=30Nm

55-30

average speed

final - initial

divide by time t(s)

What does ADA apply to?

Answers

It applies to employment agencies and to labor organizations.

An engineer is designing a runway for an airport. Several planes will use the runway and the
engineer must design it so that it is long enough for the largest planes to become airborne before the
runway ends. If the largest plane accelerates at 3.30 m/st and has a takeoff speed of 88.0 m/s, then
what is the minimum allowed length for the runway?

Answers

The minimum allowed length for the runway is  1170m.

a=3.30m/s2 is the acceleration of the plane

v=88.0 m/s is the final velocity of the plane

u=0m /s is the initial velocity of the plane

The acceleration of the object is the slope of the v-t graph, therefore,

Slope=Change in y component / Change in the x component

a = u- v / T f - T i

T f - T i =  v/a

T f - T i = 88/3.3

T f - T i = 26.67 s

The displacement,

d=1/2 b h

d=1/2(T f - T i ) * v

d = 1/2 * 26.67 s * 88.0 m / s

d = 1173.33

   = 1170m nearest three significant figures

Hence, the minimum allowed length for the runway is 1170m answers.

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On a pool of water (n = 1.5) there is a thin layer of oil (n =
1.2). Where does a phase difference occur?
a) only at the first transition
b) only at the second transition
c) at both transitions
d) no

Answers

The phase difference occurs at both transitions.

When light passes from one medium to another with a different refractive index, it undergoes a change in speed and direction, resulting in the phenomenon known as refraction. In this case, light travels from water (n = 1.5) to oil (n = 1.2), and then from oil to air (or vice versa).

At the first transition, when light passes from water to oil, there will be a phase difference. This is because the speed of light changes as it enters the oil, causing the wavefronts to bend and the phase of the wave to shift.

At the second transition, when light passes from oil to air, there will also be a phase difference. Again, the change in speed and direction of light as it enters the air causes the wavefronts to bend and the phase of the wave to shift.

Therefore, the correct answer is c) at both transitions

A phase difference occur: A phase difference occurs at both transitions. The correct option is c.

When light travels from one medium to another with a different refractive index, a phase difference occurs. In this case, the light travels from the pool of water (n = 1.5) to the layer of oil (n = 1.2), and then from the oil back to the water. At each transition, there is a change in the refractive index, causing the light waves to undergo a phase shift.

The phase shift is determined by the difference in the optical path length traveled by the light in the two media. Since the refractive index of oil is lower than that of water, the light waves experience a shorter optical path length in the oil compared to the water. This leads to a phase difference when the light waves pass through the interface between the water and oil, as well as when they pass back from the oil to the water.

Therefore, at both transitions, there will be a phase difference between the light waves due to the difference in refractive indices. The correct option is c.

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Complete question:

On a pool of water (n = 1.5) there is a thin layer of oil (n = 1.2). Where does a phase difference occur?

a) only at the first transition

b) only at the second transition

c) at both transitions

d) no phase difference

good morning! someone please answer this, ill give you brainliest and your earning 50 points.

good morning! someone please answer this, ill give you brainliest and your earning 50 points.

Answers

One step of copper mining requires blasting ore to be able to blasted and extracted from mine.

This process causes harm to the Geosphere (Lithosphere)In this step, they blast the mines inside the earth. Which causes destruction and harm to the geosphere. We know that, land comes under Geosphere also known as Lithosphere.

Mercury is used to recover minute pieces of gold that is mixed in soil and sediment. Sometimes Mercury can be lost in this process resulting in widespread contamination of local rivers and lakes.

This causes harm to the Hydrosphere.The portion of earth covered with water is known as hydrosphere.Since, The Mercury is getting mixed with the water. It is polluting the water that is the hydrosphere.

Hundreds of tons of rock are unearthed, moved and crushed in mining operation significantly increasing the amount of dust and particulates in the air.

This causes harm to the Atmosphere.The particles of dust get increased in air and eventually gets mixed and spread everywhere.The air is getting polluted which means the atmosphere is getting harmed.

Strip mining (also known as mountaintop removal) involves scraping away earth and rocks to get to coal buried near the surface. This often results in the destruction of ecosystems.

This causes harm to the Biosphere.The biosphere consists of plants and animals. And these plants and animals collectively form a habitat called ecosystem.When a ecosystem is destroyed, the biosphere is harmed.

one step of copper mining requires blasting ore to be able to blasted and extracted from the mine

Geosphere ( Lithosphere)

⇢During this process,the destruction caused will affect the soil and the ground ( Lithosphere)

Mercury is used to recover minute pieces of gold that is mixed in soil and sediment. Sometimes mercury can be lost in this process resulting in widespread contamination of local river and lakes

Hydrosphere

⇢ The widespread contamination of local river and lakes will pollute the water bodies ( hydrosphere)

Hundreds of tons of rock are unearthed, moved, and crushed in mining operations significantly increasing the amount of dust and particulates in the air.

Atmosphere

⇢The particles which will get mixed in the air,will make it poisonous to breath, resulting in a polluted atmosphere

Strip mining (also known as mountaintop removal) involves scraping away earth and rocks to get to coal buried near the surface. This often results in the destruction of ecosystems

Biosphere

⇢This process has potential to destroy the ecosystem which comes under the biosphere

An object of mass “15kg” is in free fall in a vacuum where there is no resistance determine the acceleration of the object

Answers

An object of mass “15kg” is in free fall in a vacuum where there is no resistance determine the acceleration of the object -9.8 m/s^2

An object of mass “15kg” is in free fall in a vacuum where there is no resistance

During a free fall motion an object acquires acceleration

a = g  ( gravity)

a = 9.8 m/s^2

whilst an item dropped in air that experiences no air resistance is stated to be in free fall motionwhen an item is in unfastened fall, the simplest force appearing on the object is gravity.A loose fall with equal acceleration, internet force acting on them is weight, their weight-to-mass ratios are constantly the identical, their acceleration is g, and  the acceleration because of gravity.

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A body of mass 5kg is connected by a light inelastic string which is passed over a fixed frictionless pulley to a moveable frictionless pulley of mass 1kg over which is wrapped another light inelastic string which connects masses 3kg and 2kg. Find 1) the acceleration of the masses.
2) the tensions in the strings in terms of g, the acceleration dey to gravity​

Answers

(a) The acceleration of the masses is determined as 1.1 m/s² in the direction of the 5 kg mass.

(b) The tension in the string in terms of gravity is T = g.

What is the acceleration of the masses?

(a) The acceleration of the masses is calculated by applying Newton's second law of motion.

F(net) = ma

where;

m is the massesa is the acceleration of the masses

(5 kg x 9.8 m/s² ) - (1 kg + 3 kg )9.8 m/s² = ma

9.8 N = (5kg + 1 kg + 3 kg )a

9.8 = 9a

a = 9.8 / 9

a = 1.1 m/s² in the direction of the 5 kg mass.

(b) The tension in the string in terms of gravity is calculated as follows;

T = ( 5kg)g - (1 kg + 3 kg ) g

T = 5g - 4g

T = g

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The picture below was taken in the Maldives.



Which process most likely led the beach to form?

A.
Sediment being deposited as an ocean breeze slows down along the coast

B.
Palm trees breaking apart large pieces of granite and limestone

C.
Coral reefs in the ocean breaking down and being deposited ashore

D.
Rock on the beach being weathered by the water and falling apart

The picture below was taken in the Maldives.Which process most likely led the beach to form?A.Sediment

Answers

Answer:

it is c

Explanation:

a.p.e.x

i took the test

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