what transition metal has 5 more protons than the halogen found in period 3?​

When the mass of the object is decreased by a factor of 2.2, the acceleration is increased by a factor of 2.2, new acceleration would be of 30.8 m/s/s.

The effect of reducing the mass of an object by a factor of 2.2 on its acceleration is determined by Newton's Second Law of Motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

In terms of calculations, the new acceleration can be calculated by multiplying the initial acceleration by the factor by which the mass is decreased. Therefore, the new acceleration of the object with a reduced mass of 2.2 times its original mass would be 2.2 times its initial acceleration of 14 m/s/s. This would result in a new acceleration of 30.8 m/s/s (14 x 2.2 = 30.8).

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After time t, the position function of the ball is determined as \(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

The given parameters;

The position function of the ball after time t, is calculated as follows;

\(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

The negative sign of acceleration of due to gravity is because the ball is moving upward against gravity.

Thus, after time t, the position function of the ball is determined as \(y(t) = h_0\ +\ v_0t \ - \ \frac{1}{2} gt^2\)

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A,

The highest point occurs when the vertical velocity is equal to zero.

Then, to find the time needed, we can use the formula below:

Where V is the final velocity after t seconds, V0 is the initial velocity and a is the acceleration.

So, using V = 0, V0 = 40 m/s and a = -10 m/s² (gravity acceleration), we have:

B.

To calculate the horizontal distance traveled in the 4 seconds to reach the maximum height, we can use the formula below:

Where d is the distance, v is the horizontal velocity and t is the time.

So, using v = 40 m/s and t = 4 s, we have:

Also, to find the total horizontal distance traveled until the football reaches the ground again, we can use the time of flight as double the time to reach the maximum height:

Answer:

  a) 14.1°

  b) over

Explanation:

The usual model of ballistic motion assumes that the only force on the flying object is that due to gravity. When an object is launched with initial velocity v0 at some angle θ with respect to the horizontal, the distance it travels is ...

  d = (v0)²sin(2θ)/g

Using this relation, we can find the launch angle to make the object travel a given distance:

  θ = 1/2arcsin(dg/v0²) . . . . where g is the acceleration due to gravity

__

For the arrow to hit a target 85 m away at the same height it was launched with speed 42.0 m/s, the launch angle must be ...

  θ = 1/2arcsin(dg/v0²) = 1/2(arcsin(85·9.8/42²)) ≈ 14.0893°

The arrow must be released at an angle of about 14.1°.

__

The flight time to the tree at a distance of 42.5 m will be that distance divided by the horizontal speed:

  t = 42.5/(42cos(14.0893°)) ≈ 1.0433 . . . . seconds

The height at that time is ...

  h(t) = -4.9t² +42sin(14.0893°)t ≈ 5.33 . . . meters

The arrow will go over the branch.

_____

Additional comment

Since gravity provides the only force on the arrow, its horizontal speed is constant at vh = v0·cos(θ), when the arrow is launched with speed v0 at angle θ above the horizontal. Its vertical speed will be reduced by the acceleration of gravity, so will be vv = v0·sin(θ) -gt. The height is the integral of the vertical speed, so is ...

  h(t) = (1/2)gt² +v0·sin(θ)t

The height will be 0 at t=0 and at t=2v0sin(θ)/g, so the horizontal distance traveled will be ...

  d = vh·t

  = (v0·cos(θ))(2v0·sin(θ)/g) = (v0²/g)(2·sin(θ)cos(θ))

  = v0²sin(2θ)/g

Note that this is all simplified by the fact that the target and launch point are at the same level (h=0).

At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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As the horse trots a fencepost that is 36m away from you in 11.0 second, the average velocity of the horse is 3.27 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

A horse trots past you and then a fencepost that is 36m away from you.

Time taken to  make this trot = 11.0 second.

Hence,  the average velocity of the horse is = total distance travelled/time interval

= 36/11.0 m/s

= 3.27 m/s.

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19.3 gcm3 19.3 g c m 3 is equivalent to 19300 kgm3 due to the decimal place shifting due to the conversion being in metric measurements.

The amount of objects, including people, animals, plants, and other living things, that are present in a region is known as the density. The number of objects is divided by the area to determine density. The number of inhabitants in a nation divided by its size, measured in square kilometers or miles, is the population density of that nation.

In reference to the amount of matter contained in a thing, density refers to how much volume the object or substance occupies.

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Answer:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This tendency to resist changes in a state of motion is inertia.

Explanation:

We have the next information

Where

we substitute the values

The speed of the wave is 0.95m/s

The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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In a tractor pull, a tractor put 250,000 J of work into pulling a large mass. The tractor pulls the mass using 98,000N of force. The tractor pulled the mass to a distance of 2.55 meters

We may use the work done formula to solve this problem:

Work = Force  x Distance x Cosine (angle between force and displacement)

Yet, because the force and displacement are applied in the same direction, the angle between them is zero, and the cosine of zero is one. As a result, we may reduce the formula to:

Work = Force x Distance

Because we know the work done is 250,000 J and the force exerted is 98,000 N, we can rewrite the formula to solve for distance:

Distance = Work / Force

Distance = 250,000 J / 98,000 N

Distance = 2.55 meters

As a result, The tractor pulled the mass to a distance of 2.55 meters

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Answer:

If the wavelength is 2.5 meters, each node will be half a wavelength apart from each other. Therefore, each node will be 1.25 meters apart.

Explanation:

The distance between nodes of a standing wave is equal to half the wavelength of the wave. This is because nodes are points along the wave where there is zero amplitude or displacement, and they occur at fixed intervals that are determined by the wavelength of the wave. Therefore, the distance between nodes is directly proportional to the wavelength of the wave.

Answer:

226 Per/ deg c

Explanation:

We know that

\(Rt = R1 *(1 + T1 * DT)\)

Here

R1 =  Resistance at the room temperature = 95 ohms

Rt= Resistance of the final temperature = 115 ohms

T1 = Temperature coefficient  

Putting these value in the previous equation we get

\(115 = 95 *(1 + T1 * (71-23))\)

\(115=95*(1+48T1)\)

\(115=95 +4560T1\)

\(20=4520T1\)

\(T1=\frac{4520}{20}\)

T1=226 per Deg C

The kinetic energy of an object with mass 5kg and a constant velocity of 15m/s is 562.5J.

Kinetic energy is the energy possessed by an object because of its motion, equal (nonrelativistically) to one half the mass of the body times the square of its speed.

The kinetic energy of an object can be calculated using the following formula:

K.E = ½ mv²

Kinetic energy = ½ × 5 × 15²

Kinetic energy = 562.5J

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Answer:

First, let's calculate the potential energy stored in the spring:

PE = (1/2)kx²

where k is the spring constant and x is the distance the spring is compressed. Plugging in the given values, we get:

PE = (1/2)(600.0 N/m)(7.5 m)² = 16875 J

This potential energy is converted into kinetic energy as the roller coaster moves along the track. At the horizontal section, all of the potential energy has been converted into kinetic energy:

KE = (1/2)mv²

where m is the mass of the roller coaster and v is its velocity. Plugging in the given values, we get:

16875 J = (1/2)(205.0 kg)(6.0 m/s)²

Simplifying and solving for the vertical displacement, we get:

Δy = (KE/mg) - 7.5 m

where g is the acceleration due to gravity. Plugging in the values, we get:

Δy = [(1/2)(205.0 kg)(6.0 m/s)²/(205.0 kg)(9.81 m/s²)] - 7.5 m

Δy = 8.47 m

Therefore, the roller coaster is 8.47 meters above the starting level at the second (flat) level.

Explanation:

Two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then  the magnitude of the resultant force is 15 N and the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

The acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

The magnitude of the acceleration of the object is 3  \(m/s^{2}\).

To find the magnitude and direction of the resultant force, we need to add the two given forces together.

Given:

f1 = (8i + 3j) N

f2 = (4i + 6j) N

To find the resultant force (\(F_res\)), we simply add the corresponding components:

\(F_res\) = f1 + f2

= (8i + 3j) + (4i + 6j)

= (8 + 4)i + (3 + 6)j

= 12i + 9j

The magnitude of the resultant force (\(|F_res|\)) can be found using the Pythagorean theorem:

\(|F_res|\)= \(\sqrt{(12^2) + (9^2)}\)

= \(\sqrt{144 + 81}\)

= \(\sqrt{225}\)

= 15 N

So, the magnitude of the resultant force is 15 N.

To find the direction of the resultant force, we can use trigonometry. The direction can be represented by the angle θ between the positive x-axis and the resultant force vector. We can calculate θ using the inverse tangent function:

θ = arctan(9/12)

= arctan(3/4)

≈ 36.87 degrees

Therefore, the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

Now let's calculate the acceleration of the object in the x and y components. We know that force (F) is related to acceleration (a) through Newton's second law:

F = ma

For the x-component:

\(F_x\)= 12 N

m = 5 kg

Using  \(F_x\)= \(ma_x\), we can solve for \(a_x\):

12 N = 5 kg * \(a_x\)

\(a_x\)= 12 N / 5 kg

\(a_x\) = 2.4 \(m/s^{2}\)

For the y-component:

\(F_y\) = 9 N

m = 5 kg

Using \(F_y\) = \(ma_y\), we can solve for \(a_y\):

9 N = 5 kg * \(a_y\)

\(a_y\) = 9 N / 5 kg

\(a_y\)= 1.8  \(m/s^{2}\)

So, the acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

To find the magnitude of the acceleration (|a|), we can use the Pythagorean theorem:

|a| = \(\sqrt{(a_x^2) + (a_y^2)}\)

= \(\sqrt{(2.4^2) + (1.8^2}\)

= \(\sqrt{5.76 + 3.24}\)

= \(\sqrt{9}\)

= 3  \(m/s^{2}\)

Therefore, the magnitude of the acceleration of the object is 3  \(m/s^{2}\)

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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Answer:

F_suv= 49050 N

Explanation:

We are told that a 2000 kg car moving down the road runs into a 5000 kg stationary suv. The car applies a force of 1400 N on the suv.

Now, according Newton's first law of motion, an object will continue in it's present state of rest except it is acted upon by an external body.

This means the force acting on the stationary Suv is force of gravity.

Thus; F_suv = 5000 × 9.81

F_suv= 49050 N

Explanation:

There are 1024/2 = 512 SHEETS   (each is numbered on two sides)

  3 inches * 25.4 mm/inch / 512 sheet = .1488 mm per sheet

The initial velocity of the car is u = 0 m/s because the car starts from rest.

The acceleration of the car is a = \(2m/s^{2}\).

The instantaneous velocity is v = 16 m/s.

By applying the formula that connects the details that we have with the duration

a = v − u t

      t

we get the duration as follows

Make t the subject of the formula

    t = v − u

            a

=  16m/s− 0 m/s

      \(2M^{2}\)

= 8s.

The duration for that speed change is 8s.

Calculating acceleration involves dividing velocity by using time or in phrases of SI units, dividing the meter according to the second m/s by the second one. Dividing distance by time twice is the same as dividing distance via the rectangular of time. hence the SI unit of acceleration is the meter according to 2nd squared. If the acceleration is consistent, it's far viable to discover acceleration without time if we have the preliminary and final pace of the item as well as the amount of displacement. The system v2=u2+2as where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement is used.

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

D

Explanation:

Using the formula for average acceleration, which is:

average acceleration = (final velocity - initial velocity) / time

Where the initial velocity is 0 m/s and the final velocity is 60 m/s, and the time is 3 seconds, we get:

average acceleration = (60 m/s - 0 m/s) / 3 s = 20 m/s²

Therefore, the answer is (d) 20 m/s².

According to Newton's first law of motion, none force is to be exerted on the ball to keep it going.

The three fundamental laws of classical mechanics known as Newton's laws of motion describe how an object's motion and the forces acting on it interact. The following is a paraphrasing of these laws:

Unless a force acts upon a body, it remains at rest or in continual straight-line motion.

When a force acts on a body, the force is equal to the time rate at which the body's momentum changes.

When two bodies exert force on one another, the direction and amount of the force are opposed.

It is given that a cannonball is launched in frictionless space from a spaceship. Once the ball is launched into space, it cannot be slowed down by drag. Following Newton's first rule of motion, the cannonball would simply continue moving at the same speed until it collided with another object.

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Mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.

When a roller coaster starts at a height of 40 meters and reaches a height of 20 meters, mechanical energy changes. In physics, mechanical energy is the sum of potential and kinetic energy that is present in the objects. When an object is moved, it gains or loses energy, thus the mechanical energy changes. There are two forms of mechanical energy, namely kinetic energy and potential energy. Kinetic energy is the energy that a moving object possesses due to its motion, while potential energy is the energy that an object possesses due to its position or shape.
In the case of a roller coaster, when it starts at a height of 40 meters, it has potential energy that is equal to its mass multiplied by the acceleration due to gravity multiplied by its height. As it moves down the track, the potential energy gets converted into kinetic energy, which is the energy of motion. When the roller coaster reaches a height of 20 meters, it has a lower potential energy compared to when it started. The difference in potential energy is equal to the amount of work done by the force of gravity in bringing the roller coaster down from a height of 40 meters to a height of 20 meters. At the same time, the roller coaster has a higher kinetic energy than when it started, as it gained speed during the descent.
Therefore, in summary, mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.

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1 x 10⁻¹² C are stored in the system.

The power required to move a charge in opposition to an electric field is known as electric potential energy. A charge must be moved through a stronger electric field with more energy, but it also must be moved through a weaker electric field with more energy.

Electric potential at a place in an electric field is the amount of work done to move the unit positive charge from infinity to that point, and electric potential energy is fundamentally different.

Given are the following values: Stored charge, Q= 1x 10⁻¹⁰ C Voltage, V=100 v

We are aware that the formula for a system's capacitance is C=Q/V

= 1 x 10⁻¹⁰ / 100.

=1 x 10⁻¹² C

As a result, it is the necessary remedy.

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Answer:

54mph

Explanation:

The net-work required to accelerate the car of mass 1200 kg is 840000 J.

Work can be deifned as the product of force and distance.

To calculate the amount of net-work required to accelerate 1200 kg car from 25 m/s to 45 m/s, we use the formula

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the net-work required is 840000 J.

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