What produces the Coriolis Force on the movement of Earth's air masses? The rotation of the Earth from east to west. Warm light air from the Equator moves north. The rotation of the Earth from west to east. Heavy cool air from the north moves south.

I have observed and experienced behaviors that are learned as a result of environmental influences, and I can furnish examples to support this assertion.

Recycling serves as a noteworthy instance. During my childhood, I acquired the habit of recycling owing to the teachings and guidance of my parents and educators, which became firmly established in me.

Water conservation serves as another illustration. Having experienced repeated droughts in my locale, I developed a sense of awareness about the utilization of water and inculcated practices such as shutting off the tap while brushing my teeth.

My daily habits have been influenced by the environmental elements in my surroundings and have now become ingrained in my routine.

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Two low pass signals, each band limited 4KHz, are to be time-multiplexed into a single channel using PAM. Each signal is impulse sampled at a rate 10KHz. is mathematically given as

Generally, the equation for the minimum clock frequency is mathematically given as

minF=2*F

Therefore

minF=2*10

minF=20Hz

b)

the minimum cut-off frequency of the LPF

nCF this simply depicts of specifies the  sampling rate

Hence

nCF=fs

nCF= 10Khz

c)

The minimum and maximum acceptable bandwidth of the LPF

The minimum acceptable bandwidth depicts or specifies the sampling band limit.

minimum acceptable =Sampling band limit

minBL= 4Fz

The maximum acceptable bandwidth of the LPF is given by the impulse signal rate  minus the value of the minimum band limit, Hence

maxBL=10khz - 4Khz

maxBL=6Khz

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ANSWER:

(a) 141. 12 m

(b) 1.44 m/s²

STEP-BY-STEP EXPLANATION:

Given:

Time (t) = 14 s

Speed (v) = 45 mi/h

We must convert the speed in meters per second, like this:

First, we calculate the acceleration as follows:

and the distance is determined like this:

The equation of length is fo(1-1/M) and distance used for adjustment of eye piece is 20cm.

A refracting telescope's magnification is calculated by dividing the objective's focal length by the eyepiece's focal length.

e. g. A reflecting telescope has a 5 cm eyepiece and an objective with a focal length of 70 cm. It will be magnified by 70 / 5 = 14.

a) L = fo + fe

M = -fo / fe========> fe = -fo / M

L = fo - fo/M = fo*(1-1/M)

b) M = 50 = -fo/fe

L1 = fo*(1-(1/50)) = 2*(1-(1/50)) = 1.96 m

L2 = fo*(1-(1/50)) = 2*(1-(1/100)) = 1.98 m

d = L2 - L1 = 0.02m = 20 cm

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(a) The direction of wave propagation is along the negative z-axis.

(b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms.

(c) The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.

If the direction of wave propagation is specified as along the negative z-axis, we can conclude that the wave is traveling in the opposite direction to the positive z-axis. In the given expression: E = 50 sin(10^8 + 2z) ay V/m

Since the wave is traveling along the negative z-axis, it means that as z increases (in the positive direction), the wave is propagating in the opposite direction.

Hence, the direction of wave propagation for the given wave is along the negative z-axis.

To find the wavelength (λ), frequency (f), and wave impedance (Er), we can relate the electric field (E) and magnetic field (H) components using the wave equation in a nonmagnetic medium:

E = c * H,

where c is the speed of light in the medium, which can be approximated as 3 × \(10^{8}\) m/s in free space.

(a) Direction of wave propagation: Along the positive z-axis.

(b) Calculating λ, f, and Er:

Since the electric field (E) is given as E = 50 sin (\(10^{8}\) + 2z) ay V/m, we can see that the angular frequency (ω) is \(10^{8}\) rad/s and the wave number (k) is 2.

The relationship between wave parameters is given by: c = λ * f, where c is the speed of light.

Using the relation c = ω/k, we can solve for λ and f:

λ = 2π/k = 2π/2 = π m (meters)

f = ω/2π = \(10^{8}\)/2π ≈ 1.59 × \(10^{7}\) Hz (Hertz)

To find the wave impedance (Er), we can use the equation Er = E/H:

Er = E/c = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ≈ 0.1667 sin (\(10^{8}\) + 2z) ohms.

(c) The magnetic field (H) can be calculated using the relationship H = E/c:

H = (E/c) = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.

The direction of wave propagation is along the negative z-axis. (b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms. The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.

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Answer:

The evidence that the universe is expanding comes with something called the red-shift of light. Light travels to Earth from other galaxies. As the light from that galaxy gets closer to Earth, the distance between Earth and the galaxy increases, which causes the wavelength of that light to get longer. Distant galaxies are getting further away hinting at a point of origin. The composition of all observed matter in this universe points at a common origin point for all matter in the universe.

The three crucial evidences that supported the Big Bang theory are the CMB or cosmic microwave background, the expanding universe, the abundance of elements in the universe.

Big Bang theory is one of the important theory scientists used in earliest to describe the origin of universe and the phenomenon of evolution.

Here,

2. The Big Bang theory described the origin of universe as an expansion from an atmosphere of high density and extreme temperature which lead to a huge explosion of matter known as the  'Big Bang' and thus creation of  the universe.

The three crucial evidences that supported the Big Bang theory are:

The CMB or cosmic microwave background, the expanding universe, the abundance of elements in the universe.

3.(a) Light spectra was an important factor that supported the Big Bang theory mainly by the phenomenon called Doppler shift. Doppler shift occurs when stars move away, they get shifted to longer wavelength. This phenomenon is called red-shift or Doppler's Red shift. This was applicable in the case of Big Bang theory such that the theory claimed that, as a result of explosion which is the Big Bang, the material particles move away. This was similar to the red shift.

(b) The motion of distant galaxies was an evidence of the expansion of universe and soo the Big Bang theory. It was explained in such a way that, as the galaxies move away from us, it shows the more expansion of universe and the time duration since the origin of universe.

(c) The composition of matter in the universe was an important evidence that supported the Big Bang theory. The composition of universe that there is high abundance of hydrogen and helium in the atmosphere was claimed by the Big Bang theory.

Hence,

The three crucial evidences that supported the Big Bang theory are the CMB or cosmic microwave background, the expanding universe, the abundance of elements in the universe.

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Answer:

18 kg * m/s

Explanation:

The equation for momentum is:

momentum = mass * velocity

And although the problem already gave velocity, you must calculate the mass from the graviational force.

Fg = 3.4N = mg = 9.8m

mass = 3.4 N / 9.8 m/s^2 = 0.3469 kg

Momentum = 52m/s * 0.3469 kg - 18.041 kg * m/s = 18

Answer:

Explanation:ans:0 . Because when we connect this conductive sphare with earth then all charge will be gone in earth

Answer:

  v = \(n \frac{\hbar }{m r}\)

the sppedof the electron is also quantized

Explanation:

The angular momentum of a rotating body is

         L = m v r

in Bohr's atomic model the quantization postulate is that the angular momentum is equal to

         L = n \(\hbar\)

we substitute

        n \(\hbar\) = m v r

        v = \(n \frac{\hbar }{m r}\)

where n is an integer.

Therefore, the sppedof the electron is also quantized, that is, sol has some discrete values.

According to the law of conservation of energy, statement which is true about conservation of energy is that the total energy is always conserved.

According to law of conservation of energy, it is evident that energy is neither created nor destroyed rather it is restored at the end of a chemical reaction .

Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.

Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Julius Mayer in the year 1842.

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The volume of the gas at 101.3 kPa would be approximately 651.25 cm³.

To calculate the change in volume of a gas from an initial pressure to a final pressure, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's law can be expressed as:

P1 * V1 = P2 * V2

Where:

P1 = Initial pressure (80.8 kPa)

V1 = Initial volume (817 cm³)

P2 = Final pressure (101.3 kPa)

V2 = Final volume (to be calculated)

Let's plug in the values into the equation and solve for V2:

80.8 kPa * 817 cm³ = 101.3 kPa * V2

V2 = (80.8 kPa * 817 cm³) / 101.3 kPa

V2 ≈ 651.25 cm³

Therefore, the volume of the gas at 101.3 kPa would be approximately 651.25 cm³.

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Answer:

Answer: Eclipses do not happen at every new moon, of course. This is because the moon's orbit is tilted just over 5 degrees relative to Earth's orbit around the sun. For this reason, the moon's shadow usually passes either above or below Earth, so a solar eclipse doesn't occur.

Explanation:   :>

The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.

The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.

To calculate the time interval, we can use the following formula:

time = distance / speed

where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.

distance = 2 x 300m = 600m

speed = 343 m/s

time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)

Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

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In Coulomb's law, if one of the charges is doubled while the other remains the same, the magnitude of the force will also double, since the force is directly proportional to the product of the charges.

Coulomb's Law describes the electrostatic force between two charged particles. The force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, Coulomb's Law can be expressed as:

F = k * (q1 * q2) / r^2

where F is the force between the charges, q1 and q2 are the magnitudes of the charges, r is the distance between them, and k is the Coulomb constant.

If one of the charges is doubled while the other remains the same, the magnitude of the force will also double, since the force is directly proportional to the product of the charges. Therefore, the new equation for the magnitude of the force in this scenario would be:

F' = k * (2q * q) / r^2 = 2 * (k * (q * q) / r^2) = 2F

where F' is the new force and F is the original force. So, when one of the charges is double, the magnitude of the force in Coulomb's Law will also double.

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Answer:

8 is c and 9 is b it is shown though the practice as god lol

Question 8

The net force acting on the cart is:

F = 150 N - 90 N

F = 60 N

Question 9

By the Newtons second law:

F = ma

Solving for a:

a = F/m

a = 60 N / 30 kg

a = 2 m/s²

Potential at C with respect to B is +65 volts (C with respect to ground) - +80 volts (B with respect to ground) is -15 volts with respect to B.

To find the potentials at B, C, and D with respect to the ground:

Potential at B with respect to ground:

Since A is at +100 volts with respect to ground and +20 volts with respect to B, we can deduce that B is 100 - 20 = +80 volts with respect to ground.

Potential at B = +80 volts with respect to ground.

Potential at C with respect to ground:

C is at +15 volts with respect to D, and D is at +50 volts with respect to E. Since E is at ground potential (0 volts), we can calculate the potential at C with respect to ground by adding the potentials:

Potential at C = +50 volts (D with respect to E) + 15 volts (C with respect to D) = +65 volts with respect to ground.

Potential at D with respect to ground:

D is at +50 volts with respect to E, and E is at ground potential (0 volts). Therefore, the potential at D with respect to ground is:

Potential at D = +50 volts (D with respect to E) + 0 volts (E with respect to ground) = +50 volts with respect to ground.

Now, let's calculate the potential at C with respect to B and D:

Potential at C with respect to B:

We know that A is at +20 volts with respect to B. Combining this information with the potential at A (+100 volts with respect to ground), we can determine the potential at B with respect to ground:

Potential at B = +100 volts with respect to ground - +20 volts (A with respect to B) = +80 volts with respect to ground.

Since we already calculated the potential at C with respect to ground as +65 volts, we can find the potential at C with respect to B:

Potential at C with respect to B = +65 volts (C with respect to ground) - +80 volts (B with respect to ground) = -15 volts with respect to B.

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The magnitude of the electrical field would be 1.5x10^3 N/C.

The electrostatic force experienced by a charged particle in an electric field is given by the formula:

F = qE

Where F is the electrostatic force, q is the charge of the particle, and E is the electric field strength.

In this case, the electrostatic force acting on the particle is 3.0x10^-6 N and the charge of the particle is -2.0x10^-9 C. So we have:

3.0x10^-6 N = (-2.0x10^-9 C)E

Solving for E, we get:

E = (3.0x10^-6 N) / (-2.0x10^-9 C)

E = -1.5x10^3 N/C

Since the electric field is a vector quantity, its magnitude is always positive. Therefore, the magnitude of the electric field in this case is:

|E| = 1.5x10^3 N/C

So the magnitude of the electric field is 1.5x10^3 N/C, directed downward.

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Answer:

To find the work done, we need to calculate the force applied to the block and the distance it moves.

The force applied to the block can be resolved into two components: one parallel to the floor and one perpendicular to the floor. The parallel component of the force is responsible for pushing the block forward, while the perpendicular component does not contribute to the work done.

The parallel component of the force is:

F_parallel = F * cos(30°) = F * √3/2

where F is the magnitude of the force applied.

The force of friction opposing the motion is:

F_friction = μ * F_norm

where μ is the coefficient of friction and F_norm is the normal force acting on the block, which is equal to the weight of the block since it is on a level floor:

F_norm = m * g = 25 kg * 9.81 m/s^2 = 245.25 N

where g is the acceleration due to gravity.

So the force of friction is:

F_friction = 0.4 * 245.25 N = 98.1 N

Since the block is moving at constant speed, the force applied must be equal and opposite to the force of friction:

F_parallel = F_friction

F * √3/2 = 98.1 N

F = 56.6 N

The work done by the force applied is:

W = F_parallel * d = 56.6 N * 5 m = 283 J

Therefore, the work done by the force applied is 283 J

Given parameters;

Time taken to complete a lap  = 8.667s

Radius of flower = 13.9cm

    convert to SI unit of m,  100cm = 1m

            13.9cm gives \(\frac{13.9}{100}\)   = 0.139m

Unknown  = speed

To solve this problem, we need to first find the circumference of the flower.

 Circumference of the circular flower  = 2 π r

    where r is the radius of the flower;

           Circumference  = 2 x 3.142 x 0.139 = 0.87m

Now to find the how fast the bug is travelling,

   Speed  = \(\frac{distance}{time}\)

Since the bug covered 1 lap, the distance is 0.87m

Now input the parameters and solve for speed;

    Speed  = \(\frac{0.87}{8.667}\)  = 0.1m/s

The bug is travelling at a speed of  0.1m/s

Approximately 3.16 x 10¹² machines at a distance of 5 m are needed to exceed 115 dB at a distance of 5 m.

Decibel (dB) is a unit of measurement that is used to express the relative intensity of sound or the ratio of two power quantities. It is a logarithmic unit that compares the power level of a sound to a reference level.

The decibel scale is logarithmic because the human ear perceives changes in sound intensity logarithmically. Therefore, the use of the decibel scale allows us to express a wide range of sound intensities using a more manageable numerical range.

a) To calculate the volume in decibels, we can use the given formula:

L = 10 lg(I/I0)

First, let's calculate the intensity of the noise:

1 kW = 1000 W

0.01% of 1000 W = 0.01 x 1000 W = 10 W

Area of a sphere with a radius of 5 m = 4πr² = 4π(5 m)² = 314.16 m²

Therefore, the intensity of the noise at a distance of 5 m from the machine is:

I = 10 W / 314.16 m² = 0.0318 W/m²

Now we can use the formula to calculate the volume:

L = 10 lg(I/I0) = 10 lg(0.0318 W/m² / 10⁻¹⁶ W/cm²) = 105 dB

Therefore, the volume of the noise at a distance of 5 m from the machine is 105 dB.

b) To calculate the number of machines needed to exceed 115 dB, we can use the formula in reverse:

L = 10 lg(I/I0)

115 dB = 10 lg(I/I0)

11.5 = lg(I/I0)

I/I0 = 10¹¹°⁵

Now we can calculate the total intensity needed at a distance of 5 m from the machines:

I_total = 10¹¹°⁵ W/m²

For one machine, the intensity of the noise at a distance of 5 m is:

I_machine = 10 W / 314.16 m² = 0.0318 W/m²

So the number of machines needed is:

N = I_total / I_machine = 10¹¹°⁵/ 0.0318 = 3.16 x 10¹²

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(a)  the horizontal distance between the saddle and limb when the man makes his move is approximately 11.386 meters.

(b)  the man is in the air for approximately 0.843 seconds.

To determine the horizontal distance between the saddle and limb when the man makes his move, we need to consider the horizontal velocity of the man when he drops from the tree limb.

Given:

Speed of the horse (constant velocity), v = 13.5 m/s

Vertical distance between the limb and saddle, h = 3.55 m

a) To find the horizontal distance, we can use the formula:

horizontal distance = horizontal velocity × time

Since the man drops vertically, his initial horizontal velocity is zero. The only horizontal velocity he will have is due to the motion of the horse.

The time taken by the man to fall can be determined using the equation for free fall:

h = (1/2) × g × t²

Where g is the acceleration due to gravity (approximately 9.8 m/s²) and t is the time.

Rearranging the equation, we get:

t = √(2h / g)

Substituting the given values:

t = √(2 × 3.55 / 9.8) ≈ 0.843 s

Now, we can find the horizontal distance:

horizontal distance = v × t

horizontal distance = 13.5 × 0.843 ≈ 11.386 m

Therefore, the horizontal distance between the saddle and limb when the man makes his move is approximately 11.386 meters.

b) The time the man is in the air can be calculated using the same equation for free fall:

t = √(2h / g)

Substituting the given value of h:

t = √(2 × 3.55 / 9.8) ≈ 0.843 s

Thus, the man is in the air for approximately 0.843 seconds.

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There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.

However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.

Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.

Explanation:

Competition in the Los Angeles Flower District results in better quality flowers.

Competition results in better quality flowers because in the competition, best quality of flowers will be selected as a winner so the competitors produces best quality of flowers in order to claim the prize so we can conclude that Competition in the Los Angeles Flower District results in better quality flowers

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Answer:

1.8 ms to the left

Explanation:

Answer:1.8 ms to the left

Explanation:

Answer:

nvbnncbmkghbbbvvvvvvbvbhgggghhhhb

Answer:

ultraviolet light

plz mark me as brainliest.

Answer:

Ultra violet

Explanation: