What is the y-intercept of f(x)=(3/5)^x?

Period of the functions: The period of the function f(t) = (7 cos t)² is given by 2π/b where b is the period of cos t.The period of the function f(t) = cos (2φt²/m) is given by T = √(4πm/φ). The period of the function f(t) = (7 cos t)² is given by 2π/b where b is the period of cos t.

We know that cos (t) is periodic and has a period of 2π.∴ b = 2π∴ The period of the function f(t) =

(7 cos t)² = 2π/b = 2π/2π = 1.

The period of the function f(t) = cos (2φt²/m) is given by T = √(4πm/φ) Hence, the period of the function f(t) =

cos (2φt²/m) is √(4πm/φ).

The function f(t) = (7 cos t)² is a trigonometric function and it is periodic. The period of the function is given by 2π/b where b is the period of cos t. As cos (t) is periodic and has a period of 2π, the period of the function f(t) = (7 cos t)² is 2π/2π = 1. Hence, the period of the function f(t) = (7 cos t)² is 1.The function f(t) = cos (2φt²/m) is also a trigonometric function and is periodic. The period of this function is given by T = √(4πm/φ). Therefore, the period of the function f(t) = cos (2φt²/m) is √(4πm/φ).

The period of the function f(t) = (7 cos t)² is 1, and the period of the function f(t) = cos (2φt²/m) is √(4πm/φ).

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Approximately 72.19% of women are not qualified to be fighter pilots due to their heights.

To determine the percentage of women who are not qualified due to their heights, we need to find the area under the normal distribution curve that falls outside the range of 62 to 78 inches.

First, let's calculate the z-scores for both 62 and 78 inches using the formula: z = (x - mean) / standard deviation.

For 62 inches: z = (62 - 63.7) / 2.9 = -0.5862
For 78 inches: z = (78 - 63.7) / 2.9 = 4.9655

Next, we can use a standard normal distribution table or a calculator to find the proportion of the distribution that falls outside these z-scores.

The area to the left of -0.5862 is approximately 0.2781.
The area to the right of 4.9655 is approximately 0.

To find the percentage of women not qualified, we need to calculate the area between -0.5862 and 4.9655, which is equal to 1 - (0.2781 + 0) = 0.7219.

Therefore, approximately 72.19% of women are not qualified to be fighter pilots due to their heights.

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Answer:

\(m=\frac{-1}{3}\)

Step-by-step explanation:

In the easiest explanation, the answer would be \(m=\frac{-1}{3}\)

Using \(m=\frac{rise}{run}\)  you will go down one point from \((-1,-1)\) because rise is -1. From that point, you will go three points to the left that being because run is a positive number. Then you will find yourself being at the second point which is \((2,-2)\).

Another explanation is basically using the slope formula

\(m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }\)

Answer:

A) -1/3

Step-by-step explanation:

Answer:

Step-by-step explanation:

Michelle earns $3 an hour more than Dave.

The value of x as an int variable is 0

An int(integer) variable is a variable containing only whole numbers.

Given the expression;

x = - 3 + 4 % 6/ 5

Let's make into proper fraction, we have

x = - 3 + {}4/ 100 × 6/ 5

Multiply through

x = -3 + 6/ 5/ 4/ 100

x = -3 + {6/ 5 ÷ 0. 4}

x = -3 + {3}

expand the bracket

x = -3 + 3

Add like terms

x = 0

Thus, the value of x as an int variable is 0

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Complete question;

Assume that x is an int variable. what value is assigned to x after the following assignment statement is executed? x = -3 + 4 % 6/ 5;

Answer:

cooma 2.5

Step-by-step explanation:

i did the quiz

am different    \_(*-*)_/

Answer:

It is d

Step-by-step explanation:

:)

Answer:

It is D

Step-by-step explanation:

Just took the test on edg

Answer:

hi

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1) undefined

2) 2

3) 0

4) -3

Answer:

y= -cos(x)+2

Step-by-step explanation:

Lmk if you need an explanation and I'll add it.

The musical theater group should charge $14.25 per ticket to maximize revenue. To find the ticket price that maximizes revenue, we need to determine the revenue function and then differentiate it with respect to the ticket price to find the critical points.

We can then evaluate the revenue at these points to determine the maximum. Let x be the number of dollars charged for admission above the base price of $7.75, and let y be the number of tickets sold at that price. Then, the revenue function is given by:

R(x) = (1200 - 50x)(7.75 + x)

Expanding this expression, we get:

R(x) = 9300 + 650x - 50x^2

To find the ticket price that maximizes revenue, we need to find the critical points of the revenue function. We can do this by differentiating the revenue function with respect to x and setting the derivative equal to zero:

R'(x) = 650 - 100x = 0

Solving for x, we get:

x = 6.5

This means that the additional charge above the base price that maximizes revenue is $6.50. Therefore, the ticket price that maximizes revenue is:

7.75 + 6.50 = $14.25

So, the musical theater group should charge $14.25 per ticket to maximize revenue.

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Answer:

\(x = -\dfrac 23\\\\x = -2\)

Step by step explanation:

\(3x^2 +8x +4 =0\\\\\text{The quadratic formula,}~ x = \dfrac{-b\pm\sqrt{b^2 -4ac}}{2a}.\\\\\text{By comparing}~ 3x^2 +8x +4~ \text{with the standard form}~ ax^2 +bx +c,\\\\a = 3, ~b = 8 ,~ c = 4\\\\\text{Now,}~\\\\x = \dfrac{-8\pm\sqrt{8^2 -4 \times 3 \times 4}}{2(3)}\\\\\\~~~=\dfrac{-8\pm\sqrt{64-48}}{6}\\\\\\~~~=\dfrac{-8\pm\sqrt{16}}{6}\\\\\\~~~=\dfrac{-8\pm 4 }{6}\\\)

\(x = \dfrac{-8+4}{6}=-\dfrac{4}{6}= -\dfrac 23\\\\x= \dfrac{-8-4}{6}= -\dfrac{12}{6}=-2\)

Answer:The value of the surface area (in square centimeters) of the cone is equal to the value of the volume (in cubic centimeters) of the cone. The formula for the surface area S of a cone is S=πr2+πrl, where r is the radius of the base and l is the slant height.

Step-by-step explanation:

Answer:

A cone is 360 triangles rotated in a circle, so find the hypotenuse of the triangle and multiplying it by 360 you would get the surface area of the cone

(っ◔◡◔)っ ♥ Hope It Helps ♥

Assuming you're trying to find the value of r...

Answer:

r = 1

Step-by-step explanation:

Take your starting equation:

16 = 16r

Since r is multiplied by 16, divide both sides by 16 to isolate r.

16 / 16 = 1

16r / 16 = r

The result is 1 = r, which can be written as:

r = 1

Answer:14

Step-by-step explanation: so if you add 21 and 264 and 20 u would get 14 hehehehhehehe im da best your not :)

Answer:

w = 1.5 , x = 4

Step-by-step explanation:

assuming you require to find w and x

Δ ABE and Δ ACD are similar ( AA postulate )

then the ratios of corresponding sides are in proportion, that is

\(\frac{AB}{AC}\) = \(\frac{BE}{CD}\) ( substitute values )

\(\frac{3}{3+w}\) = \(\frac{4}{6}\) = \(\frac{2}{3}\) ( cross- multiply )

2(3 + w) = 9 ( divide both sides by 2 )

3 + w = 4.5 ( subtract 3 from both sides )

w = 1.5

and

\(\frac{AE}{AD}\) = \(\frac{BE}{CD}\) ( substitute values )

\(\frac{x}{x+2}\) = \(\frac{4}{6}\) = \(\frac{2}{3}\) ( cross- multiply )

3x = 2(x + 2)

3x = 2x + 4 ( subtract 2x from both sides )

x = 4

Answer:

It might be C if im wrong sorry

Step-by-step explanation:

The missing part of the equation is \(-7.0\times10^4 s^2kg⋅m^2 / 1000000.\)

To fill in the missing part of the equation, let's analyze the given information and the desired conversion. The equation is:

\((-7.0\times 10^4 s^2g⋅m^2)\cdot \pi = ? s^2kg\cdot m^2\)

In this equation, we have a quantity expressed in\(s^2g\cdot m^2\) units on the left-hand side. To convert it to \(s^2kg\cdot m^2\) units, we need to multiply it by a conversion factor.

To perform the conversion, we can use the fact that 1 kg is equal to 1000 g. Therefore, the conversion factor we need is:

1 kg / 1000 g

To ensure that the units cancel out correctly, we need to square this conversion factor because we have \(s^2g\cdot m^2\) on the left-hand side. So the missing part of the equation is:

\((-7.0\times 10^4 s^2g\cdot m^2)\cdot \pi = (-7.0\times 10^4 s^2g\cdot m^2)\cdot (1 kg / 1000 g)^2\)

Simplifying this expression, we get:

\((-7.0\times10^4 s^2g\cdot m^2)\cdot \pi = -7.0 \times10^4 s^2kg\cdot m^2 / 1000000\)

Therefore, the missing part of the equation is \(-7.0 \times 10^4 s^2kg\cdot m^2 / 1000000.\)

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keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

\(x-3y=9\implies -3y=-x+9\implies y=\cfrac{-x+9}{-3} \\\\\\ y=\cfrac{-x}{-3}+\cfrac{9}{-3}\implies y=\cfrac{1}{3}x-3\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\)

so we're really looking for the equation of a likne whose slope is 1/3 and it passes through (-10 , 9)

\((\stackrel{x_1}{-10}~,~\stackrel{y_1}{9})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{ \cfrac{1}{3}}(x-\stackrel{x_1}{(-10)}) \implies y -9= \cfrac{1}{3} (x +10) \\\\\\ y-9=\cfrac{1}{3}x+\cfrac{10}{3}\implies y=\cfrac{1}{3}x+\cfrac{10}{3}+9\implies {\Large \begin{array}{llll} y=\cfrac{1}{3}x+\cfrac{37}{3} \end{array}}\)

Answer:

45 levels

Step-by-step explanation:

60% of 75 is 45 i think

The SRED Credit remainder after applying the maximum SRED Credit for this year is $0.

The Scientific Research and Experimental Development (SRED) program provides tax incentives for companies conducting eligible research and development activities. The SRED credit is calculated based on qualified SRED expenses and can be used to reduce the tax liability of a company.

In this case, the qualified SRED expenses for the current year are $10,000. However, the SRED credit remainder is determined after applying the maximum SRED credit for the year. Since the maximum SRED credit has already been applied, the remaining SRED credit is $0.

The taxable loss from the previous year ($50,000) and the part I tax before SRED ($1,500) are not directly relevant to determining the SRED credit remainder. The maximum SRED credit has already been utilized, resulting in a remaining credit of $0.

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Step-by-step explanation:

Break it up into two trapezoids as shown

area = trap1 + trap2

      = 2 *   (7+3) / 2   + 3 *  ( 7 + 3) / 2 = 10 + 15 = 25 units^2

Answer:

enjoy it .................

Answer:

Translates up 1 and to the left 2

Step-by-step explanation:

I'm not completely sure if this is right but I hope it helps :/

Answer:

14.45

Step-by-step explanation:

To determine the equation of the tangent plane and normal line of the given curve at the point P(2, -3, 18), we need to find the partial derivatives of the function f(x, y, z) = x^2 + y^2 - 2xy - x + 3y - z - 4.

Taking the partial derivatives with respect to x, y, and z, we have:

fx = 2x - 2y - 1

fy = -2x + 2y + 3

fz = -1

Evaluating these partial derivatives at the point P(2, -3, 18), we find:

fx(2, -3, 18) = 2(2) - 2(-3) - 1 = 9

fy(2, -3, 18) = -2(2) + 2(-3) + 3 = -7

fz(2, -3, 18) = -1

The equation of the tangent plane at P is given by:

9(x - 2) - 7(y + 3) - 1(z - 18) = 0

Simplifying the equation, we get:

9x - 7y - z - 3 = 0

To find the equation of the normal line, we use the direction ratios from the coefficients of x, y, and z in the tangent plane equation. The direction ratios are (9, -7, -1).Therefore, the equation of the normal line passing through P(2, -3, 18) is:

x = 2 + 9t

y = -3 - 7t

z = 18 - t

where t is a parameter representing the distance along the normal line from the point P.

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Answer:

2/3

Step-by-step explanation:

Slope = (-1-(-3))/(3-0) = 2/3

Answer:

slope = 2/3

Step-by-step explanation:

equation: y = x2/3 -3

Answer:

my answer is D.)3 m + 2 = -10

Step-by-step explanation:

1. The solution to the first differential equation is given by e^2yx - ysin(xy) + y^2 + C = 0, where C is an arbitrary constant.

2. The general solution to the second differential equation is x(3x - y^2) = C, where C is a positive constant.

To solve the first-order differential equations, let's solve them one by one:

1. (e^2y - ycos(xy))dx + (2xe^2y - xcos(xy) + 2y)dy = 0

We notice that the given equation is not in standard form, so let's rearrange it:

(e^2y - ycos(xy))dx + (2xe^2y - xcos(xy))dy + 2ydy = 0

Comparing this with the standard form: P(x, y)dx + Q(x, y)dy = 0, we have:

P(x, y) = e^2y - ycos(xy)

Q(x, y) = 2xe^2y - xcos(xy) + 2y

To check if this equation is exact, we can compute the partial derivatives:

∂P/∂y = 2e^2y - xcos(xy) - sin(xy)

∂Q/∂x = 2e^2y - xcos(xy) - sin(xy)

Since ∂P/∂y = ∂Q/∂x, the equation is exact.

Now, we need to find a function f(x, y) such that ∂f/∂x = P(x, y) and ∂f/∂y = Q(x, y).

Integrating P(x, y) with respect to x, treating y as a constant:

f(x, y) = ∫(e^2y - ycos(xy))dx = e^2yx - y∫cos(xy)dx = e^2yx - ysin(xy) + g(y)

Here, g(y) is an arbitrary function of y since we treated it as a constant while integrating with respect to x.

Now, differentiate f(x, y) with respect to y to find Q(x, y):

∂f/∂y = e^2x - xcos(xy) + g'(y) = Q(x, y)

Comparing the coefficients of Q(x, y), we have:

g'(y) = 2y

Integrating g'(y) with respect to y, we get:

g(y) = y^2 + C

Therefore, f(x, y) = e^2yx - ysin(xy) + y^2 + C.

The general solution to the given differential equation is:

e^2yx - ysin(xy) + y^2 + C = 0, where C is an arbitrary constant.

2. x(yy' - 3) + y^2 = 0

Let's rearrange the equation:

xyy' + y^2 - 3x = 0

To solve this equation, we'll use the substitution u = y^2, which gives du/dx = 2yy'.

Substituting these values in the equation, we have:

x(du/dx) + u - 3x = 0

Now, let's rearrange the equation:

x du/dx = 3x - u

Dividing both sides by x(3x - u), we get:

du/(3x - u) = dx/x

To integrate both sides, we use the substitution v = 3x - u, which gives dv/dx = -du/dx.

Substituting these values, we have:

-dv/v = dx/x

Integrating both sides:

-ln|v| = ln|x| + c₁

Simplifying:

ln|v| = -ln|x| + c₁

ln|x| + ln|v| = c₁

ln

|xv| = c₁

Now, substitute back v = 3x - u:

ln|x(3x - u)| = c₁

Since v = 3x - u and u = y^2, we have:

ln|x(3x - y^2)| = c₁

Taking the exponential of both sides:

x(3x - y^2) = e^(c₁)

x(3x - y^2) = C, where C = e^(c₁) is a positive constant.

This is the general solution to the given differential equation.

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