The volume of the sphere is 5,575.28 ft³.
What is the sphere?The volume of the sphere is calculated by applying the following formula as shown below;
V = ⁴/₃ πr³
where;
r is the radius of the sphereThe radius of the sphere is calculated as follows;
r = d/2
where;
d is the diameterr = 22 ft / 2
r = 11 ft
The volume of the sphere is calculated as;
V = ⁴/₃ π(11)³
V = 5,575.28 ft³
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121/2% in to a fraction
9514 1404 393
Answer:
1/8
Step-by-step explanation:
You can replace % with /100 to make it a fraction.
12 1/2% = (12 1/2)/100 = (25/2)/100 = 25/200 = 1/8
__
Or, you can reduce the decimal fraction.
12.5% = 12.5/100 = 0.125 = 125/1000 = 1/8
(45 POINTS!!!) Which is the equation of a parabola with a directrix at y = −3 and a focus at (−2, 3).
y = one twelfth(x − 2)
2 y = one twelfth(x + 2)
2 y = −one twelfth(x + 2)
2 y = −one twelfth(x − 2)2
Answer:
y = −one twelfth(x − 2)2
Step-by-step explanation:
y = −one twelfth(x − 2)2
Answer:
y = −one twelfth(x − 2)2
Step-by-step explanation:
PLEASE HELP
If the spinner is spun, what are the ODDS that the pointer lands on the number 6 or greater?
Answer:
What's the spinner? How many numbers are on it?
Step-by-step explanation:
The two-way table represents data from a survey asking schoolchildren whether they are attending a summer camp, taking swimming lessons, or both.
A 4-column table with 3 rows. The first column has no label with entries swimming lessons, no swimming lessons, total. The second column is labeled camp with entries 42, 18, 60. The third column is labeled no camp with entries 32, 4, 36. The fourth column is labeled total with entries 74, 22, 96.
Which is the joint relative frequency for school children who plan to attend camp and have swimming lessons? Round the answer to the nearest percent.
4%
19%
33%
44%
The joint relative frequency for school children who plan to attend camp and have swimming lesson is 44%.
The correct option to the given question is option d.
We are required to find the joint relative frequency for school children who plan to attend camp and have swimming lessons, rounded to the nearest percent.
To find the joint relative frequency, we use the formula as follows:
Joint relative frequency = frequency of interest / total frequency
Joint relative frequency for school children who plan to attend camp and have swimming lessons = 42 / 96
(As we are looking for the students who plan to attend camp and have swimming lessons, we are interested in the first column of the table and the entry at the intersection of the first row and second column.)
Joint relative frequency for school children who plan to attend camp and have swimming lessons = 0.4375
Joint relative frequency for school children who plan to attend camp and have swimming lessons (rounded to the nearest percent) = 44%(option d).
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What is the domain and range of each relation
Answer:
1 ans
domain=(-2,0,2,4)
range=(-3,-1,0)
2 ans
domain=(-3,-1,0,3)
range=(-1,0,1,2,3)
Step-by-step explanation:
What are 3 attributes of a Square based pyramid
Answer:
It has 5 Faces.
The 4 Side Faces are Triangles.
The Base is a Square.
It has 5 Vertices (corner points)
It has 8 Edges.
Step-by-step explanation:
btw you can choose 3
Ali, Basti and Cian stand at three points A, B and C respectively. Suppose that the measure of angle ABC is 50 degrees , the measure of angle BAC is 60 degrees and Ali is exactly 150 ft away from Basti. Find the distance between Basti and Cian.
The distance between Basti and Cian is approximately 138.2 ft. Option D
To find the distance between Basti and Cian, we can use the Law of Sines, which relates the lengths of sides to the sines of their opposite angles in a triangle.
Let's label the points: A, B, and C. Ali is at point A, Basti is at point B, and Cian is at point C.
Given:
Angle ABC = 50 degrees (angle opposite side AC)
Angle BAC = 60 degrees (angle opposite side BC)
Ali is 150 ft away from Basti (side AB)
We want to find the distance between Basti and Cian, which is side BC.
Using the Law of Sines, we have:
BC/sin(50) = AB/sin(60)
Substituting the known values:
BC/sin(50) = 150/sin(60)
To find BC, we can rearrange the equation:
BC = (150/sin(60)) * sin(50)
Using a calculator to evaluate the expression:
BC ≈ 138.2 ft
Option D is correct.
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Are the vectors U1 = and U2 = parallel?
Answer:
Express the vector →u below as a sum of two vectors →u1 and →u2, where →u1 is parallel to the vector →v given below, and →u2 is perpendicular to →v.
a restaurant offers a $12 dinner special that has 7 choices for an appetizer, 10 choices for an entrée, and 3 choices for a dessert. How many different meals are available when you select an appetizer, an entrée, and a dessert?
a meanl can be chosen __ ways
a meal can be chosen is 546 different ways.
Question: Find the value of the question mark.
Answer: __ ft
Answer:
24 ft
Step-by-step explanation:
You use the pythagorean theorem: 45^2+x^2=51^2
x=24, -24.
Sides can be negative, so x=24 ft.
Person to answer gets 30 points!!!! Please set up the equation in y=__x+__ form please
Answer:
y = 0.464X + 1.4
Step-by-step explanation:
From the given table,
Set of points given in the table is {(10, 6.8), (20, 10.2), (30, 13.9), (40, 21.2), (50, 24.5)}
By using calculator for line of best fit,
Equation of the line will be,
y = 0.464X + 1.4
A class fundraiser is earning $7 per car wash w and $4 per cake c sold. The cakes cost $2 to make and the supplies or the car wash cost $1 per car. They will wash less than 50 cars and bake no more than 30 cakes. They want to raise at least $320 to give to a local charity. What system represents this situation
Answer:
w<50
c≤30
6w+2c≥320
Step-by-step explanation:
W stands for the car wash, and C stands for the cakes. Naturally, it would be 7w+4c≥320 but each cake costs $2 to make and each car wash costs $1 per car. This makes the system 6w+2c≥320. They will wash less than(<) 50 cars and bake no more than(≤) 30 cakes. I hope this helped :).
To solve the problem we must know about Expressions.
What is an Expression?In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.
Given to us
Earning per car wash = $7
Earning per cake = $4
Cost of supplies per car wash = $1
Cost of cake = $2
They will wash less than 50 cars and
Bake no more than 30 cakes
They want to raise at least $320
Assumption
Let the number of cakes they sold be represented by x, and the number of car washes they did be represented by y.
Profit from Car washProfit from Car wash
= Earning per car wash - Cost of supplies per car wash
= $7 - $1
= $6
Profit from CakeProfit from Cake
= Earning per Cake - Cost of a cake
= $4 - $2
= $2
What is Total Profit?The system that represents profit
$320 = ($6)y + ($2)x
320 = 6y + 2x
Number of Cake they will bake,As it is given that they will not make more than 30 cakes, therefore,
x ≤ 30
Number of Carwashes they will do,As it is given that they will wash less than 50 cars.
y < 50
Hence, the following equations can represent the system,
320 = 6y + 2xx ≤ 30y < 50Learn more about Expression:
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Yet again just need answers to this
Answer:
Decreasing Interval
Step-by-step explanation:
An ice cream shop has a sign in the shape of an ice cream cone. The sign is made using a semicircle and a triangle, as modeled below.
Which is the best estimate of the area of the sign in square inches?
Answer: 50in²
Step-by-step explanation:
The area of the ice cream cone will be equal to 50.13 square inches.
What is an area?The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the semicircle in a two-dimensional plane is called the area of the semicircle.
The space occupied by the triangle in a two-dimensional plane is called the area of the triangle.
Given that the diameter of the semicircle is 6 inches and the height of the triangle is 12 inches.
The area of the cone will be calculated as,
A = Area of semicircle + Area of triangle
A = (1/2)πr² + (1/2) x B x H
A = (1/2) π (3)² + (1/2) x 12 x 6
A = 14.137 + 36
A = 50.13 square inch
Therefore, the area of the ice cream cone will be equal to 50.13 square inches.
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to find the quotient 3/4 divided 1/8 multiply what by what
Answer:
Make 1/8 a reciprocal which would be 8/1 so 3/4 x 8/1 is 24/4 = 6
Quan likes to exercise by running every day. On average, he runs 5 miles each day. This varies by about 0.3 mile. What are the maximum and minimum numbers of miles Quan is expected to run each day?
Answer:
Quan runs a maximum of 5.3 miles and a minimum of 4.7 miles every day.
Step-by-step explanation:
Let x= the actual measurement.
|actual − ideal|≤ tolerance
Use an absolute value inequality to express this situation.
|x−5|≤0.3
Rewrite as a compound inequality.
−0.3≤x−5≤0.3
Solve the inequality.
4.7≤x≤5.3
Answer the question. Quan runs a maximum of 5.3 miles and a minimum of 4.7 miles every day.
Please help me with this.
Here are the correct matches to the expressions to their solutions.
The GCF of 28 and 60 is 4.
(-3/8)+(-5/8) = -4/4 = -1.
-1/6 DIVIDED BY 1/2 = -1/6 X 2 = -1/3.
The solution of 0.5 x = -1 is x = -2.
The solution of 1/2 m = 0 is m = 0.
-4 + 5/3 = -11/3.
-2 1/3 - 4 2/3 = -10/3.
4 is not a solution of -4 < x.
1. The GCF of 28 and 60 is 4.
The greatest common factor (GCF) of two numbers is the largest number that is a factor of both numbers. To find the GCF of 28 and 60, we can factor each number completely:
28 = 2 x 2 x 7
60 = 2 x 2 x 3 x 5
The factors that are common to both numbers are 2 and 2. The GCF of 28 and 60 is 2 x 2 = 4.
2. (-3/8)+(-5/8) = -1.
To add two fractions, we need to have a common denominator. The common denominator of 8/8 and 5/8 is 8. So, (-3/8)+(-5/8) = (-3 + (-5))/8 = -8/8 = -1.
3. -1/6 DIVIDED BY 1/2 = -1/3.
To divide by a fraction, we can multiply by the reciprocal of the fraction. The reciprocal of 1/2 is 2/1. So, -1/6 DIVIDED BY 1/2 = -1/6 x 2/1 = -2/6 = -1/3.
4. The solution of 0.5 x = -1 is x = -2.
To solve an equation, we can isolate the variable on one side of the equation and then solve for the variable. In this case, we can isolate x by dividing both sides of the equation by 0.5. This gives us x = -1 / 0.5 = -2.
5. The solution of 1 m = 0 is m = 0.
To solve an equation, we can isolate the variable on one side of the equation and then solve for the variable. In this case, we can isolate m by dividing both sides of the equation by 1. This gives us m = 0 / 1 = 0.
6. -4 + 5/3 = -11/3.
To add a fraction and a whole number, we can convert the whole number to a fraction with the same denominator as the fraction. In this case, we can convert -4 to -4/3. So, -4 + 5/3 = -4/3 + 5/3 = -11/3.
7. -2 1/3 - 4 2/3 = -10/3.
To subtract two fractions, we need to have a common denominator. The common denominator of 1/3 and 2/3 is 3. So, -2 1/3 - 4 2/3 = (-2 + (-4))/3 = -6/3 = -10/3.
8. 4 is not a solution of -4 < x.
The inequality -4 < x means that x must be greater than -4. The number 4 is not greater than -4, so it is not a solution of the inequality.
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over a period of a week the 4 people in group C ran a total pf 27 miles while the 6 people in group D ran a total lf 39 miles. On avarage who ran more miles Group C or Group D.
Group C ran more miles than Group D
the central value of a set of data is expressed by the average of a list of data. It is defined mathematically as the ratio of the total number of data points to the number of units in the list. In terms of statistics, the term "mean" also refers to the average of a certain set of numerical data. The average of 2, 3, and 4 is, for instance, (2+3+4)/3 = 9/3 = 3. The center value of 2, 3, and 4 in this instance is 3, thus. Finding the mean value of a bunch of numbers is the definition of average.
Average = Total Values / Total Values
Group C = 27/4 = 6.75
Group D = 39 /6 = 6.5
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6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Which equation represents a line which is parallel to the line y=1/5x -1
5x +y =3
X+ 5y =10
5y - x = -20
5x - y = -3
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Answer:
(c) 5y - x = -20
Step-by-step explanation:
When the x- and y-terms are on the same side of the equation, the slope of the line will be ...
m = -(coefficient of x)/(coefficient of y)
So, the slopes of the offered choices are ...
a) -5/1 = -5
b) -1/5
c) -(-1)/5 = 1/5 . . . . . parallel to given line
d) -5/-1 = 5
The lines will be parallel when their slopes are the same. The slope of the given line is the coefficient of x, 1/5. Choice C has the same slope.
Show that Sin3xCos3x is the same as Sin 6x
The solution to the trigonometric equation is sin( 6x ) = 2sin(3x)cos(3x)
What are trigonometric relations?
Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles
The six trigonometric functions are sin , cos , tan , cosec , sec and cot
Let the angle be θ , such that
sin θ = opposite / hypotenuse
cos θ = adjacent / hypotenuse
tan θ = opposite / adjacent
tan θ = sin θ / cos θ
cosec θ = 1/sin θ
sec θ = 1/cos θ
cot θ = 1/tan θ
Given data ,
Let the equation be represented as A
Now , the value of A is
A = sin (6x)
From the trigonometric relations ,
The value of sin( 2x ) = 2sin(x)cos(x)
Now , when x is replaced by 6x
Substituting the values in the equation , we get
sin ( 6x ) = 2 sin ( 6x/2 ) cos ( 6x/2 )
On simplifying the equation , we get
sin ( 6x ) = 2 sin ( 3x ) cos ( 3x )
So , the value of the trigonometric relation is
sin(6x) = 2sin(3x)cos(3x)
Hence , the equation is sin(6x) = 2sin(3x)cos(3x)
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Find the present value of an annuity which pays ` 200 at the end of each 3 months for 10 years assuming
money to be worth 5% converted quarterly?
(a) ` 3473.86
(b) ` 3108.60
(c) ` 6265.38
(d) None of thes
The present value of the annuity is approximately `7032.08. The correct answer is option (d) None of these.
To find the present value of an annuity, we can use the formula:
PV = PMT * (1 - (1 + r)^(-n)) / r
Where PV is the present value, PMT is the periodic payment, r is the interest rate per period, and n is the number of periods.
In this case, the periodic payment is `200, the interest rate is 5% (or 0.05) converted quarterly, and the number of periods is 10 years, which equals 40 quarters.
Plugging in these values into the formula, we get:
PV = 200 * (1 - (1 + 0.05)^(-40)) / 0.05
Simplifying the equation, we find:
PV ≈ 200 * (1 - 0.12198) / 0.05
PV ≈ 200 * 0.87802 / 0.05
PV ≈ 35160.4 / 0.05
PV ≈ 7032.08
Therefore, the present value of the annuity is approximately `7032.08.
None of the provided answer options (a), (b), or (c) match this result. The correct answer is (d) None of these.
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En cierto laboratorio se cultiva la cepa de una bacteria, causal de múltiples problemas. Con fin de determinar la rapidez de reproducción de dicha bacteria, esta se coloca en un medio de crecimiento y condiciones favorables. La población existente es de 250 bacterias y se observa que cada hora se duplica la cantidad
The exponential function giving the number of bacteria after x hours is given as follows:
\(y = 250(2)^x\)
How to define an exponential function?An exponential function has the definition presented according to the equation as follows:
\(y = ab^x\)
In which the parameters are given as follows:
a is the value of y when x = 0.b is the rate of change.The parameter values for this problem are given as follows:
a = 250, b = 2.
Hence the function is given as follows:
\(y = 250(2)^x\)
Missing InformationThe problem asks for the exponential function giving the number of bacteria after x hours is given as follows:
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Christie makes changes to her budget at the end of every month. What is her reason for doing this in terms of smart financial planning?
A.
She keeps changing her mind about her goals.
B.
She is reviewing her goals and aligning the budget to work toward them.
C.
Her needs keep changing, so she changes her monthly budget.
D.
She realizes that her budget is tightly aligned to her goals.
The most appropriate reason for Christie making changes to her budget at the end of every month in terms of smart financial planning is B. She is reviewing her goals and aligning the budget to work toward them.Option B is correct.
Smart financial planning involves regularly evaluating and adjusting one's budget to ensure that it reflects their financial goals and current circumstances. By reviewing her goals, Christie can assess if her budget is still aligned with those goals and make any necessary changes to stay on track.
Life circumstances, such as changes in income, expenses, or financial priorities, may warrant adjustments to the budget. Christie recognizes that her needs may change over time, and by modifying her monthly budget, she can ensure that her financial resources are allocated appropriately to meet her evolving goals.
Regularly revisiting and modifying the budget allows Christie to adapt her financial plans, optimize her spending, and make informed decisions to achieve her financial objectives. Option B is correct.
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Match the coordinates with the points on the coordinate plane
Answer:
Step-by-step explanation:
\((-2\frac{1}{2},3\frac{1}{2})\)
Since, x-coordinate is negative and y-coordinate is positive, point will lie in the 2nd quadrant.
Answer is point P.
(-3, 6)
Point L represents the given coordinates.
\((-4\frac{1}{2},2)\)
Point P represents the given coordinates.
\((2\frac{1}{2},2\frac{1}{2})\)
Since, x and y coordinates are positive, point will lie in the 1st quadrant.
Point Q represents the given coordinates.
\((-1\frac{1}{2},-3\frac{1}{2})\)
Since, both x and y coordinates are negative, point will lie in the 3rd coordinate.
Point R represents the given coordinates.
If you vertically compress the square root parent function by a factor of 1/3, what is the equation of the new function?
9514 1404 393
Answer:
y = (1/3)√x
Step-by-step explanation:
Vertical scaling of a function is accomplished by multiplying the function by the scale factor. If you want to scale the square root function by a factor of 1/3, then the scaled function is ...
y = (1/3)√x
The four walls of a room including the doors and windows have to be painted.
The dimensions of the room are 5m x 5m x 6 m. Find the area to be painted.
Answer:
600
Step-by-step explanation:
5x5=25 25x6= 150x4 walls=600
Why should I probably get my first credit card from the same institution that has my checking and/or savings account?Because building a relationship with a financial institution makes good OA sense You should not. You should get your first card at one of those really cool OB. student websites. A better idea is to pick your credit card company based on which gift I like Oc the best. OD Because local institutions offer better gifts
I probably get my first credit card from the same institution that has my checking and/or savings account because that is the right thing to do.
What is a credit card?The credit card is a type of card that could be used to pay for utilities. The credit card is a thin plastic card that is issued by a person's financial institution and is recognized for financial transaction.
However, the credit car should be used with caution so that a person do not accumulate a lot of debt on the credit card that could lead to the bankruptcy of the individual that is using the cards in question.
Now, I probably get my first credit card from the same institution that has my checking and/or savings account because that is the right thing to do.
Learn more about credit card:https://brainly.com/question/27350251
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whats 2+2 will offer nothing
Answer:
4
Step-by-step explanation:
Find the equation of a line that passes through the point (2,-4) and has a gradient of -5. Leave your answer in the form y = m x + c
the slope goes by several names
• average rate of change
• rate of change
• deltaY over deltaX
• Δy over Δx
• rise over run
• gradient
• constant of proportionality
however, is the same cat wearing different costumes.
\((\stackrel{x_1}{2}~,~\stackrel{y_1}{-4})\hspace{10em} \stackrel{slope}{m} ~=~ - 5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{- 5}(x-\stackrel{x_1}{2}) \implies y +4= -5 (x -2) \\\\\\ y+4=-5x+10\implies {\Large \begin{array}{llll} y=-5x+6 \end{array}}\)