Answer:
8.29 mL
Explanation:
A researcher requests a sample of radioactive sodium,
24
Na, from the McMaster Nuclear Reactor. They want the sodium to be in the chemical form NaCl. The easiest way to prepare the sample is to irradiate NaCl in the reactor core. This creates both
24
Na and
38
Cl. The researcher does not want
38
Cl in the sample. However, the half-life of sodium is much longer than the chlorine. If the sample is left for long enough, the
38
Cl will decay, leaving only
24
Na. The sample is created by reactor staff. The half-life of
24
Na is 15 hours. The half-life of
38
Cl is 37.2 minutes. The activity of the
24
Na when the sample is removed from the core is 1MBq. The activity of the
38
Cl when the sample is removed from the core is 2.7MBq. Question 1 (Please answer with numbers only in the first answer box): To check things are working, the staff check the total NaCl sample activity, 2 hours after removal from the reactor core. To one decimal place, in units of MBq. what should the total activity of the sample at 2 hours after removal be? Question 2 (Please answer with numbers only in the second answer box): The sample is useful to the researcher when the 38Cl activity is 1% of the
24
Na activity. To the nearest minute, how many minutes after the sample comes out of the reactor core can it be given to the researcher?
The total activity of the sample two hours after removal from the reactor core is 0.7552 MBq. The sample can be given to the researcher 11 hours and 42 minutes after removal from the reactor core.
Question 1The total activity of the NaCl sample two hours after removal from the reactor core can be calculated using the equation of radioactive decay.
Activity = Initial activity × (1/2)t/h
where
Activity = activity at time t
Initial activity = activity at time zero
h = half-life
t = time
For Na-24, t = 2 hours, h = 15 hours, and initial activity = 1 MBq.
Activity of Na-24 after 2 hours= 1 × (1/2)2/15= 0.7552 MBq
Therefore, the total activity of the sample two hours after removal from the reactor core is 0.7552 MBq.
Question 2The activity of the Cl-38 after time t can be calculated using the equation below:
Activity of Cl-38 = Initial activity of Cl-38 × (1/2)t/h
where
Activity = activity at time tInitial activity = activity at time zeroh = half-life
t = time
For Na-24, t = 2 hours, h = 15 hours, and initial activity = 1 MBq.
For Cl-38, t = ?, h = 37.2 minutes (0.62 hours), and initial activity = 2.7 MBq.
The researcher wants the Cl-38 activity to be 1% of the Na-24 activity.
Activity of Cl-38 = 0.01 × activity of Na-24= 0.01 × 1= 0.01 MBq
Activity of Cl-38 = Initial activity of Cl-38 × (1/2)t/h0.01 = 2.7 × (1/2)t/0.62(1/2)t/0.62 = 0.01/2.7(1/2)t/0.62 = 0.0037037(1/2)t = log 0.0037037/ log 0.50.5t = 5.8546t = 11.7092 hours (to the nearest minute)= 11 hours 42 minutes
Therefore, the sample can be given to the researcher 11 hours and 42 minutes after removal from the reactor core.
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Which two correctly relate the attraction between the particles of a liquid and
the temperature at which the liquid changes state?
A. Strong attractions mean the liquid melts at a lower temperature.
B. Strong attractions mean the liquid boils at a lower temperature.
C. Strong attractions mean the liquid boils at a higher temperature.
O D. Strong attractions mean the liquid melts at a higher temperature.
Answer:
C & D
Explanation:
The attractive force between particles of a liquid determines the temperature at which the liquid changes state: the stronger the attraction, the larger amount of energy is required to break the bonds to boil; i.e. at a higher temperature. So C. Strong attractions mean the liquid boils at a higher temperature is correct.
By the same reasoning, the stronger attractive force between particles also means that it takes more energy to change state from solid to liquid; i.e. a higher melting point. So D. Strong attractions mean the liquid melts at a higher temperature is also correct.
1125 J of energy is used to heat 250 g of iron to 55 °C. The specific heat capacity of iron is 0.45 J/(g·°C).
What was the temperature of the iron before it was heated?
55 °C
55 °C
35 °C
35 °C
45 °C
45 °C
20 °C
Answer:
45 °C.
Explanation:
From the question given above, the following data were obtained:
Heat (Q) = 1125 J
Mass (M) = 250 g
Final temperature (T₂) = 55 °C
Specific heat capacity (C) = 0.45 J/gºC
Initial temperature (T₁) =?
The initial temperature of the iron can be obtained as illustrated below:
Q = MC(T₂ – T₁)
1125 = 250 × 0.45 (55 – T₁)
1125 = 112.5 (55 – T₁)
Divide both side by 112.5
1125/112.5 = 55 – T₁
10 = 55 – T₁
Collect like terms
10 – 55 = –T₁
–45 = –T₁
Multiply through by –1
45 = T₁
T₁ = 45 °C
Therefore, the initial temperature of the iron is 45 °C
a 1) How would you make 1 liter of a 10% NaCl solution from a solid stock? Provide details of what kind of containers you would use.
To make 1 liter of a 10% NaCl solution from a solid stock, you will require the following materials and containers.MaterialsSolid NaClDistilled water1-Liter volumetric flask250-mL volumetric flask 2-beakersProcedureTo prepare 1 liter of a 10% NaCl solution, the following procedure should be followed:Measure out 100g of NaCl using a balance.
Measure the weight of an empty 250-mL volumetric flask.Add the NaCl to a 250-mL beaker and add a small amount of distilled water to it to dissolve the NaCl.Carefully pour the dissolved NaCl solution into the 250-mL volumetric flask. Add distilled water to the mark on the flask to make up the volume. Stopper the flask and invert it several times to mix the solution.Measure the weight of the 1-Liter volumetric flask.Add the 250-mL volumetric flask solution to a 1-Liter volumetric flask.Add distilled water to the mark on the flask to make up the volume.
Stopper the flask and invert it several times to mix the solution.The final volume of the solution will be 1 liter of a 10% NaCl solution.PrecautionsEnsure the NaCl has completely dissolved before adding more water to avoid making a less concentrated solution.Measure the weight of the volumetric flask before and after adding the solution to calculate the volume of solution that was added.Use distilled water to prepare the solution.
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what is the average kinetic energy of 4.51 mol of a gas of molar mass 33.8 g/mol and rms speed 866 m/s
Answer:
A big load of icecream/ loaded cake.
Explanation:
Is Al2O3 an element or compound?
Al2O3, also known as aluminum oxide, is a chemical compound composed of aluminum and oxygen. It is a white crystalline substance that is commonly used in a variety of industrial and commercial applications, including as a abrasive material, a refractory material, and as a high-temperature insulator.
In chemistry, the term "element" refers to a pure substance made up of only one type of atom. A "compound" is a substance made up of two or more elements combined in a fixed ratio. Al2O3 is a compound because it is made up of two different elements, aluminum and oxygen, that are chemically bonded together.
The chemical formula for aluminum oxide, Al2O3, represents the ratio of atoms in the compound. The "2" in the formula represents the number of aluminum atoms, while the "3" represents the number of oxygen atoms. This means that for every two aluminum atoms, there are three oxygen atoms in the compound.
In conclusion, Al2O3 is a chemical compound and not an element because it is made up of two different elements combined in a fixed ratio.
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which of the following salts will be substantially more soluble in acidic solution than in pure water? (multiple answers are possible., choose all that apply. points deducted for incorrect choices. minimum score of zero.) group of answer choices pbcl2 al(oh)3 ba3(po4)2 agi fes hg2br2
Option A). The salts that will be substantially more soluble in an acidic solution than in pure water are PbCl₂, Al(OH)₃, and FeS.
1. Look for salts containing anions that can react with H+ ions from acidic solutions, making them more soluble. These anions include Cl-, OH-, S₂-, and PO₄₃-.
2. From the given choices, identify the salts containing these anions:
- PbCl₂ (contains Cl-)
- Al(OH)₃ (contains OH-)
- Ba₃(PO₄)₂ (contains PO₄₃-)
- FeS (contains S₂-)
3. Consider the cations' ability to form soluble complexes with the anions. Al₃+ and Fe₂+ can form soluble complexes with OH- and S₂-, respectively, while Pb₂+ can form soluble complexes with Cl-.
4. Based on this analysis, the salts that will be more soluble in acidic solutions are:
- PbCl₂
- Al(OH)₃
- FeS
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which of these interactions that hold hair strands together is/are ph sensitive? i. a salt bridge ii. a hydrogen bond iii. a disulfide linkage group of answer choices i, ii, and iii i and iii i and ii iii only i only
The interactions that hold hair strands together and are pH-sensitive are (iii) a disulfide linkage. The correct answer is "iii only".
Disulfide linkages are formed between sulfur atoms in the amino acid cysteine, which is present in the protein structure of hair. These linkages are responsible for the structural stability and strength of hair. When the pH of the hair is altered, such as through the use of chemical treatments or hair products, the disulfide linkages can be disrupted. This can lead to changes in the shape and texture of the hair. Therefore, the presence and integrity of disulfide linkages in hair are pH-sensitive. On the other hand, salt bridges and hydrogen bonds, mentioned in options (i) and (ii) respectively, are not directly pH-sensitive. Salt bridges are ionic interactions that can be influenced by pH indirectly through changes in ionization states of charged amino acids. Hydrogen bonds, while important for the structure of hair, are not directly affected by pH changes.
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using the data you acquired from the tube in the dish containing 0.05 m naoh, about how long did you predict it would take for glucose absorbed in the gut to diffuse to muscles in your foot
Using the data you acquired from the tube in the dish containing 0.05 M NaOH, predict it would take for glucose absorbed in the gut to diffuse to muscles in your foot is I: 8,000 minutes (about 133 hours).
Definition of Diffusion
Diffusion is a process resulting from the movement of molecules where the flow moves from an area of high concentration to an area of low concentration.
In this definition, the difference in concentration of two solutions is also known as a concentration gradient. Even though there is no difference in concentration, movement of molecules can still occur to reach equilibrium.
The process of diffusion also occurs in the human body. diffusion is the process of moving particles of a substance from a high concentration solution to a low concentration solution to achieve equilibrium.
An example of diffusion in the human body is when we inhale, the alveoli expand and oxygen enters the lungs. Then, when you exhale, the alveoli collapse and carbon dioxide leaves the body. Well, this process occurs because molecules move from high to low concentrations.
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which substance contains elements, chemically combined in a fixed proportion
The substance that contains elements chemically combined in a fixed proportion is called a compound.
In a compound, the elements are bonded together through chemical bonds such as ionic bonds, covalent bonds, or metallic bonds. The atoms in a compound are arranged in a specific and predictable manner, forming a unique chemical formula that represents the elemental composition of the compound.
For example, water (H2O) is a compound composed of two hydrogen atoms (H) and one oxygen atom (O). The ratio of hydrogen to oxygen in water is always 2:1. Regardless of the source or method of production, the ratio of hydrogen to oxygen atoms in water remains constant.
Similarly, sodium chloride (NaCl) is a compound made up of one sodium atom (Na) and one chlorine atom (Cl). The ratio of sodium to chlorine in sodium chloride is always 1:1.
The fixed proportion of elements in a compound is a fundamental characteristic of chemical compounds and is a result of the specific arrangement and bonding of the atoms within the compound. This fixed proportion allows compounds to have unique properties and behaviors that differ from those of the individual elements composing them.
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Name the sub atomic particles in part Z of a boron atom give the relative charges of these sub atomic particles
Answer:
Neutrons and protons
Explanation:
There are three fundamental subatomic particles, these are;neutrons protons and electrons.
Ernest Rutherford successfully showed that every atom does possess a central core that contain positively charged particles (protons) called the nucleus. Chadwick later discovered the existence of neutrons.
Both protons and neutrons are found in the nucleus. Z represents the nucleus of the boron atom and houses the neutrons and protons of the boron atom.
Can someone please help me with this, ill give you a heart, a five star rating, and the brainliest answer!
Answer:
A not
B yes
C yes
D yes
Explanation:
A 2C 6H but 10O and 7O so no
B 3C 6O 2Fe on each side so yes
C 4H 1S 6O 2Na so yes
D 2Ag 2Cl 1Ca 2N 6O so yes
Nowadays it is very important to reduce one's carbon "ootprint" (how much carbon we produce in our daly lifestyles). Mrimiting the use of fossal fuels and instead tosoring to renewable sourchis o ener
Nowadays, it is very important to reduce one's carbon "footprint" (how much carbon we produce in our daily lifestyles). By limiting the use of fossil fuels and instead turning to renewable sources of energy, we can significantly reduce our carbon emissions and mitigate the impacts of climate change.
One way to reduce our carbon footprint is by transitioning to renewable energy sources such as solar, wind, and hydropower. These sources of energy produce minimal greenhouse gas emissions compared to fossil fuels like coal, oil, and natural gas. Installing solar panels on rooftops, utilizing wind turbines, and supporting hydroelectric power can help generate clean and sustainable energy.
Another important aspect is adopting energy-efficient practices and technologies. This includes using energy-efficient appliances, LED lighting, and improving insulation in buildings to reduce energy consumption. Conserving energy in transportation by opting for public transportation, carpooling, biking, or walking can also make a significant difference.
Additionally, reducing waste and promoting recycling and composting can help minimize greenhouse gas emissions. Waste decomposition in landfills produces methane, a potent greenhouse gas. By reducing, reusing, and recycling materials, we can lower our carbon emissions and conserve resources.
Furthermore, making conscious choices in our daily lives can contribute to reducing our carbon footprint. This includes minimizing water usage, eating a plant-based diet or reducing meat consumption, and supporting sustainable and local products.
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Which of the following is not a unit of volume?
(A) L
(B) mL
(C) m^3
(D) cm^2
Answer:
D
Explanation:
write all the laws of thermodynamics.
8. Standard reduction potentials are given for reduction half-reactions relative to the hydrogen half-reaction. In Part 1 of this experiment, you will determine reduction potentials rela- tive to the reduction of copper and silver. Predict what the reduction potentials should be relative to the silver and copper electrodes. It may help to think of this as a vertical ruler. As you move the ruler up, the zero shifts up and the numbers change accordingly. E (volts) STANDARD REDUCTION POTENTIALS AT 25°C E (volts) E (volts) Referenced to Referenced to the Hydrogen the Copper Electrode Electrode Half-Reaction Referenced to the Silver Electrode 0.80 0.80 0.0 Ag+ + e + Ag (5) Cu2+ + 2e → Cu () 0.34 0.0 0,34 2H+ + 2e → H2(g) 0.0 Not measured Not measured Fe2+ + 2 e Fe (s) - 0.41 Zn2+ + 2e → Zn (5) - 0.76
The reduction potential of Cu²⁺ is 0.34 volts and the reduction potential of Ag⁺ is 0.8 volts
The reduction potentials of Ag⁺ and Cu²⁺ relative to the silver and copper electrodes, respectively, can be found by using a vertical ruler to shift the zero point of the reference hydrogen half-reaction.
Relative to the silver electrode, the reduction potential of Ag⁺ is 0.8 volts and
The reduction potential of Cu²⁺ is 0.0 volts.
Relative to the copper electrode, the reduction potential of Ag⁺ is 0.0 volts and
The reduction potential of Cu²⁺ is 0.34 volts.
The reduction potentials of the other half-reactions (Fe²⁺, Zn²⁺) cannot be measured relative to the silver and copper electrodes, as they are not included in the vertical ruler.
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in a 1 m solution of n2h4(aq) , arrange the species by their relative molar amounts in solution.you are currently in a ranking module. turn off browse mode or quick nav, tab to move, space or enter to pick up, tab to move items between bins, arrow keys to change the order of items, space or enter to drop.greatest amountleast amount
In a 1 molar solution of N2H4(aq), the species present in the solution are N2H4 and H2O.
To arrange them by their relative molar amounts in solution, we need to consider their stoichiometry.
The balanced chemical equation for the dissolution of N2H4 in water is:
N2H4(aq) + H2O(l) -> NH3(aq) + NH4OH(aq)
From the equation, we can see that 1 mole of N2H4 produces 1 mole of NH3 and 1 mole of NH4OH.
Therefore, the molar amounts of N2H4, NH3, and NH4OH in the solution are equal.
So, in a 1 molar solution of N2H4(aq), the relative molar amounts of species present in solution are:
- N2H4: greatest amount
- NH3: least amount
- NH4OH: least amount
Please note that the given question does not mention any other species, so we consider only N2H4, NH3, and NH4OH in our answer.
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Which change will cause gravitational force between and a soccer ball to increase?
Answer:
Moving the balls closer together. The distance decreases and force increases.
In the SN1 reaction of 2-chloro-2-methylpropane with water at different temperatures, the following reaction rate constants were obtained: 17°C, 0. 0052 s-1; 30°C, 0. 0202 s-1; 42°C, 0. 0608 s-1. Calculate the half-life of this reaction at 36°C. In seconds
The half-life of the reaction at 36°C is 19.2 seconds.
We can use the following equation to determine the half-life of the reaction at 36°C;
\(t_{1/2}\) = ln(2) / k
where \(t_{1/2}\) is the half-life of the reaction and k is the reaction rate constant at the given temperature.
First, we need to find the reaction rate constant at 36°C. We can use the two rate constants given for 30°C and 42°C and the Arrhenius equation;
ln(k₂/k₁) = (-Ea/R) × (1/T₂ - 1/T₁)
where k₁ and k₂ are the rate constants at temperatures T₁ and T₂, Ea will be the activation energy, R is gas constant, and T is temperature in Kelvin.
We can choose 30°C (303 K) as T₁ and 42°C (315 K) as T₂, and solve for ln(k₂/k₁) to get;
ln(k₂/k₁) = (-Ea/R) × (1/T₂ - 1/T₁)
ln(0.0608/0.0202) = (-Ea/8.314 J/(mol×K)) × (1/315 K - 1/303 K)
Ea ≈ 52.7 kJ/mol
Next, we can use the Arrhenius equation to find the rate constant at 36°C (309 K);
k = A × exp(-Ea/RT)
k = 0.0202 s⁻¹ × exp(-52.7 kJ/mol / (8.314 J/(mol×K) × 309 K))
k ≈ 0.036 s⁻¹
Finally, we can use the half-life equation with this rate constant to find the half-life at 36°C;
\(t_{1/2}\)= ln(2) / k
\(t_{1/2}\) = ln(2) / 0.036 s⁻¹
\(t_{1/2}\) ≈ 19.2 s
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PLEASE HELP ME QUICKLY (select all that apply) Enzymes made by extremophiles can be harvested and used in everyday applications. These uses include
making laundry detergents.
making dish detergents.
recycling old tires.
de-hairing hides.
making paper.
Answer:
A, B, D, E
Explanation:
did it on edg
Answer:
A. Making laundry detergent
B. Making dish detergent
D. De-hairing hides
E. Making paper
Explanation:
Write the complete and net ionic equations for the following reactions. If only the reactants are given, predict the products and balance the equation first.
Explanation:
u can put them in order crossed are spectator ions. hope this helps:)
what is a mixture of elements and compounds
The substance in the image above would be classified as a mixture of elements (option E).
What is a compound and mixture?A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.
On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.
According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.
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Express the dosage using the ratio format you prefer. (Use mg for milligrams and mL for an injectable solution that contains 250mg in each 0.6 mL 3. [-/3 Points] CURRENMEDMATH11 12.3.002. EP. Consider the following. A 40mg in 2.5 mL solution will be used to prepare a 26mg dosage. Calculate the dosage using ratio and proportion. Express your final answer in mL to the
40mg
mL
=
X mL
26mg
40x
X
=
=
mL
[-/1 Points] CURRENMEDMATH11 12.3.004. Calculate the dosage (in milliliters). Express your answer to the nearest tenth. Assess y A 36mg per 2 mL strength solution is used to prepare 22mg. mL
The dosage of 26mg can be prepared using approximately 1.625 mL of the 40mg in 2.5 mL solution.
The dosage of 22mg can be prepared using approximately 1.222 mL of the 36mg per 2 mL strength solution.
To calculate the dosage using ratio and proportion, we can set up a proportion based on the strength of the solution.
40mg in 2.5 mL solution will be used to prepare a 26mg dosage.
Let X represent the mL of the solution needed to prepare the 26mg dosage.
We can set up the proportion as follows:
40mg/2.5mL = 26mg/X mL
Cross-multiplying and solving for X, we have:
40mg * X mL = 2.5mL * 26mg
40X = 65
X = 65/40
X ≈ 1.625 mL
For the second question:
36mg per 2 mL strength solution is used to prepare 22mg.
Let Y represent the mL of the solution needed to prepare the 22mg dosage.
We can set up the proportion as follows:
36mg/2mL = 22mg/Y mL
Cross-multiplying and solving for Y, we have:
36mg * Y mL = 2mL * 22mg
36Y = 44
Y = 44/36
Y ≈ 1.222 mL
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What happens to the tape at the closer markers compared to the markers that are further away?
What contribution to atomic theory resulted from Albert Einstein's work?
O A. A new understanding that the nucleus contained protons and
neutrons
O B. A new understanding of what caused some elements to be
radioactive
O C. The discovery that different numbers of neutrons produced
isotopes
OD. A new model of the atom that described electrons as being in a
cloi
Answer:
a new model of the atom that describe electrons as being in a cloud
Explanation:
Barium chloride emits a green color when flame tested. What can be said about the wavelength of light it emits?
The complete question is as follows: Barium chloride (BaCl2) emits a green color when flame tested. What can be said about the wavelength of light it emits? Select all that apply.
A) The thermal energy is transferred to the outer electrons of the barium ions.
B) The electrons gain enough energy to excite them to a higher energy level.
C) The electrons drop back down to their ground state, gaining energy.
D) The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Answer: The following can be said about the wavelength of light that Barium chloride emits:
The thermal energy is transferred to the outer electrons of the barium ions. The electrons gain enough energy to excite them to a higher energy level.The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.Explanation:
As barium chloride is emitting green color when flame tested. This means that thermal energy is being transferred to the outer electrons of barium ions.
A visible light is emitted by a substance when its electrons move from a region of higher energy level to lower energy level. This is because energy is given off by the electrons when they move in a lower region.
This is only possible when the electrons gain enough energy to excite them to a higher energy level.
Also, the electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.
Thus, we can conclude that following can be said about the wavelength of light that Barium chloride emits:
The thermal energy is transferred to the outer electrons of the barium ions. The electrons gain enough energy to excite them to a higher energy level.The electrons release energy emitting a wavelength of 500-560 nm, corresponding to a green light, when going back to their ground state.The angular momentum of an electron will be:
The angular momentum of an electron is the product of its mass, velocity and radius of orbit mvr. This is equivalent to nh/2π.
What is angular momentum ?Angular momentum is the rotational analogue of linear momentum. The momentum of a moving object is the ability to bring the force acting on it make the maximum displacement.
Momentum is the product of mass and velocity. According to Bohr theory of atom, the angular momentum , that is the momentum associated with an object moving through a circular path is the product of radius of the path and linear momentum.
Linear momentum = mv
angular momentum = mv r.
Hence, the angular momentum of an electron is mvr.
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Answer:
Perpendicular to its orbit
Explanation:
The angular momentum of an object in circular motion, whether an electron or a macroscopic object, will be perpendicular to the plane of circular motion.
9. Name the element which has the following numbers of particles:
I
A. iron
B. iodine
C. Helium
D. calcium
E. lead
F. hydrogen
check your periodic table to see if they are correct
atomic number, proton number and electron are the same
to find neutron = mass number - atomic number
Devise a 6‑step synthesis of the starting material from the product. The cyclopentene is a key intermediate.
Cyclopentene is industrially produced in large quantities. It is used as a monomer for the synthesis of plastics, in addition to other chemical syntheses.
The 6‑step synthesis of the starting material from the productReaction 1 - Preparation of keto-aldehyde
Reaction 2 - Preparation of cyclopentene carbaldehyde
Reaction 3 -Preparation of α,β-epoxy-carbaldehyde cyclopentane
Reaction 4 - Preparation of cyclopentene alcohol
Reaction 5 -Preparation of α,β-epoxy-cyclopentane alcohol
Reaction 6 -Preparation of α,β-epoxy-carbaldehyde cyclopentane
With this information we can conclude that cyclopentene is used as a monomer for the synthesis of plastics.
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calculate the mass (in grams) of khp required to react completely with the naoh in 35 ml of 0.100m naoh (see
The mass (in grams) of KHP required to react completely with the NaOH in 35 ml of 0.10 M NaOH is:0.71 g.
Firstly Calculate the number of moles of KPH required and convert to grams.
First, we need to determine how many moles of NaOH we have. We have 35 mL of a 0.10 M NaOH solution.
M = moles/liter, so we have a 0.10 mole/liter solution in 35 mL.
We get 35 mL x 1 L/1000 mL = 0.035 L when we convert mL to liters.
To calculate the number of moles, multiply the number of liters by the moles/liter: 0.035 L x 0.10 moles/L = 0.0035 moles NaOH
We know we need 0.0035 moles KPH because our reaction equation above says we need 1 mole of KPH for every mole of NaOH.
We must now convert moles of KPH to grams of KPH. According to the problem, the molecular mass of KPH is 204 g/mol.
To calculate the number of grams, multiply the number of moles by the molecular mass:
0.0035 moles KPH * 204g/mol = 0.71 g KPH
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