What is the volume in liters occupied by 9.02 g of Freon-12 gas, CCl2F2, at 0.940 atm and 35°C?

Answer:

1.379 M

Explanation:

The computation of the molarity of a solution is as follows;

As we know that

Molarity(M) = number of moles of solute ÷  volume of solution ( in L )

Given that

Mass = 10 grams

Molar mass of acetone(C3H6O) = 58 g/mol

moles = mass ÷ molar mass

= 10 g ÷ 58 g/mol

= 0.172414 mol

Now the molarity of the solution is  

Volume of solution = 125 mL = 0.125 L

As

1 L = 1000 mL

so,

125 mL = (125 mL  × ( 1 L ÷ 1000 mL) = 0.250 L)

Now the molarity is

= 0.172414 mol  ÷ 0.125 L

= 1.379 M

The values of Δs for the water, the surroundings, and the universe for the evaporation of water from an open pan at 25°c is Positive, Negative, Positive.

What is spontaneous process?

A spontaneous process in thermodynamics is one that happens without the system receiving any outside input.

According to the second law, a spontaneous process,

ΔS\(universe > 0\)

As it transitions from a liquid to a gaseous form, water. Entropy changes in favor whenever a phase transition occurs from a liquid to a gas,

So ΔS \(water > 0\)

The amount of thermal energy required to cause water to evaporate is determined by multiplying the molar enthalpy of vaporization by the amount of evaporating water in moles. The surrounding provides this thermal energy,

So Δq \(surroundings < 0\).

We know that: As long as this thermal energy is transferred reversibly,

\(Delta S surr = Delta q surr/T\)

T is always positive since it is being measured in kelvins, which is the thermodynamic scale. The fact that

\(Delta q surr < 0 so Delta S surr < 0.\)

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Answer:

an ecosystem

Explanation:

it compromises of living and non living things in an environment.

The experiment on determining the effect of soil type on plant growth can be improved by controlling variables such as the amount of sunlight and the pH of water.

Option 1, "Change the amount of water given to each plant," is not a way to improve the experiment because it introduces a new variable that can affect plant growth. If the student wants to test the effect of soil type, then the plants should receive the same amount of water, which is enough to keep the soil moist, but not so much that it causes waterlogging.

Option 2, "Make sure the plants receive the same amount of sunlight," is a way to improve the experiment because sunlight is a factor that can affect plant growth, and therefore, it is important to control the amount of sunlight that each plant receives.

Option 3, "Make sure the plants receive water with the same pH," is also a way to improve the experiment because the pH of water can affect plant growth, and therefore, it is important to keep the pH of water the same for all plants.

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Answer:

ь

They slow down

Explanation:

The mass of the marshmallow is 10.9 g.

The mass of a substance is the quantity of matter present in that substance.

The volume of a substance is the amount of space a given mass of that substance occupies.

The density of a substance is the ratio of the mass and a given volume of that substance.

Therefore, the relationship between mass, volume and density is given below as:

From the data provided:

volume of the marshmallow = 2.75 in³

1 inch³ = 16.39 cm³

volume in cm³ = 16.39 * 2.75

volume of the marshmallow = 45.07 cm³

density of the marshmallow = 0.242 g/cm³

Mass of the marshmallow = volume × density

Mass of the marshmallow = 0.242 g/cm³ * 45.07 cm³

Mass of the marshmallow = 10.9 g

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Time increases as the volume of hydrochloric acid remains the same. This is because the concentration of hydrochloric acid would remain constant, affecting the reaction rate. Option B

Based on factors that affect the rates of chemical reactions, the expected trend in the table can be analyzed.

In this experiment, calcium carbonate reacts with hydrochloric acid to produce carbon dioxide gas. The reaction rate is influenced by factors such as concentration, surface area, temperature, and presence of a catalyst. Let's examine the options provided:

A. Time increases as the volume of hydrochloric acid decreases:

This option suggests that as the volume of hydrochloric acid decreases, the time taken for carbon dioxide to form increases. However, in general, a decrease in the volume of hydrochloric acid would result in an increase in its concentration.

B. Time increases as the volume of hydrochloric acid remains the same:

If the volume of hydrochloric acid remains the same, it means the concentration of hydrochloric acid is constant. In this case, the reaction rate is not expected to change significantly, and the time taken for carbon dioxide to form should remain relatively constant. Therefore, this option is plausible.

C. Time decreases as the mass of calcium carbonate decreases:

If the mass of calcium carbonate decreases, the surface area of the reactant particles decreases. A smaller surface area would result in less contact between reactant particles, leading to a slower reaction rate. Thus, the time taken for carbon dioxide to form would be expected to increase, making this option unlikely.

D. Time decreases as the mass of calcium carbonate remains the same:

If the mass of calcium carbonate remains the same, the surface area of the reactant particles also remains the same. Therefore, the reaction rate should remain relatively constant, and the time taken for carbon dioxide to form would not show a significant change. Thus, this option is also plausible.

Option B is correct.

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Answer:

If you add the masses of all the products after fission, they are LESS than the mass of the reactants.

Explanation:

A nuclear fission reaction is a radioactive reaction which in which a heavy nucleus spontaneously disintegrates into 2 lighter nuclei and some neutrons with a release of large amount of energy.

When nuclear fission occurs, a mass deficit between the decaying nuclei and the product occurs. It is this mass that actually yields the energy that is produced as a by product of the reaction.

In the given Galvanic cell, the electrons are flowing from left to right. The Zinc is oxidized into Zn²⁺ ions.

A galvanic cell can be described as an electrochemical cell in which electricity is produced from spontaneous Oxidation-Reduction reactions. Galvanic cells exhibit spontaneous redox reactions but the energy generated from the said reaction.

A common apparatus of the galvanic cell consists of two different metals or electrodes such as Zinc and copper electrodes, each immersed in different beakers containing their respective ion solution. Therefore, the Zinc electrode is placed in ZnSO₄ solution and the copper electrode is placed in CuSO₄ solution.

On the left end, the zinc metal is oxidized into Zn²⁺ ions, and the electrons from the Zinc electrode travel to the copper electrode (right end). The cooper Cu²⁺ ions from the CuSO₄ solution accepts those electrons and deposit as copper metal on the copper electrode.

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Answer:

pH = 7.30

Explanation:

You can find the pH using the following equation:

pH = -log[H⁺]

In this equation, [H⁺] represents the hydrogen ion concentration. You can plug the given value into the equation and solve to find the pH.

pH = -log[H⁺]

pH = -log[5 x 10⁻⁸]

pH = 7.30

Answer:

Water

Explanation:

Mass of fluid is 145 - 45 g

                     = 100 g

Density of liquid:

\(\frac{\text{mass of liquid}}{\text{volume of liquid}}\)

Plug in:

\(\frac{100\text{mg}}{100\text{ml}}\)

\(\frac{1\text{g}}{1\text{ml}}\)

 = \(1 \text{g}/{\text{ml}\)

We know that 1 ml = 1 \(cm^3\)

But density of water is 1 g/cc [at 20 degree Celsius]

Therefore, the answer is option B.

Answer:

oxygen

Explanation:

Answer:

Using the dilution equation, we can solve for the initial volume required. We need 18.75 mL of 2.0 M NaCl solution.

Explanation:

Answer:

c

Explanation:

it goes in lowest energy orbital

MnO4- + 4e- → MnO2 + 2H2O Now the half-equation is balanced in alkaline medium.

To balance the half-equation MnO4- → MnO2 in alkaline medium, we need to follow the steps for balancing redox reactions in basic solution. The goal is to balance the number of atoms and charges on both sides of the equation.

Start by balancing the atoms other than oxygen and hydrogen. In this case, we only have manganese (Mn) atoms. There is one Mn atom on both sides, so the Mn atoms are already balanced.

Balance the oxygen atoms by adding water (H2O) molecules to the side that lacks oxygen. Since there are four oxygen atoms on the left side (MnO4-) and only two on the right side (MnO2), we need to add two water molecules to the right side:

MnO4- → MnO2 + 2H2O

Next, balance the hydrogen atoms by adding hydrogen ions (H+) to the side that lacks hydrogen. In this case, the left side (MnO4-) already has sufficient hydrogen atoms, so no hydrogen ions need to be added.

Balance the charges by adding electrons (e-) to the side that has a higher charge. MnO4- has a charge of -1, while MnO2 has no charge. Since the left side has a higher charge, we need to add electrons to the right side:

MnO4- + 4e- → MnO2 + 2H2O

Now the half-equation is balanced in alkaline medium. The Mn atoms, oxygen atoms, hydrogen atoms, and charges are all balanced. The addition of water and hydrogen ions helps balance the oxygen and hydrogen atoms, while the addition of electrons balances the charges.

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Answer:

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Answer:potassium is more reactive than Mg because both lie in the same group and the element potassium has more electropositivity than magnesium

Explanation:

I hope it will help you

Answer: B. Potassium(K)

Explanation:

Answer:

\(V=23.5L\)

Explanation:

Hello,

In this case, it is convenient to compute the car's mileage in km/L as follows:

\(25.0\frac{mi}{gal}*\frac{1km}{0.6214mi}*\frac{1gal}{3.78L}=10.64\frac{km}{L}\)

In such a way, since the distance is measured to be 250 km, the volume requirement is:

\(V=\frac{250km}{10.64kg/L}\\ \\V=23.5L\)

Regards.

Using the concentration equation, m = CVMo where m is the mass of solute, C is the concentration (M), V is the volume of solution (L) and Mo is molar mass of the solute (g):

Given,

Molar mass of NaCl, M = 58.5g/mol

Volume of the solution, V= 100ml = 0.1L

Molarity, S= 1M

Mass of the solute,W=?

W=SMV

= 1×58.5×0.1

= 5.85g

Answer:

Lead

that can be found in the periodic table of elements

Explanation:

9.02 g of Freon-12 gas occupies a volume of approximately 2.424 liters at 0.940 atm and 35°C.

To determine the volume of Freon-12 gas (CCl2F2) at the given conditions 9.02 g of Freon-12 gas occupies a volume of approximately 2.424 liters at 0.940 atm and 35°C.

The ideal gas law equation can be used to calculate the volume of Freon-12 gas (CCl2F2) at the given conditions:

PV = nRT

Where:

P = atmospheric pressure

V = litres = volume

n = the number of moles.

R is the ideal gas constant (0.0821 Latm/(molK)).

T = Kelvin temperature

We must first convert the supplied temperature from Celsius to Kelvin:

T(K) = 35°C + 273.15 = 308.15 K

Using the molar mass of Freon-12, we can then compute the number of moles:

CCl2F2 molar mass = (1 12.01 g/mol) + (2 35.45 g/mol) + (2 19.00 g/mol) = 120.91 g/mol

Mass / molar mass = number of moles

The number of moles is equal to 9.02 g / 120.91 g/mol = 0.0746 mol.

We can now plug these values into the ideal gas law equation:

PV = nRT

(nRT) / P V = (0.0746)mol * 0.0821 L·atm/(mol·K) * 308.15 K) / 0.940 atm

V = 2.424 L

Therefore, 9.02 g of Freon-12 gas occupies a volume of approximately 2.424 liters at 0.940 atm and 35°C.

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It's never a good idea to use your credit card when experiencing strong emotions, especially if you tend to steer toward 'retail therapy.

The following are categorized into polar or nonpolar molecules:

a) Beryllium chloride (BeCl₂) is a nonpolar molecule. The Be-Cl bond is polar due to the electronegativity difference between beryllium and chlorine, but the molecule is linear with the two polar bonds pointing in opposite directions, resulting in a net dipole moment of zero.

b) Hydrogen sulphide (H₂S) is a polar molecule. The H-S bond is polar due to the electronegativity difference between hydrogen and sulfur, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.

c) Sulphur trioxide (SO₃) is a nonpolar molecule. The S-O bonds are polar due to the electronegativity difference between sulfur and oxygen, but the molecule is trigonal planar with the three polar bonds pointing in different directions, resulting in a net dipole moment of zero.

d) Water (H₂O) is a polar molecule. The H-O bond is polar due to the electronegativity difference between hydrogen and oxygen, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.

e) Trichloromethane (CHCl₃) is a polar molecule. The C-Cl bonds are polar due to the electronegativity difference between carbon and chlorine, and the molecule has a tetrahedral shape, resulting in a net dipole moment that is not zero.

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The expression 7.0x\(10^7\) ÷ 2.0x\(10^4\) can be expressed in proper scientific notation as 3.5x10^3.

To express the division 7.0x\(10^7\) ÷ 2.0x\(10^4\) in proper scientific notation, we need to perform the division and adjust the result to the appropriate format.

Dividing the numbers, we get:

7.0x\(10^7\) ÷ 2.0x\(10^4\)= 3.5x\(10^{(7-4)\)= 3.5x\(10^3\)

The result of the division is 3.5, and we adjust the exponent by subtracting the exponent of the divisor from the exponent of the dividend (7 - 4 = 3).

Therefore, the proper scientific notation representation of the division 7.0x\(10^7\) ÷ 2.0x\(10^4\) is 3.5x\(10^3\).

Scientific notation is a way to express numbers using a coefficient (in this case, 3.5) multiplied by a power of 10 (in this case, 10^3). It allows for more concise representation of very large or very small numbers.

In this case, the division resulted in a number that is smaller than the dividend and has a positive exponent, indicating a smaller magnitude compared to the original numbers. The coefficient represents the significant digits of the result, while the power of 10 represents the scale or magnitude of the number.

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From the given choice of substances, the one that is not a molecule is Mn.

Molecules are defined as the smallest unit of a substance that can exist and still retain the properties of that substance.

Molecules of substance are usually formed from the atom of the substances when two or more atoms of the same elements or different elements combine.

Molecules of substances are capable of existing alone but atoms of an element must combine to form molecules.

Considering the given substance to determine whether they are molecules or not:

H₂S is a molecule because it contains more than one atom of elements.

O₃ is a molecule because it contains more than one atom of elements.

KOH is a molecule because it contains more than one atom of elements.

Mn is a not molecule because it contains only one atom of elements.

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The expression for the volume of liquid flowing per unit time through the cylindrical tube is (π∆P\(r^4\))/(8ηl) ∆t.

To derive an expression for the volume of liquid flowing per unit time through a cylindrical tube, we can apply the principles of fluid mechanics, considering the pressure gradient, viscosity coefficient, and tube radius.

The volume flow rate (Q) is defined as the volume of fluid passing through a cross-sectional area per unit time. In this case, we will consider the flow through a cylindrical tube of radius r and length l.

The Hagen-Poiseuille equation describes the flow rate in terms of the pressure gradient (∆P), viscosity coefficient (η), and tube dimensions:

Q = (π∆P \(r^4\))/(8ηl)

where k = π/8 is a constant.

To derive the expression for the volume of liquid flowing per unit time (∆V/∆t), we need to multiply the flow rate (Q) by the time interval (∆t):

∆V/∆t = Q ∆t

= (π∆P \(r^4\))/(8ηl) ∆t

Now, if we assume a constant pressure difference (∆P) and substitute k = π/8, the expression becomes:

∆V/∆t = (k∆P \(r^4\))/(ηl) ∆t

Simplifying further:

∆V/∆t = (π∆P\(r^4\))/(8ηl) ∆t

So, the expression for the volume of liquid flowing per unit time through the cylindrical tube is (π∆P \(r^4\))/(8ηl) ∆t.

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The solubility of Ca(OH)2 in a 0.469M CaCl2 solution at 31°C, at given Ksp of Ca(OH)2 is determined as 1.626 mM.

The dissociation reaction of Ca(OH)2 is given as follows;

Ca(OH)₂  ⇄ Ca²⁺  + 2OH⁻¹

                     x           2x

Concentration of Ca²⁺ = 0.469 M

Ksp = [x][2x]²

ksp = (0.469)(2x²)

ksp = 4(0.469)x²

ksp = 1.876x²

4.96 x 10⁻⁶ = 1.876x²

x² = (4.96 x 10⁻⁶)/(1.876)

x² = 2.643 x 10⁻⁶

x = √(2.643 x 10⁻⁶)

x = 1.626 x 10⁻³ M

x = 1.626 mM

Thus, the solubility of Ca(OH)2 in a 0.469M CaCl2 solution at 31°C, at given Ksp of Ca(OH)2 is determined as 1.626 mM.

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