what is the value of x? x+3=8

the answers would be x = 1 and x = -2/3.

Step-by-step explanation:

3x + 3 × 5 = 18

3x + 15 = 18

3x = 18 - 15

3x = 3

x = 3/3

x = 1

Answer:

(136.60 - 61.60) / 30 = 2.5 hours

Step-by-step explanation:

First, subtract the cost of parts from the total: 136.60 - 61.60 = 75

Now you have the total labor cost. Divide by the hourly rate: 75 / 30 = 2.5

The area of waffle in the cone is the amount of space covered by the waffle

The cone has 5630 square millimeter of waffle

The surface area of a cone is calculated using:

A = πr * (r+\(\sqrt{\)(h^2 + r^2))

For the complete 72 mm tall cone, we have:

Height (h) = 72 mm

Radius (r) = 42 mm/2 = 21 mm

So, the surface area is:

A = πr * (r+\(\sqrt{\)(h^2 + r^2))

A = 3.142 * 21 * (21+\(\sqrt{\)(72^2 + 21^2))

Evaluate

A = 3.142 * 21 * (21+75)

A = 6334.272

When the cone is cut at the top, we have:

Height (h) = 24 mm

Radius (r) = 14 mm/2 = 7 mm

So, the surface area is:

A = πr * (r+\(\sqrt{\)(h^2 + r^2))

A = 3.142 * 7 * (7+\(\sqrt{\)(24^2 + 7^2))

Evaluate

A = 3.142 * 7 * (7 + 25)

A = 703.808

Calculate the difference (d) between the areas

d = 6334.272 - 2.5*703.808

Evaluate

d = 5630.464

Approximate

d = 5630

Hence, the cone has 5630 square millimeter of waffle

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Answer:

43.98

Step-by-step explanation:

The circumference of a circle with a radius of 7 units is approximately 43.98 units, which corresponds to option A.

The Circumference of a circle is defined as the product of the diameter of the circle and pi.

Given that the radius of the circle is 7 units, we can substitute this value into the formula:

To find the circumference of a circle, we can use the formula C = 2πr, where C represents the circumference and r represents the radius.

C = 2π(7) = 14π

Use the approximation π ≈ 3.14:

C ≈ 14(3.14) = 43.96

Rounding this value to the nearest hundredth, we get approximately 43.98 units.

Therefore, the circumference of a circle with a radius of 7 units is approximately 43.98 units.

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A product analyst has evaluated four potential statistical forecasting methods. D) Bias=.2; MAD=3 is the provide the most accurate forecast. The option d is correct.

To determine which method would provide the most accurate forecast, we need to look at both bias and mean absolute deviation (MAD).  

Based on the given information, the method with the lowest MAD is option D, with a MAD of 3. This indicates that, on average, the forecasted values are closest to the actual values using this method.

However, we also need to consider bias. A positive bias means that the forecasted values are consistently higher than the actual values, while a negative bias means that the forecasted values are consistently lower than the actual values. Ideally, we want a bias as close to 0 as possible.

Option D has a bias of 0.2, which is relatively low and indicates that the forecasted values are only slightly higher than the actual values on average. Therefore, option D would provide the most accurate forecast based on the given information.  Correct answer is option D

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we dunno, hmmm let's check for the slope for PQ

\(P(\stackrel{x_1}{-8}~,~\stackrel{y_1}{-10})\qquad Q(\stackrel{x_2}{-5}~,~\stackrel{y_2}{-12}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-12}-\stackrel{y1}{(-10)}}}{\underset{\textit{\large run}} {\underset{x_2}{-5}-\underset{x_1}{(-8)}}} \implies \cfrac{-12 +10}{-5 +8} \implies \cfrac{ -2 }{ 3 } \implies - \cfrac{2 }{ 3 }\)

keeping in mind that perpendicular lines have negative reciprocal slopes, then if both are truly perpendicular, then line RS will have a slope of

\(\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{ \cfrac{-2}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-2}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-2} \implies \cfrac{3}{ 2 }}}\)

let's see if that's true

\(R(\stackrel{x_1}{9}~,~\stackrel{y_1}{-6})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{-5}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-5}-\stackrel{y1}{(-6)}}}{\underset{\textit{\large run}} {\underset{x_2}{17}-\underset{x_1}{9}}} \implies \cfrac{-5 +6}{8} \implies \cfrac{ 1 }{ 8 } ~~ \bigotimes ~~ \textit{not perpendicular}\)

Answer:

Step-by-step explanation:

No they are not perpendicular.

Perpendicular lines have slopes that are negative reciprocals of each other.

PQ slope = -12 - -10/-5 --8 = -2/3

RS slope = -5 - -6/17 -9 = 1/8

Slope are not negative reciprocals - the lines are not perpendicular.

Slope formula is m = y2 - y1/x2 - x1

Use this to determine slope.

For example if the the slope of RS was 3/2 - the lines would be perpendicular.

My sample will include people who are  older. I will survey those people through an online survey that I will send out email or post

I will use targeted ads on social media platforms ,I will also use search engine optimization (SEO)to ensure that my survey is seen by the right people. The survey will be conducted over a  two weeks. In order to ensure that I get a representative sample of people, I will use demographic and psychographic targeting. This will include targeting people based on their age, gender, location, interests, and other relevant characteristics. My sample will include people who are  older. I will survey those people through an online survey that I will send out email or post

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Answer:

x=-3

Step-by-step explanation:

Let's solve your equation step-by-step.

−7+2(−4x−3)=11

Step 1: Simplify both sides of the equation.

−7+2(−4x−3)=11

−7+(2)(−4x)+(2)(−3)=11(Distribute)

−7+−8x+−6=11

(−8x)+(−7+−6)=11(Combine Like Terms)

−8x+−13=11

−8x−13=11

Step 2: Add 13 to both sides.

−8x−13+13=11+13

−8x=24

Step 3: Divide both sides by -8.

−8x

−8

=

24

−8

x=−3

The function y = \(3x^3 - 3\) is a non linear function.

A linear function is a function that can be expressed in the form y = mx + b. where m and b are constants and x and y are variables. In other words, a linear function has a constant slope and is a straight line when graphed.

However, the function y = \(3x^3 - 3\)  does not have a constant slope and does not plot as a straight line.

is a cubic function, has degree 3, and its graph has a characteristic S-shape. So this is a non-linear function.

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Answer:

The correct option is (a) 3759.

Step-by-step explanation:

The complete question is:

The natural resources of an island limit the growth of the population. The population of the island is given by the logistic equation \(P(t)=\frac{3759}{1+3.94e^{-0.38t}}\)where t is the number of years after 1980. What is the limiting value of the population?

(a) 3759

(b) 23

(c) 761

(d) 1017

Solution:

The limiting value is the value of the function P (t) for t → ∞.

As t → ∞, the expression \((3.94e^{-0.38t})\) → 0.

Thus, making the denominator of P (t) 1.

So, the limiting value of the population is, 3759.

Thus, the correct option is (a) 3759.

The results obtained using the algebraic approach and the matrix approach should be the same. Both methods are mathematically equivalent and provide the most probable values of A and B that minimize the sum of squared weighted residuals.

To solve the system of equations using the weighted least squares method, we need to minimize the sum of the squared weighted residuals. Let's solve the problem using both the algebraic approach and matrices.

Algebraic Approach:

We have the following equations:

A + 2B = 10.50 + V1 ... (1)

2A - 3B = 5.55 + V2 ... (2)

2A - B = -10.50 + V3 ... (3)

To minimize the sum of squared weighted residuals, we square each equation and multiply them by their respective weights:

\(2^2 * (A + 2B - 10.50 - V1)^2\)

\(3^2 * (2A - 3B - 5.55 - V2)^2\\1^2 * (2A - B + 10.50 + V3)^2\)

Expanding and simplifying these equations, we get:

\(4(A^2 + 4B^2 + 10.50^2 + V1^2 + 2AB - 21A - 42B + 21V1)\\9(4A^2 + 9B^2 + 5.55^2 + V2^2 + 12AB - 33A + 16.65B - 11.1V2)\\(A^2 + B^2 + 10.50^2 + V3^2 + 2AB + 21A - 21B + 21V3)\\\)

Now, let's sum up these equations:

\(4(A^2 + 4B^2 + 10.50^2 + V1^2 + 2AB - 21A - 42B + 21V1) +\\9(4A^2 + 9B^2 + 5.55^2 + V2^2 + 12AB - 33A + 16.65B - 11.1V2) +\\(A^2 + B^2 + 10.50^2 + V3^2 + 2AB + 21A - 21B + 21V3)\int\limits^a_b {x} \, dx\)

Simplifying further, we obtain:

\(14A^2 + 31B^2 + 1113 + 14V1^2 + 33V2^2 + 14V3^2 + 14AB - 231A - 246B + 21V1 - 11.1V2 + 21V3 = 0\)

Now, we have a single equation with two unknowns, A and B. We can use various methods, such as substitution or elimination, to solve for A and B. Once the values of A and B are determined, we can substitute them back into the original equations to find the most probable values of A and B.

Matrix Approach:

We can rewrite the system of equations in matrix form as follows:

| 1 2 | | A | | 10.50 + V1 |

| 2 -3 | | B | = | 5.55 + V2 |

| 2 -1 | | -10.50 + V3 |

Let's denote the coefficient matrix as X, the variable matrix as Y, and the constant matrix as Z. Then the equation becomes:

X * Y = Z

To solve for Y, we can multiply both sides of the equation by the inverse of X:

X^(-1) * (X * Y) = X^(-1) * Z

Y = X^(-1) * Z

By calculating the inverse of X and multiplying it by Z, we can find the values of A and B.

Comparing Results:

The results obtained using the algebraic approach and the matrix approach should be the same. Both methods are mathematically equivalent and provide the most probable values of A and B that minimize the sum of squared weighted residuals.

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Answer:

b, c, d.

Step-by-step explanation:

Statements 2) Line SW has an undefined slope, 3)Line TV has a slope of 0, and 4) Lines RS and TV are parallel are correct.

It is given that there are three lines RS, TV, and SW.

Line RS goes through (-8, 6) and (2, 6).

Line TV goes through (-6, -4) and (8, -4).

Line SW goes through (2, 6) and (2,-8).

It is required to find true statements.

Statements are:

A straight line is a combination of endless points joined on both sides of the point.

The slope 'm' of any straight line is given by:

\(m=\frac{y_{2}-y_{1}}{{x_{2}-x_{1}}}\)

Where \((x_{1}, y_{1}) and (x_{2}, y_{2})\) are points lie on the line.

1. Finding line RS slope by using the above formula:

   \(m=\frac{6-6}{2-(-8)}\)

   \(m=0\)

2. similarly finding line SW slope:

   \(m=\) ∞

3. similarly finding line TV slope:

   \(m=0\)

4. If the two lines are parallel then their slope will be equal.

   The slope of RS = The slope of TV.

   Hence RS and TV are parallel.

5. If two lines are perpendicular then their product of slope will be -1.

   Here we can see the product of the slope of SW and RS is not defined.

   Hence these two lines aren't perpendicular.

Therefore, statements 2, 3, and 4 are correct.

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There are infinitely many solutions and thus infinitely many values for x and y in the first system of equations. There are no solution for the second system of equations.

An equation is the statement of two expressions located on two sides connected with an equal to sign. The two sides of an equation is usually called as left hand side and right hand side

The first system of equations are,

y = 1/2 x + 1

-2x + 4y = 4

Multiplying throughout the first equation by 4, we get

4y = 2x + 4

and the second equation is 4y = 2x + 4

Both the equations are same and so the lines coincide.

They have infinitely many solutions.

The second system of equations are,

y = -x - 3

y + x = 2 ⇒ y = -x + 2

Both are in the form of y = mx +c, which is the equation of the line in slope intercept form.

Here m is the slope.

Given lines have the coefficient of x same, and so slopes are same.

So the lines are parallel.

Two parallel lines does not have a solution.

Hence the first system of equations have infinitely many solutions and second system of equations does not have any solution.

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the minimum surface area for the box is 4800 cm².

Forming the Equation of SurfaceArea

It is given that the given rectangular box is square-based and top is open. hence, it consists of  square and 4 rectangles.

Let the side of the square be a, and height of the box be h.

Then, the total surface area of the box will be given by,

S = a² + 4ah _________ (1)

Also, it is given that the volume of the box is, V = 32000 cm³

The volume of the rectangular box, V = a² h

Eliminating One of the Variables From the Equation

The volume of the rectangular box, V = a² h

⇒ a² h = 32000

⇒ h = 32000/a² _______ (2)

Substituting this value of h in equation (1), we get,

S = a² +4a(32000/a²)

S = a²+128000/a

Minimizing the Surface Area Equation

To find the minima, put, dS/da = 0

dS/da = 2a-128000/a²

⇒ 2a-128000/a² = 0

Multiplying the whole equation with a², we get,

2a³-128000 = 0

⇒ 2a³ = 128000

⇒ a³ = 128000/2

⇒ a³ = 64000

⇒ a = 40 cm

Calculating the Minimum Surface Area

From, equation (2), h = 32000/(40)²

h = 32000/1600

h = 20 cm

Now, substituting the computed values of a and h in equation (1), we get,

S = (40)² +4(40)(20)

S = 1600 +3200

S = 4800 cm²

∴ The minimum surface area of the box is 4800 cm².

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The new length of the unstretched hanging-spring is 70 cm.

Hooke's law states that the spring's length change as a result of a compressive or tensile load is directly proportionate to the size of the force placed on the spring. Mathematically,

F = kx

Where;

K is the spring constant, while x represents the spring's length change.

As per the question-

L is the spring's uncompressed length: L = 0.5 m

Weight F1 linked to the spring: F1 = 100 N

First weight's effect on elongation x1: 60 - 50 = 10 = .01 m.

As per the Hooke's law;

F1 = Kx1

K = F1/X1

K = 100 / 0.1

K = 1000 N/m

Spring constant = 1000 N/m.

For the added 100-N block.

F = Kx2

x2 = F/K

x2 = 100 + 100 / 1000

x2 = 0.2m

x2 = 20 cm

L = 50 + 20 = 70 cm.

Thus, new length of the unstretched hanging-spring is 70 cm.

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Answer:

And $1 buys 5 ounces of ground turkey

Step-by-step explanation:

40 / 8 = 5

$5

Plz mark as brainliest if correct! Have a nice day!!!

-Lil G

To find the total differential of the function w = e^y * cos(x) * z^2, we can take the partial derivatives with respect to each variable (x, y, and z) and multiply them by the corresponding differentials (dx, dy, and dz).

The total differential can be expressed as:

dw = (∂w/∂x) dx + (∂w/∂y) dy + (∂w/∂z) dz

Let's calculate the partial derivatives:

∂w/∂x =   \(-e^{y} * sin(x) * z^{2}\)

∂w/∂y =  \(e^{y} * cos(x) * z^{2}\)

∂w/∂z =  \(2e^{y} *cos (x)* z\)

Now, let's substitute these partial derivatives into the total differential expression:

\(dw = (-e^{y} * sin(x) * z^{2} ) dx + (e^{y}* cos(x) * z^{2} ) dy + 2e^{y} *cos (x)*z) dz\)

Therefore, the total differential of the function w = e^y * cos(x) * z^2 is given by:

\(dw = (-e^{y} * sin(x) * z^{2} ) dx + (e^{y} * cos(x) * z^{2} ) dy + ( 2e^{y} * cos(x) * z) dz\)

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Answer:

The y-intercept is -6.

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

The problem is put in different fractions to make it more confusing.

1 1/15 miles+ 1 3/5 miles+ 1 2/3 miles

We can find the common denominator of all of the fractions.

\(1 \frac{1}{15} + 1 \frac{9}{15} + 1 \frac{10}{15} \\= 3+\frac{20}{15} =4 \frac{5}{15}\\\\=\)4  1/3

\(monday = 1 \frac{1}{15} \)

\(tuesday = 1 \frac{3}{5} \)

\(wednesday = 1 \frac{2}{3} \)

the total number of miles Kenya ran in 3 days.

\( \frac{16}{15} + \frac{8}{5} + \frac{5}{3} \)

\( = \frac{16}{15} + \frac{8 \times 3}{5 \times 3} + \frac{5 \times 5}{3 \times 5} \)

\( = \frac{16 + 24 + 25}{15} \)

\( = \frac{65}{15} = \frac{13}{3} \)

\( = 4 \frac{1}{3} \)

therefore, the correct answer is option D.

Answer:

4.4763 billion km

Answer:

y = x, y = x^3, y = x^5

Step-by-step explanation:

For it to be symmetrical over the origin, you need to replace x with -x and y with -y AND make sure it equals to the original function. So for example, take y = x^5. Replace the x and y with -c and -y respectively:

-y = -x^5

Both are still negative so if you divide by -1, it is just the original function so it is symmetrical over origin.

If you don't understand something, comment and I will try my best to answer it

The x-coordinate of the point of intersection is the number of units that must be produced in order for the company to break even. This is because the revenue and cost curves intersect at this point, meaning that the company will make neither a profit nor a loss.

The revenue curve represents the amount of money that the company will make from selling x units of the commodity. The cost curve represents the amount of money that the company will spend to produce x units of the commodity. When the two curves intersect, this means that the revenue and cost are equal. Therefore, the company will break even when it produces x units of the commodity.

In this case, the x-coordinate of the point of intersection is 4000. This means that the company will break even if it produces 4000 units of the commodity.

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Answer:

\(x(y^6+2)^2\)

Step-by-step explanation:

Given polynomial expression:

\(4x+4xy^6+xy^{12}\)

Factor out the common term x:

\(x(4+4y^6+y^{12})\)

Now factor (4 + 4y⁶ + y¹²).

Rewrite the exponent 12 as 6·2:

\(4+4y^6+y^{6 \cdot 2}\)

\(\textsf{Apply the exponent rule:} \quad a^{bc}=(a^b)^c\)

\(4+4y^6+(y^6)^2\)

Rearrange to standard form:

\((y^6)^2+4y^6+4\)

Rewrite 4y⁶ as 2·2·y⁶ and 4 as 2²:

\((y^6)^2+2\cdot2\cdot y^6+2^2\)

\(\textsf{Apply\;the\;Perfect\;Square\;formula:}\quad a^2+2ab+b^2=(a+b)^2\)

Therefore, a = y⁶ and b = 2:

\(\implies (y^6)^2+2\cdot2y^6+2^2=(y^6+2)^2\)

Therefore, the given polynomial expression can be written as a product of two factors, x and (y⁶ + 2)²:

\(\boxed{4x+4xy^6+xy^{12}=x(y^6+2)^2}\)