What is the value of x in the equation -6x = 5x + 22?

Options:
A. ) –22
B. ) –2
C. ) 2
D. )22
Thank you!

| t | 0 | 1 | 2 | 3 | 4 | 5 |

| d | 0 | 60 | 120 | 180 | 240 | 300|

\(\rule{300pt}{3pt}\)

\(\rule{300pt}{3pt}\)

Take any two points from the table and find the slope.

Points:

(1,60) & (3,180)

\( \large \tt \: m = \frac{ y_{2} - y_{1}}{ x_{2} - x_{1}} \)

\( \sf \: m = \frac{180 - 60}{3 - 1} \)

\( \sf \: m = \frac{120}{2} \)

\( \sf \: m = \cancel \frac{120}{2} = 60\)

Therefore, Slope is 60..

Answer:

Step-by-step explanation:

y = 3x + 9

Answer:

$3040 profit made

Step-by-step explanation:

$13×95=$1235 cost to make all the shoes they sold

$45×95=$4275 money she made

$4275-$1235=$3040 profit

The algorithm/abstract strategy to justify the fraction 3/5 involves interpreting it as a division, performing the division, and obtaining the decimal representation as the results.

To justify the fraction 3/5, we can use the concept of division and understand it as a ratio or proportion.

Algorithm/Abstract Strategy:

Start with the numerator, which is 3.

Identify the denominator, which is 5.

Interpret the fraction as a ratio or comparison between the numerator and denominator.

Understand that 3/5 represents a division where the numerator (3) is divided by the denominator (5).

Perform the division: 3 ÷ 5.

Simplify the division to its simplest form, if necessary.

The result of the division, in this case, is the decimal representation of the fraction.

If required, convert the decimal representation to a percentage or any other desired form.

For example, if we perform the division 3 ÷ 5, the result is 0.6.

So, 3/5 can be justified as the ratio or proportion where the numerator (3) is divided by the denominator (5) resulting in 0.6.

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Answer:

223.8

Step-by-step explanation:

I failed the test to get the answer

Answer:

the answer is 223.8

Step-by-step explanation:

Answer:

\(6x^4y^8\sqrt{5x}\)

Step-by-step explanation:

\(\textsf{When $x > 0$ and $y > 0$, we want to find the expression that is equivalent to}\) \(\sqrt{180x^9y^{16}}.\)

\(\textsf{First, apply the radical rule:} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}\)

\(\sqrt{180}\sqrt{x^9}\sqrt{y^{16}}\)

\(\textsf{Rewrite $x^9$ as $x^{8+1}$:}\)

\(\sqrt{180}\sqrt{x^{(8+1)}}\sqrt{y^{16}}\)

\(\textsf{Apply the exponent rule:} \quad a^{b+c}=a^b \cdot a^c\)

\(\sqrt{180}\sqrt{x^{8}\cdot x^1}\sqrt{y^{16}}\)

\(\sqrt{180}\sqrt{x^{8}}\sqrt{x}\sqrt{y^{16}}\)

\(\textsf{Apply\:the\:radical\:rule:\:}\sqrt[n]{a^m}=a^{\frac{m}{n}},\:\quad a\geq 0\)

\(\sqrt{180}\;x^{\frac{8}{2}}\sqrt{x}\;y^{\frac{16}{2}}\)

\(\sqrt{180}\;x^4\sqrt{x}\;y^8\)

\(\sqrt{180}\sqrt{x}\;x^4\;y^8\)

\(\textsf{Rewrite $180$ as $(6^2 \cdot 5)$:}\)

\(\sqrt{6^2 \cdot 5}\sqrt{x}\;x^4\;y^8\)

\(\textsf{Apply the radical rule:} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}\)

\(\sqrt{6^2} \sqrt{5}\sqrt{x}\;x^4\;y^8\)

\(\textsf{Apply the radical rule:} \quad \sqrt{a^2}=a, \quad a \geq 0\)

\(6 \sqrt{5}\sqrt{x}\;x^4\;y^8\)

\(\textsf{Apply the radical rule:} \quad \sqrt{a}\sqrt{b}=\sqrt{ab}\)

\(6 \sqrt{5x}\;x^4\;y^8\)

\(\textsf{Rearrange:}\)

\(6x^4y^8\sqrt{5x}\)

\(\textsf{Therefore, when $x > 0$ and $y > 0$, the expression that is equivalent to}\)

\(\sqrt{180x^9y^{16}}\;\textsf{is}\;\;\boxed{6x^4y^8\sqrt{5x}}\:.\)

Complete Question:

Lucas is planting grass on the shaded portions of the yard. What will be the total area of covered by grass? Fill in the missing.

Part A= 12 x ? = ? ft²

Part B= 0.5 x ? x 9 = ?ft²

Part C= 0.5 x 7 x ? = ?ft²

Total Area= ?ft²

Answer:

\(A = 108ft^2\)

\(B = 27ft^2\)

\(C = 24.5ft^2\)

\(Area = 159.50ft^2\)

Step-by-step explanation:

Given

See attachment

From the attachment;

Part A is a rectangle with dimension 9ft by 12ft

So,

\(A = 12ft * 9ft\)

\(A = 108ft^2\)

Part B is a triangle with dimension: height = 6 and base = 9

The height is calculated as:

\(Height = 12ft - 6ft = 6ft\)

And the base is:

\(Base = 18ft - 9ft = 9ft\)

So, the area is:

\(B = 0.5 * 6ft * 9ft\)

\(B = 27ft^2\)

Part C is a triangle with dimension: height = 7 and base = 7

So, the area is:

\(C = 0.5 * 7 * 7ft^2\)

\(C = 24.5ft^2\)

Total Area is:

\(Area = A + B + C\)

\(Area = 108ft^2 + 27ft^2 + 24.5ft^2\)

\(Area = 159.50ft^2\)

Answer: banana- 88

Orange-55

Apple-143

Step-by-step explanation:

220 divided by 5, times 2,

that’s the banana trees

220 divided by 4, that’s the oranges

Add the answers together

Take the answer away from 220 that’s the apples

The function oscillates between two horizontal asymptotes, y=3 and y=-3, as x approaches the vertical asymptotes.

How to study graph?

To graph the function y=3cot(x) between 0 and 2, we can start by identifying the key characteristics of the cotangent function. The cotangent function is defined as the ratio of the adjacent side to the opposite side of a right triangle, with respect to a given angle. As such, the cotangent function is periodic with a period of π and has vertical asymptotes at x=nπ, where n is an integer.

The coefficient of 3 in the given function y=3cot(x) vertically stretches the function by a factor of 3, and does not affect the period or the vertical asymptotes.

Between 0 and 2, there are two vertical asymptotes at x=0 and x=π. To graph the function, we can plot a few points along the curve, using the symmetry properties of the cotangent function. Specifically, the cotangent function is odd, meaning that cot(-x)=-cot(x), and thus the graph is symmetric about the origin.

At x=π/4, we have cot(π/4)=1, and thus y=3cot(π/4)=3. Similarly, at x=3π/4, we have cot(3π/4)=-1, and thus y=3cot(3π/4)=-3. Using the symmetry property, we can also plot points at x=-π/4 and x=-3π/4, with y=3cot(-π/4)=-3 and y=3cot(-3π/4)=3, respectively.

Connecting these points with smooth curves, we can see that the graph of y=3cot(x) oscillates between two horizontal asymptotes, y=3 and y=-3, as x approaches the vertical asymptotes at x=0 and x=π.

Overall, the graph of y=3cot(x) between 0 and 2 can be summarized as follows:

There are two vertical asymptotes at x=0 and x=π.

The function oscillates between two horizontal asymptotes, y=3 and y=-3, as x approaches the vertical asymptotes.

The graph is symmetric about the origin.

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The speed of the second pedestrian is 5 kilometers per hour.

Let's say that the speed of the second pedestrian is S.

We know that the other pedestrian walks at a speed of 4km/h, and they (together) travel a distance of 27km in 3 hours, then we can write the linear equation:

(4km/h + S)*3h = 27km

It says that both pedestrians work, together, a total of 27km in 3 hours.

Now we can solve that linear equation for S, to do this, we need to isolate S in the left side of the equation.

4km/h + S = 27km/3h = 9 km/h

S = 9km/h - 4km/h = 5km/h

The speed of the second pedestrian is 5 kilometers per hour.

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Answer:

f(2) = 13.6

Step-by-step explanation:

Using the recursive formula and f(1) = 4 , then

f(2) = 0.4 f(1) + 12 = (0.4) × 4) + 12 = 1.6 + 12 = 13.6

The entire expression is a sum with 0 factors

The coefficients are 1/2, 1 and 7

From the question, we have the following parameters that can be used in our computation:

1/2x² + x + 7

The above expression is a quadratic expression and it has three terms

Quadratic expressions with real roots have 2 factors, otherwise it would have 0 factor

The expression 1/2x² + x + 7 does not have a real root because

b² < 2ac

Also in the expression, the coefficients are 1/2, 1 and 7

i.e. a = 1/2, b = 1 and c = 7

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Complete question

consider the expresson 1/2x² + x + 7.

complete 2 descriptions of the part of the expression

The entire expression is a sum with __ factors

The coefficients are _

Parents of children under the age of 18.

It is seldom feasible to get data from every member of a group of individuals when conducting research on them. In its place, you pick a sample. The population that will actually take part in the study is the sample. It is referred to as a sampling method. You can use one of the following two main sampling techniques in your study:

Random selection is a key component of probability sampling, which enables you to draw robust statistical conclusions about the entire group.

Non-probability sampling entails non-random selection based on practicality or other factors, making it simple to gather data.

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Answer:

  C)  42

Step-by-step explanation:

The parallel lines divide the transversals proportionally.

  x/35 = 30/25

  x = 35(6/5) . . . . multiply by 35, reduce the fraction

  x = 42

Answer:

\(\bold{\dfrac{63}{143}}\)

Step-by-step explanation:

Number of Democrats = 6

Number of Republicans = 7

Total number of members = 6+7 = 13

To find:

Probability of selecting two Democrats and two Republicans if 4 members are selected in the committee = ?

Solution:

This is a selection problem.

Total number of ways to select 4 members in the committee out of total 13 = \(_{13}C_4 = \dfrac{13\times 12\times 11\times 10}{4\times 3\times 2} = 715\)

Number of ways to select 2 Democrats = \(_{6}C_2 = \dfrac{6\times 5}{2} = 15\)

Number of ways to select 2 Republicans = \(_{7}C_2 = \dfrac{7\times 6}{2} = 21\)

Number of ways to select 2 Democrats and 2 Republicans = 15 \(\times\) 21 = 315

Formula for probability of an event E can be observed as:

\(P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}\)

Here, required probability:

\(\dfrac{315}{715} = \bold{\dfrac{63}{143}}\)

The percentages of each snack type that were sold are given as follows:

A percentage is one example of a proportion, as it is obtained by the number of desired outcomes divided by the number of total outcomes, and then multiplied by 100%.

Hence the percentages for each type are obtained as follows:

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-1 does not equal 0, the equation is not true for any value of "a". This means that there is no value of "a" for which the function f(x) is continuous at x = 1.

To determine the value of "a" for which the function f(x) is continuous at x = 1, we need to check if the left-hand limit and the right-hand limit of f(x) as x approaches 1 are equal, and if the value of f(x) at x = 1 is equal to these limits.

First, let's calculate the left-hand limit of f(x) as x approaches 1. For x < 1, the function is given by f(x) = (ax² - 1). To find the left-hand limit, we substitute x = 1 into this expression:

lim(x→1-) f(x) = lim(x→1-) (ax² - 1) = a(1²) - 1 = a - 1.

Next, let's calculate the right-hand limit of f(x) as x approaches 1. For x > 1, the function is given by f(x) = (a(x² - 2x + 1)). Substituting x = 1 into this expression, we have:

lim(x→1+) f(x) = lim(x→1+) (a(x² - 2x + 1)) = a(1² - 2(1) + 1) = a(1 - 2 + 1) = a.

For the function f(x) to be continuous at x = 1, the left-hand limit and the right-hand limit should be equal. Therefore, we have:

a - 1 = a.

To solve this equation for "a," we subtract "a" from both sides:

-1 = 0.

Since -1 does not equal 0, the equation is not true for any value of "a". This means that there is no value of "a" for which the function f(x) is continuous at x = 1.

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Answer:

r = 15.5

Step-by-step explanation:

4/3 pi r^3 = 15500 cm^3

r^3 = 15500 ÷ (4/3 pi)

r^3 = 3700.35

r = cube root of 3700.35

r = 15.467

r = 15.5

Answer:

4/3 π r³= 15500

r³=15500×3/4×7/22

r≈15.2 cm

Step-by-step explanation:

Answer:

Step-by-step explanation:

Y-intercept is -2.

Using slope formula, 2-(-2)/2-0 = 4/2 = 2 = slope.

Plugging into slope-intercept form:

y=mx+b => y=2x-2

Answer:

\( {x}^{2} + \frac{4}{3} x - \frac{1}{3} \)

can be subtracted

The work required to pump the water out of the spout is approximately 64,307,077 ft-lb

To find the work required to pump the water out of the spout, we need to calculate the weight of the water in the tank and then convert it to work using the formula: work = force × distance.

First, let's calculate the volume of water in the tank. The frustum of a cone can be represented by the formula: V = (1/3)πh(r1² + r2² + r1r2), where r1 and r2 are the radii of the two bases and h is the height.

Given r1 = 3 ft, r2 = 6 ft, and h = 12 ft, we can calculate the volume:

V = (1/3)π(12)(9 + 36 + 18) = 270π ft³

Now, we can calculate the weight of the water using the density of water:

Weight = density × volume = 62.5 lb/ft³ × 270π ft³ ≈ 53125π lb

Next, we convert the weight to force by multiplying it by the acceleration due to gravity (32.2 ft/s²):

Force = Weight × acceleration due to gravity = 53125π lb × 32.2 ft/s² ≈ 1709125π lb·ft/s²

Finally, we can calculate the work by multiplying the force by the distance. Since the water is being pumped out of the spout, the distance is equal to the height of the frustum, which is 12 ft:

Work = Force × distance = 1709125π lb·ft/s² × 12 ft ≈ 20509500π lb·ft ≈ 64307077 lb·ft

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The size of the city in 10 years is equal to 29,802.32

Given the following data:

To calculate the size of the city in 10 years:

In this exercise, you're required to determine the size of this city in the next ten (10) years.

Mathematically, the exponential growth of a population is given by this formula;

\(P = a(1+r)^t\)

Where:

Substituting the given parameters into the formula, we have;

\(P = 3200(1+0.25)^{10}\\\\P = 3200(1.25)^{10}\\\\P = 3200 \times 9.3132\)

P = 29,802.32

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The distribution is not normal. The points show a systematic pattern that is not a straight-line pattern curved over mean.

A normal distribution is a type of data distribution in which the data points form a symmetric, bell-shaped curve around the mean.

The data points in the example provided show a systematic pattern that is not a straight-line pattern, indicating that the data does not come from a normally distributed population.

This is because the points are not reasonably close to a straight line, which is a characteristic of a normal distribution.

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9/26

2 8/9 = 26/9

Reciprocal of 16/9 is 9/26

The total area of the shaded region for the region x = 5y³ , x = 5y² in the interval ( 5, 1 ) is equal to ( 5 / 12 ).

From the attached graph :

The area of the shaded region :

x = 5y³ , x = 5y² for the interval ( 5, 1 ) is equal to :

= \(\int\limits^1_0 {( 5y^{2 } - 5y^{3 }}) \, dy\)

=  [ ( 5y³/3 ) - ( 5y⁴ / 4 ) ]\(| \limits^1_0\)

Substitute the lower limit and upper limit we get,

= (5 /3 )( 1 )³ - 0  - ( 5 / 4 )( 1⁴) + 0

= ( 5 / 3 ) - ( 5 / 4 )

= ( 20 - 15 ) / 12

= 5 / 12

Therefore, the total area of the shaded region in the given graph for the lower and upper limit is equal to ( 5 / 12 ) .

The given question is incomplete, I answer the question in general according to my knowledge:

Find the total area of the shaded region x = 5y³ , x = 5y² for the interval

( 5, 1 ).

Graph is attached.

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Answer:

B

Step-by-step explanation:

312-96=216

216/24=9

Answer:

B

Step-by-step explanation:

24x9+96