What if the well was 40 feet deep, the frog climbs 6 feet per hour, and it slips back only 1 foot while resting for an hour?
If the well was 40 feet deep and the frog climbs 6 feet per hour, it would take the frog 40/6 = 6.67 hours to reach the top of the well.
However, the frog slips back 1 foot while resting for an hour, so the frog would only have covered 5 feet of the well after each hour of climbing. The frog would need to climb for a total of
40/5 = 8 hours
to reach the top of the well. Additionally, the frog would need to take 8 hours of rest to make up for the slipping back.
So the total time it would take the frog to get out of the well would be 8 hours + 8 hours = 16 hours.
If the well was 40 feet deep and the frog climbs 6 feet per hour, it would take the frog 40/6 = 6.67 hours to reach the top of the well.
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it is desired to estimate the mean tensile strength for roof hangers. it is known that the standard deviation of measurements of tensile strength is 0.25. (units are newton per square meter.) as it is very important for safety, the 99% confidence interval needs to have a margin smaller than 0.06. what is the minimum required sample size?
The minimum required sample size is 47 as it is very important for safety, the 99% confidence interval needs to have a margin smaller than 0.06.
To estimate the mean tensile strength for roof hangers with a 99% confidence interval margin of 0.06, we can use the formula:
Margin of error = z* (standard deviation / sqrt(sample size))
where z is the z-score for the desired confidence level, which for a 99% confidence interval is 2.576.
Plugging in the given values, we get:
0.06 = 2.576 * (0.25 / sqrt(sample size))
Solving for the sample size, we get:
sample size = (2.576 * 0.25 / 0.06)^2
sample size = 89.59
Rounding up to the nearest whole number, the minimum required sample size is 90.
Therefore, we need to take a sample of at least 90 roof hangers to estimate the mean tensile strength with a 99% confidence interval margin of 0.06.
To estimate the mean tensile strength for roof hangers with a 99% confidence interval and a margin of error smaller than 0.06, you'll need to determine the minimum required sample size.
For a 99% confidence level, the Z-score (critical value) is approximately 2.576.
The known standard deviation is 0.25. The desired margin of error is less than 0.06. Use the formula:
Margin of Error = Z-score * (Standard Deviation / sqrt(Sample Size))
Rearrange the formula to find the sample size:
Sample Size = (Z-score * Standard Deviation / Margin of Error)^2
Sample Size = (2.576 * 0.25 / 0.06)^2
Sample Size ≈ 46.24
Since you cannot have a fraction of a sample, round up to the nearest whole number. The minimum required sample size is 47.
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True or False: A slope of 0 means the line dosen't move up or down, it is flat
Answer:
Step-by-step explanation: yes
help no wrong answers ALOT OF POINTS
This is NOT a function.
For a relation to be a function, each x-value needs to have only 1 y-value. This is not the case for the data points given here. The x-value 160 has 7 different y-values. If these points were graphed, it would form a straight line and a straight line is not a function (it does not pass the vertical line test!).
Hope this helps!
Use The Power Reduction Formulas To Rewrite The Expression. (Hint: Your Answer Should Not Contain Any Exponents Greater Than 1.) Cos2(7x)
The expression will become cos²(7x) = \(\frac{1}{2}\)(1 + cos14x).
Power reduction formulas like double angle and half angle formula are used to simplify the calculations requires to solve a given expression.
Power reduction formulas allow us to reduce the power on one of the trigonometric functions when the power is an even integer.
The trigonometric power reduction identities allow us to rewrite expressions involving trigonometric terms with trigonometric terms of smaller powers.
The power reduction formula is
cos²θ = \(\frac{1}{2}\)(1 + cos2θ)
sin²θ =\(\frac{1}{2}\)(1 - cos2θ)
For the given equation we will use cosine formula.
Therefore
cos²(7x) = \(\frac{1}{2}\)(1 + cos2(7x))
cos²(7x) = \(\frac{1}{2}\)(1 + cos14x).
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(05.06)
Which of the following points lie in the solution set to the following system of
inequalities? (1 point)
y<-3x+3
y
O (1.-5)
O (1.5)
O (5.1)
0 (-1.5)
how many kilograms are in 44 pounds? 1 kg=2.2lbs
Answer:
20 kilograms
Step-by-step explanation:
Answer:
About 19.95 kilograms
Step-by-step explanation:
Hope this helped! :)
A center has a center at X(4, -3) and a point on the circle is W(8, 0). What is the location of Y on the diameter WY?
Answer: (0, -6)
Step-by-step explanation:
The center is the midpoint of the diameter, meaning that the coordinates of Y must be (0, -6).
Right math answer gets brainlyest
Answer:
ji aap ka answer (24) hai
Opportunity to get Brainliest! I will put various questions and will mark BRAINLIEST!
Answer:
parallel
Step-by-step explanation:
Parallel lines have equal slopes.
Calculate the slopes m using the slope formula
m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)
with (x₁, y₁ ) = (- 1, 2) and (x₂, y₂ ) = (2, 3)
m = \(\frac{3-2}{2+1}\) = \(\frac{1}{3}\)
Repeat with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (3, 1)
m = \(\frac{1-0}{3-0}\) = \(\frac{1}{3}\)
Since slopes are equal then parallel
A gas station ensures that its pumps are well calibrated. To analyze them, we took
80 samples of how much gasoline was dispensed when filling a 10gl tank. The average of the 100
samples was 9.8gl, it is also known that the standard deviation of each sample is 0.1gl. Do not care
find the probability that the dispensers dispense less than 9.95gl
To find the probability that the dispensers dispense less than 9.95 gallons, we can use the Central Limit Theorem and approximate the distribution of the sample mean as a normal distribution.
Given that the average of the 80 samples is 9.8 gallons and the standard deviation of each sample is 0.1 gallons, we can consider the sample mean as an estimate of the population mean. The Central Limit Theorem states that as the sample size increases, the distribution of the sample mean approaches a normal distribution, regardless of the shape of the population distribution.
Since the sample size is large (80 samples), we can approximate the distribution of the sample mean as a normal distribution with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size. In this case, the population standard deviation is 0.1 gallons, and the square root of the sample size is √80.
To calculate the probability that the dispensers dispense less than 9.95 gallons, we can standardize the value using the z-score formula:
z = (x - μ) / (σ / √n)
Where x is the value we are interested in (9.95 gallons), μ is the population mean (9.8 gallons), σ is the population standard deviation (0.1 gallons), and n is the sample size (80).
Substituting the values into the formula:
z = (9.95 - 9.8) / (0.1 / √80)
Calculate the z-value and find the corresponding probability from the standard normal distribution table or using statistical software.
By finding the probability associated with the z-value, you can determine the probability that the dispensers dispense less than 9.95 gallons.
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Jonczyk Company is considering two different, mutually exclusive capital expenditure proposals. Project A will cost $454,000, has an expected useful life of 13 years and a salvage value of zero, and is expected to increase net annual cash flows by $68,000. Project B will cost $300,000, has an expected useful life of 13 years and a salvage value of zero, and is expected to increase net annual cash flows by $47,000. A discount rate of 9% is appropriate for both projects. Click here to view PV table.
Calculate the net present value and profitability index of each project. (If the net present value is negative, use either a negative sign preceding the number e.g. -45 or parentheses e.g. (45). Round present value answers to 0 decimal places, e.g. 125 and profitability index answers to 2 decimal places, e.g. 15.52. For calculation purposes, use 5 decimal places as displayed in the factor table provided, e.g. 1.25124.)
Net present value is a measure of profitability. The NPV of an investment is the net cash inflow received over the project's life, less the initial cash outflow, adjusted for the time value of money.
A higher NPV means the project is more lucrative. The profitability index measures the benefit-cost ratio of a project and is calculated by dividing the present value of future cash flows by the initial cash outflow. A profitability index greater than one indicates that the project will be profitable, whereas a profitability index less than one indicates that the project will not be profitable.
Calculation of Net Present Value (NPV) of Project AInitial Outlay = $454,000Net annual cash flows = $68,000Discount Rate = 9%Use the PV of an annuity of $1 table to determine the PV of net cash flows.Using the formula for NPV,NPV of Project A = PV of net cash flows – Initial OutlayNPV of Project A = 68,000 × 7.63930 – 454,000NPV of Project A = $56,201.85Calculation of Profitability Index of Project AProfitability Index of Project A = Present value of future cash flows / Initial OutlayProfitability Index of Project A = 68,000 × 7.63930 / 454,000Profitability Index of Project A = 1.14
Calculation of Net Present Value (NPV) of Project BInitial Outlay = $300,000Net annual cash flows = $47,000Discount Rate = 9%Use the PV of an annuity of $1 table to determine the PV of net cash flows.Using the formula for NPV,NPV of Project B = PV of net cash flows – Initial OutlayNPV of Project B = 47,000 × 6.10338 – 300,000NPV of Project B = $37,100.86Calculation of Profitability Index of Project BProfitability Index of Project B = Present value of future cash flows / Initial OutlayProfitability Index of Project B = 47,000 × 6.10338 / 300,000Profitability Index of Project B = 0.96
The NPV and profitability index calculations show that project A is the better investment since it has a higher NPV and profitability index than project B.
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{x - 2y + 4z = 4 -5x + 9y - 22z = -16 -2x + 3y - 10z = k In order for the system of equations above to be a consistent system, k must be equal to
In order for the system of equations to be a consistent system, the value of k must be equal to -4.
To determine the value of k that makes the system of equations consistent, we can use the method of elimination or substitution. Let's use the method of elimination.
First, we can multiply the first equation by 5, the second equation by -1, and the third equation by 2 to make the coefficients of x in the three equations cancel each other out when added together.
The modified system of equations becomes:
5x - 10y + 20z = 20
5x - 9y + 22z = 16
-4x + 6y - 20z = 2k
Now, let's subtract the first equation from the second equation:
(5x - 9y + 22z) - (5x - 10y + 20z) = 16 - 20
y + 2z = -4
Next, let's add this equation to the third equation:
(-4x + 6y - 20z) + (y + 2z) = 2k - 4
-4x + 7y - 18z = 2k - 4
For the system of equations to be consistent, there must be no contradictions or inconsistencies. This means that the equations must be linearly dependent, and the last equation must be a multiple of the second equation.
Comparing the last equation (-4x + 7y - 18z = 2k - 4) with the second equation (y + 2z = -4), we can see that the two equations will be dependent and consistent if 2k - 4 is equal to 0.
2k - 4 = 0
2k = 4
k = 2
Therefore, in order for the system of equations to be a consistent system, the value of k must be equal to -4.
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What is the answer for the wuesy
Answer:
22
Step-by-step explanation:
6 divided 6 equals 1 and 1 times 22 equals 22
Brainliest ?
Which of the following formulas expresses h in terms of l and s?
(choices shown in attached image)
(picture for problem shown in attached image)
Answer: D
Step-by-step explanation:
Find the area of triangle ABC.
A. 24 cm
B. 32 cm2
C. 48 cm2
D. 64 cm
E. 128 cm2
I don’t need an explanation just the answer thank you c:
Answer:
24 centimetre
hope it is helpful
8) Find the perimeter of the parallelogram? *7 points17 cm5 cm15 cm44274849
ANSWER
44 cm
EXPLANATION
The perimeter of a polygon is the sum of the side lengths. In this case we have two sides that are 7 cm long and two sides that are 15 cm long. The perimeter is:
\(\begin{gathered} P=7\operatorname{cm}+7\operatorname{cm}+15\operatorname{cm}+15\operatorname{cm} \\ P=14\operatorname{cm}+30\operatorname{cm} \\ P=44\operatorname{cm} \end{gathered}\)i have a painting, if it's an original it's worth 500k if it isn't it's worth 10k. the probability it's an original is 0.2. i have an option to pay 100k
Option 1 (not paying 100k) has a higher expected value of 108k, while Option 2 (paying 100k) has an expected value of 8k. Therefore, it would be more financially beneficial not to pay the 100k.
Your question is about a painting and whether it is an original or not. If it is an original, it is worth 500k, and if it is not, it is worth 10k. The probability that it is an original is 0.2. You have the option to pay 100k.
Based on the information provided, let's calculate the expected value of each option:
1. Option 1: Do not pay 100k:
- Probability of it being an original: 0.2
- Value if it's an original: 500k
- Value if it's not an original: 10k
- Expected value: (0.2 * 500k) + (0.8 * 10k) = 100k + 8k = 108k
2. Option 2: Pay 100k:
- Probability of it being an original: 0.2
- Value if it's an original: 500k - 100k (paid) = 400k
- Value if it's not an original: 10k - 100k (paid) = -90k (negative value)
- Expected value: (0.2 * 400k) + (0.8 * -90k) = 80k - 72k = 8k
Comparing the expected values, Option 1 (not paying 100k) has a higher expected value of 108k, while Option 2 (paying 100k) has an expected value of 8k. Therefore, it would be more financially beneficial not to pay the 100k.
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A box contains 22 pennies, 44 nickels, and 66 dimes. Six coins are drawn without replacement, with each coin having an equal probability of being chosen. What is the probability that the value of the coins drawn is at least 5050 cents
Answer:
127/924 ≈ 0.1374
Step-by-step explanation:
Given a box with 2 pennies, 4 nickels, 6 dimes, you want the probability that 6 randomly chosen coins will have a value of 50 cents or more.
50 centsThe ways 50 cents (or more) can be made from those coins are ...
6 dimes5 dimes + 1 nickel5 dimes + 1 penny4 dimes + 2 nickelsCount the waysThere is 6C6 = 1 way to choose 6 dimes.
There are (6C5)(4C1) = 6·4 = 24 ways to choose 5 dimes and 1 nickel
There are (6C5)(2C1) = 6·2 = 12 ways to choose 5 dimes and 1 penny
There are (6C4)(4C2) = 15·6 = 90 ways to choose 4 dimes and 2 nickels
The total number of ways to get 50¢ or more is ...
1 +24 +12 +90 = 127
The total number of ways to choose 6 coins from the 12 is ...
12C6 = 924
ProbabilityThe probability of choosing 6 coins that total 50¢ or more is ...
127/924 ≈ 0.1374
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Someone tell me just the equation for question b.
Answer:
2 2/4
Step-by-step explanation:
because I guess they want you too add so I added them
You estimate that you will owe $62,100 in student loans by the time you graduate. The interest rate is 4.6 percent. If you want to have this debt paid in full within 25 years, how much must you pay each month? Monthly payment =$ Allowed attempts: 3 Now suppose you decide to defer your payments for 2 years. What will the balance of your loans be when you start to make payments? (Hint interest will still be charged monthly). New balance =$ Allowed attempts: 3 At this point, how much will you need to pay each month to pay the debt in full over 25 years? New payment =$ Alowed attempts:3 Suppose you want to make up for lost time and pay off your debts within 25 years from graduation, despite the deforral. What monthly payment is required to meat this goal? Monthly payment =$
Monthly payment before deferral: $345.09. Balance after deferral: $67,901.53. Monthly payment after deferral: $380.57. Monthly payment to pay off debt within 25 years from graduation: $421.63.
To calculate the monthly payment for a student loan, we can use the loan amortization formula.
Monthly payment calculation:
We can use the formula for calculating the monthly payment on an amortizing loan:
PMT = (P * r) / (1 - (1 + r)^(-n))
where PMT is the monthly payment, P is the loan amount, r is the monthly interest rate, and n is the total number of payments.
Given:
P = $62,100 (loan amount)
r = 4.6% per year / 12 months = 0.046/12 (monthly interest rate)
n = 25 years * 12 months = 300 (total number of payments)
Substituting these values into the formula, we can calculate the monthly payment:
PMT = (62,100 * (0.046/12)) / (1 - (1 + (0.046/12))^(-300))
Balance after deferral period:
To calculate the balance after the deferral period of 2 years, we need to calculate the interest accrued during that period and add it to the original loan amount:
Interest accrued during deferral = P * r * deferral period (in years)
New balance = P + Interest accrued during deferral
New monthly payment after deferral period:
To calculate the new monthly payment after the deferral period, we can use the same formula as before, but with the new balance and the remaining number of payments:
New PMT = (New balance * r) / (1 - (1 + r)^(-n))
Monthly payment to pay off the debt within 25 years from graduation:
To calculate the monthly payment to pay off the debt within 25 years from graduation, we need to adjust the remaining number of payments:
Remaining number of payments = 25 years * 12 months - deferral period
Then we can use the same formula as before to calculate the monthly payment.
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construct a data set for which the paired t-test statistic is very large, but for which the usual two-sample or pooled t-test statistic is small. in general, describe how you created the data. does this give you any insight regarding how the paired t-test works?
The paired t-test statistic is infinity, which indicates a significant difference in the means of math scores and science scores.
Let's consider an example of a paired t-test and a two-sample t-test on a dataset of 5 students' scores in two different exams: math and science. Let's assume that the students took both exams, and their scores are paired. We want to test whether there is a significant difference in the means of math scores and science scores.
We calculate the difference between each student's math score and science score and compute the mean difference and standard deviation of the differences:
Student Math Score Science Score Difference
1 80 75 5
2 90 85 5
3 85 80 5
4 95 90 5
5 75 70 5
Mean difference = 5
Standard deviation of differences = 0
We can calculate the paired t-test statistic as:
t = (mean difference - hypothesized difference) / (standard deviation of differences / square root of sample size)
Let's assume the hypothesized difference is 0 (i.e., there is no difference between the means). Then the t-test statistic is:
t = (5 - 0) / (0 / √(10)) = infinity
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a set of data with 200 numbers is normally distributed with a mean of 65 and a standard deviation of 9 . how many numbers in the data would you expect to be between 56 and 74?
You would expect approximately 136 numbers in the data set to be between 56 and 74.
To determine the number of numbers you would expect to be between 56 and 74 in a normally distributed data set with a mean of 65 and a standard deviation of 9, we can utilize the properties of the standard normal distribution.
First, we need to standardize the values of 56 and 74 by converting them to z-scores. The z-score formula is:
z = (x - μ) / σ
where z is the z-score, x is the data value, μ is the mean, and σ is the standard deviation.
For 56:
z = (56 - 65) / 9
z = -1
For 74:
z = (74 - 65) / 9
z = 1
Next, we need to find the area under the standard normal curve between the z-scores -1 and 1. We can use a standard normal distribution table or a calculator to find this probability.
Using a standard normal distribution table, the area between -1 and 1 is approximately 0.6826. This represents the proportion of the data that falls within one standard deviation of the mean.
To find the number of numbers expected to be between 56 and 74, we multiply the proportion by the total number of data points:
Expected number = Proportion * Total number of data points
Expected number = 0.6826 * 200
Expected number ≈ 136.52
As a result, you would anticipate that roughly 136 of the data set's numbers would fall between 56 and 74.
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What is the area of the polygon? 30cm 21cm 14cm 46cm
Answer:
1,044
Step-by-step explanation:
14 x 46 = 644
16 x 25 = 400
644 + 400 = 1,044
Nicole purchased a package of 5 coconut cookies. The total weight of the cookies was 0.5 ounces. How many did each cookie weigh
Answer:
0.1 ounce
Step-by-step explanation:
5 cookies = 0.5 ounces
1 cookie = 0.5 / 5 = 0.1 ounce
spent $95 buying 13 books to donate to the local elementary school. Activity books cost $5 each and story books cost $11 each, how many of each type of book did purchase?
Answer:
Number of Activity books = 8
Number of Storybooks = 5
Explanation:
Let x represent the number of activity books.
Let y represent the number of storybooks.
Let's go ahead and set up our equations as follows;
\(\begin{gathered} x+y=13\ldots\ldots\text{.}\mathrm{}\text{Equation 1} \\ 5x+11y=95\ldots\ldots\ldots\ldots\text{.Equation 2} \end{gathered}\)From equation 1, we can see that x = 13 - y
Let's go ahead and substitute the value of x into equation 2 and solve for y;
\(\begin{gathered} 5(13-y)+11y=95 \\ 65-5y+11y=95 \\ 6y=30 \\ y=\frac{30}{6} \\ y=5 \end{gathered}\)Since y = 5, let's substitute the value of y into equation 1 and solve for x;
\(\begin{gathered} x+5=13 \\ x=13-5 \\ x=8 \end{gathered}\)A company director investigated whether there is a difference in the mean number of overtime hours worked each week by employees assigned to two different managers. Each manager, A and B, manages 100 employees. Random samples of 35 employees from manager A and 40 employees from manager B were selected. The number of overtime hours worked was recorded for the 75 employees each week. Have the conditions been met for inference with a confidence interval for the difference in the population means?
A Yes, all conditions have been met.
B No, because the data were not collected using a random method.
C No, because the size of at least one of the samples is greater than 10 percent of the population.
D No, because the sample sizes are not large enough to assume the distribution of the difference in sample means is normal.
E No, because the sample sizes are not the same.
The answer is D. No, because the sample sizes are not large enough to assume the distribution of the difference in sample means is normal.
Determine sample mean?In order to perform inference with a confidence interval for the difference in population means, certain conditions need to be met. One of the conditions is that the sample sizes should be sufficiently large.
For the distribution of the difference in sample means to be approximately normal, both sample sizes should ideally be large, typically with a guideline of at least 30 observations. In this case, the sample sizes are 35 for manager A and 40 for manager B, which are relatively small compared to the guideline.
Therefore, (D) the condition of having large enough sample sizes to assume a normal distribution for the difference in sample means is not met. As a result, the conditions for inference with a confidence interval for the difference in population means have not been met.
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Whose solution is correct and why? Nico is correct because he knew that Negative four-fifths = StartFraction negative 4 over negative 5 EndFraction. Nico is correct because he knew that Negative four-fifths = StartFraction negative 4 over 5 EndFraction. Lorena is correct because she knew that Negative four-fifths = StartFraction negative 4 over 5 EndFraction Lorena is correct because she knew that Negative four-fifths = StartFraction negative 4 over negative 5 EndFraction
This question is incomplete
Complete Question
Nico and Lorena used different methods to determine the product of three fractions.
Nico’s Method =
(one-sixth) (Negative four-fifths)(2) = (StartFraction 2 over 1 EndFraction) (one-sixth) (negative four-fifths) = StartFraction (2) (1) (negative 4) over (1) (6) (5) EndFraction = Negative StartFraction 8 over 30 EndFraction
Lorena’s Method
= Negative StartFraction 4 over 15 EndFraction (2) (one-sixth) (Negative four-fifths) = (StartFraction 2 over 1 EndFraction) (one-sixth) (negative four-fifths) = StartFraction (2) (1) (negative 4) over (1) (6) (5) EndFraction = Negative StartFraction 8 over Negative 30 EndFraction = StartFraction 4 over 15 EndFraction
Whose solution is correct and why?
a) Nico is correct because he knew that Negative four-fifths = StartFraction negative 4 over negative 5 EndFraction.
b) Nico is correct because he knew that Negative four-fifths = StartFraction negative 4 over 5 EndFraction.
c) Lorena is correct because she knew that Negative four-fifths = StartFraction negative 4 over 5 EndFraction
d) Lorena is correct because she knew that Negative four-fifths = StartFraction negative 4 over negative 5 EndFraction
Answer:
b) Nico is correct because he knew that Negative four-fifths = StartFraction negative 4 over 5 EndFraction.
Step-by-step explanation:
In the above question
We start from Nico's method
Nico’s Method =
Step 1 : (one-sixth) (Negative four-fifths)(2)=
(1/6)(-4/5)(2)
Step 2 : (StartFraction 2 over 1 EndFraction) (one-sixth) (negative four-fifths) =
= (2/1)(1/6)(-4/5)
Step 3: StartFraction (2) (1) (negative 4) over (1) (6) (5) EndFraction
= (2)(1)(-4)/(1)(6)(5)
Step 4: Negative StartFraction 8 over 30 EndFraction
= (-8/30)
Step 5 : Negative StartFraction 4 over 15
EndFraction
= -4/15
Nico is correct
For Lorena’s Method
Step 1: Negative StartFraction 4 over 5 EndFraction (2) (one-sixth)
= -4/5(2)(1/6)
Step 2: (Negative four-fifths) = (StartFraction 2 over 1 EndFraction) (one-sixth) (negative four-fifths) =
(2/1)(1/6)(-4/-5)
Step 3: StartFraction (2) (1) (negative 4) over (1) (6) (negative 5) EndFraction
(2)(-1)(-4)/(1)(6)(-5)
Step 4: Negative StartFraction 8 over Negative 30 EndFraction =
-8/-30
Step 5: StartFraction 4 over 15
EndFraction
= 4/15
Lorena is wrong because
that Negative four-fifths ≠StartFraction negative 4 over negative 5 EndFraction
Mathematically
-4/5 ≠ -4/-5
Therefore,option b) Nico is correct because he knew that Negative four-fifths = StartFraction negative 4 over 5 EndFraction.
What are the coefficients in the polynomial 4x2 + 3x-3?
•4, -3, -3
•4, 3
•4, 3, 3
•-4, -3
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
\(\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\)
What are the coefficients in the polynomial 4x²+3x-3?
\(\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}\diamond\)
Coefficient:- A number before a variable
Coefficients in this polynomial:-
4 (the number before x²) and 3 (the number before x)
So we conclude that the right option is:-
\(\bigcirc\!\!\!\!\!\large\checkmark\) 4, 3 (Option B)
Good luck.- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
given the sample of twenty numbers: 52, 54, 58, 59, 59, 60, 60, 63, 65, 66, 67, 68, 69, 73, 74, 77, 78, 79, 79, 98. the first quartile is?
We have that, the first quartile of the given sample of twenty numbers is 59.
How do we calculate the first quartile of the sample?To find the first quartile of the given sample of twenty numbers
52, 54, 58, 59, 59, 60, 60, 63, 65, 66, 67, 68, 69, 73, 74, 77, 78, 79, 79, 98
use the following formula: Formula to calculate the first quartile:
\($$\mathrm{Q_1} = \mathrm{\frac{n+1}{4}}$$\)
So, plugging the values into the formula,
\($$\mathrm{Q_1} = \frac{20+1}{4}$$$$\mathrm{Q_1} = \frac{21}{4}$$$$\mathrm{Q_1} = $5.25 $\)
Then round 5.25 to the nearest whole number. To do this, compare 0.25 to 0.5, if it is greater than or equal to 0.5, then round up. If it is less than 0.5, round down. Since 0.25 is less than 0.5, round 5.25 to the nearest whole number. Therefore, the first quartile of the given sample of twenty numbers is 59.
See more information about quartiles at: https://brainly.com/question/28169373
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