The solution of log(2x + 6) to the power of 8 = 3 is x = -1.8.
Given logarithm:
log(2x+6)^8 = 3
we know that:
log a^n = n log a
8 log(2x+6) = 3
log(2x+6) = 3/8
Converting into exponential form
2x +6 = 10^3/8
2x + 6 = 10^0.375
2x = 2.4 - 6
2x = -3.6
x = -1.8
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The figure shows three tennis balls in a can with each tennis ball having a diameter of 2.5 inches. What is the total volume of the air space around the three tennis balls?
The total volume of the air space of spherical ball is A = 12.265625 inches³
Given data ,
Since each tennis ball has a diameter of 2.5 inches, the radius of each ball is 1.25 inches.
The air space around the balls can be thought of as a cylinder with a height equal to the diameter of one ball and a radius equal to the radius of one ball.
The height of the cylinder is 2.5 inches, and the radius is 1.25 inches.
The formula for the volume of a cylinder is:
V = πr²h
V = ( 3.14 ) ( 1.25 )² ( 7.5 )
V = 36.796875 inches³
where V is the volume, r is the radius, and h is the height.
So, the volume of the one ball is:
V₁ = ( 4/3 )π(1.25)³
V₁ = 8.177083 inches³
The total volume of three balls is = volume of 3 spherical balls
V₂ = 3V₁ = 3(8.177083) ≈ 24.53125 cubic inches
Therefore, the total volume of the air space around the three tennis balls is approximately A = 36.796875 inches³ - 24.53125 inches³
A = 12.265625 inches³
Hence , the volume of air space is A = 12.265625 inches³
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Given the function f(x) = 0.5|x - 41-3, for what values of x is f(x) = 7?
x = -24, x = 16
x= -16, x = 24
x=-1, x = 9
x = 1, x = -9
The values of x for which f(x) = 7 are x = 61 and x = 21.
To find the values of x for which f(x) = 7, we can set up the equation and solve for x.
The given function is f(x) = 0.5|x - 41| - 3.
Setting f(x) equal to 7, we have:
0.5|x - 41| - 3 = 7.
First, let's isolate the absolute value term:
0.5|x - 41| = 7 + 3.
0.5|x - 41| = 10.
To remove the absolute value, we can consider two cases:
Case: (x - 41) is positive or zero:
0.5(x - 41) = 10.
Multiplying both sides by 2 to get rid of the fraction:
x - 41 = 20.
Adding 41 to both sides:
x = 61.
So x = 61 is a solution for this case.
Case: (x - 41) is negative:
0.5(-x + 41) = 10.
Multiplying both sides by 2:
-x + 41 = 20.
Subtracting 41 from both sides:
-x = -21.
Multiplying both sides by -1 to solve for x:
x = 21.
So x = 21 is a solution for this case.
Therefore, the values of x for which f(x) = 7 are x = 61 and x = 21.
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4. Chelsea determined that the value of x in the triangle at the right was 5.
a. Find the value of each angle by substituting 5 for x.
b. Was Chelsea's solution, x = 5, correct? How do you know?
15x
x
11x
(8x+5)
Z
Step-by-step explanation:
a) 11*5=55
15*5=75
8*5+5=45
b) No, because (55+75+45=175°) and the perimeter of a triangle is 180°
Explain how to use Pascal's Triangle to expand the binomial (3x-4y)^11
The expansion of (3x-4y)¹¹ using Pascal's Triangle is:
177147x¹¹ - 2598156x¹⁰y - 17321040x⁹y² - 69284160x⁸y³ - 184757760x⁷y⁴ - 344881152x⁶y⁵ - 458941536x⁵y⁶ - 437944320 x⁴y⁷ - 291962880x³y⁸ - 129761280x²y⁹ + 34603008xy¹⁰ - 4194304y¹¹.
What is Pascal's Triangle?The triangle-shaped array of integers known as Pascal's triangle has one at the top and one on each of its two sides. Every new number has a value equal to the sum of the two numbers above it and is located between two other numbers and underneath them. Pascal's triangle is a triangular array of binomial coefficients that appears in algebra, combinatorics, and probability theory.In algebra, a triangle-shaped grouping of integers known as Pascal's triangle provides the coefficients for the expansion of any binomial formula, such as (x + y)ⁿ. Although it is much older, it bears the name of the French mathematician Blaise Pascal from the 17th century.So, the expression is:
(3x-4y)¹¹Now, use Pascal's Triangle to expand as follows:
(Refer table attached below for expansion)Therefore, the expansion of (3x-4y)¹¹ using Pascal's Triangle is:
177147x¹¹ - 2598156x¹⁰y - 17321040x⁹y² - 69284160x⁸y³ - 184757760x⁷y⁴ - 344881152x⁶y⁵ - 458941536x⁵y⁶ - 437944320 x⁴y⁷ - 291962880x³y⁸ - 129761280x²y⁹ + 34603008xy¹⁰ - 4194304y¹¹.
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The population of a city was 10,000 in 2010. The population increase at an annual rate of 2.5% per year. Is the growth model function that represents the population of the city linear?
Answer:
The growth model that represents the population of this city is not linear--it is exponential:
\(f(t) = 10000( {1.025}^{t} )\)
\(t = 0 \: represents \: 2010\)
Which of the following is the correct substitution into the quadratic formula?
3x2 + 4x +5=0
Answer:
answer is D
x = -4±√4^2 - 4(3)(5)
2(3)
Step-by-step explanation:
ax^2 + bx + c = 0
3x^2 + 4x + 5 = 0
x = -b ±√b^2 - 4ac
2(a)
x = -4±√4^2 - 4(3)(5)
2(3)
Answer:
The last choice is correct.
Step-by-step explanation:
Use only the coefficients and the constant, a, b & c. not the variable x.
. Why is the following arrangment of squares not an array?
When it comes to arrays in mathematics, it usually involves objects or numbers that are arranged in rows and columns.In order for a set of squares to be considered an array, it must meet certain requirements. These requirements are:All rows must have the same number of squares. All columns must have the same number of squares. Squares must be organized in an orderly manner. A set of squares that does not meet these requirements is not an array.
An array is a set of objects or values that are organized in a specific order. It is used in programming, mathematics, and other fields to make data manipulation and analysis easier.
When it comes to arrays in mathematics, it usually involves objects or numbers that are arranged in rows and columns.In order for a set of squares to be considered an array, it must meet certain requirements. These requirements are:All rows must have the same number of squares. All columns must have the same number of squares. Squares must be organized in an orderly manner. A set of squares that does not meet these requirements is not an array.
For example, if a set of squares is arranged in a random or disorganized manner, it cannot be considered an array because it does not meet the orderly requirement. Additionally, if the number of squares in each row or column is different, it cannot be considered an array because it does not meet the uniformity requirement.
Overall, it is important to remember that an array is a specific type of organization and cannot be applied to any random set of objects or values.
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I NEED HELP PLEASE ANSWER SOON !!
Answer:
wacha le vas a hacer x-3+21=67
According to records, the amount of precipitation in a certain city on a November day has a mean of inches, with a standard deviation of inches. What is the probability that the mean daily precipitation will be inches or less for a random sample of November days (taken over many years)
Answer:
The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of \(Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}\), in which \(\mu\) is mean amount of inches of rain and \(\sigma\) is the standard deviation.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean \(\mu\) and standard deviation \(\sigma\), the z-score of a measure X is given by:
\(Z = \frac{X - \mu}{\sigma}\)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \(\mu\) and standard deviation \(\sigma\), the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(s = \frac{\sigma}{\sqrt{n}}\).
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question:
Mean \(\mu\), standard deviation \(\sigma\)
n days:
This means that \(s = \frac{\sigma}{\sqrt{n}}\)
Applying the Central Limit Theorem to the z-score formula.
\(Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}\)
What is the probability that the mean daily precipitation will be of X inches or less for a random sample of November days?
The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of \(Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}\), in which \(\mu\) is mean amount of inches of rain and \(\sigma\) is the standard deviation.
Solve for the indicated variable. 6y + 5x = 7 for x
Answer:
\(x = \frac{-6y+7}{5}\)
Step-by-step explanation:
\(6y + 5x = 7\)
Isolate x ;
\(5x = 7-6y\\\\5x =-6y+7\)
Divide both sides of the equation by 5
\(\frac{5x}{5} = \frac{-6y+7}{5} \\\\x = \frac{-6y +7}{5}\)
Helppppppppppppppppp
Bronson is ordering a sundae at a restaurant, and the server tells him that he can have up to four toppings: butterscotch sauce, caramel, peanuts, and strawberries. Since he cannot decide how many of the toppings he wants, he tells the server to surprise him. If the server randomly chooses which toppings to add, what is the probability that Bronson gets just butterscotch sauce, peanuts, and strawberries
Answer:
20%
Step-by-step explanation:
if zero toppings is an option, then there would be 5 possibilities for toppings
0,1,2,3,or 4
the server randomly chose 3 toppings so that would be one out of 5 or 20%.
(If the server did not have the option to put zero toppings on then there would be only 4 options 1,2,3, or 4 toppings and the correct answer would be one out of 4 or 25%.)
What equation can be solved to find one of the missing side lengths of a triangle?
Answer:
Step-by-step explanation:
1 find out what kind of its is
if its equivelent you might use 60 as thee angles then find out
Find the missing angles in the image below. Use two different angle theories to explain how you found at least two missing angles.
Answer:
A.35°, 114°, 31°.
B.61°,119°,153°,27° and 92°
SolutionA. alternates angles are equal;
35°=35°
Vertically opposites angles are equal;
114°=114°
Sum of interior angles of a triangle is 180;
114+35+x=180
x=180-(114+35)
x=31
Picture B.
Corresponding angles are equal;
61°=61°
Sum of angles on a straight line is 180°
61+x=180
x=180-61
x=119°
Corresponding angles are equal;
153°=153°
Sum of angle on straight line is 180;
153+x=180
x=180-153
x=27
Sum of interior angle of a triangle is 180;
27+61+X=180
x=180-(27+61)
x=92
Describe how the graph of y = ln x - 3 relates to the graph of its parent function y = ln x. aIt is shifted 3 units up. bIt is shifted 3 units down. cIt is shifted 3 units right. dIt is shifted 3 units left.
Step 1:
Write the parent function
\(y\text{ = In(x)}\)Step 2:
The parent function y = In(x) is shifted 3 units down to get y = In(x) - 3
Final answer
Option B
It is shifted 3 units down.
What is the slope of a line that goes
through the points (4, -1) and (3,
8)?
Answer:
m=-9
Step-by-step explanation:
For a survey based on 2,700 adults, what is the approximate margin of error? (round your answer to the nearest thousandth.)
The approximate margin of error for a survey based on 2,700 adults, when rounded to nearest thousand is 0.021.
In statistical surveys, the margin of error is a measure of the expected amount of random sampling error that is present in a survey's results. It is a range of values that is likely to contain the true value of the population parameter being estimated, with a certain degree of confidence.
In other words, the margin of error is the amount by which the sample estimate may differ from the true value of the population parameter.
The margin of error is affected by several factors, such as the size of the sample and the level of confidence. A larger sample size typically results in a smaller margin of error because larger samples provide more accurate estimates of the population parameter.
Similarly, a higher level of confidence requires a larger margin of error, since the interval of values that could contain the true population parameter becomes wider as the level of confidence increases.
Assuming a 95% level of confidence, the formula for calculating the margin of error is:
Margin of error = z * sqrt(p * (1 - p) / n)
where:
z is the z-score for the desired level of confidence (1.96 for 95%)
p is the sample proportion, which is the proportion of the sample that exhibits a particular characteristic of interest (e.g., the proportion of respondents who support a certain political candidate)
n is the sample size, which is the number of observations in the sample.
If the sample proportion is not known, it is common to use a value of 0.5, which corresponds to the maximum possible margin of error for a given sample size. This is because the maximum sampling error occurs when the sample proportion is closest to 0.5, which gives the least amount of information about the true population parameter.
To calculate the margin of error for a survey of 2,700 adults, we can assume a sample proportion of 0.5 and a 95% level of confidence. Plugging these values into the formula, we get:
Margin of error = 1.96 * sqrt(0.5 * (1 - 0.5) / 2700)
= 1.96 * sqrt(0.25 / 2700)
= 1.96 * 0.008
= 0.016
Rounding to the nearest thousandth, the approximate margin of error is 0.021. This means that we can expect the survey results to be within plus or minus 2.1 percentage points of the true population parameter, with a 95% level of confidence.
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four times a number increased by 8 is 54?
Answer:
4x+8=54 this is the correct answer
Select the sketch of the right rectangular prism with height of 2cm and bases that are 5 cm by 3 cm.
Answer: See image
Step-by-step explanation:
The bases are 5cm times 3cm, meaning that 2 parallel sides have to be 5cm by 3cm, 2 other parallel sides have to 2cm by 3cm, and the 2 other parallel sides have to be 5cm by 2cm.
Helllppppppp I can’t figure this out
Answer:
Step-by-step explanation:
2x^2 + 9x + 4=0
2x^2+8x+x+4=0
2x(x+4) +1 (x+4) =0
2x+1 = 0
x+ 4 =0
2x= -1
x= -1/2
x=-4
Therefore x = -4 and x = -1/2
Match the following. Match the items in the left column to the items in the right column. 1. domain the first element of a relation or function; also known as the input value. 2. output a relation in which every input value has exactly one output value. 3. input the x-value of a function. 4. relation any set of ordered pairs (x, y) that are able to be graphed on a coordinate plane. 5. function the y-value of a function. 6. range the second element of a relation or function; also known as the output value.
The matching of items and their corresponding descriptions are 1. Domain, 2.Output, 3. Input, 4. Relation, 5. Function, and 6. Range.
What is the appropriate matching of the following items?1. Domain - the first element of a relation or function; also known as the input value.
3. Input - the x-value of a function.
6. Range - the second element of a relation or function; also known as the output value.
4. Relation - any set of ordered pairs (x, y) that are able to be graphed on a coordinate plane.
2. Output - a relation in which every input value has exactly one output value.
5. Function - the y-value of a function.
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Can someone please help me ASAP:(
Answer:
3 =x
Step-by-step explanation:
(segment piece) x (segment piece) = (segment piece) x (segment piece)
3x(x+1) = 4x*x
Divide each side by x
3(x+1) = 4x
Distribute
3x+3 = 4x
Subtract 3x from each side
3x-3x +3 = 4x-3x
3 =x
Find the x-intercepts of the polynomial function. State whether the graph crosses the x-axis, or touches the x-axis and turns around, at each intercept
f(x) = (x + 1)(x - 5)(x - 1)^2
The x-intercepts will be at x = 0 , -2 A line crosses the x-axis at the x-intercept, and the y-intercept is where the line crosses the y-axis.
What is polynomial function?A polynomial function is a function in an equation, such as the quadratic equation, cubic equation, etc., that only uses non-negative integer powers or only positive integer exponents of a variable. A polynomial with an exponent of 1 is, for instance, 2x+5. A polynomial is a function that has the formula f(x) = anxn + anxn + anxn+1 +... + a2x2 + a1x + a0. The highest power of x in the formulation of a polynomial is its degree. Constant (non-zero) polynomials, linear polynomials, quadratics, cubic, and quartics, respectively, are polynomials of degree 0, 1, 2, 3, and 4.Given
f(x) = x²(x+2)
To find the x-intercepts ⇒ f(x) = 0
∴ x²(x+2) = 0
∴ x² = 0 OR x+ 2 = 0
∴ x = 0 or x = -2
So, the x-intercepts will be at x = 0 , -2
We must graph the function f in order to determine whether the graph crosses the x-axis, hits the x-axis, and then reverses at each intercept (x)
The attached figure represents the graph of f(x)
As shown in the figure:
1) The graph crosses the x-axis at x = -2
2) The graph touches the x-axis and turns around at x = 0
The complete question is,
Find the x-intercepts. State whether the graph crosses the x-axis or touches the x-axis and turns around at each intercept. Show your work.
f(x) = x2(x + 2)
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Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.) integral 4 + Squareroot x + x/x dx
The answer of this queation :∫ (4 + √x + x/x) dx = 4x + 2/3 x^(3/2) + x + C
where C = C1 + C2 + C3 is the constant of integration for the entire expression.
eparate integrals:
∫ 4 dx + ∫√x dx + ∫ x/x dx
The first two integrals can be easily integrated as follows:
∫ 4 dx = 4x + C1, where C1 is a constant of integration.
∫√x dx = 2/3 x^(3/2) + C2, where C2 is a constant of integration.
For the third integral, note that x/x simplifies to 1 for all nonzero x.
∫ x/x dx = ∫ 1 dx = x + C3, where C3 is a constant of integration.
Putting it all together, we have:
∫ (4 + √x + x/x) dx = 4x + 2/3 x^(3/2) + x + C
where the integration constant for the entire statement is C = C1 + C2 + C3.
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simplifly the expression4.2n+5-3.2n
n+5
Subtract 4.2n and 3.2n
I roll a number cube twice. what is the probabity of rolling an even number and a 5?
Answer:
4/6
Step-by-step explanation:
there are three even numbers (3/6) and 3 odd numbers but you are only looking for 5 (1/6) so the answer is 4/6
hopefully this helps you :)
pls mark my answer brainlest I need it ;)
Find and of the function = − −( − ).
Answer:
Thats not possible
Step-by-step explanation:
There is no:
numbersvariablesonly negative signs5. A bag contains 5 blue marbles, 3 red marbles, and 2 yellow marbles. You select a marble at random. Wha
is Plyellow)?
2
8
5
5
Answer:
i cant rlly see the question bc its cut out but i yhink its 8
Step-by-step explanation:
total Amount of Marbles in the bag is:
5 + 3 = 8
So, since there are 5 Red marbles, the probability of drawing one is 5 / 8.
Now that you pulled that marble out, you have 7 marbles total left in the bag, 4 of those are read (5 originally, minus the one you took out.
So, the probability of the second round is 4/7.
To find the overall probability, you multiply those probabilities together:
4/7*5/8 = 20/56
PLEASE ANSWER ASAP WILL MARK BRAINLIEST!!
Select the favorable outcomes for rolling a sum of seven.
O (5-1) (5-2) (5-3) (5-4) (5-5) (5-6)
O (1-6) (2-5) (3-4) (4-3) (5-2) (6-1)
O (1-1) (1-2) (1-3) (2-1) (2-2)(3-1)
O (1-1) (2-2) (3-3) (4-4) (5-5) (6-6)
Answer:
The second one
O (1-6) (2-5) (3-4) (4-3) (5-2) (6-1)
Step-by-step explanation:
Favorable outcome is the outcome that we are looking for
The outcome that we are looking for when rolling two = die is a sum of 7
The set (1-6) (2-5) (3-4) (4-3) (5-2) (6-1) all add up to equal 7
( 1 , 6 ) 1 + 6 = 7
( 2 , 5 ) 2 + 5 = 7
( 3 , 4 ) 3 + 4 = 7
etc.
Which means that they are the favorable outcomes for rolling a seven
Professor A.B.C company opens his own company, Electronic Tutorial Services, and completes the following transactions in June:
6/1 A.B.C company invests 20,000 in the business.
6/3 Purchased 12,100 of equipment.
6/4 Paid 220 premium for an insurance policy.
6/6 Purchased office supplies on Account 140.
6/9 Purchased a new computer for 9,000. Paid 40% cash agreed to pay the remainder Later.
6/10 Billed student Omar 58 for tutorial services that were performed.
6/14 Paid for the supplies purchased on June 6th.
6/15 the owner suggested to purchased new Building for his company by 22,000
6/25 Received 85 cash from student Salim Ali for tutorial services performed.
6/30 Student billed on June 10 pays the amount due to A.B.C company.
6/30 A.B.C company withdraws 60 for personal use.
Required: Prepare the all Accounting Cycles
In June, A.B.C company invested $20,000, purchased equipment, paid insurance premium, bought office supplies, billed students for tutorial services, received cash, paid for supplies, withdrew personal funds.
Accounting Cycles:
1. June 1:
- A.B.C company invests $20,000 in the business.
- Prepare the journal entry:
- Debit: Cash ($20,000)
- Credit: Capital ($20,000)
2. June 3:
- Purchased equipment for $12,100.
- Prepare the journal entry:
- Debit: Equipment ($12,100)
- Credit: Cash ($12,100)
3. June 4:
- Paid $220 premium for an insurance policy.
- Prepare the journal entry:
- Debit: Insurance Expense ($220)
- Credit: Cash ($220)
4. June 6:
- Purchased office supplies on account for $140.
- Prepare the journal entry:
- Debit: Office Supplies ($140)
- Credit: Accounts Payable ($140)
5. June 9:
- Purchased a new computer for $9,000. Paid 40% in cash and agreed to pay the remainder later.
- Prepare the journal entry for the cash payment:
- Debit: Computer ($3,600) [40% of $9,000]
- Credit: Cash ($3,600)
- Prepare the journal entry for the remaining amount:
- Debit: Computer ($5,400)
- Credit: Accounts Payable ($5,400)
6. June 10:
- Billed student Omar $58 for tutorial services performed.
- Prepare the journal entry:
- Debit: Accounts Receivable ($58)
- Credit: Tutorial Services Revenue ($58)
7. June 14:
- Paid for the supplies purchased on June 6th ($140).
- Prepare the journal entry:
- Debit: Accounts Payable ($140)
- Credit: Cash ($140)
8. June 15:
- The owner suggested purchasing a new building for the company for $22,000.
- No journal entry is required at this point. It is a decision made by the owner.
9. June 25:
- Received $85 cash from student Salim Ali for tutorial services performed.
- Prepare the journal entry:
- Debit: Cash ($85)
- Credit: Accounts Receivable ($85)
10. June 30:
- Student billed on June 10 pays the amount due ($58).
- Prepare the journal entry:
- Debit: Cash ($58)
- Credit: Accounts Receivable ($58)
11. June 30:
- A.B.C company withdraws $60 for personal use.
- Prepare the journal entry:
- Debit: Withdrawals ($60)
- Credit: Cash ($60)
These transactions represent the accounting cycles for the given period.
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