Answer:
Step-by-step explanation:
10
whats the gcf of 56 and 72
To find the GCF (Greatest Common Factor) of 56 and 72, we need to list out the factors of each number and find the highest common factor.
Factors of 56: 1, 2, 4, 7, 8, 14, 28, 56
Factors of 72: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72
We can see that the common factors are 1, 2, 4, and 8. Out of these, the highest factor is 8. Therefore, the GCF of 56 and 72 is 8.
The greatest common factor (GCF) of 56 and 72 is 8.
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The mean distance of the earth from the sun (let's call it d) is 93 million miles. The distance varies as much as 1.6 million miles. Write the equation that describes the possible distances of the earth from the sun, using as distance unit millions of miles.
Use d as the variable
(this is copy-pasted from the textbook)
Answer:
The equation that can be used to describe the possible distances of the Earth from the Sun, with the distances given in million of miles is;
d = 93 ± 1.6
Step-by-step explanation:
The parameters given are;
The mean distance of the Earth from the Sun, d = 93 million
The amount by which the distance varies = 1.6 million
Therefore, the equation that can be used to describe the possible distances of the Earth from the Sun, with the distances given in million of miles is given as follows;
d = 93 ± 1.6
Therefore, the range of values for the distance of the Earth from the Sun can be presented as follows;
93 - 1.6 ≤ d ≤ 93 + 106
Which gives
91.4 ≤ d ≤ 94.6
(01.02 HC)
Write each expression with a single rational exponent. Show each step of your process. Which expressions are equivalent? Justify your reasoning.
By applying radical, power and rational properties we have the following results after simplifying expressions:
\(x^{\frac{3}{4} }\)x\(x^{\frac{11}{10} }\)xHow to reduce radical and rational expressions into a single power expression with rational exponent
In this question we need to simplify four given expressions by using the following radical and power properties:
\(\sqrt[n]{x} = x^{\frac{1}{n} }\) (1)\(x^{m+n} = x^{m}\cdot x^{n}\) (2)\(x^{m-n} = \frac{x^{m}}{x^{n}}\) (3)\((x^{m})^{n} = x^{m\cdot n}\) (4)Now we proceed to simplify each of the four expressions:
\(\sqrt[4]{x^{3}} = x^{3/4}\)\(\frac{1}{x^{-1}} = (x^{-1})^{-1} = x\)\(\sqrt[10]{x^{5}\cdot x^{4}\cdot x^{2}} = \sqrt[10]{x^{11}} = x^{\frac{11}{10} }\)\(x^{\frac{1}{3} }\cdot x^{\frac{1}{3} }\cdot x^{\frac{1}{3} } = x\)To learn more on power functions: https://brainly.com/question/18719083
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in a circle of radius 3.4 cm, what is the length of the arc opposite a central angle that measures 46 degrees?
The length of the arc opposite a central angle that measures 46 degrees is 2.72 cm.
What is circle?
The measurement of the circle's boundaries is called as the circumference or perimeter of the circle. whereas the circumference of a circle determines the space it occupies. The circumference of a circle is its length when it is opened up and drawn as a straight line. Units like cm or unit m are typically used to measure it. The circle's radius is considered while calculating the circumference of the circle using the formula. As a result, in order to calculate the circle's perimeter, we must know the radius or diameter value.
in a circle of radius 3.4 cm
central angle that measures 46 degrees
length of arc = (46/360) * 2π*3.4
=2.72cm
Hence the length of the arc opposite a central angle that measures 46 degrees is 2.72 cm
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sketch the region enclosed by the graphs of the given functions. y = sec2(x), y = 8 cos(x), − 3 ≤ x ≤ 3
The region graph enclosed by the given functions y = sec2(x) and y = 8 cos(x) for -3 ≤ x ≤ 3 can be sketched as follows.
1. Plot the graphs of the given functions:
y = sec2(x) and y = 8 cos(x) for -3 ≤ x ≤ 3.
2. Shade the area enclosed the two graphs.
3. The region enclosed by the given functions is shown below.
The region enclosed by the given functions y = sec2(x) and y = 8 cos(x) for -3 ≤ x ≤ 3 can be sketched as follows. Firstly, plot the graphs of the two functions on the same coordinate plane. Then, shade the area enclosed by the two graphs. The resulting region is a curved area that starts from the point (-3, 8 cos(-3)) on the left, curves up until it reaches the point (3, 8 cos(3)) on the right and then curves down until it reaches the point (-3, 8 cos(-3)). The enclosed region is a continuous, curved area that lies between the two graphs.
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Can someone help me on this plzzz and thank u
Answer:
I think 23
Step-by-step explanation:
a-3+a-3+a-3 = 60
3a-9 =60
3a = 69
a= 69/3
a=23
What equation is being represented by this line?
Answer:
The equation that represented by the line is y = -x + 2
Step-by-step explanation:
The slope-intercept form of the linear equation is y = m x + b, where
m is the slope of the lineb is the y-intercept (value y at x = 0)The rule of the slope is m = \(\frac{y2-y1}{x2-x1}\) , where
(x1, y1) and (x2, y2) are two points on the lineFrom the given figure
∵ The line passes through points (2, 0) and (0, 2)
∴ x1 = 2 and y1 = 0
∴ x2 = 0 and y2 = 2
→ Substitute them in the rule of the slope to find it
∵ m = \(\frac{2-0}{0-2}=\frac{2}{-2}=-1\)
∴ m = -1
→ Substitute it in the form of the equation above
∵ y = -1(x) + b
∴ y = -x + b
∵ b is value y at x = 0
∵ At x = 0, y = 2
∴ b = 2
→ Substitute it in the equation above
∴ y = -x + 2
∴ The equation that represented by the line is y = -x + 2
Need help with this………
Answer:
(-4,2)
Step-by-step explanation:
It's the coordinates that the two lines cross at.
This exercise explores the effect of linear transformations f :R² + R2. (a) For points v, w E R², let l be the line segment joining them (i.e., I consists of the convex linear combinations tv + (1 – t)w with 0 0, so the third is at (a,b) with b + 0 (as the third vertex cannot be on the line through the other two vertices); any triangle can be arranged to be such a T by sliding and rotating it in RP
This exercise explores the effect of linear transformations on points in R² to R². It considers the line segment between two points and the concept of a "triangle inequality" for any three points on a plane.
The exercise focuses on the effect of linear transformations on points in R² (a 2-dimensional space) to R². It starts by considering two points, v and w, in R² and defines the line segment l that joins them. This line segment is characterized by the convex linear combinations of v and w, where t ranges from 0 to 1. These combinations represent the points along the line segment.
The exercise then introduces the concept of a "triangle inequality" for any three points on a plane. It states that for any three points, v, w, and u, on a plane, the distance between v and u is less than or equal to the sum of the distances between v and w, and between w and u. This inequality helps establish the relationship between the points in the triangle formed by v, w, and u.
To further explore this concept, the exercise introduces a triangle T with vertices v, w, and u. It states that the first two vertices, v and w, are at (0,0) and (1,0) respectively. The third vertex, u, is at (a,b) with b > 0. This condition ensures that the third vertex cannot lie on the line passing through the other two vertices. The exercise suggests that any triangle can be transformed to such a T by sliding and rotating it in RP, the real projective plane.
Overall, the exercise delves into the impact of linear transformations on points in R² and emphasizes the triangle inequality as a fundamental concept for analyzing the relationships between points on a plane.
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Write an equation in slope intercept form of the line that passes through (-2,10) and (1,1).
Answer:
Step-by-step explanation:
1st use the two points to find the slope of the line that passes thru those two points
m = y2 - y1 / x2 - x1
where point1 = ( x1, y1 ) and point2 = (x2, y2 )
your are given P1 = ( -2,10) and P2 = (1,1)
find the slope
m = 1-(-2) / 1-10
m = 1+2 / -9
m = 3 / -9
m = - 1/3
then use the point-slope formula [y-y1 = m(x-x1)] with either of the two points, I'll use P2 b/c it seems easier (1,1) , you get the same results with either point and work the problem to the slope-intercept form [y = mx +b ]
y -y1 = m(x-x1)
y-1 = -1/3(x-1)
y-1 = -1/3x + 1/3
y = -1/3x + 1/3 + 1
y = -1/3x + 4/3
:) got it ?
PLEASE HELP!! You have to solve for x but it’s the similar triangles way
Answer:
x = 26
Step-by-step explanation:
A segment joining the midpoints of 2 sides of a triangle is half the length of the third side, thus
x + 9 = \(\frac{1}{2}\)(3x - 8) ( multiply both sides by 2 to clear the fraction )
2(x + 9) = 3x - 8
2x + 18 = 3x - 8 ( subtract 2x from both sides )
18 = x - 8 ( add 8 to both sides )
26 = x
-3x+4y=8
Convert the equation from standard form to slope intercept form
Answer:
\(\large\boxed{ \tt y=\frac{3}{4}x+2}\)
Step-by-step explanation:
\(\textsf{We are asked to convert the given equation from standard form to slope-intercept form.}\)
\(\textsf{Standard form is a more complex form of a linear equation.}\)
\(\textsf{Let's review important information necessary.}\)
\(\large\underline{\textsf{Standard Form;}}\)
\(\tt Ax+By=C\)
\(\textsf{For this equation, A, B, and C are integers.}\)
\(\textsf{C is the y-intercept.}\)
\(\textsf{A is the slope.}\)
\(\textsf{B represents how many times the whole equation \underline{was} multiplied by.}\)
\(\underline{\textsf{A more simplified equation;}}\)
\(\tt x + y = c\)
\(\textsf{We need to change this equation into slope-intercept form.}\)
\(\large\underline{\textsf{Slope-Intercept Form;}}\)
\(\tt y = mx+b\)
\(\textsf{Note that this equation \underline{isn't} multiplied.}\)
\(\textsf{M represents the slope.}\)
\(\textsf{B represents the y-intercept.}\)
\(\textsf{We should change where the y is, and divide the equation by how much B is.}\)
\(\large\underline{\textsf{To Start;}}\)
\(\tt-3x+4y=8\)
\(\textsf{The y-intercept is 8.}\)
\(\textsf{The slope is -3.}\)
\(\textsf{The equation is multiplied by 4, so we should divide by 4.}\)
\(\large\underline{\textsf{Divide by 4;}}\)
\(\tt \frac{-3x+4y}{4} =\frac{8}{4}\)
\(\tt -\frac{3}{4}x+y=2\)
\(\textsf{Now, for slope-intercept form, y has to \underline{equal} the slope and the y-intercept added together.}\)
\(\textsf{Modify the equation where y is the result by adding the slope to both sides.}\)
\(\large\underline{\textsf{Change into Slope-Intercept Form;}}\)
\(\tt -\frac{3}{4}x+y=2\)
\(\tt -\frac{3}{4}x + \frac{3}{4}x+y=2 + \frac{3}{4} x\)
\(\underline{\textsf{Switch around the slope and the y-intercept;}}\)
\(\large\boxed{ \tt y=\frac{3}{4}x+2}\)
Answer:
y = (3/4)x + 2
Step-by-step explanation:
Now we have to write,
→ The equation in slope-intercept form.
The equation is,
→ -3x + 4y = 8
The slope-intercept form is,
→ y = mx + b
Let's rewrite the given equation,
→ -3x + 4y = 8
→ 4y = 8 + 3x
→ 4y = 3x + 8
→ y = (3x + 8)/4
→ y = (3x/4) + (8/4)
→ [ y = (3/4)x + 2 ]
Hence, the answer is y = (3/4)x + 2.
Select the correct answer.
The manager at a car dealership is tracking the selling prices of two different used car models. When the tracking began, the selling price of
model A was less than $8,000, and the selling price of model B was at most $10,000. The manager has determined that the price of model A is
decreasing at a rate of 12% each year, and the price of model B is decreasing at a rate of 15% each year.
Which system of inequalities can be used to determine after how many years, t, that the selling price, y, will be the same for both car models?
O A.
Ов.
Jy < 8,000(0.88)
y < 10,000(0.85)
Sy < 8,000(1.12)
y < 10,000(1.15)
9 < 8,000(0.88)
y < 10,000(0.85)
Sy < 8,000(1.12)"
1y 10,000(1.15)
Oc.
OD
Answer:it’s C
Step-by-step explanation:
The system of inequalities can be used to determine, if The selling price of model A was less than $8,000, The selling price of model B was at most $10,000, are x < 8000 × 0.88, and y < 1000 × 0.85.
What is the selling price?The selling price of a good or service is the final cost to the seller, or what the buyer actually pays. A commodity or service in a specific amount, weight, or measurement can be exchanged.
It is one of the most crucial things for a business to decide. It is significant since it determines whether it will survive. Sales of a product are directly impacted by its price.
Given:
The selling price of model A was less than $8,000,
The selling price of model B was at most $10,000,
The price of model A is decreasing at a rate of 12% each year,
The price of model B is decreasing at a rate of 15% each year,
Write the inequality as shown below,
Assume the selling price of A is x,
x < 8000
Assume the selling price of B is y,
y < 1000
The decreased selling price of A,
x < 8000 × (1 - 0.12) = x < 8000 × 0.88
The decreased selling price of B,
y < 1000 × (1 - 0.15) = y < 1000 × 0.85
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6+x^4-3x^2-5x
WHAT IS THE CONSTANT AND WHY
Answer:
6
Step-by-step explanation:
The constant is the number that's all by itself with no variable.
x is the variable. It can vary (change) as you use different values for x.
There are four terms here in the expression in your question they are separated by the plus or minus signs.
2 and 4 are exponents. 3 and 5 are coefficients.
x^4 is a fourth degree term. 3x^2 is a second degree term. 5x is a first degree term. The whole expression is 4th degree because the highest exponent is 4.
But the 6 is all by itself. 6 is the constant.
The number of times a player has golfed in one’s lifetime is compared to the number of strokes it takes the player to complete 18 holes. The correlation coefficient relating the two variables is –0.26. Which best describes the strength of the correlation, and what is true about the causation between the variables? It is a weak negative correlation, and it is not likely causal. It is a weak negative correlation, and it is likely causal. It is a strong negative correlation, and it is not likely causal. It is a strong negative correlation, and it is likely causal.
The true fact about the causation between the variables is option a; It is a weak negative correlation, and it is not likely causal
Given,
The number of strokes needed to finish 18 holes is linked to how many times a player has played golf in their lifetime. There is a -0.26 connection between the two variables.
Variables include "how many times a player has played golf throughout their lifetime" and "how many strokes it takes a player to play 18 holes."
Given that -0.26 is more closely related to 0 than to 1, it denotes a mild negative correlation.
Additionally, it is unlikely that the amount of rounds of golf a person has played during their lifetime has any bearing on how many strokes it takes them to complete 18 holes.
That is,
The true fact about the causation between the variables is option a; It is a weak negative correlation, and it is not likely causal
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a) (7x10^5)x(3x10^2) in standard form b) (2x10^5)/(4x10^2) in standard form
The given expressions written in standard form are;
A) 21 × 10⁷
B) 5 × 10²
This is about expression of given algebra in standard form making use of laws of indices.
A) We are given;
(7 × 10⁵) × (3 × 10²)
Now according to the law of indices, when we want to multiply 2 numbers with same bases and different exponents, we retain the bases and add the exponents.
Also, when we want to multiply 2 numbers with different bases and same exponent, we multiply the bases and retain the exponent.
Applying that to our question gives;
(7 × 3)¹ × (10)⁽⁵ ⁺ ²⁾
⇒ 21 × 10⁷
B) We are given;
(2 × 10⁵)/(4 × 10²)
According to the law of indices, when we want to divide 2 numbers with same bases and different exponents, we retain the bases and subtract the exponents.
Also, when we want to divide 2 numbers with different bases and same exponent, we divide the bases and retain the exponent.
Thus;
(2/4)¹ × (10)⁽⁵ ⁻ ²⁾ = 0.5 × 10³
0.5 can also be expressed as; 5 × 10⁻¹
Thus, 5 × 10⁻¹ × 10³ = 5 × 10²
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Harper, inc., acquires 40 percent of the outstanding voting stock of kinman company on january 1, 2020, for $334,900 in cash. the book value of kinman's net assets on that date was $625,000, although one of the company's buildings, with a $70,800 carrying amount, was actually worth $135,550. this building had a 10-year remaining life. kinman owned a royalty agreement with a 20-year remaining life that was undervalued by $147,500. kinman sold inventory with an original cost of $77,700 to harper during 2020 at a price of $111,000. harper still held $18,750 (transfer price) of this amount in inventory as of december 31, 2020. these goods are to be sold to outside parties during 2021. kinman reported a $51,800 net loss and a $26,600 other comprehensive loss for 2020. the company still manages to declare and pay a $15,000 cash dividend during the year. during 2021, kinman reported a $57,200 net income and declared and paid a cash dividend of $17,000. it made additional inventory sales of $120,000 to harper during the period. the original cost of the merchandise was $75,000. all but 30 percent of this inventory had been resold to outside parties by the end of the 2021 fiscal year. prepare all journal entries for harper for 2020 and 2021 in connection with this investment. assume that the equity method is applied. (if no entry is required for a transaction/event, select "no journal entry required" in the first account field. do not round intermediate calculations.)
In 2020, Harper, Inc. acquired 40% of the outstanding voting stock of Kinman Company for $334,900 in cash.
The book value of Kinman's net assets was $625,000, but there were certain adjustments needed. One of Kinman's buildings was undervalued by $64,750 ($135,550 - $70,800), and there was an undervaluation of $147,500 for the royalty agreement. Harper also purchased inventory from Kinman for $111,000, out of which $18,750 was still held in inventory by the end of the year. Kinman reported a net loss of $51,800 and other comprehensive loss of $26,600 in 2020, but it still paid a $15,000 cash dividend.
To record these transactions, Harper would make the following journal entries in 2020:
1. To record the investment in Kinman's stock:
Investment in Kinman Company Stock 334,900
Cash 334,900
2. To adjust the building's carrying amount and recognize the related depreciation:
Investment in Kinman Company Stock 64,750
Depreciation Expense 6,475
Accumulated Depreciation 6,475
3. To adjust the undervalued royalty agreement:
Investment in Kinman Company Stock 147,500
Royalty Agreement 147,500
4. To record the purchase of inventory from Kinman:
Inventory 111,000
Investment in Kinman Company Stock 111,000
5. To recognize the equity in Kinman's net loss and comprehensive loss:
Equity in Net Loss 20,720
Equity in Other Comprehensive Loss 10,640
Investment in Kinman Company Stock 31,360
6. To record the receipt of the cash dividend:
Cash 15,000
Dividend Income 15,000
In 2021, Kinman reported a net income of $57,200 and paid a cash dividend of $17,000. Harper purchased additional inventory worth $120,000 from Kinman, out of which 70% ($84,000) was sold to outside parties by year-end. Harper would make the following journal entries in 2021:
1. To recognize the equity in Kinman's net income:
Equity in Net Income 22,880
Investment in Kinman Company Stock 22,880
2. To record the receipt of the cash dividend:
Cash 17,000
Dividend Income 17,000
3. To record the purchase of additional inventory from Kinman:
Inventory 120,000
Investment in Kinman Company Stock 120,000
4. To eliminate the unrealized profit in inventory:
Investment in Kinman Company Stock 8,400
Equity in Net Income 8,400
Overall, these journal entries reflect the investment in Kinman Company, adjustments for undervalued assets, recognition of income or loss, and dividend payments. The equity method is used to account for the investment, where Harper recognizes its share of Kinman's net income or loss and adjusts the investment account accordingly.
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Please help me with this page
Answer:
a) A = 1, C = 0, and D > 0 --> Graph B
b) A = 1, C = 0, and D < 0 --> Graph C
c) A > 1, C > 0, and D > 0 --> Graph D
d) 0 < A < 1, C < 0, and D < 0 --> Graph A
Which number is equivalent to the improper fraction 35/4
Step-by-step explanation:
If you want to make the improper fraction into a mixed fraction/decimal;
35/4 = 32/4 + 3/4 = 8 3/4 = 8.75.
The number equivalent to the improper fraction 35/4 is 8 3/4.
We have,
To convert the improper fraction 35/4 into a mixed number, divide the numerator (35) by the denominator (4):
35 ÷ 4 = 8 remainder 3
The quotient, 8, represents the whole number part, and the remainder, 3, represents the numerator of the fractional part.
So, the equivalent mixed number is:
8(3/4)
Therefore,
The number equivalent to the improper fraction 35/4 is 8 3/4.
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Point G is on line segment \overline{FH}
FH
. Given FH=4x+8,FH=4x+8, FG=x,FG=x, and GH=5x,GH=5x, determine the numerical length of \overline{GH}.
GH
.
The numerical length of GH = 20 units
FH is a line segment.
G is a point on the line segment.
Then G divides the line segment FH into two line segments FG and GH.
We are given the lengths of FH, FG and GH in terms of x.
That is, FH=4x+8, FG=x and GH=5x
We need to find the numerical length of the line segment GH. We first need to find the x for this.
As G cuts the line segment FH into two parts, the length of the line segment FH is the sum of the lengths of the line segments FG and GH.
That is, FH = FG + GH
⇒ 4x+8 = x +5x
⇒ 4x+8 = 6x
⇒ 2x = 8
⇒ x = 4
So the numerical length of GH = 5x = 5 x 4 = 20 units
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plz help i am very confused
Answer
6 1/6
Step-by-step explanation:
write and equation in slope-intercept form to represent each table x-3,6,9,12 y-5, -1, -7, -13
The equation that represents the table, in slope-intercept form, is: y = -2x + 11.
How to Write the Equation of a Line in Slope-intercept Form?The slope-intercept form of an equation that represents a line is expressed as y = mx + b, where:
m = slope = change in y / change in x.b = y-interceptUsing two pairs of values from the table, (6, -1) and (9, -7):
Slope (m) = (-7 -(-1)) / (9 - 6)
Slope (m) = -6/3
Slope (m) = -2.
Find the y-intercept, b, by substituting m = -2 and (x, y) = (6, -1) into y = mx + b:
-1 = -2(6) + b
-1 = -12 + b
-1 + 12 = b
b = 11
To write the equation, substitute m = -2 and b = 11 into y = mx + b:
y = -2x + 11
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Which rule is a recursive rule for the sequence 1, -6, 36, -216,...?
( I'll put the answers a screenshot )
PLZZ Help I've been stuck for so long
Answer:
The last answer
Step-by-step explanation:
We can check
For example,
a5=-6×a4
a5=-6×(-216)
a5=1296
The number of serious crimes reported daily in a certain city is a random variable X with mean 2 and variance 4. According to Chebyshev's inequality, P(X2 >=10) is less than or equal to what?
Chebyshev's Inequality states that, for any given dataset, the proportion of the values that lie within k standard deviations of the mean is always at least:1 - 1/k², where k is a positive integer greater than
1.Chebyshev's Inequality applies to all distributions, regardless of whether they're normal or skewed. The number of serious crimes reported daily in a certain city is a random variable X with mean 2 and variance 4. According to Chebyshev's inequality, P(X² >=10) is less than or equal to 1/5.So, the answer is: 1/5.
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ASAP!! ITS URGENT
If the base of a right prism is a rhombus whose diagonals are 6 km and 8 km and
whose altitude is 15 km, then the volume of the prism is…
Answer:
The total surface area of the prism is \(SA=348 \ \text{in}^2\)
Step-by-step explanation:
we know that
The two diagonals of a rhombus are perpendicular and bisect each other
All sides are congruent
The surface area of a prism is equal to
\(SA=2B+Ph\)
where
B is the area of the base of prism
P is the perimeter of the base of prism
h is the height of the prism
step 1
Find the length side of the rhombus
Applying Pythagoras Theorem
\(c^2=a^2+b^2\)
we have
c is the length side of the rhombus
a and b are the semi diagonals of the rhombus
\(a=8\div2=4 \ \text{in}\)
\(b=6\div2=3 \ \text{in}\)
substitute
\(c^2=4^2+3^2\)
\(c^2=25\)
\(c=5 \ \text{in}\)
step 2
Find the perimeter of the base P
The perimeter of the rhombus is equal to
\(P=4c\)
\(P=4(5)=20 \ \text{in}\)
step 3
Find the area of the base B
The area of the rhombus is
\(B=\dfrac{1}{2}[D1\times D2]\)
D1 and D2 are the diagonals of the rhombus
substitute
\(B=\dfrac{1}{2}[8\times 6]=24 \ \text{in}^2\)
step 4
Find the surface area of the prism
\(SA=2B+Ph\)
substitute the values
\(SA=2(24)+(20)(15)\)
\(SA=348 \ \text{in}^2\)
Evaluate 8-m/n+p^2 when m=8,n=2,p=7
Answer:
\(0\)
Step-by-step explanation:
\( \frac{8 - m}{n + p {}^{2} } = \frac{8 - 8}{2 + 49} = \frac{0}{51} = 0\)
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Answer:
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Step-by-step explanation:
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Answer:
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. Importance of hydrologic cycle The role of water is central to most natural processes - Transport - Weathering, contaminant transport - Energy balance - transport of heat, high heat capacity - Greenhouse gas - 80% of the atmospheric greenhouse effect is caused by water vapor - Life - for most terrestrial life forms, water determines where they may live; man is exception
The hydrologic cycle, also known as the water cycle, plays a crucial role in the Earth's natural processes. It involves the continuous movement of water between the Earth's surface, atmosphere, and underground reservoirs.
The importance of the hydrologic cycle can be understood by considering its various functions:
Transport: The hydrologic cycle facilitates the transport of water across the Earth's surface, including rivers, lakes, and oceans. This movement of water is vital for the distribution of nutrients, sediments, and organic matter, which are essential for the functioning of ecosystems.
Weathering and Contaminant Transport: Water plays a significant role in weathering processes, such as erosion and dissolution of rocks and minerals. It also acts as a carrier for contaminants, pollutants, and nutrients, influencing their transport through the environment.
Energy Balance: Water has a high heat capacity, which means it can absorb and store large amounts of heat energy. This property helps regulate the Earth's temperature and climate by transporting heat through evaporation, condensation, and precipitation.
Greenhouse Gas: Water vapor is a major greenhouse gas that contributes to the Earth's natural greenhouse effect. It absorbs and re-emits thermal radiation, trapping heat in the atmosphere. Approximately 80% of the atmospheric greenhouse effect is attributed to water vapor.
Life: Water is vital for supporting life on Earth. It provides a habitat for numerous organisms and serves as a medium for various biological processes. Terrestrial life forms, including plants, animals, and humans, rely on water availability for their survival, growth, and reproduction.
It is important to note that while water is critical for most terrestrial life forms, human beings have developed technologies and systems that allow them to inhabit regions with limited water availability. However, water still remains a fundamental resource for human societies, and the hydrologic cycle plays a crucial role in ensuring its availability and sustainability.
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The area of a mattress is 56 square feet. The width of the bed is x+4 and the length is 8. Solve for the value of
x by creating an equation using the area formula, then find the width of the mattress.
The width of the mattress is 7.
Give that
The area of the mattress is 56 square feet. The length is 8.And, the width of the bed is x + 4.Now as we know that
Area of the rectangle = Length × width
56 square feet = 8 × (x + 4)
56 = 8x + 32
56 - 32 = 8x
x = 3
So, the width is
= 3 + 4
= 7
Therefore we can conclude that the the width of the mattress is 7.
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