please mark as brainiest
Answer:
I'm going to go with C
Step-by-step explanation:
because the puppy has to be black out of all of the pets not just the black ones thus 10/55
how to do this? Angles ?
It’s already labeled..
Multiply, or add the numbers labeled on them. It’s really not about the angles
Sorry I didn’t really give you an answer but I hope this helped!
Find the sum of the series
{1875 + 750 + 300+...
+3.072}
Answer:
Find the indicated sum for each geometric series.
{1875+750+300+⋯+3.072}
Answer: 3122.952
Step-by-step explanation:
{1875+750+300+⋯+3.072}
r=0.4 3.072=1875(0.4)n−1
0.0016384=(0.4)n−1
7=n−1→n=8
Sn=1875(1−(0.4)8)1−0.4=3122.952
I think is like this.
which transformation is represented in the diagram
Answer:
C reflection
Step-by-step explanation:
Find the missing side of each triangle
Answer:
B) x = √118 mi
Step-by-step explanation:
This is a right triangle, so we can the measure of x using the Pythagorean theorem, which is
a^2 + b^2 = c^2, where
a and b are the shorter legs,and c is the hypotenuse (longest side opposite the right angleIn the figure, the sides measuring x mi and √26 mi are the legs, so we plug these in for a and b in the theorem,and the side measuring 12 mi is the hypotenuse, so we plug it in for c in the theorem:Step 1: Plug in x and √26 for a and b and 12 for c and simplify:
x^2 + (√26)^2 = 12^2
x^2 + 26 = 144
Step 2: Subtract 26 from both sides to isolate x^2:
(x^2 + 26 = 144) - 26
x^2 = 118
Step 3: Take the square root of both sides to isolate x:
√(x^2) = √118
x = √118 mi
Can someone please help me
Answer:
153.94 cm
Step-by-step explanation:
d=2r (need radius (r) to solve for the area)
14=2r
r=7
A=πr²
A=π(7)²
A=π49
A=153.94
y=-1/5x-2 grid square
Grid Square is another name for the coordinate plane. It can be inferred therefore that the equation [y=-1/5x-2] is to be graphed.
How do you graph y=-1/5x-2?To graph the above equation, we need to find the (x, y) pairs that satisfy the equation, then draw a line for the points.
Note that we can find this by simply substituting random values into x to find the y pair.
For example,
Where y = -(1/5)x - 2
If x = 1, then
y = (-(1/5) * 1) -2
y = -2.2
Where x = 2 then,
y = -2.4
Where x = 3
y = -2.6
Where x = 4
y = -2.8
Where x = 5
y = -3
Thus, the (x,y) pairs are as follows:
(1, -2.2)
(2, -2.4)
(3, -2.6)
(4, -2.8)
(5, -3)
Plotted on a graph, we would get the result attached.
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SAT QUESTION HELLP ME
Answer:
22.5
Step-by-step explanation:
we can use the ratios to turn x+y+z=180 to x+4x+3x= 180
then solve for 180
x = 22.5
Answer: D.) 22.5°
Have a nice day!
When Carla looked at the library, she noticed that for every 2 nonfiction books, there were 5 fiction books. If there are 161 books total, how many of them are not nonfiction books.
Answer:
138 nonfiction
Step-by-step explanation:
Ratio problem, we are going to use the part to all approach
Step one:
given data
the ratio of nonfiction to fiction books is 2 to 5
otherwise expressed as 2:5
the total ratio is 2+5= 7
the total number of books is 161,
applying the part to all approach
nonfiction to all is
let the nonfiction be x
2/7=x/161
cross multiply we have
7x= 161*6
7x=966
divide both sides by 7
x=966/7
x=138 nonfiction
138 nonfiction
what if the number of debilitating network viruses detected in a day at the firewalls of an internet service provider within a certain geographic region is fueling a possible management decision to upgrade the detection system. the decision will be made based on the results of the following data analysis. the mean number of network viruses detected in a day is 3.0. what is the probability that in any given day one network viruses will be detected?
Using the Poisson distribution formula, the probability of detecting a single network virus on a given day is approximately 0.1494 or 14.94%.
For the probability of seeing one network virus on any given day, we can use the Poisson distribution formula:
P(X = x) = (e^-λ * λ^x) / x!
Where:
P(X = x) is the probability of detecting x network viruses in a day
e is the mathematical constant e (approximately equal to 2.71828)
λ is the mean number of network viruses detected in a day
x is the number of network viruses detected in a day
Given that the mean number of network viruses detected in a day is 3.0, we have:
λ = 3.0
Now, the probability of detecting one network virus in a day, we plug x = 1 into the formula:
P(X = 1) = (e^-3.0 * 3.0^1) / 1!
= (0.0498 * 3.0) / 1 ⇒ 0.1494
Therefore, the probability of detecting one network virus on any given day is approximately 0.1494 or 14.94%.
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A store imploys 11 woman and 12 men
What percentage of the employees are men?
Need help with this problem step by step asap
-27-8v>-7(6v-5)+6
Answer:
Step-by-step explanation:
v > 2
hope this helps :)
mai lee bought a computer for her home office and depreciated it over 5 years using the straight line method. if its initial value was $2350, what is its value 3 years later
In this scenario, if a computer was bought for $2350 and is being depreciated over 5 years, the annual depreciation is $470, and its value 3 years later would be $1410.
The straight-line method of depreciation is a method of calculating the decline in value of an asset over time. Using this method, an asset's value is spread evenly over its useful life.
In this scenario, if the computer was bought for $2350 and is being depreciated over 5 years, the annual depreciation is ($2350 / 5) = $470.
Three years later, the computer's value would be $2350 - ($470 x 3) = $1410. This is because the value of the computer is decreasing by $470 per year, and after three years, the total amount of depreciation would be $470 x 3 = $1410.
It's important to note that the straight-line method of depreciation is a simple method and it does not reflect the real-world scenario in which assets may have a higher value of depreciation in the initial years and less in the later years. But it's easy to calculate and use.
In conclusion, if an asset is depreciated using the straight-line method, its value decreases evenly over its useful life. It's important for businesses to understand the various methods of depreciation and choose the one that best suits their needs.
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In the following equation, what would be the most logical first step when solving for z.
Answer:
Multiply 5/2 to both sides
Step-by-step explanation:
Doing so 'cancels' out the coefficient of (z+1) on the left-hand side.
A population has parameters μ = 56.7 and σ = 75.9. You intend to draw a random sample of size n = 246. What is the mean of the distribution of sample means? What is the standard deviation of the distribution of sample means? (Report answer accurate to 2 decimal places.)
The mean of the distribution of sample means is 56.7, and the standard deviation of the distribution of sample means is approximately equal to 4.82.
To calculate the mean of the distribution of sample means, we use the fact that the mean of a sample is an unbiased estimate of the population mean, and therefore the mean of the distribution of sample means is equal to the population mean. Thus, the mean of the distribution of sample means is 56.7.
To calculate the standard deviation of the distribution of sample means, we use the formula for the standard error of the mean, which is the population standard deviation divided by the square root of the sample size. Thus, the standard deviation of the distribution of sample means is equal to 75.9 divided by the square root of 246, which is approximately equal to 4.83.
Therefore, the mean of the distribution of sample means is 56.7, and the standard deviation of the distribution of sample means is approximately 4.83
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Can someone help me with this problem and show your work
Two cars, which are 210 miles apart, drive towards
each other at constant speeds. The speed of the
second car is 20 miles per hour faster than the first car.The cars pass each other in 1 1/2 hours. What is the speed of both cars?
Answer:
slower car=60 miles/hr
faster car =80 miles/hr
Step-by-step explanation:
the speed of slower car =x
the speed of faster car=x+20
they both 210 miles apart
(x+x+20)*(1 1/2 )=210
(2x+20)(3/2)=210
3x+30=210
3x=210-30
3x=180
x=180/3 ⇒ x=60
x+20 ⇒ 60+20=80
[Question 1] You are working with a population of crickets. Before the mating season you check to make sure that the population is in Hardy-Weinberg equilibrium, and you find that the population is in equilibrium. During the mating season you observe that individuals in the population will only mate with others of the same genotype (for example Dd individuals will only mate with Dd individuals). There are only two alleles at this locus ( D is dominant, d is recessive), and you have determined the frequency of the D allele =0.6 in this population. Selection acts against homozygous dominant individuals and their survivorship per generation is 80%. After one generation the frequency of DD individuals will decrease in the population. F
:According to the question:You are working with a population of crickets. Before the mating season you check to make sure that the population is in Hardy-Weinberg equilibrium, and you find that the population is in equilibrium.
During the mating season you observe that individuals in the population will only mate with others of the same genotype (for example Dd individuals will only mate with Dd individuals). There are only two alleles at this locus ( D is dominant, d is recessive), and you have determined the frequency of the D allele =0.6 in this population. Selection acts against homozygous dominant individuals and their survivorship per generation is 80%. After one generation the frequency of DD individuals will decrease in the population.
According to the Hardy-Weinberg equilibrium equation p² + 2pq + q² = 1, the frequency of D (p) and d (q) alleles are:p + q = 1Thus, the frequency of q is 0.4. Here are the calculations for the Hardy-Weinberg equilibrium:p² + 2pq + q² = 1(0.6)² + 2(0.6)(0.4) + (0.4)² = 1After simplifying, it becomes:0.36 + 0.48 + 0.16 = 1This means that the population is in Hardy-Weinberg equilibrium. This is confirmed as the frequencies of DD, Dd, and dd genotypes
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The median of a quanitive data set is always one of the infiviual data values. True or false
The given statement "The median of a quantitative data set is always one of the individual data values" is false.
What is a median?When a given data set is arranged in ascending order the observation which at the between of the data is the median of that data set. It is a value in the set whose left and right both have the same number of observations.
The given statement is not true, this is because the median is the mid-value of any data set.
If the number of data observations is odd then the median of a quantitative data set is always one of the individual data values.But if the number of data observations is even then the median is the average of the two numbers present in between the data observations.Hence, the given statement "The median of a quantitative data set is always one of the individual data values" is false.
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7+5-3*2(6*7)/4
• convert the above specified infix expression into
postfix expression
• Evaluate the resulted postfix expression
• convert the specified infix expression into prefix
expres
The postfix expression of "7+5-3*2(6*7)/4" is "7 5 + 3 2 * 6 7 * 2 * - 4 /". Evaluating the postfix expression gives the result of the expression. The prefix expression for the given infix expression is "/ - + 7 5 * 3 * 2 ( * 6 7 ) 4".
To convert the infix expression "7+5-3*2(6*7)/4" into postfix expression, we follow the rules of operator precedence and associativity. The postfix expression is obtained by placing operators after their operands.
The postfix expression for the given infix expression is:
"7 5 + 3 2 * 6 7 * 2 * - 4 /"
To evaluate the postfix expression, we use a stack data structure. We scan the postfix expression from left to right and perform the corresponding operations.
Starting with an empty stack, we encounter the operands "7" and "5". We push them onto the stack. Then we encounter the operator "+", so we pop the last two operands from the stack (5 and 7), perform the addition operation (7 + 5 = 12), and push the result back onto the stack.
We continue this process for the remaining operators and operands in the postfix expression. Finally, after evaluating the entire expression, the result left on the stack is the final answer.
To convert the infix expression into prefix expression, we follow similar rules but scan the expression from right to left. The prefix expression is obtained by placing operators before their operands.
The prefix expression for the given infix expression is:
"/ - + 7 5 * 3 * 2 ( * 6 7 ) 4"
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If 3 people stay in a hotel for today and by gh600.00 .what is the cost of 5 people staying for 8 days.
so it'd be 600 / 3 which gives you 200.00 that's what each person paid a day given that there's 5 five times 200 is one day 1000.00x 8 = ($8000.00) for 5 people for 8 days
At a local prechool there i a ratio of 3 boy to every 4 girl. If there are 245 total prechooler how many are boy
If there are 245 total preschoolers, there will be 105 boys.
What is unitary method?The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units. What can be values and units.Let's say you go to the store to buy six apples. You are informed by the shopkeeper that he is offering 10 apples for Rs 100. In this instance, the value and the units are the price of the apples.Recognizing the units and values is crucial when using the unitary technique to a problem.Always write the items that need to be computed on the right side and the things that are known on the left side to simplify things. We are aware of the quantity of apples and the amount of money in the aforesaid problem.acc to our question-
Fraction of boys = 3/7Fraction of girls = 4/7Total number of students = 245The number of boys will be:= 3/7 × 245.= 105 boysTherefore, there are 105 boys in the school.
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Subtract 5 1/3 —2 5/6. Explain how to
use compensation to simplify the
subtraction.
Answer:
first 5 1/3 convert it into 5 2/6, and than you turn it into 4 8/6 than you subtract 4 8/6 and 2 5/6 and you get 2 3/6= 2 1/2
Jordan writes 3(4x – 8) = 12x – 8
Explain why his expansion is not correct
Complete the following table and write down each of the expansions
x x -2
x
X (X – 2)
somebody please help me
Answer:
is the answer 2 3/4
Step-by-step explanation:
Tonya brought a jacket for $34. 23 a pillow for $11. 75 and a baseball cap for $16. 25 she paid $50 and the rest ship out for my friend is Tonia got $7. 77 in change from the cashier how much did she fall from Friend to pay for all the items
Tonia would need to pay Tonya $42.23 to cover the cost of all the items.
Tonya's total purchase was $34.23 + $11.75 + $16.25 = $62.23. She paid $50 and received $7.77 in change, which means she paid a total of $50 - $7.77 = $42.23 for her purchases. Therefore, Tonia would need to pay Tonya $42.23 to cover the cost of all the items.
Tonya purchased a jacket for $34.23, a pillow for $11.75, and a baseball cap for $16.25. She paid $50, and received $7.77 in change from the cashier. To find out how much she borrowed from her friend, first calculate the total cost of the items and the amount she actually paid:
Total cost of items = $34.23 + $11.75 + $16.25 = $62.23
Amount Tonya paid = $50 - $7.77 = $42.46
Now, subtract the amount she paid from the total cost of the items:
Amount borrowed from friend = $62.23 - $42.46 = $19.77
So, Tonya borrowed $19.77 from her friend to pay for all the items.
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a train travels north at 103km/hr is it a axample of speed ,velocity ,acceleration or speed and acceleration
Answer:
get photomath
Step-by-step explanation:
Henry is standing on a catamaran at an elevation of 10 1010 feet relative to sea level. His friend Thomas is scuba diving at an elevation of − 12 1 2 −12 2 1 minus, 12, start fraction, 1, divided by, 2, end fraction feet relative to sea level. Which friend has greater elevation? Choose 1 answer: Choose 1 answer: (Choice A) A Henry (Choice B) B Thomas Which friend is farther from sea level? Choose 1 answer: Choose 1 answer: (Choice A) A Henry (Choice B) B Thomas
Answer:
A.) Henry
B.) Thomas
Step-by-step explanation:
Given the following :
Henry's elevation = 10feets relative to sea level
Thomas elevation = -12 1/2 that is (-25/2) feet relative to sea level
Person with greater elevation:
Elevation can be described as height, in this case, the sea level used as the reference point. Therefore, a positive distance denotes an elevation above the reference point (which is the sea level). Therefore, Henry has a greater elevation of 10 feet( a distance above 0).
B) Who is farther from sea level:
This can be calculated by comparing the absolute distance between the elevation of both Henry and Thomas relative to the reference point(sea level)
Take reference point as 0
Absolute distances relative to sea level:
Henry's distance | 10 - 0 | = 10
Thomas's distance | -(25/2)- 0 | = 12 1/2
Answer:
A then B
Step-by-step explanation:
What is the inequality shown?
Simplify the expression 11c+3(−5c+4d)
step by step explanation:
-4c+12d
1. Distribute:
11c+3(-5c+4d)
11c-15c+12d
2. Combine like terms:
11c-15c+12d
-4c+12d
In a randomly selected 100 students in a large college, 20 of them had at least one sibling. Does this provide strong evidence that more than 15% of college students in America have at least one sibling? Find the p-value (round off to second decimal place).
The p-value is approximately 0.027 (rounded off to two decimal places).
To determine whether there is strong evidence that more than 15% of college students in America have at least one sibling, we can use a hypothesis test with a significance level of 0.05.
Let p be the proportion of college students in America who have at least one sibling. The null hypothesis is that p ≤ 0.15, and the alternative hypothesis is that p > 0.15.
Under the null hypothesis, the number of students in a sample of 100 who have at least one sibling follows a binomial distribution with parameters n = 100 and p = 0.15. We can use this distribution to calculate the probability of observing 20 or more students with at least one sibling in a sample of 100 if the null hypothesis is true.
The p-value is the probability of observing a test statistic as extreme or more extreme than the observed value, assuming the null hypothesis is true. In this case, the test statistic is the number of students with at least one sibling in a sample of 100.
Using a binomial distribution calculator or software, we find that the probability of observing 20 or more students with at least one sibling in a sample of 100 if p = 0.15 is approximately 0.027.
Since the p-value is less than the significance level of 0.05, we reject the null hypothesis and conclude that there is strong evidence that more than 15% of college students in America have at least one sibling.
Therefore, the p-value is approximately 0.027 (rounded off to two decimal places).
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