what is the pkb of the conjugate base of each of the following acids? (a) iodic acid hio3, ka = 1.6 10-1

The mass of carbon dioxide released during the reaction is 2.6 grams.

To determine the mass of carbon dioxide released during the reaction between sodium hydrogen carbonate (NaHCO3) and acetic acid (CH3COOH), we need to calculate the difference in mass before and after the reaction.

Before the reaction:

Mass of NaHCO3 = 3.8 g

Mass of acetic acid = 10.5 g

Total mass before the reaction = Mass of NaHCO3 + Mass of acetic acid = 3.8 g + 10.5 g = 14.3 g

After the reaction:

Mass of the contents of the reaction vessel = 11.7 g

To find the mass of carbon dioxide released, we calculate the difference in mass:

Mass of carbon dioxide released = Total mass before the reaction - Mass of the contents of the reaction vessel

= 14.3 g - 11.7 g

= 2.6 g

Therefore, the mass of carbon dioxide released during the reaction is 2.6 grams.

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for some reason it won't let me type the answer, it's the first option

The solution with the highest value of i is therefore A, 0.1 M K2SO4, which should have the most ideal behavior.

The colligative properties of a solution are the properties that are dependent on the concentration of the solute particles rather than their identity. Osmotic pressure, boiling point elevation, freezing point depression, and vapor pressure lowering are examples of colligative properties of a solution.

The solution with the most ideal behavior would have the greatest value of van't Hoff factor i, which represents the number of particles into which a substance dissociates when it is dissolved in a solvent.

A. K2SO4, 0.1 M: Since it is an ionic compound, K2SO4 should dissociate into three ions when dissolved in water: 2K+ and SO42-. This results in an i value of 3.

B. CaCl2, 0.1 M: CaCl2 should dissociate into three ions when dissolved in water: Ca2+ and 2Cl-. This results in an i value of 3.

C. LiF, 3.0 M: LiF is a covalent compound, which does not dissociate in aqueous solution. Therefore, the i value will be 1.

D. MgSO4, 0.1 M: MgSO4 should dissociate into three ions when dissolved in water: Mg2+ and SO42-. This results in an i value of 3.

E. NaCl, 0.1 M: NaCl should dissociate into two ions when dissolved in water: Na+ and Cl-. This results in an i value of 2.

The solution with the highest value of i is therefore A, 0.1 M K2SO4, which should have the most ideal behavior.

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Answer:

B. Non-metals

Explanation:

The element with the atomic number of 17 is Cl.

Chlorine belongs to the group 7 in the periodic table. It is a non metal.

Correct option: B. Non-metals

Answer:

See the explanation

Explanation:

In this question we have to take into account that we have to get the same amount of atoms on both sides, so:

Reaction 1

\(BaCl_2~+~H_2SO_4~=>~BaSO_4~+~2HCl\)

We have 1 Ba, 2 Cl, 2 H and 4 O on both sides

Reaction 2

\(Ca(OH)_2~+~CO_2~=>~CaCO_3~+~H_2O\)

We have 1 Ca, 2O, 2 H and 1 C on both sides

Reaction 3

\(2Al~+~3CuCl_2~=>~2 AlCl_3~+~3Cu\)

We have 2 Al, 3 Cu, and 3 Cl on both sides

Reaction 4

\(2SO_2~+~O_2~=>~2SO_3\)

We have 2 A and 6O on both sides

Reaction 5

\(2NH_3~+~3CuO~=>~3Cu~+~N_2~+~3H_2O\)

We have 2 N, 3 H, 3 Cu and 3O on both sides.

I hope it helps

Answer:

A gray-black magnetic mineral which consists of an oxide of iron and is an important form of iron ore.

Explanation:

Answer:

Naturally-magnetized pieces of magnetite, called lodestone, will attract small pieces of iron, which is how ancient peoples first discovered the property of magnetism.

Explanation:

Answer:

Electromotive force or e.m.f is defined as the battery's energy per Coulomb of charge passing through it. like other measures of energy per charge emf has SI unit of volts , equivalent to joules per coulomb.

The volume of the solution is 562.9 mL.

To find the volume of the solution, we need to use the formula:

concentration (molarity) = moles/volume (in liters)

We are given the concentration of the solution, which is 0.175 M. We can use this to find the number of moles of barium chloride in the solution:

0.175 M = moles / volume (in liters)

moles = concentration x volume (in liters)

We don't know the volume of the solution yet, but we can find the number of moles of barium chloride by rearranging the formula:

moles = concentration x volume (in liters)

volume (in liters) = moles / concentration

To find the moles of barium chloride, we first need to convert the mass given to moles using the molar mass of barium chloride. The molar mass of BaCl₂ is:

Ba: 137.33 g/mol

Cl₂: 2 x 35.45 g/mol =70.90 g/mol

Total: 137.33 + 70.90 = 208.23 g/mol

So, the number of moles of barium chloride is:

moles = 20.5 g / 208.23 g/mol

moles = 0.0986 mol

Now we can use the formula above to find the volume of the solution:

volume (in liters) = moles / concentration

volume (in liters) = 0.0986 mol / 0.175 M

volume (in liters) = 0.5629 L

Finally, we need to convert the volume to milliliters:

volume (in mL) = 0.5629 L x 1000 mL/L

volume (in mL) = 562.9 mL

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As we know STP means Standard Temperature and Pressure. Where, Pressure is 1 atm and temperature is 273 K and also Ideal gas law ( PV=nRT)

Where –

Now, according to the question –

Calculation –

\(\qquad\) \(\pink{\twoheadrightarrow\bf PV = nRT}\)

\(\qquad\) \(\twoheadrightarrow\sf V = \dfrac{nRT}{P}\)

\(\qquad\) \(\twoheadrightarrow\sf V =\dfrac{ 1.14 \times 0.0821 \times 273 }{ 1}\)

\(\qquad\) \(\twoheadrightarrow\sf V = \dfrac{25.55}{1}\)

\(\qquad\) \(\pink{\twoheadrightarrow\sf V = 25.55 L}\)

_______________________________________

Answer:

D A and B that is the answer

The molar solubility of Ca(OH)₂ in 0.05m Cacl₂ =  4.42 × 10⁻¹⁰ when concentration of Ca₂ is 0.06685 .

                          Ca(OH)₂ + 2HCl   → CaCl₂ + 2H₂O

So,

2 mol HCl neutralises in  1 mol Ca(OH)₂.

Part  1

Volume of HCl = 19.45 mL

                                  Moles = Molarity × Volume (L)

                                Moles of HCl = 0.05 M × 0.01945 L

                                           = 0.00097 mol

Now,

2 mol HCl : 1 mol Ca(OH)₂

1 mol HCl : 0.5 mol Ca(OH)₂

0.00097mol : 0.000485 mol Ca(OH)₂

So,

[Ca(OH)₂] = 0.000485 M

Now,

                                  1 mol Ca(OH)₂ : 2 mol OH-

So,

                                   [OH⁻] = 2 × [Ca(OH)₂]

                                       = 0.00097 M

Similarly evaluating  for part 2 we get-

[OH⁻] = 0.00095 M

Avg [OH⁻] = 0.00096 M

                    [Ca²⁺]                                         [OH⁻]

Initial              0                                                   0

Change             +x                                         +2x

Equilibrium      x                                                   2x

Now,

2x = 0.00096 M

x = 0.00048 M

So,

[Ca²⁺] = 0.00048 M

Now,

                                            Ksp = [Ca2+] × [OH-]²

                                                = x × (2x)²

                                                     = 4x³

                                                = 4.42 × 10⁻¹⁰

A substance's molar solubility is expressed as the molecular weight of the solute dissolved in one liter of solution. The number of ions dissolved per liter of solution is referred to as molar solubility. Here, dissolvability addresses the quantity of particles broke down in a given measure of dissolvable. The solvency (by which we typically mean the molar dissolvability ) of a strong is communicated as the centralization of the "broke down strong" in a soaked arrangement.

Temperature, pressure, and the solid's polymorphic form all affect solubility. Thermodynamic solvency is the convergence of the solute in immersed arrangement in balance with the most steady gem type of the strong compound.

Incomplete question :

0.05 M CaCl2 270C 0.0500 M Temperature of Ca(OH)₂ in 0.05 M CaCl₂: Concentration of standard HCl solution: Calculate the (OH"! from the titration data and the stoichiometry of the dissolution process to determine the molar solubility of Ca(OH), in 0.05 M CaCl₂ Report Table KSP.5: Titation Calculations (calcium hydroxide solubility in CaCl₂ solution) Table view List view Titration of saturated Ca(OH), in CaCl, with HCI Trial 1 Trial 2 19.45 Final buret reading (ml) Initial buret reading (mL) 19.00 0.00 0.00 Volume of HCl added (m) Concentration of OH" (M) (2pts) Average (OH) Complete the following ICE table using your titration data and the stoichiometry of the dissolution reaction. Report Table KSP.6: ICE Table: Solubility of Ca(OH)₂ in 0.05 M CaCl₂ Table view Equilibrium concentrations of Ca²+ and OH Ca(OH)₂ [ca?) List view [он1 Choose Choose- Choose Choose Initial Choose Choose Choose Choose Change Choose Choose Choose Choose Equilibrium (2pts) Concentration of Ca? (M) (2pts) What is the molar solubility of Ca(OH)₂ in 0.05 M CaCl

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This circuit allows electrical charges to flow because it is a closed loop that connects the battery, the light bulb, and the switch, allowing the electricity to flow from the battery to the light bulb, and then back to the battery.

A circuit is a closed path in an electrical or electronic system through which electric current can flow. Circuits are composed of electrical components such as wires, resistors, capacitors, and transistors, which are connected together in order to create a functional system. Circuits are used in all sorts of electrical and electronic devices, from computers and phones to televisions and cars. In order for a circuit to work properly, it must be designed and constructed with a specific purpose in mind.

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Answer:

8 moles of Fe2O3

Explanation:

You can use the mole ratio give. For every 3 O2 you produce 2 Fe2O3. With this you can find the number of moles. 12 O2 multiplied by the ratio 2/3 gives you 8 moles

B. 2Na:Cl2

2 moles of sodium react with 1 mole of chlorine to generate 2 moles of sodium chloride.

5 moles of sodium will react with 2/51 =2.5 moles of chlorine to form 5.0 moles of NaCl.

Because 3.0 moles of chlorine are present, chlorine is an excess reagent.

As a result, the Cl is the oxidising agent since it pushed the 2I to lose one electron while also gaining two electrons. 2I is the reducing agent.

Sodium is in the 0 oxidation state on the LHS and changes to +1 in the product, therefore it is oxidised. Hydrogen was +1 on the reactant side and goes to 0 oxidation state on the RHS, hence it is reduced.

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Answer:

"2.Orbital." I think

Explanation:

Risk*

Explosive materials need to be handled carefully and stored appropriately to avoid the possibility of initial combustion.   The following are some of the precautions to take when handling explosive materials: Avoid any type of friction, impact, or shock, whether small or large, when handling explosive materials.

Keep the containers of explosive materials tightly sealed to prevent the infiltration of moisture or contaminants. Store the explosives in a cool, dry, and well-ventilated environment, keeping them away from any heat sources or flammable materials. Keep the explosives away from direct sunlight to prevent the heat from building up and causing an explosion.

In conclusion, explosive materials should be handled and stored with care to prevent initial combustion, which may lead to an explosion. Explosives should be stored in a dry, cool, and well-ventilated area, and containers should be kept tightly sealed to prevent moisture or contaminants from entering. Explosives should also be kept away from any heat sources or flammable materials.

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Low pressure systems associated with high temperatures because warm air rises :)

Answer: 72.07%

Explanation:

P4 + 6 Cl2 --> 4PCl3

Since 123.90g/mol P4 is equivalent to 4(137.33g/mol PCl3)

So, 79.48g P4 = 4(137.33g/mol)(79.48g)/(123.90g/mol)

= 352.38g PCl3 formed

Percentage yield = (253.9/352.38) * 100 = 72.07%

Q.2.1 With the use of examples applicable to the case study, explain human resource forecasting. Human resource forecasting refers to the process of estimating and planning for the future staffing needs of an organization.

Q.2.3 One work-study method that could be recommended for Proteco Oil's refinery is the method of time and motion study.

Q.2.1 It involves analyzing the current workforce, identifying future workforce requirements, and developing strategies to meet those needs. In the case of Proteco Oil's Pressed Purity, human resource forecasting would involve predicting the number and types of employees needed to support the company's growth and expansion.

For example, as Pressed Purity expands its export operations into China and throughout the Asia Pacific region, they would need to forecast the additional human resources required to manage international logistics, distribution, and marketing. This may include hiring employees with expertise in international trade, language skills, and knowledge of the target markets. Human resource forecasting would also consider the need for additional staff at the state-of-the-art refinery in Kingaroy to handle increased production and quality control.

Q.2.2 Product differentiation refers to the process of distinguishing a product from its competitors by highlighting unique features, benefits, or characteristics. In the context of Pressed Purity, product differentiation is evident in several aspects of their offerings.

One example of product differentiation is their focus on being 100% Australian. This sets them apart from other oil manufacturers in Australia who may rely on imported ingredients. By promoting their Australian origin, Pressed Purity appeals to consumers who prioritize supporting local businesses and value the quality associated with Australian products.

Additionally, Pressed Purity emphasizes being chemical and preservative-free. This addresses the growing consumer demand for natural and healthier food options. By positioning their oils as naturally chemical-free, Pressed Purity differentiates themselves from competitors who may not have such a strong emphasis on natural and chemical-free products.

Q.2.3 One work-study method that could be recommended for Proteco Oil's refinery is the method of time and motion study. Time and motion study involves analyzing and improving work processes by observing and measuring the time required to complete specific tasks or activities.

In the context of the refinery, a time and motion study could be conducted to identify any inefficiencies or bottlenecks in the oil processing operations. This could involve observing workers as they perform tasks and measuring the time taken for each step of the process. By analyzing the data collected, the refinery management can identify areas where time can be saved, processes can be streamlined, and productivity can be improved.

For example, the time and motion study may reveal that certain equipment or machinery in the refinery is causing delays or requiring excessive manual labor. Based on these findings, the management can make informed decisions on investing in more efficient equipment or implementing process improvements to optimize productivity and reduce costs.

Q.2.4 Proteco Oil used the following criteria for market segmentation:

Demographic segmentation: The primary target audience for Pressed Purity is mostly females, aged 25-60+ years, with a contemporary cooking attitude. These consumers are health-conscious and seek natural and chemical-free options for themselves and their families. The secondary target audience includes men and women of all ages who consider themselves gourmet home chefs and are open to new tastes.

Psychographic segmentation: Pressed Purity targets consumers who prioritize natural and chemical-free products. By emphasizing the use of 100% natural ingredients and being genuinely Australian, Pressed Purity appeals to health-conscious consumers who value the quality and authenticity of the products they consume. They also cater to gourmet home chefs who are looking for unique and flavorful cooking options.

Geographic segmentation: Initially, Proteco Oil focused on the domestic market in Australia.

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Explanation:

cells, dna, chromosomes, body systems

Answer:

sunlight is the answer i think

The energy is required to take a 15.0-g sample of ice at −15.0 °c to liquid water at 45.0 °c is 8.30kj.

The term enthalpy is defined as the sum of the system's internal energy and the product of its pressure and volume.  

Ice warming Cs = 2.09 J/g∙°C

Enthalpy of fusion ∆H = 6.02 kJ/mol

Liquid water warming Cs = 4.18 J/g∙°C

Enthalpy of vaporization ∆H = 40.7 kJ/mol

Steam Warming Cs = 2.01 J/g∙°C

Step 1: Warm ice from −15.0°C to 0°C.

q1 = 470.25 joule

Step 2: Melt ice.

q2 = 5016.66

Step 3: Warm liquid water from 0°C to 45.0°C.

q3 = 2821.5 joule

The total energy is the sum of the energy of each step.

q = q1 + q2 + q3

= 470.25 + 5016.66 + 2821.5

= 8.30kj

Thus, energy is required to take a 15.0-g sample of ice at −15.0 °c to liquid water at 45.0 °c is 8.30kj.

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Answer:

NH4+ ammonium ion hydroxide ion

SO32- sulfite ion perchlorate ion

NO3- nitrate ion chlorate ion

NO2- nitrite ion chlorite ion

1. Helium has a boiling point of 4 k, and as it does so, the London dispersion force breaks bonds and interactions.

2. Helium has a boiling point of 20 k, and as it does so, the London dispersion force breaks bonds and interactions.

3. Hydrogen is able to break covalent bonds when heated from 30 K to 6000 K.

The least powerful bond-interaction force is the London dispersion force. The atoms of a substance are temporarily attracted to one another. Two atoms' electrons combine in a way that causes them to form dipoles. This force underlies every helium gas reaction.

When two species share electrons, a covalent link is created. Usually, they happen amongst compounds with comparable electronegativities. Bond strength is based on how many bonds there are between the atoms.

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Carbon dioxide molecules can absorb and emit infrared radiation, and they are one of the most abundant constituents of Earth's atmosphere.

Thus, the correct options are:d) Are one of the most abundant constituents of Earth's atmospheree) Can move in many ways, thus absorbing and emitting infrared radiation

Carbon dioxide is a trace gas present in the Earth's atmosphere. It's a vital component of Earth's carbon cycle, which helps to regulate Earth's temperature and support life as we know it. Carbon dioxide molecules are one of the most common gases in the atmosphere, accounting for around 0.04% of the Earth's atmosphere.

The greenhouse effect is caused by carbon dioxide, methane, and other greenhouse gases. When the Sun's energy reaches the Earth's surface, it is absorbed and then radiated back into space as infrared radiation. Greenhouse gases absorb this radiation and trap it in the atmosphere, which causes the Earth's temperature to rise and the climate to change.

Carbon dioxide molecules are capable of absorbing and emitting infrared radiation due to their molecular structure, which consists of one carbon atom and two oxygen atoms. This property of carbon dioxide is the main reason it's classified as a greenhouse gas.

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Answer:

seed and spores

Explanation:

I wish I'm correct

hope this helps

If I'm wrong SORRY

No approximations or assumptions need to be made in the calculation of the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid.

The pH and the tartrate ion 1C4H4O6 2-2 concentration of a 0.250 M solution of tartaric acid can be calculated using the acid-dissociation constants and the Henderson-Hasselbalch equation. The acid-dissociation constants (Ka1 and Ka2) of tartaric acid are 1.14x10-2 and 5.01x10-5, respectively.

The pH of the solution can be calculated using the Henderson-Hasselbalch equation: pH = pKa + log([base]/[acid]) where [base] is the concentration of the conjugate base (the tartrate ion) and [acid] is the concentration of the acid (tartaric acid). Since the solution is 0.250 M in tartaric acid, [acid] = 0.250 M and [base] = 0.250 M - [tartrate ion], which can be calculated using the Ka1 and Ka2 values.

For Ka1, the tartrate ion 1C4H4O6 2-2 concentration can be calculated as 0.250 M - 0.250 * 1.14x10-2 = 0.249 M. For Ka2, the tartrate ion 1C4H4O6 2-2 concentration can be calculated as 0.250 M - 0.250 * 5.01x10-5 = 0.249 M.

Using the Henderson-Hasselbalch equation, the pH of the solution can be calculated as pH = pKa + log([base]/[acid]). The pKa values of tartaric acid are 3.92 and 5.63 respectively. Therefore, for Ka1, the pH of the solution can be calculated as pH = 3.92 + log(0.249/0.250) = 3.91, and for Ka2, the pH of the solution can be calculated as pH = 5.63 + log(0.249/0.250) = 5.63.

No approximations or assumptions need to be made in the calculation of the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid, as the Henderson-Hasselbalch equation and the acid-dissociation constants of tartaric acid can be used.

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A conjugate acid-base pair is the pair of two compounds which differ by the presence of a proton. An acid will donate protons to a base and become a conjugate base. A base will accept protons and become a conjugate acid.Conjugate acid/base pairs are as follows:H2PO4− and HPO42−H2CO3 and CO32−HCl and Cl−H3O+ and OH−Explanation:

H2PO4− and HPO42−H2PO4− can donate a proton to become HPO42− and the latter can accept a proton to become H2PO4−.H2CO3 and CO32−H2CO3 can donate a proton to become CO32− and the latter can accept a proton to become H2CO3.HCl and Cl−HCl can donate a proton to become Cl− and the latter can accept a proton to become HCl.H3O+ and OH−H3O+ can donate a proton to become OH− and the latter can accept a proton to become H3O+.Therefore, the following are conjugate acid/base pairs:H2PO4− and HPO42−H2CO3 and CO32−HCl and Cl−H3O+ and OH−

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